The slope of the tangent line to the line 2x+3y=5 can be found by differentiating 2x+3y=5.
Differentiating 2x+3y=5 with respect to x, we get
[tex]\begin{gathered} 2+3\frac{dy}{dx}=0 \\ 3\frac{dy}{dx}=-2 \\ \frac{dy}{dx}=\frac{-2}{3} \end{gathered}[/tex]m=dy/dx is the slope of tangent line.
Hence, slope, m=-2/3.
Now, the equation of the tangent line passing through point (x1, y1)=(-2, 3) with slope m=-2/3 can be found as,
[tex]\begin{gathered} m=\frac{y_1-y}{x_1-x} \\ \frac{-2}{3}=\frac{3-y}{-2-x} \\ -2(-2-x)=3(3-y) \\ 4+2x=9-3y \\ 3y+2x=5 \end{gathered}[/tex]Therefore, the equation of the tangent line is 3y+2x=5.
Victor normally sells roadside cashews for $12 per pound and his roadside stands today is discounting the price 25% if Carla buys 2 3/4 pounds of roasted cashews at the Discounted price how much will she pay
Victor sells roadside cashews for $12 per pound.
Today, the price is discounted by 25%. The discount is
25% of $12 = 25/100*$12 = $3
Thus the discounted price is $12 - $3 = $9 per pound
Carla buys 2 3/4 pounds of roasted cashews at that discounted price, thus she will pay:
$9 * 2 3/4
Expressing 2 3/4 as a single fraction:
2 3/4 = 2 + 3/4 = (8+3)/4 = 11/4
Carla will pay:
$9 * 11/4 = $24.75
Carla will pay $24.75
The letters S, E, M, I, T, R, O, P, I, C, A, and L are written on pieces of paper and placed in a hat. Without looking, you draw one letter. Find the probability of drawing a consonant.
Answer:
P = 7/12
Explanation:
There are 12 letters in the hat and 7 of them (S, M, T, R, P, C, L) are consonants. The probability of drawing a consonant is the ratio of the number of consonants to the total number of letters, so the probability is
P = 7/12
Question 8 of 10The diagonal of a TV is 30 inches long. Assuming that this diagonal forms apair of 30-60-90 right triangles, what are the exact length and width of the TV?A. 60 inches by 60/3 inchesB. 15 inches by 15/5 inchesC. 60/2 inches by 600/2 inchesO D. 15.2 inches by 15.2 inches
The diagram of the triangle formed is shown below
The length is BC and the width is AB
To find BC, we would apply the cosine trigonometric ratio which is expressed as
Cos# = adjacent side /hypotenuse
hypotenuse = AC = 30
adjacent side = BC
# = 30
Thus, we have
[tex]\begin{gathered} \text{Cos}30\text{ = }\frac{BC}{30} \\ \text{Note, Cos30 = }\frac{\sqrt[]{3}}{2} \\ We\text{ have} \\ \frac{\sqrt[]{3}}{2}=\text{ }\frac{BC}{30} \\ 2BC\text{ = 30}\sqrt[]{3} \\ BC\text{ = }\frac{30\sqrt[]{3}}{2} \\ BC\text{ = 15}\sqrt[]{3} \end{gathered}[/tex]To find AB, we would apply the sine trigonometric ratio which is expressed as
Sin# = opposite side /hypotenuse
hypotenuse = AC = 30
opposite side = AB
# = 30
Thus, we have
Sin30 = AB/30
Recall, sin30 = 0.5
Thus,
0.5 = AB/30
AB = 30 * 0,5
AB = 15
Thus, the correct option is B
-5x+2=-9x+38 am crying
The given equation is
[tex]-5x+2=-9x+38[/tex]First, we add 9x on each side.
[tex]\begin{gathered} -5x+9x+2=-9x+9x+38 \\ 4x+2=38 \end{gathered}[/tex]Then, we subtract 2 from each side.
[tex]\begin{gathered} 4x+2-2=38-2 \\ 4x=36 \end{gathered}[/tex]At last, we divide the equation by 4.
