Would you be able to assist me in answering these questions ?

Would You Be Able To Assist Me In Answering These Questions ?

Answers

Answer 1

A direct variation is a relationship between 2 variables in which the changes are proportionate. The variables are related by a constant. This is also called a slope. Thus, the graph would always be a straight line. Therefore,

c) Direct variation models are always a type of linear models

a) The straight line always pass through the origin(0, 0)

b) A polynomial is an expression containing variables and coefficients. The variable can be in the form x^n where n can be any positive integer. This means that n can be 1,2,3,4.....If n is 1, the polynomial expression is linear. Thus, it can be a direct variation model. Therefore,

Direct variation models are sometimes a type of polynomial models

d) An exponential model is not linear. The form of a linear model is

y = ax

where a is the constant of pro

An exponential model is y = ab^x

The models are not the same. Thus,

Direct variation models are never a type of exponential model


Related Questions

Only need help with finding the mean and standard deviation.

Answers

Given

Probability distribution table

Find

Mean and standard deviation

Explanation

mean for probability distribution is given by

[tex]mean=\sum_^xP(x)[/tex]

so , mean

[tex]\begin{gathered} 0+0.25+0.54+0.36+0.64 \\ 1.79 \end{gathered}[/tex]

standaed deviation

[tex]\begin{gathered} \sum_^x^2P(x) \\ 0+0.25+1.08+1.08+2.56 \\ 4.97 \end{gathered}[/tex]

Final Answer

mean = 1.79

standard deviation = 4.97

Determine the signs of given trigonometric function of an angle in standard position with given measure.cos (-302°) and sin (-302°)

Answers

Explanation

Exercise: Calculate the sign of cos(-302°) and sin(-302°).

We can know the sign of the trigonometric value of an angle depending on which quadrant the angle is located. In the case of cosine and sine, we have the following rules:

Let's calculate the sign of cos(-302°) first. Note that the angle within the cosine is negative; this means that it must be measured from the x-axis clockwise. Now, every quadrant has a total measure of 90°; then, dividing 302 by 90 we obtain

[tex]\frac{302}{90}\approx3.4,[/tex]

which means that -302° goes through two complete quadrants and a partial part of a third one. Since we must measure the angle clockwise, -302 lies in the first quadrant.

By the diagram above, the sign of -302° is +.

On the other hand, looking at the sine diagram, we see that the sign of sine(-302°) is + as well.

Answer

The signs of cos(-302°) and sin(-302°) are both +.

2. A shop owner raises the price of a $150 pair of shoes by 40%. After a few weeks,because of falling sales, the owner reduces the price of the shoes by 40%. Acustomer then says that the shoes are back at the original price.d. By what percent should the shoes be decreased in order to have the priceback at $150?Kk

Answers

Answer:

Explanations:

Given the following parameters;

Original price of shoe = $150

If the price is increased by 40%, the new price will be expressed as:

[tex]\begin{gathered} New\text{ price}=\$150+(0.40\times\$150) \\ New\text{ price}=\$150+\$60 \\ New\text{ price}=\$210 \end{gathered}[/tex]

If the the owner reduces the price of the shoes by 40% due to falling price, hence;

[tex]\begin{gathered} New\text{ price}=210-(0.4\times210) \\ New\text{ price}=210-84 \\ New\text{ price}=\$126 \end{gathered}[/tex]

Let f(x) = 4x^3-5x^2Then f(x) has a local minimum at x= ____a local maximum at x= ____and inflection point at x= ____ write inflection points (if any) in numerical order smallest first

Answers

Given:

[tex]f\mleft(x\mright)=4x^3-5x^2[/tex]

Find-: Local minimum and local maximum and inflection point.

Sol:

Derivative of function.

