a ladder is leaning against the side of a brick wall the base of the ladder is 6 feet away from the brick wall the top of the ladder touches the brick wall at 8 feet from the ground how long is the ladder 4ft 10 feet or 14 feet or 7 feet

Answers

Answer 1

The base of ladder is at distance of b = 6 feet from the wall.

The height of top of ladder from ground is h = 8 feet.

Let the length of ladder be l.

Determine the length of ladder by using the pythagoras theorem.

[tex]\begin{gathered} l^2=(6)^2+(8)^2 \\ =36+64 \\ =100 \\ l=\sqrt[]{100} \\ =10 \end{gathered}[/tex]

So length of the ladder is 10 feet.

A Ladder Is Leaning Against The Side Of A Brick Wall The Base Of The Ladder Is 6 Feet Away From The Brick

Related Questions

15. Graph the rational function ya*-*Both branches of the rational function pass through which quadrant?Quadrant 2Quadrant 3Quadrant 1Quadrant 4

Answers

SOLUTION:

CONCLUSION:

Both branches of the rational function pass through Quadrant 1.

Solve the following equation for x. (x - 5) -6 2 OX= -2 O x=2 x=-17 X=-7

Answers

You have teh following equation:

(x - 5)/2 = - 6

In order to find the solution to the previous equation, proceed as follow:

(x - 5)/2 = -6 multiply by 2 both sides

x - 5 = -6(2)

x - 5 = -12 add 5 both sides

x = -12 + 5 simlify

x = -7

Hence, the solution to the gicen equation is x = -7

Last weekend, 5% of the tickets sold at Seaworldwere discount tickets. If Seaworld sold 60 tickets inall, howmany discount tickets did it sell? Use thepercent proportion.

Answers

Let:

N = Total tickets

d = discount tickets

r = percent of discount tickets sold

so:

[tex]\begin{gathered} d=N\cdot r \\ where\colon \\ N=60 \\ r=0.05 \\ so\colon \\ d=60\cdot0.05 \\ d=3 \end{gathered}[/tex]

3 discount tickets were sold

a square pyramid has a base height edge length of 3m and a slant height of 6m. find the lateral area and surface area of the pyramid

Answers

hello

given that the pyramid has the shape of a triangle, we can easily find the height of the pyramid using pythagoran's theorem

from triangle b, let's use the formula and solve for y

[tex]\begin{gathered} x^2=h^2+z^2 \\ 6^2=h^2+1.5^2 \\ 36=h^2+2.25 \\ \text{collect like terms} \\ h^2=36-2.25 \\ h^2=33.75 \\ \text{solve for h} \\ h=\sqrt[]{33.75} \\ h=5.809\approx5.81m \end{gathered}[/tex]

having known the value of the heigh of the pyramid, we can now proceed to solve for the lateral area and surface area

for the lateral area, the formula is given as

[tex]\begin{gathered} A_l=l\sqrt[]{l^2+4h} \\ l=\text{edge length} \\ h=\text{height of pyramid} \end{gathered}[/tex][tex]\begin{gathered} A_l=l\sqrt[]{l^2+4h} \\ l=3m \\ h=5.81m \\ A_l=3\sqrt[]{3^2+4\times5.81_{}} \\ A_l=17.03m^2 \end{gathered}[/tex]

the lateral area of the figure is 17.03 squared meter.

let's solve for the surface area

the formula for the surface area of a square pyramid is given as

[tex]\begin{gathered} A=l^2+2l\sqrt[]{\frac{l^2}{4}+4h^2} \\ l=3m \\ h=5.81 \\ A=3^2+2\times3\sqrt[]{\frac{3^2}{4}+4\times5.81^2} \\ A=9+6\sqrt[]{\frac{9}{4}+135.0244} \\ A=79.298\approx79.3m \end{gathered}[/tex]

is it option one or two I don't need to work

Answers

From the options, the function has the next form

[tex]y=a\cdot b^x[/tex]

where a and b are two constants.

The function pass through the point (0, 2), then:

[tex]\begin{gathered} 2=a\cdot b^0 \\ 2=a\cdot1 \\ 2=a \end{gathered}[/tex]

The function pass through the point (1, 10), then:

[tex]\begin{gathered} 10=2\cdot b^1 \\ \frac{10}{2}=b \\ 5=b \end{gathered}[/tex]

Therefore, the function is:

[tex]y=2\cdot5^x^{}[/tex]

A window had a length of 2ft & width of 3ft. What is the area of the window?

Answers

The formula used to calculate the area of the window will be

[tex]\begin{gathered} \text{Area}=l\times w \\ \text{where,} \\ l=2ft \\ w=3ft \end{gathered}[/tex]

By substituting the values, we will have

[tex]\begin{gathered} \text{Area}=l\times w \\ \text{Area}=2ft\times3ft \\ \text{Area}=6ft^2 \end{gathered}[/tex]

Hence,

The final answer = 6ft²

Graph the following inequalitiesy ≥ -x/4 + 5

Answers

Solution

The graph of the inequality is shown below

How does g(t) = 1/2t change over the interval t = 0 to t = 1?

Answers

we have the equation

[tex]g(t)=\frac{1}{3^t}[/tex]

Find out the rate of change over the interval [0,1]

Remember that

the formula to calculate the rate of change is equal to

[tex]\frac{g(b)-g(a)}{b-a}[/tex]

In this problem

a=0

b=1

g(a)=g(0)=1

g(b)=g(1)=1/3

therefore

the function decreases by a factor of 3

A circle has a circumference of 25 feet, what is the diameter? Your answer

Answers

Given :

The circumference of the circle = 25 feet

π = 3.14

The circumference of the circle =

[tex]2\pi\cdot r=\pi\cdot d[/tex]

Where r is the radius and d is the diameter

so,

[tex]\begin{gathered} \pi\cdot d=25 \\ \\ d=\frac{25}{\pi}=\frac{25}{3.14}\approx7.96 \end{gathered}[/tex]

if we rounded to the nearest feet, the diameter = 8 feet

Lines m and n are parallel. Which are corresponding angles?Angles 1 and 3Angles 1 and 5Angles 1 and 4Angles 1 and 2

Answers

EXPLANATION

By the corresponding angles theorem, we can affirm that the following angles are corresponding ones:

angles 1 and 5 are corresponding because they occupy the same relative position.

a bag contains 30 marbles. 8 are pink, 11 are blue, 4 are yellow and 7 are purple. Calculate the probability of randomly selecting a marble that is not blue .

Answers

In order to find the probability of a marble not being blue, we need to find how many marbles are not blue.

To do so, we just need to sum the number of pink, yellow and purple marbles:

[tex]8+4+7=19[/tex]

Now, to find the probability, we just need to divide the number of non-blue marbles by the total number of marbles.

[tex]\frac{19}{30}=0.6333=63.33\text{\%}[/tex]

If cos(0) = 24/25, and 0 is in Quadrant I, then what is cos(0/2)? Simplify your answer completely, rationalize the denominator, and enter it in fractional form.

Answers

The given information is:

[tex]\begin{gathered} \cos (\theta)=\frac{24}{25} \\ \theta\text{ is in quadrant I} \end{gathered}[/tex]

cos (theta/2) is given by:

[tex]\cos (\frac{\theta}{2})=\pm\sqrt[]{\frac{1+\cos\theta}{2}}[/tex]

In Quadrant I, cos (theta) is positive, then the answer is positive. By replacing the known values:

[tex]\begin{gathered} \cos (\frac{\theta}{2})=\sqrt[]{\frac{1+\frac{24}{25}}{2}} \\ \cos (\frac{\theta}{2})=\sqrt[]{\frac{\frac{25+24}{25}}{2}} \\ \cos (\frac{\theta}{2})=\sqrt[]{\frac{\frac{49}{25}}{2}} \\ \cos (\frac{\theta}{2})=\sqrt[]{\frac{49}{25\times2}} \\ \cos (\frac{\theta}{2})=\sqrt[]{\frac{49}{50}} \\ \cos (\frac{\theta}{2})=\frac{\sqrt[]{49}}{\sqrt[]{50}} \\ \cos (\frac{\theta}{2})=\frac{7}{\sqrt[]{50}} \\ \cos (\frac{\theta}{2})=\frac{7}{\sqrt[]{50}}\cdot\frac{\sqrt[]{50}}{\sqrt[]{50}} \\ \cos (\frac{\theta}{2})=\frac{7\sqrt[]{50}}{50} \\ \cos (\frac{\theta}{2})=\frac{7\sqrt[]{25\times2}}{50} \\ \cos (\frac{\theta}{2})=\frac{7\cdot\sqrt[]{25}\cdot\sqrt[]{2}}{50} \\ \cos (\frac{\theta}{2})=\frac{7\cdot5\cdot\sqrt[]{2}}{50} \\ \text{Simplify 5/50} \\ \cos (\frac{\theta}{2})=\frac{7\sqrt[]{2}}{10} \end{gathered}[/tex]

This is so hard I don’t understand this pls help

Answers

From the given question

There are given that the matrix.

Now,

To find the inverse of any matrix, first find their determinant.

Then,

According to the properties of the matrix:

If the determinant of any matrix is zero, then their inverse has undefined.

So,

From the determinant of the given matrix:

[tex]\begin{gathered} \begin{bmatrix}{4} & {8} & {} \\ {7} & {14} & \\ {} & {} & {}\end{bmatrix}=(14\times4)-(8\times7) \\ =56-56 \\ =0 \end{gathered}[/tex]

The determinant of the given matrix is zero

So, their inverse has not been defined.

Hence, the correct option is A.

1.1.22Question HelpAngie and Kenny play online video games. Angie buys 1 software package and 3 months of game play, Kenny buys 2 software packages and 2 months of gameplay. Each software package costs $25. If their total cost is $125, what is the cost of one month of game play?

Answers

We have a system of linear equations:

Let S be the price of software package and M be the price of the month of game play.

Angie buys 1 software package and 3 months of gameplay, while Kenny buys 2 software packages and 2 months of game play. The total cost for them is $125.

We can write this as:

[tex]\begin{gathered} (1S+3M)+(2S+2M)=125 \\ 3S+5M=125 \end{gathered}[/tex]

We also know that each software package cost $25. This can be written as:

[tex]S=25[/tex]

We can replace this last equation in the first one, and calculate M:

[tex]\begin{gathered} 3S+5M=125 \\ 3(25)+5M=125 \\ 75+5M=125 \\ 5M=125-75 \\ 5M=50 \\ M=\frac{50}{5} \\ M=10 \end{gathered}[/tex]

The cost of one month of game play is $10.

SOLVE PLEASE -2x^2+18x+____

Answers

In this case, we'll have to carry out several steps to find the solution.

Step 01:

Data

- 2x² + 18x + _________

Step 02:

(a + b) = a² + 2ab + b²

a² = -2x²

[tex]a\text{ = }\sqrt[]{-2\cdot x^{2}}\text{ = x }\sqrt[]{-2}[/tex]

[tex]a\text{ = }\sqrt[]{2}i[/tex]

2ab = 18x

[tex]2(x\sqrt[\text{ }]{-2)}\cdot\text{ b = 18 x}[/tex][tex]b\text{ = }\frac{18x}{2x\sqrt[]{-2}}=\frac{9}{\sqrt[]{-2}}=\frac{9}{\sqrt[]{2\text{ }}i}[/tex]

Two ways to express the solution:

[tex]\begin{gathered} -2x^{2\text{ }}+\text{ 18x + 9/}\sqrt[]{-2} \\ -2x^2+18x\text{ + 9 / }\sqrt[]{2}i \end{gathered}[/tex]

How many people were using program 2 but not program 3?

Answers

Let Program 1, Program 2, and Program 3 be represented by P1, P2, and P3.

Given:

n(P1 n P2) = 6

n(P2 n P3) =8

n(P1 n P3) = 5

n(P1 n P2 n P3) = 2

n(P1 U P2' U P3') =18

n(P2) = 22

n(P3 U P1 U P2') = 16

n(P1 U P2 U P3)' = 17

Representing the information on a Venn diagram:

The number of people that were using Program 2 but not Program 3:

[tex]\begin{gathered} n(P_2UP_3^{\prime})=n(P_2)-n(P_2nP_3)\text{ } \\ =\text{ 22 - 8} \\ =\text{ 16} \end{gathered}[/tex]

Number of people surveyed

The number of people surveyed is the sum of the individual subsets:

[tex]\begin{gathered} =\text{ 18 + 10 + 13 + 4 + 6 + 3 + }2\text{ + 17} \\ =\text{ 73} \end{gathered}[/tex]

A girl cycled a total of 15 kilometers by making 5 trips to work. How many trips will she have to make to cover a total of 24 kilometers? Solve using unit rates.

Answers

We need to find how many trips she will have to make to cover a total of 24 kilometers.

We know that she covered 15 kilometers by making 5 trips. Thus, the number of kilometers made on each trip is:

[tex]\frac{15\text{ kilometers}}{5\text{ trips}}=\frac{15\div5\text{ kilometers}}{5\div5\text{ trip}}=\frac{3\text{ kilometers}}{1\text{ trip}}[/tex]

Then, she made 3 kilometers on 1 trip (unit rate).

Now, to cover 24 kilometers, she needs to make 8 trips, because:

[tex]\begin{gathered} 3\text{ kilometers }\times8=24\text{ kilometers} \\ \\ 1\text{ trip }\times8=8\text{ trips} \end{gathered}[/tex]

Thus:

[tex]\frac{3\text{ kilometers}}{1\text{ trip}}=\frac{3\text{ kilometers}}{1\text{ trip}}\times\frac{8}{8}=\frac{3\times8\text{ kilometers}}{1\times8\text{ trips}}=\frac{24\text{ kilometers}}{8\text{ trips}}[/tex]

Answer: She will have to make 8 trips.

What is the difference between area and perimeter of a two-dimension figure? What is the difference in the area formulas for a parallelogram and triangle

Answers

The perimeter is a measure of the distance around the shape. This means that to find the perimeter we usually are going to add the lenghts of the sides of the figure (the circle is an exception to that rule since this is a curve figure).

The are is a measure of the space inside the figure. This means that to find the area we usually are going to multiply the lenghts of the sides of the figure to get the area.

Now the area of a triangle is given as:

[tex]A=\frac{1}{2}bh[/tex]

whereas the area of a paralelogram is given by:

[tex]A=bh[/tex]

From this we notice that the area of the triangle is half the area of a parallelogram.

PLEASE HELP 15 POINTS!! I'M GIVING BRAINLIEST

Answers

The value of sinα  in the right angle triangle is [tex]\frac{16\sqrt{281} }{78961}[/tex]

What is a right-angle triangle?

A right-angled triangle is a triangle, that has one of its interior angles equal to 90 degrees or any one angle is a right angle. Therefore, this triangle is also called the right triangle or 90-degree triangle. The right triangle plays an important role in trigonometry.

sin α = opposite/hypotenuse

opposite = 16, hypotenuse [tex]\sqrt{281}[/tex]

sin α = [tex]\frac{16}{\sqrt{281} }[/tex]

By rationalizing, the denominator which means multiply the fraction by [tex]\frac{\sqrt{281} }{\sqrt{281} }[/tex]

[tex]\frac{16}{\sqrt{281} }[/tex] x [tex]\frac{\sqrt{281} }{\sqrt{281} }[/tex] = [tex]\frac{16\sqrt{281} }{78961}[/tex]

sin [tex]\alpha[/tex] = [tex]\frac{16\sqrt{281} }{78961}[/tex]

In conclusion, the value of sin[tex]\alpha[/tex] = [tex]\frac{16\sqrt{281} }{78961}[/tex]

Learn more about trigonometric ratios: https://brainly.com/question/1165363

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What are all the ordered pairs that are solutions to the inequality 2x-3y>=12

Answers

To answer this question, we need to solve this inequality for y as follows:

[tex]2x-3y\ge12[/tex]

Then, we have:

[tex]-3y\ge12-2x\Rightarrow\frac{-3y}{-3}\leq\frac{12}{-3}-\frac{2x}{-3}\Rightarrow y\leq-4+\frac{2x}{3}[/tex]

As we can see the direction of the inequality changed because we multiplied it by a negative number.

