You have a galaxy that is too far away to see individual stars, but you can see a little smudge of light from the galaxy.What would be the best way to find the distance to this galaxy?Group of answer choices- Red shift- Radar ranging- Triangulation- Cepheid variables- H-r diagram, brightness-distance- Type 1A supernova, brightness-distance

Answers

Answer 1

Using a high-resolution telescope like the Hubble space telescope is the most effective approach to determining the distance to a galaxy.

The most distant star ever observed is Icarus, a huge blue star that covers more than half the universe. Even with the biggest telescopes in the world, they are typically too faint to be seen.

However, scientists were able to find this far-off star and achieve new distance records because of a natural variation that considerably intensifies the star's feeble shine. Icarus was also used to test the dark matter hypothesis and investigate the makeup of nearby galaxy clusters.

This star is so far away, hidden in a very vast spiral galaxy, that it took nine billion years for its light to reach Earth. The cosmos seems to have existed when it was around 30% older than it is now.

This star can be seen because of gravitational lensing, a cosmic phenomenon. Light is bent and amplified by the gravity of large foreground galaxy clusters, which functions like a natural lens in the cosmos. A single backdrop object's light can produce several images. Light is bright enough to see extremely faint and far-off objects and is substantially intensified.

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Related Questions

The specific gravity of an material is defined as the ratio of the density of the material to the density of water. The specific gravity of ice is 0.917, whereas that of seawater is 1.025.
What fraction of an iceberg is above the surface of the water?
\frac{V_{above}}{V_{total}} = ____________

Answers

The fraction of the iceberg that is above the surface of the water is 8.3 %.

The specific gravity of any material is defined as the ratio of the density of the material to the density of water.

Mathematically, the formula for specific gravity of materials =

= S.G = density of the material / density of water

Specific gravity of the iceberg = 0.917

Specific gravity of the seawater = 1.025

The fraction of the iceberg submerged in the seawater =

= 0.917 = 0.917 x 100 %

= 91.7 %

The fraction of the iceberg that is above the surface of the water =

= 1 - 0.917

= 0.083

= 0.083 x 100 %

= 8.3 %

Thus, the fraction of the iceberg submerged in the water is a function of the specific gravity of the iceberg.

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In a two-slit interference pattern, the intensity at the peak of the central maximum is I_0.
Â
a. At a point in the pattern where the phase difference between the waves from the two slits is 62.0 degrees, what is the intensity? Give your answer as a fraction of I_0. (I/I_0 =)
Â
b. What is the path difference for light with a wavelength of 473 nm from the two slits at a point where the phase angle is 62.0 degrees?

Answers

The centre maximum's peak intensity in a two-slit interferogram is 0.75 I 0I intense.

What are some instances of intensity?

The degree, volume, or quantity of a phenomenon, such as fire, passion, weather, work, or passion, is known as its intensity. The word "intensity" has been linked to passion, fire, and murder in the past. When describing the intensity of something like a flame or possibly a love affair, it is utilized.

What is the scientific definition of intensity?

Energy density times wave speed equals intensity, which is the amount of energy a wave transports over a surface of a given area in a unit of time. Watts per sq.m are the most common units used to measure it. The strength or amplitude of a wave will determine its intensity.

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order the structures that a pressure wave passes through in the cochlea, beginning from the oval window and ending at the round window.

Answers

The cochlea is the organ responsible for hearing, and it is composed of several interconnected structures through which a pressure wave passes. Beginning at the oval window, the pressure wave then moves through:

Scala vestibuliReissner's membrane Scala tympaniBasilar membrane

And finally exits through the round window.

The Structures of the Cochlea: A Journey from the Oval Window to the Round Window

Order the structures that a pressure wave passes through in the cochlea:

Oval windowScala vestibuliReissner's membraneScala tympaniBasilar membraneRound window

This chain of structures creates a pathway that allows the pressure wave to pass through the cochlea, converting sound waves into signals that are then sent to the brain and interpreted as sound.