[tex]\begin{gathered} f\mleft(x\mright)=4x^3-5x^2 \\ f^{\prime}\left(x\right)=12x^2-10x \\ f^{\prime}\left(x\right)=2x\left(6x-5\right) \end{gathered}[/tex]

The critical point is:

[tex]\begin{gathered} f^{\prime}\left(x\right)=0 \\ 2x\left(6x-5\right)=0 \\ 2x=0;6x-5=0 \\ x=0;x=\frac{5}{6} \end{gathered}[/tex]

Local minima is:

[tex]\left(x,f\lparen x\right))=\lparen\frac{5}{6},-1.157)[/tex]

Local minima at x=5/6

Local maxima at x=0

Inflection point.

[tex]\begin{gathered} f=4x^3-5x^2 \\ \text{ Inflection point} \\ x=\frac{5}{12} \end{gathered}[/tex]

Which of the following is graphed below?

Answers

The function that is graphed here is option A;

y = {x³ - 3, x ≤ 2 and x² + 6, x > 2

Given,

The graph

Function;

A function is a mathematical phrase, rule, or law that establishes the link between an independent variable and a dependent variable (the dependent variable).

We have to find the function that is graphed here from the given options.

Here,

The function that is graphed here is option A;

y = {x³ - 3, x ≤ 2 and x² + 6, x > 2

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Use the table of values for f and g below to find the indicated compositions.f(g(8))=Answerg(f(5))=Answerf(f(4))=Answerg(g(2))=Answer

Answers

Starting from the first question, we want:

[tex]f(g(8))[/tex]

Let's start from the inside part:

[tex]g(8)[/tex]

Since the inside of "g" is 8, this means we need to check for the row with x = 8, thay is, "8" in the column "x". Finding this row, we check the value in this row and column "g", which is "4".

This means that:

[tex]g(8)=4[/tex]

Now, we can substitute this back in:

[tex]f(g(8))=f(4)[/tex]

And we can do similarly. We check the row which has "4" in the "x" column and see the corresponding value in column "f". We can see that it is also "4", so, the answer for the first is:

[tex]f(g(8))=f(4)=4[/tex]

Lastly, for the second, we do the same thing, the inside part is:

[tex]f(5)[/tex]

So, we got to line x = 5 and check column "f". It is 0, so:

[tex]\begin{gathered} f(5)=0 \\ g(f(5))=g(0)_{} \end{gathered}[/tex]

Now, we check row x = 0 and column "g" to find "9", so:

[tex]g(0)=9[/tex]

Thus, the answer for the second is:

[tex]g(f(5))=g(0)=9[/tex]

am I supposed to x all this together I need help with the answer please thank you

Answers

The volume of the tank can be calculated using the Volume of a cylinder formula, which is:

[tex]V=\pi\cdot r^2\cdot h[/tex]

Where:

v = volume;

r = radius;

h = height.

In this exercise:

r = Diameter/2 = 12/2 = 6 ft

h = 16 ft

So, substituting the values:

[tex]\begin{gathered} V=\pi\cdot6^2\cdot16 \\ V=\pi\cdot36\cdot16 \\ V=576\pi \end{gathered}[/tex]

Using π = 3.14:

[tex]\begin{gathered} V=576\cdot3.14 \\ V=1808.64 \\ V=1809ft^3 \end{gathered}[/tex]

Answer:

The volume of the tank is 1809 ft³.

create a linear equation in the slope-intercept form that contains points (2,8) and (6,-4)

Answers

the two points are,

A(2,8)

B (6,-4)

the equation of the line in the slope intercept form is,

[tex]y-8=\frac{-4-8}{6-2}(x-2)[/tex][tex]\begin{gathered} y-8=\frac{-12}{4}(x-2) \\ y-8=-3x+6 \\ y=-3x+14 \end{gathered}[/tex]

thus, the equation of the line is

y = -3x + 14

The table below represents the data collected at a sandwich shop for the last six months withrespect to the type of bread people ordered (sourdough or wheat) and whether or not theygot cheese on their sandwich.With cheeseWithout cheeseSourdough800425Wheat1200700What is the P(cheese | wheat)? Show all work to receive full credit. You can place your workin this box or attach it in the box on the final question.