[tex]\begin{gathered} \frac{4x}{4}=\frac{36}{4} \\ x=9 \end{gathered}[/tex]Hence, the solution is x = 9.what would be the best first step in solving this system x^2 - 3x + 2y = -4 y = 3x + 2A. isolate x in the first equationB. substitute for y in the first equationc. substitute for x in the second equationD.n isolate x in the second equation
Explanation
we are asked to solve the system of equations:
[tex]\begin{gathered} x^2-3x+2y=-4 \\ y=3x+2 \end{gathered}[/tex]The first step in getting the solution to this will be to substitute for y = 3x +2 in the first equation
Therefore, option B is correct
Given the graph of a function f. A) Graph f(x) -3B) Graph f(x+4)C) Graph -f(x)See picture of the graph of function f attached
From the given problem, the figure shows the graph of f(x).
Note that translating the graph in a manner of :
[tex]f(x)+c[/tex]will shift the graph c units upward if the sign is positive or c units downward if the sign is negative.
We are looking for the graph of f(x) - 3
Since the sign is negative, we will shift the grahp 3 units downward, the graph will be like this.
As you can see, the orginal graph intersects at the origin (0, 0). The new graph intersects at (0, -3) since we moved or shifted the graph 3 units downward.
Additional :
If f(x) is translated in a manner of f(x+c), the graph will be shifted c units to the left if c is positive and will be shifted c units to the right if c is negative.
If f(x) is transformed in a manner of -f(x), the graph will reflect over the x-axis.
If the original point is (x, y). It will become (x, -y)
How do you write 7 square root x^5 in exponential form
Given:
[tex]7(\sqrt[]{x})^5[/tex]To find the exponential form:
[tex]\begin{gathered} 7(\sqrt[]{x})^5=7(x^{\frac{1}{2}})^5 \\ =7x^{\frac{5}{2}} \end{gathered}[/tex]Hence, exponential form is,
[tex]7x^{\frac{5}{2}}[/tex]Click on ,begin emphasis,all,end emphasis, the factors of the polynomial.
Let's assume that we have a polynomial p(x) with a leading coefficient a and zeros are labelled with letters r. Then its factors have the form:
[tex](x-r)[/tex]Remember that the zeros of a function are the x-values of its x-intercepts i.e. the points where it meets with the x-axis. By looking at the picture you'll notice that the graph of the function intercepts the x-axis at three x values: -3, -1 and 3. Then the factors of this polynomial are:
[tex]\begin{gathered} (x-(-3))=(x+3) \\ (x-(-1))=(x+1) \\ (x-3) \end{gathered}[/tex]AnswerThen the correct options are (x+3), (x-3) and (x+1).
Create a box and whisker plot (Label everything!!)
Solution
We have the following data:
11,16,11,15,9,10,11,13,15,17,10,14,17,10,13,15,11,12,12,11,12,14,15,15,13,10,15,12,11
We can calculate the median and the respective quartiles so we need to sort the data and we have:
9 10 10 10 10 11 11 11 11 11 11 12 12 12 12 13 13 13 14 14 15 15 15 15 15 15 16 17 17
Then we have:
Min = 9
Q1 = 11
Median = 12
Q3= 15
Max = 17
And then we can create the boxplot and we got:
Kevin scored at the 60th percentile on a test given to 9840 students. How many students scored lower than Kevin? students
Kevin scored at the 60th percentile on a test given to 9840 students.
Percentile of Kevin = 60th
Number of students = 9840
The objective is to find the number of students, those scored lower than Kevin
Let x be the number of students, those scored lower than Kevin.
The formula for the percentile is as follows;
[tex]\text{ Percentile=}\frac{Number\text{ of students who scored lower than kevin}}{Total\text{ number of students}}\times100[/tex]Substitute the value;
[tex]\begin{gathered} \text{ Percentile=}\frac{Number\text{ of students who scored lower than kevin}}{Total\text{ number of students}}\times100 \\ 60=\frac{x}{9840}\times100 \\ x=\frac{9840\times60}{100} \\ x=5904 \end{gathered}[/tex]Therefore, there are 5904 students who cored lower than Kevin out of 9840
Answer : 5904 students
There are 28 students in a homeroom. How may différent ways can they be chosen tobe elected President, Vice President, Treasurer, and Secretary?
