A) Graph the ellipse. Use graph paper or sketch neatly on regular paper. The ellipse must be hand drawn - no computer tools or graphing calculator. Give the center of the ellipse. Give the vertices of the ellipse. Give the endpoints of the minor axis. Give the foci.

A) Graph The Ellipse. Use Graph Paper Or Sketch Neatly On Regular Paper. The Ellipse Must Be Hand Drawn

Answers

Answer 1

The general equation of an ellipse is:

[tex]\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1.[/tex]

Where:

• (h, k) are the coordinates of the centre,

,

• a and b are the lengths of the legs.

The parts of the ellipse are:

In this case, we have the equation:

[tex]\frac{(x+1)^2}{5^2}+\frac{(y-4)^2}{4^2}=1.[/tex]

So we have:

• (h, k) = (-1, 4),

,

• a = 5,

,

• b = 4.

A) The graph of the ellipse is:

B) The center of the ellipse is (h, k) = (-1, 4).

C) The vertices of the ellipse are:

• (h + a, k) = (-1 + 5, 4) = ,(4, 4),,

,

• (h - a, k) = (-1 - 5, 4) =, (-6, 4),,

D) The endpoints of the minor axis are:

• (h, k + b) = (-1, 4 + 4 ) = ,(-1, 8),,

,

• (h, k - b) = (-1, 4 - 4) = ,(-1, 0),.

E) To find the focuses, we compute c:

[tex]c=\sqrt[]{a^2-b^2}=\sqrt[]{5^2-4^2}=\sqrt[]{25-16}=\sqrt[]{9}=3.[/tex]

The focuses of the ellipse are:

• (h + c, k) = (-1 + 3, 4) = ,(2, 4),,

,

• (h - c, k) = (-1 - 3, 4) = ,(-4, 4),.

Answer

A)

B) (-1, 4)

C) (4, 4), (-6, 4)

D) (-1, 8), (-1, 0)

E) (2, 4), (-4, 4)

A) Graph The Ellipse. Use Graph Paper Or Sketch Neatly On Regular Paper. The Ellipse Must Be Hand Drawn
A) Graph The Ellipse. Use Graph Paper Or Sketch Neatly On Regular Paper. The Ellipse Must Be Hand Drawn
A) Graph The Ellipse. Use Graph Paper Or Sketch Neatly On Regular Paper. The Ellipse Must Be Hand Drawn

Related Questions

At State College last term, 61 of the students in a Physics course earned As, 89 earned Bs, 119 got Cs, 79 were issued Ds, and 70 failed the course. If this grade distribution was graphed on a pie chart, how many degrees would be used to indicate the A region? Round your answer to the nearest whole degree.

Answers

The number of degrees that would be used to indicate region A is 53°

EXPLANATION

Number of students with As = 61

Number of students with Bs = 89

Number of students with Cs =119

Number of students with Ds = 79

Number of students with F = 70

To find the number degrees that would be used to indicate A region, we will use the formula below:

[tex]\text{ Region A in degre}e=\frac{Number\text{ of As}}{\text{Total number of student}}\times360^o[/tex]

Number of As = 61

Total number of students = 61 + 89 + 119 + 79 + 70 = 418

Substitute the values into the formula and evaluate.

[tex]A\text{ region in degre}e=\frac{61}{418}\times360^o[/tex][tex]=52.55885[/tex][tex]\approx53^o\text{ to the nearest degre}e[/tex]

Therefore, the number of degrees ithat would be used to indicate region A is 53°

Prescription 1: According to the eScience Lab Manual for Lab 1, Experiment 3, you need to prepare 65 mL of a 60% soda/syrup “prescription”.To do this, you can use the 80% soda solution and the syrup solution (0% strength) that you have in inventory.How many mLs of soda solution do you need to create this final solution?

