5(2x-7)+42-3x=2 what is the answer

Answers

Answer 1

Problem

5(2x-7)+42-3x=2 what is the answer ​

Solution

For this case we can distribute the terms on this way:

10x -35 +42 -3x = 2

Now we can aggrupate similar terms and we got:

7x= 2+35-42

7x = -5

And then solving for x we got:

x= -5/7


Related Questions

Which of the following graphs represents the equation 3x + 2y = 24?

Answers

Answer:

C

Step-by-step explanation:

if x=0

2y = 24

2/2 y = 24/2

y = 12


if y =0

3x = 24

3/3 x = 24/3

x = 8

For each table below, describe whether the table represents a function that increasing or decreasing.

Answers

To determine the table that represents a function that is increasing, we check if the following holds.

• When x increases, f(x) increases.

In Options A, as x increases, f(x) increases.

In Options B, as x increases, g(x) decreases.

In Options C, as x increases, h(x) decreases.

In Options D, as x increases, z(x) increases.

Therefore, the table that

Ciara has a bag of 50 colored marbles. There are yellow, green, and white marbles. She empties the bag, sorts the marbles, and counts11 yellow marbles and 19 green marbles. She wants to write a ratio of the number of green marbles to the number of white marbles. How can she find the number ofwhite marbles without counting them?

Answers

The total number of marbles is, 50.

11 yellow marbles

19 green marbles

x be the number of white marbles.

Without counting, x can be calculated as,

[tex]\begin{gathered} 11+19+x=50 \\ x=50-11-19=20 \end{gathered}[/tex]

Therefore the ratio of green marbles to white marbles is,

[tex]\frac{G}{W}=\frac{19}{20}[/tex]

Thus option B is correct.

find the ratio of the primeter to the area of the square

Answers

Given data:

The given figure of square.

The perimeter of the square is,

[tex]P=4(x+3)[/tex]

The area of the square is,

[tex]A=(x+3)\times(x+3)[/tex]

The ratio of the perimeter to the area of the given square is,

[tex]\begin{gathered} \frac{P}{A}=\frac{4(x+3)}{(x+3)(x+3)} \\ =\frac{4}{x+3} \end{gathered}[/tex]

Thus, the ratio of the perimeter to the area of the given square is 4/(x+3).

6cmA bakery sells hollow chocolate spheres. The larger diameter of eachsphere is 6 cm. The thickness of the chocolate of each sphere is 0.65 cm.Part A: What is the amount of chocolate in each hollow sphere? Stateyour answer to the nearest tenth of a cubic centimeter.o

Answers

As given by the question

There are given that the larger diameter of each sphereis 6 cm.

Now,

(A).

From the formula of volume:

[tex]V=\frac{4}{3}\pi\times r^3[/tex]

Then,

[tex]\begin{gathered} V=\frac{4}{3}\pi\times r^3 \\ V=\frac{4}{3}\pi\times(3)^3 \\ V=\frac{4}{3}\pi\times27 \\ V=4\pi\times9 \\ V=113.097 \end{gathered}[/tex]

Now,

From the formula without thickness:

[tex]\begin{gathered} V=\frac{4}{3}\times\pi\times r^3 \\ V=4\times\pi\times1.5 \\ V=18.8495 \end{gathered}[/tex]

Then,

[tex]\begin{gathered} V=113.097-18.8495 \\ V=94.2475 \\ V=94.2cm^3 \end{gathered}[/tex]

Hence, the volume of chocolate is 94.2 cm^3.

Find the area of the figure. Remember to label use ^2 for units squared.10 ft15 ftA=12 ft

Answers

Solution

Find the area of the figure.