There are 28 students in a homeroom. How many différent ways can they be chosen to be elected President, Vice President, Treasurer, and Secretary?
In this problem, we have a permutation
so
Find out 28P4
[tex]28P4=\frac{28!}{(28-4)!}[/tex]28P4=491,400
therefore
the answer is 491,400Let f(x)=x^2 and g(x)=x-3. Find (f o g)(-5)
Solution
Given that
[tex]\begin{gathered} f(x)=x^2 \\ \\ g(x)=x-3 \\ \\ \Rightarrow(f\circ g)(-5)=f(g(-5)) \\ \\ g(-5)=-5-3=-8 \\ \\ \Rightarrow f(g(-5))=f(-8) \\ \\ f(-8)=(-8)^2=64 \\ \\ \Rightarrow(f\circ g)(-5)=64 \end{gathered}[/tex]What is the value of x? ? 21 21 Drawing not to scale 78 156 D787
We can find the value of x, by using the property of issoceles triangle:
A isosceles triangle is a triangle that has two sides of equal length.
In the given figure, triangle have two sides of equal length 21, thus the given triangle is issoceles.
Since, the angle opposite to the equal sides are equal,
so, the third angle of the given triangle is x
The sum of all angles in a triangle is equal to 180 degrees.
In the given figure : x, x & 34
[tex]\begin{gathered} x\text{ + x +34=180} \\ 2x+34=180 \\ 2x=180-34 \\ 2x=146 \\ x=\frac{146}{2} \\ x=73 \end{gathered}[/tex]So, x = 73º
Answer: D) 73º
Find X and y intercepts 7x+10y=40
To find the intercept of the function on the x-axis, replace y = 0 and solve for x:
[tex]\begin{gathered} y=0 \\ 7x+10y=40 \\ 7x+10(0)=40 \\ 7x+0=40 \\ 7x=40 \\ \text{ Divide by 7 from both sides of the equation} \\ \frac{7x}{7}=\frac{40}{7} \\ x=\frac{40}{7} \end{gathered}[/tex]Therefore, the x-intercept of the function is in the ordered pair:
[tex](\frac{40}{7},0)[/tex]To find the intercept of the function on the y-axis, replace x = 0 and solve for y:
[tex]\begin{gathered} x=0 \\ 7(0)+10y=40 \\ 0+10y=40 \\ 10y=40 \\ \text{ Divide by 10 from both sides of the equation} \\ \frac{10y}{10}=\frac{40}{10} \\ y=4 \end{gathered}[/tex]Therefore, the y-intercept of the function is in the ordered pair:
[tex](0,4)[/tex]PLEASE HELP ASAPName all sets to which the number belongs. There may be more thanone answer.Sqaurerootof50
We have to find to which group the square root of 50 belongs.
Not all square roots are irrational, but some are, like the square root of prime numbers.
In this case we have to factorize 50:
[tex]\sqrt{50}=\sqrt{25\cdot2}=\sqrt{25}\cdot\sqrt{2}=5\sqrt{2}[/tex]As we know that the square root of 2 is irrational, a multiple of this has to be irrational.
So the square root of 50 is an irrational number.
Which number line shows points are to represent the opposite of P
Explanation
The given image marks point p at -3 . Therefore, the opposite of -3 is +3. The corresponding number line that marks R as +3 is given as
Answer: Option 2
Can someone explain this to me please thank you !!
The figure can be drawn as,
From the triangle ABC,
[tex]\begin{gathered} \sin 70=\frac{AB}{AC} \\ \sin 70=\frac{h}{400ft} \\ h=400\sin 70ft \\ h=375.87ft \\ \approx376ft \end{gathered}[/tex]Thus, the required value of height is 376 ft.
In parallelogram DEFG, DE=6 Inches and DF= 6.4 Inches. Diagonals GE and DF Intersect at point H. If GH=4 inches, what is the length of GE?
SOLUTION
Consider the figure below:
It is given that the diagonals DF and GE intersects at H
Recall that the daigonals of parallelogram bisect each other
It follows:
[tex]GH=HE[/tex]Since it is given that GH=4, it follows:
[tex]HE=4[/tex]Using segment addition postulate, it follows:
[tex]\begin{gathered} GE=GH+HE \\ GE=4+4 \\ GE=8 \end{gathered}[/tex]Therefore the required answer is GE=8 inches
Sally's wallet contains• 5 quarters• 3 dimes• 8 nickels• 4 penniesSally will randomly choose a coin, replace it, and randomly choose another coin. What is teh probability thatshe will choose a dime and then a quater?
