The given percentage is 1.75%.
To find the decimal expression of this percentage, we just have to divide it by 100. It's important to know that when we divide a number by 100, we just have to move the decimal point two spots to the left, as follows
[tex]\frac{1.75}{100}=0.0175[/tex]Therefore, as a decimal is 0.0175.
Now, to find the simplified fraction, we divide the number by 10000, as follows
[tex]\frac{175}{10000}[/tex]The reason for dividing by 10000 is that we need to have a whole number in the numerator, so the extra two zeros allow us to get rid of the two of the number. Now, we simplify the fraction dividing each part by 5
[tex]\frac{175\colon5}{10000\colon5}=\frac{35}{2000}=\frac{7}{400}[/tex]Once we get the simplest fraction, we can finish.
Therefore, as a simplified fraction is 7/400.
What is the m stand for in -3 = m-14
Step 1:
Write the equation
- 3 = m - 14
Step 2: Collect similar terms
- 3 = m - 14
m = -3 + 14
m = 11
Final answer
m = 11
. Find the value of each expression. Show your work. (a) 1.42 (b) 300 = 2(0.5 +4.5) ? 3 ) te) -23
For the first expression, we have 1.4², this can be expressed as 1.4×1.4 and then we get:
[tex]1.4^2=1.4\times1.4=1.96[/tex]For the second expression, 300 ÷ 2(0.5 + 4.5)² we must start by solving the sum inside the parenthesis, then we get:
300 ÷ 2(0.5 + 4.5)² = 300 ÷ 2(5)²
Then, solve the exponent on the right of the division symbol:
300 ÷ 2(5)² = 300 ÷ 2×25
Now, solve the multiplication
300 ÷ 2×25 = 300 ÷ 50
Now, we can solve the division
300 ÷ 50 = 6
Then, 300 ÷ 2(0.5 + 4.5)² = 6
For the last expression, we must start with the exponent:
[tex]\begin{gathered} \frac{1}{3}\div2(\frac{1}{2})^3 \\ \frac{1}{3}\div2\times\frac{1}{2^3} \\ \frac{1}{3}\div2\times\frac{1}{8}^{} \end{gathered}[/tex]Now we can solve the multiplication:
[tex]\frac{1}{3}\div2\times\frac{1}{8}^{}=\frac{1}{3}\div\frac{2}{8}^{}[/tex]In order to divide one fraction by another one we just have to keep the first fraction unchanged, change the ÷ for a × and flip the second fraction, like this:
[tex]\frac{1}{3}\div\frac{2}{8}^{}=\frac{1}{3}\times\frac{8}{2}=\frac{1\times8}{3\times2}=\frac{8}{6}=\frac{4}{3}[/tex]Then, the value of the last expression is 4/3
What is the amplitude of the sine funtion y=2 sin(4x)
A. 4
B. 2
C. r/2
D. r/4
Answer:
it´s C
Step-by-step explanation: Just took the test trust
Identify all of the functions below. { ( 5 , 1 ) , ( 2 , 2 ) , ( 6 , 6 ) , ( 3 , 4 ) , ( 1 , 1 ) } x y 7 3 0 5 1 3 5 5 3 0 { ( 5 , 1 ) , ( − 5 , 2 ) , ( 2 , 6 ) , ( 6 , 4 ) , ( − 2 , 1 ) } { ( 5 , 1 ) , ( 2 , 2 ) , ( 2 , 6 ) , ( 2 , 4 ) , ( 1 , 1 ) } { 3 , 5 , 9 , 7 , 7 } x y 2 3 2 5 1 3 8 2 5 0
The relations and tables that represent a function include the following:
A. {(5, 1), (2, 2), (6, 6), (3, 4), (1, 1)}.
B. x 7 3 0 5 1
y 3 5 5 3 0
C. {(5, 1), (−5, 2), (2, 6), (6, 4), (-2, 1)}.
What is a function?In Mathematics, a function can be defined as a mathematical expression which is typically used for defining and representing the relationship that exists between two or more variables such as an ordered pair in tables or relations.
This ultimately implies that, a function is typically used in mathematics for uniquely mapping an input variable (domain) to an output variable (range).
In this context, the given relation {(5, 1), (2, 2), (2, 6), (2, 4), (1, 1)} is not considered as a function because it has the same input variable (domain) that is mapped to different output variable (range) i.e (2, 2) and (2, 6).
