A figure skater is spinning slowly with arms outstretched. Shebrings her arms in close to her body and her moment of inertiadecreases by 1/2. Her angular speed increases by a factor of
A. 2
B. 1
C. 4
D. square root of 2
E. 1/2
In the same situation if she decreases her moment of inertiaby a factor of 2, how does her angular speed change?
A. Its reduced by a factor of 4
B. Its reducded by a factor of 2
C. It increases by a factor of 4
D. It increases by a factor of 2
E. It doesnt change
Is the relationship between angular speed and moment ofinertia inversely proportional, or does angular speed have todouble to compensate for any decrease in moment of inertia? I needhelp understanding the relationship between the two. I=2k/omegasquared, correct?

Answers

Answer 1

The angular speed increases by a factor of 2 and when she decreases her moment of inertia by a factor of 2 her angular speed change.

Angular momentum is a characteristic of rotating bodies determined by the product of their angular velocity and moment of inertia.

Angular momentum = Angular velocity x Moment of inertia

The angular momentum is calculated by

L = IW

Where,

I = Inertia momentum

W = angular velocity

It can be calculated by applying the law of conservation of angular momentum as given below:

= [tex]I_{i} W_{i} =I_{f} W_{f}[/tex]

Where, i = initial, f = final

Since the final inertia momentum of figure skater gets decreased by 1/2 from the initial,

= [tex]\frac{1}{2}I_{i} = I_{f}[/tex]

Therefore, the final angular speed would become

 [tex]I_{i} W_{i} = \frac{1}{2} I_{i} W_{f}[/tex]

 [tex]2W_{i} = W_{f}[/tex]

Hence, which means that angular speed increases by a factor 2.

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Related Questions

james crosses a river that is flowing west at 5 m/s. if he paddles his boat at 2 m/s north, what is his velocity with respect to the shore?

Answers

He is moving toward the coast at a velocity of 13 m/s. James can cross a river flowing at 5 m/s in the west if he paddles his boat at 2 m/s north. There isn't any acceleration up.

The rate of change in an object's position relative to a frame of reference is called velocity, and it depends on time. An object's speed and direction of motion are specified by its velocity. A crucial idea in kinematics is velocity. The pace at which an object's position changes in relation to a frame of reference and time is referred to as its velocity.

v2 - u2 = 2as 5 - u2 = 144 - 144 + 25 = 169 U = 13 m/s

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which of the elements of a legal contract does an insurance premium payment represent?

Answers

Consideration is the element of a legal contract that the insurance premium payments represent.

A legally binding agreement is referred to as a "contract". It consists of five fundamental components:

OfferAcceptanceConsiderationCompetent partiesLegal purpose

What is "consideration" as one of the fundamental components of a contract?

A party provides another party with consideration when they provide something of value. Each party has committed to respecting the terms of the agreement by exchanging compensation in this manner. Every legal contract must have this component. The initial premium payment is the applicant's consideration for insurance contracts. If a fee is included in the application, coverage could start the day it is filed. The first premium would not become due to the insurer/insurer agent until after the application has been submitted in such case.

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What is the wave velocity of a sound with 500 Hz and wavelength of 0.5 m?

Answers

ANSWER - A wave of frequency 500 Hz has a velocity of 360 m s−1.

the period t (in seconds) of a pendulum is given by , where l stands for the length (in feet) of the pendulum. if , and the period is 12.56 seconds, what is the length? the length of the pendulum is

Answers

The length of the pendulum is  128.57 feet.

What is time period?

The duration of time it takes for any string element to complete an oscillation is known as the time period of an wave oscillation.

The period T (in seconds) of a pendulum is given by: T = 2π√(l/g).

The period is 12.56 seconds.

Acceleration due gravity: g = 32.1741 feet/second².

Hence,  the length of the pendulum be = (T/2π)²g

=  (12.56/2π)²×32.1741 feet

= 128.57 feet.

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The specific gravity of an material is defined as the ratio of the density of the material to the density of water. The specific gravity of ice is 0.917, whereas that of seawater is 1.025.