Sally's wallet contains the following coins
Quarters = 5
Dimes = 3
Nickels = 8
Pennies = 4
What is the probability that she will choose a dime and then a quarter?
Recall that the probability of an event is given by
[tex]P=\frac{\text{number of favorable outcomes}}{\text{total number of outcomes}}[/tex]The probability that she will choose a dime is given by
[tex]P(dime)=\frac{3}{5+3+8+4}=\frac{3}{20}[/tex]The probability that she will choose a quarter is given by
(note that replacement is allowed so the total number of coins remains the same)
[tex]P(quarter)=\frac{5}{5+3+8+4}=\frac{5}{20}=\frac{1}{4}[/tex]So, the probability that she will choose a dime and then a quarter is
[tex]\begin{gathered} P(dime\: and\: quarter)=P(dime)\times P(quarter) \\ P(dime\: and\: quarter)=\frac{3}{20}\times\frac{1}{4} \\ P(dime\: and\: quarter)=\frac{3}{80} \end{gathered}[/tex]Therefore, the probability that she will choose a dime and then a quarter is 3/80
evaluate the function found in the previous step at x=-2
Given:
[tex]5x^2+2y=-3x-2y[/tex]To evaluate the function at x=-2, we simplify the given relation first:
[tex]\begin{gathered} 5x^2+2y=-3x-2y \\ \text{Simplify and rearrange} \\ 2y+2y=-3x-5x^2 \\ 4y=-3x^{}-5x^2 \\ y=\frac{-3x^{}-5x^2}{4} \end{gathered}[/tex]We let y=f(x):
[tex]f(x)=\frac{-3x^{}-5x^2}{4}[/tex]Next, we plug in x=-2 into the function:
[tex]\begin{gathered} f(x)=\frac{-3x^{}-5x^2}{4} \\ f(-2)=\frac{-3(-2)-5(-2)^2}{4} \\ \text{Simplify} \\ f(-2)=\frac{-14}{4} \\ f(-2)=-\frac{7}{2} \end{gathered}[/tex]Therefore,
[tex]f(-2)=-\frac{7}{2}[/tex]Circle all systems of equations that have NO solutions. A. y = 5 – 3x y = -3x + 4 B. y = 4x – 1 4y = 16x – 4 C. 5x – 2y = 3 10x – 4y = 6 D. 3x + 7y = 42 6x + 14 y = 50 E. y = 5 + 2x y = 5x + 2
To determine if a system of equation have solution you have to determine if the slope (m) is equal or diferent.
If the slope is the same it has NO solution
If the slope is different has a solution
If the equations are equivalents have infinite solutions
To determine the slope the equation must be is the form:
[tex]y=mx+b[/tex]Then
A.
y = 5 – 3x
In this equation the slope is m = -3
y = -3x + 4
In this equation the slope is m= - 3
The system has NO solution
B.
y = 4x – 1
m= 4
4y = 16x – 4
You need to simplify the equation, as follow:
[tex]\frac{4}{4}y=\frac{16}{4}x-\frac{4}{4}[/tex][tex]y=4x-1[/tex]Then the equation are the same it means the system has infinited solutions.
C.
5x – 2y = 3
[tex]-2y=3-5x[/tex][tex]y=-\frac{3}{2}+\frac{5}{2}x[/tex]m= 5/2
10x – 4y = 6
[tex]-4y=6-10x[/tex][tex]y=-\frac{6}{4}+\frac{10}{4}x[/tex]Simplify:
[tex]y=-\frac{3}{2}+\frac{5}{2}x[/tex]Then the equation are the same it means the system has infinited solutions.
D.
