Do you have a pcture of this problem?
thanks
5
1.) A.) Name the 'item' on which point L exists.B.) If ML= 6x - 4, LH = 10x+1 and MH = 29, find the length of ML.
Now for the point A), L is in the middle of M and H, and the interval will be:
[tex](M,H)[/tex]For the second point, We need to put the value of the segments in the draw...
From the draw, we can deduce that:
[tex]ML+LH=MH[/tex]We replace with values:
[tex]\begin{gathered} ML+LH=MH \\ 6x-4+(10x+1)=29 \end{gathered}[/tex]We solve to x:
[tex]\begin{gathered} 6x-4+(10x+1)=29 \\ 6x\text{ -4 +10x +1=29 ; we agroup the values with x} \\ (6x+10x)-4+1=29 \\ 16x-3=29 \\ 16x=29+3 \\ 16x=32 \\ x=\frac{32}{16}=2 \\ x=2 \end{gathered}[/tex]Finally, if the value of x = 2, then whi can replace in:
[tex]\begin{gathered} ML=6x-4 \\ ML=6(2)-4 \\ ML=12-4 \\ ML=8 \end{gathered}[/tex]Your answer of point B) is ML=8.
The values of events A, B, and C are provided. Compare the probabilityof event A occurring, given that event C occurred to the probability ofEvent B happening, given that event C occurred (Compare P(A/C) toP(BIC)] Which event is more likely?P(A) = 0.45P(B) = 0.30P(C) = 0.25
The conditional probability P(A/C) is given by
[tex]P(A|C)=\frac{P(A\cap C)}{P(C)}[/tex]If event A is independent to event C, we can write
[tex]P(A|C)=\frac{P(A)\cdot P(C)}{P(C)}=P(A)[/tex]Similary, if event B is independent to event C, we get
[tex]P(B|C)=\frac{P(B)\cdot P(C)}{P(C)}=P(B)[/tex]Then, by comparing both results we can see that event A is more likey than event B.
help!!! i’ll mark brainliest!!!
For the given diagram, both the triangles are congruent that is ΔLKM ≅ ΔJKM by using theorem of ASA ( Angle side Angle).
As given in the question,
In the given diagram of the triangles,
Given : ∠LKM ≅ ∠JKM
∠LMK ≅ ∠JMK
To prove : ΔLKM ≅ ΔJKM
∠LKM ≅ ∠JKM ( given )
∠LMK ≅ ∠JMK ( given )
KM ≅ KM ( using reflexive property of congruence )
By applying ASA theorem ( Angle Side Angle )
ΔLKM ≅ ΔJKM
Therefore, for the given diagram, both the triangles are congruent that is ΔLKM ≅ ΔJKM by using theorem of ASA ( Angle side Angle).
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Miss Johnson has a tree in her garden that grows apples in the spring and summer the tree has a diameter of 32 ft from its base what is the circumference of that tree in Miss John's Garden
We know that the circunference of a circle is:
[tex]C=2D[/tex]where D is the diameter so the circunference will be:
[tex]\begin{gathered} C=2\cdot32 \\ C=64 \end{gathered}[/tex]how do i do this i need answers help please
SOLUTION:
Step 1:
In Question 8, we have that:
The three vertices of Triangle ABC are located in Quadrant III.
The image of Triangle ABC after a reflection in the x-axis in the x-axis is
[tex]\text{Triangle A}^IB^IC^I[/tex]Then, the triangle
[tex]A^IB^IC^I[/tex]is located in II -- OPTION B
What’s the scale factor?What’s the value of x? Show your work
Given the original triangle and the scale triangle, you can determine that they are similar.
• Therefore, you can find the scale factor by dividing the lengths of the corresponding sides given in the exercise:
[tex]\begin{gathered} sf=\frac{42\operatorname{cm}}{7cm} \\ \\ sf=6 \end{gathered}[/tex]• In order to find the value of "x", you need to multiply the corresponding side (whose length is 3 centimeters) by the scale factor:
[tex]\begin{gathered} x=(3\operatorname{cm})(6) \\ \\ x=18\operatorname{cm} \end{gathered}[/tex]Hence, the answers are:
- Scale factor:
[tex]sf=6[/tex]- Value of "x":
[tex]x=18\operatorname{cm}[/tex]CheckWhich applies the power of a power rule properly to simplify this expression?(7-8)O (78)4 = 7-8) +(-4) = 7-12 =17121O (7-8)4 = 7(+8)+(-4) = 74 =741O (7-3) = 71-8)(-4) = 7-32 =732O 7-8,4 = 7(-8)(-4) = 72IntroDone
We are given the expression below
[tex](7^{-8})^{-4}[/tex]This expression can be solved by using one of the laws of indices which is denoted below:
[tex](a^m)^n=a^{m\times n}[/tex]Using the above the given expression beocmes
[tex]undefined[/tex]9 divided by 2765 that’s what I’m am asking for
Answer: 307.22222222222 ......
Step-by-step explanation: use the bus stop method to help you
The age of the Earth is inferred from the-A. age of the uranium -235B. age of the Grand CanyonC. age of the Canyon Diablo meteoriteD. age of dinosaurs
The age of the Earth is inferred from the - age of the Canyon Diablo meteorite .
To find : The age of the Earth
Age - Age is defined as the length of time during which a thing or being existed .
a ) the half life of age of uranium-238 , uranium's most abundant and longest-lived isotope is approximately 4.47 billion years ago .
b ) the age of Grand Canyon is 1.8 billion years ago .
c ) The fragment of the Canyon Diablo meteorite determined the elements that formed as radioactive uranium decayed over billions of years.
d ) age of dinosaurs was about 252 million to about 66 million years ago .
Hence , c ) age of the Canyon Diablo meteorite .
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On (07.03) Choose the correct simplification of the expression b5.54. (1 point)
explanation/ Working:
[tex]c^2.c^9=c^2\times c^9=c^{2+9}=c^{11}[/tex]Rule on iindex says when the base is same, you should add the powers
[tex]c^2.c^9=\text{ (c}\times c)\times(c\times c\times c\times c\times c\times c\times c\times c\times c)=c^{11}[/tex]the ordered pair (2,16) is a solution for which equation(s) check all that apply
We have the following:
We must evaluate each equation (x = 2), if the result is 16 it will be a solution
A.
[tex]y=(2\cdot2)^2=4^2=16[/tex]B.
[tex]y=(2+2)^2=(4)^2=16[/tex]C.
[tex]y=2\cdot2^2=2\cdot4=8[/tex]D.
[tex]y=2\cdot2+2=4+2=6[/tex]Therefore, the correct answer is A and B
Write an equivalent expression of 4(6x+12), and state the property you used to write it.
Solution
Using the distributive property
4(6x + 12)
[tex]4(6x+12)=4\times6x+4\times12=24x+48[/tex]Solve the following system of equation using substitution4x + 2y = 10?/1x - y = 13What is the solution for x?
ANSWER
x = 6
EXPLANATION
The substitution method consists on taking one equation to solve for one variable as a function of the other. Then substitute that variable with the expression we find in the other equation and then solve for that other variable.
In this case, we want to solve for x, so we'll take one of the equations and find y as a function of x. For the second equation:
[tex]\begin{gathered} x-y=13 \\ y=x-13 \end{gathered}[/tex]Now we replace y by x - 13 in the first equation:
[tex]4x+2(x-13)=10[/tex]And solve for x:
[tex]\begin{gathered} 4x+2x-2\cdot13=10 \\ 6x-26=10 \\ 6x=10+26 \\ 6x=36 \\ x=\frac{36}{6} \\ x=6 \end{gathered}[/tex]y=-2xy=x-8how do you do this
Separate
y =- 2xy
-2xy = x - 8
Now solve first equation
and then second equation
PART2
y = -2x
y= -4x + 10
Is solved by , substracting both equations
Then
(y - y) = -2x - ( -4x + 10)
0 = -2x + 4x - 10
10 = 2x
10/2= xx
Suppose that when your friend was born, your friend's parents deposited $9000 in an account paying %6.6 interest compounded . What will the account balance be after 13 years
We are given the following information
Deposited amount = P = $9000
Interest rate = r = 6.6% = 0.066
Compounding interval = n = quarterly = 4
Number of years = t = 13
We are asked to find the accumulated amount (or ending balance)
Recall that the compound interest formula is given by
[tex]A=P(1+\frac{r}{n})^{n\cdot t}[/tex]Where
A = Accumulated amount (or ending balance)
P = Deposit amount
r = Interest rate in decimal
n = Number of compounding in a year
t = Number of years
Now let us substitute the given values into the above formula
[tex]\begin{gathered} A=P(1+\frac{r}{n})^{n\cdot t} \\ A=9000\cdot(1+\frac{0.066}{4})^{4\cdot13} \\ A=9000\cdot(1+0.0165)^{52} \\ A=9000\cdot(1.0165)^{52} \\ A=\$21077.85 \end{gathered}[/tex]Therefore, after 13 years, the account balance will be $21077.85
1 The graph of y=-1/2x+2 is positive over the interval (- infty∞,4) and negative over the interval (4,infty∞,). What happens on the graph when x=4?
The answer is letter B.
evaluate: 4163 divided by 38
Steps: We select the part of the dividend that is divisible by the divisor. Then we find the result of this division, then we subtract the result of that product by the part of the dividend we selected prior by the result of the product. Then we select the next number on the dividend and try to divide it with the divisor, if we can't we add a 0 to the result and add one more number from the dividend. When there are no more numbers on the dividend to add, we add a 0 and a dot on the result.
collin noticed that various combinations of the nickels and dimes could add uo to $0.75 let x equal the numver of nickles let y equal the number of dimes what is the domain where y is a function of x and the total value is $0.75
Input data
nickles = 5 cents
dimes = 10 cents
x = number of nickles
y = number of dimes
I need help with question 4, I've included the prior answers from questions 1, 2 and 3 to help you. I've also included what the previous questions were so you have some context of the situation. Although, I think you only need the answers from part C ( which is the graph I've including) to answer question 4
We are asked to determine the equation of the midline for the periodic function. This can be seen below.
Explanation
Using the parameters from the graph, the function can be expressed as;
[tex]y=(100sinx)+150[/tex]The graph that contains the equation of the midline can be seen below.
Therefore, the equation of the midline is
Answer:
[tex]y=150[/tex]I require assistance on a troubling problem
Given data:
The given table.
The standard expression for the exponential function is,
[tex]y=a(b)^x[/tex]Substitute o for x and 5 for y in the above expression.
[tex]\begin{gathered} 5=a(b)^0 \\ 5=a \end{gathered}[/tex]Substitute 1 for x, 15 for y, and 5 for a in the standard exponential expression.
[tex]\begin{gathered} 15=5(b)^1 \\ b=3 \end{gathered}[/tex]The exponential expression can be written as,
[tex]y=5(3)^x[/tex]Thus, the expression for the exponential function is y=5(3)^x.
Riley has 200 stands 35% are from Europe 10% from Asia and 20% are from Australia the rest of the stamps are from North America how many of rileys stamps are from North America
Explanation:
First, we need to calculate the rest of the percentage. So, if the total percentage is 100%, the percentage that corresponds to North America can be calculated as:
100% - (35% + 10% + 20%)
100% - (65%)
35%
So, 35% of the stands are from North America.
Now,
The values of x and y vary directly and one pair of values are given write an equation that relates xand y simplify completely
The values of x and y vary directly. Hence, we can write
[tex]y=kx[/tex]Here, k is the constant of proportionality.
Substitute x=0.1 and y=0.9 in the above equation and solve for k.
[tex]\begin{gathered} 0.9=k\times0.1 \\ k=\frac{0.9}{0.1} \\ k=9 \end{gathered}[/tex]Put the value of k in y=kx.
Therefore, y=9x.
the graph represent 1, and the equation represents function 2: function 2: y=8x + 12how much more is the rate of function 2 then the rate of change of function 1?answer choices:a.3b.4c.5d.8
as the graph represent a constant function, we have that the rate for function 1 is 0. The rate for the second function is 8. So we get that the the answer is D
4x-1=3y+5 it says find the slope
Solution
We have the following equation given:
4x -1 = 3y +5
We can rewrite the expression on this way:
3y = 4x -1-5
3y = 4x -6
Then we can divide both sides of the equation by 3 and we got:
y = 4/3x -2
Then the slope would be:
m= 4/3
Find the lengths of the missing sides in the triangle. Write your answers as integers or as decimals rounded to the nearest tenth. Not drawn to scale x= 6.9, y = 5.7 x=8, y = 11.3 x 11.3, y = 8 x = 5.7, y = 6.9
x=11.3 y=8
Explanationhere we have a right triangle, so we can use a trigonometric function to find the missing sides
so
Step 1
a)let
[tex]\begin{gathered} angle=45\text{ \degree} \\ opposite\text{ side=8} \\ adjacent\text{ side=y} \\ hypotenuse=x \end{gathered}[/tex]Step 2
now, fin the missing length
a) y
to find the adjacent side we can use the stan function
[tex]tan\theta=\frac{opposite\text{ side}}{adjacent\text{ side}}[/tex]replace and solve for y( adjacent side)
[tex]\begin{gathered} tan45=\frac{8}{y} \\ y=\frac{8}{tan\text{ 45}}=\frac{8}{1} \\ y=8 \end{gathered}[/tex]b)x (hypotenuse)
to find the hyoptenuse we can use the sin function ,
[tex]\sin\theta=\frac{opposite\text{ side}}{hypotenuse}[/tex]replace and solve for x
[tex]\begin{gathered} sin\text{ 45=}\frac{8}{x} \\ x=\frac{8}{sin\text{ 45}}=11.3 \\ x=11.3 \end{gathered}[/tex]therefore, the answer is
x=11.3 y=8
I hope this helps you
100 pts RESPOND QUICK PLS! Planes S and R both intersect plane T . Horizontal plane T intersects vertical planes S and R. Planes T and S intersect at line x. Planes T and R intersect and line y. Horizontal line v intersects line x at point B and line y at point A. Line z intersects the lower half of plane S at point C. Point D is on line z but not on a plane. Which statements are true based on the diagram? Select three options. Plane S contains points B and E. The line containing points A and B lies entirely in plane T. Line v intersects lines x and y at the same point. Line z intersects plane S at point C. Planes R and T intersect at line y.
Answer:
The line containing points A and B lies entirely in plane T.
Line z intersects plane S at point C.
Planes R and T intersect at line y.
Step-by-step explanation:
draw a sketch (see picture)
Plane S contains points B and E. - can't be true - there is no point E
The line containing points A and B lies entirely in plane T. - since lines x and y are both on plane T, and points B and A lie on x and y respectively
Line v intersects lines x and y at the same point. - can only be true IF points A and B are the same point
Line z intersects plane S at point C. - given
Planes R and T intersect at line y. - given
Answer:
The line containing points A and B lies entirely in plane T.
Line z intersects plane S at point C.
Planes R and T intersect at line y.
Step-by-step explanation:
Note: The given diagram does not match the description. Please see the attachment for the correct diagram.
Planes
A plane is a flat, two-dimensional surface that extends into infinity.
A plane can be named by the letters naming three non-collinear points in the plane or by an uppercase script letter.
Parallel planes are planes that never intersect. Intersecting planes are not parallel and always intersect along a line.Statement 1
Plane S contains points B and E.
This statement is untrue, since point E is contained in Plane R and point B is contained in Plane S.
Statement 2
The line containing points A and B lies entirely in plane T.
This statement is true.
Statement 3
Line v intersects lines x and y at the same point.
This statement is untrue since lines x and y are on different planes.
Statement 4
Line z intersects plane S at point C.
This statement is true.
Statement 5
Planes R and T intersect at line y.
This statement is true.
What function best represents the perimeter of the orange boxes? *
The formula used to calculate the perimeter of a rectangle is given to be:
[tex]P=2l+2h[/tex]FIRST BOX
For the first orange box, we have that:
[tex]\begin{gathered} l=x+x=2x \\ h=2 \end{gathered}[/tex]Note that the box is divided into 2 parts.
Therefore, this perimeter is:
[tex]P_1=2(2x)+2(2)=2(2x)+4[/tex]SECOND BOX
For the second orange box, we have that:
[tex]\begin{gathered} l=x+x+x=3x \\ h=2 \end{gathered}[/tex]Note that the box is divided into 3 parts.
Therefore, the perimeter is:
[tex]P_2=2(3x)+2(2)=2(3x)+4[/tex]Using the associative property of multiplication, we have that:
[tex]P_2=3(2x)+4[/tex]Since x = 5, we have:
[tex]\begin{gathered} P_1=2(10)+4 \\ P_2=3(10)+4 \end{gathered}[/tex]where 2 and 3 are the number of divisions of the boxes.
If we represent the number of divisions with x, we have the perimeter's function to be:
[tex]P=10x+4[/tex]ANSWER
The correct option is the THIRD OPTION.
From a point x = 80 feet in front of a public library, the angles of elevation to the base of the flagpole and the top of the flagpole are = 29.5° and 39° 45', respectively. The flagpole is mounted on the front of the library's roof. Find the height of the flagpole.
Let's draw the scenario to better understand the details.
To be able to determine the height of the flagpole, let's create two different triangles with 29.5° and 39° 45' angle. The two triangles have one common base at 80 Feet, yet have different heights at H+h and H respectively.
Where,
H = Height of the library
h = Height of the flag
The two triangles are proportional at a common base, thus, let's generate this expression using the Law of Sines:
[tex]\frac{H+h}{\sin(39\degree45^{\prime})}\text{ = }\frac{H}{\sin(29.5^{\circ})}[/tex]Let's simplify,
[tex]\frac{H+h}{\sin(39\degree45^{\prime})}\text{ = }\frac{H}{\sin(29.5^{\circ})}\text{ }\rightarrow\text{ (}H+h)(\sin (29.5^{\circ}))\text{ = (H)(}\sin (39\degree45^{\prime}))[/tex][tex]H\sin (29.5^{\circ})\text{ + h}\sin (29.5^{\circ})\text{ = H}\sin (39\degree45^{\prime})\text{ ; but }29.5^{\circ}=29^{\circ}30^{\prime}[/tex][tex]H\sin (29^{\circ}30^{\prime})\text{ + h}\sin (29^{\circ}30^{\prime})\text{ = H}\sin (39\degree45^{\prime})[/tex][tex]\text{h}\sin (29^{\circ}30^{\prime})\text{ = H}\sin (39\degree45^{\prime})\text{ - }H\sin (29^{\circ}30^{\prime})[/tex][tex]\text{ h(}0.4924235601)\text{ = H(0.63943900198) -H}(0.4924235601)[/tex][tex]\text{ h(}0.4924235601)\text{ = H(0.14701544188)}[/tex][tex]undefined[/tex]
At the rodeo, the bronco riding event takes place in a large dirt ring which has a diameter of 14 yards. What is the ring's radius?
The ring's radius is 7 yards.
Diameter = 14 yd.
The diameter can be defined as:
It is the length of the line passing through the center that touches two points on the edge of the circle.
Also, diameter is double of the radius
That is:
Diameter = 2 times the radius
Diameter = 2 × radius
Let the radius be r
14 = 2 × r
2 r = 14
Divide both the sides by 2:
2 r / 2 = 14 / 2
r = 7 yards.
Therefore, we get that, the radius of the ring will be 7 yards.
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(5n+6)(5n-5) distribute property
We have the following:
[tex](5n+6)\cdot(5n-5)[/tex]we apply distribute property:
[tex]25n^2-25n+30n-30=25n^2+5n-30[/tex]Resultant of the distributive property is 25n² + 5n - 30 .
Given,
(5n+6)(5n-5)
Now,
Distributive property in multiplication : a x (b x c) = (axb) x c
Thus apply the property in the given expression,
(5n+6)(5n-5)
= 25n² - 25n + 30n - 30
Solve the terms with variable n,
= 25n² + 5n - 30
Final expression : 25n² + 5n - 30
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