Write an algebraic expression for each phrase.1.the product of r and seven7x3. two more than the product of y and four2. the sum of 8 and p4. the quotient of k and ten
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2) The symbol used to repesent sum is '+'. Thus, the algebraic expression for the the sum of 8 and p is
8 + p
Related Questions
2(4+-8)⁶+3 evaluate the Expression
Answers
The given expression is
2(4+-8)⁶+3
The first step is to evaluate the bracket.
4 + - 8 = 4 - 8 = - 4
The expression becomes
2(-4)^6 + 3
= 2(4096) + 3
= 8192 + 3
= 8195
Find the value of x.
Answers
Answer
Option A is correct.
x = 5 units
Explanation
We can draw the triangle and divide it into two similar right angle triangles shown below
In a right angle triangle, the side opposite the right angle is the Hypotenuse, the side opposite the given angle that is non-right angle is the Opposite and the remaining side is the Adjacent.
The Pythagorean Theorem is used for right angled triangle, that is, triangles that have one of their angles equal to 90 degrees.
The side of the triangle that is directly opposite the right angle or 90 degrees is called the hypotenuse. It is normally the longest side of the right angle triangle.
The Pythagoras theorem thus states that the sum of the squares of each of the respective other sides of a right angled triangle is equal to the square of the hypotenuse. In mathematical terms, if the two other sides are a and b respectively,
a² + b² = (hyp)²
For each of the triangles,
a = 4
b = 3
hyp = x
a² + b² = (hyp)²
4² + 3² = x²
x² = 16 + 9
x² = 25
x = √25
x = 5 units
Hope this Helps!!!
Question 7Find the slope of the line that goes through the given points.(-1, 7).(-8, 7)1092
Answers
Given:
There are given that the two points;
[tex](-1,7)\text{ and (-8,7)}[/tex]Explanation:
To find the slope of the line from the given point, we need to use the slope formula:
So,
From the formula of the slope:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]Where,
[tex]x_1=-1,y_1=7,x_2=-8,y_2=7_{}[/tex]Then,
Put all the above values into the given formula:;
So,
[tex]\begin{gathered} m=\frac{y_2-y_1}{x_2-x_1} \\ m=\frac{7_{}-7_{}}{-8_{}-(-1)_{}} \end{gathered}[/tex]Then,
[tex]\begin{gathered} m=\frac{7_{}-7_{}}{-8_{}+1_{}} \\ m=\frac{0}{-7} \\ m=0 \end{gathered}[/tex]Final answer:
The slope of the given line is 0.
Hence, the correct option is B (0)
If mQR = 80° and mQS = 150°, what is m
Answers
we have that
m
by exterior angle
so
substitute given values
m
mA swimmer is 1 mile from the closest point on a straight shoreline. She needs to reach her house located 4miles down shore from the closest point. If she swims at 3 mph and runs at 6 mph, how far from her house should she come ashore so as to arrive at her house in the shortest time?
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Let's draw a diagram of this problem.
ABC is the shore.
D to A is 1 miles (given).
A to C is 4 miles (given).
If we let AB = x, then BC would be "4 - x".
Now, using pythgorean theorem, let's find BD:
[tex]\begin{gathered} AB^2+AD^2=BD^2 \\ x^2+1^2=BD^2 \\ BD=\sqrt[]{1+x^2} \end{gathered}[/tex]We know
[tex]D=RT[/tex]Where
D is distance
R is rate
T is time
Swimmer needs to go from D to B at 3 miles per hour. Thus, we can say:
[tex]\begin{gathered} D=RT \\ T=\frac{D}{R} \\ T=\frac{\sqrt[]{1+x^2}}{3} \end{gathered}[/tex]Next part, swimmer needs to go from B to C at 6 miles per hour. Thus, we can say:
[tex]\begin{gathered} D=RT \\ T=\frac{D}{R} \\ T=\frac{4-x}{6} \end{gathered}[/tex]So, total time would be:
[tex]T=\frac{\sqrt[]{1+x^2}}{3}+\frac{4-x}{6}[/tex]We want to find the shortest possible time. From calculus we know that to find the shortest possible time, we need to differentiate the function T, set it equal to 0 to find the critical points and then use that point in the function T to find the shortest possible time.
