On a chemical reaction, we always have formulas on the left and right parts of the equation.
On the left, we have the reactants and on the right we have the products.
An acid is simply a type of chemical, so an acid can appear anywhere on a chemical reaction.
A catalyst is a chemical that participates on the reaction but it is not consumed. The reactants for instance, participate and are consumed.
Because catalyst are not consumed like reactants, thay need to go on another part of the equation so we don't confuse it with the other. Its place is on the arrow of the reaction.
Thus, the fomuala on the arrow is a catalyst.
Read this excerpt from "The World on Turtle's Back."
In the Sky-World was a man who aimed to please his pregnant wife. His wife told him that she wanted some bark from the roots of the Great Tree. Though the husband knew it was wrong, he dug up the roots of the tree for his wife. In doing so, he broke a hole in the floor of the Sky-World, and was shocked to find empty space underneath. He was terrified and told his wife what he did.
Which words in this excerpt support the idea that the husband was very devoted to his wife?
a man who aimed to please his pregnant wife
the husband knew it was wrong
he broke a hole in the floor of the Sky-World
He . . . told his wife what he did
The words in this excerpt which support the idea that the husband was very devoted to his wife is "the husband knew it was wrong".
What is an excerpt?
An excerpt is described as a short extract from a film, broadcast, or piece of music or writing.
From the excerpt above, we can conclude that the husband was devoted to his wife by digging up the roots of the tree for his wife even when he knew it was wrong to do do and so he broke a hole in the floor of the Sky-World, and was shocked to find empty space underneath.
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Please help!! 100pts and brainliest!
Rb+
Fe2+
H-
Al3+
Cl-
O2-
Using the ions above, write the formulas and give the names for 5 possible ionic compounds involving these ions.
Using the ions, the formulas and give the names for 5 possible ionic compounds involving these ions are :
1) Rubidium hydride - RbH
2) Iron(II)chloride - FeCl₂
3) Aluminum chloride - AlCl₃
4) Rubidium oxide - Rb₂O
5) Iron(II)oxide - FeO
1) Rubidium hydride - RbH
In Rubidium hydride : Rubidium forms Rb⁺ ion. hydrogen form H⁻ ion. they combined and form ionic compound. The one positive charge on rubidium neutralizes the one negative on hydrogen.
2) Iron(II)chloride - FeCl₂
In iron(II)chloride : iron form Fe⁺² and Chlorine form Cl⁻ ion. +2 charge are neutralizes by the two chlorine negative ion.
3) Aluminum chloride - AlCl₃
In this Aluminum form Al³⁺ and chlorine forms Cl⁻ and form ionic compound, Aluminum chloride.
4) Rubidium oxide - Rb₂O
In Rubidium oxide : Rubidium for Rb⁺ and oxygen form O²⁻.
5) Iron(II)oxide - FeO
In the ionic compound iron(II)oxide : Iron forms Fe²⁺ ion and oxygen forms O²⁻ ion.
Thus, Using the ions, the formulas and give the names for 5 possible ionic compounds involving these ions are :
1) Rubidium hydride - RbH
2) Iron(II)chloride - FeCl₂
3) Aluminum chloride - AlCl₃
4) Rubidium oxide - Rb₂O
5) Iron(II)oxide - FeO
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PLEASE HELP - 100 PTS AND BRAINLIEST
Provide an example of each of the following mixtures and state whether it is a homogeneous or heterogeneous mixture. Support your answers.
a) A mixture of a solid and a liquid.
b) A mixture of two gases.
c) A mixture of two liquids.
d) A mixture of two solids.
Answer (cuz i found it xD)
a) Dirt and water [mud] (Heterogenous - mud can settle down at the bottom and leaving the mixture with much less mud at the top of the container than at the bottom)
b) Smoke and fog [smog] (Heterogenous - Smog often carries around a lot of different particles other than just smoke and fog. These are not the same particles as another smog cloud a few miles over)
c) Milk and chocolate syrup [chocolate milk] (Heterogenous - The chocolate syrup can settle at the bottom leaving different amounts on both top and bottom of the mixture.)