Answers

The percentage of the iceberg that is visible above the water's surface will be 11.5% if specific gravity of ice is 0.917.

We know very well that density is defined as the division of mass with per unit volume. It is an important factor in order to find  the fluid and its properties. Its SI.unit is kg/m³.

We know very well that the mass and density relation is given by the formula

mass = density × volume

We are given density of ice = 917 kg/m³,density of the seawater=1025 kg/m³

Therefore, the ratio by which the iceberg submerge is found as

=>[tex]V_s[/tex]/V=ρ/ρ[tex]_o[/tex]

where V and ρ is defined as the volume of the iceberg and ρ is defined as the density of the substance.

=>[tex]V_s[/tex]/V=0.917/1.025

=>[tex]V_s[/tex]/V =917/1025

=>[tex]V_s[/tex]/V=0.895

or we can 89.5% of ice is submerged inside the water.

But we need to find the percentage which is visible to us, it means we need to subtract the submerged percentage from total percentage possible.

⇒The percentage which is visible to us=100-.89.5 %

⇒The percentage which is visible to us=11.55 %

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protons in an atomic nucleus are typically 10-15 m apart. what is the electric force of repulsion between nuclear protons?

Answers

The electric force of repulsion between nuclear protons is 230 Newton.The size of the force varies inversely as the square of the distance between the two charges.

Electric charge consists of two types i.e. positively electric charge and negatively electric charge.There was a famous scientist who investigated about this charges. His name is Coulomb and succeeded in formulating the force of attraction or repulsion between two charges i.e. :

F = electric force (N)

k = electric constant (N m² / C²)

q = electric charge (C)

r = distance between charges (m)

The value of k in a vacuum = 9 x 10⁹ (N m² / C²)

F = k(q1 q2)/ r^2

Distance between protons = d = 10⁻¹⁵ m

charge of proton = q = 1.6 × 10⁻¹⁹ C

Here q1=q2

electric force = F =230N

Coulomb's Law: Two protons in an atomic nucleus are typically separated by a distance of 2×10−15m. The electric repulsive force between the protons is huge, but the attractive nuclear force is even stronger and keeps the nucleus from bursting apart.

2 Nuclei and the Need for an Attractive Nuclear Force. The Coulomb force also acts within atomic nucleii, whose characteristic dimension is 10 m, which is called a fermi. There are two protons in a He nucleus, which repel each other because of the Coulomb force.

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the moon has a mass of 1×1022 kg, and the gravitational field strength at a distance r from the planet is 0.001 n/kg. what is the gravitational force exerted on the moon while it is in orbit around the planet?

Answers

The gravitational force exerted on the moon while it is in orbit around the planet is 1×10¹⁹ N

How do I determine the gravitaional force?

From the question given above, the following data were obtained:

Mass of moon (M) = 1×10²² KgGravitational field strength (E) = 0.001 N/KgGravitational force (F) =?

From the above data, we can obtain the gravitational force as illustrated below:

Gravitational field strength (E) = force (F) / mass (M)

E = F / M

0.001 = F / 1×10²²

Cross multiply

F = 0.001 × 1×10²²

F = 1×10¹⁹ N

Thus, from the above calculation, we can conclude that the gravitational force is 1×10¹⁹ N

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A mass is connected to a spring and is allowed to move horizontally. The mass is at a position L when the spring is unstretched. The mass is then moved, stretching the spring, and released from rest. It then moves with simple harmonic motion. (a) At the instant that the mass passes through the position where the spring is unstretched, what can be said about its instantaneous acceleration? Grade Summary It is maximum. OIt is zero It is non-zero but not maximum Potential per attempt) Hint I give up 1% -ム33% Part (b) At the instant that the mass asses through the position where the spring is unstretched, what can be said about its instantaneous ーム33% Part (c) At the instant that the spring is compressed the most, what can be said about the magnitude of its instantaneous velocity?

Answers

The spring is then stretched by moving the bulk after which it is set free. It then moves in straightforward harmonic motion. While not maximal, it is not zero either.

Is a mass attached to a spring if its duration is?

The square root of the mass and the spring constant have opposite relationships with respect to the period of a spring-mass system.

What is mass motion when it is connected to a spring?

If there is no friction and the mass is moved just a "small" distance from its equilibrium position at x = 0, the motion of a mass linked to a spring is said to be simple harmonic motion. The displacement needs to be minimal enough to avoid stretching the spring above its elastic limit and causing distortion.

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A bicycle has a kinetic energy of 124 J. What kinetic energy would the bicycle have if it had
a) twice the mass and was moving at the same speed?
b) the same mass and was moving with twice the speed?
c) one-half the mass and was moving with twice the speed?
d) the same mass and was moving with one-half the speed?
e) three times the mass and was moving with one-half the speed?

Answers

Answer:

Below

Explanation:

KE = 1/2 mv^2

  soooo   ...

a) doubling m doubles KE
b) doubling 'v' makes KE 4 times greater (because v is v^2)

c) 1/2 *2^2 = double KE

d ) 1/2^2 = 1/4 KE

e)  3 * 1/2^2 = 3/4 KE

A mass is connected to a spring and is allowed to move horizontally. The mass is at a position L when the spring is unstretched. The mass is then moved, stretching the spring, and released from rest. It then moves with simple harmonic motion. (a) At the instant that the mass passes through the position where the spring is unstretched, what can be said about its instantaneous acceleration? Grade Summary It is maximum. OIt is zero It is non-zero but not maximum Potential per attempt) Hint I give up 1% -ム33% Part (b) At the instant that the mass asses through the position where the spring is unstretched, what can be said about its instantaneous ーム33% Part (c) At the instant that the spring is compressed the most, what can be said about the magnitude of its instantaneous velocity?

Answers

a) The instant that the mass passes through the position where the spring is unstretched, what can be said about its instantaneous acceleration being zero,

c)  The instant that the spring is compressed the most, what can be said about the magnitude of its instantaneous velocity of Speed ​​is Zero

a) the equation that governs the simple harmonic motion is

        x = A cos (wt +φφ)

Where A is the amplitude of the movement, w is the angular velocity, and φ the initial phase determined by the initial condition

Body acceleration is

        a = d²x / dt²

Let's look for the derivatives

        dx / dt = - A w sin (wt + φ)

        a = d²x / dt² = - A w² cos (wt + φ)

In the instant when it is not stretched x = 0

As the spring is released at maximum elongation, φ = 0

           0 = A cos wt

           Cos wt = 0         wt = π / 2

Acceleration is valid for this angle

          a = -A w² cos π/2 = 0

Acceleration is zero

b)

c) When the spring is compressed x = A

Speed ​​is

            v = dx / dt

            v = - A w sin wt

We look for time

           A = A cos wt

           cos wt = 1         wt = 0, π

For this time the speedy vouchers

           v = -A w sin 0 = 0

Speed ​​is cero

Harmonic movement refers to the movement of an oscillating mass studies when the restoring pressure is proportional to the ​displacement, however in contrary directions. Harmonic motion is periodic and may be represented with the aid of a sine wave with regular frequency and amplitude. An example of that is a weight bouncing on a spring. The motion is called harmonic due to the fact musical contraptions make such vibrations that during flip cause corresponding sound waves in the air.

it is a sort of periodic motion with extreme points. simple harmonic motion is an oscillatory motion wherein the particle's acceleration and force are without delay proportional to its displacement from the mean region at every factor. it's miles a special case of oscillatory movement.

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Consider this situation: a bucket of water, attached to a rope, is being pulled upward out of a well. Of the forces listed, identify which act upon the bucket.

Answers

The forces which acts on a bucket of water when it pulled upward out of a well are:  b) Gravity force  e) Tension force and f) Air resistance force. So, correct listed options are b, e, f.

The forces imparted through a rope, string, or wire while two contradicting forces draw on it is known as Tension force. The pressure force pulls energy similarly on the bodies at the closures and is applied along the whole length of the wire. Gravity force is acted due to gravitational force acted by the gravity on the object.

Each actual article in touch with another applies a force to that item. In view of the sort of articles, names are given to these contact forces. You can allude to strain as one of the powers following up on an item, like a rope, link, or chain.

Hence, correct options are b, e, f.

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(Complete question) is:

Consider this situation: A bucket of water, attached to a rope, is being pulled upward out of a well. Of the forces listed, identify which act upon the bucket.

a. Normal Force

b. Gravity Force

c. Applied Force

d. Friction Force

e. Tension Force ​

f. Air Resistance Force

A farmer with 2000 meters of fencing wants to enclose a rectangular plot that borders on a straight highway. If the farmer does not fence the side along the highway, what is the larges area that can be enclosed?.

Answers

The sides xx and y will be parallel to the road and perpendicular to it, respectively.

2x + y = 2000 y = 2000 2x A = 2x + y = 2x2 + 2000 x

Locate the vertex:

=500 ⇒y=2000−2x\s​=1000\s ⇒A=x⋅y\s​=500⋅1000=500000

The largest area is 500000 square meters.

By rectangle, what do you mean?

A rectangle is a quadrilateral with parallel sides that are equal to one another and four equal vertices. Due of this, it is also known as an equiangular quadrilateral. Due to their equal and parallel opposite sides, rectangles are also known as parallelograms.

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a spaceship, 200 m long as seen on board, moves by the earth at. what is its length as measured by an earth-bound observer?

Answers

The length of the spaceship as measured by an earth-bound observer is equal to 48.6 m

What is length contraction?

Length contraction can be described as the phenomenon that the length is measured to be shorter than its proper length, which is the length as measured in its own rest frame and is also known as Lorentz contraction.

The original formula of the length contraction leads to the relation:

[tex]{\displaystyle L=L_{0}{\sqrt {1-\frac{v^{2}}{c^{2}}}}[/tex]

In the above equation, both L and L₀ are measured parallel to the line of movement of the object.

Given, the original length of the spaceship, L₀ = 200 m

The speed of the spaceship, v = 0.970 c

The apparent length of the spaceship can be calculated as:

[tex]{\displaystyle L=200\times {\sqrt {1-\frac{(0.970c)^{2}}{c^{2}}}}[/tex]

L = 48.6 m

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Your question was incomplete, most probably the complete question was,

A spaceship, 200 m long as seen on board, moves by the earth at 0.970c. What is its length as measured by an earth-bound observer?

a 3.1-kg object falls vertically downward in a viscous medium at a constant speed of 2.5 m/s. how much work is done by the force the viscous medium exerts on the object as it falls 85 cm?

Answers

The work is done by the force the viscous medium exerts on the object as it falls 85 cm is -26.35 joules.

   The mass of the object is m = 3.1kg

    The speed of fall is v = 2.5 m/s

    The depth of fall is d = 85cm

Now here given that the velocity is constant, then the work energy is zero.

So, work done by the potential energy of the object and that of the viscous liquid we have

      W = Wv + Wp

Where  Wv is work done by viscous liquid and

Wv is the work done by the object

           Wp = mgd

So  

      0  = Wv + mgd

 Wv = -mgd

substituting values

Wv = -3.1x10x85

Wv = 26.35 joules

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the flywheel of a steam engine begins to rotate from rest with a constant angular acceleration of 1.47 rad/s2. it accelerates for 24.7 s, then maintains a constant angular velocity. calculate the total angle through which the wheel has turned 59.5 s after it begins rotating.

Answers

The flywheel of a steam engine starts revolving at rest with a constant angular acceleration of 1.47 rad/s2, therefore the wheel has rotated across a total angle of 1709.67 rad after 59.5 seconds.

To answer the question, we write down the flywheel's motion equation as 2 = 1 + t.

Where:

Initial angular velocity for the body is 0 rad/s in equation (1) Initial and final angular velocities

Time is equal to 24.7 seconds and angle acceleration is 1.47 rad/s2.

After entering the values, we discover that 2 2 = 0 + 1.35 rad/s2* 24.7 s = 38.205 rad/s.

Thus, 540.60075 rad + 1169.073 rad = 1709.67375 rad 1709.67 rad is the equation for the total angle the flywheel covered in 59.5 seconds.

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determine δhvap for a compound that has a measured vapor pressure of 24.3 torr at 273 k and 135 torr at 325 k.

Answers

The enthalpy of vaporization as determined from the different temperatures is  23.6 kJ/mol.

What is  the enthalpy of vaporization?

The enthalpy of vaporization has to do  with the heat that is given out when a substances is converted from liquid to vapor under standard conditions.

We can use te formula;

ln(P2/P1) = -ΔHvap/R(1/T2 - 1/T1)

P2 = final pressure

P1 = initial pressure

ΔHvap = enthalpy of vaporization

T2 = final temperature

T1 = initial temperature

Then;

ln(135/24.3) = -ΔHvap/8.314 (1/325 - 1/273)

1.7 =  -ΔHvap/8.314 (0.0031 - 0.0037)

1.7 =  -ΔHvap/8.314 (-0.0006)

1.7 = 0.0006ΔHvap/8.314

To obtain the enthalpy of vaporization here;

ΔHvap = 1.7 * 8.314/0.0006

= 23.6 kJ/mol

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in a binary-star system that produces a nova, the white dwarf pulls matter from the companion star. the matter forms an accretion disk that orbits the white dwarf. then a specific sequence of events must take place for a nova event to occur.

Answers

The chronological steps that lead to the observed nova event are as follows:

Material accumulates onto the white dwarf star's surface, making its temperature and density increase.Accumulated surface hydrogen begins nuclear fusion at 10 million Kelvin.The reactions from nuclear fusion cause a temporary yet significant increase in luminosity.As nuclear fuel is either burned up or blown into space, nuclear fusion ceases and the star dims down.

A nova event is an astronomical event that causes the occurrence of a bright star that slowly fades over time (usually in weeks or months). It's mainly caused by white dwarf stars that are involved in a close binary system.

Attached below is an image of the Nova Eridani in 2009 taken by Kevin Heider.

Your question seems incomplete, but the completed version is most likely as follows:

In a binary-star system that produces a nova, the white dwarf pulls matter from the companion star. The matter forms an accretion disk that orbits the white dwarf. Then a specific sequence of events must take place for a nova event to occur.

Rank the steps leading up to the observed nova event in chronological order from first to last.

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Need some help with this physics problem!

Answers

The gravitational attraction between Tom and Sally is 2.32×10⁻¹⁰ N.

What is gravitational attraction?

This the force of attraction between all masses in the universe; especially the attraction of the earth's mass for bodies near its surface.

To calculate the gravitational attraction between Tom and Sally, we use the formula below.

Formula:

F = GMm/r²............ Equation 1

Where:

F = Gravitational attraction between Tom and SallyG = Universal constantM = Mass of Tomm = Mass of Sallyr = Distance between Tom and Sally.

From the question,

Given:

M = 70.8 kgm = 48.1 kgG = 6.672589×10⁻¹¹ N.m²/kg²r = 31.3 m

Substitute these values into equation 1

F = (70.8×48.1×6.672589×10⁻¹¹)/(31.3²)F = 2.32×10⁻¹⁰ N

Hence, the gravitational attraction is 2.32×10⁻¹⁰ N.

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assume that three irregularly shaped planet-like objects, each smaller than our moon, have just been discovered orbiting the sun at a distance of 35 au. one of your friends argues that the objects should be classified as planets because they are large and orbit the sun. another friend argues that the objects should be classified as dwarf planets, like pluto. state whether you agree or disagree with either or both of your friends. explain your reasoning.

Answers

It does not meet all three criteria to be considered a planet.

What are three criteria to be considered as planet?

They determined that a planet must meet the following three requirements:

It must be a body that orbits the Sun independently; as moons orbit planets, they cannot be regarded as planets.It must possess sufficient mass to be drawn into a roughly spheroidal shape by its own gravity.To "dominate" its orbit, it must be massive enough (i.e. its mass must be much larger than anything else which crosses its orbit)

According to the question:

I concur with the buddy who says that it should be categorized as a dwarf planet, similar to Pluto, as Pluto is not large enough. Because it is also smaller than the Earth, it does not meet all three criteria to be considered a planet.

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It does not meet all three criteria to be considered a planet.

What are three criteria to be considered as planet?

They determined that a planet must meet the following three requirements:

It must be a body that orbits the Sun independently; as moons orbit planets, they cannot be regarded as planets.

It must possess sufficient mass to be drawn into a roughly spheroidal shape by its own gravity.

To "dominate" its orbit, it must be massive enough (i.e. its mass must be much larger than anything else which crosses its orbit)

I agree with my friend who believes it should be classified as a dwarf planet, comparable to Pluto, because Pluto is insufficiently huge. It does not match all three requirements for being called a planet because it is also smaller than the Earth.

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rank the following steps that lead to a type i supernova event in order of when they occur from first to last.

Answers

The steps that lead to a type I supernova event, in order of when they occur from first to last, are:

Initial Stateaccretion disk on growing WDWD at Chandrasekhar limit carbon fusion beginsdetonation Final State

Initial state: The supernova process begins with a white dwarf star (WD) in a binary system. The WD is orbited by a companion star that is transferring matter onto the WD, forming an accretion disk around the WD.

Accretion disk on growing WD: As the companion star continues to transfer matter onto the WD, the accretion disk grows larger. This causes the WD to become more massive and increase in size.

WD at Chandrasekhar limit: At a certain point, the WD reaches the Chandrasekhar limit, which is the maximum mass a WD can have without collapsing. This occurs when the WD's mass is about 1.4 times the mass of the Sun.

Carbon fusion begins: As the WD continues to grow in mass and size, the pressure and temperature at its core become so high that carbon fusion begins. This process releases a huge amount of energy, which causes the WD to expand rapidly and become unstable.

Detonation: The unstable WD eventually reaches a critical point, known as the detonation point, where a sudden, explosive release of energy occurs. This is the beginning of the actual supernova event.

Final state: After the detonation, the WD continues to expand and cool, eventually becoming a supernova remnant. This is the final state of the supernova process.

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Complete Question:

rank the following steps that lead to a type i supernova event in order of when they occur from first to last.

-Initial State

-accretion disk on growing WD

-detonation

-carbon fusion begins

-WD at Chandrasekhar limit

-Final State

anderson video - solenoids 4 of 5 review | constants first, launch the video solenoids. after watching the video, answer the follow-up question below. select to launch video part a a solenoid with 200 loops is 60 cm long. it has a current of 4.2 a. what is the magnetic field in this solenoid?

Answers

The magnetic field in this solenoid is  0.3438 X 10⁻³ mT.

Number of loops = n = 200

Length of the solenoid = l = 60 cm = 0.6m

Thus, turns per m = 200/0.6 = 333.33

Current through the solenoid = i = 4.2

The magnetic field through the solenoid is = B =

= B = μ X n X I

= B = ( 4 X π X 10⁻⁷ X 200 X 4.2 ) / 0.60

= B = 10500.4 X 10⁻⁷ / 0.60

= B = 34383.66 X 10⁻⁷ T

= B = 0.3438 X 10⁻³ mT

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a spring is attached at one end to support b and at the other end to collar a, as represented in the figure. collar a slides along the vertical bar between points c and d. in the figure, the angle is the angle created as the collar moves between points c and d.

Answers

A. Distance of point A to point B is: 3.4 feet

B. The value of ∅ is: 54.8 .

Callback:

The trigonometric ratios to solve for the length or angle of the missing right triangle are: SOH CAH TOA.

The given image shows a right triangle.

