a pendulum is swinging in a stationary elevator with period t. when the elevator accelerates upwards, what happens to the period of oscillation?

The vertical acceleration the rocket should have so that his apparent weight is equal to his true weight on earth is 8.2 m/s².

Imagine you are driving along and accelerating horizontally, which is to say, increasing the car's speed as it is traveling straight ahead. When you encounter a bump in the road, the vehicle experiences vertical acceleration and then returns to the ground as a result of gravity. Vertical motions go perpendicular to the horizon, and horizontal motions move parallel to (or horizontally) (or up and down). Additionally, vertical motion has constant acceleration whereas horizontal motion has constant velocity.

The given parameters;

acceleration due to gravity on moon, g = 1.6 m/s²

The true weight of the rocket is calculated from Newton's second law of motion;

F = ma

Apparent weight on moon = true weight on Earth

mg + ma =  mG

where;

G is the acceleration due to gravity on Earth

m(a + g) = mG

a + g = G

a = G - g

a = 9.8 - 1.6

a = 8.2 m/s²

Thus, the vertical acceleration the rocket should have so that his apparent weight is equal to his true weight on earth is 8.2 m/s².

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The answer is B goes 4 times higher than A.

examining movement to spot falling objects

For instance, a ball is initially moving upward when it is thrown into the air. As the ball approaches its highest point, the magnitude of velocity decreases because gravity accelerates an object toward the earth at a constant rate (g).

The body moves up when it is thrown upward until both the ball's velocity and the force acting on it are zero. The ball then travels at zero velocity with the acceleration caused by gravity until it touches the ground. The ball increases in height as it rises, as well as moving up.

We know,

v²-u²=2gs

[tex]u_{A}[/tex] = [tex]u_{B}[/tex] = 0

[tex]V^{2} _{A}[/tex] = 2g[tex]h_{A}[/tex]

[tex]h_{A}[/tex] = [tex]V^{2} _{A}[/tex]/2g

[tex]V^{2} _{b}[/tex] = 2g[tex]h_{B}[/tex]

[tex]h_{B}[/tex] = 2[tex]h_{A}[/tex]

Now,

[tex]h_{B}[/tex]= 2[tex]h^{2} _{A}[/tex]/2g

[tex]h_{B}[/tex] =4[tex]h^{2} _{A}[/tex]/2g = 4 [tex]h_{A}[/tex]

Therefore B goes 4 times higher than A.

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The work done by the ball on a string is 0J if a ball is travelling around as circle with a circumference of 2.0m

We know that circumference or perimeter of circle=2πr where r is the radius of the circle.

So, we have circumference=2m

Therefore,2πr=2

=>r=2/2π

=>r=(1/π) m

Now, we know very well that when a body moves a displacement dx under the action of force, some amount of work is done by the force on the body and that force is given by

W=[tex]\int\limits {F}. \, dx[/tex]

where F is defined as the force acting on the body

and dx is the displacement of the body.

On expanding the above formula, we get

=>W=Fdxcosθ where cosθ is the angle between the force and displacement of the body.

Since Tension is actually centripetal force which is acting along the center of the circle where ball displacement is in perpendicular direction to the tension.

It means angle between Tension and ball's displacement is 90°. So,cos90°=0

Therefore, W=Fdxcos90

=>W=0J.

Hence, amount of work done is 0J.

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(Complete question) is:

A ball on a string travels once around a circle with a circumference of 2. 0 m. The tension in the string is 5. 0 N. What amount of work done by the ball on the string?

Frequency and relative frequency is calculated by using the value of size of given data.

The times an occasion happens is known as a Frequency. Relative frequency is an exploratory one, yet at the same not a hypothetical one. Since it is a trial one, it is feasible to get different relative frequencies when we rehash the examinations. To compute the frequency we really want

Stage 1: To change over the frequencies into relative frequencies, we want to do the accompanying advances.

Stage 2: Gap the given frequency by the all out N i.e 40 which we assume.(Total sum of all frequencies).

Stage 3 : Gap the frequency by all out number We should perceive how : 1/40 = 0.25.

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A flight attendant pushes a cart down the aisle of a plane in flight. in determining the acceleration of the cart relative to the plane, The velocity of the plane, need to consider.

The pace at which a distance changes over time is referred to as speed. It has a dimension of time-distance. As a result, the fundamental unit of time and the basic unit of distance are combined to form the SI unit of speed. Thus, the meter per second (m/s) is the SI unit of speed. Let us suppose a flight attendant pushes a cart down the aisle of a plane in flight with a force (F) in Newton respectively. Also acceleration of the cart relative to the plane.