Let's differentiate the function T:
[tex]\begin{gathered} T=\frac{\sqrt[]{1+x^2}}{3}+\frac{4-x}{6} \\ T=\frac{1}{3}(1+x^2)^{\frac{1}{2}}+\frac{4}{6}-\frac{1}{6}x \\ T=\frac{1}{3}(1+x^2)^{\frac{1}{2}}+\frac{2}{3}-\frac{1}{6}x \\ T^{\prime}=(\frac{1}{2})\frac{1}{3}(1+x^2)^{-\frac{1}{2}}\lbrack\frac{d}{dx}(1+x^2)\rbrack-\frac{1}{6} \\ T^{\prime}=\frac{1}{6}(1+x^2)^{-\frac{1}{2}}(2x)-\frac{1}{6} \\ T^{\prime}=\frac{2x}{6(1+x^2)^{\frac{1}{2}}}-\frac{1}{6} \\ T^{\prime}=\frac{x}{3\sqrt[]{1+x^2}}-\frac{1}{6} \end{gathered}[/tex]Now, we find the critical point:
[tex]\begin{gathered} T^{\prime}=\frac{x}{3\sqrt[]{1+x^2}}-\frac{1}{6} \\ T^{\prime}=0 \\ \frac{x}{3\sqrt[]{1+x^2}}-\frac{1}{6}=0 \\ \frac{x}{3\sqrt[]{1+x^2}}=\frac{1}{6} \\ \text{Cross Multiplying:} \\ 6x=3\sqrt[]{1+x^2} \\ \text{Square both sides:} \\ (6x)^2=(3\sqrt[]{1+x^2})^2 \\ 36x^2=9(1+x^2) \\ 36x^2=9+9x^2 \\ 36x^2-9x^2=9 \\ 27x^2=9 \\ x^2=\frac{9}{27} \\ x=\frac{\sqrt[]{9}}{\sqrt[]{27}} \\ x=\frac{3}{3\sqrt[]{3}} \\ x=\frac{1}{\sqrt[]{3}} \end{gathered}[/tex]Plugging this value into the equation of T, we get:
[tex]\begin{gathered} T=\frac{\sqrt[]{1+x^2}}{3}+\frac{4-x}{6} \\ T=\frac{\sqrt[]{1+(\frac{1}{\sqrt[]{3}})^2}}{3}+\frac{4-\frac{1}{\sqrt[]{3}}}{6} \\ T=\frac{\sqrt[]{1+\frac{1}{3}}}{3}+\frac{4-\frac{1}{\sqrt[]{3}}}{6} \\ T=\frac{\sqrt[]{\frac{4}{3}}}{3}+\frac{4-\frac{1}{\sqrt[]{3}}}{6} \\ T=\frac{\frac{2}{\sqrt[]{3}}}{3}+\frac{4-\frac{1}{\sqrt[]{3}}}{6} \\ T=\frac{2}{3\sqrt[]{3}}+\frac{4-\frac{1}{\sqrt[]{3}}}{6} \end{gathered}[/tex]Now, we can use the calculator to find the approximate value of T to be:
T = 0.9553 hours
This is the optimized time.
Converting to approximate minutes, it will be:
57.32 minutes
Answer:[tex]T=0.9553\text{ hours}[/tex]There are two types of tickets sold at the Canadian Formula One Grand Prix race. The price of 6 grandstand tickets and 4 general admission tickets is $3200. The price of 8 grandstand tickets and 8 general admission tickets is $4880. What is the price of each type of ticket?
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Let:
x = price of the grandstand ticket
y = price of the general admission ticket
The price of 6 grandstand tickets and 4 general admission tickets is $3200, so:
[tex]6x+4y=3200[/tex]The price of 8 grandstand tickets and 8 general admission tickets is $4880, so:
[tex]8x+8y=4880[/tex]Let:
[tex]\begin{gathered} 6x+4y=3200_{\text{ }}(1) \\ 8x+8y=4880_{\text{ }}(2) \end{gathered}[/tex]Using elimination method:
[tex]\begin{gathered} 2(1)-(2)\colon_{} \\ 12x-8x+8y-8y=6400-4880 \\ 4x=1520 \\ x=\frac{1520}{4} \\ x=380 \end{gathered}[/tex]replace the value of x into (1):
[tex]\begin{gathered} 6(380)+4y=3200 \\ 2280+4y=3200 \\ 4y=3200-2280 \\ 4y=920 \\ y=\frac{920}{4} \\ y=230 \end{gathered}[/tex]The price of the grandstand ticket is $380 and the price of the general admission ticket is $230
Can you please check number 4 and check parts a, b, and c to make sure it’s right please
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if the scale in the drawing is 1 centimeter= 20 meters, then:
a) Playground 3 centimeters.