Part A: Distance from point A to point B.

reference angle (∅) = 28°

hypotenuse = AB = ?

adjacency = 3 feet To find

AB, apply the trigonometric function CAH Replace

cos ∅ = adj/hyp

. ft (nearest tenth of a foot)

Part B: Value of ∅ at AB = 5.2 feet.

∅ = ?

adj = 3 feet

hyp = AB = 5.2 feet

To find ∅, apply the trigonometric function CAH:

cos ∅ = adj/hyp).

Trigonometry helps find angles and distances and is commonly used in science, engineering, video games, and more. right triangle.

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does the doppler effect occur when the source and observer are both moving towards each other? if so, how would this affect the perceived frequency?

Answers

When the source and observer are both moving towards each other, receive frequency will be same.

What is Doppler effect?

The change in frequency of a wave in proportion to an observer who is moving relative to the wave source is known as the Doppler effect, Doppler shift, or simply Doppler, depending on the context. It bears the name of the Austrian scientist Christian Doppler, who first characterized it in 1842.

The Doppler effect, also known as the Doppler shift, is a term used to explain changes in frequency caused by moving sources of sound or light with regard to an observer. As the source gets closer to the observer, the waves it is emitting become compressed and have a greater frequency.

Observer and source moving in same direction, then the frequency becomes:

f = (v ± v₀) × f/ [v ± v(s)]

Now, assume observer is behind the source ,source is moving towards observer and observer is moving away from source:

f₁ = (v - v₀) × f/[v - v(s)]

Here, received frequency will be same, thus Doppler effect occur due to relative motion.

Yes , the perceived frequency will be same as the source frequency.

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a girl throws a rock horizontally, with a velocity of 8.0 m/s, from a bridge. it falls 20 m to the water below. how far does the rock travel horizontally before striking the water, assuming negligible air resistance?

Answers

The rock thrown horizontally at 8.0 m/s from a bridge before it hits the water = 16.15 m.

Free fall motion

Free fall motion is a motion that falls from a height without having an initial velocity. As long as the object is falling, air resistance is negligible, its acceleration is constant and the magnitude is equal to the acceleration due to gravity. In addition, the time it takes for an object to fall does not depend on its mass, but depends on its height.

We have,

The velocity of the rock = 8.0 m/s ⇒ v

Fall height of the rock = 20 m ⇒ h

And, to determine  how far does the rock travel horizontally before striking the water, we use the equation:

d = v x t

We have the velocity (v), but don't have the time (t).

So, determine the time first

Use the equation to determine the height:

h = ½ gt²

20 =  ½ (9.8)t²

t² = 4.08

t = [tex]\sqrt{4.08}[/tex]

= 2.01 s

So, the distance the stone traveled before striking to the water:

d = (8.0) (2.01)

= 16.15 m

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a contact lens is made of plastic with an index of refraction of 1.30. the lens has an outer radius of curvature of 2.04 cm and an inner radius of curvature of 2.54 cm. what is the focal length of the lens?

Answers

The focal length of a camera lens, which is frequently stated in millimeters, is its fundamental description (mm), to the point where light rays converge to form a sharp image of an object.

An optical medium's refractive index, commonly referred to as the refraction index, is a dimensionless statistic that describes how well the medium bends light. Focal length, the amount of light that enters a substance is refracted or bent depends on the substance's refractive index. When a beam travels across the boundary between two media with refractive indices of n1 and n2, its angles of incidence and refraction are, respectively, n1 sin 1 and n2 sin 2, which describe this. The refractive indices determine the critical angle for total internal reflection, the intensity of the reflected light (Fresnel's equations), Brewster's angle, and the volume of light reflected when it reaches the interface. Since the speed of light in a medium is equal to v = c/n and the wavelength in that medium is equal to 0/n, where 0 is the wavelength of that light in vacuum, the refractive index can be thought of as the parameter that lowers those values relative to their vacuum values. This assumes that vacuum has a refractive index of 1, and that the frequency of the wave (f = v/) is unaffected by the refractive index.

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an object of mass 0.50 kg is transported to the surface of planet x where the object's weight is measured to be 20 n. the radius of the planet is 4.0 x 106 m. what is the mass (kg) of planet x?

Answers

Mass of the planet = 9.59 * 10²⁴ Kg

Given that,

Mass of the object, m = 0.5 kg

Weight of the object, W = 20 N

Radius of the planet, r = 4*10⁶ m

The weight of an object is given by :

W = m*g

g is the acceleration due to gravity on the surface of Planet

g = W/m

  = 20/0.5

  =40 m/s²

The expression for g is given by :

g = GM/r²

M= (r²g) / G

M = 9.59 * 10²⁴ Kg

   

So, the mass of the planet X is 9.59 * 10²⁴ Kg. Hence, this is the required solution.    

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how much tension must a cable withstand if it is used to accelerate a 1400-kg car vertically upward at 0.70 m/s2?

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9,800 Newtons of pressure must be supported by the wire (N). T = m x a, where T is tension, m is the car's mass, and an is the velocity, can be utilized to compute that.

T=1400 kg x 0.70 m/s2.

T = 9,800 N

First, figure out how much force is needed to start the car moving.

Force = mass × accelerate

Force = 1400 kg × 0.70 m/s2

Force = 980 N

Step 2: Calculate the tension in the cable.

Tension = Force

Tension = 980 N

Consequently, to propel the vehicle vertically upwards towards a speed of 0.70 m/s2, the wire should endure a tension of 980 N.

A force which draws on something and extends it is known as tension in thermodynamics. This force can be applied across a thread, wire, cord, or even other media. Pulling apart of the medium's extremities causes it to decompress, which is the reverse of compression. To determine the tension in a media, divide the pressure acting on its endpoints by both the surface of its pass.

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how much tension must a cable withstand to accellerate a 1400 kg car vertically upward at 0.70 m/s^2

Answers

Answer:

Below

Explanation:

The cars upward accel adds to the gravity accel (think about how suddenly heavy you feel when the elevator starts to move upward)

F = tension = ma

                   = 1400 * ( .7 + 9.81) = 14714 N

How does lack of sleep affect muscle recovery?

Answers

Sleep is crucial for muscle building. Our muscles develop and fix when we take proper sleep.

Preparing isn't the main thing that can experience the ill effects of absence of sleep. Sleep altogether affects muscle recuperation, and in the event that you don't get sufficient it will influence your endeavors in the exercise center too. At the point when we are drained during our exercises, we might have the option to push through in any case however this negatively affects our body synthesis objectives as well!

We become all the more quickly flustered or deterred with unfortunate activity execution when sluggish which leads us into vices like jumping out for an additional little while of shuteye later around evening time.

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if pressure increases by 1.000 atm for every 10.00 m of depth, at what depth was the diver working? assume the temperature remains constant.

Answers

The diver was working at a depth of 100 m. This can be determined by solving the following equation:

1.000 atm × 10.00 m = X atm × 100 m

X = 10 atm

This means that the pressure increased by 10 atm for every 100 m of depth, which means the diver was working at a depth of 100 m.

Since the temperature remained constant, the pressure increase was solely due to the change in depth.

The pressure increases by 1.000 atm for every 10.00 m of depth. This is known as the hydrostatic pressure equation, which states that pressure (P) is equal to the density of the fluid (rho) multiplied by the acceleration of gravity (g) multiplied by the depth (h):

P = rho * g * h

In this case, we can rearrange the equation to solve for h, the depth at which the diver was working:

h = P / (rho * g)

Since we know that the pressure increases by 1.000 atm for every 10.00 m of depth, we can assume that the pressure at the depth at which the diver was working is P. Therefore, we can substitute P for the pressure in the equation:

h = P / (rho * g)

Since the temperature remains constant, we can assume that the density of the fluid (rho) is also constant. Therefore, we can substitute the value of rho into the equation:

h = P / (rho * g)

Finally, we can substitute the value of acceleration of gravity (g) into the equation:

h = P

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