If a yard contains 36 inches, then 21 inches is the 7/12 fraction of a yard
A yard contains 36 inches
We know
One yard = 36 inches
Here we have to use the unitary method for the conversion
The unitary method is the method of the value of a single unit.
36 inches = 1 yard
Then one inch = 1 / 36 yard
21 inches = (1 / 36) × 21
Multiply the terms
= 21 / 36
Divide both numerator and denominator by 3
= (21 / 3) / (36 / 3)
Divide the terms
= 7 /12 yard
Hence, if a yard contains 36 inches, then 21 inches is the 7/12 fraction of a yard
The complete question is
A yard contains 36 inches. 21 inches is what fraction of a yard ?
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A guidebook says that one night at a mid-range hotel the capital city, republica cost between $25 an $40 us dollars. The hotel capital city offers a one week rental for 150 rp ( republica pounds) the current exchange rate is 1=0.0147 usd ($us dollars) does the price per night at the hotel capitol suggest that it a mid range hotel?
To determine if the hotel capital suggests is a mid-range hot, we need to do the conversion:
[tex]150rp\cdot\frac{0.0147\text{usd}}{1rp}=2.2\text{ usd}[/tex]By the exchange rate 1rp=0.0147usd, notice the rental week of Hotel Capital city is $2.2
Then, for the night:
[tex]\frac{2.2}{7}=0.31[/tex]Then, a night at Hotel Capital City would be $0.31. It is not a mid-range hotel.
Write the equation of the line in slope-intercept form. Through the points (-8, 15) and (6, 15)
Question: Write the equation of the line in slope-intercept form. Through the points (-8, 15) and (6, 15)
Solution:
The equation of the line in slope-intercept form is :
y = mx + b
where m is the slope of the line, and b is the y-coordinate of the y-intercept of the line. Now, the slope of the line is given by the following formula:
[tex]m\text{ = }\frac{Y2-Y1}{X2-X1}[/tex]Where (X1,Y1) and (X2,Y2) are points on the line. In our case, we have that:
(X1, Y1) = (-8,15)
(X2,Y2) = (6,15)
Replacing these values in the equation of the slope we obtain:
[tex]m\text{ = }\frac{Y2-Y1}{X2-X1}\text{ =}\frac{15-15}{6-(-8)}\text{ = 0}[/tex]then we have a horizontal line, because the slope is 0, for that, the equation of the line would be:
y = mx + b = 0(x) + b
then
y = b
now, take any point on the line, for example (x,y) = (6,15). Replacing this value in the previous equation, we obtain that the equation of the line is given by:
[tex]y\text{ = 15}[/tex]Which binomial is a factor of 49x2 + 84xy + 36y2?А. 7х + 6уВ. x+6yC. х- 6уD. 7х- 6уPLEASE HELP ASAP I WILL GIVE YOU BRAINLIEST!!!!!!
Factoring 2nd-degree polynomials make use of the factors of the numerical coefficient of the first and last term.
The numerical coefficient of our first term is 49. The possible factors of 49 are 1 and 49, 7 and 7, -1 and -49, and -7 and -7.
The numerical coefficient of our last term is 36. The possible factors of 36 are 1 and 36, 6 and 6, 12 and 3, 4 and 9, -1 and -36, -6 and -6, -3 and -12, and -4 and -9.
Since the choices only show 1,7 and 6,6, we will only be focusing on these factors. Our goal here would be for us to have a result of +84 when the two pairs of factors are multiplied and then multiplied to two.
The second row gives us the middle term +84. Therefore, the factors of the polynomial are (7x + 6y)(7x + 6y). The answer is Option A.
Use the correct trigonometric function to solve for both x and y .
As per given by the question.
There are given that a triangle.
Now,
Suppose given triangle is ABC.
Then, redraw the given triangle.
Now,
For finding the value of x, and y;
First find the value of x with the help of sine trigonometric function.
So,
[tex]\sin 35^{\circ}=\frac{AB}{AC}[/tex]Then,
Substitute the value x for AB and 22 for AC.
SO,
[tex]\begin{gathered} \sin 35^{\circ}=\frac{AB}{AC} \\ \sin 35^{\circ}=\frac{x}{22} \\ 0.57=\frac{x}{22} \\ x=0.57\times22 \\ x=12.54 \end{gathered}[/tex]Now,
For finding the value of y,
Here, use pythagoras theorem in triangle ABC.
