The inequality that represents the situation is:
[tex]1.49x+1.75\le24[/tex]Where x is the number of Kit Kat we could buy.
will you kindly assist me pls. work math step by step answer in numbers pls. to work how you got the answer
Translating for numbers, we have:
[tex]\frac{1}{5}=0,2\rightarrow3\frac{1}{5}=3,2[/tex]This way, we can make what follows:
[tex]Day_1+Day_2=3\frac{1}{5}+4=3,2+4=7,2_{}[/tex]Calculating now the amount is needed to complete the 9 miles:
[tex]Day_3=9-7,2\text{ = 1,8}[/tex]--------------------------------------------------------------------------------------------------------
And from here, the solution with the fractions.
We can start with the sum of what Shelly has biked in the first two days:
[tex]Day_1+Day_2=3\frac{1}{5}+4=7\frac{1}{5}_{}[/tex]This is the amount of mile she has already biked. But we know she needs to complete all the 9 miles in the third day. So, the difference from 9 and the amount she already did is the amount she needs to bike in the third day.
[tex]\text{Day}_3\text{ = 9 - 7}\frac{1}{5}\text{ = 1}\frac{4}{5}[/tex]what is the value of x would make lines l and m parrallel
We know that if l and m are parallel there might be some angles that are equal to others:
Alternate interior angles
The angles closed by a blue circle are alternate interior angles, then they should be equal if l||m.
Vertcial angles
The angles closed by an orange circle are vertical angles, because they are opposite to each other on two crossed lines.
Now, we know two angles of the triangle of the middle:
We know that the addition of all the inner angles of a triangle is 180º. This is:
50º + 55º + xº = 180º
↓
105º + xº = 180º
Now, we can find x:
105º + xº = 180º
↓
xº = 180º - 105º
xº = 75º
Answer: xº = 75ºwhat scale factor or multiplier of the dilation below
Given:
The triangle ABC is similar to the triangle A'B'C'
So, the corresponding sides are proportions
So, the factor of dilation will be:
[tex]\frac{A^{\prime}B^{\prime}}{AB}=\frac{8}{12}=\frac{2}{3}[/tex]so, the answer will be 2/3
The points scored on a test for a sample of 39 students are summarized in the following table
the mean score of the test for sample of 39 students is 76.92.
The data is given as:
Number of students Score of each student Total score
07 90 630
17 80 1360
11 70 770
04 60 240
The total number of students = 7 + 17 + 11 + 4
n = 39
Total scores = 630 + 1360 + 770 + 240
T = 3000
Mean score = T / n
M = 3000 / 39
M = 1000 / 13
M = 76.92
Therefore, the mean score of the test for sample of 39 students is 76.92.
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Consider the quadratic function.What are the x-intercepts and y-intercept?What is the equation of the axis of symmetry?What are the coordinates of the vertex?Graph the function on the coordinate plane. Include the axis of symmetry.
Kindly check below
1) Let's do it in parts.
