In order to get the required expression you take into account that when you eliminate a prenthesis preceded by a minus sign, terms inside the parenthesis change their sign.
Then, for the following expression, you have:
- k - (-6.2m + 1)
- k + 6.2m - 1 that is, signs inside the parenthesis have changed
If y=-4 when x = 10, find y when x = 2.
With the help of the cross-multiplication method, we know that the value y is -4/5 when x is 2.
What do we mean by the cross-multiplication method?In mathematics, more specifically in elementary arithmetic and elementary algebra, one could cross-multiply an equation between two fractions or rational expressions to make the equation easier or to determine the value of a variable.
To cross-multiply two fractions, multiply the numerator of the first fraction by the denominator of the second, and the numerator of the second fraction by the denominator of the first.
So, the value of y when x = 2 is:
We know that when y = -4, then x = 10.
Now, calculate y when x = 2.
y/x = y/x
-4/10 = y/2
10y = -8
y = -8/10
y = -4/5
Therefore, with the help of the cross-multiplication method, we know that the value y is -4/5 when x is 2.
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1. Graph each of the following equations below using a tale of values or by another method. Fill in theInformation for each graph.X-intercept:a) y = x2 + 4x - 5y-intercept:хуVertex:Max/MinAxis of SymmetryDomain:Range:
The equation is
[tex]y=x^2+4x-5[/tex]We can already find the vertex using the vertex formulas
[tex]\begin{gathered} x_V=-\frac{b}{2a}=\frac{-4}{2}=-2 \\ \\ \\ y_V=-\frac{\Delta}{4a}=-\frac{b^2-4ac}{4a}=-\frac{16+20}{4}=-\frac{36}{4}=-9 \end{gathered}[/tex]Therefore the vertex is
[tex](x_V,y_V)=(-2,-9)[/tex]Now we have the vertex we also have the axis of symmetry and the max/min of the function, in that case, it's a minimum because a > 0. Therefore
[tex]\begin{gathered} \text{ axis of symmetry = }x_V=-2 \\ \\ \min\lbrace y\rbrace=y_V=-9 \end{gathered}[/tex]We can find the x-intercept easily
[tex]\begin{gathered} x=\frac{-b\pm\sqrt{b^2-4ac}}{2a} \\ \\ x=\frac{-4\pm\sqrt{4^2+4\cdot5}}{2} \\ \\ x=\frac{-4\pm\sqrt{16+20}}{2} \\ \\ x=\frac{-4\pm\sqrt{36}}{2} \\ \\ x=\frac{-4\pm6}{2} \\ \\ \end{gathered}[/tex]Hence
[tex]\begin{gathered} x=\frac{-4\pm6}{2}=-2\pm3 \\ \\ x_1=-1 \\ x_2=-5 \end{gathered}[/tex]The y-intercept is just the c value, then it's -5.
Now we can do the domain, there's no restriction for parabolas in the domain, then
[tex]\text{ domain = }\mathbb{R}[/tex]And the range is
[tex]\text{ range = \lbrack}y_V,+\infty)=[-9,+\infty)[/tex]I need help with my pre-calc work! The question image is attached.Which of the functions are bounded below? Check the two that apply.g(x) = -4xg(x) = xˆ2g(x) = xˆ3g(x) = | x + 4 | - 1
using a graphing tool
graph the functions
see the attached figure to better understand the problem
Remember that
A function f is bounded below if there is some number b that is less than or equal to every number in the range of f.
therefore
in this problem
g(x)=x^2 and g(x)=x^3 are bounded below
which number is four units away from -1a) -3b) - 4 c) 3d) 4
3 (option c)
Explanation:Four units away from -1 could be towards the negative number line or positive number line
Towards the negative number from -1 = -2, -3, -4, -5
4th number = -5
Towards the positive number from -1 = 0, 1, 2, 3
4th number = 3
From the above, the number that could be found in the option is 3
Hence, four units away from -1 is 3 (option c)
FEΗIdentify the similar triangles.ΔH FEΝΔΔΗFE Δ
According to the given figure, the common parts between triangles are angle G, side GH and angles H and E being equal to 90°.
So, the similar triangles are FHG and HEG because that's the position where the corresponding equivalent parts match.
Additionally, triangle HFE would be similar to triangles FGH and HGE.Need help finding the x-intercepts for equation in picture. I can see them on the graph but I need to work it out by solving.