Answers

Let:

x = mL of soda solution

y = mL of syrup solution

The soda solution is 80% strength and the syrup solution is 0% strength, thus the combination of x and y of each solution gives strength of:

80x + 0y

This combination must be 60% strength, thus:

80x + 0y = 60(x + y) [1]

The total amount of solution is 65 mL, thus:

x + y = 65

Substituting in [1]

80x + 0y = 60*65

Operating and simpliifying:

80x = 3900

Dividing by 80:

x = 48.75

I need 48.75 mL of soda solution

Find the slope of the line that passes thru the points (1,2) & (7,7)

Answers

Determine the slope of line passing through points (1,2) and (7,7).

[tex]\begin{gathered} m=\frac{7-2}{7-1} \\ =\frac{5}{6} \end{gathered}[/tex]

So slope of the line is 5/6.

Line L passes through point (10,−1) and line P is the graph of 5x−7y=8.
If L⊥P , what is the equation of L?

Answers

The equation of line L is  [tex]7x+5y=70[/tex].

Given,

Line L passes through point (10,-1)

Equation of line P = [tex]5x-7y=8[/tex]

Line L is perpendicular to line P

First find the slope of line P, for that convert the equation into the general form [tex]y=mx+c[/tex]

Where, m=slope

[tex]5x-7y=8\\\\5x-8=7y\\\\y=\frac{5}{7}x-\frac{8}{7}[/tex]

Comparing with general form,

[tex]m=\frac{5}{7}[/tex]

Any line perpendicular to it should have slope in the form [tex]-\frac{1}{m}[/tex]

So, the slope of line L becomes  [tex]-\frac{7}{5}[/tex]

Equation of line L can be written as [tex]y-y1=m(x-x1)[/tex]

Where, (x1,y1) is the point through which line passes and 'm' is the slope of line L

[tex]y-(-1)=-\frac{7}{5}(x-10)\\\\5(y+1)=-7x+70\\\\5y+5=-7x+70\\\\7x+5y=70[/tex]

Thus, the equation of line L is [tex]7x+5y=70[/tex]

To learn more about equation of line refer here

https://brainly.com/question/10915693

#SPJ1

Use the graph and the translation (x,y) → (x+2, y + 5) to answer parts a and b below.

Answers

Answer:

A → A' (-7, 10)

B → B' (1, 5)

C → C' ( -3, 3)

Explanations:

The translation rule is:

(x+2, y+5)

We are going to get the coordinates of the vertices A, B, and C.

We will also get the coordinates of the vertices A', B', and C' after translation.

A (-9, 5)

B (-1, 0)

C (-5, -2)

After the translation (x+2, y+5)

A' (-9+2, 5+5)

A' (-7, 10)

B' (-1+2, 0+5)

B' (1, 5)

C' (-5+2, -2+5)

C' (-3, 3)

Therefore:

A → A' (-7, 10)

B → B' (1, 5)

C → C' ( -3, 3)

Want an extra challenge? This screen is **optional**: 30° If you want more practice to really level up your Right Triangle Trig skills, see if you can solve for the missing sides of the Right Triangle pictured to the left. C a You can enter your results and check your work in the table below. 7 HINT: The side that is 7 units long is OPPOSITE the 30° angle. Length of Hypotenuse (c) Length of Other Leg (a) Did I Get Them Right?!

Answers

Answer:

c = 14

a = 7√3

Explanation:

To find the value of c, we will use the sin(30) because sin(30) is equal to the opposite side over the hypothenuse. So:

[tex]\sin (30)=\frac{7}{c}[/tex]

Additionally, sin(30) is also equal to 0.5, so we can replace this value and solve for c:

[tex]\begin{gathered} 0.5=\frac{7}{c} \\ 0.5c=7 \\ c=\frac{7}{0.5} \\ c=14 \end{gathered}[/tex]

Therefore, the length of the hypotenuse (c) is 7.