a) We can find the x-intercepts by using the factor zero property from each factor. Like this:
[tex]\begin{gathered} -(x+4)=0\Rightarrow-x-4=0\Rightarrow-x=4\Rightarrow x=-4 \\ (x-1)=0\Rightarrow x=1 \end{gathered}[/tex]The best way to find the y-intercept with this factored form is by plugging into that equation x=0
[tex]\begin{gathered} f(x)=-\left(x+4\right)\left(x-1\right) \\ y=-\left(x+4\right)\left(x-1\right) \\ y=-(0+4)(0-1) \\ y=-(4)(-1) \\ y=4 \end{gathered}[/tex]b) Expanding those factors by distributing them (FOIL) we can find this:
[tex]\begin{gathered} f(x)=-\left(x+4\right)\left(x-1\right) \\ f(x)=-\left(xx+x\left(-1\right)+4x+4\left(-1\right)\right) \\ f(x)=-x^2-3x+4 \end{gathered}[/tex]So now, let's find the x-coordinate of the vertex V(h,k):
[tex]\begin{gathered} h=\frac{-b}{2a}=\frac{-(-3)}{2(-1)}=\frac{3}{-2}=-\frac{3}{2} \\ Axis\:of\:symmetry:x=-3/2 \end{gathered}[/tex]c) The coordinates of the vertex can be found by plugging the x-coordinate into the quadratic function. This way:
[tex]\begin{gathered} f(x)=-\left(x+4\right)\left(x-1\right) \\ f(-\frac{3}{2})=-(-\frac{3}{2}+4)(-\frac{3}{2}-1)=\frac{25}{4} \\ \\ V(-\frac{3}{2},\frac{25}{4}) \end{gathered}[/tex]d) Finally, we can plot that function by setting a table:
So plotting these points (-2,6),(-1,6), (0,4), (1,0),(2,-6) and opening down the parabola for a is -1 we can plot this:
Han spent a total of $221.76, before tax, on bags of chips for the basketball team, and each bag cost $3.52. What is the total number of bags of chips that Han bought?
Given:
a.) Han spent a total of $221.76, before tax, on bags of chips for the basketball team.
b.) Each bag cost $3.52.
Let's determine the number of bags of chips bought.
[tex]\text{ No. of bags of chips bought = }\frac{\text{ Total cost}}{\text{ Price of each bag}}[/tex][tex]\text{ = }\frac{\text{ 221.76}}{\text{ 3.52}}[/tex][tex]\text{ = 63}[/tex]Therefore, Han bought 63 bags of chips for the basketball team.
The answer is 63.
Instructions: varies indirectly with . If =7 when =−4, find when =2. Use the forward slash (i.e. "/") for all fractions (e.g. -1/2 is the same as −12).
y varies directly as x
This can be written mathematically as:
y = kx
If y = 7, x = -4
Solve for the constant k
7 = -4k
k = -7/4
The equation is:
y = -7/4 x
When x = 2
substitute x =2 anto the equatio n y = -7/4 x
[tex]\begin{gathered} y=-\frac{7}{4}\times2 \\ \\ y=-\frac{7}{2} \end{gathered}[/tex]- 16m’n-(-25m’n)+(-7m’n)Which of the following is equivalent to the expression above?
As a rule , - times - = + and - times + = -
[tex]\begin{gathered} -16m^2n-(-25m^2n)+(-7m^2n\text{ ) } \\ =-16m^2n+25m^2n-7m^2n\text{ ( based on the rule above )} \\ =+9m^2n-7m^2n\text{ ( -16 + 25 = + 9 )} \\ =+2m^2n \end{gathered}[/tex]Therefore the correct answer to the question is 2m squared n
The ratio of the length of an airplane wing to its width is 9 to 1. If the length of a wing is 43.9 metérs, how wide must it be? The airplane wing must be ____ meters wide. (Round to the nearest hundredth.)
To compute the width of the wing, we can use the next proportion
[tex]\frac{9\text{ meters long}}{43.9\text{ meters long}}=\frac{1\text{ meter wide}}{x\text{ meters wide}}[/tex]Solving for x,
[tex]\begin{gathered} 9\cdot x=1\cdot43.9 \\ x=\frac{43.9}{9} \\ x=4.88 \end{gathered}[/tex]The airplane wing must be 4.88 meters wide.
24 2. Which two teams have equivalent ratios of wins to losses? Team Wins Losses Leopards 15 10 Pirates 12 8 Knights 14 7 Lions 18 10
The ratio wins to losses of each team are:
[tex]\begin{gathered} \text{Leopards:}\frac{15}{10}=\frac{3}{2} \\ \text{ Pirates:}\frac{12}{8}=\frac{3}{2} \\ \text{Knights:}\frac{14}{7}=2 \\ \text{Lions:}\frac{18}{10}=\frac{9}{5} \end{gathered}[/tex]Then, Leopards and Pirates have the same ratio
Example 10 in. 20 in. A carpenter builds the table shown. If the floor is level, how likely is it that a ball placed on the table will roll off? 20 in. 10 in.