d) Copper and Zinc [brass] (Homogenous - Brass is always copper + zinc, though the ratios can vary greatly. If it were heterogenous we would see variety in things such as color, which we don't)
Example of each of the following mixtures and state whether it is a homogeneous or heterogeneous mixture
A mixture of a solid and a liquid - Dirt and water [mud] (Heterogenous - mud can settle down at the bottom and leaving the mixture with much less mud at the top of the container than at the bottom)
A mixture of two gases - Smoke and fog [smog] (Heterogenous - Smog often carries around a lot of different particles other than just smoke and fog. These are not the same particles as another smog cloud a few miles over)
A mixture of two liquids - Milk and chocolate syrup [chocolate milk] (Heterogenous - The chocolate syrup can settle at the bottom leaving different amounts on both top and bottom of the mixture.)
A mixture of two solids - Copper and Zinc [brass] (Homogenous - Brass is always copper + zinc, though the ratios can vary greatly. If it were heterogenous we would see variety in things such as color, which we don't)
Mixture is the compound made up of two or more chemical component which are not chemically linked called as mixture
Here mixture of solid and liquid is dirt and water means water is the liquid whereas dirt is the solid and mixture of two gases are smoke and fog this two are gases that's why it is called mixture of gases and mixture of two liquid are milk and chocolate syrup because they are syrup that's why they are mixture of two liquid and mixture of two solid are copper and zinc copper is also the solid and zinc is also the solid that's why it is the mixture of two solid
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part A: A very flexible helium-filled balloon is released from the ground into the air at 20. ∘C . The initial volume of the balloon is 5.00 L , and the pressure is 760. mmHg . The balloon ascends to an altitude of 20 km , where the pressure is 76.0 mmHg and the temperature is − 50. ∘C . What is the new volume, V2 , of the balloon in liters, assuming it doesn't break or leak?part B: Consider 4.60 L of a gas at 365 mmHg and 20. ∘C . If the container is compressed to 3.00 L and the temperature is increased to 33 ∘C , what is the new pressure, P2 , inside the container? Assume no change in the amount of gas inside the cylinder.
ANSWER
The volume of the gas is V2 is 38.1 liters
EXPLANATION
Given that;
[tex]\begin{gathered} \text{ The initial temperature of the balloon is 20}\degree C \\ \text{ The initial volume of the balloon is 5.0L} \\ \text{ The initial pressure of the balloon is 760 mmHg} \\ \text{ The final temperature of the balloon is - 50}\degree C \\ \text{ The final pressure of the balloon is 76 mmHg} \end{gathered}[/tex]To find the final volume of the balloon, follow the steps below
Step 1; Write the general gas law equation
[tex]\text{ }\frac{P1\text{ }\times\text{ V1}}{T1}\text{ }=\text{ }\frac{\text{ P2}\times\text{ V2}}{T2}[/tex]Step 2; Convert the temperature to kelvin
[tex]\begin{gathered} \text{ t1 }=\text{ 20}\degree C \\ \text{ T }=\text{ t }+\text{ 273.15} \\ \text{ T }=\text{ 20 + 273.15} \\ \text{ T = 293.15K} \\ \\ t2\text{ }=\text{ -50}\degree C \\ \text{ T = -50 + 273.15} \\ \text{ T}=\text{ 223.15K} \end{gathered}[/tex]Step 3; Substitute the given that into the formula given
[tex]\begin{gathered} \text{ }\frac{760\times5}{293.15}\text{ }=\text{ }\frac{76\text{ }\times\text{ V2}}{223.15} \\ \text{ cross multiply} \\ \text{ 760 }\times\text{ 5}\times\text{ 223.15 }=\text{ 76 }\times\text{ v2}\times\text{ 293.15} \\ \text{ 847970 }=\text{ 22, 279.4 }\times\text{ v2} \\ \text{ divide both sides by 22294} \\ \text{ }\frac{8479890}{222794}=\text{ }\frac{22294\text{ V2}}{22294} \\ \text{ v2 }=\text{ 38.1 Liters} \end{gathered}[/tex]Hence, the volume of the gas is V2 is 38.1 liters
7 While grocery shopping on a Sunday afternoon, Jonas sees a pot roast that has been marked down. The pot roast has an expiration date set for Tuesday, but Jonas wants to host dinner for friends on Friday night. Which would be the BEST way for Jonas to make sure the pot roast is safely prepared? A. Cook the pot roast on Sunday and refrigerate it until Friday night. B. Buy the pot roast and keep it in the refrigerator until Friday night. C. Freeze the pot roast until he is ready to prepare it Friday night. D. Keep the pot roast in the refrigerator but cook it on Tuesday.