So, from the pythagoras theorem;
[tex]AB^2+BC^2=AC^2[/tex]Then,
Substitute the value in above formula;
So,
[tex]\begin{gathered} AB^2+BC^2=AC^2 \\ x^2+y^2=(22)^2 \end{gathered}[/tex]Now, put the value 12.54 for x,
So,
[tex]\begin{gathered} x^2+y^2=(22)^2 \\ (12.54)^2+y^2=(22)^2 \\ 157.25+y^2=484 \\ y^2=484-157.25 \\ y^2=326.75 \end{gathered}[/tex]Then,
[tex]\begin{gathered} y^2=326.75 \\ y=\sqrt[]{326.75} \\ y=18.076 \end{gathered}[/tex]Hence, the value of x is 12.54 and the value of y is 18.076.
Chauncey is studying a 250-mg sample of a radioasubstance has a half-life of 5 days. Write an equatsubstance, s, is left after n days?aS =b= 250 (3)s = 250 (3)s = 250 (0.5)s = 250 (0.5)$5nd
Answer:
[tex]s=250(0.5)^{\frac{n}{5}}[/tex]Step by step explanation:
Exponential functions are represented by the following expression:
[tex]\begin{gathered} f(x)=ab^x \\ \text{where,} \\ a=\text{initial amount} \\ b=\text{decay factor} \\ x=\text{time(days)} \end{gathered}[/tex]Then, for this situation, we have an initial amount of 250, a decay factor of (0.5) in 5 days:
[tex]s=250(0.5)^{\frac{n}{5}}[/tex]For each of the following, find the Lateral Area, Surface Area, and Volume. Leave answers in terms ofFt, and if applicable, round to the nearest tenth.1. TA =V=A sphere with radius of 21 cm.
Given a sphere with radius R, the volume and the surface area formulas are expressed as:
[tex]\begin{gathered} V=\frac{4}{3}\pi R³ \\ \\ A=4\pi R² \end{gathered}[/tex]Now, if we have a sphere of radius R = 21 cm = 0.688976 ft. Then, using the formulas:
For the volume
[tex]\begin{gathered} V=\frac{4}{3}\pi(0.688976)³ \\ \\ \therefore V=1.37\text{ ft^^b3} \end{gathered}[/tex]For the surface area
[tex]\begin{gathered} A=4\pi(0.688976)² \\ \\ \therefore A=5.97\text{ ft^^b2} \end{gathered}[/tex]triangle QRS is reflected across the y axis to create triangle QRS complete the rule that describes the coordinates of triangle QRS after the reflection has occurred
The rule for describing the reflection of the given figure QRS is as follow:
If the coordinate of each point of the triangle is (x,y), then, after the reflection across the y axis the new coordinates become:
(x,y) => (-x,y)
Answer:
[tex](x',y')=(-x,y)[/tex]
Translate the sentence into an inequality.Twice the difference of a number and 10 is greater than 29.
We will have the following:
[tex]2(x-10)>29[/tex]Can someone help me with this question?
So the average decrease will be 50% for the season of 5 weeks as the definition of percent decrease will be "The difference between starting and ending values is the percentage decrease. It displays a percentage loss of value compared to the original regardless of the units. The difference between the initial and final amounts is the amount of decrease".
What is percent decrease?The difference between starting and ending values is the percentage decrease. It displays a percentage loss of value compared to the original regardless of the units. The difference between the initial and final amounts is the amount of decrease.
Here,
The percent decrease will be,
48000-24000=24000
24000/48000*100=50%
24000-12000=12000
12000/24000*100=50%
12000-6000=6000
6000/12000*100=50%
6000-3000=3000
3000/6000*100=50%
3000-1500=1500
1500/3000*100=50%
Due to the definition of percent decrease being a season of five weeks, the average decrease will be 50% "The percentage decrease is the difference between the starting and ending values. Regardless of the units, it shows a percentage decline in value relative to the starting point. The amount of decrease is the difference between the initial and final amounts ".
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of the exterior angle of a regular octagon measures (11x+1), fond the value of x.
Recall that a regular octagon is an image with eight equal sides and equal internal angles.
So, considering that the exterior angles of any polygon should add to 360 degrees, the addition of the 8 equal exterior angles of the octogon should add to 360.
We are given the expression for each exterior angle as: (11 x + 1)
then, 8 times this should render 360 degrees, and we write an equation that gives such relationship as:
8 * (11 x + 1) = 360
use distributive property to eliminate the parenthesis
88 x + 8 = 360
subtract 8 from both sides:
88 x = 360 - 8
88 x = 352
x = 352 / 88
x = 4
Therefore please type 4 in the given box.
what is the area of a semicircle with a diameter of 2 ?
we have that
the area of semicircle is equal to
[tex]A=\frac{1}{2}\cdot\pi\cdot r^2[/tex]we have
r=2/2=1
substitute
[tex]\begin{gathered} A=\frac{1}{2}\cdot\pi\cdot1^2 \\ A=\frac{\pi}{2} \end{gathered}[/tex]area is equal to pi/2 square unitsA new car worth $27,000 is depreciating in value by $3,000 per year. After how many years will the car's value be $3,000?