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question what would cause a backpack sitting on the floor of the school bus to suddenly fly forward? responses the bus makes a hard turn to the left. the bus makes a hard turn to the left. the bus is going forward and suddenly stops. the bus is going forward and suddenly stops. the bus is going backward and suddenly stops. the bus is going backward and suddenly stops. the bus makes a hard turn to the right.

Answers

Answer:

Below

Explanation:

Going forward and stops .....the backpack wants to keep going forward due to its inertia.

Kara less was applying her makeup when she drove into south's busy parking lot last friday morning. Unaware that lisa ford was stopped in her lane 30 feet ahead, kara rear-ended lisa's rented taurus. Kara's 1300-kg car was moving at 11 m/s and stopped in 0. 14 seconds.

Answers

The momentum of Kara's car before the collision, given that it was moving with a velocity of 11 m/s is 14300 Kg.m/s

Momentum of an object is simply defined as the product of mass and velocity. Mathematically it is expressed as:

Momentum = mass × velocity

Using the above formula, we can obtain the momentum of Kara's car before the collision as follow::

Mass of Kara's car = 1300 Kg

Velocity of Kara's car = 11 m/s

Momentum of Kara's car =?

Momentum = mass × velocity

= 1300 Kg × 11 m/s

= 14300 Kg.m/s

Thus, the momentum of Kara's car is 14300 Kg.m/s

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what pressure does light emitted uniformly in all directions from a 200-w incandescent light bulb exert on a mirror at a distance of 5.0 m?

Answers

The pressure exerted on the mirror by the light emitted from the 200-w incandescent light bulb is negligible. This is because the pressure exerted by light is proportional to the intensity of the light .

and the intensity of the light drops off as the square of the distance. At a distance of 5.0 m, the intensity of the light is extremely low, and thus the pressure is practically zero.

Step 1: Calculate the intensity of light:

We know that the power of the light bulb is 200 W, so the intensity of light is given by:

I = P/4πd2

Where P is the power of the light and d is the distance from the light to the mirror.

In this case, we have:

I = 200 W / 4π(5.0 m)2

I = 0.0025 W/m2

Step 2: Calculate the pressure exerted by the light on the mirror:

We know that the pressure exerted by the light on the mirror is given by:

P = I/c

Where I is the intensity of the light and c is the speed of light.

In this case, we have:

P = 0.0025 W/m2/3.00 x 108 m/s

P = 8.3 x 10-10 N/m2

Therefore, the pressure exerted by the light emitted from the 200-w incandescent light bulb  on a mirror at a distance of 5.0 m is 8.3 x 10-10 N/m2.

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Element x has two isotopes. If 72. 0% of the element has an isotopic mass of 84. 9 amu and 28. 0% has an isotopic mass of 87. 0 amu, the average atomic mass of element x is numerically equal to.

Answers

The average atomic mass of element X is numerically equal to 85.48 amu.

Isotopes can be defined as the variants of chemical elements that possess the same number of protons and electrons, but a different number of neutrons. In other words, isotopes are variants of elements that differ in their nucleon ( The total number of protons and neutrons) numbers due to a difference in the total number of neutrons in their respective nuclei. i.e. same atomic number but different masses.

Given , Percentage of isotope 1 = 72%

            Percentage of isotope 2 = 28%

            Mass of isotope 1 = 84.9 amu

            Mass of isotope 2 = 87 amu

i.e.

Average atomic mass = (0.72 * 84.9) + (0.28 * 87) = 85.48 amu

So the average atomic mass of element X is numerically equal to 85.48 amu.

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1. suppose a spaceship which is traveling at c/2 passes a light source. what is the velocity of light from the source in the reference frame of the spaceship?

Answers

The speed of light from the source in the spacecraft's frame of reference is given by the formula Ux = Ux+v/C2+2Uxv/C2. The pace at which an object's position changes in relation to a frame of reference.