The best way for Jonas to make sure the pot roast is safely prepared is Freeze the pot roast until he is ready to prepare it Friday night
Pot roast is the browned meat cooked with the vegetable in a covered pot
So according to the given data while grocery shopping on a Sunday afternoon, jonas sees a pot roast that has been marked down the pot roast has an expiration date set for Tuesday, but Jonas wants to host dinner for friends on Friday night then the best way for Jonas to make sure the pot roast is safely prepared is Freeze the pot roast until he is ready to prepare it Friday night because he wants to host dinner for friends on Friday night then he bought earlier then it would be spoiled because is is a meat that's why the correct option is C bought the pot roast and freeze it until Friday night and when he want then make it
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In the reaction 2 HgO --> 2 Hg + O2, how many moles of O2 are produced when 3.4 moles of HgO are decomposed?
In order to find the number of moles of O2 in this reaction we need to set up the properly balanced equation, which the question already gave us:
2 HgO -> 2 Hg + O2
From this equation we see that the molar ratio between HgO and O2 is 2:1, which means that for every 2 moles of HgO reacting we will end up having 1 mol of O2 as product, now what if we have 3.4 moles of HgO:
2 HgO = 1 O2
3.4 HgO = x O2
x = 1.7 moles of O2
A solution containing 30 g of potassium chlorate in 100 mL of water at 70 °C isSupersaturated MagasaturadeUnsaturated Saturated
According to the given solubility diagram, the solubility of potassium chlorate in water at 70°C is 30g/100g of water.
It means that if at 70°C there are 30g of this salt, the solution is saturated.
The correct answer is the last choice, saturated.
Answer question number 11. The question is in the image.
Answer
Explanation
Ethane has a molecular formula of C₂H₆. Its structural formula is CH₃-CH₃ or
A 2.5 M solution has an initial volume of 150.0 mL. The solution is diluted to a final volume of 300.0 mL. What is the new concentration?
The final or new concentration of a solution that was diluted to 300mL is 1.25M.
How to calculate concentration?The final concentration or molarity of a solution can be calculated using the following formula;
CaVa = CbVb
Where;
Ca = initial concentrationCb = final concentrationVa = initial volumeVb = final volumeAccording to this question, 2.5 M solution has an initial volume of 150.0 mL. The solution is diluted to a final volume of 300.0 mL. The final concentration can be calculated as follows:
2.5 × 150 = Cb × 300
375 = 300Cb
Cb = 1.25M
Therefore, the 1.25M is the new concentration of the solution.
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Consider a 2190
lb automobile clocked by law‑enforcement radar at a speed of 85.5 mph (miles per hour). If the position of the car is known to within 5.0 ft at the time of the measurement, what is the uncertainty in the velocity of the car?
The uncertainty in the velocity of the car is 7.85×10⁻³¹
Velocity is the directional speed of an object n motion as an indication of its rate of change in position as observed from a particular frame of reference and as measured by a particular standard of time
Here given data is
Mass of automobiles = 2190 lb = 993.26kg
Speed of car = v = 85.5 mph = 38.2 m/s
Uncertainty in the position of car = Δx = 5 f = 1.52m
the uncertainty in the velocity of the car is determined by heinsberg uncertainty principle
ΔPΔx ≥ h/4π
mΔvΔx ≥ h/4π
Δv ≥ h/4π×mΔx
Δv ≥ 6.626×10⁻³⁴/4π× 993.26kg× 1.52m
Δv ≥ 7.85×10⁻³¹
The uncertainty in the velocity of the car is 7.85×10⁻³¹
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Convert 91 mL to µL and write the answer in scientific notation.