Additionally, the given relation {3, 5, 9, 7, 7} would be classified as a set and not a function.
In conclusion, the table shown below does not represent a function because the same input variable (domain) that is mapped to different output variable (range) i.e (2, 3) and (2, 2).
x 2 3 2 5 1
y 3 8 2 5 0
Read more on function here: brainly.com/question/3632175
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can someone please help I've gone through 4 different teachers
a) see graph below
b) The coordinate of F" = (12/13, 0)
c) cos(D") = 12/13
sin(D") = 5/13
tan(D") = 5/12
Explanation:Given:
A triangle on a coordinate with the units on the vertical and horizontal axis unlabeled
To find:
To label the diagram D"E"F" and determine the coordinates of F"
To label the diagram, we will use the previous diagrams and solutions.
From the information given, the new diagram is similar to the triangle DEF
For similar triangles, the ratio of their corresponding sides will be equal. Also, the corresponding angles are also equal
This means D corresponds to D", E corresponds to E" and F corresponds to F"
labeling the diagram:
b) To get the coordinates of F', we will use the similarity theorem about ratio of corresponding sides:
we have the hypotenuse = 1
the adjacent or base = not given
To get the base, we will use cosine ratio (CAH)
cos D" = adj/hyp
let the adjacent = b
cosD" = b/1
From previous solution of cos D and cos D', the result was 12/13
equating the ratio:
[tex]\begin{gathered} cosD^{\prime}^{\prime}\text{ = }\frac{b}{1}\text{ } \\ cos\text{ D = 12/13} \\ cos\text{ D = cos D'' \lparen similarity theorem\rparen} \\ \frac{b}{1}\text{ = }\frac{12}{13} \\ b\text{ = 12/13} \end{gathered}[/tex]This means the x coordiante of E" = 12/13
Next, we will find the opposite
sin D" = opp/hyp
sinD'' = opp/1
sin D = 5/13
sin D = sin D" (similarity theorem)
[tex]\begin{gathered} \frac{5}{13}=\frac{opp}{1}\text{ } \\ opp\text{ = 5/13} \end{gathered}[/tex]The coordinates of D"E"F":
The coordinate of F" = (12/13, 0)
How: This was determined using the similarity theorem. Comparing the ratio of the corresponding sides of triangle DEF with triangle D"E"F".
cos(D") , sin(D") and tan(D") will have same value as cos (D), sin(D) and tan (D) respectively.
This is because they are similar triangles and the corresponding angles in similar triangles are equal
cos(D") = 12/13
sin(D") = 5/13
tan(D") = 5/12
If u= {1,2,3,4,5,6,7,8,9} a = the event of drawing an odd B= the event of drawing prime number Find p( A unión b)
Using venn diagrams:
Therefore, the union will be given by:
[tex]P(A\cup B)=\mleft\lbrace1,2,3,5,7,9\mright\rbrace[/tex]There are 39 fewer 2nd graders than 3rd graders. There are 67 2nd graders. How many 3rd graders are there?
ANSWER
106 3rd graders
EXPLANATION
Let the number of 2nd graders be x.
Let the number of 3rd graders be y.
We have that there are 39 fewer 2nd graders than 3rd graders. This means that:
x = y - 39
There are 67 2nd graders. This means that:
x = 67
This means that:
67 = y - 39
y = 67 + 39
y = 106
Therefore, there are 106 3rd graders.
The cost of a pound of nails increased from $2.40 to $2.53. What is the percent of increase to the nearest whole-number percent?
The formula to find the percent increase of two values is:
[tex]\text{ Percent Increase }=\frac{\text{ New price - Old price}}{\text{ Old price}}\cdot100[/tex]In this case, we have:
[tex]\begin{gathered} \text{ Old price }=\text{ 2.40} \\ \text{ New price }=\text{ 2.53} \end{gathered}[/tex][tex]\begin{gathered} \text{ Percent Increase }=\frac{2.53-2.4}{2.4}\cdot100 \\ \text{ Percent Increase }=\frac{0.13}{2.4}\cdot100 \\ \text{ Percent Increase }\approx0.054\cdot100\Rightarrow\text{ The symbol }\approx\text{ is read 'approximately'} \\ \text{ Percent Increase }\approx5\% \end{gathered}[/tex]Therefore, the percent of increase to the nearest whole-number percent is 5%.