And is a result of time. An object's speed and direction of motion are specified by its velocity. A crucial idea in kinematics is velocity. Two different categories of frame of reference are as follows: An object that is fixed or moving at a constant speed is said to have an inertial frame of reference. The First Law of Motion of Newton is directly relevant in this frame. The frame of reference refers to the context in which an observer is placed when recording data.

Ux = Ux+v/C^2+Uxv/C^2

here, c =c/2

Ux = Ux+v/C^2+2Uxv/C^2

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Calculate the speed of a horse that travels 512 m in 450 seconds.

Answers

It is an exercise of uniform rectilinear movement.

Uniform rectilinear motion is one in which an object moves in a straight line, in one direction, with a constant speed.

When we speak of constant speed, we mean that the movement maintains the same speed; That is, the object does not move faster or slower, always at the same speed.

Calculate the speed of a horse that travels 512 m in 450 seconds.

Data:

V = ?

d = 512 m

t = 450 s

The uniform motion formula is: V=d/t

We clear, but in this case it is not necessary, since we want to calculate the velocity.

     V = d/t      V = 512 m/450 s      V = 1.14 m/s

The speed of a horse that covers 512 m in 450 seconds is 1.14 m/s.

Answer: The speed registered by the horse is 1.13 seconds.

Step by step explanation:

¿Calculate the speed of a horse that travels 512 m in 450 seconds?

Data:

V = ?D = 512mT = 450 seconds

To calculate the speed of the horse, first we are going to divide but for this it is necessary to calculate its speed.

V = D/TV = 512 m/450 sV = 1,13 seconds.

Rpt: The speed registered by the horse is 1.13 seconds.

water is pumped at a rate of 32 m3 /s from the reservoir and out through the pipe, which has a diameter of 1.50 m. what power must be supplied to the water to effect this discharge?

Answers

The power must be supplied to the water to effect this discharge is 28174.32 kW.

Why is Reynolds number used?

The ratio of viscous forces to inertial forces is known as the Reynolds number. A dimensionless number called the Reynolds number is used to group fluid systems where the influence of viscosity plays a significant role in regulating the velocities or the flow pattern of a fluid.

Discharge = Q = 32 m³/s

Velocity of flow=V=Q/A = 32/( π(1.5)²/4)= 18.11 m/s

Reynold's no is given by

Re = VD/v = (18.11)(1.5)/(1.31x10⁻⁶) = 20736641.22

For steel pipe

Roughness = e = 0.045 mm

Relative roughness = E= e/D= (0.045x10⁻³)/1.5=0.00003

Friction factor from Moody's diagram is

f = 0.00988

Apply Bernoulli's theorem b/w top of left reservoirs and exit of pipe

A - denote left reservoir and B- denote exit of pipe

Pa/y + V₂²/2g + Za + hp = Pb/ γ+Vb²/2g + Zb + hf

Where

Pa= Pb=0

Va= 0, Vb = V = 18.11 m/s

Za = (100-95) = 5 m, Zb=(140-95) = 45 m

Frictional head loss =hf = flV²/2gD= (0.00988x300x18.11²)/(2x9.81x1.5)

Frictional head loss = hf = 33.03 m

hp = pump head

Putting values

0+0+5+hp = 0 +18.11²/(2x9.81) +45 +33.03

=> hp = 89.75 m

Power that must be supplied is given by

P = γQhp

P = 9.81x32x89.75

P = 28174.32 kW.

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100 POINTS FOR HELP

A chef needs to increase the temperature of a food dish. She thinks she can do this by stacking another dish on top of it. She has three dishes to choose from for the top dish: A, B, and C.


Which one of these dishes would make the food dish the warmest when placed on top of it? As part of your answer, explain how the energy and temperature of both the top dish and the food dish will change when the food dish warms up, and why.