ANSWER
[tex]\text{ 91000}\mu L[/tex]EXPLANATION
Given that;
The volume is 91mL
Let x represent the volume in microliter
Recall, that 1mL is equivalent to 1000 microliters
[tex]\begin{gathered} \text{ 1mL }\rightarrow\text{ 1000}\mu L \\ \text{ 91mL }\rightarrow\text{ x}\mu L \\ \text{ cross multiply} \\ \text{ 1mL }\times\text{ x}\mu L\text{ = 1000}\mu L\text{ }\times\text{ 91mL} \\ \text{ isolate x} \\ \text{ x}\mu L\text{ = }\frac{1000\mu L\times91\cancel{mL}}{1\cancel{mL}} \\ \\ \text{ x }\mu L\text{ = }1000\text{ }\times\text{ 91} \\ \text{ x = 91000}\mu L \end{gathered}[/tex]Hence, the answer is 91000 microliters
what is the mass of aluminum used if o.1 moles of aluminum chloride is produced by aluminum chloride reaction?
The mass of aluminum used if 0.1 moles of aluminum chloride is produced by aluminum chloride reaction is 13.33 g.
given that :
number of moles of aluminum chloride = 0.1 moles
The balanced chemical reaction as:
2Al + 3Cl₂ -----> 2AlCl₃
2 moles of moles of AlCl₃ produced by 2 moles of Al
therefor 0.1 moles of AlCl₃ produced by 0.1 moles of Al
number of moles of Al = 0.1 mol
Mass of Al = number of moles × molar mass
= 0.1 × 133.34 g/ mol
= 13.33 g
Thus, The mass of aluminum used if 0.1 moles of aluminum chloride is produced by aluminum chloride reaction is 13.33 g.
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Study the phase diagram of a saltwater solution compared to pure water.
Answer
The solute is more volatile when compared to the solvent.
Explanation
From the diagram, the solute is more volatile when compared to the solvent. This is because a volatile solute (i.e., a solute that has a vapor pressure of its own) will contribute to the vapor pressure above a solution in which it is dissolved.
Hence, the correct option is: The solute is more volatile when compared to the solvent.
I need to balance the equation __kciO3➡️__kcio4+__ KCIAnd How many moles of potassium chloride are produced from 3.90 moles of potassium chlorate ?
Explanation:
To balance the equation, we need to have the same number of atoms of each element on both sides of the equation.
So in this case:
4KCIO3 → 3KCIO4 + KCI
where:
reactants:
K - 4
Cl - 4
O - 12
Products:
K - 4
Cl - 4
O - 12
Potassium chloride is KCl and potassium chlorate is KClO3. The balanced reaction equation tells us that:
4 mol of KClO3 produces 1 mol of KCl, we know it because of the equation:
4 KCIO3 → 3 KCIO4 + 1 KCI
So we can do a rule of 3 to find out the quantity in moles produced when we have 3.90 moles of KClO3:
4 mol KClO3 --- 1 mol KCl
3.9 moles KClO3 --- x
4x = 1*3.9
x = 3.9/4
x = 0.975 moles
Answer: 4 KCIO3 → 3 KCIO4 + KCI and 0.975 moles.
5. You have 2 Liters of a 5 M Solution of H3PO4. How many grams are present?
Answer
979.94 grams
Explanation
Given:
Volume of solution = 2 L
Molarity = 5 M
What to find:
The mass in grams of H3PO4 present in the solution.
Step-by-step solution:
The first step is to calculate the moles of H3PO4 present using the molarity formula below:
[tex]\begin{gathered} Molarity=\frac{Moles}{Volume\text{ }in\text{ }L} \\ \\ \Rightarrow Moles=Molarity\times Volume\text{ }in\text{ }L \end{gathered}[/tex]Put the values of the given parameters into the formula to get the moles:
[tex]Moles=5M\times2L=10\text{ }mol[/tex]The moles of H3PO4 present in the solution = 10 mol.
Therefore, the mass present can be determined using the mole formula:
[tex]\begin{gathered} Moles=\frac{Mass\text{ }in\text{ }grams}{Molar\text{ }mass} \\ \\ \Rightarrow Mass\text{ }in\text{ }grams=Moles\times Molar\text{ }mass \end{gathered}[/tex]From the periodic table, the molar mass of H3PO4 can be known as 97.994 g/mol.
So putting moles = 10 mol and molar mass = 97.994 g/mol, then the mass is:
[tex]Mass=10\text{ }mol\times97.994\text{ }g\text{/}mol=979.94\text{ }grams[/tex]Therefore, the mass in grams of H3PO4 present in the solution = 979.94 grams.