Thompson and Thompson is a steel bolts manufacturing company. Their current steel bolts have a mean diameter of 137 millimeters, and a standard deviation of 8 millimeters.If a random sample of 31 steel bolts is selected, what is the probability that the sample mean would be greater than 133.5 millimeters? Round your answer to four decimal places.
The probability that the sample mean would be greater than 133.5 is 0.9926
Explanation:Given:
Mean = 137
Standard deviation = 8
Sample = 31
To find the probability that the sample mean would be greater than 133.5, we have:
[tex]\begin{gathered} z=\frac{X-\mu}{\frac{\sigma}{\sqrt{n}}} \\ \\ =\frac{133.5-137}{\frac{8}{\sqrt{31}}}=-2.4359 \\ \\ P(X>133.5)=1-P(z<-2.4359) \\ =1-0.0074274 \\ \approx0.9926 \end{gathered}[/tex]Which equation is parallel to the above equation and passes through the point (35, 30)?Group of answer choicesy=5/7x +79y=5/7x +30y= 5/7x +10y= 5/7x + 5
Notice that all the options contain the term
[tex]\frac{5}{7}x[/tex]Setting x=35, we obtain
[tex]\frac{5}{7}(35)=5\cdot5=25[/tex]Finally,
[tex]30=25+5[/tex]Then, the answer is
[tex]\begin{gathered} y=\frac{5}{7}x+5 \\ \text{set x=35} \\ \Rightarrow y=\frac{5}{7}\cdot35+5=25+5=30 \end{gathered}[/tex]Option D is the answer, y=5x/7+5.
Notice that all the options have the same slope as that of the line y=5x/+10
A hot air balloon is sitting on the ground. Hot air was added causing the balloonto ascend at a rate of 4 feet per second for 60 seconds.A. Use integers to write an expression to determine the location of the airballoon relative to its starting location.
Since the rate in which the balloon ascends is constant this means that we can represent its altitude (the location relative to its starting point) as a linear function.
A linear funtion is given by:
[tex]y=mx+b[/tex]where m is the slope or rate of change and b is the y-intecept (the value of y when x=0).
In our case let x be the time it passes since the balloon started ascending and let y be its altitude. With this definition for the variables we conclude that in our case the rate of change is 4 and, since the ballon started on the ground, the valur of b is zero. Therefore the expression we need is:
[tex]y=4x[/tex]Note:
It is important to notice that this expression is only valid for:
[tex]0\leq x\leq60[/tex]This comes from the fact that that the balloon ascends at that rate for 60 seconds and the fact that the time can't be negative.
Answer: The answer to that would be y=4 x 60 or just write it as y= 240
But in expression form it would be 0<_x<_60
Hope this helps.
Find the surface area of the pyramid. Round your answer to the nearest hundredth.
Okay, here we have this:
Considering the provided information, we are going to calculate the surface area of the pyramid, so we obtain the following:
Let's use the following formula to find the surface area:
Surface area=Area of the base+1/2*Perimeter of the base*Slant Height
Replacing:
Surface area=(12.2ft¨* 12.2 ft)+1/2 * (12.2 ft * 4) * 9.5ft
Surface area=148.84 ft² + 1/2 * 48.8 ft * 9.5 ft
Surface area=148.84 ft² + 231.8 ft²
Surface area=380.64 ft²
Finally we obtain that the correct answer is the first option.
what is 12/1020 in algorithm
Answer:
12/1020=
0 R 12
Step-by-step explanation:
f(x) = x +4g(x) = 3x2 – 7Find (f .g)(x).A. (f-9)(x) = 3.73 – 28O B. (f.g)(x) = 3x2 + 12x2 – 7x - 28OC. (f.g)(x) = 3.r3 +28O D. (f.g)(x) = 3.7° + 12.2 - 72 +28
Recall that:
[tex](f\cdot g)(x)=f(x)\cdot g(x)\text{.}[/tex]Substituting f(x)=x+4 and g(x)=3x²-7 we get:
[tex]\begin{gathered} (f\cdot g)(x)=_{}(x+4)(3x^2-7), \\ (f\cdot g)(x)=3x^3-7x+12x^2-28, \\ (f\cdot g)(x)=3x^3+12x^2-7x-28. \end{gathered}[/tex]Answer: Option B.