Answers

Given:

The table represents the data collected at a sandwich shop for the last six months with respect to the type of bread

We will find P(cheese | wheat)

We will use the following formula:

[tex]P(A|B)=\frac{P(A\cap B)}{P(B)}[/tex]

Let A represents cheese, and B represents wheat

From the table:

[tex]\begin{gathered} A\cap B=1200 \\ B=1200+700=1900 \end{gathered}[/tex]

So, the probability will be as follows;

[tex]P\left(cheese|wheat\right)=\frac{1200}{1900}=\frac{12}{19}[/tex]

So, the answer will be:

P(cheese | wheat) = 12/19 = 0.63

Solve this quadratic equation and explains the steps to help you solve it . Also which two specific methods help you to solve it: Is it quadratic formula, Factoring, Square Root Property or Completing square. And explains.

Answers

Recall that the quadratic formula states that, the solutions to the quadratic equation

[tex]ax^2+bx+c=0[/tex]

are

[tex]\frac{-b\pm\sqrt{(-b)^2-4ac}}{2a}.[/tex]

Now, in the given equation, a=-1 ,b=-6, and c= 8. Therefore, the solutions to the equation are:

[tex]x=\frac{6\pm\sqrt{36+32}}{-2}.[/tex]

Simplifying the above result, we get:

[tex]x=-3\pm(-1)\sqrt{17}.[/tex]

Answer:

[tex]\begin{gathered} x_1=-3+\sqrt{17,} \\ x_2=-3-\sqrt{17}. \end{gathered}[/tex]

The ages of grandparents of students in Mr. Keyes' third period class are listed below.52 54 57 61 56 6167 64 63 57 60 50A. Create the five-number summary that represents the data set.B. Create a box plot that represents the data set.

Answers

Given the data set (ages of grandparents):

52, 54, 57, 61, 56, 61, 67, 64, 63, 57, 60, 50

Let's create a five-number summary that represents the given data set and also create a box plot.

A) A five number summary of a data set consists of the following:

• Minimum value

,

• First quartile

,

• Median

,

• Third quartile

,

• Maximum value

Let's determine the five-number summary of the given data set.

• Minimum value:

The minimum value is the smallest number from the given data set.

Thus, the minimum is = 50

• First quartile:

The first quartile is also called the lower quartile. It is the median of the lower half of the data set.

To find the first quartile, list out the lower half of the data set after arranging the data in acsending order.

Arrange in ascending order: 50, 52, 54, 56, 57, 57, 60, 61, 61, 63, 64, 67

Lower half: 50, 52, 54, 56, 57, 57

Median of lower half:

[tex]\frac{54+56}{6}=\frac{110}{2}=55[/tex]

Therefore, the first quartile is = 55

• Median:

Median is the middle term of the data set.

50, 52, 54, 56, 57, 57, 60, 61, 61, 63, 64, 67

The middle terms are = 57 and 60

To find the median, divide the sum of the middle terms by 2.

Thus, we have:

[tex]\frac{57+60}{2}=\frac{117}{2}=58.5[/tex]

Therefore, the median of the data set is 58.5

• Third Quartile:

The third quartile is also called the upper quartile. It is the median of the upper half of the data set.

Upper half of data set = 60, 61, 61, 63, 64, 67

Median of upper half =

[tex]\frac{61+63}{2}=\frac{124}{2}=62[/tex]

Therefore, the third quartile is 62

• Maximum value:

The maximum value is the greatest number in the given data set.

The greatest number in the data set is 67.

Therefore, the maximum value is 67.

We have the five-number summary that represents the data set below:

• Minimum = 50

,

• First quartile = 55

,

• Median = 58.5

,

• Third quartile = 62

,

• Maximum = 67

b) Let's create a box plot that represents the data set.

We have the box plot below:

A Factor with the distributive property Apply the distributive property to factor out the greatest common factor, 56+32 Stuck? Watch a video or use a hint.

Answers

the greatest commmon factor of 56 and 32 is 8

so in order to use the distributive property

8(7+4)=56+32=88

I need help w this question for geometry Find the total area

Answers

Explanation

We are asked to find the total area of the figure

To do so, we will split the area into 2 as shown below

For figure A

We have a trapezoid

The area of a trapezoid is

[tex]\begin{gathered} Area=\frac{1}{2}(a+b)\times height \\ b=13 \\ a=3 \\ height=8 \\ area=\frac{1}{2}(13+3)\times8 \\ area=\frac{26}{2}\times8 \\ area=13\times8 \\ area=104yd^2 \end{gathered}[/tex]

For figure B

The figure is a parallelogram

The area of a parllelogram is given by

[tex]base\times height=13\times(15-8)=13\times7=91yd^2[/tex]

Therefore, the total area is the sum of the areas of the two figures which will be

[tex]104+91=195yd^2[/tex]

Thus, the area is 195 yd²

11. A cylinder and a sphere both have the same radius, 4. The height of the cylinder isequal to the diameter of the sphere. Select the expression that describes thevolume of the cylinder that is not occupied by the sphere. (Use 3.14)A. 39.67B. 85.33T1 - 128TTC. 124.560D. 128TT – 85.33TT

Answers

Given that :

the radius of the cylinder and sphere = 4 units

the height of the cylinder (h) is equal to the diameter (d) of the sphere

the diameter of the sphere = 2 x radius = 2 x 4 = 8 units

also, the height of the cylinder = 8 units

The volume of the cylinder can be calculated using the formula:

[tex]\begin{gathered} V=\pi r^2h \\ V=\pi\times4^2\times8 \\ V=128\pi \end{gathered}[/tex]

The volume of the Cylinder

[tex]\begin{gathered} V=128\times3.14 \\ V=401.92uits^3 \end{gathered}[/tex]

Answer:

Given that :

the radius of the cylinder and sphere = 4 units

the height of the cylinder (h) is equal to the diameter (d) of the sphere

the diameter of the sphere = 2 x radius = 2 x 4 = 8 units

also, the height of the cylinder = 8 units

The volume of the cylinder can be calculated using the formula:

The volume of the Cylinder

Step-by-step explanation:

( 5/13 Marie made a $4,500 down payment on a car. The total cost of the car was $19,000. She made 50 equal monthly payments to pay the car in full. How much did Marie pay per month? Equation: Solution:

Answers

The total cost is $19,000, but Marie already did a payment of $4,500, so the remaining cost is:

[tex]19000-4500=14500[/tex]

Now, this remaining cost was paid in 50 equal monthly payments, so in order to find the value of this monthly payment, we just need to divide the remaining cost by 50:

[tex]\frac{14500}{50}=\frac{1450}{5}=290[/tex]

So Marie paid $290 per month.

I really need help. volume of this figure using 3.14 without rounding.

Answers

We get that the volume of the figure is the volume for the rectangular prism and the cylinder with radius 4

[tex]\begin{gathered} V=16\cdot11\cdot11+3.14\cdot4^2\cdot9 \\ =1936+452.16 \\ =2388.16 \end{gathered}[/tex]

what the closest volume of a cylinder with a height of 10 and a circumference of 8

Answers

In order to calculate the volume of a cylinder, we can use the following formula:

[tex]V=\pi r^2h[/tex]

Where r is the base radius and h is the height.

If the circumference is 8, we have:

[tex]\begin{gathered} C=2\pi r \\ 8=2\pi r \\ r=\frac{4}{\pi} \end{gathered}[/tex]

Now, calculating the volume, we have:

[tex]\begin{gathered} V=\pi(\frac{4}{\pi})^2\cdot10 \\ V=\frac{160}{\pi} \\ V=50.93 \end{gathered}[/tex]

So the correct option is the second one.

cambio siete decimos a una fracción igual Común denominador de 100

Answers

Answer:

70/100

Explicación:

2 fracciones son iguales si una de ellas puede ser calculada multiplicando el numerador y el denominador de la otra por el mismo número.

Por lo tanto, 7/10 es equivalente a:

[tex]\frac{7}{10}=\frac{7\cdot10}{10\cdot10}=\frac{70}{100}[/tex]

Multiplicamos por 10 arriba y abajo para que el denominador fuera 100. De este modo obtemos que 7/10 es igual a 70/100.

Transformation (x + 2, y - 3) is applied to triangle ABC.What are the coordinates of B’ (the transformation of point B)?A) (-5, 3)B) (2, - 1)C) (0, - 2)D) (2, - 3)

Answers

Transformation:

[tex](x+2,y-3)[/tex]

The coordinate of B in (x, y) we can get from the graph, which is (-2, 1):

Thus, the transformation based on the information given is:

[tex](-2+2,1-3)[/tex]

Simplifying:

[tex](0,-2)[/tex]

Answer: C) (0, -2)

PLEASE HELP I’M IN MIDDLE SCHOOL AND I CANT FIND THE ANSWERS. ITS ALSO DUE IN A FEW HOURS.

Answers

To form a triangle the three angles must follow the inequality principle that says: The sum of any two sides must always be greater than the length of the third side. With this in mind let's check the angles.

For the first item we have:

[tex]\begin{gathered} 70+90>20\rightarrow160>20 \\ 70+20>90\rightarrow90>90 \\ 20+90>70\rightarrow110>90 \end{gathered}[/tex]

Since the second inequality is invalid the angles don't form a triangle.

For the second item we have:

[tex]\begin{gathered} 55+45>75\rightarrow100>75 \\ 55+75>45\rightarrow130>45 \\ 45+75>55\rightarrow120>55 \end{gathered}[/tex]

Since all the inequations are valid then the angles form a triangle. Since all the angles are smaller than 90 degrees, then this is an acute triangle.

For the third item we have:

[tex]\begin{gathered} 27+27>126\rightarrow54>126 \\ 27+126>27\rightarrow153>27 \end{gathered}[/tex]

Since the second inequation is invalid, then the angles don't form a triangle.

For the fourth item we have:

[tex]\begin{gathered} 38+87>55\rightarrow125>55 \\ 38+55>87\rightarrow93>87 \\ 55+87>38\rightarrow142>38 \end{gathered}[/tex]

Since all the inequalities are valid, then the angles form a triangle. All of its angles are smaller than 90 degrees, therefore this triangle is an acute triangle.

an elevation on the tenth floor goes down 9 floors then it goes up 19 floors down three and finally down 12 what floor does it end up on write an equation to show how you found your answer

Answers

onIn order to solve this, we have to add the number of floors the elevator goes up and subtract the number of floors the elevator goes down, like this:

Initially, it goes down 9 floors since it was at the 10th floor we get:

10 - 9 = 1

Then, after it goes down 9 floors it gets to the first floor, then it goes up 19 floors , now we get:

1 + 19 = 20

After it goes up to the 19th floor from the fits one, it gets to the 20th floor, then it goes down 3 floors, now we get:

20 - 3 = 17

After it goes down 3 floors it gets to the 17th floor, then it goes 12 floors down from the 17th floor:

17 - 12 = 15

At the end, the elevator ends up in the 15th floor

Simply the expression. (Cos x) (sec x)-(sin^2 x)

Answers

[tex]Cos^{2}x[/tex] is the solution for the expression [tex](Cosx)(secx) - sin^{2}x[/tex]

The given expression is:

[tex](Cosx)(secx) - sin^{2}x[/tex]

Recall form Pythagorean Identity that;

[tex]secx = \frac{1}{cosx}[/tex]

We apply this property to obtain;

[tex](cosx)(\frac{1}{cosx}) - sin^{2}x[/tex]

By simplifying we get that;

[tex]1 - sin^{2}x[/tex]

Recall from the Pythagorean, we identity that;

[tex]1 - sin^{2}x = cos^{2}x[/tex]

Hence the answer is  [tex]cos^{2}x[/tex]  is the solution for the expression [tex](Cosx)(secx) - sin^{2}x[/tex]

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A direct variation includes the points (3, 12) and (n, 8). Find n.

Answers

For a direct variation between each point (x, y),

[tex]\begin{gathered} x\propto y \\ x=ky \\ k=\frac{x}{y} \end{gathered}[/tex]

For (x₁, y₁) = (3, 12),

[tex]\begin{gathered} k=\frac{3}{12} \\ k=0.25 \end{gathered}[/tex]

To find n, consider (n, 8) = (x, y)

[tex]\begin{gathered} x=ky \\ \end{gathered}[/tex]

Substituting,

[tex]\begin{gathered} n=0.25\times8 \\ n=2 \end{gathered}[/tex]

Therefore, the value of n is 2

5. How much must be deposited now at 5% compounded semi-annually to yield an annuity payment of ₱30,000 at the beginning of each 6-month period for 6 years?

Answers

SOLUTION

Given the question in the question tab, the following are the solution steps to calculate the amount to be deposited

STEP 1: Write the formula for Future value annuity

[tex]FV=P\times\frac{(1+r)^n-1}{r}[/tex]

Where:

FV = present value of an ordinary annuity

P=value of each payment

r=interest rate per period

n=number of periods

STEP 2: Write the given parameters

[tex]\begin{gathered} FV=30000,r=5,n=12,r=\frac{5}{100}=0.05,P=? \\ n=12\text{ because }6\text{months period for 6 years will be 2}\times6=12 \end{gathered}[/tex]

STEP 3: Calculate the P

[tex]\begin{gathered} FV=P\times\frac{(1+r)^n-1}{r} \\ 30000=P\times\frac{(1+0.05)^{12}-1}{0.05} \\ 30000=P\times\frac{(1.05)^{12}-1}{0.05} \\ 30000=P\times\frac{(1.05)^{12}-1}{0.05} \\ 30000=P\times\frac{1.795856326^{}-1}{0.05} \\ 30000=P\times\frac{0.795856326^{}}{0.05} \\ 30000=\frac{0.795856326P^{}}{0.05} \\ By\text{ cross multiplication,} \\ 30000\times0.05=0.795856326P \\ 1500=0.795856326P \\ \frac{0.795856326P}{0.795856326}=\frac{1500}{0.795856326} \\ P=1884.762301 \\ P\approx1884.76 \end{gathered}[/tex]

Hence, the amount that must be deposited now is approximately 1884.76 to the nearest cents

The 32 students in Mrs. Colby's class will share 80 slices of pizza equally. How many slices will each student get? Enter the correct answer to complete the statement. The students will each get slices. Explain how to get the fraction after you find the remainder. The slices leftover can each be cut in ? giving everyone another? v of a slice.

Answers

The 32 students in Mrs. Colby's class will share 80 slices of pizza equally. How many slices will each student get? Enter the correct answer to complete the statement. The students will each get slices. Explain how to get the fraction after you find the remainder. The slices leftover can each be cut in ? giving everyone another? v of a slice.​

step 1

Divide 80 by 32

80/32=40/16=20/8=10/4=5/2=2.5=2 1/2

each student get 2 1/2 slices

2 1/2=2+0.5=2+1/2

the fraction is 5/2

so

5/2=4/2+1/2=2+1/2=2 1/2

we have 32 students by 2 1/2

so

32 students by 2

32*2=64 slices

the remainder is

80-64=16 slices

divide 16 by 32

16/32=1/2

therefore

2+1/2=2 1/2

the answers part 2 are

The 16 slices leftover can each be cut in 2 half........giving everyone another (1/2) of a slice

Please help with this question: I have attached the image A survey was done where males and females were asked if they would prefer to eat chicken or steak. The results of the survey are shown in the two-way frequency table. ChickenSteakMale0.2380.216Female0.3110.235What percent of the males surveyed prefer chicken?Enter your answer to the nearest tenth of a percent in the box. __%

Answers

23.8%

Explanation:

Since 0.238 represent the frequency of male who eats chicken

0.238 / 100 = 23.8%

Answer: 52.4%

Step-by-step explanation: I took the test and that was the correct answer.

Describe the transformations: F(x) = - 3(x +1)^2 + 5 What is the Parent Function: Opens UP or DOWN:Stretch or Shrink: Vertical Movement Up or Down, how many units:Horizontal Movement Left or Right, how many units:

Answers

You have the following transformation:

[tex]F(x)=-3(x+1)^2+5[/tex]

The previous function if a parabola. the Parent Function of any parabola is:

[tex]y=x^2[/tex]

All others parabolas can be obtained by applying transformation to the Parent Function.

If you expand the parenthesis of F(x), you obtain:

[tex]\begin{gathered} F(x)=-3(x^2+2x+1)+5=-3x^2-6x-3+5 \\ F(x)=-3x^2-6x+2 \end{gathered}[/tex]

The dominant term, that is, the term with the variable x powered to 2, has a negative coefficient, it demands that the parabola open DOWN.

The coefficient of the dominant term is -3, then I-3I = 3 > 1. It means that the function stretches away from the x-axis.

The function streches way from x-axis by a factor of 3 units.

Vertical movement Up with 5 units. This is becasue the constant of the function, 5, which means the vertical translation of the Pater Function, if the constant is positive the translation is upward, if the translation is negative, it is downward.

Horizontal translation Left with 1 untit. The horizontal trasnlation is given by the constant term inside the quadratic parenthesis, in this case is + 1, whichi represents a translation of the graph to the left.

is a projectile is launched from a height of 5 m with an intial velocity of 25 meters per second, how many seconds will it take the projectile to hit the ground

Answers

In this problem we know that the initial velocity in the horizontal axis is 25, however the initial velocity in the y axis will be o so we can use this equation:

[tex]y=y_0+v_it+\frac{1}{2}at^2[/tex]

So to find the time the object get the grownd we can replace the initial high for 5 miter, the final one for 0 and the aceleration by -9.8 (gravity) so:

[tex]0=5+0(t)+\frac{1}{2}(-9.8)t^2[/tex]

and we solve for t so:

[tex]\begin{gathered} 9.8t^2=5\cdot2 \\ t^2=\frac{10}{9.8} \\ t\approx\sqrt[]{1} \\ t\approx1 \end{gathered}[/tex]

So the projectil takes one secon to hit the grownd

In an electrical circuit with resistors placed in parallel, thereciprocal of the total resistance is equal to the sum of thereciprocals of each resistance:

Answers

Answer:

C

[tex]R_2=16.16\Omega[/tex]

Explanation:

Given the below equation;

[tex]\frac{1}{R_c}=\frac{1}{R_1}+\frac{1}{R_2}[/tex]

We're also given;

[tex]\begin{gathered} R_1=25\Omega \\ R_c=10\Omega \end{gathered}[/tex]

Let's substitute the given values into the equation, we'll have;

[tex]\frac{1}{10}=\frac{1}{25}+\frac{1}{R_2}[/tex]

Let's subtract 1/25 from both sides of the equation;

[tex]\begin{gathered} \frac{1}{10}-\frac{1}{25}=\frac{1}{R_2} \\ \frac{5-2}{50}=\frac{1}{R_2} \\ \frac{3}{50}=\frac{1}{R_2} \end{gathered}[/tex]

Let's cross multiply;

[tex]\begin{gathered} 3R_2=50 \\ R_2=\frac{50}{3} \\ R_2=16.16\Omega \end{gathered}[/tex]

Kaira's gross pay is $6,820. Her deductions total $917.27. What percent of her grosspay is take-home pay?Round to the nearest whole percent.

Answers

Answer:

87%

Explanation:

• Kaira's gross pay = $6,820

,

• Deductions = $917.27

First, determine her take-home pay.

[tex]\begin{gathered} \text{Take}-\text{home Pay}=\text{Gross Pay-Deductions} \\ =6,820-917.27 \\ =\$5902.73 \end{gathered}[/tex]

Next, determine what percent of her gross pay is her take-home pay.

[tex]\begin{gathered} \text{Percent}=\frac{\text{Take}-\text{Home Pay}}{\text{Gross Pay}}\times100 \\ =\frac{5902.73}{6820}\times100 \\ =86.55\% \\ \approx87\% \end{gathered}[/tex]

87% of her gross pay is her take-home pay.

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