a 36 n box is pulled at a constant horizontal velocity across a table with a force of 27 n. what is the coefficient of friction between the box and the table?

The pendulum's length should be decreased to 0.9840 m.

Given that, clock loses 26 s per day

Length of the pendulum = 0.9930 m

In a day there are, 24* 60* 60 = 86400 sec/day

We know the formula for time period as ,

T = 2π √(l/g)

⇒ 2π* √(0.9930 / 9.8) = 2.00005277 sec

Error ratio = 26/86400 = 0.00030093 = 3.009 * 10⁻⁴

T error = 2.00005277 * 3.009 * 10⁻⁴ = 6.0181 * 10⁻⁴

T correct = T original - T error

⇒ 2.00005277 - 0.00060181 = 1.99 sec

T = 2π √(L/g), where L is the new length

Making L as subject, we have,

L = g* T²/ 4π² = 9.8* 1.99² / 4* 3.14² = 38.81/39.44 = 0.9840

Thus, to obtain the correct time, reduce the length of the pendulum to 0.9840m.

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Parallax of vega is observed to be 0.13 arc seconds when observed from the standard base of 1 AU.

a) 7.713 parsec is the distance to vega in parsecs.

Thus, 25.15 light year is that distance in light years.

When the distance is large enough that the parallax angle is very small, the parallax angle is proportional to the inverse of the distance (1/d). Conversely, if we can measure the parallax angle, we know that the distance to the object is proportional to the inverse of that angle.

Given that,

the distance between sun and vega = d

distance between sun and earth = L

angle (θ) = 0.13 arc second

θ = 0.13 × 0.000278°

θ = 3.61 × 10⁻⁵

tan θ = 1 AU /d

or, d = 1 AU / tan θ

or, d = 1 AU / tan (3.61 × 10⁻⁵)

or, d = 1.591 × 10⁶ AU

and 1 AU = 4.848 × 10⁻⁶ parsec

Thus, d = 7.713 parsec.

1 AU = 1.581 × 10⁻⁵

d = 25.15 light year.

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An airspeed indicator's red line represents the top speed an aircraft can fly in calm air; this speed should never be purposely exceeded. The never-exceed speed is the name given to this speed.

The values are given in meters. The trail will be white if the plane is less than 100 meters in the air. If the trail is higher than 100 meters, it will first turn yellow, then green, then light blue, dark blue, purple, and finally red at an altitude of more than 2500 meters. Hope this was helpful. On one of their wings, most commercial aircraft have a green light, and on the other, a red light. The green light is positioned on the right wing of the aircraft, while the red light is on the left wing.

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It took 5 minutes to establish the universe's primary chemical makeup.

Nucleosynthesis is the process by which new atomic nuclei are produced from pre-existing nuclei and nucleons (protons and neutrons). According to current beliefs, a process known as Big Bang nucleosynthesis took place a few minutes after the Big Bang to produce the first nuclei through nuclear reactions.

Star nucleosynthesis offers hints on both stellar evolution and the distribution of matter across the cosmos in space-time. Chemical abundances inside the solar system, which attest to their abundance at the time of solar system creation, provide a probe to nucleosynthesis in our galaxy.

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The formula for calculating elastic potential energy stored in spring is elastic potential energy = 0.5 × spring constant ×extension square.

When an elastic body is deformed, energy stored in the body is called elastic potential energy. This energy gets stored in the object till the time it is deformed. When force is removed, this energy changes into kinetic energy.

An object that can store elastic potential energy has a high elastic limit. When an object is deformed beyond the elastic limit, it can not gain its shape after removing force.

The force that is needed to stretch the spring is directly proportional to its displacement. It is given as

F =k x

Wherein,

k = spring constant

x = displacement

The Elastic Potential Energy Formula of the spring stretched is given as

P.E. = 1/2 k

Where,

P.E = elastic potential energy and it’s expressed in Joule.

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110 J, the lever lift with an input force of 20. 0 n is 110 J.

The solution:The ratio of a lever's effort arm to its load arm determines its mechanical advantage.This is also known as the lever principle.

The pulley's raised object is referred to as the load, and the force needed to lift it is referred to as the effort force.Inside the diagram, a pulley is used to raise a block of wood by applying a force F, also known as the effort force.The load is typically multiplied by the number on ropes to determine the effort.

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With a wetted area of 3500 square metres and a length of 125 metres, a ship can travel at a maximum speed of 7.2 m/s. Power output from propellers is 1100 kilowatt. Also disregarded is wave drag.

The speed of a change in an object's location in any direction. Speed is defined as the ratio of distance to the amount of time it took to cover that distance. Due to its lack of magnitude and merely having a direction, speed is a scalar number. Power is the quantity of energy that is transferred or transformed in a certain length of time. The watt, which is equal to one joule per second in the International System of Units, is the unit of power. Power may also be referred to as activity in earlier writings.

R is equal to 1025*125/0.00107 power, or 0.0217 v(1025/2).

V^2*3500\sV =7.2m/s

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The mass must be added to the object to change the period to 1.90s is 0.428Kg.

A thing's time period is the length of time needed for it to complete one oscillation. Any wave element's angle displacement in relation to time is known as its frequency. T is the period, and f is the frequency, and the formula for time is T = 1/f. equals c / f, where c is the wave speed (m/s) and f is the frequency (Hz).

A mass of 0.460 kg oscillates with a period of 1.90 s when it is suspended from a spring.

The time period's formula is provided by,

T = 2π √m/k ....(1)

K denotes the spring's constant, and m denotes the mass.

The new duration is specified by,

T' = 2π √m'/K....(2)

where K is the spring constant, and m' is the final total mass following the addition.

Subtract equation (1) from equation (2).

T/T' = √m/m'

Now change the previously mentioned expression with the known terms.

1.5/1.9 = √0.46/m'

To find the value of m', simplify the expression above.

m' = 0.5/0.5625

m' = 0.888kg

Now, we can calculate the mass that must be added to the object to make the period 1.90s:

m' = 0.889 - 0.460

m' = 0.428Kg.

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The hallmark of perceptual processes is the ability to determine that the direction of an object—even one that is not of a perceptual species—is the proper response. (Select A).

Direction can refer to a thing's course, the route one must follow to get there in particular, the direction something is beginning to take shape, or the direction you are facing. Going straight instead than left is an example of direction.

One is given instructions when they are given what to do and in what order. You are provided a set of instructions for many of your homework tasks and assessments. Understanding the motivation behind the instructions is crucial.

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The focal length of projection lens is  0.039m.

The opposite of a concave lens is a convex lens. Contrary to concave lenses, light rays converge in convex lenses. In contrast to the concave lens, the convex lens is bigger in the middle and thinner at the edges, therefore it converges the incident rays into its central axis.

Instead of being bent inward, the convex lens' edges are curved outward. The image seems smaller and inverted when the light is extremely focused beyond the focal length of the lens.

A convex lens's opposite side's center of curvature, , creates the image of an object placed in the center of curvature, , of the lens. As seen in the given illustration, the picture that forms is inverted and the same size as the object.

The image is inverted

h/H

= -1.8/0.024

the distance from slide to screen d=p+q=76p

M =75

d=p+q=76p

p= 0.0395m

p= 39.5cm and q = 75p = 2.96

and

a)1/0.395+1/2.96=1/f

f = 0.039m

b) from above p = 39.5 mm

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The statement "The angular momentum of the propellers of a small airplane point directly forward from the plane" is false.

Angular momentum is a measure of an object's rotational motion and is defined as the product of the object's moment of inertia and its angular velocity. In the case of an airplane, the propellers spin about an axis that is perpendicular to the plane's direction of motion, so the angular momentum of the propellers points in the direction of this axis.

This direction is not necessarily directly forward from the plane and can vary depending on the orientation of the propellers and the plane's motion. Therefore, it is not true that the angular momentum of the propellers of a small airplane points directly forward from the plane.

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The slit width to wavelength ratio due to which the first minimum of single slit diffraction pattern appears = 1 : 0.5

According to the question, we know that we have to calculate the ratio of slit width to wavelength,

Given, A single-slit diffraction

The angle at which the diffraction pattern is occurring = 30°

Order of diffraction given  = 1 ( minimum )

We could calculate the path diffraction using the formula,

d sinθ = nλ ( minimum )

d sin 30 = 1 x λ

d / λ = 1 / sin 30

d / λ = 1 / 0.5

d : λ = 1 : 0.5

Therefore, the slit width to wavelength ratio due to which the first minimum of single slit diffraction pattern appears = 1 : 0.5

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The mass of the bowling ball is 5kg and the energy of player will be 62.5 kcl. With the denominator is greater the acceleration should decrease by the same factor that increases the mass.

Newton's second law states that force is proportional to mass and acceleration.

F = m a

The applied force creates an acceleration in the elephant a = F / m. If the mass of the elephant increases m2> m, the expression takes the form a = F / m2. With the denominator is greater the acceleration should decrease by the same factor that increases the mass.

The frequency of a wave depends on the properties of medium density and the elasticity properties change the amplitude depends on the energy carried by the wave, that is, the amplitude is proportional to the height of the wave (oscillation).

Therefore, The mass of the bowling ball is 5kg and the energy of player will be 62.5 kcl. With the denominator is greater the acceleration should decrease by the same factor that increases the mass.

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When the ball is released from rest 2m from the ground, it will hit the ground at 0.63 seconds.

Here, we will use free fall kinematics equations.The ball hits the ground due to gravity of earth. we use equation of motion and will find time after which ball hit the ground. There are 3 main equations of motion. The paper ball falls from the rest, so the initial velocity will be 0.

[tex]s = ut + \frac{1}{2} a {t}^{2} [/tex]

S is the height

u is the initial velocity

g is the gravity (9.81 m/s²)

t the time

Now, the height will be 2m, u = 0

and we have to solve it for t

[tex]2 = 0 \times t + \frac{1}{2} \times 10 \times {t}^{2} [/tex]

[tex]2 = 5 {t}^{2} [/tex]

[tex] {t}^{2} = \frac{2}{5} [/tex]

t = 0.63

t = 0.63 seconds.

hence, the ball will hit the ground after 0.63 seconds of it's release.

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Because the range of the Coulomb force is longer, heavier atoms have more neutrons than protons.

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Michael and the cart exert equal and opposite forces on each other.

When equal and opposite force is applied, it do not let the body to move. This equal and opposite force is called couple.

Whenever two equal and opposite forces act on a moving object, motion remains unaffected because the net force acting on the body is zero. Thus, the object will not move.

This basically justifies Newton's third law of motion which states, for every action (force) in nature there is an equal and opposite reaction. If object A exerts a force on object B, object B also exerts an equal and opposite force on object A.

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In the question, the floating level is known as upthrust. It happens due to the density of that object.

Upthrust is an upward force on an object (in this case the wooden block) provided by the liquid (water) as a result of it displacing some of the liquid. Thus floating objects will normally displace some part of the liquid; making some part of it to be submerged in water.

The percentage of the submerged wooden block can be calculated as

length (in height) of the wood block submerged in water/total length (in height) of the wood × 100

This concept is based on the density of the floating object.The concept of density seeks to measure the weight of an object in relation to its size. It is the measure of how packed together the particles of that object are.

An object placed in a liquid displaces a certain volume of the liquid, based on the relative density of the object and the liquid.

If an object is less dense than a liquid in which it is placed, it displaces a smaller volume of the liquid than its volume, hence only some part of the object will be seen to be under the liquid, the other part will float.

If an object is denser than the liquid in which it is placed, it displaces a larger volume of the liquid than its own volume, making the object to sink and is submerged.

Therefore, if the density of an object and the liquid into which it is submerged is the same. the object's mass per unit volume is the same as the liquid's mass per unit volume.

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Answer:

the answer is 0.5 m/s it's c

the period of revolution of the space station is 25.1 seconds.

Calculation :

acceleration ac=v2/r

velocity v=(2*pi*r)/T

therefore T2 = (4*pi²*r)/ac

                 = (4*pi²*40)/2.5  

                given, diameter = 80m  therefore  radius  r=40m

                 =  25.1 seconds

A space station is a spacecraft capable of supporting a human crew in orbit for long periods of time, and is therefore a kind of living space in space. No greater propulsion or landing system. An orbital station or orbital space station is a satellite (that is, a type of orbital spaceflight). A station needs a docking port so that other spacecraft can dock to transfer crew and supplies. The purpose of maintaining an orbital outpost varies by program. The space station was launched primarily for scientific purposes, but military launches have also taken place.

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When operating at a frequency of 10 GHz, 16.54 cm is needed to reduce the fields of this mode's magnitude by 20 dB.