In a compound that contains monatomic ions, which of the following gets named first?the nonmetalthe metalthe anionthe roman numeral of the valence number
If we given a compound such as K₂SO₄, this compound would be named as such that the metal comes first, followed by the anion or non-metal and lastly roman numeral of the valence number.
So in naming this compound, we would go as
Potassium tetraoxosulphate (VI)
Where potassium is the metal, tetraoxosulphate is the anion and lastly the roman number of the valence electron.
Another example would would be MgCl₂
The name of this compound is magnesium chloride.
In this compound, the metal is named first as well, followed by the non-metal. The roman numeral of the valence electron is not written here because the value is 1 and we don't need to write it.
Another example of the above is CaBr
This compound is calcium bromide
The metal is named first and then the non-metal. The roman numeral of the valence number is not written becaue it is also 1.
Lastly example would be NaNO₃
This compound is named as sodium trioxonitrite(v)
The metal is also named first, followed by the anion and lastly the roman numeral of the valence number.
From the explanation above, the answer to this question is The Metal
Name of element or compoundFormula of element or compound CoCarbon Iron Au KCl CS2Silicon
Answer:
• Formula: ,Co,, Name: ,Cobalt,.
,• Formula: ,C,, Name: ,Carbon,.
,• Formula: ,Fe,, Name:, Iron,.
,• Formula: ,Au,, Name: ,Gold,.
,• Formula: ,KCl,, Name: ,Potassium chloride,.
,• Formula: ,CS2,, Name: ,Carbon disulfide,.
,• Formula: ,Si,, Name: ,Silicon,.
Explanation:
• Co is an element.
,• Carbon is an element.
,• Iron is an element.
,• Au is an element.
,• KCl is a compound with K and Cl. The name has the positive part first (Potassium) and the second part has the name of the negative part (chloride).
,• CS2 is a compound with C and 2 S. The name has the number of each element, carbon is 1 so it is just Carbon, and there are 2 sulfurs (disulfide).
,• Silicon is an element.
What technique can be applied in the study of the
universe and the composition of space?
A. analytical
B. mathematical
C. astrological
D. spectrophotometer
3Ca + 2AICI3 —> 3CaCI2 + 2AIIf you react 100, grams of aluminum chloride, AICI3, with excess calcium, how many grams of calcium chloride,CaCI2, are produced ?
Firstly, we need to convert the 100 g of AlCl₃ to number of moles, using:
[tex]M_{AlCl_3}=\frac{m_{AlCl_3}}{n_{AlCl_{3}}}[/tex]The molar weight of AlCl₃ is calculating consulting the atomic weights:
[tex]\begin{gathered} M_{AlCl_3}=1\cdot M_{Al}+3\cdot M_{Cl} \\ M_{AlCl_3}=(1\cdot26.982+3\cdot35.453)g/mol \\ M_{AlCl_3}=(26.982+106.359)g/mol \\ M_{AlCl_3}=133.341g/mol \end{gathered}[/tex]Thus:
[tex]\begin{gathered} M_{AlCl_3}=\frac{m_{AlCl_3}}{n_{AlCl_3}} \\ n_{AlCl_3}=\frac{m_{AlCl_3}}{M_{AlCl_3}}=\frac{100g}{133.341g/mol}=0.749957\ldots mol \end{gathered}[/tex]For each 2 moles of AlCl₃, we produce 3 moles of CaCl₂. So:
2 mol AlCl₃ --- 3 mol CaCl₂
0.749957... mol AlCl₃ --- x
[tex]\begin{gathered} \frac{2}{0.749957\ldots mol}=\frac{3}{x} \\ 2x=2.24987\ldots mol \\ x=1.12494\ldots mol \end{gathered}[/tex]Now, we convert back to grams, but now we need the molar weight of CaCl₂:
[tex]\begin{gathered} M_{CaCl_2}=1\cdot M_{Ca}+2\cdot M_{Cl} \\ M_{CaCl_2}=(1\cdot40.078+2\cdot35.453)g/mol \\ M_{CaCl_2}=(40.078+70.906)g/mol \\ M_{CaCl_2}=110.984g/mol \end{gathered}[/tex]Thus:
[tex]\begin{gathered} M_{CaCl_{2}}=\frac{m_{CaCl_2}}{n_{CaCl_{2}}} \\ m_{CaCl_2}=M_{CaCl_2}\cdot n_{CaCl_2}=110.984g/mol\cdot1.12494\ldots mol=124.850\ldots g\approx125g \end{gathered}[/tex]So, 100 g of AlCl₃ will produce approximately 125 g of CaCl₂.