Given that events A and B are independent with P(A)=0.55 and P(B)=0.72P determine the value of P(A|Brounding to the nearest thousandth
Which best describes one way to show 1/3 shaded.
Draw a circle, cut into 3 equals parts and shade 1 part
The population of a small town in central Florida has shown a linear decline in the years 1985-1997. In 1985 the population was 46000 people. In 1997 it was 38080 people.
Given:
(1985,46000)
(1997,38080)
(a)
General linear equation is:
[tex]y=mx+c[/tex]here y represent the population and x represent time so equation is:
[tex]p=mt+c[/tex][tex]\begin{gathered} \text{slope}=m \\ m=\frac{p_2-p_1_{}}{t_2-t_1} \end{gathered}[/tex][tex]\begin{gathered} (p_1,t_1)=(1985,46000) \\ (p_2,t_2)=(1997,38080) \end{gathered}[/tex]
slope is:
[tex]\begin{gathered} m=\frac{p_2-p_1}{t_2-t_1} \\ m=\frac{38080-46000}{1997-1985} \\ m=\frac{-7920}{12} \\ m=-660 \end{gathered}[/tex]So equation is:
[tex]\begin{gathered} p=mt+c \\ p=-660t+c \end{gathered}[/tex]Point (1985,46000)
[tex]\begin{gathered} p=-660t+c \\ p=46000 \\ t=1985 \\ p=-660t+c \\ 46000=-660(1985)+c \\ c=46000+1310100 \\ c=1356100 \end{gathered}[/tex]So equation is:
[tex]\begin{gathered} p=mt+c \\ p=-660t+1356100 \end{gathered}[/tex](b)
population in 2000.
[tex]t=2000[/tex][tex]\begin{gathered} p=mt+c \\ p=-660t+1356100 \\ t=2000 \\ p=-660(2000)+1356100 \\ p=36100 \end{gathered}[/tex]so population in 2000 is 36100.
you mix 1/2 cup of oats for every 1/4 cup of honey to make 12 cups of granol. How much oats and honey do you use?
Given that you mix 1/2 cup of oats for 1/4 cup of honey to make 12 cups of granol, we can write this as:
[tex]undefined[/tex]what is 80% of 685?
To know the percentage of a quantity, we have to divide the percentage we want to know (in this case 80%), over 100%. Then, that part has to be multiplied by that result as it is the part that corresponds to 80%.
0. Dividing 80% over 100%
[tex]\frac{80}{100}=0.8[/tex]2. Multiplying by the quantity
[tex]0.8\times685=548[/tex]Answer: 548
Find the slope and y-intercept write y-intercept as order pair
The slope and y-intercept of a line.
The equation of a line can be expressed as:
y = mx + b
Where m is the slope and b is the y-intercept. The slope of a line that passes through the points (x1,y1) and (x2,y2) is calculated as:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]The figure shows a horizontal red line. We only need two points (or ordered pairs) to calculate the slope. Let's get them from the graph: (0,-5) and (2,-5).
Calculate the slope:
[tex]m=\frac{-5-(-5)}{2-0}=\frac{-5+5}{2}=0[/tex]The slope is 0.
The y-intercept, as shown in the equation of the line, is the value of y when x=0.
Looking at the graph, we can identify the value of y=-5 when x=0. In fact, y=-5 for any value of x.
Thus, the y-intercept as an ordered pair is (0,-5)
Describe the association represented in the graph.no associationstrong, negativestrong positive D weak, negative.
Given:
the scatter plot is shown in the graph
We will Describe the association represented in the graph.