Answers

Answer:

It is not possible to determine which of the dishes, A, B, or C, would make the food dish the warmest without more information. In general, the temperature of the food dish will increase as a result of heat transfer from the top dish to the food dish. This transfer of heat will cause the temperature of the top dish to decrease. The amount of heat transferred and the resulting change in temperature for both dishes will depend on the heat capacities and initial temperatures of both dishes, as well as the amount of time they are in contact with each other. In order to determine which of the dishes, A, B, or C, would make the food dish the warmest, more information about these factors would be needed.

Explanation:

while on mars, you drop your martian detector while climbing out of the rover. if you're standing on a platform 8 meters from the ground and the acceleration due to gravity on mars is -3.8 m/s^2, how long does it take for the martian detector to hit the ground? report an error 1.3 s 9.9 s 2.1 s 13 s 21 s

Answers

It take  1.45s to the Martian detector to hit the ground.

We are know that,

Acceleration = a = - 3.8 m/s²

Distance = r = 8m

Final velocity = v =  0 (The rock's velocity is zero at its maximum height.)

Time = ?

Thus to calculate the hitting time of the Mars ground we can use the formula,

acceleration  = change in velocity / time

First of all we have to calculate the initial velocity (u) of the Martian i.e.

a = u²/r

u² = a.r

u² = (-3.8m/s²)× 8m

u² = -30.4m²/s²

u = - 5.51 m/s

Putting the value of initial velocity in the above equation we can get the hitting time,

-3.8 m/s² = 0 - (5.51m/s)/t

t = (-5.51m/s)/(-3.8m/s²)

t = 1.45s

The Martian detector hits the ground in 1.45 seconds.

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a tall tree is growing across a river from you. you would like to know the distance between yourself and the tree,as well as its height, but are unable to make the measurements directly. however, by using a mirror to form an image of the tree and then measuring the image distance and the image height, you can calculate the distance to the tree as well as its height. suppose that this mirror produces an image of the sun, and the image is 0.8501 m from the mirror. the same mirror is then used to produce an image of the tree. the image of the tree is 0.9605 m from the mirror. (a) how far away is the tree? (b) the image height of the tree has a magnitude of o. 14 m. how tall is the tree?

Answers

a)how far the tree was found to be 0.9605 m

b) the height of the tree was found to be 0.14m

What exactly is object distance?

Object Distance, denoted by s, is the distance between an object and an optical element.

What are the qualities of a mirror image?

• The image obtained is fictitious.

•The picture is flipped laterally.

• The picture is upright.

• The picture has the same dimensions as the thing.

• The distance between the image acquired from the mirror and the item gained from the mirror is the same.

As a result, the distance between the tree and the mirror is the same as the distance between the picture and the mirror, i.e. 0.9605 m, and the height of the tree is the same as the height of the image, which is 0.14 m.

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a)how far the tree was found to be 0.9605 m

b) the height of the tree was found to be 0.14m

What exactly is object distance?

Object Distance, denoted by s, is the distance between an object and an optical element.

What are the qualities of a mirror image?

• The image obtained is fictitious.

•The picture is flipped laterally.

• The picture is upright.

• The picture has the same dimensions as the thing.• The distance between the image acquired from the mirror and the item gained from the mirror is the same?

As a result, the distance between the tree and the mirror is the same as the distance between the picture and the mirror, i.e. 0.9605 m, and the height of the tree is the same as the height of the image, which is 0.14 m.

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the coefficient of kinetic friction between the block and the table is 0.320. find the distance d from the box to the edge of the table if it takes 1.5 s for the box to reach the edge once it begins to move.

Answers

The distance d from the box to the edge of the table if it takes 1.5 s for the box to reach the edge once it begins to move is 1 m

μk = 0.32

t = 1.5 sec

For mass B,

mBg - T = mB a

For mass A,

T - F f = mA a

T - μKmAg = mAa

a = 1.35 × 9.8 - 0.32× 3  × 9.8/ 4.35

a = 0.88 m/[tex]S^{2}[/tex]

vi = 0

d = Vi t + 1/2 a[tex]t^{2}[/tex]

distance d = 0.99 ≈ 1m

Distance is a scalar quantity that describes "how much ground an object has covered" while moving. Displacement is a vector quantity that describes "how far out of place an object is"; it represents the overall shift in position of the object. Distance is a measurement of how far apart two things or locations are, either quantitatively or occasionally qualitatively. Distance in physics or common language can refer to a physical length or an estimate based on other factors (e.g. "two counties over"). The term is also frequently used metaphorically to denote a measurement of the degree of difference between two similar objects (such as statistical distance between probability distributions or edit distance between strings), given that spatial cognition is a rich source of conceptual metaphors in human thought.

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what is the total number of unique ways to distribute two identical objects in three separate containers when there is no limit on the number of objects that can be in a container?

Answers

There are 6 unique ways to distribute two identical objects in three separate containers.

Unique ways are the different ways in which the objects can be separately placed in the containers.

Number of ways are:

Container 1: both Object ; Container 2: 0 object ; Container 3: 0 objectContainer 1: 0 Object ; Container 2: both object ; Container 3: 0 objectContainer 1: 0 Object ; Container 2: 0 object ; Container 3: both objectContainer 1: 1 Object ; Container 2: 1 object ; Container 3: 0 objectContainer 1: 0 Object ; Container 2: 1 object ; Container 3: 1 objectContainer 1: 1 Object ; Container 2: 0 object ; Container 3: 1 object

These are the 6 ways to distribute two identical objects in three separate containers.

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What is energy associated with motion called?

Answers

The energy associated with motion is called kinetic energy.

Your body doesn't just have energy when you're in motion. When an object is in motion it has a finite amount of kinetic energy. However, when not in motion, the body can store energy in the form of potential energy.

The body can also have a certain internal energy. This can be explained as follows. Energy is basically the ability of any body to do work. Suppose you are sitting ideally in your room and suddenly you realize that someone has changed the position of your study desk and you want to change it. So I pushed the table and moved it to where it suited me. This means that we have applied a finite force that causes displacement, i.e. we have done some work. So you had the ability to work properly. This means that you had energy in the form of internal energy.

[tex]mgh+\frac{mV^2}{2}=Energy \\\\m[gh+V^2/2]=E[/tex]

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A pinball i launch at (ma=0. 1kg )to launched at 12. 6 m/. People compre the pinball machine pring by 0. 2m to reach thie initial velocity for the pinball. Which type if pring do you chooe to mot cloely reach the targeted launch peed of 12. 6m/?

Answers

For this situation, I would recommend using a compression spring, as this type of spring will provide the most consistent force over the full range of compression.

What are the applications of Compression Springs?

The applications of compression springs include:

Automobiles: It would be quite challenging to produce the majority of cars without at least some compression springs. In automobiles, compression springs are utilized in a variety of components, including suspension, hoses, and even seats. They are used in the seats to help them adjust to the body and provide comfort. Naturally, a number of sizes and forms are available to accommodate the wide range of uses for car compression springs.

Pens: A ballpoint pen can be used to monitor a compression spring. The pen can write with the tip exposed thanks to this spring, which then covers it inside the housing to keep the ink from drying out. This enables the use of pens without their bulky, losable caps.

Aeronautics: Without various kinds of springs, most air flight would be impossible. Air turbines, navigation systems, engine controls, wheels, brakes, meters, fuel cells, and diesel engines are just a few of the parts of an aeroplane that need springs, even if they may not be visible.

Firearms: When thinking about tension, think about compression springs. Consider the effort required to fire a bow and arrow. If a compression spring is used in place of the human component, the crossbow becomes a far more straightforward weapon.

Compression springs are mechanical springs that are designed to create resistance to a compressive force. Compression springs are typically made with a higher spring constant, which is the measure of how much force is required to compress the spring by a certain amount. With a higher spring constant, a shorter compression is required to achieve the desired launch speed. They are used in many different applications. Compression springs are commonly used to absorb shock, store energy, and return an object back to its original shape after being compressed.

Hence, compression spring is used to reach the targeted launch speed.