Area of the figure : Area of a parallelogram = base x height

base = 15ft

height = 10ft

[tex]\begin{gathered} A=bh \\ A=(15\times10)ft^2 \\ A=150ft^2 \end{gathered}[/tex]

Therefore the area of the figure = 150ft²

write the equation of the line that is perpendicular to the graph of y=3/4x-3, and whose y-intercept is -8

Answers

write the equation of the line that is perpendicular to the graph of y=3/4x-3, and whose y-intercept is -8

step 1

Find the slope of the given line

y=(3/4)x-3

the slope is m=3/4

step 2

Find the slope of the perpendicular line

REmember that

If two lines are perpendicular, then the product of their slopes is equal to -1 (inverse reciprocal)

so

the slope of the perpendicular line is

m=-4/3

step 3

Find the equation of the line

we have

m=-4/3

y-intercept is -8

so

b=-8

y=mx+b

substitute

y=-(4/3)x-8

Part 2

write an equation of the line that is parallel to the graph of y=-4x-9, and whose y-intercept is 3

step 1

Find the slope of the given line

y=-4x-9

the lope is m=-4

step 2

Find the slope of the parallel line

Remember that

If two lines are parallel, then their slopes are the same

so

the slope of the parallel line is m=-4

step 3

Find the equation of the line in slope intercept form

y=mx+b

we ahve

m=-4

b=3

substitute

y=-4x+3

PLEAS WILL GIVE BEST RATE OR BRANILEST NEED HELP ASAP

Answers

Given figure is of a quadrilateral, with four sides.

We have, the sum of all the interior angles in a quadrileteral is 360.

Thus, we have,

[tex]80+95+38+x=360[/tex]

Solving for x, we have,

[tex]\begin{gathered} x+213=360 \\ x=360-213=147 \end{gathered}[/tex]

Thus, x = 147.

2 3/4 divided by 10
Find the quotient. If possible, rename the quotient as a mixed number or a whole number. Write your answer in simplest form, using only the blanks needed.

Answers

The quotient is 11/40.

What is a mixed number?

It is formed by combining three parts a whole number, a numerator and a denominator. Here, the numerator and denominator are  a part of the proper fraction that makes the mixed number. These are also known as mixed fractions. It contains both an integer or a whole number. A mixed fraction or number is therefore a product of a whole number and a proper fraction.

2 3/4= 11/4

11/4 is divided by 10 then,

It becomes 11/40

So, the quotient is 11/40

Here, 11/40 cannot be converted into a mixed number.

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Area of a triangle = 16ft²B = 4ftH = ?

Answers

Given:

Area of a triangle, A = 16 ft²

Base of the triangle, b = 4 ft

Height of the triangle, h, is unknown.

To find the height of the triangle, h, apply the formula below:

[tex]A=\frac{1}{2}b\times h[/tex]

Rewrite the formula for h.

Multiply both sides by 2:

[tex]\begin{gathered} 2A=\frac{1}{2}b\times h\times2 \\ \\ 2A=b\times h \end{gathered}[/tex]

Divide both sides by b:

[tex]\begin{gathered} \frac{2A}{b}=\frac{b\times h}{b} \\ \\ \frac{2A}{b}=h \\ \\ h=\frac{2A}{b} \end{gathered}[/tex][tex]h=\frac{2A}{b}[/tex]

Where,

A = 16 ft²

b = 4 ft

Substitute values into the formula and evaluate.

We have:

[tex]\begin{gathered} h=\frac{2A}{b} \\ \\ h=\frac{2(16)}{4} \\ \\ h=\frac{32}{4} \\ \\ h=8\text{ ft} \end{gathered}[/tex]

Therefore, the value of h is 8 ft

ANSWER:

H = 8 ft

Julian has a hundred songs on his media player he knows that 1/4 of the song or Jazz and the rest are pop which statement correctly describes the song on Julian media player

Answers

100 songs

1/4 of those are Jazz songs and the rest 3/4 are Pop songs

1/4=0.25

3/4=0.75

To know how many Jazz songs are multiply 100*0.25= 25 Jazz songs

Pop songs: 100*0.75= 75 pop songs

kareem correctly answered 85% of the questions on his math test. He missed 6 questions. How many questions were on his test

Answers

Answer:

40 questions

Explanation:

The total number of questions on his test represents 100%.