As shown, when drawing a line of best fit of the points, the line will be with a negative slope that will be a strong negative
So, the answer will be: strong, negative
A company sells a product for $72 each. The variable costs are $15 per unit and fixed costs are $29,697 per month
Step 1
Given;
Step 2
A)
[tex]\begin{gathered} Revenue=\text{ Number of units sold }\times\text{ cost per unit} \\ Let\text{ each quant}\imaginaryI\text{ty of good sold be x} \\ cost\text{ per unit= \$72} \\ TR=72\times x=72x \\ \end{gathered}[/tex][tex]\begin{gathered} B)\text{ }total\text{ cost=f}\imaginaryI\text{xed cost + var}\imaginaryI\text{able cost} \\ TC=29697+15x \end{gathered}[/tex]C)At breakeven, TR = TC
[tex]\begin{gathered} 72n=29697+15x \\ 72x-15x=29697 \\ 57x=29697 \\ x=\frac{29697}{57}=521 \end{gathered}[/tex]the number of units needed to breakeven is 521
D) To calculate the TR, we substitute 521 for n in the given function for TR as seen below:
[tex]\begin{gathered} TR=72x \\ TR=72(521)=\text{ \$}37512 \end{gathered}[/tex]TR = $37512
Answers;
[tex]\begin{gathered} A)\text{ 72x} \\ B)\text{ 29697 +15x} \\ C)\text{ 521 units} \\ D)\text{ \$37512} \end{gathered}[/tex]
A set of data items normally distributed with a mean of 60. Convert the data item to a z-score, if the data item is 47 and standard deviation is 13.
To answer this question, we need to remember what the z-score is. The formula for it is as follows:
[tex]z_{\text{scorre}}=\frac{x-\mu}{\sigma}[/tex]We have that:
• mu is the population mean
,• x is the raw score we want to normalize or convert into a z-score
,• sigma is the population standard deviation.
Then, since we have that the mean is equal to 60, the raw score, x, is equal to 47, and the standard deviation is 13, then, we have that the z-score is:
[tex]z_{\text{score}}=\frac{47-60}{13}=\frac{-13}{13}\Rightarrow z_{score}=-1[/tex]Then, the z-score is equal to -1. That is, x is one standard deviation below the population mean.
Q. A student earned a grade of 80% on a math test that had 30 problems. How manyProblems on this test did the students answer correctly
In order to calculate how many answers the student did correctly, we just need to find 80% of 30, that is, the product of 80% and 30.
Knowing that 80% corresponds to 0.8, we have:
[tex]80\text{\% of }30=0.8\cdot30=24[/tex]So the students answered 24 questions correctly.
which one of the following options is true when considering the expansion of the binomial expression (x+y)^4?A) The sum of the exponents of each term of the expansion of (x+y)^4 is 5.B) The expansion of (x+y)^4 will yield 4 termsC) The last term of the expansion of (x+y)^4 is y^4D) The coefficients of the expansion of (x+y)^4 are: 1,4,4,1.
Given:
[tex](x+y)^4[/tex]To Determine: The binomial expansion of the given
Solution
Using binomial expansion formula below
[tex](x+y)^n=\sum_{k\mathop{=}0}^n(^n_k)x^{n-k}y^k[/tex]12² × 5 + 5 .........
The solution to the given expression will be,
[tex]12^2\times5+5=144\times5+5=720+5=725[/tex]Determine the equation in slope intercept form
I need help with my math
Let's evaluate the point into the equation in order to check if it satisfies it.
[tex]\begin{gathered} y=4x+2;_{\text{ }}(2,10) \\ x=2,y=10 \\ so\colon \\ 10=4(2)+2=8+2=10 \\ 10=10 \\ This_{\text{ }}is_{\text{ }}true \end{gathered}[/tex]Therefore, the ordered pair is a solution to the equation
For / (x) = 4x+1 and g(x)=x2-5, find
We need to find g(x)/f(x) so we will put them over each other as a fraction
[tex]\frac{g(x)}{f(x)}=\frac{x^2-5}{4x+1}\text{ , x}\ne\frac{-1}{4}[/tex]In any algebraic fraction, denominators can not be zero, so we avoid any values make it equal to zero like -1/4 in our question
I need help with a algebra 1 testThe graph of linear f passes through the point (1,-9) and has a slope of -3what is the zero of fanswers are24-6-2
hello
to solve this question, we can simply use the equation of a slope on this
[tex]\begin{gathered} y=mx+c \\ m=\text{slope} \\ y=y-\text{coordinate} \\ x=x-\text{coordinate} \end{gathered}[/tex]now we can simply bring out our data and then proceed to input in and solve for c
[tex]\begin{gathered} y=mx+c \\ y=-9 \\ x=1 \\ m=-3 \\ y=mx+c \\ -9=-3(1)+c \\ -9+3=c \\ c=-6 \end{gathered}[/tex]from the calculations above, the answer to this question is -6 which corresponds to option c.
NB; the point at which is referred as the zero of a graph is known as the intercept. This is the point at which graph crosses the x-axis