Therefore the only factor will be in consideration that will be velocity because we will be neglecting all other factors such as air resistance, relative plane etc.

Hence option (c) will be the correct answer: The velocity of the plane.

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The two bare wires line up with the ground fault interrupter plug's two pins. The ground fault interrupter will off the power if the hot wire comes into contact with water, the ground fault interrupter will disconnect the circuit.

In the scenario when the hot wire provides a 120 VAC current source, the neutral wire provides the hot wire's return path.

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The wavelength of an electron is 0.363 × 10⁻¹⁰m if it is moving with a velocity of 2×10⁷m/sec

For an electron energy relation with frequency and wavelength is same as photon have, but the wavelength relation for an electron is different from photon wavelength relation.

According to de-broglie postulates, we know that if a electron is moving with velocity v and having mass m, then its wavelength is given by

Wavelength=(plank's constant)/(mass of electron × velocity of electron)

=>λ = h/(m × v)

Plank's constant value is independent of external effects like temperature, pressure, work, torque etc.

Now, we know that h=6.62×10⁻³⁴(J/m)-sec

mass of electron =9.1×10⁻³¹Kg

and velocity of electron=2×10⁷m/sec

So,λ =(6.62×10⁻³⁴(J/m)-sec) / (9.1×10⁻³¹Kg×2×10⁷m/sec)

=>λ = (6.62×10⁻³⁴) / (18.2×10⁻²⁴)

=>λ=0.363 × 10⁻¹⁰m

Hence, wavelength of electron is 0.363 × 10⁻¹⁰m.

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Answer:

flooding

Explanation:

The rotational inertial of a wheel  is 12.618 [tex]kgm^{2}[/tex]

the formula of angular velocity (ω) = Rotation per min x frequency

                                                     = [tex]\frac{(714 * 2 * 3.14)}{60}[/tex]

                                                  ω   = 74.8 radian/sec

We know,

The kinetic energy is

                       [tex]KE = \frac{1}{2}Iw^{2}[/tex]

Where,

I = Moment of inertia

ω = Angular velocity

So,

   the rotational inertial of a wheel [tex](I) = \frac{2KE}{w^{2} }[/tex]

                                                         = [tex]\frac{2 * 35300}{74.8^{2} }[/tex]

                                                        = 12.618 [tex]kgm^{2}[/tex]

Rotational inertia is a property of everything that can be turned. It represents the difficulty of changing an object's rotational velocity around a certain rotational axis as a scalar value.

In rotational mechanics, rotational inertia plays a similar role to mass in linear mechanics. Of course, an object's mass has an impact on its rotational inertia. It also depends on how that mass is dispersed with respect to the axis of rotation.

An object's angular location or orientation over time is represented by a pseudovector termed angular velocity. Radians per second (rad/sec) is the SI unit for angular velocity.

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Answer:

Explanation:

i think this will help

The Force acting on the sports car is 7500N if it has a mass of 1500Kg and acceleration is 5m/sec².

We know that acceleration is defined as the ratio of velocity to the time taken. We know that if a body has mass and acceleration, then we have a formula F=ma which is derived from newton second law of motion. Acceleration can be many type like angular acceleration, average acceleration, linear acceleration. There is proper relationship between linear acceleration and angular acceleration.

According to newton second law of motion, Force is defined as the ratio of change in momentum of the object to the time taken.

Now, we have mass=1500Kg,a=5m/sec²

Using the above formula and putting the values, we get

=>F=(1500×5)

=>F=7500Kg-m/sec²

=>F=7500N.

Hence, required force is 7500N.

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The lens will form real image that can be focused screen.

As air has less optical density than water, and the shape of air lens is concave, it would act as converging lens when placed in water. And hence it can form a real image that can be focused on a screen.

The behavior of lens can be justified by calculating the focal length. For concave lens R1 is negative and R2 is positive.

Since, focal length is positive and behave as converging lens and forms the real image.

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The power of the flash is   [tex]2.36 * 10^{-9} W[/tex].

First we calculate the energy of a single photon; i.e.