According to the given image, the table has a flat surface, whcih means the ball would not roll off because there's no slope or inclination. Also, assuming that there's no other forces being applied, the ball should not roll off.
The probability that VSU and KSU both win a basketball game in the same week is 47%. Theprobability that VSU wins is 50%. What is the probability that KSU will win given that VSUhas already won?
EXPLANATION
Let the probability that KSU will win a game be Pr(A), and let the probability that VSU wins be Pr(B). Therefore;
[tex]\begin{gathered} Pr(A\cap B)=0.47 \\ Pr(B)=0.5 \end{gathered}[/tex]We can then use the conditional probability formula below.
[tex]Pr(A|B)=\frac{Pr(A\cap B)}{Pr(B)}[/tex]Therefore, the probability that KSU will win given that VSU has already won becomes
[tex]Pr(A|B)=\frac{0.47}{0.50}=0.94[/tex]Answer: 0.94
Consider the functions g(x) = 2x + 1 and h(x) = 2x + 2 for the domain 0 < x < 5 Without evaluating or graphing the functions, how do the ranges compare?
Without evaluating or graphing the functions, it is obvious that the minimum and maximum values in the range of h(x) is greater than the minimum and maximum values in the range of g(x) by 1.
What is a domain?In Mathematics, a domain simply refers to the set of all real numbers for which a particular function is defined. This ultimately implies that, a domain represents the input values (x-values) to a function.
What is a range?In Mathematics, a range can be defined as the set of all real numbers that connects with the elements of a domain. This ultimately implies that, a range refers to the set of all possible output numerical values (real numbers), which are shown on the y-axis of a graph.
In conclusion, the minimum and maximum values in the range of h(x) differs from those of function g(x) by 1.
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How to round off 18,600 to the nearest 10,000
Answer:
The nearest 10,000 is;
[tex]20,000[/tex]Explanation:
We want to round off the given number to the nearest 10,000.
[tex]18,600[/tex]We will find the closest ten thousand to the given number;
[tex]18,600\rightarrow20,000[/tex]Therefore, the nearest 10,000 is;
[tex]20,000[/tex]
.
A culture of bacteria has an initial population of 220 bacteria and doubles every 8
hours. Using the formula Pt = Po · 2a, where P is the population after t hours, Po
is the initial population, t is the time in hours and d is the doubling time, what is the
population of bacteria in the culture after 11 hours, to the nearest whole number?
The population of bacteria in the culture after 11 hours is 581 using the exponential decay formula.
What is meant by population?The total number of people living in a particular area, such as a city or town, region, country, continent, or the entire world, is typically referred to as the population. Governments frequently conduct censuses to estimate the number of residents living within their jurisdiction. A census is a process for gathering, analyzing, compiling, and releasing statistics regarding a population.
A culture of bacteria has an initial population of 220 bacteria, which doubles every eight hours, according to the information provided.
By applying the formula,
P(t)=P₀.[tex]2^{t/d}[/tex]
P(t) is the population at the end of t hours.
P0 is the starting populace.
d is the doubling time, while t is the time in hours.
After 11 hours, we are asked to determine the bacteria population.
First, we will enter the following values in the doubling life formula as substitutes:
P(t)=220([tex]2^{t/8}[/tex])
Now we will substitute t=11 in our formula to find the population of bacteria after 11 hours as follows:
P(11)=220([tex]2^{17/8}[/tex])
P(11)=220([tex]2^{1.4}[/tex])
P(11)=220(2.639015822)
P(11)=580.5834807≈581
P(11)=581
Consequently, after 11 hours, there will be 581 bacteria.
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I'll send you the pic
1. 5 (3) = 15
2. 4 (8) = 32
3. 6 (3/2) = 9
4. 12 ( ) = ?
Gaby's piggy bank contains quarters and nickels worth $7.50. If she has 58 coins in all, howmany of each does she have?
let the number of quarters = x , and the number of nickels = y
quarter = $0.25 and nickel = $0.05
So, x + y = 58
x = 58 - y
and 0.25 x + 0.05 y = 7.5
so,
0.25 (58 - y) + 0.05 = 7.5
14.5 - 0.25 y + 0.05 y = 7.5
-0.2 y = -7
y = -7/-0.2 = 35
x = 58 - 35 = 23
So, the number of quarters = 23 and the number of nickels = 35
Latrice eamns 5 points for each question she answers correctly. Her grade, g is described by g = 5c, where c is the number of questions answered correctly. What is the dependent variable-Number of points per question-total grade-number of questions missed-number of questions right
The equation that describe's Latrice grade is given by:
g = 5c
g represen
the sum of 2 numbers is 75. the second number is 3 less than twice the first. find the numbers
SOLUTION
Let one of the numbers be x
Using the statement: The second number is 3 less than twice the first
Then the second number is
[tex]2x-3[/tex]Since, the sum of 2 numbers is 75
It follows:
[tex]x+2x-3=75[/tex]Solve for x
[tex]\begin{gathered} 3x=75+3 \\ 3x=78 \\ x=\frac{78}{3} \\ x=26 \end{gathered}[/tex]Therefore the first number is 24
The second number is
[tex]\begin{gathered} 2(26)-3 \\ =49 \end{gathered}[/tex]therefore the numbers are 49 and 26.
Gifty works out that the material for a dress cost R dollar per meter and 3 meters are required for the dress. Acessories cost $50.00. what is the total amount of money Gifty will need to spend on the dress in terms of R? If Gifty has $4000 to spend on her dress including accessories, what is the maximum value of R?
We are given that
Cost of dress per meter = $R
Total cost of dress = $ 3R
Cost of Acessories = $50
We want to find:
Part A
The total amount of money Gifty will need to spend on the dress in terms of R
To find the total amount, we just add up
Let T denotes the total amount of money
[tex]\begin{gathered} T=3R+50 \\ \end{gathered}[/tex]Thus, the total amount is $ (3R + 50)
Part B
If Gifty has $4000 to spend on her dress including accessories, what is the maximum value of R?
We only need to equate T to 4000 and solve for R
[tex]\begin{gathered} T=4000 \\ 3R+50=4000 \\ 3R=4000-50 \\ 3R=3950 \\ R=\frac{3950}{3} \\ R=1316.666667 \\ R=1316.67\text{ (to 2 decimal places)} \end{gathered}[/tex]Thus, the maximum value of R is $1316.67
3. The difference of two-thirds of a number x and6 is at least -24. Which inequality represents allpossible values for x?
We will solve as follows:
The expression represented in the text is:
[tex]\frac{2}{3}x-6\ge-24[/tex]Now, we solve for x:
[tex]\Rightarrow\frac{2}{3}x\ge-18\Rightarrow2x\ge-54[/tex][tex]\Rightarrow x\ge-27[/tex]So, the solution is x >= 27. [Option D]
Simple calculator test - determine the angle, θ, to the nearest whole degree from each of the following:A. cos(θ) = 0.2079B. tan(θ) = 0.2126C. sin(θ) = 0.5446
Step 1
Find the value of θ using the inverse sign of all the functions.
A)
[tex]\begin{gathered} cos(\theta)=0.2079 \\ \theta=\cos^{-1}(0.2079) \\ \theta\approx78^{\circ} \end{gathered}[/tex]B)
[tex]\begin{gathered} tan(\theta)=0.2126 \\ \theta=\tan^{-1}(0.2126) \\ \theta\approx12^{\circ} \end{gathered}[/tex]C)
[tex]\begin{gathered} sin(\theta)=0.5446 \\ \theta=\sin^{-1}(0.5446) \\ \theta\approx33^{\circ} \end{gathered}[/tex]7. The manager of a local restaurant has found that his cost function for producing coffee is C(x) = .097x, where C(x) is the total cost in dollars of producing x cups. (He is ignoring the cost of the coffeepot and the cost labor.) Find the total cost of producing the following numbers of cups of coffee. (a) 1000 cups (b) 1001 cups (c) What is the marginal cost for any cup? Let C(x) be the total cost in dollars to manufacture x items. Find the average cost in exercises 8 and 9.
To solve for the total cost of producing the following numbers of cups of coffee:
[tex]\begin{gathered} C(x)=0.097x \\ \end{gathered}[/tex]where
[tex]\begin{gathered} x=nu\text{mber of cups of coff}e \\ C(x)=total\text{ cost }in\text{ dollars of producing x cups} \end{gathered}[/tex](a) The total cost of producing 1000 cups =
[tex]\begin{gathered} C(x)=0.097x \\ x=1000 \\ C(x)=1000(0.097)=\text{ \$97} \end{gathered}[/tex](b) The total cost of producing 1001 cups =
[tex]\begin{gathered} C(x)=0.097x \\ x=1001 \\ C(x)=1001(0.097)=\text{ \$97}.097 \end{gathered}[/tex](c) The marginal cost for any cup = $0.097
marginal cost can be found by taking the derivative of the function
[tex]\begin{gathered} C(x)=0.097x \\ C^1(x)=0.097=\text{ \$0.097} \end{gathered}[/tex]Not ConnectedThunde...lt BridgeNot Connected2 (07.01 HC)answer the following question. Find the value of sin x and cosy. What relationship do the ratios of sin x® and cos yº share?
The given triangle is a right-angled triangle.
Consider PO is Hypotenuse.
By using the Pythagoras formula, we get
[tex]PO^2=8^2+6^2[/tex][tex]PO^2=64+36[/tex][tex]PO^2=100=10^2[/tex][tex]PO=10[/tex]Consider the angle x:
Recall the sine formula
[tex]\sin \theta=\frac{Opposite\text{ side}}{\text{Hypotenuse}}[/tex]Substitute Opposite side =6 and Hypotenuse=10, we get
[tex]\sin x^o=\frac{6}{10}[/tex][tex]\sin x^o=\frac{3}{5}[/tex][tex]\text{Use sin }36.869=\frac{3}{5}[/tex][tex]\sin x^o=\sin 36.869[/tex][tex]x^o=37[/tex]Consider the angle y:
Recall the sine formula
[tex]\sin \theta=\frac{Opposite\text{ side}}{\text{Hypotenuse}}[/tex]Substitute Opposite side =8 and Hypotenuse=10, we get
[tex]\sin y^o=\frac{8}{10}[/tex][tex]\sin y^o=\frac{4}{5}[/tex][tex]\text{Use }\sin 53.13^{}=\frac{4}{5}[/tex][tex]\sin y^o=\sin \text{ 53.13}[/tex][tex]y^o=53^{}[/tex]Hence the required values are
[tex]x^o=37^o[/tex][tex]y^o=53^o[/tex]claudia earns overtime pay when she works more then 40 hours in a week how many hours of overtime pay did she work for the week of march 4march 4-10march 4 -- 8.5march 5 -- offmarch 6 -- 9.25march 7 -- 8.75march 8 -- 10march 9 -- offmarch 10 -- 7.75A.44.25B. 40.0C. 4.25D. 2.25
She earns overtime pay when she works more than 40 hours in one week . The number of overtime pay she works for the weeks of march 4 can be calculated below
[tex]\begin{gathered} \text{total hour worked =}8.5\text{ +9.25+8.75+10+7.75=}44.25 \\ \text{The number of overtime pay for the w}eek\text{ of march 4 is 44.25} \end{gathered}[/tex](k²-7k+ 10) ÷ (k − 1)
Which values has three significant figures?14001001101.22310
a) 1400 has 2 significant figures, zeros are no consider as significant figures
b) 1001 has 4 significant figures, zeros in between two nonzero numbers are significant figures
c) 101.2 has 4 significant figures, zeros in between two nonzero numbers are significant figures. Nonzero number are significant figures
d) 2310 has three significant figures. 2,3 and 1 are significant figures.
whats the variance and the standard deviation of the data set 6,9,2,5,4,10,3,12,2,7,7,8
Given:
6,9,2,5,4,10,3,12,2,7,7,8
Required:
To find the variation and standard deviation of the given data set.
Explanation:
Now variation is
[tex]s^2=\frac{\sum_{i\mathop{=}1}^n(x_i-x)^2}{n-1}[/tex]The numerator in the above is sum of the square of the given data.
Therefore,
[tex]\begin{gathered} =(6-6.25)^2+(9-6.25)^2+(2-6.25)^2+(5-6.25)^2+(4-6.25)^2+(10-6.25)^2+ \\ (3-6.25)^2+(12-6.25)^2+(2-6.25)^2+(7-6.25)^2+(7-6.25)^2+(8-6.25)^2 \end{gathered}[/tex][tex]\begin{gathered} s^2=\frac{112.25}{12-1} \\ \\ =\frac{112.25}{11} \\ \\ =10.2045 \end{gathered}[/tex]Final Answer:
[tex]10.2045[/tex]Thinking: Two students were having a discussion. They stated:“Since we factored f(x) = 2x2 + 3x + 1 into (2x+1)(x+1) we could say this:If we let h(x) = 2x + 1 and g(x) = x + 1, then we can say f(x) = h(x)g(x)” Howmight you verify their statement?
Given:
If we let h(x) = 2x + 1 and g(x) = x + 1 and
[tex]f(x)=2x^2+3x+1[/tex]Required:
How might you verify their statement?
Explanation:
We have h(x) and g(x)
[tex]\begin{gathered} =h(x)g(x) \\ =(2x+1)(x+1) \\ =2x^2+2x+x+1 \\ 2x^2+3x+1=f(x) \\ f(x)=h(x)g(x) \end{gathered}[/tex]Answer:
Hence, verified the statement.
What are the coordinates of point P on the directed line segment from R to Q such that 5 Pis 6 the length of the line segment from R to Q? Round to the nearest tenth, if necessary. A (-3.5, 2.3 ) B. (3.5, -2.3 ) C. (-3, 2) D. (3, 2)
Answer
Option A is correct.
P(x, y) = (-3.5, 2.3)
Explanation
Mathematically, if a point P(x, y) divides the coordinates R(x₁, y₁) and Q(x₂, y₂) internally in the ratio m:n then point P(x, y) is given as
x = [(mx₂ + nx₁)/(m + n)]
y = [(my₂ + ny₁)/(m + n)]
For this question,
R(x₁, y₁) and Q(x₂, y₂) = R (4, -1) and Q (-5, 3)
m:n = 5:1 (5/6 of a distance divides the two parts of the distance into 5/6 and 1/6, hence, the ratio is 5:1)
x₂ = -5
x₁ = 4
y₂ = 3
y₁ = -1
m = 5
n = 1
x = [(mx₂ + nx₁)/(m + n)]
x = [(5×-5 + 1×4)/(5 + 1)]
x = [(-25 + 4)/(5 + 1)]
x = (-21/6)
x = -3.5
y = [(my₂ + ny₁)/(m + n)]
y = [(5×3 + 1×-1)/(5 + 1)]
y = [(15 - 1)/(5 + 1)]
y = (14/6)
y = 2.3
P(x, y) = (-3.5, 2.3)
Hope this Helps!!!