[tex]\begin{gathered} \frac{1cm}{20m}=\text{ }\frac{3cm}{x}= \\ \text{ x\lparen1cm\rparen=\lparen20m\rparen\lparen3cm\rparen} \\ x=\text{ 60 meters} \end{gathered}[/tex]b) Tennis courts= 5.2cm
[tex]\begin{gathered} \frac{1cm}{20m}=\text{ }\frac{5.2cm}{x} \\ x(1cm)=\text{ \lparen5.2cm\rparen\lparen20m\rparen} \\ x=\text{ 104 meters} \end{gathered}[/tex]c) Walking trail= 21.7 cm
[tex]\begin{gathered} \frac{1cm}{20m}=\frac{21.7cm}{x} \\ \\ x(1cm)=(21.7cm)(20m) \\ x=\text{ 434 meters} \end{gathered}[/tex]Write a recursive formula for the sequence: 8, 4, 2, 1,...Tn + 1 = Tn × 12Tn + 1 = Tn × (2)Tn + 1 = Tn - 4(n - 1)Tn + 1 = Tn + 4(n - 1)
Answers
Given:
The sequence is:
8, 4, 2, 1,...
Required:
Find a recursive formula for the given sequence.
Explanation:
The given sequence is:
8, 4, 2, 1,...
The common ratio of the sequence is:
[tex]\begin{gathered} \frac{4}{8}=\frac{1}{2} \\ \frac{2}{4}=\frac{1}{2} \\ \frac{1}{2} \end{gathered}[/tex]Since the common ratio for the given series is 1/2.
[tex]\begin{gathered} \frac{T_{n+1}}{T_n}=\frac{1}{2} \\ T_{n+1}=\frac{1}{2}T_n \end{gathered}[/tex]Final Answer:
The recursive formula for the given sequence is
[tex]T_{n+1}=\frac{1}{2}T_{n}[/tex]Manuel used pattern blocks to build the shapes below. The block marked A is a square, B is a trapezoid, C is a rhombus (aparallelogram with equal sides), and D is a triangle. Find the area of each of Manuel's shapes.
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Solving for area of first figure
Recall the following formula for area of 2D figures
[tex]\begin{gathered} A_{\text{square}}=s^2 \\ A_{\text{trapezoid}}=\frac{a+b}{2}h \end{gathered}[/tex]The first figure consist of 2 figures with a square of side length of 2.5 cm, and a trapezoid with length 2.5 cm for the upper base, 5 cm for the lower base, and 2 cm for the height.
Calculate the area by getting the sum of the areas of the two figures
[tex]\begin{gathered} \text{Square: }s=2.5\text{ cm} \\ \text{Trapezoid: }a=2.5\text{ cm},b=5\text{ cm},h=2\text{ cm} \\ \\ A=s^2+\frac{a+b}{2}h \\ A=(2.5\text{ cm})^2+\frac{2.5\text{ cm}+5\text{ cm}}{2}\cdot2 \\ A=6.25\text{ cm}^2+\frac{7.5\text{ cm}}{\cancel{2}}\cdot\cancel{2}\text{ cm} \\ A=13.75\text{ cm}^2 \end{gathered}[/tex]The area of the first figure therefore is 13.75 square centimeters.
Solving for the area of the second figure
Recall the following areas for 2D figures
[tex]\begin{gathered} A_{\text{triangle}}=\frac{1}{2}bh \\ A_{\text{rhombus}}=bh \end{gathered}[/tex]Using the same procedures as above, we get the following
[tex]\begin{gathered} \text{Triangle: }b=2.5\text{ cm},h=2.2\text{ cm} \\ \text{Rhombus: }b=2.5\text{ cm},h=2\text{ cm} \\ \\ A=\frac{1}{2}(2.5\text{ cm})(2.2\text{ cm})+(2.5\text{ cm})(2\text{ cm}) \\ A=\frac{1}{2}(5.5\text{ cm}^2)+5\text{ cm}^2 \\ A=2.75\text{ cm}^2+5\text{ cm}^2 \\ A=7.75\text{ cm}^2 \end{gathered}[/tex]Therefore, the area of the second figure is 7.75 square centimeters.
How many different combinations of nine different carrots can be chosen from a bag of 20? O 125,970 O 167,960
Answers
We have a bag of 20 carrots, all different, and we have to calculate the possible combinations in groups of 9 carrots.
We can calculate this with the formula for combinations (as the order does not matter):
[tex]_{20}C_9=\binom{20}{9}=\frac{20!}{9!(20-9)!}=\frac{20!}{9!11!}=167960[/tex]Answer: there are 167,960 possible combinatios
Mrs.Gall orders 240 folders and divides them equally among 3 classes. How many folders does each class receive? What basic fact did you use?