Now, we can calculate the length of the other leg using the Pythagorean theorem, where:

[tex]a=\sqrt[]{c^2-7^2}^{}[/tex]

So, replacing the value of c by 14, we get:

[tex]\begin{gathered} a=\sqrt[]{14^2-7^2} \\ a=\sqrt[]{196-49} \\ a=\sqrt[]{147} \\ a=\sqrt[]{49\cdot3} \\ a=7\sqrt[]{3} \end{gathered}[/tex]

Therefore, the length of the other leg (a) is 7√3

Gina was working in the laboratory on an experiment involving the population of bacteria. If her initial starting amount in a petri dish was 125 bacteria, how many would be in the petri dish after 24 hours?

Answers

Answer:

It would be a lot of bavgeria

Answer:

450000

Step-by-step explanation:

125×(60×60)

=125×3600

=450000

Hi I am having trouble with solving and finding the answers to this problem Find the perimeter of the figure. Use 3.14 for ππ and round to at least 1 decimal place.

Answers

Given:-

An reatacngle with a half sphere at one side.

To find:-

The perimeter of the given image.

Now we are going to find the perimeter of the half sphere. The formula to find half sphere is,

[tex]\pi r+d[/tex]

Where r is radius and d is diameter.

The radius of the sphere is 2.5 and the diameter is 5. Substituing the values we get,

[tex]\begin{gathered} \pi r+d=3.14\times2.5+5 \\ \text{ =12.85} \\ \text{ =12.9} \end{gathered}[/tex]

Now we find the perimeter of the rectangle below. we get,

[tex]5+5+5=15_{}[/tex]

Now to get the total perimeter we need to add both the values. so we get,

[tex]12.9+15=27.9[/tex]

So the required perimeter is 27.9

hi, I actually have this question not this one sorry

Answers

we know that

If V is the midpoint of SU

then

SV=VU

substitute the given values

2x+18=8x-6

solve for x

8x-2x=18+6

6x=24

x=4

Find SV

SV=2x+18

SV=2(4)+18

SV=26 units

so

VU=26 units

and

SU=2SV

SU=2(26)

SU=52 units

Name
1.
Write an expression showing the sum of 8 and a number f.
How do I write this as an expression

Answers

The sum of 8 and a number of f can be written as follow:

8 + f

I’m confused the other answer is QUANTITATIVE sorry that it’s in capital but I don’t really get it

Answers

answer is

discrete and quantitative

The electrical resistance of a wire varies directly with the length of the wire and inversely with the square of the diameter of the wire. If a wire 432 feet long and 4 millimeters in diameter has a resistance of 1.26 ohms, find the length of a wire of the same material whose resistance is ohms and whose diameter is millimeters.

Answers

Let

R ----> resistance in ohms

L ---> the length of the wire in ft

D ---> the diameter of the wire in mm

In this problem, the equation is of the form

[tex]R=K\frac{L}{D^2}[/tex]

we have

L=432 ft

D=4 mm

R=1.26 ohms

so

Find out the value of K (constant of proportionality)

substitute the given values

[tex]\begin{gathered} 1.26=K\frac{432}{4^2} \\ \\ K=\frac{1.26*16}{432} \\ \\ K=0.0467 \end{gathered}[/tex]

Part 2

The formula is

[tex]R=0.0467\frac{L}{D^2}[/tex]

For

R=1.41 ohms

D=5 mm

substitute in the formula above

[tex]\begin{gathered} 1.41=0.0467\frac{L}{5^2} \\ solve\text{ for L} \\ L=\frac{1.41*25}{0.0467} \\ L=754.8\text{ ft} \end{gathered}[/tex]The answer is 754.8 feet

x + 7y = -3 and y = 7x + 25. Are these parallel, perpendicular, or neither.

Answers

In order to know if those lines are parallel, perpendicular or neither we need to compare the slopes.

When two lines are parallel they have the same slope, when they are perpendicular their slopes are negative reciprocal, which means:

[tex]\begin{gathered} m_1=-\frac{1}{m_2} \\ \text{Then} \\ m_1\cdot m_2=-1 \end{gathered}[/tex]

Now, we need to arrange both equations into the slope-intercept form y=mx+b

Where m is the slope and b is the y-intercept.