3x + 7y = 42
[tex]7y=42-3x[/tex][tex]y=\frac{42}{7}-\frac{3}{7}x[/tex][tex]y=6-\frac{3}{7}x[/tex]m= -3/7
6x + 14 y = 50
[tex]14y=50-6x[/tex][tex]y=\frac{50}{14}-\frac{6}{14}x[/tex][tex]y=\frac{25}{7}-\frac{3}{7}x[/tex]m= -3/7
The system has NO solution
E.
y = 5 + 2x
m= 2
y = 5x + 2
m= 5
The system has one solution
Then the systems that have NO solution are: A and D
On the math test last week,Jacob got 85% of the questions correct. How can this be percent be written as a fraction ?
The number in percent can be expressed as the fraction of 100. So 85% can be expressed as,
[tex]\begin{gathered} \frac{85}{100}=\frac{17\cdot5}{20\cdot5} \\ =\frac{17}{20} \end{gathered}[/tex]85% is expressed as 17/20 in fraction.
Answer: 17/20
Answer:
85/100 = 17/20
Step-by-step explanation: In general, 85% is 85/100, but we can shorten that to an easier answer like 17/20.
Algebra1B CP identify a nonviable solution and explain why it is nonviable within the context of the problem
SOLUTION
Step 1 : Attached is the graph that shows the solutions of the two equations:
Step 2: We need the get the values of x and y in the two sets of the equations.
[tex]\begin{gathered} x\text{ + 2y }\leq\text{ 500 --equ 1 multiplied by 3 = 3 x + 6y }\leq\text{ 1500 ---equ 3} \\ 3x\text{ + 4y }\leq\text{ 1200 ---- equ 2} \\ \text{equ 3 minus equ 2, we have that :} \\ 6y\text{ - 4y }\leq\text{ }1500\text{ - 1200} \\ 2y\text{ }\leq\text{ 300} \\ \text{Divide both sides by 2 , we have that:} \\ y\text{ }\leq150 \\ \text{put y }\leq\text{ 150 in equ 1, } \\ x\text{ + 2y }\leq\text{ 500} \\ x\text{ + 2 (150 ) }\leq\text{ 500} \\ x\text{ + 300 }\leq\text{ 150} \\ x\text{ }\leq\text{ 500 - 300} \\ x\text{ }\leq\text{ 200} \end{gathered}[/tex]CONCLUSION: It means that the number of shirts, x = 200
while the number of pyjamas , y = 150
A randomly generated list of numbers from 0 to 4 is being used to simulatean event, with the number 4 representing a success. What is the estimatedprobability of a success?A. 20%B. 75%C. 25%D. 80%
Given:
A randomly generated list of numbers from 0 to 4 is being used to simulate an event, with the number 4 representing success.
Required:
What is the estimated probability of success.
Explanation:
The probability is
[tex]=\frac{\text{ Number of favorable cases}}{\text{ Total number of cases}}[/tex]0, 1, 2, 3, 4, 5 are choices.
Favorable case is number 4.
So, probability
[tex]\begin{gathered} =\frac{1}{5} \\ =0.2 \\ =20\% \end{gathered}[/tex]Answer:
Option A is correct.
Jenny is selling raffle tickets. For every 3 tickets, she charges $18. Complete the table below showing the number of tickets and the amount Jenny charges. Number of tickets 3 7 10 Х 5 ? Charge ($) 18 30 48
Given that for every 3 tickets, Jenny charges $18.
Let's find the amount charged for 1 ticket:
[tex]\text{Price per ticket = }\frac{18}{3}=\text{ \$6 per ticket}[/tex]Therefore, Jenny charges $6 for each ticket.
For 5 tickets, the charge is:
5 * 6 = $30
For 7 tickets, the charge is:
7 * 6 = $42
For 10 tickets, the charge is:
10 * 6 = $60
For 8 tickets, the charge is:
8 * 6 = $48
Hi I’m looking to get a step by step solution in solving this problem in the red
Given:
[tex]\begin{gathered} f(x)=13x+2 \\ \\ g(x)=3x^2-13 \\ \\ h(x)=\frac{13}{x+13} \end{gathered}[/tex]Find-:
The inverse of a function.