Given,

f=18 GHz,

TE₁₀ mode,[tex]f_{c}[/tex]=12GHz

wave length,λ=?,phase constant ,β=?

d=? when magnitude by 20dB

if the operating frequency is 10 GHz

defined, F₁₀=[tex]\sqrt{1-(\frac{f_{c} }{f})^{2} }[/tex] = [tex]\sqrt{1-(\frac{12}{18})^{2} }[/tex] = 0.75

wavelength,λ₁₀=λ₀/F₁₀=1/0.75=1.33cm

phase constant ,β₁₀=2π/λ₁₀ =2π/(1/0.75)*10⁻²

β₁₀=2π*0.75*100

β₁₀=150π rad/m

for operation below the cutoff frequency,

[tex]r_{mn}[/tex]=[tex]\alpha_{mn}[/tex]=[tex]\sqrt{4\pi^{2}\mu \epsilon(f_{c}^{2}-f^{2}) }[/tex]

[tex]\alpha _{10}[/tex]=[tex]\beta \sqrt{(f_{c}/f)^{2} -1 }[/tex]

here,[tex]\beta =\frac{2\pi f}{u_{0} }[/tex]

[tex]\beta[/tex]=6.67π rad/m

α₁₀=6.67π[tex]\sqrt{(12/10)^{2}-1 }[/tex]

α₁₀=13.9 [tex]N_{p}[/tex]/m

[tex]e^{-\alpha_{10}d }[/tex]=1/10

-α₁₀d=-2.3

d=2.3/139

d=16.54cm

The number of waves that pass a fixed point in a unit of time is known as the frequency in physics. It is also the number of cycles or vibrations that a body in periodic motion experiences in a unit of time. When a body in periodic motion moves through a series of events or locations before returning to its initial state, it is said to have experienced one cycle or one vibration. moreover, simple harmonic motion; angular velocity.

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The final temperature of the gas will be 40 degrees Celsius.

The average kinetic energy of gas particles is proportional to the absolute temperature of the gas, and all gases at the same temperature have the same average kinetic energy.

The temperature of a substance is directly related to its kinetic energy. Kinetic energy is the energy that a substance has because  its molecules are in motion, so when a substance absorbs heat, the molecules move faster and the  kinetic energy of the substance increases.

As the average kinetic energy of its particles increases, the  thermal energy of the object increases. Therefore, the thermal energy of an object increases as its temperature increases. Since the average Kinetic Energy has doubled, so has the absolute temperature.

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The energy stored in the spring is 4 j when it is stretched 0.40 meters; the spring constant is 50 nm.

Elastic potential energy to define is the potential energy stored in spring when it is stretched by an external force. The energy remains stored before force is removed.

The force that needed to stretch the elastic body is directly proportional to displacement, means extension. It is given as

F =kx

Wherein,

k = spring constant

x = displacement

The Elastic Potential Energy Formula of the spring stretched is given as

P.E. = 1/2 k[tex]x^{2}[/tex]

Where,

P.E = elastic potential energy and it’s expressed in Joule.

To calculate P.E. =1/2 ×0.5 ×0.4 × 0.4 j

                           = 4j

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The pressure doubles and the density of sample of gas remains the same when the absolute temperature of a sample of monatomic ideal gas is doubled at constant volume.

The effect of doubling the absolute temperature of a sample of a monoatomic ideal gas is that, the pressure doubles and density of the sample of gas remains the same.

According to ideal gas equation; PV = nRT; Where P is pressure and V is the Volume, n is the number of moles, R is the ideal gas constant and T is the absolute temperature.

Therefore, when the temperature of the mono atomic ideal gas is doubled, the pressure of the gas will also doubles.

However, in a closed chamber mass of the ideal gas is invariant, since density depends only on the mass and volume therefore the density of the ideal is gas will remain the same.

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It is assumed that,

Initial speed of the vehicle: u = 50 mph = 73.34 ft/s

Finally, it stops, or v = 0 (car deceleration, a = - 44 ft/s2).

The distance traveled before the car comes to a stop must be determined. Allow the distance to be s. The third law of motion can be used to compute it as:

v² - u² = 2as

s = v² - u²/ 2a

s = 0 - ( 73.34 ft / s )² ÷ 2 - {-44} ft/ s²

s = 61.13 ft

Therefore, the car travels 61.13 feet before coming to a stop. As a result, this is the necessary solution.

Deceleration is the opposite of acceleration. The deceleration will be computed by dividing the final velocity minus the initial velocity, by the amount of time is taken for this drop in velocity.

If the deceleration is constant, we know that stopping distance is equal to the area under the v − t graph or D s = 1 2 × v × t s, where ts is the stopping time. So D s = 1 2 × 13.4[m / s] × t s[s] = 0.030 m.

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The coefficient of friction between the rope and the support is 0.34

The amount of friction between two surfaces is measured by the coefficient of friction, or. A low coefficient of friction value means that less effort is needed to cause sliding than would be needed if the coefficient of friction were to be high.

We have to solve this problem by making use of the Capstan's equation

The equation is given as:

[tex]T_{load } = T_{hold} e^u^o[/tex]

u is μ , the coefficient of friction

o is Φ

the load = 7000

the hold support is 100N

Φ = 2π for a complete rotation

given that the rope is wrapped for 2 times we would have Φ = 4π

then

[tex]7000 = 100e^u^4^\pi[/tex]

take the log of both sides

u = log7000 / 100*4π

u = 0.338

Hence the coefficient of friction from what has been calculated is 0.34

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Mechanical energy is not conserved because the roller coaster loses energy due to friction and air resistance as it travels down the track.

In a roller coaster, the energy changes from potential energy to kinetic energy and back again many times over the course of a ride.

As there are external forces acting on the system, the mechanical energy will not be conserved.

When the coaster moves down the track, the amount of available mechanical energy decreases throughout the ride because of the friction between the track and coaster and air resistance. These two forces absorb energy from the cart and transform it into thermal energy as well as sound energy, which is then lost to the surrounding.

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The initial speed of that car assuming a level road is 29.63 m/s.

The acceleration of the cars is calculated by applying Newton's second law of motion as shown below.

F = μmg

ma = μmg

a = μg

where;

The acceleration of the cars is calculated as follows;

a = 0.7 x 9.8 m/s²

a = 6.86 m/s²

The initial speed of the car is calculated by applying the following kinematic equation as shown below.

v² = u²  - 2as

where;

the final velocity of the car when it stops = 0

0 = u²  - 2as

u² = 2as

u = √ (2as)

u = √ (2 x 6.86 x 64)

u = 29.63 m/s

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Time taken by the ball to reach its original height is 4 seconds.

The vertical motion is a motion that occurs when we toss an object completely up. Because the initial velocity or force is only applied in the vertical axis, this motion only moves vertically; if there is any horizontal movement, the air is to blame.Because a uniformly accelerated motion typically goes in the "x" axis, the vertical motion could be viewed as a version that moves in the "y" axis. The acceleration of the vertical motion will be equal to the gravity, therefore it can be thought of as a uniformly accelerated motion.

Given that gravity is an acceleration that points downward, it will always have a negative sign. One of the key prerequisites for vertical motion is that the object's initial velocity must be greater than zero; otherwise, the object will begin to rise and slow down until its initial velocity equals zero, at which point it will begin to fall and its velocity will steadily increase in the opposite direction until it collides with the ground.

The time take by the ball to reach back to its original height will be equal to twice of time taken to reach its maximum height.

According to the kinematic equations of motoion we know that

v = u + at

Here v = final velocity, u = initial velocity , a = acceleration, t = time taken to reach maximum height

We know that;

v = 0 m/s

u = 19.6 m/s

g = -9.8 m/s^2

Thus

t = v - u/a

 = 0 - 19.6/ (-9.8)

= 2s

Thus time taken by the ball to reach its original height is 2 x t = 4s.

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Answer:

No the car did not skid

Explanation:

What is kinetic friction?

Kinetic friction is all about trying to stop one surface from skidding against another surface. When you have two things such as the wheel and the ground sliding against each other, this is kinetic friction.

Given:

The distance cover by the car is 3.5 m

radius ,r = 0.25m

Hence ,

The disctance the car will cover :

s = revolution x 2πr

s = 3 x 2*(3.14)*0.25

s = 4.71 m

Thus the car should cover 4.71 m but it only completes 3.5m as per given scenario.

Hence , the car will not skid.

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The magnitude of torque about the point where the beam is bolted into place is 12544 Nm.

The length of the beam = l = 4 m

The mass of the steel beam = M = 500 Kg

Mass of the construction worker = m = 70 Kg

Torque of steel beam = T₁

Torque of worker = T₂

The magnitude of torque = T =

Torque is the force in a distance the relation is proportional so the torque of weight first is:

= Torque of steel beam = Force of steel beam X distance

= T₁ = F₁ X d

= T₁ = M X g X l

= T₁ = 500 X 9.8 X 4

= T₁ = 9800 Nm

Torque is the force in a distance the relation is proportional so the torque of weight second is:

= Torque of steel beam = Force of steel beam X distance

= T₂ = F₂ X d

= T₂ = m X g X l

= T₂ = 70 X 9.8 X 4

= T₂ = 2744 Nm

Net torque = T =

= T = T₁ + T₂

= T = 9800 + 2744

= T = 12544 Nm

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