The second line is already in slope-intercept form:

[tex]y=7x+25[/tex]

Thus, its slope is 7.

The first line in slope-intercept form is:

[tex]\begin{gathered} x+7y=-3 \\ 7y=-3-x \\ y=\frac{-3-x}{7} \\ y=\frac{-3}{7}-\frac{x}{7} \\ \text{ By reordering terms} \\ y=-\frac{x}{7}-\frac{3}{7} \end{gathered}[/tex]

Then it slope is -1/7.

Their slopes are not the same, then they aren't parallel, but let's check if they are perpendicular:

[tex]\begin{gathered} m1\cdot m2=-1 \\ -\frac{1}{7}\cdot7=-1 \\ -1=-1 \end{gathered}[/tex]

They are negative reciprocal, then they are perpendicular lines.

Solve this system of equations by graphing. First graph the equations, and then type the solution.y=x+7y= –7/3x-3

Answers

Solution

For this case we have the following system of equations:

y= x+7

y= -7/3 x -3

We can create the plot and we got:

Then the answer for this case should be:

x= -3 and y= 4

consider the line 4x+9y=-8find the equation of the line that is perpendicular to this line and passes through the point (-2, -2)find the equation of the line that is parallel of this line and passes through the point (-2, -2)

Answers

[tex]\begin{gathered} \text{The equation of the line is,} \\ 4x+9y=-8 \\ 9y=-4x-8 \\ y=-\frac{4}{9}x-\frac{8}{9} \\ \text{The slope is}\Rightarrow m=-\frac{4}{9} \\ perpendicular\text{ slope}\Rightarrow m^{\prime}=\frac{9}{4} \\ 1. \\ x_1=-2,y_1=-2 \\ So,\text{ the perpendicular equation of line is} \\ y-y_1=m^{\prime}(x-x_1) \\ y+2=\frac{9}{4}(x+2) \\ 4y+8=9x+18 \\ 4y=9x+10 \\ y=\frac{9}{4}x+\frac{5}{2}(\text{Ans)} \\ 2. \\ The\text{ parallel equation is,} \\ y-y_1=m(x-x_1) \\ y+2=-\frac{4}{9}(x+2) \\ 9y+18=-4x-8 \\ 9y=-4x-26 \\ y=-\frac{4}{9}x-\frac{26}{9}(\text{Ans)} \end{gathered}[/tex]

Suppose that 73% of the residents in a particular community speak English as their primary language.a. What is the probability that exactly seven out of eight random residents in this community will speak English as their primary language?

Answers

Explanation

The question can be solved using the probability distribution formula, which can be seen below.

[tex]P_x=nCxp^xq^{n-r}[/tex]

Part A

From the image we can see that n=8 and p=0.73 while q= 1-0.73 = 0.27

Therefore for;

[tex]\begin{gathered} P(7)=8C7(0.73)^7(0.27)^1 \\ =\frac{8!}{7!1!}\times(0.73)^7(0.27)^1 \\ =0.23862 \end{gathered}[/tex]

Answer: 0.2386

Part B

[tex]\begin{gathered} Pr(x\ge7)=Pr(7)+Pr(8)=8C7(0.73)^7(0.27)^1+8C8(0.73)^8(0.27)^0 \\ =\frac{8!}{7!1!}\times(0.73)^7(0.27)^1+\frac{8!}{8!0!}\times(0.73)^8(0.27)^0 \\ =0.23862+0.08064 \\ =0.31926 \end{gathered}[/tex]

Answer: 0.3193

Part C: Out of a random number of 40 people in the community, the expected number of people that speak English as a lnaguage will be;

[tex]\frac{73}{100}\times40=29.20[/tex]

Answer: 29.20

Cuts iy ucaly cal-VUMU Problem Sandy has a garden in her backyard. The drawing shows How many bags of fertilizer will Sandy need to cover the dimensions of her garden. A bag of fertilizer covers 3 her garden? square feet The area of the garden is feet Sandy will need garden bags of fertilizer to cover her 4 ft. 6 ft.

