The additional kinetic energy that the child gains after reaching the bottom of the hill is 200 Joule. The result is obtained by using the principle of Conservation of Mechanical Energy.
What is Conservation of Mechanical Energy?The principle of conservation of energy states that "The total energy is neither increased nor decreased in any process. Energy can be transformed from one form to another, and transferred from one object to another, but the total amount remains constant."
In the same way, the Conservation of Mechanical Energy states that the total mechanical energy of a system is conserved. It can be expressed as
[tex]E_{1} = E_{2}[/tex]
[tex]K_{1} + U_{1} = K_{2} + U_{2}[/tex]
[tex]\frac{1}{2} mv_{1} ^{2} + mgh_{1} = \frac{1}{2} mv_{2} ^{2} + mgh_{2}[/tex]
Where
E₁ = mechanical energy at point 1E₂ = mechanical energy at point 2K₁ = kinetic energy at point 1K₂ = kinetic energy at point 2U₁ = potential energy at point 1U₂ = potential energy at point 2m = mass of an objectv₁ = velocity of object at point 1v₂ = velocity of object at point 2h₁ = height of object at point 1h₂ = height of object at point 2At one point, a child has:
U₁ = 200 JK₁ = 500 JHow much more kinetic energy does the child gain at the bottom of the hill?
At the bottom of the hill, the height of the child is zero, h₂ = 0. So, the potential energy is
[tex]U_{2} = mgh_{2}[/tex]
[tex]U_{2} = mg(0)[/tex]
[tex]U_{2} = 0[/tex]
The kinetic energy at the bottom of the hill is
[tex]K_{1} + U_{1} = K_{2} + U_{2}[/tex]
[tex]500 + 200 = K_{2} + 0[/tex]
[tex]K_{2} = 700 J[/tex]
The kinetic energy added for the remainder of the motion is
[tex]K = K_{2} - K_{1}[/tex]
[tex]K = 700 - 500[/tex]
[tex]K = 200 J[/tex]
Hence, the additional kinetic energy that the child gains after reaching the bottom of the hill is 200 Joule.
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how do you find your body composition
Answer (with explanation):
BMI = body composition
formula to find BMI = weight/height^2
so for example:
weight = 50kg and height = 150cm = 1.5m (make sure convert cm to m)
BMI = 50/(1.5)^2 = 50/2.25 ≈ 22.22
so the BMI would be about 22.22
The formula shown below is used to calculate the energy released when a specific quantity of fuel is burned. Calculate the energy released by a burning sample of fuel if the temperature of 100g of water was raised by 20°C. (Specific heat capacity of water = 4,200J/kg °C
The energy released by a burning sample of fuel is 8400 J.
The formula referenced in the question is:
Q = m.c.ΔT
where m is the mass of the water sample
c is the specific heat capacity of water
ΔT is the variation in temperature
Q is the thermal energy
According to the question,
c = 4,200 J/kg °C
ΔT = 20 °C
m = 100 g = 0.1 kg
On Solving, we put these values in the formula to evaluate the thermal energy,
Q = 0.1 * 4,200*20 = 8400 J
Thus, the energy released by a burning sample of fuel is 8400 J.
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A ball is kicked with a speed of 20 m/s at an angle of 15 degrees to the horizontal. With what vertical velocity was it kicked with?
Answer:
Explanation:
Given:
V₀ = 20 m/s
α = 15°
___________
Vy - ?
Vy = V₀·sin α = 20·sin 15° = 20·0.2588 ≈ 5.2 m/s
4. Can you curl your tongue up on the sides? tongue-curling in humans is a dominant genetic trait. Suppose a man who is tt for tongue-curling marries a woman who is also tt for this trait. What are the possible genotypes and phenotypes of their children and the percent chance for each?.
The possible genotypes and phenotypes of their children and the percent chance for each is 0%.
The capacity to roll one's tongue outweighs the lack of capacity.The two people have the homozygous recessive character if the dominant allele is R and the recessive allele is r.This indicates that the organism's genotype will be "rr."If such people cross each other:
Parents X Parents
gamma r r
Children rr
That results in :
The genotype of the offspring will be homozygous recessive (rr) based on the genetic cross.Because they lack the dominant allele, the child will therefore be unable to roll their tongue.The possible genotypes and phenotypes of their children and the percent chance for each is 0%.
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The magnetic field of an electromagnetic wave moving in the z-direction is given by in si units. What is the maximum electric field strength?.
The maximum electric field strength is f=1.98×10⁵
The magnetic field of a plane-polarized electromagnetic wave moving in the z-direction is given by :
B=1.2×10⁶ sin[2π(Z/240-10⁷t/8)].....(1)
The general equation of the magnetic field wave is given by :
B=B°sin(kz-wt) ....(2)
Equation (1) is in form of equation (2), if we compare equations (1) and (2) we find that,
w=10⁷/8
We need to find the frequency of the wave. It is given by :
f=w/2π
f=10⁷/8×2π
f=1.98×10⁵ Hz
So, the frequency of the wave is f=1.98×10⁵ Hz.
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According to Loftus, why is the study of eyewitness memory important? Be sure to include a specific quotation from the excerpt above to support your explanation.
Do the Loftus studies support the use of eyewitness testimony as evidence? Be sure to include specific details from the studies to support your position.
Loftus thought that, to a certain extent, eye witness recollection was significant during a court case or prosecution. Eye witness memory, according to Loftus, is crucial since it provides a different perspective and gauges how reliable a witness's testimony is.
What is eyewitness memory?A person's memory of a particular occurrence, sometimes a crime or accident of some sort, that he or she directly witnessed or experienced. Given the occurrence of phenomena like the weapon-focus effect and the disinformation effect, the credibility of eyewitness evidence is a significant problem in forensic psychology.The law certainly cares about knowing something about the precision, completeness, and malleability of such memories, he said. So he doesn't entirely back the use of eye witness memory. This is so that, because an eyewitness's memory is "malleable," the prosecutor's tone of voice could persuade the witness to alter his or her statement.According to Loftus, eye witness recall is crucial since it provides a different viewpoint and gauges how reliable a witness's testimony is. It also gauges the degree to which it can be trusted. It is evident that the law is interested in learning more about the precision, completeness, and malleability of such memories." His assertion amply supports the significance of eye witness recall.To know more about eyewitness memory, visit:
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The image I've attached holds the question.What is the satellite’s speed?Answer in units of m/s.What is the period of the satellite’s orbit?Answer in units of h.
Given:
The gravitational constant, G=6.67259×10⁻¹¹ N·m²/kg⁻²
The mass of the moon, M=7.36×10²² kg
The radius of the orbit of the satellite, R=955.2 km=955.2×10³ m
To find:
1. Satellite's speed.
2. The period of satellite.
3. The acceleration of the satellite.
Explanation:
1.
The gravitational force applied by the moon on the satellite provides the satellite with the centripetal force that is neccessary for the satellite to orbit the moon.
Thus,
[tex]\begin{gathered} F_c=F_g \\ \frac{mv^2}{R}=\frac{GMm}{R^2} \\ v=\sqrt{\frac{GM}{R}} \end{gathered}[/tex]Where F_c is the centripetal force, F_g is the gravitational force, and v is the orbital velocity of the satellite.
On substituting the known values,
[tex]\begin{gathered} v=\sqrt{\frac{6.67259\times10^{-11}\times7.36\times10^{22}}{955.2\times10^3}} \\ =2267.46\text{ m/s} \end{gathered}[/tex]2.
The orbital period of the satellite in seconds is given by,
[tex]T=\frac{2\pi R}{v}[/tex]Thus the period of the satellite in hours is given by,
[tex]T=\frac{2\pi R}{v\times3600}[/tex]On substituting the known values,
[tex]\begin{gathered} T=\frac{2\pi\times955.2\times10^3}{2267.46\times3600} \\ =0.74\text{ hr} \end{gathered}[/tex]3.
The acceleration of the satellite is given by,
[tex]a=\frac{v^2}{R}[/tex]On substituting the known values,
[tex]\begin{gathered} a=\frac{2267.46^2}{955.2\times10^3} \\ =5.38\text{ m/s}^2 \end{gathered}[/tex]Final answer:
1. The orbital velocity of the satellite is 23267.46 m/s
2. The period of the satellite is 0.74 hr
3. The acceleration of the satellite is 5.38 m/s²
explain how the current would change if the amount of voltage increased, but resistance stayed the same. using ohms law
When the voltage in a circuit is increased, the current flowing in the circuit will also increase
How would I know what will happen to the current?Ohm's law states that the current flowing through a metallic conductor is directly proportional to the voltage provided all physical properties like resistance remains constant This is represented mathemathically as:
Voltage (V) = Current (I) × resistance (R)
V = IR
If R is constant, then
V₁ / I₁ = V₂ / I₂
Where
V₁ and V₂ are the initial and new voltageI₁ and I₂ are the initial and new currentNow, let us see what will happen to the current when we increase the initial voltage, say by a factor of 2. This is illustrated below:
Initial voltage (V₁) = V Initial current (I₁) = INew voltage (V₂) = 2VNew current (I₂) = ?V₁ / I₁ = V₂ / I₂
V / I = 2V / I₂
Cross multiply
V × I₂ = I × 2V
Divide both sides by V
I₂ = (I × 2V) / V
I₂ = I × 2
I₂ = 2I
Thus, we can see that the new current also increase by a factor of 2
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1. If a cart with a mass of 5 kg is accelerated at a rate of 12 m/s/s, then what is theNUMERICAL value for the force?
*The mass of the cart is
m=5 kg
*The acceleration is
[tex]undefined[/tex]A cannonball
of mass 25kg is
fired straight up at an initial
velocity of 8m/s. The
gravitational field strength is
9.8m/s. Calculate the
maximum height it can reach?
If a cannonball of mass 25 kg is fired straight up at an initial velocity of 8 m / s, the maximum height it can reach is 3.27 m
v² = u² + 2 a s
v = Final velocity
u = Initial velocity
a = Acceleration
s = Distance
u = 8 m / s
a = - 9.8 m / s²
At maximum height,
v = 0
Using the equation from equations of motion,
0 = 8² + ( 2 * - 9.8 * s )
19.6 s = 64
s = 3.27 m
Therefore, the maximum height it can reach is 3.27 m
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The formula shown below is used to calculate the energy released when a specific quantity of fuel is burned. What is the missing factor?
Q = m c Δt is the formula used to determine the energy released when a certain amount of fuel is burned.
To calculate the amount of energy required to raise the temperature of a known mass of a substance, we can use the specific heat formula:
Q = m × c × ΔT
In the formula for specific heat, the letters Q, m, c, and ΔT stand for the quantities that represent the energy transferred in joules, the mass of the substances in kilograms, the specific heat capacity in J/kg degrees C, and the change in temperature in degrees Celsius respectively.
Distinct materials have different relationships between heat energy and temperature, and the term "specific heat" summarizes how these relationships play out. When heat energy is delivered to a substance, its temperature will vary by a certain amount.
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In the diagram, q1 = +8.60 x 10-6 C,92 +5.10 x 10-6 C, and q3 = -3.30 x 10-6 C.Find the magnitude of the net force on 92.0.350 m9192magnitude (N)0.155 m93(Make sure you know the direction of each force!Opposites attract, similar repel.)
Given:
• q1 = +8.60 x 10⁻⁶ C
,• q2 = +5.10 x 10⁻⁶ C.
,• q3 = -3.30 x 10⁻⁶ C.
,• d12 = 0.350 m
,• d23 = 0.155m
Let's find the magnitude of the net force on q2.
First find the force on the charge 1 and 2:
[tex]\begin{gathered} F_{12}=-\frac{kq_1q_2}{(d_{12})^2} \\ \\ F_{12}=-\frac{9\times10^9*8.60\times10^{-6}*5.10\times10^{-6}}{0.350^2} \\ \\ F_{12}=-3.22\text{ N} \end{gathered}[/tex]Also for the force on charge 2 and 3, we have:
[tex]\begin{gathered} F_{23}=\frac{kq_2q_3}{(d_{23})^2} \\ \\ F_{23}=\frac{9\times10^9*5.10\times10^{-6}*(3.30\times10^{-6})}{0.155^2} \\ \\ F_{23}=6.305\text{ N} \end{gathered}[/tex]Now, the magnitude of net force on q2 will be:
[tex]\begin{gathered} F_{net}=\sqrt{(F_{12})^2+(F_{23})^2} \\ \\ F_{net}=\sqrt{(-3.22)^2+6.305^2} \\ \\ F_{net}=\sqrt{10.38+39.75} \\ \\ F_{net}=\sqrt{50.13} \\ \\ F_{net}=7.08\text{ N} \end{gathered}[/tex]Therefore, the magnitude of the net force on q2 is 7.08 N.
• ANSWER:
7.08 N
what is a frame of reference.....
Answer: A frame of reference is a set of criteria or stated values in relation to which measurements or judgements can be made. A reference point is an object that happens to be at rest. Given an example Car A and Car B are moving but without a reference you would not be able to know the car that is moving but with a signboard you can be able to tell which Car moved forward or backward.
Explanation:
Hope this was helpful
a mouse runs a distance of 2.0 meters in 16 seconds. calculate the speed of the mouse
S=d/t
S=2/16
S=0.125m/s
A ball rolls off a cliff and falls for 4.5 s. What is the final vertical velocity of the ball? (Answer must be negative!!!)
Answer:
-199 m/s
Explanation:
Ignoring the horizontal velocity, the vertical velocity =
a *t a = -9.81 m/s^2
-9.81 ( 4.5^2) = - 199 m/s
When the mass of the cylinder increased from 3.0 kg to 6.0 kg, what happened to the amount of heat generated in the system? it decreased by a factor of 3. it decreased by a factor of 2. it increased by a factor of 2. it increased by a factor of 3.
Option c. It is increased by 2.
Heat generation that is thermal capacity of an object is dependent on mass. So if the mass of an object increases, the heat generation also increases.
How thermal capacity is related to mass?
Thermal capacity= mass × specific heat
As we can see by the formula, that the thermal capacity is directly proportional to mass. So if the mass of the object increases, so does the thermal capacity.
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The answer is C:
It increased by a factor of 2.
A student in track and field is running a hurdles race. The hurdles are 91.4 cm tall. The student is running with a horizontal velocity of 4.00 m/s and leaps with a vertical velocity of 9.00 m/s. If the student makes this leap 0.400 m before the hurdle, will they clear the hurdle?
No, they will not be able to clear the hurdle from the given distance of their leap.
What are the projectile motion?Projectile motion includes vertical and horizontal velocity components. It's important to understand that the two are independent of each other. But what is a projectile and what is a good example. Well, a projectile is an object that is thrown by applying a force that falls under gravity and is subject to the resistance of the medium in which it travels. It can be thrown into the air and fall under the influence of gravity.
First of all the time required to reach the hurdle is:
by using horizontal velocity we have time = [tex]\frac{distance}{speed}[/tex]
t = [tex]\frac{0.400}{4}[/tex]
t = 0.100s
Now for the vertical distance covered by student:
S = ut + [tex]\frac{1}{2}[/tex] gt²
S = 9 × 0.100 + [tex]\frac{1}{2}[/tex] 9.8 × 0.100²
S = 0.851m or 85.1cm
Since the distance calculated is less than the height of hurdles which is 91.4 cm so the student may not be able to clear the hurdle.
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Describe where microwaves are found on the ems compared to the other six forms of radiation.
On the EMS microwaves fall between radio waves and infrared radiations.
Electromagnetic radiation, which travels through space and conveys electromagnetic radiant energy, makes up electromagnetic radiation.
EMS consists of
radio waves, microwaves, infrared radiations, visible light, ultraviolet radiations, X-rays, gamma rays.These waves are all components of the electromagnetic spectrum. Electromagnetic waves are synchronized oscillations of the electric and magnetic fields that make up electromagnetic radiation in a classic way. Due to the periodic alteration of the electric or magnetic field, electromagnetic radiation or waves are produced. Different wavelengths of the electromagnetic spectrum are created depending on the manner in which this periodic change takes place and the power generated. Electromagnetic waves move at the speed of light, in a vacuum.
An image is attached for further clarification.
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What is the weight of a girl with a mass of 30 kg on Earth?
N
Use g= 9.81 m/s² and do not include units in your answer.
The weight of a girl would be 294 N on Earth with a mass of 30 Kg.
Arithmetic operations can also be specified by the addition, subtract, divide, and multiply built-in functions.
+ Addition operation: Adds values on either side of the operator.
For example 4 + 2 = 6
- Subtraction operation: Subtracts the right-hand operand from the left-hand operand.
for example 4 -2 = 2
* Multiplication operation: Multiplies values on either side of the operator
For example 4*2 = 8
The weight on Earth of a girl would be the product of the mass and acceleration due to gravity on Earth
So the required solution would be:
⇒ weight = mass × acceleration due to gravity on Earth
⇒ weight = 30 × 9.8
⇒ weight = 294 N.
Hence, the weight of a girl would be 294 N on Earth with a mass of 30 Kg.
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A 3.0kg cat and a 14kg dog exert a force of gravity on each other equal to 1.12 x 10^-10 N. how far apart are they
The expression for the gravitational force between two bodies is given by:
[tex]F=G\frac{m_1m_2}{r^2}[/tex]where,
G: Cavendish's constant = 6.67*10-11Nm^2/kg^2
m1 = 3.0kg
m2 = 14kg
Solve the equation above for r:
[tex]\begin{gathered} r=\sqrt{\frac{Gm_1m_2}{F}} \\ r=\sqrt[]{\frac{(6.67\cdot10^{-11}\frac{Nm^2}{\operatorname{kg}^2})(3.0kg)(14kg)}{10\cdot10^{-10}N}} \\ r\approx1.67m \end{gathered}[/tex]Hence, the distance between the dog and the car is approximately 1.67m
one type of wagon wheel consists of a 2.0-kgkg hoop fitted with four 0.80-kgkg thin rods placed along diameters of the hoop so as to make eight evenly spaced spokes. part a for a hoop of radius 0.40 mm , what is the rotational inertia of the wheel about an axis perpendicular to the plane of the wheel and through the center?
The rotational inertia of the wheel is 1.344 × 10⁻⁴ kgm²
What is rotational inertia?Rotational inertia of an object is the measure of the ability for the object to rotate about an axis which may or may not pass thorugh the object.
Hoiw to find the rotational inertia of the wheel?Since in one type of wagon wheel consists of a 2.0-kg hoop fitted with four 0.80-kg thin rods placed along diameters of the hoop so as to make eight evenly spaced spokes and for a hoop of radius 0.40 mm, we need to find the rotational inertia of the wheel about an axis perpendicular to the plane of the wheel and through the center?
The rotational inertia of the wheel is given by I = I₁ + I₂ where I₁ = rotational inertia of hoop = and I₂ = rotational inertia of thin rods
Now the rotational inertia of the hoop is, I₁ = m₁r² where
m₁ = mass of hoop = 2.0 kg and r = radius of hoop = 0.40 mmAlso, the rotational inertia of each thin rod is I₃ = m₂L²/2 where
m₂ = mass of thin rod = 0.80 kg and L = length of rod = 2r where r = radius of hoop = 0.4 mm = 0.004 mSince there are four thin rods, I₂ = 4I₃
= 4m₂L²/2
= 2m₂L²
= 2m₂(2r)²
= 2m₂(4)r²
= 8m₂r²
So, I = I₁ + I₂
I = m₁r² + 8m₂r²
I = (m₁ + 8m₂)r²
So, substituting the values of the variables into the equation, we have
I = (m₁ + 8m₂)r²
I = (2.0 kg + 8 × 0.80 kg)(0.004 m)²
I = (2.0 kg + 6.4 kg)(0.000004 m²)
I = (8.4 kg)(0.000016 m²)
I = 0.0001344 kgm²
I = 1.344 × 10⁻⁴ kgm²
The rotational inertia of the wheel is 1.344 × 10⁻⁴ kgm²
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A rocket is launched with horizontal velocity of 42.3 m and a vertical velocity of 78%. what is the rocket's hang time, max vertical displacement, and horizontal displaceuent?
The rocket's hang time if it is launched with horizontal velocity of 42.3 m / s and a vertical velocity of 78% is 30.53 s
If vertical velocity is 78 % then the horizontal velocity must be 22 %
So 1 % = 42.3 / 22 = 1.92 m / s
Vertical velocity = 78 * 1.92
Vertical velocity = 149.97 m / s
Initial velocity, u = √ uy² + ux²
u = √ ( 149.97 )² + ( 42.3 )²
u = √ 22491.82 + 1789.29
u = 155.82 m / s
tan θ = uy / ux
tan θ = 149.97 / 42.3
tan θ = 3.55
θ = 74.3°
a ) Hang time,
T = 2 u sin θ / g
T = 2 * 155.82 * sin 74.3° / 9.8
T = 30.53 s
b ) Maximum vertical displacement,
H = u² sin²θ / 2 g
H = 155.82² sin²( 74.3 ) / 2 * 9.8
H = 644.16 m
c ) Maximum horizontal displacement,
R = u² sin 2θ / g
R = 155.82² sin² ( 74.3 ) / 9.8
R = 2283.3 m
Therefore,
a ) Hang time = 30.53 s
b ) Maximum vertical displacement = 644.16 m
c ) Maximum horizontal displacement = 2283.3 m
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full answer = brainliest
Answer:
F = 2N
Explanation:
Moment of 3.0N = 3 × (90 - 50)
3×40
= 120Ncm
Moment of 2.0N = 2.0 × 30
= 60Ncm
Value of F = F × 30
= 30F
60 + 30F = 120
30F = 120 - 60
30F/30 = 60/30
F = 2N
. a 1.20 kg box is firmly attached to a spring with a spring constant of 32.0 n/m (the other end of the spring is attached to a wall); the surface the box is on is frictionless surface. you stretch the spring by 0.500 m and hold the box steady for a moment. you then begin pushing it with a constant 4.00 n force directed parallel to the surface (the figure shows the point where the spring is neither stretched nor compressed and the direction of the force you apply). hot compress will the spring will the spring be at the next instant the box is at rest?
If the spring is pushed with a constant force of 4 N force directed parallel to the surface, the spring will be compressed by 0.5 m at the next instant the box is at rest.
Us = 1 / 2 k x²
W = F x
Us = Potential energy of the spring
k = Spring constant
x = Displacement
F = Force
W = Work done
k = 32 N / m
F = 4 N
xi = 0.5 m
According to law of conservation of energy,
Change in potential energy = Total Work done by the force
1 /2 k xf² - 1 / 2 k xi² = F xf + F xi
1 / 2 * 32 ( xf² - 0.5² ) = 4 ( xf + 0.5 )
4 ( xf² - 0.25 ) = xf + 0.5
4 xf² - xf - 1.5 = 0
This is in the form of a quadratic equation,
x = - b ± √ ( b² - 4 a c ) / 2 a
a = 4
b = - 1
c = - 1.5
xf = - ( - 1 ) ± √ [ ( - 1 )² - ( 4 * 4 * -1.5 ) ] / ( 2 * 4 )
xf = 1 ± √ 25 / 8
xf = 1 ± 5 / 8
xf = 0.75 or - 0.5
Since it is compressed,
xf = - 0.5 m
Therefore, the spring will be compressed by 0.5 m at the next instant the box is at rest.
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8) The weight of a pony standing still on Earth is 1025N.
What is the pony's mass?
A)
m=
g
g
1025 N
9.8 m/s²
JP
C) Where will the pony weigh the least (Moon, Jupiter, impossible)?
pick one of these three
D) Where will the pony have less mass (Moon, Jupiter, impossible)?
pick one of these three
Explanation:
mass = newton ÷ g
m = 1025 ÷ 10
mass= 102.5kg
The dock workerbpushes on a 1200 N crate but it doesnt move. How much work is performed by him.
Work is performed by him is zero.
What is work?Work in physics is the energy that is transferred to or from an item when a force is applied along a displacement. In its simplest form, it equals the product of the force's magnitude and the distance traveled for a constant force directed in the direction of motion.
Given in the question a force of 1200 N crate but it doesn't move.
Work = force x distance. In units, Joules = Newtons x meters.
So: Work = 1200 Newtons x 0 meters
Work = 0 joules.
Work is performed by him is zero.
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one example of these kinds of economic activities is ____
One very good example of kinds of economic activities simply is buying and selling goods.
How buying and selling of goods an an economic activitiesEconomics simply refers to the study of social science which human relationship in relationships with ends and and scarce means which have alternative uses.
However, economics from the description above also involves the buying and selling of goods or products. These selling of these goods is also a function of the quantity demanded.
In conclusion, we can now confirm and deduce from the explanation given above that we the quantity of goods demanded will determine its sales.
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at what stage of solar system formation is the sun extremely active and gas is blown out to the outer solar system by the suns radiation pressure and strong solar wind
Using the theories of solar system, we got that at stage-2 of solar system formation is the sun extremely active and gas is blown out to the outer solar system by the suns radiation pressure and strong solar wind.
Protostar is created as the gas collapsed over the time, it became denser and hotter. Over time, the spherical inner core started forming, which was hotter than rest of the star.
Most of the collapsing mass which is collected in the center, forming the Sun, while the rest of the mass flattened into a protoplanetary disk out of which the planets, moons.
Hence, the stage of solar system formation in which the sun extremely active and gas is blown out to the outer solar system by the suns radiation pressure and strong solar wind is stage-2.
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the ebola virus can often have symptoms similar to bacteria pneumonia, an infection of these symptome include chest pain, shortness of breath and fever. which statement best summarize the differen es betweens these two diseas?
The statement that best summarizes the difference between the two diseases is viruses are not living organisms, but bacteria are living. The correct option is b.
What are viruses and bacteria?Bacteria are living organisms, and they are both bad and good, they come under archaea. They are present everywhere on earth. Viruses are a non-living entity, and it only gets alive when it gets a living body or host.
Since bacteria can also proliferate, not just viruses, there is no difference. There is something known as "good bacteria," but the virus is frequently the one that is more hazardous.
Therefore, the correct option is b. Viruses are not living organisms, but bacteria are living.
To learn more about viruses and bacteria, refer to the link:
https://brainly.com/question/21825429
#SPJ1
The question is incomplete. Your most probably complete question is given below:
a. Viruses can replicate because they are living organisms, while bacteria cannot.
b. Viruses are not living organisms, but bacteria are living.
c. Viruses can be beneficial to living organisms, but bacteria are often infectious.
d. Viruses are living organisms, while bacteria are not.
Advanced Wireless Services (AWS) is a wireless telecommunications spectrum band used for mobile voice and data services, video, and messaging. The AWS band uses frequencies in several segments: from 1695 to 2200 MHz. a) Determine the corresponding range of wavelengths used by the AWS mobile devices. b) To what region/band of electromagnetic spectrum does the range belong
Given data
*The given frequency is
[tex]f_1_{}=1695\text{ MHz}=1695\times10^6\text{ Hz}[/tex]*The another given frequency is
[tex]f_2=2200\text{ MHz=}2200\times10^6\text{ Hz}[/tex]*The given speed of light is c = 3.0 × 10^8 m/s
(a)
The formula for the wavelength is given as
[tex]\lambda_1=\frac{c}{f_1}[/tex]Substitute the known values in the above expression as
[tex]\begin{gathered} \lambda_1=\frac{(3\times10^8)}{(1695\times10^6)^{}} \\ =0.176\text{ m} \end{gathered}[/tex]The another wavelength for the another frequency is calculated as
[tex]\begin{gathered} \lambda_2=\frac{c}{f_2} \\ =\frac{(3.0\times10^8)}{(2200\times10^6)} \\ =0.136\text{ m} \end{gathered}[/tex](b)
Radio spectrum is an electromagnetic spectrum where the frequency range belongs of wireless telecommunication.