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Answer:
80
Step-by-step explanation:
240 folders divided by 3 class
Graph the line parallel to x= -1 that passes through (8,4).could you also draw a picture
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The line x = -1 is a vertical line, since it has a specific x-coordinate and no y-coordinate.
A line parallel to a vertical line is also a vetical line, so our line will have the equation x = b, where we need to find the value of b.
Since our line passes through the point (8, 4), we know that its x-coordinate will be 8, so our line is x = 8.
Drawing the lines (x = -1 in blue and x = 8 in green), we have:
The answer that should be graphed is just the green line.
157 - 95x + 72 + 13x =
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given equation
157-95x+72+13x
First arrange the variables terms together and constant terms together,
157+72-95x+13x
Now simplify constant terms together and variable terms together
229-82x
82x=229
x=229/82
x=2.79
8. An urn contains 3 red, 2 blue, and 5 green marbles. If we pick 4 marbles with replacement and
count the number of red marbles in the 4 picks, the probabilities associated with this experiment are
P(0) = 0.24, P(1) = 0.41, P(2)= 0.265, P(3) = 0.076, and P(4) = 0.009. The probability of less than
2 red marbles is:
a. 0.41.
b. 0.65.
c. 0.915.
d 0.991
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The probability of less than 2 red marbles is B. 0.65.
What is probability?Probability is the likelihood that an event will occur.
In this case, the urn contains 3 red, 2 blue, and 5 green marbles. Also, the probabilities associated with this experiment are give as:
P(0) = 0.24, P(1) = 0.41, P(2)= 0.265, P(3) = 0.076,
Therefore, the probability of less than 2 red marbles will be:
P(0) + P(1)
= 0.24 + 0.41
= 0.65.
Learn more about probability on:
brainly.com/question/24756209
#SPJ1
. A pie company made 57 apple pies and 38 cherry pies each day for 14 days. How many apples pies does the company make in all?
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To determine the total number of apples pies done, multiply the number of apple pies done each day by 14:
[tex]57\cdot14=798[/tex]Hence, the company made a total of 798 apple pies.
Select the appropriate graph for each inequality.1. {x|x<-3}a.<用HHHHH>-10 -1 -8 -7 -6 - 4 -3 -2 -1 01 23 4 5 6 7 8 9 10
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Given the inequality x| x< -3
The graph of the inequality will be as following :
It is reported that approximately 20 squaremiles of dry land and wetland were convertedto water along the Atlantic coast between 1996and 2011. A small unpopulated island in the AtlanticOcean is 2000 ft wide by 9,380 feet long. Atthis rate, how long before the island issubmerged?
Answers
2 months
1) Notice that the sinking rate is 20miles² per 5 years (2011-1996) so:
[tex]\frac{20}{5}=\frac{4m^2}{y}[/tex]So the rate is 4 square miles per year.
2) We need to convert those measures from feet to miles:
[tex]\begin{gathered} 1\text{ mile=5280ft} \\ 2000ft=\frac{2000}{5280}=0.378miles \\ 9380ft=\frac{9380}{5280}=1.7765miles \end{gathered}[/tex]So, now let's find the area multiplying the width by the height:
[tex]\begin{gathered} A=1.7765\cdot0.378 \\ A=0.671517m^2 \end{gathered}[/tex]Now, considering the sinking rate of 4miles²/year we can write the following pair of ratios:
[tex]\begin{gathered} 1year-------4miles^2 \\ x----------0.6715 \\ 4x=0.6715 \\ \frac{4x}{4}=\frac{0.6715}{4} \\ x=0.17 \\ \\ --- \\ 0.17\times12\approx2 \end{gathered}[/tex]Note that we found that approximately 0.17 year is necessary to submerge tat island, converting that to months, we can state that in approximately 2 months
8 divided by 856 long division
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Answer: look at the attachment bellow
is 88∘ more than the smaller angle. Find the measure of the larger angle.
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Let
x -----> large angle
y ----> smaller angle
so
Remember that
If two angles are supplementary, then their sum is equal to 180 degrees
so
x+y=180
y=180-x ------> equation A
and
x=y+88
y=x-88 -----> equation B
equate both equations
180-x=x-88
x+x=180+88
2x=268
x=134 degrees
the answer is 134 degreesfind first four terms of an arithmetic series if last term is 10 times first term and sum to n terms is 121
Answers
Answer: 120
Step-by-step explanation:
S = n/2 (a(1) + a(n)), where n is the number of terms (10), a(1) is the first term (3), and a(n) is the last term (21).
By substitution, we have,
S = 10/2 (3 + 21)
S = 120
What is the best approximation for the area of a semi-circle with a diameter of 11.8 ( Use 3.14 for pie
Answers
Answer:
54.7units^2
Explanation:
Area of a semi-circle = \pid^2/8
d is the diameter of the semi circle
Given d = 11.8
Area = 3.14(11.8)^2/8
Area of the semi circle = 3.14(139.24)/8
Area of the semi circle = 437.2136/8
Area of the semi circle = 54.6517units^2
Hence the best approximation is 54.7units^2
Find the length of an arc of a circle whose central angle is 212º and radius is 5.3 inches.Round your answer to the nearest tenth.
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The formula for the arc length is,
[tex]L=2\pi r\cdot\frac{\theta}{360}[/tex]Substitute the values in the formula to determine the arc length.
[tex]\begin{gathered} L=2\pi\cdot5.3\cdot\frac{212}{360} \\ =19.61 \\ \approx19.6 \end{gathered}[/tex]So answer is 19.6 inches.
Quadrilateral A'B'C'D'is the image of quadrilateral of ABCD under a rotation of about the origin (0,0)a. -90b. -30c. 30d. 90
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In this problem we have a couterclockwise about the origin
sp
Verify
option D
rotation 90 degrees counterclockwise
(x,y) -----> (-y,x)
so
A(-2,3) ------> A'(-3,-2) ------> is not ok
therefore
answer is option CDetermine if the following side lengths could form a triangle. Prove your answer with an inequality 3,3,7
Answers
According to the definition of triangle, the sum of two sides of a triangle must be greater than the third one.
In this case, the sum of 3 and 3 is 6 which is not greater than 7, it means that these length can't form a triangle:
[tex]3+3<7[/tex]That is the inequality that explains why they can form a triangle.
A company purchased 10,000 pairs of men's slacks for $18.86 per pair and marked them up $22.63. What was the selling price of each pair of slacks? Use the formula S=C+M
Answers
Problem:
A company purchased 10,000 pairs of men's slacks for $18.86 per pair and marked them up $22.63. What was the selling price of each pair of slacks? Use the formula S=C+M.
Solution:
Cost = $18.86
Markup = $22.63
Markup = Sell Price - Cost
Sell Price = Cost + Markup
Sell Price = 18.86+ 22.63
Sell Price = $41.49
The selling price of each pair of slacks was $41.49.
what is the anss? btw this is just a practice assignment.
Answers
Anime, this is the solution:
Part A. This exponential is decay because the factor of the exponential is below one, and it decreases every year.
Part B.
5,100 * (0.95)^5 =
5,100 * 0.77378 =
3,946 (rounding to the nearest carbon atom)
Use a 30 - 60 - 90 triangle to find the tangent of 60 Degrees
Answers
Let's put more details in the given figure to better understand the solution:
Let's now determine the Tangent of 60 degrees:
[tex]\text{ Tangent (60}^{\circ})\text{ = }\frac{\text{ Opposite}}{\text{ Adjacent}}[/tex][tex]\text{ = }\frac{\text{ }\sqrt[]{3}}{1}[/tex][tex]\text{ Tangent (60}^{\circ})\text{ = }\sqrt[]{3}[/tex]Therefore, the tangent of 60 degrees is √3.
The answer is Option 1 : √3
(−2) × 36 × (−5) = ______.
Answers
we have 3 terms, two of them are negative
when operating multiplications, minus by plus gives minus and minus byminus gives plus, so the final result will be positive.
[tex]\begin{gathered} (-2)\cdot36\cdot(-5)=\text{?} \\ (-2)\cdot36\cdot(-5)=360 \\ \end{gathered}[/tex]The anwer is 360
Please help me im so stressed rnIS (-2, 6) a solution of -3y + 10= 4x?
Answers
Given the expression:
[tex]-3y+10=4x[/tex]Let's check if (x,y) = (-2,6) is a solution by substituting each value on the equation:
[tex]\begin{gathered} x=-2 \\ y=6 \\ -3y+10=4x \\ \Rightarrow-3(6)+10=4(-2) \\ \Rightarrow-18+10=-8 \\ \Rightarrow-8=-8 \end{gathered}[/tex]since we got on both sides -8, we can see that (-2,6) is a solution of -3y+10=4x
I need to make sure this is correct please graph.
Answers
We have the expression:
[tex]y=\frac{4}{5}x+8[/tex]In order to plot the function we replace two values for x and we will get two values for y [Respectively], that is:
x = 0 => y =(4/5)(0)+8 => y = 8
x = 1 => y = (4/5)(1)+8 => y = 8.8
We then have the two points:
(0, 8)
(1, 8.8)
By looking at the fucntion we can tell is a function that describes a line, now we graph: