Write the MIPS assembly code to find the area of a given shape. Your program must take a floating-point value and shape (Circle - 1, Triangle - 2, Square - 3) as input and return the circumference/perimeter and area of the shape. Assume the floating-point value units are meters and the triangle is an equilateral triangle. [Note: you can search for the expression to calculate the area and circumference/perimeter of these shapes]
Answers
Answer:
Explanation:
.data
msg1: .asciiz "Enter the floating point value = "
msg2: .asciiz "\nEnter the shape (Circle - 1, Triangle - 2, Square - 3) = "
msg3: .asciiz "\nThe perimeter of the triangle with side = "
msg4: .asciiz " meters is "
msg5: .asciiz " meters.\n"
msg6: .asciiz "\nThe area of the triangle with side = "
msg7: .asciiz " square meters.\n"
msg8: .asciiz "\nThe circumference of the circle with radius = "
msg9: .asciiz "\nThe area of the circle with radius = "
msg10: .asciiz "\nThe perimeter of the square with side = "
msg11: .asciiz "\nThe area of the square with side = "
pi: .float 3.1415816
eq_tr_area: .float 0.43305186
two: .float 2
three: .float 3
four: .float 4
.text
li $v0,4 # system call code for printing string = 4
la $a0,msg1 # load address of string to be printed into $a0
syscall # call operating system to perform print operation
li $v0,6 # system call code for reading floating point number
syscall # call operating system to perform read operation
li $v0,4 # system call code for printing string = 4
la $a0,msg2 # load address of string to be printed into $a0
syscall # call operating system to perform print operation
li $v0,5 # system call code for reading integer
syscall # call operating system to perform read operation
move $t0,$v0
IF:
bne $t0,1,ELSE_IF #if not 1 then goto elseif
li $v0,4 # system call code for printing string = 4
la $a0,msg8 # load address of string to be printed into $a0
syscall # call operating system to perform print operation
li $v0, 2 # system call code for printing float = 2
mov.s $f12,$f0 #move the single precision f2 in f12
syscall # call operating system to perform print operation
li $v0,4 # system call code for printing string = 4
la $a0,msg4 # load address of string to be printed into $a0
syscall # call operating system to perform print operation
l.s $f1,pi
l.s $f3,two
mul.s $f3,$f3,$f1 #calculate 2*pi*radius
mul.s $f3,$f3,$f0
li $v0, 2 # system call code for printing float = 2
mov.s $f12,$f3 #move the single precision f2 in f12
syscall # call operating system to perform print operation
li $v0,4 # system call code for printing string = 4
la $a0,msg5 # load address of string to be printed into $a0
syscall # call operating system to perform print operation
li $v0,4 # system call code for printing string = 4
la $a0,msg9 # load address of string to be printed into $a0
syscall # call operating system to perform print operation
li $v0, 2 # system call code for printing float = 2
mov.s $f12,$f0 #move the single precision f2 in f12
syscall # call operating system to perform print operation
li $v0,4 # system call code for printing string = 4
la $a0,msg4 # load address of string to be printed into $a0
syscall # call operating system to perform print operation
mul.s $f2,$f0,$f0 #calculate radius *radius
mul.s $f2,$f2,$f1 #calculate pi *r^2
li $v0, 2 # system call code for printing float = 2
mov.s $f12,$f2 #move the single precision f2 in f12
syscall # call operating system to perform print operation
li $v0,4 # system call code for printing string = 4
la $a0,msg7 # load address of string to be printed into $a0
syscall
ELSE_IF:
bne $t0,2,ELSE #if not 2 then check else
li $v0,4 # system call code for printing string = 4
la $a0,msg3 # load address of string to be printed into $a0
syscall # call operating system to perform print operation
li $v0, 2 # system call code for printing float = 2
mov.s $f12,$f0 #move the single precision f2 in f12
syscall # call operating system to perform print operation
li $v0,4 # system call code for printing string = 4
la $a0,msg4 # load address of string to be printed into $a0
syscall # call operating system to perform print operation
l.s $f3,three
mul.s $f3,$f3,$f0 #calculate 3*side
li $v0, 2 # system call code for printing float = 2
mov.s $f12,$f3 #move the single precision f2 in f12
syscall # call operating system to perform print operation
li $v0,4
la $a0,msg5
syscall
li $v0,4
la $a0,msg6
syscall
li $v0, 2
mov.s $f12,$f0
syscall
li $v0,4
la $a0,msg4
syscall
l.s $f3,eq_tr_area
mul.s $f2,$f0,$f0
mul.s $f2,$f2,$f3
li $v0, 2