Answers

Determine the area of the garden by using the following formula for the area of a triangle:

A = b·h/2

where

b: base = 4 ft

h: height = 6 ft

replace the previous values of the parameters into the formula for A:

A = (4 ft)(6 ft)/2

A = 12 ft²

next, take into account that:

1 bag of fertilizer = 3 ft² of garden

then, you have:

number of bags of fertilizer = (12 ft²)/(3 ft²) = 4 bags

Answer:

Determine the area of the garden by using the following formula for the area of a triangle:

A = b·h/2

where

b: base = 4 ft

h: height = 6 ft

Replace the previous values of the parameters into the formula for A:

A = (4 ft)(6 ft)/2

A = 12 ft²

Next, take into account that:

1 bag of fertilizer = 3 ft² of garden

then, you have:

number of bags of fertilizer = (12 ft²)/(3 ft²) = 4 bags

Step-by-step explanation:

Dr. Jordan is a veterinarian. The table shows the weights of 5 kittens at her office. What is the mean weight of the kittens? Kitten Weight (ounces) Kitten 1 6 Kitten 2 11 Kitten 3 6 Kitten 4 10 Kitten5 7

Answers

Recall that the mean of a given set of values is given as

[tex]\begin{gathered} \text{Mean = }\frac{sum\text{ of all the items or values}}{total\text{ number of item or values}} \\ =\text{ }\frac{6+11+6+10+7}{5} \\ =\frac{40}{5} \\ =8 \end{gathered}[/tex]

word problem using a two-step near inequallyPablo wants to rent a boat and spend less than $47. The boat costs $6 per hour, and Pablo has a discount coupon for $7 off. What are the possible numbers ofhours Pablo could rent the boat?Use t for the number of hours.Write your answer as an inequality solved fort

Answers

Answer:

Pablo could rent the boat for less than 9 hours.

t < 9

Explanation:

Since Pablo wants to spend less than $47 to rent a boat and we're told that the boat costs $6 per hour and Pablo has a discount of $7 off, we can go ahead and represent this as an inequality as shown below using t to represent the number of hours;

[tex]6t-7<47[/tex]

To solve for t, let's add 7 to both sides;

[tex]6t<54[/tex]

Let's divide both sides by 6;

[tex]\begin{gathered} \frac{6t}{6}<\frac{54}{6} \\ t<9 \end{gathered}[/tex]

From the above, we can see that Pablo could rent the boat for less than 9 hours in order to spend less than $47.

Replace * with a digit that allows you to reduce the fraction. If there are two * in thesame fraction, replace them with the same digit. Find all possible values of * in eachfraction.6*2/1*0

Answers

There are 10 possible digits that we can replace. These are from 0 - 9.

Let's start replacing with 0 first. The fraction will be 602/100 and can be reduced to 301/50.

If we replace * with 1, the fraction will be 612/110 and be reduced to 306/55.

If we replace * with 2, the fraction will be 622/120 and be reduced to 311/60.

If we replace * with 3, the fraction will be 632/130 and be reduced to 316/65.

We can use all the digits from 0 - 9 to replace * and it will allow us to reduce the fraction because the numerator and denominator ends in 2 and 0 respectively.

From the time Ryan wakes up, he spends To hour to get ready and 1 hour to travelfrom home to school..How much time does he take to get to school from the time he wakes up?

Answers

[tex]\begin{gathered} Ryan\text{ spends }\frac{7}{10}\text{ }hour\text{ to get ready} \\ GoIng\text{ to school takes }\frac{1}{4}\text{ hour} \\ Time\text{ from waking up to getting school=}\frac{7}{10}+\frac{1}{4} \\ Time\text{ from waking up to getting school=}\frac{28+10}{40} \\ Time\text{ from waking up to getting school=}\frac{38}{40} \\ Time\text{ from waking up to getting school=}\frac{19}{20} \\ Rayn\text{ takes }\frac{19}{20}hour\text{ from waking up to getting school} \end{gathered}[/tex]

drop down menu to select the correct symbols to indicate your answer in interval notation. If a number is not an integer then round it to the nearest hundredth. To indicate positive infinifty ( \infty ) type the three letters "inf". To indicate negative infinity(-\infty ) type "-inf" with no spaces between characters.{{x|x\geq7}}AnswerAnswer,AnswerAnswer

Answers

In order to write this set in interval notation, first let's understand what the set represents.

This set includes all numbers that are greater than or equal to 7.

That is, the smaller number in the set is 7, and the greater value doesn't exist, so we can use positive infinity to represent that the set only grows.

Since number 7 is included in the set, we use square brackets, and since positive infinity is not included in the set (because it's not a number that is in the set), we use parenthesis, so the interval notation is:

[tex]\lbrack7,\text{inf)}[/tex]

A line segment, ST, has endpoints S(-7,-3) and T(-1,-1). Which of the following equations represents the perpendicular bisector of the line segment? A. y = 2x - 15 B. y = -3x - 14 C. y = 6x - 14 D. y = -3x - 20

Answers

SOLUTION

The given points are: (-7,-3) and (-1,-1)

The slope of the line segment is:

[tex]\begin{gathered} m=\frac{-1-(-3)}{-1-(-7)} \\ m=\frac{-1+3}{-1+7} \\ m=\frac{2}{6} \\ m=\frac{1}{3} \end{gathered}[/tex]

Recall that the product if solpes of perpendicular line give -1.

The the slope of the perpendicula bisector is:

[tex]\begin{gathered} m_1=\frac{1}{\frac{1}{3}} \\ m=3 \end{gathered}[/tex]

Therefore the slope of the perpendicular bisector is -3.

Recall that the perpendicular bisector passes through the center of a line segment.

Hence the perpendicular bisector will pass through:

[tex]\begin{gathered} (\frac{-7-1}{2},\frac{-3-1}{2}) \\ =(\frac{-8}{2},\frac{-4}{2}) \\ =(-4,-2) \end{gathered}[/tex]

Using the point slope form, the equation of the perpendicular bisector is:

[tex]\begin{gathered} y-(-2)=-3(x-(-4)) \\ y+2=-3x-12 \\ y=-3x-12-2 \\ y=-3x-14 \end{gathered}[/tex]

Therefore the required equation is:

[tex]y=-3x-14[/tex]

2. Lisa owns 40% of the stock in a private catering corporation.There are 1,200 shares in the entire corporation.How many shares does Lisa own?

Answers

To find the umber of shares Lisa owns we need to calculate how many shares 40 % represents from the total 1,200 shares.

[tex]\begin{gathered} \frac{40}{100}\frac{\text{ \%}}{\text{ \%}}\text{ = }\frac{x}{1200}\text{ }\frac{shares}{shares} \\ 100\cdot x=40\cdot1200 \\ x\text{ = }\frac{48000}{100}=480\text{ shares} \end{gathered}[/tex]

A larger pipe fills a water tank twice as fast as a smaller pipe. When both pipes are used, they fill the tank in 55 hours. If the larger pipe is left off, then how long would it take the smaller pipe to fill the tank?

Answers

For this exercise you need to use the Work-rate formula. This is:

[tex]\frac{t}{t_A}+\frac{t}{t_B}=1[/tex]

Where:

- "t" is the time for the objects A and B together.

- The individual time for object A is:

[tex]t_A[/tex]

- The individual time for object B is:

[tex]t_B[/tex]

In this case, you can idenfity that:

[tex]\begin{gathered} t=55 \\ t_A=2t_B \\ _{} \end{gathered}[/tex]

Substitute them into the formula:

[tex]\frac{55}{2t_B_{}_{}}+\frac{55}{t_B}=1[/tex]

Now you must solve for:

[tex]t_B[/tex]

You get that this is:

[tex]\begin{gathered} \frac{55+2(55)}{2t_B}=1 \\ \\ \frac{55+110}{2t_B}=1 \\ 165=(1)(2t_B) \\ \\ \frac{165}{2}=t_B_{} \\ \\ t_B=82.5 \end{gathered}[/tex]

The answer is: It takes the smaller pipe 82.5 hours to fill the tank.

Hi! I need help with a couple math questions but heres this oneTriangle XYZ is located at X (−2, 1), Y (−4, −3), and Z (0, −2). The triangle is then transformed using the rule (x−1, y+3) to form the image X'Y'Z'. What are the new coordinates of X', Y', and Z'?

Answers

Transformation rule:

[tex](x,y)\rightarrow(x-1,y+3)[/tex]

Given triangle XYZ

To get X'Y'Z' coordinates of vertices, subtract 1 to the x coordinate and add 3 to the y-coordinate:

[tex]\begin{gathered} X(-2,1)\rightarrow X^{\prime}(-2-1,1+3) \\ X^{\prime}(-3,4) \end{gathered}[/tex][tex]\begin{gathered} Y(-4,-3)\rightarrow Y^{\prime}(-4-1,-3+3) \\ Y^{\prime}(-5,0) \end{gathered}[/tex][tex]\begin{gathered} Z(0,-2)\rightarrow Z^{\prime}(0-1,-2+3) \\ Z^{\prime}(-1,1) \end{gathered}[/tex]Then, the coordinates of vertices in triangle X'Y'Z' are: X'(-3,4), Y'(-5,0) and Z'(-1,1)

Tom is 26 years older than Paul. the product of his ages is 560. How old is Paul?

Answers

Given data:

The given age of Tom is T=P+26.

The expression for the product of their ages is TxP=560.

Substitute (P+26) for T in the second expression.

[tex]\begin{gathered} (P+26)P=560 \\ P^2+26P-560=0 \\ P^2+40P-14P-560=0 \\ P(P+40)-14(P+40)=0 \\ (P+40)(P-14)=0 \\ P=-40,\text{ 14} \\ P=14 \end{gathered}[/tex]

Thus, the age of Paul is 14 years.

A coach gives 2 water bottles to each player on a basketball team. There are p players on the team. which expression can be used to determine the total number of water bottles that the gives the player on the team?

Answers

If there are p players and every player has 2 water bottles. The total number of water bottles is calculated as:

[tex]\text{Total}=2p[/tex]

So, the expression that can be used to determine the total number of water bottles is:

[tex]2p[/tex]

1. Lines p and q are intersected by line r, such that line p is parallel to line q. If m<1=7x - 36 and m<2 = 5x+12, what is the m<1

Answers

We are given a figure in which line r intersects two parallel lines p and q.

The angles labeled as ∠1 and ∠2 are known as same-side interior angles.

Same-side interior angles are supplementary meaning that their sum is equal to 180°.

So we can write,

[tex]\begin{gathered} \angle1+\angle2=180\degree \\ (7x-36)+(5x+12)=180\degree \end{gathered}[/tex]

Now let us solve this equation for x.

[tex]\begin{gathered} 7x+5x-36+12=180 \\ 12x-24=180 \\ 12x=180+24 \\ 12x=204 \\ x=\frac{204}{12} \\ x=17\degree \end{gathered}[/tex]

Now we can find the exact value of the angle ∠1

[tex]\angle1=7x-36=7(17)-36=119-36=83\degree[/tex]

Therefore, angle ∠1 = 83°

what digit is in the

Answers

Given x = 7, we have:

[tex]6x=6(7)=42[/tex]

Answer: 42

Other Questions
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