Answer:
The x-intercepts of the function are;
[tex]\begin{gathered} x=-2 \\ \text{and} \\ x=-4 \end{gathered}[/tex]Explanation:
Given the function;
[tex]f(x)=-2(x+3)^2+2[/tex]We want to derive the x-intercepts of the function.
The x-intercept is at f(x)=0;
[tex]\begin{gathered} f(x)=-2(x+3)^2+2=0 \\ -2(x+3)^2+2=0 \\ -2(x^2+6x+9)^{}+2=0 \\ -2x^2-12x-18^{}+2=0 \\ -2x^2-12x-16=0 \\ -x^2-6x-8=0 \\ x^2+6x+8=0 \end{gathered}[/tex]solving for x;
[tex]\begin{gathered} x^2+6x+8=0 \\ x^2+2x+4x+8=0 \\ (x+2)(x+4)=0 \\ x+2=0 \\ x=-2 \\ \text{and} \\ x+4=0 \\ x=-4 \end{gathered}[/tex]Therefore, the x-intercepts of the function are;
[tex]\begin{gathered} x=-2 \\ \text{and} \\ x=-4 \end{gathered}[/tex]Method 2: quadratic root property;
[tex]\begin{gathered} f(x)=-2(x+3)^2+2=0 \\ -2(x+3)^2+2=0 \\ -2(x+3)^2=-2 \\ \text{divide both sides by -2;} \\ (x+3)^2=1 \\ \text{square root both sides;} \\ \sqrt{(x+3)^2}=\sqrt{1} \\ x+3=\pm1 \\ x=-3\pm1 \\ so\text{ the values of x are;} \\ x=-3+1=-2 \\ \text{and} \\ x=-3-1=-4 \end{gathered}[/tex]Therefore, the x-intercepts are;
[tex]\begin{gathered} x=-2 \\ \text{and } \\ x=-4 \end{gathered}[/tex]Lamar has $80,000 in a savings account. the interest rate is 1% per year and is not compounded. to the nearest cent how much will he have in 3 years?
Simple Interest
The interest rate for Lamar's savings account is 1% per year. This means his money earns 1% at the end of each year.
The formula to calculate the interest is:
I = P.r.t
Where P is the principal or initial saved amount, r is the interest rate, and t is the time.
P = $80,000
r = 1%. This must be converted to decimal
r = 1 / 100 = 0.01
t = 3 years
Calculate the interest:
I = 80,000*0.01*3
I = $2,400
That amount is added to the principal:
A = P + I
A = $80,000 + $2,400
A = $82,400
He will have $82,400 in 3 years
Which of the following statements is NOT true about the data above?
Explanation
A matrix is a rectangular array of numbers arranged into columns and rows
[tex]\begin{bmatrix}{a_{11}} & {a_{21}} & {.} & {a_{1n}} \\ {a_{21}} & {.\text{.}} & {.} & {\square} \\ {a_{31}} & {.\text{.}} & {.\text{.}} & {\square} \\ {a_{41}} & {.\text{.}} & {.\text{.}} & {a_{mn}}\end{bmatrix}[/tex]where m is the number of rows and n is the number of columns
The dimensions of a matrix tells its size: the number of rows and columns of the matrix, in that order.
Step 1
check the dimension of the given functino
rows:5
columns: 4
therefore the matrix is a 5 *4 matrix: true
Step 2
the matrix shows the number of medalls for 5 countries,
we can see that the total for USA is 7, so USA has won the most overall medals in Olumpic soccer :true
Step 3
[tex]C_{3,1}[/tex]
it is
rows:3
column 1
we can see the entry for C(3,1) is
3
hence
C) false
Step 4
[tex]C_{4,1}[/tex]
it is
rows:4
column 1
it indicates Nigeria has won 1 medal in Olympic soccer
threfo
Sketch a line of best fit: The graph shows the depth y in centimeters of water filling a bathtub after x minutes. An equation for this line of best fit could be y = 2.4x-3.2. Use the sketch tool to sketch the line of best fit. A) interpolate: Use the given data to determine how much water is in the tub after 7 min. B) Extrapolate: Use the model (your equation) to predict the amount of water in the tub after 30 min. (Extrapolate means you are outside the known data.) I just want to make sure I created the line of best fit and that my answers to each question are correct.