mov.s $f12,$f2
syscall
li $v0,4
la $a0,msg7
syscall
ELSE:
bne $t0,3,END
li $v0,4
la $a0,msg10
syscall
li $v0, 2
mov.s $f12,$f0
syscall
li $v0,4
la $a0,msg4
syscall
l.s $f3,four
mul.s $f3,$f3,$f0
li $v0, 2
mov.s $f12,$f3
syscall
li $v0,4
la $a0,msg5
syscall
li $v0,4
la $a0,msg11
syscall
li $v0, 2
mov.s $f12,$f0
syscall
li $v0,4
la $a0,msg4
syscall
mul.s $f2,$f0,$f0
li $v0, 2
mov.s $f12,$f2
syscall
li $v0,4
la $a0,msg7
syscall
END:
li $v0,10
syscall
Code is as follows:
.data
msg1: .asciiz "Enter the floating point value = "
msg2: .asciiz "\nEnter the shape (Circle - 1, Triangle - 2, Square - 3) = "
msg3: .asciiz "\nThe perimeter of the triangle with side = "
msg4: .asciiz " meters is "
msg5: .asciiz " meters.\n"
msg6: .asciiz "\nThe area of the triangle with side = "
msg7: .asciiz " square meters.\n"
msg8: .asciiz "\nThe circumference of the circle with radius = "
msg9: .asciiz "\nThe area of the circle with radius = "
msg10: .asciiz "\nThe perimeter of the square with side = "
msg11: .asciiz "\nThe area of the square with side = "
pi: .float 3.1415816
eq_tr_area: .float 0.43305186
two: .float 2
three: .float 3
four: .float 4
.text
li $v0,4 # system call code for printing string = 4
la $a0,msg1 # load address of string to be printed into $a0
syscall # call operating system to perform print operation
li $v0,6 # system call code for reading floating point number syscall # call operating system to perform read operation
li $v0,4 # system call code for printing string = 4 la $a0,msg2 # load address of string to be printed into $a0 syscall # call operating system to perform print operation
li $v0,5 # system call code for reading integer syscall # call operating system to perform read operation move $t0,$v0
IF:
bne $t0,1,ELSE_IF #if not 1 then goto elseif
li $v0,4 # system call code for printing string = 4
la $a0,msg8 # load address of string to be printed into $a0
syscall # call operating system to perform print operation
li $v0, 2 # system call code for printing float = 2 mov.s $f12,$f0 #move the single precision f2 in f12 syscall # call operating system to perform print operation
li $v0,4 # system call code for printing string = 4 la $a0,msg4 # load address of string to be printed into $a0
syscall # call operating system to perform print operation
l.s $f1,pi l.s $f3,two
mul.s $f3,$f3,$f1 #calculate 2*pi*radius
mul.s $f3,$f3,$f0
li $v0, 2 # system call code for printing float = 2
mov.s $f12,$f3 #move the single precision f2 in f12
syscall # call operating system to perform print operation
li $v0,4 # system call code for printing string = 4
la $a0,msg5 # load address of string to be printed into $a0
syscall # call operating system to perform print operation
li $v0,4 # system call code for printing string = 4
la $a0,msg9 # load address of string to be printed into $a0
syscall # call operating system to perform print operation
li $v0, 2 # system call code for printing float = 2
mov.s $f12,$f0 #move the single precision f2 in f12
syscall # call operating system to perform print operation
li $v0,4 # system call code for printing string = 4
la $a0,msg4 # load address of string to be printed into $a0
syscall # call operating system to perform print operation
mul.s $f2,$f0,$f0 #calculate radius *radius
mul.s $f2,$f2,$f1 #calculate pi *r^2
li $v0, 2 # system call code for printing float = 2
mov.s $f12,$f2 #move the single precision f2 in f12
syscall # call operating system to perform print operation
li $v0,4 # system call code for printing string = 4
la $a0,msg7 # load address of string to be printed into $a0
syscall
ELSE_IF:
bne $t0,2,ELSE #if not 2 then check else
li $v0,4 # system call code for printing string = 4 la $a0,msg3 # load address of string to be printed into $a0 syscall # call operating system to perform print operation
li $v0, 2 # system call code for printing float = 2
mov.s $f12,$f0 #move the single precision f2 in f12
syscall # call operating system to perform print operation
li $v0,4 # system call code for printing string = 4
la $a0,msg4 # load address of string to be printed into $a0
syscall # call operating system to perform print operation
l.s $f3,three
mul.s $f3,$f3,$f0 #calculate 3*side
li $v0, 2 # system call code for printing float = 2
mov.s $f12,$f3 #move the single precision f2 in f12
syscall
bne $t0,3,END #if not 3 then end
li $v0,4 # system call code for printing string = 4
la $a0,msg10 # load address of string to be printed into $a0
syscall # call operating system to perform print operation
li $v0, 2 # system call code for printing float = 2