[tex]E_{1} = hc/\alpha[/tex]

where, h = planck's constant = [tex]6.63 * 10^{-34} Js[/tex]

            c = speed of light = [tex]3 * 10^{8} m/s[/tex]

            [tex]\alpha[/tex] = wavelength = 490 nm = [tex]4.9 * 10^{-7} m[/tex]

Putting these values in equation, we get

[tex]E_{1} = 4.05 * 10^{-19} J[/tex]

Total energy is given by, E=Pt

where, P = power and t= time

Now number of photons is given by : N = E/[tex]E_{1}[/tex]

⇒ [tex]NE_{1} = E[/tex]

⇒ [tex]NE_{1} /t = P[/tex]

Given, N = [tex]1.4*10^{10}[/tex] and t = 2.4 s

Putting these values in above equation we get P = [tex]2.36 * 10^{-9} W[/tex]

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The true statement is truck B will have a greater stopping distance because its speed is greater hence more distance to cover.

The equation of kinetic energy is:

½ mv²

So, the higher the speed/velocity of a moving object, the greater the energy it has.

The question was incomplete, there should be several options :

The answer is truck B will have a greater stopping distance than truck A, because its speed is greater hence more distance to cover.

Truck B also will have greater kinetic energy because it has more velocity.

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The final velocity of the cheetah is 23 m/s.

Acceleration, then, is the alteration in that velocity. As you maintain or increase speed, acceleration moves in the same direction as velocity. The direction of velocity is in this. While you are retaining or gaining speed, you are accelerating in this direction. An object is accelerating if its velocity is changing, whether by a fixed amount or a variable quantity. Additionally, an item moving at a constant speed is not accelerating. The rate at which velocity varies is known as acceleration. In other words, accelerating. Increasingly, decreasingly, and in a different direction.

A vectorial quantity with both magnitude (speed) and direction is velocity. I can answer your question by using the example of uniform circular motion. In this example, the speed is constant, but the direction is constantly shifting.

Given u = 18m/s

a = 1 m/s^2

t = 5 sec

v = final velocity

We know that according to equation of motion

v = u + at

v = 18 + 1 x 5 = 18 + 5 = 23 m/s

Th final velocity of cheetah is 23m/s.

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The best activity for her to do to improve her range of motion is flexibility.

The term the range of motion (ROM) describes the extent to which a joint or muscle may be moved or stretched. Everybody has a distinct experience. For instance, whereas some people can perform a complete split, others cannot because their joints are stiff and their muscles are unable to extend as far.

A joint is said to have a restricted range of motion when it cannot move easily and completely in its typical position. A mechanical issue within the joint, swollen tissues around the joint, or pain may restrict motion.

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The Earth bound infrared telescopes are located on the high mountain tops and in very dry climates to improve visibility.

Infrared telescopes are used to explore the structure of galaxies because it has the ability to use infrared light in detecting celestial bodies present in a galaxy. It makes use of the electromagnetic radiation emitted by these bodies that are detected and resolved by the instrument.

Infrared rays are absorbed by the water vapour in the lower parts of our atmosphere such as near the sea level. Infrared telescoped positioned on high mountains can observe the cosmos at a wavelength near-infrared. In this case, this telescope is positioned on a mountain top where the altitude is high.

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The frequency of oscillator is 1.83 X 10⁷ Hz and the kinetic energy of the proton is 1.72 X 10⁷ eV.

(a)

Radius of the circle = r = 0.500 m

Magnetic Field = B = 1.20 T

Charge of proton = q = 1.60 X 10⁻¹⁹ C

Mass of proton = m = 1.67 X 10⁻²⁷ Kg

The frequency of oscillator is = f =

= f = 1/t = (qB) / 2πm

= f = ( 1.60 X 10⁻¹⁹ X 1.20 ) / ( 2 X 3.14 X 1.67 X 10⁻²⁷)

= f = 1.83 X 10⁷ Hz

(b)

Radius of the circle = r = 0.500 m

Magnetic Field = B = 1.20 T

Charge of proton = q = 1.60 X 10⁻¹⁹ C

Mass of proton = m = 1.67 X 10⁻²⁷ Kg

The kinetic energy of proton = E =

= E = (r X q x B)² / 2 X m

= E =  (0.500 X 1.60 X 10⁻¹⁹ x 1.20)² / 2 X 1.67 X 10⁻²⁷

= E = 1.72 X 10⁷ eV

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Galaxy B is at a greater distance.

When cepheid variables are located in two different galaxies, A and B, both stars have the same average apparent magnitude. The star in the galaxy A has a bright-dim-bright period of 10 days. The star in galaxy B has a bright-dim-bright period of 30 days, hence galaxy B is at a greater distance compared to galaxy A.

Cepheid variable, one of a class of variable stars whose periods (i.e., the time for one cycle) of variation are closely related to their luminosity and that are therefore useful in measuring interstellar and intergalactic distances.

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Constant acceleration indicates that there is no change in acceleration. The slope of the linear curve in the velocity -time graph gives the constant acceleration.

Acceleration is a physical quantity which measures the rate of change in velocity. Acceleration is a vector quantity thus, having both magnitude and acceleration.

Acceleration is mathematically the ratio of change in velocity to the change in time. Thus, if we plot the velocity with different times, we can determine the acceleration from the graph.

If the velocity - time graph gives a linear curve indicating the change in velocity is directly proportional to the change in time and the acceleration is constant. The slope of the straight line, gives the constant acceleration.

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The phase angle in an RLC series circuit is determined by the source frequency.

The capacitor dominates the impedance at extremely low frequencies, and the phase angle is around$ - {90^o}C$. The inductor dominates the impedance at very high frequencies. The RLC series circuit is a very important example of a resonant circuit. It has a minimum of impedance Z=R at the resonant frequency, and the phase angle is equal to zero at resonance. The resonance of a series RLC circuit occurs when the inductive and capacitive reactances are equal in magnitude but cancel each other because they are 180 degrees apart in phase. The sharp minimum in impedance which occurs is useful in tuning applications.

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Most of the polarized light will pass through the angle of cos²30°.

When this unpolarized light passes through a polarizer, the intensity of light reduces to half =Io/2 and this light becomes polarized.

Polarization refers to a situation in which light is made to vibrate in a single direction.

What is polarization?

Let us note that polarization refers to a situation in which light is made to vibrate in a single direction.

The intensity of the light that passes through the depolarizers depends on cos θ²

where θ is the difference between the angles of polarizer's alignment

For the first configuration, θ = 90° - 60° = 30°

cos²30° = 0.75 is greater than cos²60° and cos²45°

Therefore, most of the polarized light will pass through the angle of cos²30°.

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Astronomers will never directly observe the first few minutes of the universe because at that time the universe was actually opaque or too dark. There was the absence of photons and other important essentials of light formation.

In the later stages of the universe formation, when few elements essential for the light formation and transfer started appearing, the universe became too cold to allow the light to pass through, hence it still remained invisible.

Apart from the temperature being low at the time and the absence of photons, there were several other factors that made the universe quite invisible to astronomers at that time. some of the factors include the size of the universe and the energy formed by the galaxies throughout the different eras.

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0.76 ns does it take light incident perpendicular to the glass to pass through this 6.4 cm -thick sandwich.

The measurement of how much a light beam bends as it travels through different media is called the refractive index. It may alternatively be described as the relationship between the speed of a light ray in a material and the speed of a light ray in a vacuum, or n = c/v.

The more distorted the light is, the slower it moves through the medium, and ultimately, the more effective the refraction is, the higher the index number. A higher index score for eye wear use indicates that less material is required to get the desired effect.

when light goes in a medium,its velocity reduces to c/u (where c = velocity of light, u = refractive index)

since, light ray is incident perpendicular,there would be no refraction

total time taken will be (time=distance/speed)

t = 0.052/(3 × 10⁸/3.2) + 0.014/(3 × 10⁸/1.4) + 0.023/(3 × 10⁸/1.8)

t = 0.76 ns

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The power developed by a 110 pound person lifting himself 4.0 feet in 2.5 seconds is 0.32 hp.

Power is the speed in doing work, or the rate of energy that is distributed while doing work  in a certain period of time.

The Watt unit is used as a mark of respect for a scientist named James Watt who succeeded in inventing the steam engine.

In addition, the unit of power that is often used besides watts is Horse Power (hp), where 1 hp = 746 Watts.

The equation for determining power is:

P = W/t

Where,

P = power (Watt)

W = work (Joule)

t = period (second)

We have,

4.0 feet-lbf  

Determine the work done first,

W = F x s

= (110) (4.10)

=  440 feet-lbf ⇒ 596.2 J

So, the power that was developed:

P = W/t

= (596.2)/(2.5)

= 238.5 watt ⇒ 0.32 hp

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The frequency of a sound wave is 170Hz which has a wavelength of 2.0 m and speed of sound wave 340 m /s

Frequency is the amount of occasions of a reiterating event for each unit of time. It is moreover at times insinuated as common repeat for clarity, and is indisputable from jaunty repeat. Frequency is assessed in Hertz (Hz) which is identical to one event each second. The period is the time span between events, so the period is the relating of the recurrence.

For sound wave ,we know an expression

c=ν × λ

where c is the defined as the speed of wave in any medium,

ν is  defined as the frequency of the wave and

λ is defined as the  wavelength of the wave.

Now,340 = (v×2)

=>v=340/2

=>v=170/sec

or v=170Hertz since (1Hz=1/sec)

Hence, frequency of a sound wave is 170Hertz.

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index of refraction (n) = 1.20 wavelength = 4 cm

What is wavelength radar?

Radar used to measure wind waves is called wave radar. There are several instruments available that are based on various ideas and methods, and they are all frequently termed.

In situations where it's critical to avoid direct contact with the water surface and structural interference, instruments based on radar remote sensing techniques have grown in popularity. Wave measurements from an offshore platform in deep water are an example of a situation where anchoring a wave buoy would be extremely challenging due to rapid currents. Another intriguing situation is that of a ship in motion, where it is extremely impracticable to have equipment in the sea

According to the question:

using the formula for minimum thickness of coating to inhibit reflection: thickness = λ4 thickness = 4 cm

4×1.20 thickness = 0.833 cm

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wavelength = 4 cm index of refraction (n) = 1.20

What exactly is wavelength radar?

Wave radar is a type of radar that is used to measure wind waves. There are several instruments available that are based on diverse concepts and methodologies, and they are all often referred to.

Instruments based on radar remote sensing techniques have increased in popularity in circumstances where it is vital to avoid direct contact with the water surface and structural interference. Wave measurements taken from an offshore platform in deep water are an example of a circumstance in which mooring a wave buoy would be exceedingly difficult owing to strong currents. Another fascinating circumstance is that of a ship in motion, when having equipment in the sea is exceedingly impractical.

Using the formula for minimal coating thickness to reduce reflection: 4 is the thickness 4 cm thickness

4x1.20 mm thick = 0.833 cm

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172 joules work is done on a bookshelf being pulled 5 m at an angle of 37o from the horizontal.

Work = Force * times *distance

we will use the component of the force in the direction of the distance

In this problem, let’s say the distance (5.00 m) is horizontal. The horizontal component of the force is  Fcosθ

W=(Fcosθ)(D)

or

W = (43.0)(cos37.0)(5.00)

= 172Nm

=  172 Joules

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The ratio of escape velocity of Helium, Argon   and  Xenon  is 31.5 %, 10.0 % and 5.5 % respectively.

Calculation:-

taking T = 2000 K and R = 8.315 J mol-1 K-1

Molar mass for Helium = 4.0026 x 10?3 kg mol-1

Molar mass for Argon   = 39.948 x 10?3 kg mol-1

Molar mass for Xenon  = 131.29 x 10?3 kg mol-1

We get the rms speed for the given gases as followed

Helium =  3.53 km s-1

Argon   = 1.12 km s-1

Xenon  =  0.62 km s-1

The ratio of the escape velocity to the root-mean-square speed of the given gases

The ratio of helium = 31.5 %

The ratio of argon  = 10.0 %

The ratio of xenon = 5.5 %

Yes, the fraction (or ratio) of the speed exceeding the escape velocity (31.5%) is larger in helium, which makes low abundancy of the helium in the atmosphere.

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If the stopping distance for a speed (velocity) 20mph is 100ft, then the stopping distance for a speed (velocity) 40mph is 400ft.

It defines the direction of the movement of the body or the object. The velocity of a moving object can be zero. Speed is a prime indicator of the rapidity of the object. Velocity is the prime indicator of the position as well as the rapidity of the object.

How to calculate the stopping distance when the speed (velocity) is 40mph?

Given from the question
V₁ = 20mph = 29.334ft / s

S = 100ft Now, let's use the equation of motion

v² - u² = 2as
Where

v = final velocity = 0 (because the car is stopped)

u = initial velocity

a = acceleration (negative if slowing down)

s = distance moved

0 - 29.334² = 2 * (-a) * 100

-860.483556 = - 200a

a = 4.302 ft / s²

Now, when velocity is 40mph, equal to 58.6667 ft/s

using the same equation

v² - u² = 2as

0 - 58.6667² = 2 * (-4.302) * s

-3441.78168889 = - 8.604 * s

s = 400feet (rounded)

Therefore, if you were increase your speed to 40 miles per hour, your stopping distance will be 400 feet.

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