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an athlete at the gym holds a 3.0 kg steel ball in his hand. his bio arm is 70 cm long and has a mass of 4.0 kg. what is the magni- tude of the torque about his shoulder if he holds his arm a. straight out to his side, parallel to the floor?

Answers

The magnitude of the torque about an athlete shoulder is 48.02N-m if he is holding steel ball in his hand.

We know that torque is defined as the cross product of distance of point from applied point to the force applied by the external source at that point, in other words

Torque=distance × Force

     =>τ = r × F

Total mass hold by the athlete is = 3+4=7kg.

Now, we need to focus on the force acting on an athlete. So we are assuming an athlete is standing on the surface, so acceleration due to gravity have some  role to exert  some amount of force on athlete.

Therefore, Force=mg

=>F=7×9.8

=>F=68.6Kg-m/sec²

Now, distance of force from applied point is 70cm=0.7m

Therefore, Torque=0.7×68.6

              =>Torque= 48.02N-m

Hence, value of Torque is 48.02N-m.

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a spring stretches by 21.0 cm when a 135 n object is attached. what is the weight of a fish that would stretch the spring by 31.0 cm?

Answers

The weight is 200 N of a fish that would stretch the spring by 31.0 cm.

We can use Hooke's Law to solve this problem. Hooke's Law states that the force (F) needed to stretch a spring is proportional to the amount of stretch (x). The mathematical expression for Hooke's Law is:

F = kx

where k is the spring constant.

We can rearrange this equation to solve for k:

k = F/x

We can substitute the given values for F (135 N) and x (21 cm) to calculate the spring constant:

k = 135 N/21 cm

k = 6.43 N/cm

Now that we know the spring constant, we can use Hooke's Law to calculate the force needed to stretch the spring by 31 cm.

F = kx

F = 6.43 N/cm x 31 cm

F = 199.33 N

Finally, we can use the force to calculate the weight of a fish that would stretch the spring by 31 cm. Since weight is equal to force multiplied by the acceleration due to gravity (g = 9.8 m/s2), we can use the following equation:

Weight = F x g

Weight = 199.33 N x 9.8 m

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A piece of clay was thrown so that it has a momentum of 34 kg·m/s. It hits a 0.25 kg motionless cart and sticks to it. What is the momentum of the clay and cart combined? (ignore friction)

Answers

The momentum of the clay and the cart is 34 kgm/s.

What is momentum?

Momentum can be defined as the product of mass and velocity.

To calculate the momentum of the clay and the cart, we use the formula below.

Formula:

M' = M+mu..............................Equation 1

Where:

M' = Momentum of the clay and the cartM = Momentum of the claym = Mass of the cartu = Initial velocity of the cart

From the question,

Given:

M = 34 kgm/sm = 0.25 kgu = 0 m/s (motionless)

Substitute these values into equation 1

M' = 34+(0.25×0)M' = 34 kgm/s

Hence, their momentum is 34 kgm/s.

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radio waves travel at a speed of 1.7x10^8 m/s through ice. A radio wave pulse sent into antarctic ice reflects off earth at the bottom and returns to the surface in 32.9x10^-6 s. how deep is the ice?

Answers

Then the depth of the ice is 26.55 x 10¹² m

Let speed of the radio wave be represented as 'v'

Let frequency of the radio wave be represented as 'f'

Let distance of the radio wave be represented as 's'

Let time period of the radio wave be represented as 't'

From the formula for distance:

v=s/t

v= s x 1/t

Frequency is the inverse of time period. So, 1/t in the above formula can be replaced by f.

v = s x f

putting values in the above equation

t = 32.9 x 10⁻⁶ s

v = 1.7 x 10⁸ m/s

The, f = 1/t

f = 1/3.2 x 10⁻⁶ s⁻,

So,

s = 1.7 x 10⁸ x 1/3.2 x 10⁻⁶

= 1.7/3.2 x 10⁸⁺⁶

= 0.531 x 10¹⁴

= 53.1 x 10¹²

Then the depth of the ice would be s/2 as the distance is covered twice by the wave in the given time frame.