mov.s $f12,$f0 #move the single precision f0 in f12
syscall # call operating system to perform print operation
li $v0,4 # system call code for printing string = 4
la $a0,msg4 # load address of string to be printed into $a0
syscall # call operating system to perform print operation
l.s $f3,four # multilply by 4
mul.s $f3,$f3,$f0 #calculate 4*side
li $v0, 2 # system call code for printing float = 2
mov.s $f12,$f3 #move the single precision f3 in f12
syscall # call operating system to perform print operation
END:
li $v0,10 # system call code for printing exit (end of program)
syscall # call operating system to perform print operation
Learn More:https://brainly.com/question/10169933
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Grooved pavement ahead means
Answers
Answer:it means warning
Explanation:
1
When determining the statement of purpose for a database design, what is the most important question to
Who will use the database?
O Should I use the Report Wizard?
How many copies should I print?
How many tables will be in the database?
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Answer: A) Who will use the database?
Answer:
It's A
Explanation:
Color, font, and images are all important aspects of good
I'll mark brainest
Answers
Answer:
of good design, so its c ....
Answer: Design
Color, font, and images are all important aspects of good Design.
, Hope this helps :)
Have a great day!!
spreadsheet formula for total 91?
Answers
Answer:
Go to any blank cell. Enter the number 91.
Select the cell that contains 91. Press Ctrl+C to copy.
Select your range the contains numbers.
Press Ctrl+Alt+V to open the Paste Special dialog.
In the top of the Paste Special dialog, choose Values. In the Operation section, choose Add. Click OK.
Explanation:
Complete the sentence.
In your program, you can open
Answers
In your program, you can open a file using the open() function in Python.
What is the program about?A high-level, all-purpose programming language is Python. Code readability is prioritized in its design philosophy, which makes heavy use of indentation. Python uses garbage collection and has dynamic typing.
It supports a variety of programming paradigms, such as functional, object-oriented, and structured programming. The open() function in Python allows you to open a file, read its contents, and perform various operations on it, such as writing, appending, etc.
Learn more about program on:
https://brainly.com/question/26642771
#SPJ1
Explain the difference between invention and innovation?
Answers
Programming errors can result in a number of different conditions. Choose all that apply.
The program will halt execution.
An error message will be displayed.
Incorrect results will occur.
Code will run faster.
the first 3
Answers
Answer:
The program will halt execution and and error message will be displayed. Probably number 3 too.
Answer:
A, B and C
Explanation:
CS160 Computer Science I In class Lab 10
Objective:
Work with dictionaries
Work with strings
Work with files
Assignment:
This program will read a file of English words and their Spanish translation. It then asks the user for an English word. If it exists in your dictionary the Spanish translation is displayed. If the English word does not exist in the dictionary the program states that the word does not exist in its list of words.
Specifics:
Create a text file, with one English word and a Spanish word per line, separated by a colon. You can create the language file using a text editor, you do not need to write a program to create this file. An example of the file might be:
one:uno
two:dos
three:tres
four:cuatro
five:cinco
six:seis
seven:siete
eight:ocho
nine:nueve
ten:diez
After reading the text file, using it to fill up a dictionary, ask the user for an English word. If the word exists, print out the Spanish version. If the word does not exist state that the word is not in your list. Continue this process of asking for a word until the user does not enter a word (just pressed Enter).
As you might have noticed, there is nothing in the program that limits this Spanish words. This program can be written to work with any translation, so feel free to make it be French, or German or any other language where you can come up with a list of translated words. You also are not limited to 10 words, that is just the list I came up with for the example. The number of key/values pairs that you have in your dictionary is basically limited by the memory in your computer.