The reaction mixture, at a certain temperature, contained concentrations of0.31 M of NH3, 0.85 M of N2 and 0.031 M of H2 when it reached equilibrium.Calculate Keq at this temperature.
ANSWER
Keq is 3798.42 or 3.798 x 10^3
EXPLANATION
Given that;
The concentration of NH3 is 0.31M
The concentration of N2 is 0.85M
The concentration of H2 is 0.031M
Follow the steps below to find the chemical equilibrium constant of the reaction
Step 1; Write the balanced equation of the reaction
[tex]\text{ N}_{2(g)}\text{ + 3H}_{2(g)}\text{ }\rightleftarrows\text{ 2NH}_{3(g)}[/tex]Step 2; Write the chemical equilibrium constant for the reaction
[tex]\begin{gathered} \text{ K}_{eq}\text{ = }\frac{K_f}{\text{ K}_b} \\ \text{ Where} \\ \text{ K}_f\text{ = }\lbrack NH_3\rbrack^2 \\ \text{ K}_b\text{ = }\lbrack N_2\rbrack\text{ }\lbrack H_2\rbrack^3 \end{gathered}[/tex]Step 3; Substitute the kf and kb into the formula above
[tex]\text{ K}_{eq}\text{ = }\frac{\lbrack NH_3\rbrack^2}{\lbrack H_2\rbrack^3\times\lbrack N_2\rbrack}[/tex]Recall, that
[NH3] = 0.31M
[H2] = 0.031M
[N2] = 0.85M
[tex]\begin{gathered} \text{ K}_{eq}\text{ = }\frac{(0.31)^2}{(0.85)\times\text{ \lparen0.031\rparen}^3} \\ \\ \text{ K}_{eq}\text{ = }\frac{\text{ 0.0961}}{0.85\text{ }\times\text{ 0.0000298}} \\ \\ \text{ K}_{eq}\text{ = }\frac{\text{ 0.0961}}{0.0000253} \\ \\ \text{ K}_{eq}\text{ = 3798.42 or 3.798 }\times\text{ 10}^3 \end{gathered}[/tex]Therefore, Keq is 3798.42 or 3.798 x 10^3
REACTION; C5H12 + 8O2 5CO2 + 6H2OWhen 35.5 L of C5H12 are consumed in this reaction what volume of CO2 can be produced in liters?
Using the STP (standard temperature and pressure), we can solve this problem. First, let's find the number of moles produce by 35.5 L of C5H12.
Remember that the standard temperature is 0 °C which is the same that 273 K (kelvin) and for pressure is 1 atm and the constant of ideal gas is 0.082 atm*L/(mol*K)
Let's use the formula of an ideal gas to find the number of moles:
[tex]\begin{gathered} PV=\text{nRT,} \\ n=\frac{PV}{RT}, \\ n=\frac{\text{1 atm }\cdot35.5\text{ L}}{0.082\frac{atm\cdot L}{mol\cdot K}\cdot273K}, \\ n(C_5H_{12})=1.58\text{6 moles} \end{gathered}[/tex]Now, using this number of moles, we can find the number of moles produce for CO2 and we can find its volume.
You can see that in the reaction 1 mol of C5H12 produces 5 moles of CO2, so the calculation to find the number of moles of CO2, would be:
[tex]1.586molC_5H_{12}\cdot\frac{5molCO_2}{1molC_5H_{12}_{}}=7.93molCO_2.[/tex]The next and final step is clear V (volume) from the initial formula and replaces the value of moles for CO2, like this:
[tex]\begin{gathered} V=\frac{nRT}{P}, \\ V=\frac{7.93\text{ mol}\cdot0.082\frac{atm\cdot L}{mol\cdot K}\cdot273K}{1\text{ atm}}, \\ V(CO_2)=177.52\text{ L.} \end{gathered}[/tex]So, 25,5 L of C5H12 will produce 177.52L of CO2.