The given equation of the line that best fits the data is:
[tex]y=\text{2}.4x-3.2[/tex]In order to graph it we can solve the equation for different x-values, and then find the coordinates of the points to draw the line.
For x=2, the y-value is:
[tex]\begin{gathered} y=2.4\cdot2-3.2 \\ y=4.8-3.2 \\ y=1.6 \end{gathered}[/tex]For x=7, the y-value is:
[tex]\begin{gathered} y=2.4\cdot7-3.2 \\ y=16.8-3.2 \\ y=13.6 \end{gathered}[/tex]And for x=12, the y-value is:
[tex]\begin{gathered} y=2.4\cdot12-3.2 \\ y=28.8-3.2 \\ y=25.6 \end{gathered}[/tex]Then, by placing these 3 points in the coordinate plane, we can draw the line, as follows:
The graph with the given points is:
b. Interpolate: the water is in the tube after 7 minutes 13.6 centimeters. We have already made the calculation in part a. When x=7, then y=13.6
c. Extrapolate: the amount of water after 30 minutes will be:
[tex]\begin{gathered} y=2.4\cdot30-3.2 \\ y=68.8 \end{gathered}[/tex]The predicted amount of water after 30 minutes will be 68.8 centimeters.
An expression is shown.2 3/4÷4 1/2What is the value of the expression, in simplest form?
ANSWER
[tex]\frac{11}{18}[/tex]EXPLANATION
Given:
[tex]2\frac{3}{4}\div4\frac{1}{2}[/tex]
I don't understand how to do either elimination or substituion.
We will solve by elimination as follows:
-3x - 8y = 20 [We multiply one of the equations by a number so we obtain an equal value in one of them]
8(-5x + y = 19)
-----------------------
-3x - 8y = 20
-40x + 8y = 152
------------------------- [We now add both expressions and solve for the resulting equation]
-43x = 172 => x = -4
Now that we know the value of one of the variables we replace this in one of the first equations:
=> -3(-4) - 8y = 20 => 12 -8y = 20=>-8y = 8 => y = -1
So, from this, we have that the solution for the system is (-4, -1)
I need help with this. I want to understand 7a first
Answer:
The exact length of segment XY is √4765 and the approximate length is 69.029
Explanation:
The length of a segment that goes from (x1, y1) to (x2, y2) can be calculated as
[tex]\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]So, replacing (x1, y1) by X(-32, 88) and (x2, y2) by Y(11, 34), we get:
[tex]\begin{gathered} \sqrt{(11-(-32))^2+(34-88)^2} \\ \sqrt{(11+32)^2+(-54)^2} \\ \sqrt{43^2+(-54)^2} \\ \sqrt{1849+2916} \\ \sqrt{4765} \\ 69.029 \end{gathered}[/tex]Therefore, the exact length of segment XY is √4765 and the approximate length is 69.029
how do i get 24 using numbers 5,8,0.3,5 once
The given numbers are 5, 8, 0.3, 5. To get 24 from these numbers, we form the following expression
[tex](5+5)\cdot8\cdot0.3[/tex]Let's solve it to see if it gives 24 at the end.
[tex](5+5)\cdot8\cdot0.3=(10)\cdot8\cdot0.3=10\cdot0.24=24[/tex]Therefore, the answer is
[tex](5+5)\cdot8\cdot0.3[/tex]Dante is saving money to buy a game. So far he has saved $20, which is four-fiths of the total cost of the game. How much does the game cosх$?
Money saved = $20
According to the statement we can establish the following equation
[tex]20=\frac{4}{5}X[/tex]where X is the total cost of the game
now let's find X
[tex]\begin{gathered} \frac{4}{5}X=20 \\ 5\cdot\frac{4}{5}X=20\cdot\: 5 \\ 4X=100 \\ \frac{4X}{4}=\frac{100}{4} \\ X=25 \end{gathered}[/tex]Therefore the total cost of the videogame is $25
The scatterplot shows the average number of hours each of 13 people spends at work every week and the average number of hours each of them spends recreational activities every week.Based on the scatterplot,what is the best prediction of the average number of hours a person spends at work every week if that person spends an average of 10 hours on recreational activities every week?A.33 hB.95 hC.50 hD.65 h
We want to find the best prediction of the average number of hours a person spends at work every week if that person spends an average of 10 hours on recreational activities every week.
We will construct a line that adapts to the system by simple linear regression, and then we will find the x-value that makes the line take y=10.
First, we have the data:
We remember that in a simple regression model, we want to write an equation of the form:
[tex]y=\hat{\alpha}+\hat{\beta}x[/tex]where:
[tex]\begin{gathered} \hat{\alpha}=\bar{y}-\hat{\beta}\bar{x} \\ \hat{\beta}=\frac{nS_{xy}-S_xS_y}{nS_{xx}-S^2_x}_{} \end{gathered}[/tex]And the Sx, Sy and Sxx are the sums over all the x-values, the y-values and the multiplication of the x-values and y-values (respectively).
We will find those values:
[tex]\begin{gathered} S_x=\sum ^{13}_{i=1}x_i=370 \\ S_y=\sum ^{13}_{i=1}y_i=336.5 \end{gathered}[/tex]Also, we have:
[tex]\begin{gathered} S_{xx}=\sum ^{13}_{i=1}x^2_i=12600 \\ S_{xy}=\sum ^{13}_{i=1}x_iy_i=8680_{}_{} \end{gathered}[/tex]And applying the formula, having in mind that n=13, we get:
[tex]\begin{gathered} \hat{\beta}=\frac{nS_{xy}-S_xS_y}{nS_{xx}-S^2_x}_{} \\ =\frac{13(8680)-(370)(336.5)}{13(12600)-(370^2)} \\ =\frac{-11665}{26900} \\ \approx-0.4336 \end{gathered}[/tex]And, for alpha:
[tex]\begin{gathered} \hat{\alpha}=\frac{1}{n}S_y-\hat{\beta}\frac{1}{n}S_x \\ =\frac{1}{13}(336.5)-(-0.4336)\frac{1}{13}(370) \\ \approx38.2255 \end{gathered}[/tex]This means that the linear regression equation will be:
[tex]y=38.2255-0.4336x[/tex]For finding the x-value that will have 10 hours of recreational activities, we replace the 10 value on y, and clear out the variable x:
[tex]10=38.2255-0.4336x[/tex]And thus,
[tex]\begin{gathered} 10-38.2255=-0.4336x \\ \frac{-28.2255}{-0.4336}=x \\ 65.09=x \end{gathered}[/tex]This means that when a person works 65 hours approximately, he will have 10 hours of recreational activities every week.
if your able to answer all of them i will be giving you 5 stars
The function given is:
[tex]f(x)=-16x^2+60x+16[/tex]PART AThe factorization steps are shown below:
[tex]\begin{gathered} f(x)=-16x^2+60x+16 \\ f(x)=4(-4x^2+15x+4) \\ f(x)=4(-4x^2+16x-x+4) \\ f(x)=4(-4x(x-4)-1(x-4)) \\ f(x)=4(-4x-1)(x-4) \end{gathered}[/tex]PART BTo find the x intercepts, we set f(x) equal to 0 and solve for x:
[tex]\begin{gathered} f(x)=4(-4x-1)(x-4) \\ f(x)=0 \\ 4(-4x-1)(x-4)=0 \\ -4x-1=0--------(1) \\ OR \\ x-4=0---------(2) \end{gathered}[/tex]Solving (1), we have:
[tex]\begin{gathered} -4x-1=0 \\ 4x=-1 \\ x=-\frac{1}{4} \\ x=-0.25 \end{gathered}[/tex]and, solving (2), we have:
[tex]\begin{gathered} x-4=0 \\ x=4 \end{gathered}[/tex]The x-intercepts are
[tex]\begin{gathered} x=-0.25 \\ x=4 \end{gathered}[/tex]PART CThe standard equation of a quadratic is
[tex]f(x)=ax^2+bx+c[/tex]The parabola opens upward when a is positive and opens downward when a is negative
1. When parabola opens upward, the end behavior can be described as:
[tex]\begin{gathered} x\rightarrow\infty \\ y\rightarrow\infty \\ \text{and} \\ x\rightarrow-\infty \\ y\rightarrow\infty \end{gathered}[/tex]2. When parabola opens downward, the end behavior can be described as:
[tex]\begin{gathered} x\rightarrow\infty \\ y\rightarrow-\infty \\ \text{and} \\ x\rightarrow-\infty \\ y\rightarrow-\infty \end{gathered}[/tex]Our equation has an "a" value that is negative! So, the parabola opens downward and the end behvaior can be described as:
As x goes to infinity (gets infinitely large), y goes to negative infinity (gets infinitely small) and as x goes to negative infinity (gets infinitely small), y goes to negative infinity (get infinitely small).