The equation for the worth of car after x number of years is,
[tex]\begin{gathered} y=27000-3000\cdot x \\ =27000-3000x \end{gathered}[/tex]Substitute 3000 for y in the equation to obtain the value of x.
[tex]\begin{gathered} 3000=27000-3000x \\ 3000x=27000-3000 \\ x=\frac{24000}{3000} \\ =8 \end{gathered}[/tex]So after 8 years the worth of car is $3000.
Pamela's mother purchased five boxes of candy bars. If each box contains 20 bars, how many candy bars does Pamela's mother have? Explain your answer.
If each box contains 20 bars and Pamela's mother purchased 5 boxes
To get the number of candy bars Pamela's mother have, we will simply multiply the number of box by the number oc candy in each box
That is; 5 x 20bars = 100 candy bars
Hence Pamela's mother have 100 candy bars
need help asap will give you 5 stars! need a quick worker!
Explanation
The question wants us to get the length of the missing side
To do so, we will use the trigonometric ratio:
[tex]undefined[/tex]Im trying to plot a slope function on a graph y=2x+3
1) To plot a linear equation, like y=2x +3 let's visualize the graph
2) Set this function as an equation, to find the root of that function the x coordinate
y= 2x +3 Turn this to an equation
2x +3 =0 Subtract 3 from both sides
2x +3 -3 = -3
2x+0=-3 Divide both sides by 2
x=-3/2 -3/2 = -1.5
Looking at the function, we can see that the slope m=2, m>0, and the y-intercept is 3
Now we can set a table, where we can choose any value for x and then plug it into the function
x = 0 , y = 2(0) +3 y= 3
x= 1, y = 2(1) +3 y= 5
x=-1.5 y = 2(-1.5) +3 y=0
x | y
0 3
1 5
-1.5 0
At least 3 points already determine a line
Our graph must be like this:
Is it always, sometimes, or never true that an equation in slope-intercept form represents a direct variation? Support your answer with examples
It is always true an equation in slope-intercept form represents a direct variation.
For example, the amount of money you earn by hours.
Let:
x = Number of hours
y = Amount of money
a = Money per hour = $5
The equation will be:
[tex]\begin{gathered} y=ax \\ y=5x \end{gathered}[/tex]True or false: Are vertical angles only congruent if they are marked, and why ?
The vertical angles formed when two lines intersected each other at a point
The vertical angles are always equal in mesuaresSorry
So you do not want a mark to know they are equal
The answer is false
Solve the system of linear equations by eliminations-- 3x + 4y = 186x+2y = -6does thia system have a solution?
Which can be the first step in finding the equation of the line passing through (5,-4) and (-1,8)
The equation of the line, in slope-intercept form, is written as
[tex]y=mx+b[/tex]wherein m is the slope of the line and b is the y-intercept.
The first step to solve the equation of the line that passes through two points is to find the slope of the line given two points. The slope of the line can be computed using the equation
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]For points (5, -4) and (-1, 8), the slope of the line is
[tex]m=\frac{8-(-4)}{-1-5}=\frac{12}{-6}=-2[/tex]Now, we have the initial equation of the line written as
[tex]y=-2x+b[/tex]To solve for the value of b, we use one of the points and substitute it on the initial equation above. In my case, I will be using points (5,-4), we have
[tex]\begin{gathered} -4=-2(5)+b \\ -4=-10+b_{} \\ b=10-4 \\ b=6 \end{gathered}[/tex]Hence, the equation of the line that passes through (5,-4) and (-1,8) is
[tex]y=-2x+6[/tex]solve the equation by completing the square.4x(x + 6) = -40
Answer:
The solution to the equation is;
[tex]\begin{gathered} x=-3+i \\ or \\ x=-3-i \end{gathered}[/tex]Explanation:
Given the equation below;
[tex]4x(x+6)=-40[/tex]Expanding the bracket we have;
[tex]4x^2+24x=-40[/tex]dividing through by 4;
[tex]\begin{gathered} \frac{4x^2}{4}+\frac{24}{4}x=-\frac{40}{4} \\ x^2+6x=-10 \end{gathered}[/tex]To solve by completing the square, let us add the square of half of 6 to both sides;
[tex]\begin{gathered} x^2+6x+(\frac{6}{2})^2=-10+(\frac{6}{2})^2 \\ x^2+6x+9=-10+9 \\ x^2+6x+9=-1 \\ (x+3)^2=-1 \end{gathered}[/tex]taking square roots of both sides;
[tex]\begin{gathered} x+3=\sqrt[]{-1} \\ x+3=\pm i \end{gathered}[/tex]So;
[tex]\begin{gathered} x=-3+i \\ or \\ x=-3-i \end{gathered}[/tex]Therefore, the solution to the equation is;
[tex]\begin{gathered} x=-3+i \\ or \\ x=-3-i \end{gathered}[/tex]Determine the possible numbers of positive real zeros, negative real zeros, and imaginary zeros for the function. g(x) =x^5-2x^3-x^2+6
Step-by-step explanation:
Note: The term root and zero are used interchangeably.
Use Descartes Rule of Signs,
For the function, f(x), For every sign change, we have a positive root. If we have at least 2 positive roots, we either have that said number of roots or 2 less number of roots until we reach 0.
For example if we have 8 positive roots, we either have 8,6,4,2, or 0 positive roots
For the function f(-x), For every sign change we have a negative root.. If we have at least 2 negative roots, we either have that said number of roots or 2 less number of roots until we reach 0.
For example, if we have 7 possible roots, we either have 7,5,3,1 possible negative roots.
For g(x), we have 2 sign changes, so 2 positives root or none
[tex]g( - x) = ( - x) {}^{5} - 2( - x) {}^{3} - ( - x) {}^{2} + 6[/tex]
[tex]g( - x) = - {x}^{5} + 2 {x}^{3} - {x}^{2} + 6[/tex]
We have 3 sign changes, so we have 3 or 1 negative roots.
The degree of the polynomial tells us the max possible of zeroes. So the total number of zeroes is 5. That will always be the case for this polynomial so fill every row under the total number columns as 5.
The following possible combinations
2 positive zeroes, 3 negative zeroes, 0 imaginary zeroes
2 positive zeroes, 1 negative zeroes, 2 imaginary zeroes
0 positive zeroes, 3 negative zeroes, 2 imaginary zeroes
0 positive zeroes, 1 negative zeroes, 4 imaginary zeroes
10Ana wants to multiply out the brackets in the expression 2(3a-1).She writes 2(3a-1)=6a - 1.Ana is wrong. Explain why.1Show Your WorkYou have responded to 9 of 10 questions
Answer:
[tex]2(3a-1)=6a-2[/tex]Step by step explanation:
To multiply the expression 2(3a-1), we need to use the distributive property of multiplication which states that:
[tex]a(b+c)=a\cdot b+a\cdot c[/tex]Then, for the expression 2(3a-1), the correct answer would be:
[tex]\begin{gathered} 2(3a-1)=2\cdot3a-2\cdot1 \\ 2(3a-1)=6a-2 \end{gathered}[/tex]#14 iW Ua. Give another name for UVb. Name a ray with endpoint Xc. Match each ray with its opposite ray.
Given
Find
a) another name for UV
b) Name a ray with endpoint X
c) Match each ray with its opposite ray.
Explanation
a) another name for UV is VU
b) ray with endpoint X is UX
c)
i) UZ is opposite to UY
ii) UV is opposite to UW
iii) UX is opposite to UT
Final Answer
Hence ,
a) VU
b) UX
c) UY , UW , UT
Find a cofunction with the same value as the given expression.COS(3pi/7)
We will have the following:
[tex]\cos (\frac{3\pi}{7})=\sin (\frac{\pi}{2}-\frac{3\pi}{7})[/tex][tex]=\sin (\frac{\pi}{14})[/tex]So, the cofunction with the same value as the expression gu
How large is the sample space when rolling a die five times?