So, If he correctly answered 85% of the questions, then he missed 15% of the questions because:

100% - 85% = 15%

Therefore, 15% of the questions are equivalent to 6 questions, then we need to find the number equivalent to 100%. So 100% is equivalent to:

[tex]100\text{ \% }\times\frac{6}{15\text{ \%}}=40[/tex]

Then, there were 40 questions on his test.

Find the speed of each train (set up a table )

Answers

We have two trains that leave Mexico City at the same time, one to the east and the other to the west. The train that travels to the west is 10 mph slower than the other train. The diagram of the problem is:

The combined velocity is:

[tex]V_T=v+v-4=2v-4[/tex]

The equation that relates the distance D between the trains and the time after t hours is:

[tex]D=V_T\cdot t[/tex]

If after 1.5 hours the trains are 171 miles apart, then using the equation above:

[tex]\begin{gathered} 171=V_T\cdot1.5 \\ V_T=\frac{171}{1.5} \\ V_T=114 \\ 2v-4=114 \\ 2v=118 \\ v=59\text{ mph} \end{gathered}[/tex]

Now, the speeds are:

[tex]\begin{gathered} \text{East}\colon59\text{ mph} \\ \text{West}\colon55\text{ mph} \end{gathered}[/tex]

The correct answer is 2 and 5 only please explain why tho

Answers

We have that the graph has inflection points where the slope of the function is "0".

From this function we can see that the slope is "0" when x = 2 & x = 5; in all other places the slope is different from "0".

Is AABC= ADEF? If so, name the postulate that applies.AGiven:ŁAZDZBZE

Answers

Step 1:

Knowing only angle-angle-angle (AAA) does not work because it can produce similar but not congruent triangles.

Step 2:

If the three angles (AAA) are congruent between two triangles, that does NOT mean that the triangles have to be congruent.

Final answer

Option A

Might not be congruent.

A certain paint mixture weighing 300 lb contains 20% solids suspended in water. How many pounds of water must be allowed to evaporate to raise the concentration of solids to 22%?

Answers

Answer:

27.27 lb of water must be allowed to evaporate

Explanations:

Weight of the paint mixture = 300 lb

The paint mixture contains 20% solids suspended in water

Weight of solids suspended in water = (20/100) x 300

Weight of solids suspended in water = 60 lb

Let the weight of the mixture after evaporation be w

[tex]\begin{gathered} \frac{22}{100}\times w\text{ = 60} \\ 0.22w\text{ = 60} \\ w\text{ = }\frac{60}{0.22} \\ w\text{ = }272.73\text{ lb} \end{gathered}[/tex]

The weight of the mixture after evaporation = 272.73lb

The weight of water that will be allowed to evaporate = 300 lb - 272.73 lb

The weight of water that will be allowed to evaporate = 27.27 lb

Therefore, 27.27 lb of water must be allowed to evaporate

Lesson 6: Relate Division and Multiplication Cool-down: A Different Relay Race 1. Lin and Han ran a 5 mile relay race as a team. They each ran the same distance. Dras diagram to represent the situation.

Answers

Lin and Han ran a 5 miles relay race.

If they both ran same distance, that means each of them ran;

[tex]\frac{1}{2}(5\text{miles)}=2.5\text{miles}[/tex]

So, Lin and Han ran 2.5miles each.

The diadramatic representation of this scenario is;

The image above shows a track race of 5 miles divided into two. LIN ran half of it (2.5 miles) and also Han ran the other half, also (2.5 miles)

Solve the compound inequality.3x + 12 ≥ –9 and 9x – 3 ≤ 33 x ≥ –7 and x ≤ –4x ≥ 7 and x ≤ 4x ≥ 1 and x ≤ 4x ≥ –7 and x ≤ 4

Answers

To solve this problem, we will solve each inequality for x and the solution to the system will be the intersection of the solution sets.

1) Solving the first inequality for x we get:

[tex]\begin{gathered} 3x+12\ge-9, \\ 3x\ge-9-12, \\ 3x\ge-21, \\ x\ge-\frac{21}{3}, \\ x\ge-7. \end{gathered}[/tex]

2) Solving the second inequality for x we get:

[tex]\begin{gathered} 9x-3\le33, \\ 9x\le33+3, \\ 9x\le36, \\ x\le\frac{36}{9}, \\ x\le4. \end{gathered}[/tex]

Answer:

[tex]x\ge-7\text{ and x }\le4.[/tex]

add.(7k + 3) + (3k + 2)

Answers

[tex]7k+3+3k+2=7k+3k+3+2=10k+5[/tex]

What is the acceleration of a 50 kg object pushed with a force of 500 newtons?10 m/s225,500 m/s2490 m/s225 m/s2

Answers

Let's use Newton's second law of motion:

F = m*a

Where:

F= Force = 500

m = mass = 50

a = acceleration

So:

500 = 50*a

Solve for a:

Divide both sides by 50:

500/50 = 50a/50

10 = a

a = 10m/s²

change the quadratic equation from standard from to vertex form

Answers

Answer:

[tex]y=\left[x-\left(-2\right)\right]^2+\left(-9\right)[/tex]

Explanation:

Given the quadratic equation in standard form:

[tex]y=x^2+4x-5[/tex]

1. Transpose the c-value to the left side of the equation.

[tex]y+5=x^2+4x[/tex]

2. Complete the square of the expression on the right side of the equation to get a perfect square trinomial. Add the resulting term to both sides.

[tex]\begin{gathered} y+5+(\frac{4}{2})^2=x^2+4x+(\frac{4}{2})^2 \\ \implies y+5+(2)^2=x^2+4x+(2)^2 \end{gathered}[/tex]

3. Add the numbers on the left and factor the trinomial on the right.

[tex]$ y+9=(x+2)^2 $[/tex]

4. Transpose the number across to the right side to get the equation into the vertex form, y=a(x-h)²+k.

[tex]y=(x+2)^2-9[/tex]

5. Make sure the addition and subtraction signs are correct to give the proper vertex form.

[tex]y=\left[x-\left(-2\right)\right]^2+\left(-9\right)[/tex]

The vertex form of the given quadratic equation is:

[tex]y=\left[x-\left(-2\right)\right]^2+\left(-9\right)[/tex]

is it possible for a rhombus to have a angle of 120 degrees and a angle of 30 degrees ? homework question

Answers

Solution:

From the properties of a Rhombus;

Opposite angles of a rhombus are equal.

The adjacent angles of a rhombus are supplementary, i.e. adds up to 180°

If one of the angles of a rhombus 120°, and the sum of the adjacent angles is 180°, then, the adjacent angle will be 60° (180° - 120° = 60°)

If one of the angles of a rhombus is 30°, then, the adjacent angle will be 150° (180° - 30° = 150°)

Thus, the sum of 120° and 30° is not supplementary and definitely can not be adjacent, since they do not sum up to 180°.

Hence, it is not possible

2b^2 (3a - 5b +8c)Multiply

Answers

Answer

2b² (3a - 5b + 8c)

= 6ab² - 10b³ + 16b²c

Explanation

We are told to multiply 2b² with (3a - 5b + 8c)

2b² (3a - 5b + 8c)

= 6ab² - 10b³ + 16b²c

Hope this Helps!!!

2.2Determine the value of n for which (3k - 2) = 70

Answers

The value of k is 24.

From the question, we have

(3k - 2) = 70

(3k) = 72

k=24

Subtraction:

Subtraction represents the operation of removing objects from a collection. The minus sign signifies subtraction −. For example, there are nine oranges arranged as a stack (as shown in the above figure), out of which four oranges are transferred to a basket, then there will be 9 – 4 oranges left in the stack, i.e. five oranges. Therefore, the difference between 9 and 4 is 5, i.e., 9 − 4 = 5. Subtraction is not only applied to natural numbers but also can be incorporated for different types of numbers.

The letter "-" stands for subtraction. Minuend, subtrahend, and difference are the three numerical components that make up the subtraction operation. A minuend is the first number in a subtraction process and is the number from which we subtract another integer in a subtraction phrase.

Complete question: Determine the value of k for which (3k - 2) = 70

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construct the perpendicular bisectors of each side of the triangle. Extend the bisectors until they intersect each other.

Answers

Solution:

Given:

To draw the perpendicular bisector of each side, place the compass at the two ends of the line.

Using the line WX, expand the compass to beyond half of the line and place the compass at the first point (point W), to draw an arc above and below.

Then place the compass at the other point of the line (point X), and draw an arc to intersect the initially drawn arcs.

Join the two points of intersection to get the perpendicular bisector of the line.

Repeat the same for the other two sides to get the perpendicular bisectors.

A real estate agent earned $1,625 for selling a property. If his commission rate is 5%, find the selling price of the property.

Answers

Let x be the selling price of the property, then we know that the 5% of x is $1,625.

Now, recall that the n% of an amount can be computed by multiplying the amount by

[tex]\frac{n}{100}\text{.}[/tex]

Therefore:

[tex]x\times\frac{5}{100}=1625.[/tex]

Solving the above equation for x, we get:

[tex]x=\frac{1625\times100}{5}\text{.}[/tex]

Simplifying the above result, we get:

[tex]x=32500.[/tex]

Answer:

[tex]32500[/tex]

dollars.

Evaluate / Solve b3 + ac – bif a = 4, b=5, and c = 10.A.170B.165C.160D.125

Answers

Answer

Option C is correct.

The answer is 160.

Explanation

We are told to evaluate or solve

b³ + ac - b

if a = 4, b = 5 and c = 10

So, to solve, we will just substitute the given values into the expression to be solved

b³ + ac - b

= (5)³ + (4 × 10) - 5

= 125 + 40 - 5

= 160

Hope this Helps!!!

Figure ABCDE is similar to figure VWXYZ.Solve for the side length of WX.a 1/2b. 3c. 2.5 d 2

Answers

In similar figures the ratio of corresponding sides is the same:

Corresponding sides in given figure:

AB and VW

BC and WX

CD and XY

DE and YZ

EA and ZV

As you know the length of AE and ZV and need to find the value of WX taht is correspondig side of BC, you have the next:

[tex]\frac{ZV}{EA}=\frac{WX}{BC}[/tex][tex]\frac{4}{10}=\frac{WX}{5}[/tex]

You use this equation to find the length of WX:

[tex]\begin{gathered} \frac{5\cdot4}{10}=WX \\ \\ \frac{20}{10}=WX \\ \\ \\ WX=2 \end{gathered}[/tex]Then, the length of WX is 2

Convert 77.6% to an
equivalent decimal.

Answers

Answer:

Step-by-step explanation:

0.776 in decimal form.

Instructions: Find the missing angle. Round your answer to the nearesttenth.

Answers

ANSWER

[tex]x=65.9^o[/tex]

EXPLANATION

We are given a right-angled triangle.

We have that the hypotenuse is 46.

The side opposite the given angle is 42.

The angle given is x.

To solve this, we can use trigonometric ratios SOHCAHTOA.

We will use the SOH part of it:

[tex]\sin (x)\text{ = }\frac{opposite}{hypotenuse}[/tex]

So, we have that:

[tex]\begin{gathered} \sin (x)\text{ = }\frac{42}{46} \\ \sin (x)\text{ = 0.9130 } \\ \text{ Find the sine inverse (sin}^{-1})\text{ of 0.9130 to get x:} \\ x=sin^{-1}(0.9130) \\ x=65.9^o \end{gathered}[/tex]

That is the value of the missing angle x.

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