a fisherman stands at the back of a perfectly symmetrical boat of length l. the boat is at rest in the middle of a perfectly still and peaceful lake, and the fisherman has a mass 1 /4 that of the boat. if the fisherman walks to the front of the boat, by how much is the boat displaced?

Here the missing component is company group.

Energy is the ability to do the work . scientist defines energy as the ability to do work.

We have to have a sample of people representative of the population to compare the experiment results on, because there may be other factors in the general population, in this case, improving memory, that they are saying is because of the energy drink. For example, if all of the population in the random sampling were having improved memory due to something else, then the experiment wouldn't be valid.

These groups of people are used to measure how the deviation from the improvement of memory, in this case, to an average of the population.

These are called control groups.

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When the train approaches you, the Doppler's effect gives the frequency  240.12 Hz

When the train moves away from you, the Doppler's effect gives the frequency  199.6 Hz

Given that,

Frequency of train horn, f = 218 Hz

Speed of train, Vt = 31.7 m/s

The speed of the sound , V = 344 m/s

When the train approaches you, the Doppler's effect gives the frequency as follows :

[tex]f^{'} = f (V/ V-V_{0} )[/tex]

[tex]f^{'}[/tex] = 218 * ( 344/ 344 - 31.7)

   = 240.12 Hz

When the train moves away from you, the Doppler's effect gives the frequency as follows :

[tex]f^{'} = f ( V / V+ Vt)[/tex]

   = 218 * ( 344/ 344 + 31.7)

   = 199.6 Hz

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Work done is calculated as the scalar product of force and displacement along the force's direction, so it should be zero because there is no net force acting on the object (hence the constant velocity). Thus, W is equal to 0.

Newton's first law of motion states that any object moving at a constant speed experiences no net external forces, so the total amount of forces acting on the object must be zero. The mathematical expression for an object being under no net external force is Fnet=0 or F=0.

Acceleration equals zero when velocity stays the same. Therefore, an object moving at a constant speed does not require any force.

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The band gap energy in kilojoules per mole is 1.73×105 J.

The band gap is the distance between the valence band and the conduction band of an electron. Essentially, the bandgap represents the minimum energy required to excite an electron to a state in the conduction band where it can participate in conduction. Higher frequencies and lower wavelengths of light are absorbed.

In physics, especially for solids, the band gap is also called the energy gap. It is the range of energies that exist in solids where no other electronic state can exist. In the diagram of the electronic band structure of solids, the band gap is commonly called the energy difference.

Therefore, the band gap energy of wavelength 675 nm is 1.73×105 J.

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A high or low tide that is more extreme than usual is a(n) tide, it is stronger than usual tide.

The moon is the primary cause of high and low tides. The tidal force is produced by the moon's gravitational pull. Earth and its water protrude outward on both the side that is closest to and farthest from the moon as a result of the tidal force. These watery peaks are high tides.

Your part of the Earth spins around both of these bulges every day. You encounter a high tide while you're inside one of the bulges. The tide is low when you are not in one of the bulges. On the majority of the world's coastlines, this cycle of two high tides and two low tides occurs every day.

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The image height of the given converging lens is  6.67 cm.  

The focal length of an optical gadget is a degree of the way strongly the gadget converges or diverges light; it's miles the inverse of the gadget's optical energy. A effective focal length suggests that a system converges light, while a poor focal period shows that the gadget diverges mild.

The focal length is half of the radius of curvature and is as f=R2 f = R 2 , where f is the focal period, and R is the radius of curvature.

Calculation:-

object height  = 20 cm

object distance = 1m = 100 cm

focal length = 1.5 m = 150 cm

image height = ?

height of image/height of object = f/ f - U

20/H = 150 / 150 - 100

20/H = 150/50

20/H = 3

H = 20/3

Height of object is = 6.67 cm.

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The pulse rate on a light straight string is V sqrt when a weight W is suspended from it (2V)

The correct answer is D

A distance's rate of change over time is used to calculate speed. It has a dimension of distance via time. The Vernier scales of speed is made up of the fundamental units of distance and time. The unit of speed in the metric system is meters per second.

What is considered speed? the rate at which an object's location changes in any direction. Speed is defined as the relationship between length and the time required to travel a distance. Speed is a scalar number because it has no magnitude and only a direction.

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Dilation doesn't always change the vertices.

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6.25 s does the car come to a stop and 78.125 m distance travelled before stopping.

Solution:

Given:

Initial velocity, v0 = 25 m/s

Acceleration, a = -4m/s2

Final velocity, vf = 0

Put these values in the formula,

To find time,

vf = v0 + a*t

0 = 25 - 4t

t = 25/4

t = 6.25 s

To find distance travelled,

d = ((vf + v0)/2)*t

d = 25/2 * 6.25

d = 12.5 * 6.25

d = 78.125 m

Hence,  6.25 s does the car come to a stop and 78.125 m distance travelled before stopping.

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On the starting blocks, sprinters use their feet to push backward. The blocks respond by pressing forward with a force equal to this with their feet.

Vertical forces must be larger than the pull of gravity in order to assist the sprinter in moving forward as gravity is pushing him or her downward. The propulsive force is the force that propelled the runner forward.

An interaction diagram and a free-body diagram should be included in your explanation. The player pushes down on the ground, which pushes up against him in return. As a result of his push being stronger than gravity, the player accelerates upward.

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The pendulum's new time period is T.

A bob suspended at the end of a thread that is so light as to be regarded massless makes up a simple pendulum. It serves as an example of a conservative oscillatory system. A point mass m anchored to one end of a massless rod of length L makes up this idealized representation of a pendulum.

The time period of a simple pendulum is calculated by the formula, [tex]T=2\pi\sqrt{\frac{L}{g}}[/tex] where T is the time period, L is the length of the pendulum, and g is the acceleration due to gravity. Since this formula is independent of mass, the change in the mass of the bob doesn't affect the time period. Therefore, the new time period will still be T. There is no change.

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Have a look towads questions in this question we have the the velocity of firts marble that is moving straight and it  collides elastic collision we need to find the velocty of second marbel.

In this question we apply momentum conservation.

What is elastic collision?

-- An elastic collision is an (collision) between two bodies in which the total kinetic energy of the two bodies remains the same.

What is momentum conservation?

--The conservation of momentum states that, the amount of momentum remains constant;

--Momentum is neither created nor destroyed, but only changed through the action of forces as described by Newton's laws of motion.

So we apply M1v1 = M2V2

M1= 0.1kg

V1= 1m/s

M2= 0.05kg

0.1 × 1 = 0.05 × V2

= from above calculation we have V2 = 2m/s

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Answer:

the mass of the car is very big

Explanation:

its heavy

M = 2.99 kg≅ 3kg under goes fusion

Given,

P = 1000 M W = 1 x 10^9 J/s

efficiency = 33% ; E' = 208 MeV = 3.33 x 10^-11 J

Energy released in a day

E(day) = P x t

E(day) = 10^9 x 24 hrs x 60 min x 60 sec = 8.46 x 10^13 J

energy released in fission would be:

E(fission) = E(day)/0.33 = 8.46 x 10^13/0.28 = 2.56 x 10^14 J

We have Energy released per fission(E'), so the number of fission to release E(fission) would be:

N = E(fission)/E'

N = 2.56 x 10^14/3.33 x 10^-11 = 7.68 x 10^24

Number of moles = N/Avogadro's No

n = 7.68 x 10^24/6.023 x 10^23 = 12.75 moles

Mass of required 235U92 will be:

M = n x 235 g = 12.75 x 235 = 2996.25 grams = 2.99 kg≅ 3 kg

Hence, M = 2.99 kg≅ 3kg

Fission:

Nuclear fission is a response in which the nucleus of an atom splits into two or more smaller nuclei. The fission method frequently produces gamma photons, and releases a completely massive amount of power even through the lively requirements of radioactive decay.

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The wavelength for an electron moving at 3.00x103 m/s is 244 nm

Given, Mass of electron = 9.1093 * [tex]10^{-31}[/tex]

velocity = 3.00 * [tex]10^{3}[/tex] m/s

wavelength λ = h / mv

λ = 6.626 * [tex]10^{-34}[/tex] / [tex]9.1093 * 10^{-31}[/tex] * [tex]3.00 * 10^{3}[/tex]

λ = 244 nm

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Infrared Radiation lies on third place of electromagnetic spectrum in the increasing order of frequency.

In his experiments to measure temperature differences between colors in the visible spectrum, he placed a thermometer in the path of light within each color in the visible spectrum. He noticed that the temperature rose from blue to red, and found that just beyond the red end of the visible spectrum showed even higher temperatures. Within the electromagnetic spectrum, infrared waves occur at frequencies higher than those of microwaves and slightly lower than those of red visible light, hence the name "infrared".

Infrared radiation is an integral part of the electromagnetic spectrum.

It has wavelength of 700nm and has good application for earth sciences.

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The momentum of the moving car is 30000 kg m/s.

The momentum of a moving body is calculated as the product of mass and velocity. It is a vector quantity. In simple terms, it is the strength or force gained by a moving object.

Newton's second law is related to momentum. According to newton's second law, " The time rate of change of momentum is equal to force".

We have the formula for finding the momentum,

Momentum = Mass× Velocity

P = M × V

Put the value in the formula,

P = 1200 × 25 kg m/s

= 30000 kg m/s

So, the car is moving with a momentum of 30000 kg m/s.

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By utilizing the idea of parallax, we can decide how cosmologists decide distances to stars.

Presently, we perceive how parallax estimations can be utilized to decide the distances, one of the realities we know is that if we have any desire to gauge the distance of divine bodies, we are familiar with the parallax, first and foremost, point. That's what it intends assuming we can quantify tiny parallax points, we can gauge enormous distances moreover.

The purpose for why we can not make precise estimations of parallax past a specific distance is that as the distance of the star from earth builds the parallax point turns out to be tiny.

Subsequently, presently we comprehend how parallax estimations are utilized.

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The answer is true: a fault's frictional resistance is higher when it is locked than when it is moving.

Friction refers to the force that prevents two hard surfaces from rolling or sliding over each other. Although friction force, such as the traction required to walking avoid slipping, may be advantageous, they can provide a significant amount of resistance to motion.

The adhesion forces between the contact zones of a surface, which are constantly microscopic examination uneven, appear to be the main contributor to metal friction. The shearing of these "bonded" joints and the movement of the rougher surface's imperfections scrubbing against the softer surface cause friction.

When an object slide over a surface, as no surface is 100% smooth there are some microscopic irregularities are there on the surfaces of both object as well as the surface so when the sliding takes place on the surface the irregularities get interlocked and that causes friction between surfaces.

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Internal energy of equipartition energy is due to kinetic energy of molecules.

There are now two possible cases:

1) Expansion occurs at the expense of the gas's internal energy, so the gas temperature decreases as it expands. Therefore U decreases.

2) As the temperature decreases, so does the velocity of the gas molecules and the K of the gas decreases continuously.

This concept often takes into account what considers heat as internal energy. Molecular kinetic energy, vibrations, rotations, electron "shell" positions, molecular bending, crystal lattice vibrations, etc.

Generally, pressure should be considered part of the internal energy. Theoretically, matter can be expanded or heat can be transferred to do work.

At absolute zero temperature and pressure we can see that there is still internal energy. This can be seen as a result of the blurring principle. Particles cannot be confined to too small a volume and velocity.

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The change in internal energy when heat is released is 14000J.

W=12000J

Q=2000J

Q=U+W

U=Q-W

U=14000J or 14kJ

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The benefit of employing two-sided printing that was highlighted in class as being the most important is that it only requires one sheet of paper as opposed to two when printing a two-sided document.

Printing :

Standard 2-sided printing can be used to print on both sides of a sheet. You can choose between manual and automatic printing. When printing by hand, even-numbered pages are printed first. After printing these pages, you may simply reload them to print the odd-numbered pages on the opposite side of the paper. Therefore, double-sided printing can save your business about half as much money as single-sided printing, according to certain important estimates. Due to the fact that duplex printing uses only half as much paper as one-sided printing, businesses can reduce their material costs.

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After 1 second, the bullet will be 100 m to the side and 5m downrange.

v = 100m/s

θ = 0°

g=—10 m/s^2

the x component is

x = vcos(θ)t

The y component is

y = vsin(θ)t+1/2gt^2

In 1 second, the distance traveled by the bullet is

x = 100cos(0°)⋅1

=100m

the bullet be 1 second later at the y components

y = 100sin(0°)⋅1+1/2(—10)⋅(1)^2

=0—5

=—5m

So after 1 second, the bullet will be 100 m to the side and 5m downrange.

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A body travels at an initial speed of 1.5 m/s. given a constant acceleration of 0.2 m/s², 6.5 m/sec is the speed of the body at time 25 seconds later.

The word "kinematic" comes from A.M. Ampère's "cinematique," which he created from the Greek "v" kinema ("movement, motion"), which was derived from "kinein" ("to move").

A collection of equations known as the kinematic equations is used to describe how an item moves while its acceleration is constant. Integrals, derivatives, and rates of change must all be understood in order to solve kinematics problems.

The formula v = u + at, where u is the starting velocity and an is the acceleration, is used to calculate the velocity of a particle travelling at a constant speed.

Use the kinematic equation:

v = u + at

or, v = 1.5 + [(0.2)×(25)]

or, v = 6.5 m/s

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The drift velocity of electron is 4.54 * 10⁻⁴ m/s.

Given that, Density of copper is 8.8* 10³ kg/m³

Charge of an electron is 1.6* 10⁻¹⁹ C

For the density of copper, the number of free electrons n can be calculated by

n = number of electrons per kg * ρ

⇒ (9.4776* 10²⁴ ) (8.8 * 10³ kg/ 1 m³) = 8.314 * 10²⁸ electrons per m³

Diameter of the wire is given as 2.053 mm

Let us calculate A for the provided diameter of wire

A = π * (d/2)² = π * (2.053 /2)² = 3.310* 10⁻⁶ m²

Given, I = 20 A

We know the expression for drift velocity as

Vd = I /(n* A* e) = 20 / (8.314 * 10²⁸ * 3.310* 10⁻⁶ * 1.6* 10⁻¹⁹) = 20 / (4.403 * 10⁴) = 4.54 * 10⁻⁴ m/s

Thus, the drift velocity of electron is 4.54 * 10⁻⁴ m/s.

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The height the block reachs when launched by the spring 0.917 m.

Simply said, a spring-mass system is a spring system with a block hanging or fastened to the free end of the spring. The period of any item moving in a simple harmonic motion may often be determined using the spring-mass system. There are several other uses for the spring-mass system. For instance, the spring-mass system may be used to replicate foot skin deformation and the action of human tendons using computer images. There are two ways to arrange spring mass systems. These consist of: The parallel arrangement of springs , a series of springs combined.

m = 0.5 kg , K = 100 N/m , ∆x = 0.3 m

By conservation of energy :-

KEi + PEg + PEelastic = KEf + PEg + PEelastic

0 + 0 + 0.5*K*∆x^2 = 0 + mgh + 0

0.5*100*(0.3)^2 = 0.5*9.81*h

h = 0.917 m

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Longest wavelength is 1.5 m and The frequency associated with this longest wavelength is 86.7 Hz

A waveform signal that is carried in space or down a wire has a wavelength, This is the distance in the next cycles between two identical locations (adjacent crests). This length is typically defined in wireless systems in metres (m), centimeters (cm), or millimetres (mm) (mm).

The wavelength equation of a standing wave is given by:

λn= 2/n L

Where:

L is the length of the string

n is a natural number

We use n=1 to find the longest possible wavelength, so we will have:

λ1= 2L

λ1=2 * 0.75 = 1.5m

Longest wavelength is 1.5 m

b)

The speed of the wave is given by:

v= f λ

So we just need to find the f (frequency).

f= v/λ

f = 130/1.5

f = 86.7 Hz

The frequency associated with this longest wavelength is 86.7 Hz

The complete question is : A string with a length of 0.75 m is fixed at both ends. (a) What is the longest possible wavelength for the traveling waves that can interfere to form a standing wave on this string? (b) If waves travel with a speed of 130 m/s on this string, what is the frequency associated with this longest wavelength?

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The heat flow of the thermal resistance is (r2 - r1) / 4πkr1r2).

Consider the diagram below, the heat flow will be

Fourier's law in radial coordinates

qr = -k.AdT/dr

Substituting the values of the area of sphere,

qr = -k (4πr²) dT/dr

Integrating we get

qr/4π∫dr/r^2 = ∫kdt

qr/4π ∫dr/r^2 = ∫kdt

qr/4π (1/r1 - 1/r2) = k(t2-t1)

qr = 4πkr1r2(t1-t2) / (r2 - r1)

The thermal resistance is expressed as

R = (r2 - r1) / 4πkr1r2)

Therefore, the heat flow of the thermal resistance is (r2 - r1) / 4πkr1r2).

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A piston is placed inside a gas-filled cylinder. It is calculated to be the gas's starting pressure. expanding the gas until it reaches its final volume and 18.4 kPa of pressure.

We know that P1V1 = P2V2

Now P1 = 90.1 kPa

        V1 = 10 L

       V2 = 49 L

therefore

90.1 x 10 = P2 x 49

therefore P = 18.387

P = 18.4 kPa

In order to measure an object's surface tension, a force must be applied perpendicularly to the object's surface over a given area. Alternatively spelled gauge pressure, gauge pressure is the pressure in relation to atmospheric pressure.

Pressure is expressed using a number of different units. The SI unit of pressure, the pascal (Pa), for instance, is equal to one newton per square meter (N/m2); similarly, the traditional unit of pressure in the imperial and U.S. customary systems is the pound-force per square inch (psi). Some of these measurements are the result of dividing a unit of force by a unit of area. The atmosphere (atm), which is equal to this pressure, and the tour, which is defined as 1760 of it, can also be used to describe pressure.

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The time takes for the green ball to reach the ground is equal to 0.78 s. As both balls are thrown from the same height they will take the same time to reach the ground irrespective of their velocity.

The equations of motion can be described as the equations which establish the relationship between the time, velocity, acceleration, and displacement of a moving object.

The equations of motions as the mathematical expressions:

[tex]v = u +at\\S = ut +(1/2)at^2\\v^2-u^2= 2aS[/tex]

Given, the height from which the ball is thrown, h = 3

From the 2nd equation of motion, calculate the time taken by the ball reach to the ground:

H = ut + (1/2)gt²

3 = 0 + (1/2)× 9.8×t²

t = 0.78 s

As the time is independent of the velocity of a ball so both balls take the same time to reach the ground as they are thrown from the same height.

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