Hints
You will need to determine if the key (the English word) exists in the dictionary. Use the in operator with the dictionary, or the get() method. Either can be used to avoid crashing the program, which happens if you attempt to use a key that does not exist.
An example of running the program might be:
Enter the translation file name: oneToTen.txt
> Enter an English word to receive the Spanish translation.
Press ENTER to quit.
Enter an English word: one
he Spanish translation is uno
Enter an English word: ten
The Spanish word is diez
Enter an English word: 5
I don’t have that word in my list.
Enter an English word: three
The Spanish word is tres
Answers
Answer:
The program in Python is as follows:
fname = input("Enter the translation file name: ")
with open(fname) as file_in:
lines = []
for line in file_in:
lines.append(line.rstrip('\n'))
myDict = {}
for i in range(len(lines)):
x = lines[i].split(":")
myDict[x[0].lower()] = x[1].lower()
print("Enter an English word to receive the Spanish translation.\nPress ENTER to quit.")
word = input("Enter an English word: ")
while(True):
if not word:
break
if word.lower() in myDict:
print("The Spanish word is ",myDict[word.lower()])
else:
print("I don’t have that word in my list.")
word = input("Enter an English word: ")
Explanation:
This prompts the user for file name
fname = input("Enter the translation file name: ")
This opens the file for read operation
with open(fname) as file_in:
This creates an empty list
lines = []
This reads through the lines of the file
for line in file_in:
This appends each line as an element of the list
lines.append(line.rstrip('\n'))
This creates an empty dictionaty
myDict = {}
This iterates through the list
for i in range(len(lines)):
This splits each list element by :
x = lines[i].split(":")
This populates the dictionary with the list elements
myDict[x[0].lower()] = x[1].lower()
This prints an instruction on how to use the program
print("Enter an English word to receive the Spanish translation.\nPress ENTER to quit.")
This prompts the user for an English word
word = input("Enter an English word: ")
This loop is repeated until the user presses the ENTER key
while(True):
If user presses the ENTER key
if not word:
The loop is exited
break
If otherwise, this checks if the word exists in the dictionary
if word.lower() in myDict:
If yes, this prints the Spanish translation
print("The Spanish word is ",myDict[word.lower()])
If otherwise,
else:
Print word does not exist
print("I don’t have that word in my list.")
Prompt the user for another word
word = input("Enter an English word: ")
Uhh... What is happening?.. What... Pt 2
Answers
Pistons being pistons I guess...
Answer:
Levers on the parts we cant see?
NO LINKS OR SPAMS THEY WILL BE REPORTD
Click here for 50 points
Answers
Answer:
thanks for the point and have a great day
Please Complete in Java a. Create a class named Book that has 5 fields variables: a stock number, author, title, price, and number of pages for a book. For each field variable create methods to get and set methods. b. Design an application that declares two Book objects. For each object set 2 field variables and print 2 field values. c. Design an application that declares an array of 10 Books. Prompt the user to set all field variables for each Book object in the array, and then print all the values.
Answers
Answer:
Explanation:
The following code is written in Java. I created both versions of the program that was described in the question. The outputs can be seen in the attached images below. Both versions are attached as txt files below as well.
NEED HELP IMMEDIATELY!!
What is the difference between a worm and a typical virus?
A) Worms are a type of spyware; viruses are a type of malware.
B) Worms are impossible to remove; viruses can be tracked and removed.
C) Worms are stronger than viruses; viruses are stronger than spam.
D) Worms travel independently of human action; viruses require human actions.
Answers
Answer:
Option C
Explanation:
Option A is incorrect as Worm is a form of malware
Option B is incorrect because antivirus can remove all forms of malware
Option C is correct because a worm is more problematic as compared to the virus. Also, viruses are weaker than worm because they need a host file to run but a worm can work independently.
Option D is also incorrect because both are able to self replicate.
Can anybody please help me with 7.4.7 spelling bee codehs?
Answers
Answer:
word = "eggplant"
print "Your word is: " + word + "."
for i in word:
print i + "!"
Explanation:
i don't know why but it is
Answer:
word = "eggplant"
print("Your word is !" + word + "!")
for i in word:
INDENT HERE or TAB print( i + "!")
Explanation:
Add an indentation right before the print( i + "!")