Thoroughly compare the way energy is produced in a fission nuclear power plant versus how energy is produced by fusion in stars (such as our sun). Make sure to include similarities and differences between fission and fusion.
Answer
Nuclear fusion and nuclear fission are different types of reactions that release energy due to the presence of high-powered atomic bonds between particles found within a nucleus.
In fission, an atom is split into two or more smaller, lighter atoms. Fusion, in contrast, occurs when two or more smaller atoms fuse together, creating a larger, heavier atom.
Fission reaction does not normally occur in nature.But fusion occurs in stars, such as the sun.
Fission produces many highly radioactive particles.Few radioactive particles are produced by the fusion reaction, but if a fission "trigger" is used, radioactive particles will result from that.
A critical mass of the substance and high-speed neutrons are required in fission. In contrast, a high density, high-temperature environment is required in a fusion reaction.
In a fission reaction, it takes little energy to split two atoms. Extremely high energy is required to bring two or more protons close enough that nuclear forces overcome their electrostatic repulsion in a fusion reaction.
In terms of released energy, the energy released by fission is a million times greater than that released in chemical reactions; but lower than the energy released by nuclear fusion. On the other hand, the energy released by fusion is three to four times greater than the energy released by fission.
One class of nuclear weapons is a fission bomb, also known as an atomic bomb or atom bomb. One class of nuclear weapons is the hydrogen bomb, which uses a fission reaction to "trigger" a fusion reaction.
In terms of energy production, fission is used in nuclear power plants.While fusion is an experimental technology for producing power.
Finally, Uranium is the primary fuel used in nuclear power plants.Hydrogen isotopes (Deuterium and Tritium) are the primary fuel used in experimental fusion power plants.
The minimum amount of energy needed for a reaction to take place is called the _____________.A. primer energyB. induction thresholdC. reaction thresholdD. activation energy
In a chemical reaction, there is a lot of energy involved, both being added for the reaction to occur and also being released, but for a reaction to take place, we need the so-called Activation Energy, which is the minimum amount of energy required for the compounds to react. Letter D is correct
How many moles are in 28.87 grams of Ec3H305?Ec has a molar mass of 31.79 grams/molè.(Hint: You need to determine the molar mass of Ec3H305 to solve this problem).
We have the compound Ec3H3O5. I assume that the compound Ec is an unknown compound, but we are given the molar mass of the compound Ec.
The molar mass of the molecule will be equal to the sum of the masses of each element multiplied by the number of times that it is repeated in the molecule, to make it clearer we can make the following table:
The molar mass of the molecule will be equal to 146.39g/mol, therefore the moles in 28.87 grams will be:
[tex]\begin{gathered} \text{Mol }_{}Ec_3H_3O_5=GivengEc_3H_3O_5\times\frac{1molEc_3H_3O_5}{MolarMass,gEc_3H_3O_5} \\ \text{Mol}Ec_3H_3O_5=28.87gEc_3H_3O_5\times\frac{1molEc_3H_3O_5}{146.39gEc_3H_3O_5}=0.20molEc_3H_3O_5 \end{gathered}[/tex]In 28.87g of Ec3H3O5 there are 0.20molEc3H3O5
We know that 50.5 grams of sucrose is equal to 0.148 moles of sucrose, we need to use this information to find the molarity (the unit of measuring concentration). We can calculate the molarity (M) or concentration of a solution in moles / L if we know the volume of the solution in liters (L).Let’s say you mixed your 0.148 moles of sucrose into 0.0012 L of solution.What is the molarity of this solution?
123.33mol/L
Explanations:
The formula for calculating the molarity of a solution is expressed as:
[tex]\begin{gathered} \text{Molarity}=\frac{moles\text{ of solute}}{litres\text{ of solution}} \\ \end{gathered}[/tex]Given the following parameters
• Moles, of sucrose (solute) = 0.148 moles
• Litres ,of solution = 0.0012L
Substitute the given parameters into the formula;
[tex]\begin{gathered} \text{Molarity}=\frac{0.148\text{moles}}{0.0012L} \\ \text{Molarity}=123.33\text{mol/L} \end{gathered}[/tex]Therefore the molarity of this solution is 123.33mol/L.