Then, if we can see the inequality, we find that the values that make this inequality true

are infinite values (the values of y are in function of the values of x).

Then, since we have the values given in the options, we need to check which of these values make the inequality true or we can graph a line for this inequality.

We have that the line is given by:

y = 2x/3 - 4

The x-intercept for this line is:

[tex]undefined[/tex]

What is the approximate diameter of the largest Circle she can make

Answers

We have that the circumference of a circle can be represented with the following equation:

[tex]C=\pi d[/tex]

where d represents the diameter of the circle.

In this case, we have a circle of circumference C = 30 ft made with the lights, then, using the equation and solving for d, assuming that pi equals 3.14, we get:

[tex]\begin{gathered} 30=(3.14)d \\ \Rightarrow d=\frac{30}{3.14}=9.55\approx10ft \end{gathered}[/tex]

therefore, the approximate diameter of the largest circle is 10 ft

Brightness up inequality which can be used to determine o, The number of outfit Joseph can’t purchase well staying within his budget.

Answers

let o be the number of outfits, then

o*53.96 shoud be less than or equal to 620 - all what he bought, so:

Total money: $620

Spent money: $620 - $440.12 - $19.26 - 25.72 = $134.9

The inequality will be:

53.96o ≤ 134.9

o ≤ 2.5

You need 3 sticks of butter for every 24 cookies you bake. How many cookies can I make with 5 sticks?

Answers

ANSWER

[tex]40\text{ cookies}[/tex]

EXPLANATION

We want to find the number of cookies that can be made with 5 sticks.

To solve this, we have to apply proportions. Let the number of cookies that can be made be x.

We have that:

[tex]\begin{gathered} 3s=24c \\ 5s=x \end{gathered}[/tex]

Now, cross-multiply:

[tex]\begin{gathered} 3\cdot x=24\cdot5 \\ \Rightarrow x=\frac{24\cdot5}{3} \\ x=40\text{ cookies} \end{gathered}[/tex]

That is the number of cookies that can be made.

Which of the following describes the transformation of the graph y = x 2 in graphing y = -x 2 - 5?reflect over the x-axis and shift down 5reflect over the y-axis and shift down 5reflect over the x-axis and shift left 5

Answers

The parent function of the graph is,

[tex]y=x^2[/tex]

The transformed image of the graph is,

[tex]y_1=-x^2-5[/tex]

Let us sketch out the graph of both the parent function and the transformed function.

From the image above, the parent function, y=x² was first reflected over the y-axis. Therefore, the transformation resulted into y= -x² .

After that, it was now shifted down by 5 units, which now resulted into

[tex]y=-x^2-5[/tex]

Hence, the correct answer is B(Second option), which is the parent function was reflected over the y-axis and shifted downward by 5 units.

Which describes the effect of the transformations on the graph of f(x) = x? when changed to f(x) = - = (x - 2) = 3?A)B)reflected over x-axis, stretched vertically, shifted left 2 units, and shifteddown 3 unitsreflected over x-axis, compressed vertically, shifted right 2 units, and shiftedup 3 unitsreflected over y-axis, stretched vertically, shifted left 2 units, and shifteddown 3 unitsreflected over y-axis, compressed vertically, shifted right 2 units, and shiftedup 3 units09D)

Answers

Let me start by telling you that there is a typo in the actual question (given the answers they provide for selection)

I am going to tell you the transformations that have been applied to change the function:

[tex]f(x)=x^2[/tex]

into the function:

[tex]f(x)=\frac{1}{8}(x-2)^2+3[/tex]

Then, these transformations consist on:

a reflection around the x axis (due to the negative sign in front),

a horizontal shift in TWO units to the right (given by the subtraction of 2 inside the parenthesis,

then a vertical compression in 1/8 (due to the factor 1/8 outside the parenthesis

and then a vertical shift of 3 units UP due to the +3 added at the end

Then, please select answer B in the list provided

Given the following data, find the diameter that represents the 69th percentile.AnswerHow to enter your answer (opens in new window)Diameters of Golf Balls1.531.36 1.69 1.68 1.701.601.601.361.34 1.531.32 1.401.39 1.391.44

Answers

Given that there is a Table given of diameters

1) To win the small county lottery, one must correctly select 3 numbers from 30 numbers. The order in which the selection is made does not matter. How many different selections are possible?

Answers

This problem involves combination with taken n Items taken r at a time

The formula for this combination is :

[tex]nC_r=\frac{n!}{(n-r)!r!}[/tex]

Where n is the total number of items

and r is the objects taken at a time

The factorial, n! denotes n x (n-1) x (n-2) x (n-3) x ... x (1)

For example :

2! = 2 x 1 = 2

3! = 3 x 2 x 1 = 6

4! = 4 x 3 x 2 x 1 = 24

Now from the given problem :

we have n = 30 numbers

r = selection of 3

Then the formula will be :

[tex]30C_3=\frac{30!}{(30-3)!\times3!}[/tex]

Simplifying :

27 up to 1 will be cancelled from numerator and the denominator..

Evaluating the expression will be :

24360/6 = 4060

The answer is 4060

2 radical 6 minus -2 radical 24 adding and subtracting radicals

Answers

[tex]2\sqrt[]{6}-2\sqrt[]{24}t[/tex]

Substraction:

1. Find prime factors of 24

[tex]\sqrt[]{24}=\sqrt[]{2^2\cdot6}[/tex]

2. As 2 squared has a exact square root extract it from the radical:

[tex]\sqrt[]{24}=2\sqrt[]{6}[/tex]

Then, you have the next expression:

[tex]\begin{gathered} 2\sqrt[]{6}-2\sqrt[]{24}=2\sqrt[]{6}-2(2\sqrt[]{6}) \\ \\ =2\sqrt[]{6}-4\sqrt[]{6} \end{gathered}[/tex]

Substract similar terms (taking square root of 6 as a common factor):

[tex]\begin{gathered} =(2-4)\cdot\sqrt[]{6} \\ \\ =-2\sqrt[]{6} \end{gathered}[/tex]

(a) Find an angle between 0 and 2pi that is coterminal with 10pi/3.(b) Find an angle between 0° and 360° that is coterminal with -300°.Give exact values for your answers.(a) __ radians(b) __ °

Answers

To find a coterminal angle between 0 and 2pi, you can subtract 2pi from the given angle, like this

[tex]\frac{10\pi}{3}-2\pi\text{ }[/tex]

To do the subtraction, you can convert 2pi into a fraction, like this

[tex]\frac{2\pi\cdot3}{3}=\frac{6\pi}{3}[/tex]

So, you have

[tex]\frac{10\pi}{3}-2\pi=\frac{10\pi}{3}-\frac{6\pi}{3}=\frac{4\pi}{3}[/tex]

Therefore, 4pi/3 is the angle between 0 and 2pi that y is coterminal with 10pi/3.

For point (b), you can add 360° at the angle given, like this

[tex]360+(-300)=360-300=60[/tex]

Therefore, an angle between 0° and 360° that is coterminal with -300° is 60°.

solve the system by substitution type your stepsx=2y-53x-y=5

Answers

Answer:

The solution to the system of equations is

x = 3

y = 4

Explanation:

Given the pair of equations:

[tex]\begin{gathered} x=2y-5\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\text{.}(1) \\ 3x-y=5\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\text{.}(2) \end{gathered}[/tex]

To solve these simultaneously, use the expression for x in equation (1) in equation (2)

[tex]\begin{gathered} 3(2y-5)-y=5 \\ 6y-15-y=5 \\ 6y-y-15=5 \\ 5y-15=5 \\ \\ \text{Add 15 to both sides} \\ 5y-15+15=5+15 \\ 5y=20 \\ \\ \text{Divide both sides by 5} \\ \frac{5y}{5}=\frac{20}{5} \\ \\ y=4 \end{gathered}[/tex]

Using y = 4 in equation (1)

[tex]\begin{gathered} x=2(4)-5 \\ =8-5 \\ =3 \end{gathered}[/tex]

Therefore, x = 3, and y = 4

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