Explanation-:
(a)
For the inverse of a function, x change as y and y change as x and solve for 'y'
[tex]\begin{gathered} f(x)=13x+2 \\ \\ f(y)=13y+2 \\ \\ x\rightarrow y \\ \\ y\rightarrow x \\ \\ \end{gathered}[/tex]Then solve,
[tex]\begin{gathered} y=13x+2 \\ \\ y-2=13x \\ \\ x=\frac{y-2}{13} \end{gathered}[/tex]So, value,
[tex]f^{-1}(y)=\frac{y-2}{13}[/tex](b)
[tex]g(x)=3x^2-13[/tex]So, the value is:
[tex]g(y)=3y^2-13[/tex]The inverse of a function is:
[tex]\begin{gathered} x=3y^2-13 \\ \\ x\rightarrow y \\ \\ y\rightarrow x \\ \\ y=3x^2-13 \\ \\ 3x^2=y+13 \\ \\ x^2=\frac{y+13}{3} \\ \\ x=\sqrt{\frac{y+13}{3}} \end{gathered}[/tex]So, the inverse value is:
[tex]g^{-1}(y)=\sqrt{\frac{y+13}{3}}[/tex](c)
[tex]h(x)=\frac{13}{x+13}[/tex]Value of h(y) is:
[tex]h(y)=\frac{13}{y+13}[/tex]Then solve for inverse function,
[tex]\begin{gathered} x=\frac{13}{y+13} \\ \\ x\rightarrow y \\ \\ y\rightarrow x \\ \\ y=\frac{13}{x+13} \\ \\ y(x+13)=13 \\ \\ x+13=\frac{13}{y} \\ \\ x=\frac{13}{y}-13 \end{gathered}[/tex]So, inverse value is:
[tex]h^{-1}(y)=\frac{13}{y}-13[/tex]
Took a pic for better quality, Can you answer as quick as possible, this is due at 9:00, Thanks
The scatter plot represents a group of points that is clearly decreasing at a steady rate, this means that the equation that represents them is a linear equation with negative inclination. A linear equation is given by the following formulla:
[tex]y=m\cdot x+b[/tex]Where m is the inclination and b is the y-intercept. Since the inclination must be negative, the only possible option is A.
Linear function ху 60 10-8 The values in the table represent a linear function. How does the value of y change in relation to a change in the value of x? A) for every change in x by-2, y changes by 4 B) for every change in x by 2, y changes by-4 C) for every change in x by -4, y changes by -2 D) for every change in x by -2, y changes by -4
Here, we want to get how the value of y change relative to a change in value of x
During a probability experiment, Jesse draws one marble each from two different jars and records the result. She then places the marbles back in their respective jars and repeats the experiment for a total of 10 trials. On her first trial, Jesse pulls a blue marble from the first far and a green marble from the second jar, and the results are indicated as BG. The results are shown in the table, where B stands for blue, G stands for green, and R stands for red. Trial 1 2 3 4 5 6 7 8 9 10 Result BG RB RR BG RG BB GG BR GB RR Based on the results in the table, what is the experimental probability of pulling a red marble from the first jar and a green marble from the second jar (RG) ? 1 A. 5 B. 1 6 Ос. 1 OD 1 1 10
SOLUTION AND EXPLANATION OF CONCEPT
From the table in the question, the result for Red in the first jar and green in the second trials (RG) occurs in the fifth trials
The formular for probability is give as
[tex]Pr(E)=\frac{required\text{ outcome}}{total\text{ outcome}}[/tex][tex]Pr(RG)=\frac{Number\text{ of trials for RG}}{Total\text{ number ot Trials}}=\frac{1}{10}[/tex]Hence the probability of red in the fir
Use the rules of exponents to evaluate and simplify the expression. Type all without negative exponents. Make sure “a”and “b” are both in parentheses
We are given the following expression:
[tex](ab)^{-2}[/tex]First, we will use the following property of exponentials:
[tex](xy)^{-c}=x{}^{-c}y^{-c}[/tex]Applying the property we get:
[tex](ab)^{-2}=(a^{-2})(b^{-2})[/tex]Now, we use the following property of exponentials:
[tex]x^{-c}=\frac{1}{x^c}[/tex]Applying the property we get:
[tex](a^{-2})(b^{-2})=\frac{1}{(a^2)(b^2)}=\frac{1}{(ab)^2}[/tex]Since we can't simplify any further this is the final answer.