AcellusPerform the following operationand express the answer inscientific notation.7.15x103 x 6.10x10-5[ ? ]x10!??Coefficient (green)Exponent (yellow)Enter
ANSWER
[tex]4.3615\cdot10^{-1}[/tex]STEP-BY-STEP EXPLANATION:
You are given the below expression from the question provided
[tex]7.15\cdot10^3\text{ x 6.10 }\cdot10^{-5}[/tex][tex]\begin{gathered} (7.15\text{ x 6.10) }\cdot10^{3\text{ + (-5)}}\text{ } \\ (43.615)\cdot10^{3-\text{ 5}} \\ 43.615\cdot10^{-2} \\ 4.3615\cdot10^{1\text{ -2}} \\ 4.3615\cdot10^{-1} \end{gathered}[/tex]mno2+4hcl=cl2+mncl2+2h2o if you were given 145 g of HCl how many grams of MnCl2 Could you Theoretically produce if you reacted with the excess MnO2
The first step is to use the molecular weight of HCl to convert 145g to moles of HCl (mw=36.458g/mol):
[tex]145g\cdot\frac{mol}{36.458g}=3.97mol[/tex]Now, use the ratio of the coefficients of MnCl2 to HCl, to find how many moles of MnCl2 are produced with this amount of HCl:
[tex]3.97molHCl\cdot\frac{1molMnCl_2}{4molHCl}=0.9925molMnCl_2[/tex]Use the molecular weight of MnCl2 to convert the amount of moles produced to grams:
[tex]0.9925molMnCl_2\cdot\frac{125.844g}{molMnCl_2}=124.9g[/tex]124.9g of MnCl2 are produced.
A homogeneous mixture consist ofGroup of answer choicesa solutea solventneitherboth
Explanation:
Mixtures can be homogeneous or heterogeneous.
Homogeneous mixtures have a distinct phase. Heterogeneous mixtures have two or more distinct phases.
A solution is a homogeneous mixture between two or more substances. The process used to obtain this mixture is called dissolution.
A solution is always formed by the solute and the solvent.
Answer: both
For each of the following solutions, calculate the specified value.Calculate the number of grams of 3.9 % (m/m) NaCl solution that contains 7.20 g of NaCl .Express your answer to two significant figures and include the appropriate units.
Step 1
It is known that a value of "x" % (m/m) means:
"x" grams in 100 grams of solution
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Step 2
Information provided:
3.9 % (m/m) of NaCl solution
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Step 3
Procedure:
According to step 1, it is known that:
3.9 % (m/m) => 3.9 g NaCl in 100 g
--
Now,
3.9 g NaCl ------------ 100 g of solution
7.20 NaCl ------------- X
X = 7.20 NaCl x 100 g of solution/3.9 g NaCl
X = 184.61 g = 180 g approx.
Answer: 180 g of solution
The atomic mass of copper (Cu) is 63 546 amu, the atomic mass of sulfur (S) is 32.065, and the atomic mass of oxygen (O) is 15.999 amu. Which molar mass is correct for copper sulfate (CuSO4)? (1 point) O 446.440 g/mol O 225.802 g/mol O 159.607 g/mol O 111.610 g/mol
The molar mass for copper sulfate (CuSO₄), given that the atomic mass of sulfur (S) is 32.065, and the atomic mass of oxygen (O) is 15.999 amu, is 159.607 g/mol
How do I determine the molar mass of CuSO₄?The molar mass of a compound is the sum of the individual atomic masses of the various elements that makes up the compound.
With the above information, we can obtain the molar mass for copper sulfate (CuSO₄) as follow:
Atomic mass of Copper (Cu) = 63.546 amuAtomic mass of sulfur (S) = 32.065 amuAtomic mass of oxygen (O) = 15.999 amuMolar mass of copper sulfate (CuSO₄) =?Molar mass of CuSO₄ = 63.546 + 32.065 + (4 × 15.999)
Molar mass of CuSO₄ = 63.546 + 32.065 + 63.996
Molar mass of CuSO₄ = 159.607 g/mol
Thus, we can conclude that the molar mass for copper sulfate (CuSO₄) is 159.607 g/mol
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Answer: 159.607 g/mol
Explanation: