The given statement is true
Inertia is the tendency of an object to stay at rest or in motion
a freight train, traveling at a speed of 60km/h, passes a light post over the course of 30 seconds. what is the lenght of the train
In the space of 30 seconds, a freight train moving at 60 km/h passes a light post. The train is 500 meters long.
Explain about the Speed?The first person to calculate speed by accounting for both the distance travelled and the amount of time required was the Italian physicist Galileo Galilei. Galileo described speed as the distance travelled in a unit of time.
The speed at which an object's location changes in any direction. The distance travelled in relation to the time it took to travel that distance is how speed is defined.
Miles per hour (mph), kilometers per hour (km/h), and meters per second (m/s) are the three most popular speed units (mph). The distance an object covers in a given amount of time is its speed. Speed equals distance x time is the speed equation.
Speed is 60x (5/18) m/s, or 50/3 m/s, and time is 30 seconds. Distance (train length) = speed x time = 50/3 m/s x 30 s = 500 m.
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WILL GIVE BRAINLIEST!!!! PLEASE HELP!!!!
What is the name of the organic molecule modeled below?
A - Propane
B - Propene
C - Propine
D - Propyne
Answer:
the correct objective is C
A rock on the edge of a cliff has a 1500 J of potential energy. The rock falls 20 m to
the ground. What is the mass of the rock? What force will be exerted on the ground on
impact?
Answer:
Mass = 7.65kg
Force = 75N
Explanation:
Energy Potential = mass • gravity • height
1500 J = mass • 9.8 • 20
1500 J/(9.8 m/s/s •20 m) = mass
7.65 kg = mass
Force = mass • acceleration
Force = 7.65 • 9.8m/s/s
Force = 75 N
We could also do 1500J/20m as gravity is divided in one and then multiplied again
Force = (1500J • 9.8m/s/s)/(9.8m/s/s • 20m)
Force = 1500J/20m
Force = 75N
this makes sense as Energy is defined as Newton metres as seen by the work formula, Work = Force • distance
Answer: Mass of the rock= 7.65g
Force exerted on the ground = 74.9N
Explanation:
potential energy = mass × gravity ×height
1500J = y × 9.8 × 20
1500J=196y
1500 ÷ 196 = y
y= 7.65g
force= mass × gravity
= 7.65 ×9.8
=74.9N
The length of an iron rod is measures by a brass scale. When both of them are at 10°C, the measured length is 50cm. What is the length of the rod at 40°C when measured by the brass scale at 40°C.? (a for brass=24x10-6°C, a for iron = 16x10 °C -¹)
Answer: The answer is 222.8
A dog walks 12 meters to the east and then 16 meters back to the west. For this motion, what is the distance moved?.
The total distance moved by the dog is 28meters while the magnitude of the displacement is 4 meters. Moreover, The direction of the displacement is zero degrees.
In Physics, Distance refers to the motion of an object in any direction while displacement is defined as the total distance traveled in a particular direction.
If a dog walks 12 meters to the east and then 16 meters back to the west, then the total distance covered will be calculated as:
Distance moved = 12m (East) + 16m (West)
Total Distance moved = 28 meters [East + West]
Now let's calculate the displacement.
Distance covered towards east (fro origin) = + 12 meters
Distance covered towards west (fro origin) = - 16metres
Displacement = -16 + 12
Displacement = - 4meters (-ve sign represents direction)
|D| = 4 meters
Thus, the magnitude of the displacement is 4 meters
Since the direction of movement is along the x-axis, therefore the direction is zero degrees.
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The complete question is:
A dog walks 12 meters to the east and then 16 meters back to the west.
For this motion, what is the distance moved?
What is the magnitude and direction of the displacement?
what is the net force and acceleration of a falling crate (mass including parachute 132 kg) when the upward force or air resistance is one-fourth its weight?
the net force and acceleration of a falling crate (mass including parachute 132 kg) when the upward force or air resistance is one-fourth of its weight is 7.35m/s²
We know from newton's second law
sum of forces = ma
here, the forces are weight (down) and resistance (up)
choosing down as the positive direction, we have
weight - resistance = ma
mg - [tex]\frac{1}{4}[/tex](mg)=ma
[tex]\frac{3}{4}[/tex] mg = ma or a = [tex]\frac{3}{4}[/tex] g =7.35m/s²
The net pressure is defined as the sum of all the forces appearing on an item. internet force can boost up a mass. some different pressure acts on a body either at relaxation or movement. Internet forces is a term utilized in a system while there may be an extensive range of forces.
the net pressure is the vector sum of forces performed on a particle or object. The internet pressure is an unmarried force that replaces the impact of the unique forces on the particle's motion. It gives the particle equal acceleration as all those actual forces collectively as defined via Newton's 2nd law of motion.
it's miles possible to decide the torque related to the factor of application of an internet pressure so that it maintains the movement of jets of the object below the original machine of forces. Its related torque, the net pressure, turns into the consequent force and has an identical impact on the rotational motion of the object as all actual forces have taken together.
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what would happen to the distances between bright spots (intensity maxima) on the screen if the spacing between the slits is doubled? group of answer choices
If the spacing between the slits is doubled, then the distances between bright spots (intensity maxima) on the screen will become half
From the young double slit experiment, we come up with a formula which is : β = λD/d, where β is the fringe width, λ is the wavelength of the light rays, D is the distance between the screen and the source of the rays, and the d is the distance between the two slits. here the distance between the two bright spots is also called the bandwidth. If d is doubled then the value of β will be halved.
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Look at the following transformer. The source of electricity is on the left. Therefore, the primary coil is on the left, and the secondary is on the right.
A. How much the primary current ?
B. For the above transformer what is the output power if it is only 85% efficient?
C. How much the secondary voltage?
The primary current of transformer is 9A, the secondary voltage is 63.75 V and the output power at 85% efficiency is 650.25 VA.
(a) Turns of primary coil (N₁) = 400
Turns of secondary coil (N₂) = 300
Current on secondary coil (I₂) = 12 A
Current on primary coil (I₁) =
= using transformer equation,
= N₁ × I₁ = N₂ × I₂
= I₁ = (300 ×12) / 400
= I₁ = 9 A
(b) Voltage of primary coil (V₁) = 85 V
Current on secondary coil (I₂) = 12 A
Power on primary coil (P₁) =
= P₁ = V₁ × I₁
= P₁ = 85 × 9
= P₁ = 765 VA
However, if the efficiency of the transformer is 85% then,
= 85 = (P₂ / P₁ ) × 100
= 0.85 × 765 = P₂
= P₂ = 650.25 VA
(c) Voltage of primary coil (V₁) = 85 V
Current on secondary coil (I₂) = 12 A
Current on primary coil (I₁) = 9 A
Voltage on secondary coil (V₂) =
= using transformer equation,
= I₁ × V₁ = N₂ × I₂
= V₂ = (85 × 9) / 12
= V₂ = 63.75 V
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The mass of a bike and cyclist is 75.0 kg. The rider starts at rest at a height of Om. She speeds up to 6.00 m/s. What is the mechanical energy of thebike?The answers would be one of the four choices in the pictures.
Given that the mass of the bike and cyclist is m = 75 kg and the velocity is v = 6 m/s. The height is h= 0 m
Mechanical energy is the sum of kinetic energy and potential energy.
The kinetic energy is given by the formula
[tex]\begin{gathered} K.E\text{. =}\frac{1}{2}mv^2 \\ =\frac{1}{2}\times75\times(6)^2 \\ =1350\text{ J} \end{gathered}[/tex]The potential energy is given by the formula,
[tex]\begin{gathered} P\mathrm{}E\mathrm{}=\text{mgh} \\ =75\times9.8\times0 \\ =0\text{ J} \end{gathered}[/tex]Here, g = 9.8 m/s^2 and is the acceleration due to gravity.
The mechanical energy will be
[tex]\begin{gathered} E=\text{ 1350 J+0 J} \\ =1350\text{ J} \end{gathered}[/tex]A 1,470.39 N rocket travels at constant speed for 1,522.64m in 2.11 seconds. What is the kinetic energy of the rocket?
Given data:
* The weight of the rocket is 1470.39 N.
* The distance traveled by the rocket is 1522.64 m.
* The time taken by the rocket is 2.11 seconds.
Solution:
The velocity of the rocket in terms of the distance and time is,
[tex]\begin{gathered} v=\frac{\text{distance}}{\text{time}} \\ v=\frac{1522.64}{2.11} \\ v=721.63\text{ m/s} \end{gathered}[/tex]The mass of the rocket from the weight is,
[tex]\begin{gathered} mg=1470.39 \\ m=\frac{1470.39}{g} \end{gathered}[/tex]where g is the acceleration due to gravity,
Substituting the known values,
[tex]\begin{gathered} m=\frac{1470.39}{9.8} \\ m=150.04\text{ kg} \end{gathered}[/tex]The kinetic energy of the rocket in terms of mass and velocity of the rocket is,
[tex]\begin{gathered} K=\frac{1}{2}mv^2 \\ K=\frac{1}{2}\times150.04\times721.63^2 \\ K=39066654.26\text{ J} \\ K=39.07\times10^6\text{ J} \\ K=39.07\text{ MJ} \end{gathered}[/tex]Thus, the kinetic energy of the rocket is 39.07 MJ.
Mix a liter of 20°C water with 2 liters of 30°C water and you’ll have 3 liters of water at?
We can solve this question by using the principle of calorimetry.
The density of water is 1000 kg/m^3
According to the principle of calorimetry,
Heat lost by hot body = Heat gained by the cold body.
This principle is based on conservation of energy.
Let assume that the final temperature is t(f).
So,
[tex]\begin{gathered} Q=mc\Delta t \\ Where,\text{ } \\ Q=Heat \\ m=mass \\ c=Specific\text{ }heat\text{ }capacity \\ \Delta t=Change\text{ }in\text{ }temperature \end{gathered}[/tex]For two liter of water the final temperature is t(f) and initial temperature is 30°celcius,
So here the water will lose heat because it is at higher temperature,
[tex]\begin{gathered} Heat\text{ loose by the water is,} \\ Q=mc\Delta t=1000\times2\times c\times[t(f)-30] \end{gathered}[/tex]And for 1 liter of water the gain in heat is,
[tex]Q=mc\Delta t=1000\times1\times c\times[t(f)-20][/tex]Now,
[tex]\begin{gathered} Q\text{ }lose=Q\text{ }gain \\ -1000\times2\times c\times[t(f)-30]=1000\times1\times c\times[t(f)-20] \\ -2\times[t(f)-30]=[t(f)-20] \\ -2t(f)+60=t(f)-20 \\ -3t(f)=-20-60 \\ t(f)=\frac{80}{3}=26.667\mathring{\text{ }}celcius \end{gathered}[/tex]So the final temperature of the 3 liter water = 26.667 degree cus.
12Question 17 (1 point)It's been said that "Dilution is the solution to pollution." Which of the following is anexample of this saying?✓15Gasoline leaks into a sewage system and is filtered out at the sewage treatmentplant.A doctor's office throws all their trash into the Atlantic Ocean. Waves andcurrents wash it all ashore.18An camper washes her dishes then dumps the water into a large river.Mercury is absorbed into fish and humans eat the fish.1
detectableThe solution to pollution is not dilution. That is, due to the low levels
of contaminants in the effluent and the high volume cmd rate of flow in the St.
Clair River, most substances would be dispersed to the point of undetectability
within ten metres or so, If the contaminants were still decte after ten
kilometres. for example, that would be considered using dilution as a solution.
Since ICI trecrts the waste water before it is released. and with the mixhg zones
ço small, Lusby is confident thd the discharge is hdess because the
concentration is extremely low
if you take a picture of your friend, who is standing 3.90 m from the lens, using a camera with a lens with an 85 mm focal length, how far from the sensor is the lens?
If you take a picture of your friend, who is standing 3.90 m from the lens, using a camera with a lens with an 85 mm focal length, the sensor is 1.087 m from the lens.
1 / f = 1 / v + 1 / u
f = Focal length
v = Image distance
u = Object distance
u = 3.9 m
f = 85 mm
f = 0.85 m
1 / v = 1 / f - 1 / u
1 / v = 1 / 0.85 - 1 / 3.9
1 / v = 3.05 / 3.315
v = 1.087 m
The sign convention for this formula is:
When the object is on the same side of the refracting surface as the incoming light, the value of u is taken as positive else taken as negative.When the image is on the same side of the refracting surface as the incoming light, the value of v is taken as positive else taken as negative.Therefore, the sensor is 1.087 m from the lens.
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What constant torque is required to bring it up to an angular speed of 400 rev/min in 8. 00 s , starting from rest?.
The required Torque would be 13.0895 Nm.
The force that can cause an object to rotate around an axis is measured in torque.
Similar to how force accelerates an object in linear kinematics, torque accelerates an object in an angular direction.
In rotational kinematics, torque takes the place of force in linear kinematics. There is a direct equivalent to Newton’s 2ⁿᵈ law of motion (F=maF=maF, equals, m, a),
[tex]\tau = I \alphaτ=Iαtau[/tex]= αI
Given,
Time (t) =8.00 sec
Ang Velocity (W) = 400 rev/min
Moment of Inertia (I) = 2.50 kg m²
As we know,
W=Wo+αt T
= αI
400 rev/min to rad/sec-
400 × 2π/60sec = 41.8876 rad/sec
41.8876 rad/sec = 0 + α(8 sec) α = 5.2358 rad/sec²
Torque, T=αI.
T=(5.2358)(2.50)
T=13.0895 Nm
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A solar-powered car has a kinetic energy of 110250 J. Its mass is 180 kg. Work out how fast the car is travelling Enter a number m/s
Answer: Velocity = v = 35 m/s
Explanation:
Kinetic energy of an object is defined as the energy possess by an object due to its motion. Kinetic energy K.E of an object is equal to the half of the mass of that object multiplied by square of the object's velocity.
Mathematically,
v = 35 m/s
How can you determine the velocity of a runner from a position time graph?
Answer:
below
Explanation:
The slope of the position-time graph is the velocity at any point in time
If the gravity of the moon is 1/6 of Earth’s gravity, what is the mass of an object that has a weight of 115N on the moon?
Answer:
70.3 kg
Explanation:
The MASS will be the same on the moon as on earth....but the eight is different
gravity of moon = gravity of earth/6 = 9.81 / 6 m/s^2
F = ma
F/a = m = 115 N / ( 9.81/6 m/s^2) = 70.3 kg mass
Answer:
Explanation:
Given:
g = 9.8 m/s²
g₁ = g / 6 = 9.8 / 6 ≈ 1.6 m/s²
F = 115 N
____________
m - ?
m = F / g₁
m = 115 / 1,6 ≈ 71.9 kg
how do astronomers currently think the amount of detectable (observable) matter in the universe compares to the amount of dark matter and dark energy?
Astronomers think the amount of detectable matter as one of some hundred thousand million out of which some are compared and contrasted with the help of modern telescopes.
In 1920 when astronomers began to study the spectra of stars in other galaxies , they found something most peculiar. There were same characteristic sets of missing colours as for stars in galaxy. But they were shifted by some relative amount towards red end of spectrum.The present rate of expanding universe has some resolutions in thermodynamics as the third law states "entropy of universe keeps increasing" , where entropy states the randomness of the universe.Some non luminous material that is believed to exist in space and have the ability to take any several forms including the weakly interacting particles , further having classification of hot dark matter and cold dark matter. Gravity has its field in every particle due to which the stability is maintained with centrifugal force. Something pairing to oppose this fundamental force or field is the dark energy that is negative in nature. And this is responsible for slowing the rate of expansion of universe.[tex]Dark. energy= \frac{\alpha }{\beta } \\\\\alpha =pressure \\\\\beta =energy-Density[/tex]
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Greenhouse A. Open system B. Closed system C. Isolated system
In an open system, both energy and matter are exchanged with the surroundings.
In a closed system, only energy is exchanged with the surroundings.
In an isolated system, neither matter nor energy is exchanged with the surroundings.
In the greenhouse, only energy is exchanged with the surroundings.
Thus, the greenhouse is a closed system.
A boy and a dog are both pulling oppositely on the same bone when the boy pulls as hard as he can. What is the equal and opposite force for the force of the boy pulling on the bone as described by newton's third law?.
The equal and opposite force for the force of the boy pulling on the bone, the net force is zero.
A boy and a dog are both pulling oppositely on the same bone when the boy pulls as hard as he can. There is no net force. Each dog exerts an equal amount of force in opposing directions, which causes the combined force to cancel out.
Newton's third law :
When one body applies pressure to another, the first body feels pressure that is equal to the applied pressure but applied in the opposite direction.Fa = - Fb force exerted on a body is equal and opposite to the force exerted on another body.The equal and opposite force for the force of the boy pulling on the bone, the net force is zero.
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D
This is the greatest number of beats your heart can pump in one minute.
O Resting Heart Rate
O Heart Rate
O Maximum Heart Rate
O Target Heart Rate
Question
The greatest number of beats your heart can pump in one minute is option B: Heart Rate.
What is the heart beat?
Your heart beats on average between 60 to 100 times per minute for adults, which is what is known as your heart rate.
Your body adjusts your heart rate naturally to match what you're doing or what's going on around you. Because of this, your heart rate increases at times of activity, excitement, or fear and decreases during times of rest, serenity, or comfort.
Note that your heart rate is a crucial sign of your general health. A high or slow heart rate may indicate a cardiac condition or other health issues. Having the ability to feel your heartbeat all around your body may also help doctors identify medical issues.
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Answer:
C
Explanation
Maximum Heart Rate
answer for 27. i understand the concept just want to confirm the answer
In a vacuum x-rays and microwaves have the same velocity but different wavelengths.
Correct option: D. the same
what is the power dissipated in a if it is connected to a 4.00 v battery that has negligible internal resistance?
The power dissipated if the resistor A is connected to a 4.00 V battery that has negligible internal resistance is 1.42 W
According to Ohm's law,
V = IR
V = Voltage
I = Current
R = Resistance
For resistor A,
I1 = 0.5 A
V1 = 2.55 V
R1 = 2.55 / 0.5
R1 = 5.1 Ω
I2 = 1 A
V2 = 3.11 V
R2 = 3.11 / 1
R2 = 3.11 Ω
I3 = 2 A
V3 = 3.77 V
R3 = 3.77 / 2
R3 = 1.885 Ω
I4 = 4 A
V4 = 4.58 V
R4 = 4.58 / 4
R4 = 1.145 Ω
R = ( R1 + R2 + R3 + R4 ) / 4
R = ( 5. + 3.11 + 1.885 + 1.145 ) / 4
R = 2.81 Ω
P = V² / R
P = Power
V = 4 V
P = 4² / 2.81
P = 1.42 W
Therefore, the power dissipated if it is connected to a 4.00 V battery that has negligible internal resistance is 1.42 W
The given question is incomplete. The complete question is:
The voltage drop Vab across each of resistors A and B was measured as a function of the current I in the resistor. The results are shown in the table attached. What is the power dissipated in A if it is connected to a 4.00 V battery that has negligible internal resistance?
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In order to have kinetic energy an object must be
1.moving
2. At rest
3.rigid
4.elevated
4. A car has a mass of 1,350 kg. A driver travels on a level road with an acceleration of 4.7 m/s.What force, neglecting friction, must be exerted to achieve this accelerations?
We have to use Newton's Second Law
[tex]F=ma[/tex]Where m = 1,350 kg and a = 4.7 m/s2.
[tex]\begin{gathered} F=1,350\operatorname{kg}\cdot\frac{4.7m}{s^2} \\ F=6,345N \end{gathered}[/tex]Hence, the force exerted is 6,345 Newtons.what is the mass of a hiker 350m above the ground if her GPE is 120,200 J?
Given:
The height from the ground is h = 350 m
The gravitational potential energy is GPE = 120,200 J
To find the mass of the hiker.
Explanation:
The mass of the hiker can be calculated by the formula
[tex]\begin{gathered} GPE\text{ =mgh} \\ m\text{ =}\frac{GPE}{gh} \end{gathered}[/tex]Here, g =9.8 m/s^2 is the acceleration due to gravity.
On substituting the values, the mass of the hiker will be
[tex]\begin{gathered} m\text{ =}\frac{120200}{9.8\times350} \\ =35.044\text{ kg } \end{gathered}[/tex]Thus, the mass of the hiker is 35.044 kg
The water displacement method was used to determine the density of silly putty. The initial water level in graduated cylinder was 25 ml and the final water level after placing silly putty into graduated cylinder was 29 ml. The mass of the silly putty was 8 grams. Calculate the density of the silly putty.
Answer:
The density of putty 2 g/cm³
Explanation:
Given:
V₀ = 25 ml = 25 cm³
V = 29 ml = 29 cm³
m = 8 g
______________
ρ - ?
The density of putty:
ρ = m / (V - V₀)
ρ = 8 / (29 - 25) = 8 / 4 = 2 g/cm³
What is the si unit of mass and length
Answer:
Mass: Kg (kilogram)
Length: M (meter)
the beam is balanced use the principle of moments to calculate the weight, W, of the monkey in newtons.
the objects weight on the left is 350N and the distance from the pivot is 20m. the second object on the right weight is x and distance from the pivot is 1.5m
Answer:
below
Explanation:
350 * 20 has to equal x * 1.5
350 * 20 = 1.5 x
x = 4666.7 N
The half-life of iodine-131 is 8.07 days. If 0.25 g are left after 40.35 days, how many gramswere in the original sample?
Given data
*The half-life of iodine-131 is t = 8.07 days
*The amount of quantity left is N = 0.25 g
*The number of days is T = 40.35 days
The expression for the radioactivity decay is given as
[tex]N=N_0(\frac{1}{2})^{\frac{T}{t}}[/tex]Substitute the values in the above expression as
[tex]\begin{gathered} \text{0}.25=N_0(\frac{1}{2})^{\frac{40.35}{8.07}} \\ N_0=8\text{ g} \end{gathered}[/tex]Answer:
See below
Explanation:
40.35 days / (8.07 day per half life) = 5 half lives
.25 = x ( 1/2)^5
.25 / ( 1/2)^5 = x = 8 gm originally