Depth of ice = 53.1 x 10¹²/2

Depth of ice = 26.55 x 10¹² m

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What is the frequency of a wave if its time period is 0.05 s?

Answers

The frequency of a wave is 20Hertz  if its time period is 0.05sec. Frequency is said to be inversely proportional to time period.

Frequency, in material science, the quantity of waves that pass a decent point in unit time; likewise, the quantity of cycles or vibrations gone through during one unit of time by a body in occasional movement. A body in occasional movement is said to have gone through one cycle or one vibration subsequent to going through a progression of occasions or positions and getting back to its unique state. See likewise precise speed; straightforward symphonious movement.

If the period, or time span, expected to finish one cycle or vibration is 1/2 second, the frequency is 2 every second; assuming that the period is 1/100 of 60 minutes, the frequency is 100 every hour. By and large, the frequency is  proportional of the period, or time span; i.e., frequency = 1/period = 1/(time stretch). The frequency with which the Moon spins around Earth is somewhat in excess of 12 cycles each year. The frequency of the A line of a violin is 440 vibrations or cycles each second.

So, we know that frequency is defined as inversely proportional to time period.

So, frequency=1/Time period

=>v=1/0.05

=>v=100/5

=>v=20/sec

or v=20Hertz.

Hence, frequency of wave is 20Hertz.

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Nancy is knitting a scarf. It takes her 0. 2 of an hour to knit each inch of the scarf. She wants the length of the scarf to be 60 inches. How many hours will it take her to make the scarf?.

Answers

Nancy is hard at work on a scarf. She spends twenty seconds on every inch of the scarf she knits. Her desired scarf length is sixty inches. Given, It takes 0.2 of an hour to knit a single inch of the scarf. Here, 0.2 of an hour refers to 12 minutes. Therefore, It takes 12 minutes to knit an inch of a scarf.

Since Nancy takes 12 mins to knit an inch of a scarf, then for 60 inches, it would be,

1 inch -> 12 minutes

60 inches -> 12 * 60 minutes = 720 mins to knit 60 inches of a scarf.

Now, convert the minutes into hours,

720 mins -> 720 / 60 = 12 hours.

Therefore, it takes 12 hours to knit 60 inches of a scarf.

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. unpolarized light is incident upon a smooth surface. when light reflected from this surface is totally polarized, the incident light angle is named the

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Brewster's angle

When unpolarized light is incident at Brewster's angle on a smooth glass surface, the reflected light is totally polarized while the refracted light is partially polarized

Polarization:

Polarization is a assets making use of to transverse waves that specifies the geometrical orientation of the oscillations. In a transverse wave, the route of the oscillation is perpendicular to the direction of motion of the wave.In contrast, for longitudinal waves, such as sound waves in liquids or gases, the particles are always displaced in the direction of propagation during oscillation, so these waves have no polarization. Transverse waves that indicate polarization include electromagnetic waves such as light and radio waves, gravitational waves, and sound waves in solids (transverse waves).

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If a 65-kilogram astronaut exerts a force with a magnitude of 50. Newtons on a satellite that she is repairing, the magnitude of the force that the satellite exerts on her is.

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The magnitude of force ( 50 N ) which satellite exerts on her but in opposite direction.

We will apply the Newton's Third Law of motion for solving this problem, which says that, "To each activity, there is an equivalent and inverse response". And that implies if any article (say object 1) apply some power on another article (say object 2), then, at that point, the item 2 will likewise apply same greatness of power on object 1, yet it will be in inverse heading.

So, we have amount of force exerted by a 65-kg astronaut on satellite which is 50N.

To balance that force, satellite will apply same amount of force on astronaut but in just opposite direction .

F' = - F

or F' = - 50 N.

Here, negative sign shows that the direction of force is opposite.

Hence, required value of force is 50N.

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the range of visible light wavelengths is between 3.9 x 10 -7 m and 7.0 x 10 -7 m. what is the corresponding range of frequencies for visible light?

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The range of visible light is from 7.69 * 10¹⁴ Hz.

Frequency is defined as the number of complete cycles a wave can complete in one second. We know that, the SI unit of frequency is Hertz (Hz).

We know the relation between speed of light, wavelength and frequency as

v = f * λ ----(1)

where, v is the speed of light in air

f is the frequency of visible light

λ is the wavelength of visible light

Making ' f ' as subject in the above equation as,

f = v / λ ----(2)

We know that speed of light in air is 3 * 10⁸ m/s

λ = from 3.9 * 10⁻⁷ m

Substituting the values in the above equation (2), we have

f = v / λ = (3 * 10⁸)/(3.9 * 10⁻⁷) = 0.769 * 10¹⁵ Hz = 7.69 * 10¹⁴ Hz

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you are lying on your back on the slope of a grassy hill, watching the clouds go by overhead. which is the best statement about the force of friction exerted on you by the ground in this situation?

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The best statement about the force of friction exerted on you by the ground is that a force of static friction pointing up the hill, parallel to the surface of the hill is applied to you by the ground.

Static friction is define as the force that is exerted so as to keep the object at rest. The friction experienced when individuals try to move a stationary object on a surface, without actually triggering any relative motion between the body and the surface on which it is on.

Following, the Newton's Third law of Force, every action has equal and opposite reaction. Hence, to neutralize the force acting on the ground due to you, a parallel force exerted by the ground acts on on you.

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What is the change in internal energy AU for a reaction that gives off 65 J of heat and does 38 J of work?

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The change in internal energy will be 27J when heat is released.

Every time a process occurs, it is usually accompanied by an energy shift. Energy comes in many forms, such as heat, light, and work.

The generation or absorption of energy in various processes dictates that each substance must be associated with a certain amount of energy. Its actual value depends on the nature of the material and the conditions of temperature, pressure, volume and composition.

The sum of various types of energy associated with atoms and molecules, such as electronic energy (Ee), nuclear energy (En), chemical bond energy (Ec), potential energy (Ep), and kinetic energy (Ek). Sum of translational energy (Et), vibrational state energy (Ev), and rotational energy (Er).

Represented by the symbol U or E.

U or E = Ee + En + Ec + Ep + Ek

The energy stored in matter in this way is called internal energy.

U=65-38=27J

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Ocean waves crash on the beach at a velocity of 3. 5 m/s. If the distance between the crests of each wave is 4 m, find the frequency of the waves.

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The frequency of the waves is 0.88 Hz.

It is given to us that -

Ocean waves crash on the beach at a velocity of 3. 5 m/s

The distance between the crests of each wave is 4 m

We have to find the frequency of the waves.

We know that the velocity of the ocean waves can be represented by the formula as -

v = f * λ ---- (1)

where,

f = frequency of the ocean waves

λ = distance between the crests of each wave

According to the given information, we have -

velocity, v = 3.5 m/s

and, distance between the crests of each wave, λ = 4 m

Substituting these values in equation (1), we can find out the frequency of the ocean waves as -

v = f * λ

=> 3.5 = f * 4

=> f = 3.5/4

=> f = 0.88 Hz

Thus, the frequency of the waves is 0.88 Hz.

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How will you describe the different regions of EM spectrum?

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In order from highest to lowest energy, the sections of the electromagnetic spectrum are named as gamma rays, x-rays, ultraviolet radiation, visible light, infrared radiation and radio waves.

The electromagnetic spectrum is the range of all types of electromagnetic radiation. Radiation is the energy that travels and spreads out as it goes - the visible light coming from a lamp in your house and the radio waves that come from a radio station are two types of electromagnetic radiation.

Electromagnetic radiation is an electric and magnetic disturbance travelling through space at the speed of light. It contains neither mass nor charge but travels in packets of radiant energy called photons.

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