PART D
In Part B, we found the x-intercepts. Those are the x-axis cutting points. We can draw those first.
Then,
Using the end behavior information that we found in Part C, we can draw the parabola. The rough sketch is shown:
The exact graph is shown below, for reference:
3. Marisol made 12 cups of party mix. She gave 3 cups to her mother and 3 cups to her grandmother. How much party mix did Marisol have left for herself? 3 cups ( 6 7 cups 4 cups 6 cups
We will have the following:
[tex]12-2(3\frac{3}{4})=12-2(\frac{12}{4}+\frac{3}{4})[/tex][tex]=12-2(\frac{15}{4})=\frac{9}{2}[/tex][tex]=4\frac{1}{2}[/tex]So, she will have 4 & 1/2 cups.
Point C is between A and B on AB. Use the given information to write an equation in terms of x. Then solve the equation to find x, AC, BC, and AB.
We have the following:
[tex]\begin{gathered} AB=AC+CB \\ AC=2x+5 \\ AB=27x \\ CB=5x+15 \end{gathered}[/tex]replacing:
[tex]\begin{gathered} 27x=2x+5+5x+15 \\ 27x-2x-5x=20 \\ 20x=20 \\ x=\frac{20}{20} \\ x=1 \end{gathered}[/tex]Therefore:
[tex]\begin{gathered} AC=2\cdot1+5=7 \\ AB=27\cdot1=27 \\ CB=5\cdot1+15=20 \end{gathered}[/tex]x = 1
AC = 7
AB = 27
CB = 20
A rectangular play area has an area of 7,497 square meters. If the width of the rectangle is 49 meters, find the length.
If a rectangular play area has an area of 7,497 square meters. and the width of the rectangle is 49 meters, then the length is 153 meters
A rectangular play area has an area of 7,497 square meters
If the width of the rectangle is 49 meters
Let the length of the rectangular play be l
Area of a rectangle can be given by
area = length x width
7497 = l x 49
l = 7497 / 49
l = 153
Therefore, if a rectangular play area has an area of 7,497 square meters. and the width of the rectangle is 49 meters, then the length is 153 meters
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Michael and Karim are eating buffalo wings at a constant rate. Michael can eat 5.5 wings per minute. Karim's eating information is shown in the table below. Time (minutes) Wings eaten 1 6 2 12 18 3if they both ate 6 min how many wings would each person eat
a) Karim eats faster
b) Number of wings Micheal will eat = 33 wings
Number of wings Karim will eat = 36 wings
Explanation:a) Michael eat 5.5 wings per minute
we need to find the constant rate Karim eats from the table
The constant rate = change in wings eaten/ change in time
The constant rate = (12 - 6)/(2-1) = (18-12)/(3-2)
= 6/1 = 6/1
The constant rate Karim eats = 6 wings per minute
Rate of Mcheal eating = 5.5
Rate of Karim eating = 6
Karim eats faster
Reason: Because Karim consumes more wings than Micheal when they are given same time, he will eat faster.
6 > 5.5
b) If they both ate 6 min:
Number of wings = rate × time
Number of wings Micheal will eat = 5.5 × 6 = 33 wings
Number of wings Karim will eat = 6 × 6 = 36 wings
Factor completely.28 – 7x2Show Calculator
Which car gets better mileage: a car that gets 23 miles per gallon or a car that gets 45 kilometers per gallon?
A car that gets 45 kilometers per gallon has better mileage than a car that gets 23 miles per gallon
What is mileage of a car?
The mileage of a car is the number of miles that it can travel using one gallon or litre of fuel.
The first car that gets a mileage of 23 miles per gallon
The second car gets 45 kilometers per gallon
1 mile = 1.6 km
1 km = 1/1.6 mile
45 km = (1/1.6) 45
45 km = 28.125 miles
28.125 miles > 23 miles
Therefore, a car that gets 45 kilometers per gallon has better milegae than a car that gets 23 miles per gallon
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(08.01 MC)Find the height of a square pyramid that has a volume of 12 cubic feetand a base length of 3 feet. (1 point)
Recall that we can do the following picture
We want to find the height of this pyramid and are told the volume of the pyramid. Recall that the volume of a square pyramid of height h and base length b is given by the formula
[tex]V=\frac{1}{3}b^2\cdot h[/tex]In our case, we have V=12, and b=3. So we have the following equation
[tex]12=\frac{1}{3}\cdot3^2\cdot h=3\cdot h[/tex]So, we should find the value of h from this equation. To do, we simply divide both sides by 3, so we get
[tex]h=\frac{12}{3}=4[/tex]so the height of the pyramid is 4 feet.
Is this correct? If not can you show me how to do it?
D. The rental cost in dollars, for each paddleboard.
Explanation:
You were in the right track with linking 40 to the paddleboards.
But remember that t represent the total cost and not the total number of paddleboards and kayak, and also since p represent the number of paddleboards (while k represent the number of kayak)
To find t, you need to sum the cost of all the kayaks and the sum of all the paddleboards.
=> t = 25k + 40p
with 25k = total cost of all the kayaks
and
with 40p = total cost of all the paddleboards => in others words the total number of paddleboards (p) * the cost of each paddleboards (40)
Susan earns 0.5% interest annually in her savings account. she can model her savings account balance after earning interest for a year as fx=x+0.005x or just fx=1.005x where x is the account balance
The balance of her account after one year, using simple interest, will be of
$30,150.
How to obtain the balance using simple interest?The balance of an account after t years, using simple interest, that is, a single compounding per year, is given by the equation presented as follows:
A(t) = A(0)(1 + rt).
In which the parameters of the equation are explained as follows:
A(0) is the value of the initial deposit.r is the interest rate, as a decimal.Considering that she has $30,000 in her account and the interest rate of 0.5%, the values of the parameters are given as follows:
A(0) = 30000, r = 0.005.
Hence the balance after one year will be of:
B(1) = 30000(1 + 0.005) = $30,150.
Missing InformationThe problem asks for the balance after one year, if she started with $30,000 in her account.
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A map is created on a coordinate plane . Typ's house is located at (7,8) and the library is located at (7,-6) Each unit on the coordinate plane represents 1 block. How many blocks is it from Ty's house to the library? explain
We will have to calculate the distance between the two points ( that is between Ty's house to library
[tex]\text{distance betw}en\text{ two points = }\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}[/tex][tex](x_1,y_1)=(7,8)and(x_2,y_2)=(7,-6)_{}[/tex][tex]\begin{gathered} d=\text{ }\sqrt[]{(7-7)^2+(-6-8)^2}\text{ =}\sqrt{\text{ }0^2+(-14)^2}\text{ =}\sqrt[]{14^2\text{ }} \\ d=\text{ 14} \end{gathered}[/tex]There are 14 blocks between Ty's house to the library
Stuck on this question, any help greatly appreciated.Don't understand the concept of what the question is asking
You have the line segment PQ shown in the exercise. Notice that you must copy the length of that line using the compass. Notice that one of the endpoints of the new line is R.
In order to copy it, you can follow these steps:
1. You need to place the compass on one of the endpoints of the line PQ.
2. Open the compass to the length of the segment PQ (one leg of the compass must be on the endpoint P and the other one on the endpoint Q).
3. Using the amount of opening found in the previous step, place the compass on the point R and make a mark with the other leg of the compass.
Notice that by applying these steps, you get a segment with the same length of PQ.
Therefore, the answer is:
What is the value of cos(150°)?
Given that cos(150°).
[tex]\cos (150^o)=\cos (180^o-30^o)[/tex][tex]\text{Use }\cos (180^o-30^o)=-\cos 30^o[/tex][tex]\cos (150^o)=-\cos (30^o)[/tex][tex]\text{Use }\cos (30^o)=\frac{\sqrt[]{3}}{2}\text{.}[/tex][tex]\cos (150^o)=-\frac{\sqrt[]{3}}{2}[/tex]Hence the required value is
[tex]\cos (150^o)=-\frac{\sqrt[]{3}}{2}[/tex]how do you write out this number in word 506,341,209.54
You write this number in word this way:
Five hundred six million three hundred fourty one thousand two hundred nine point fifty four.
Question 8 of 10The table below shows the number of e-mails received each day by acompany employee for two separate weeks. If the data were represented witha comparative dot plot, which day would have more dots for week 2 than forweek 1?Week 1 Week 2Monday74.Tuesday83Wednesday52Thursday97Friday69
Solution
It's Friday
Because, the number of dots for week 2 is 9, while the number of dots for week 1 is 6.
Hence, the correct option is A.