Write a function to calculate the distance between two points Distance( x1, y1,x2.2) For example Distance(0.0,3.0, 4.0.0.0) should return 5.0 Use the function in main to loop through reading in pairs of points until the all zeros are entered printing distance with two decimal precision for each pair of points.
For example with input
32 32 54 12
52 56 8 30
44 94 4439 6
5 19 51 91 7.5
89 34 0000
Your output would be:__________.
a. 29.73
b. 51.11
c. 55.00
d. 73.35
e. 92.66
Answers
Answer:
The function in Python3 is as follows
def Distance(x1, y1, x2, y2):
dist = ((x1 - x2)**2 +(y1 - y2)**2)**0.5
return dist
Explanation:
This defines the function
def Distance(x1, y1, x2, y2):
This calculates distance
dist = ((x1 - x2)**2 +(y1 - y2)**2)**0.5
This returns the calculated distance to the main method
return dist
The results of the inputs is:
[tex]32, 32, 54, 12 \to 29.73[/tex]
[tex]52,56,8,30 \to 51.11[/tex]
[tex]44,94,44,39\to 55.00[/tex]
[tex]19,51,91,7.5 \to 84.12[/tex]
[tex]89,34,00,00 \to 95.27[/tex]
Write a recursive method named factorial that accepts an integer n as a parameter and returns the factorial of n, or n!. A factorial of an integer is defined as the product of all integers from 1 through that integer inclusive. For example, the call of factorial(4) should return 1 * 2 * 3 * 4, or 24. The factorial of 0 and 1 are defined to be 1. You may assume that the value passed is non-negative and that its factorial can fit in the range of type int. Do not use loops or auxiliary data structures; solve the problem recursively.
Answers
Answer:
The function in Python is as follows:
def factorial(n):
if n == 1 or n == 0:
return n
else:
return n*factorial(n-1)
Explanation:
This defines the function
def factorial(n):
This represents the base case (0 or 1)
if n == 1 or n == 0:
It returns 0 or 1, depending on the value of n
return n
If n is positive, then this passes n - 1 to the factorial function. The process is repeated until n = 1
else:
return n*factorial(n-1)
Find the sum of the values from one to ten using recursion
Answers
Answer:
see picture
Explanation:
The result is 55, which can also be verified using the formula:
(n)(n-1)/2 => 10*9/2 = 55
Use at Least one hundred words to explain what you did the last time your handheld personal computer went slow.
Answers
Answer:
Disk defragmentation
clear up storage
restart the computer
Explanation:
PC's going slow is a very common occurence nowadays and what i had to do to usually fix slow computers is to first use disk defragmentation which will automatically sort our files and put them in the right order.Second is to delete any unnessary files,folders,programs that i no longer use or its just sitting there eating dust and finally my last resort is to restart the pc which usually helps fix most of the issues including slow PCs which might be caused by some errors during startup.
Hope this helped
A suggestion for improving the user experience
for the app navigation, has the following
severity
Usability
Low
Critical
Medium
High
Answers
User experience is one of the most important things considered in the modern IT world. Almost 90% of the population is dependent on mobile phones, electronic devices. So, one things that come is app development. Therefore, in order to enhance more growth in app development, there need to better user experience. We need to think about users and i don't Know More info.
You are installing a new graphics adapter in a Windows 10 system. Which of the following expansion slots is designed for high-speed, 3D graphics adapters?
A: USB
B: Firewire
C: PCI
D: PCIe
Answers
Answer:
pclex16
NIC
the graphic card must be high
1.Write a Java program to solve the following problem using modularity. Write a method that rotates a one-dimensional array with one position to the right in such a way that the last element becomes the first element. Your program will invoke methods to initialize the array (random values between 1 and 15) print the array before the rotation, rotate the array, and then print the array after rotation. Use dynamic arrays and ask the user for the array size. Write your program so that it will generate output similar to the sample output below:
Answers
Answer:
Explanation:
The following code is written in Java and it asks the user for the size of the array. Then it randomly populates the array and prints it. Next, it rotates all the elements to the right by 1 and prints the new rotated array.
import java.util.ArrayList;
import java.util.Arrays;
import java.util.Random;
import java.util.Scanner;
class Brainly {
public static void main(String[] args) {
Random r = new Random();
Scanner in = new Scanner(System.in);
System.out.println("Enter Size of the Array: ");
int arraySize = in.nextInt();
ArrayList<Integer> myList = new ArrayList<>();
for (int x = 0; x < arraySize; x++) {
myList.add(r.nextInt(15));
}
System.out.println("List Before Rotation : " + Arrays.toString(myList.toArray()));
for (int i = 0; i < 1; i++) {
int temp = myList.get(myList.size()-1);
for (int j = myList.size()-1; j > 0; j--) {
myList.set(j, myList.get(j - 1));
}
myList.set(0, temp);
}
System.out.println("List After Rotation : " + Arrays.toString(myList.toArray()));
}
}
( This isnt really a homework question, its more of just a general question ) I am starting to code C# and I have downloaded visual studio and dotnet, but when trying to run the code for opening a new console template it keeps giving me this error
" dotnet : The term 'dotnet' is not recognized as the name of a cmdlet, function, script file, or
operable program. Check the spelling of the name, or if a path was included, verify that the
path is correct and try again.
At line:1 char:1
+ dotnet new console
+ ~~~~~~
+ CategoryInfo : ObjectNotFound: (dotnet:String) [], CommandNotFoundException
+ FullyQualifiedErrorId : CommandNotFoundException "
Please help me fix this. ( btw i am using dotnet 6.0 SDK, but before that I was using 5.0.203
Answers
Answer:
Explanation:
This is usually an issue with the Microsoft Visual C++ redistributable. One fix that usually works is to do the following
Open Programs and Features
Uninstall and then choose Repair on Microsoft Visual C++ Redistributable (x86) and x64 version
Reinstall or repair the installation of the .NET Core SDK 1.0.1.
If this does not work, another option would be to manually change the install path of these files from "Program Files (x86) to "Program Files"
Hope this helps solve your issue.
Operating Expenses for a business includes such things as rent, salaries, and employee benefits.
Answers
Answer:
TRUE
Explanation:
Requirements description:
Assume you work part-time at a Cafe. As the only employee who knows java programming, you help to write an ordering application for the store.
The following is a brief requirement description with some sample output.
1. Selecting Breakfast or Lunch(5 points)
When the program starts, it first shows option Breakfast or Lunch. A sample output is as follows.
=== Select Breakfast or Lunch: ===
1. Breakfast
2. Lunch
You are supposed to validate the input.
If the user enters a letter or a number not between 1 and 2, the user will see an error message.
A sample output for invalid number is as follows.
Select Breakfast or Lunch [1, 2]: 0
Error! Number must be greater than 0.
Select Breakfast or Lunch [1, 2]:
2. Selecting Coffee (20 points)
When the program continues, it shows a list/menu of coffee and their prices, then asks a user to select a coffee by entering an integer number. A sample output is as follows.
=== Select Coffee: ===
1 Espresso $3.50
2 Latte $3.50
3 Cappuccino $5.00
4 Cold Brew $3.00
5 Quit Coffee selection
Select a coffee [1, 5]:
You are supposed to validate the input.
If the user enters a letter or a number not between 1 and 5, the user will see an error message.
A sample output for invalid number is as follows.
Select a coffee [1, 5]: 0
Error! Number must be greater than 0.
Select a coffee [1, 5]:
In your program, you can hard-code the information for coffee (i.e., coffee names and prices) shown above, such as "1 Espresso $3.50" and use the hard-code price, such as 3.50, for calculation of a total price of the order.
After the user makes a choice for coffe, such as 2 for Latte. The program continues asking for selecting a coffee so that the user can have multiple coffee orders. The user can enter "5" to quit coffee selection. A sample output is as follows.
=== Select Coffee: ===
1 Espresso $3.50
2 Latte $3.50
3 Cappuccino $5.00
4 Cold Brew $3.00
5 Quit Coffee selection
Select Coffee: [1, 5]: 2
=== Select Coffee: ===
1 Espresso $3.50
2 Latte $3.50
3 Cappuccino $5.00
4 Cold Brew $3.00
5 Quit Coffee selection
Select Coffee: [1, 5]: 5
3. Selecting Food (10 points)
After Coffee selection, the program shows food selection. A sample output is as follows.
=== Select Food: ===
1 Tuna Sandwich $10.00
2 Chicken Sandwich $10.00
3 Burrito $12.00
4 Yogurt Bowl $8.00
5 Avocado Toast $8.00
6 Quit Food selection
Select Food: [1, 6]: 1
Input validation is needed and works as before. Like Coffee selection which allows selecting multiple Coffee orders, food selection also repeats after the user enters a valid number between 1 and 5.
You hard-code the information for food shown above, such as "1 Tuna Sandwich $10.00" and use the hard-code price, such as 10.00, for calculation of the total price of the order.
Answers
Answer:
The code has been written in Java.
The source code of the file has been attached to this response. The source code contains comments explaining important lines of the program.
A sample output got from a run of the application has also been attached.
To interact with the program, kindly copy the code into your Java IDE and save as Cafe.java and then run the program.
The following procedure is intended to return the number of times the value val appears in the list nylist. The procedure does not work as intended, Line 1: PROCEDURE countNumoccurences (mylist, val) Line 2: Line 3: FOR EACH item IN mylist Line 4: Line 5: count = 0 Line 6: IF(item = val) Line 7: tine 8: count count + 1 tine 9: Line 10: Eine 11: RETURN (count) Line 12:) Which of the following changes can be made so that the procedure will work as intended?
A. Changing line 6 to IF(item = count)
B. Changing line 6 to IF(myList[item) - val)
C. Moving the statement in line 5 so that it appears between lines 2 and 3
D. Moving the statement in line 11 so that it appears between lines 9 and 10 ->
Answers
Answer:
C. Moving the statement in line 5 so that it appears between lines 2 and 3
Explanation:
Given
The attached procedure
Required
What should be modified
The problem in the procedure is on line 5
i.e. count = 0
This line is within the loop, and this means that the count variable is initialized to 0 each time the loop is repeated.
To solve this, the count variable has to be removed from the loop to somewhere before the loop.
Hence, option (c) is correct
Throughout our procedure, even though we proclaimed count = 0 inside the for loop, the count has been valued at 0.
After that, When a certain value is found equal to Val, the count has been incremented by 1. The count is set to 0 again in the next iteration, so at the end, if we found an element equivalent to Val 1, its real count has been returned.To get around this, we'll define count outside of the for loop to acquire the true count of instances of that specific value.Therefore, the answer is "Option C".
Learn more:
brainly.com/question/14941418
Create a program which reads in CSV data of Creatures and loads them into aHash Map. The key of this hash map will be the name of each creature. For your hash function, you can simply use the sum of all ASCII values. You can also come up with your own hash function. Your program should present a menu to the user allowing them to look up a creature by name. Additionally, create a function that allows the user to insert a new creature. This creature should be added to the existing hash map. If the name entered by the user already exists, DO NOT ADD IT TO THE HASH MAP. Simply report that the creature already exists. If the creature is unique and successfully added, report the calculated index value. Your hash array should start as size4. You will need to implement a rehashing function to maintain a load factor of 0.75. Collision resolution should be handled via separate chaining with linked lists.
Other Requirements
•Read in a CSV file from the command line when running the program.
•Convert the raw CSV data into the creature struct and add it to a HashMap
•Make sure you properly release all of your allocated memory.
•Format your code consistently.
•Function declarations, structs, and preprocess directives should be placed in a corresponding header file.
•Save your code for this problem ascreature_hash.(c|h).
Creature struct
typedef struct {
char *name;
char *type;
int hp;
int ac;
int speed;
} Creature;
Example Run
1. Search
2. Add Creature
3. Exit
> 1
Enter name: Terrasque
Unable to find "Terrasque"
1. Search
2. Add Creature
3. Exit
> 2
Enter name: Storm Giant
Enter type: Huge giant
Enter HP: 230
Enter AC: 16
Enter speed: 50
Storm Giant added at index 3.
CSV file: Name, hp, ac, speed, type
Rakshasa,110,16,40,Fiend
Priest,27,13,25,Humanoid
Berserker,67,13,30,Humanoid
Fire Elemental,102,13,50,Elemental
Kraken,472,18,20,Monstrosity
Centaur,45,12,50,Monstrosity
Mage,40,12,30,Humanoid
Hell Hound,45,15,50,Fiend
Basilisk,52,15,20,Elemental
Androsphinx,199,17,40,Monstrosity
Efreeti,200,17,40,Elemental
Balor,262,19,40,Fiend
Chain Devil,142,19,40,Fiend
Adult Black Dragon,195,19,80,Dragon
Adult Blue Dragon,225,19,80,Dragon
Adult Red Dragon,256,19,80,Dragon
Please help in C
Answers
Answer:
Explanation:
class TableInput{
Object key;
Object value;
TableInput(Object key, Object value){
this.key = key;
this.value = value;
}
}
abstract class HashTable {
protected TableInput[] tableInput;
protected int size;
HashTable (int size) {
this.size = size;
tableInput = new TableInput[size];
for (int i = 0; i <= size - 1; i++){
tableInput[i] = null;
}
}
abstract int hash(Object key);
public abstract void insert(Object key, Object value);
public abstract Object retrieve(Object key);
}
class ChainedTableInput extends TableInput {
ChainedTableInput(Object key, Object value){
super(key, value);
this.next = null;
}
ChainedTableInput next;
}
class ChainedHashTable extends HashTable {
ChainedHashTable(int size) {
super(size);
// TODO Auto-generated constructor stub
}
public int hash(Object key){
return key.hashCode() % size;
}
public Object retrieve(Object key){
ChainedTableInput p;
p = (ChainedTableInput) tableInput[hash(key)];
while(p != null && !p.key.equals(key)){
p = p.next;
}
if (p != null){
return p.value;
}
else {
return null;
}
}
public void insert(Object key, Object value){
ChainedTableInput entry = new ChainedTableInput(key, value);
int k = hash(key);
ChainedTableInput p = (ChainedTableInput) tableInput[k];
if (p == null){
tableInput[k] = entry;
return;
}
while(!p.key.equals(key) && p.next != null){
p = p.next;
}
if (!p.key.equals(key)){
p.next = entry;
}
}
public double distance(Object key1, Object key2){
final int R = 6373;
Double lat1 = Double.parseDouble(Object);
}
}
com to enjoy dont give fkin lecture hsb-tnug-fyt
Answers
Answer:
This is my faverrrrate part of computer science lol.
Explanation:
HTML tag that makes a text field used by javascript statement
Answers
You own a small hardware store. You have been in business since 1995 and have always been profitable. You’ve never seen a need to do any marketing or advertising since you were able to stay profitable without those things. Plus, you lack any real understanding of how to use technology and it makes you anxious just thinking about technology or social media. However, your son just graduated from college and came home to live with you for the summer before he starts his new marketing manager job at a big firm. He tells you that you are probably losing a big share of the market by avoiding technology and social media. He also says that many of these items can be implemented very easily, and he would volunteer to continue to manage the social media sites in his spare time even after he starts his new job.
Answers
Answer:
Was this a TROLL?
Explanation:
How should you add a appointment to your outlook calendar
Answers
answer:
press on the date thing
In c please
Counting the character occurrences in a file
For this task you are asked to write a program that will open a file called “story.txt
and count the number of occurrences of each letter from the alphabet in this file.
At the end your program will output the following report:
Number of occurrences for the alphabets:
a was used-times.
b was used - times.
c was used - times .... ...and so, on
Assume the file contains only lower-case letters and for simplicity just a single
paragraph. Your program should keep a counter associated with each letter of the
alphabet (26 counters) [Hint: Use array|
| Your program should also print a histogram of characters count by adding
a new function print Histogram (int counters []). This function receives the
counters from the previous task and instead of printing the number of times each
character was used, prints a histogram of the counters. An example histogram for
three letters is shown below) [Hint: Use the extended asci character 254]:
Answers
Answer:
#include <stdio.h>
#include <ctype.h>
void printHistogram(int counters[]) {
int largest = 0;
int row,i;
for (i = 0; i < 26; i++) {
if (counters[i] > largest) {
largest = counters[i];
}
}
for (row = largest; row > 0; row--) {
for (i = 0; i < 26; i++) {
if (counters[i] >= row) {
putchar(254);
}
else {
putchar(32);
}
putchar(32);
}
putchar('\n');
}
for (i = 0; i < 26; i++) {
putchar('a' + i);
putchar(32);
}
}
int main() {
int counters[26] = { 0 };
int i;
char c;
FILE* f;
fopen_s(&f, "story.txt", "r");
while (!feof(f)) {
c = tolower(fgetc(f));
if (c >= 'a' && c <= 'z') {
counters[c-'a']++;
}
}
for (i = 0; i < 26; i++) {
printf("%c was used %d times.\n", 'a'+i, counters[i]);
}
printf("\nHere is a histogram:\n");
printHistogram(counters);
}