7776
ExplanationThe size of the sample space is the total number of possible outcomes.for example, for a dice, the possible outcomes are 1, 2,3 4, 5 or 6, when rolling a dice five times we have:
Each time you roll the dice there are 6 possible outcomes. (1 of 6)
[tex]6[/tex]now, you have to roll the dice five times
then
[tex]\text{sample space=6}^5=6\cdot6\cdot6\cdot6\cdot6=7776[/tex]I hope this helps you
Consider the following graph of two functions.(8-1-2)Step 3 of 4: Find (8.5(-2)Enable Zoom/Pan866) = -3010-35SG) = x + 3
The question requires that we evaluate the value of:
[tex](g\cdot f)(-2)[/tex]Recall that:
[tex]\left(g\cdot \:f\right)\left(x\right)=g\left(x\right)\cdot \:f\left(x\right)[/tex]Therefore, we have that:
[tex]\left(g\cdot\:f\right)\left(-2\right)=g\left(-2\right)\cdot\:f\left(-2\right)[/tex]We can get the values of g(-2) and f(-2) from the graph as shown below:
Therefore, we have:
[tex]\begin{gathered} g(-2)=5 \\ f(-2)=1 \end{gathered}[/tex]Hence, we can calculate the composite function to be:
[tex]\begin{gathered} (g\cdot f)(-2)=5\times1 \\ (g\cdot f)(-2)=5 \end{gathered}[/tex]To solve rational equation shown below, find the common denominator
Given:
[tex]\frac{3}{2x+1}=\frac{5}{4x+3}[/tex][tex]3(4x+3)=5(2x+1)[/tex][tex]12x+9=10x+5[/tex][tex]12x-10x=5-9[/tex][tex]2x=-4[/tex][tex]x=-\frac{4}{2}[/tex][tex]x=-2[/tex]The endpoints of AB are A(9,4) and B(5,-4). The endpoints of its image after a dilation are A'(6,3) and B'(3,-3). Find the scale factor and explain each of your steps.
It is given that the line segment AB is dilated to give another line segment A'B'.
Since it is a dilation, the length of the image will be a multiple of the length of the preimage.
To find the scale factor, divide the length of the image by the length of the preimage.
Recall that the length of a line segment with endpoints (a,b) and (c,d) is given as:
[tex]\sqrt[]{(c-a)^2+(d-b)^2}[/tex]To find the length AB of the preimage, substitute the coordinates (a,b)=(9,4) and (c,d)=5,-4) into the formula:
[tex]AB=\sqrt[]{(5-9)^2+(-4-4)^2}=\sqrt[]{(-4)^2+(-8)^2}=\sqrt[]{16+64}=\sqrt[]{80}[/tex]To find the length A'B' of the image, substitute the coordinates (a,b)=(6,3) and (c,d)=(3,-3) into the formula:
[tex]A^{\prime}B^{\prime}=\sqrt[]{(3-6)^2+(-3-3)^2}=\sqrt[]{(-3)^2+(-6)^2}=\sqrt[]{9+36}=\sqrt[]{45}[/tex]Divide the length of the image by the length of the preimage to calculate the scale factor:
[tex]\frac{A^{\prime}B^{\prime}}{AB}=\frac{\sqrt[]{45}}{\sqrt[]{80}}=\sqrt[]{\frac{45}{80}}=\sqrt[]{\frac{9}{16}}=\frac{\sqrt[]{9}}{\sqrt[]{16}}=\frac{3}{4}[/tex]Hence, the scale factor is 3/4.
The answer is 3/4.
2. Given that the quadrilateral PQRS is a parallelogram, ST = 6x + 3 andQT= 4x + 27, what is the length of QS?161145138150None of these answers are correct
Given: The quadrilateral PQRS
To Determine: The value of QS
Solution
Please note that the diagonal of a quadrilaterals bisect each other. This is as shown below
Therefore ST equals QT
[tex]\begin{gathered} ST=QT \\ 6x+3=4x+27 \\ 6x-4x=27-3 \\ 2x=24 \\ x=\frac{24}{2} \\ x=12 \end{gathered}[/tex][tex]\begin{gathered} QS=ST+QT \\ QS=6x+3+4x+27 \\ QS=10x+30 \\ QS=10(12)+30 \\ QS=120+30 \\ QS=150 \end{gathered}[/tex]Hence QS = 150
Estimate the instantaneous rate of change of the function f(x)=x2−2x+1 at x=−1 using the average rate of change over successively smaller intervals.
The instantaneous rate of change of the function f(x)=x²−2x+1 at x=−1 using the average rate of change over successively smaller intervals is 4.
What is function?A function from a set X to a set Y assigns exactly one element of Y to each element of X. The set X is known as the function's domain, and the set Y is known as the function's codomain. A function is an expression, rule, or law in mathematics that defines a relationship between one variable (the independent variable) and another variable (the dependent variable). A function is defined as a relationship between a set of inputs that each have one output. A function is a relationship between inputs in which each input is related to exactly one output. Every function has a domain and a codomain, as well as a range. In general, a function is denoted by f(x), where x is the input.
Here,
x²-2x+1
x=-1
(-1)²-2*-1+1
1+2+1=4
the instantaneous rate of change=4
Using the average rate of change over successively smaller intervals, the instantaneous rate of change of the function f(x)=x²-2x+1 at x=1 is 4.
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