Answer:
2
Explanation:
Because 2 waves 4 secs means 1 in 2s
The period of these waves is 2s. and The right option is A)2s.
The period of a wave is the time taken by a wave to complete one cycle.
The formula of period from the question is given below.
⇒ Formula:
T = t/2.................... Equation 1⇒ Where:
T = Period of the wavet = time taken for two complete oscillationFrom the question,
⇒ Given:
t = 4 seconds.⇒ Substitute these value above into equation 1
T = 4/2T = 2 seconds.Hence, The period of these waves is 2s.
The right option is A)2s
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Two automobiles, each of mass 1000 kg, are moving at the same speed, 20 m/s, when they collide and stick together. In what direction and at what speed does the wreckage move (a) if one car was driving north and one south (b) if one car was driving north and one east?
A. The wreckage after collision is moving at the speed 18 m/s to the south.
B. The wreckage after collision is moving at the speed 9.0 m/s to the north.
C. The wreckage after collision is moving at the speed 9.0 m/s to the south.
D. The wreckage after collision is moving at the speed 18 m/s to the north.
E. The wreckage after collision is motionless.
Answer:
The reckage after collision is motionless (E)
Explanation:
The first law of thermodynamics states that energy is neither created nor destroyed but is converted from one form to another.
The kind of collision described in the question above is known as a perfectly inelastic collision, and in this type of collision, the maximum kinetic energy is lost because the objects moving in opposite directions have a resultant momentum that is equal, but in opposite directions hence they cancel each other out.
The calculation is as follows:
m₁v₁ + m₂v₂
where:
m₁ = m₂ = 1000kg
v₁ = 20 m/s
v₂ = -20 m/s ( in the opposite vector direction)
∴ resultant momentum = (1000 × 20) + (1000 × -20)
= 20000 - 20000 = 0
∴ The reckage after collision is motionless
Answer:
The wreckage after collision is moving at the speed 18 m/s to the south.
Explanation:
a.
2. The following examples are good conductors except:
a. Silver
b. Metal
Plastic
d. Copper
Answer:
plastic
Explanation:
what factors affect potential energy
Why are dominant alleles always shown as capital letters?
Answer:
When writing a genotype, the dominant allele is usually represented by a capital letter, while the recessive allele has a lowercase letter.
Explanation:
Please mark me brainlest.
Answer:
Because in a punnett square, dominant alleles need to be differentiated from the recessive alleles, to do this, we write the dominant alleles as capital letters.
Explanation:
Why does a person feel cooler under a rotating fan?
What a fan does is create a wind chill effect. ... By blowing air around, the fan makes it easier for the air to evaporate sweat from your skin, which is how you eliminate body heat. The more evaporation, the cooler you feel.
A transverse wave is represented below. 1.5 m 0.20 m What is the approximate amplitude and wavelength of the wave? amplitude = 0.20 m, wavelength = 0.60 m B. amplitude = 0.20 m, wavelength = 0.30 m C. amplitude = 0.10 m, wavelength = 0.60 m OO amplitude = 0.10 m, wavelength = 0.30 m
Answer:
C. amplitude = 0.10 m, wavelength = 0.60 m
Explanation:
The diagram shows an oscillating progressive wave, with its amplitude and wavelength.
Amplitude of a wave is the maximum distance covered either upward or downward.
So that,
amplitude of the wave, A = [tex]\frac{0.2}{2}[/tex]
= 0.1
Amplitude of the wave = 0.1 m
Wavelength in this case is the distance from crest to crest, or trough to trough of the wave.
So that,
wavelength = [tex]\frac{1.5}{2.5}[/tex]
= 0.6
wavelength of the wave = 0.6 m
Therefore, the amplitude of the wave is 0.10 m, while the wavelength is 0.60 m.
What is the terminal velocity of blood? A. 8.9 feet/seconds B. 9.8 feet/seconds C. 25.1 feet/second D. 52.1 feet/seconds
Answer:
the answer is c) 25.1 feet/second
Explanation:
because the blood droplets can not increase speed past terminal velocity 100.
The terminal velocity of blood is 25.1 ft/s in air. So, option C is correct.
What is meant by terminal velocity ?Terminal velocity is defined as the maximum velocity to which a freely falling drop can accelerate.
Here,
When a drop of blood is observed, it can be found that due to the effect of gravity, the velocity of the freely falling blood drop increases. So, it moves with increasing velocity, which is due to the influence of acceleration due to gravity. During the free fall of blood drop, there are resistive forces in air that opposes the motion or tries to reduce the velocity of the blood drop. The friction in air affects the freely falling blood drop and the blood drop tends to reduce its velocity and reaches a maximum of velocity after which it cannot accelerate, which is due to the frictional force in air. This maximum velocity is called terminal velocity. The terminal velocity of blood is 25.1 feet/second.
Hence,
The terminal velocity of blood is 25.1 ft/s in air.
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You wish to make a simple amusement park ride in which a steel-wheeled roller-coaster car travels down one long slope, where rolling friction is negligible, and later slows to a stop through kinetic friction between the roller coaster's locked wheels sliding along a horizontal plastic (polystyrene) track. Assume the roller-coaster car (filled with passengers) has a mass of 743.0 kg and starts 83.4 m above the ground. (a) Calculate how fast the car is going when it reaches the bottom of the hill. m/s (b) How much does the thermal energy of the system change during the stopping motion of the car
Answer:
(a) The car is going approximately 40.43 m/s at the bottom of the hill
(b) The thermal energy will increase by 607,268.76 J
Explanation:
In the question, we have;
The height of the roller coaster above ground = 83.4 m
The mass of the roller coaster, m = 743.0 kg
(a) By the conservation of energy principle, we have;
The potential energy at the top of the hill, P.E., is equal to the kinetic energy at the bottom of the hill, K.E.
∴ P.E. = K.E.
P.E. = m·g·h
Where;
m = The mass of the roller coaster = 743.0 kg
g = The acceleration due to gravity = 9.8 m/s²
h = The height of the roller coaster = 83.4 m
Therefore, we have;
P.E. = 743.0 kg × 9.8 m/s² × 83.4 m = 607,268.76 J
P.E. = 607,268.76 J
K.E. = 1/2·m·v²
∴ K.E. = 1/2 × 743.0 kg × v²
P.E. = K.E.
∴ P.E. = K.E. = 607,268.76 J
1/2 × 743.0 kg × v² = 607,268.76 J
v² = 607,268.76 J/(1/2 × 743.0 kg) = 1,634.64 m²/s²
v = √(1,634.64 m²/s²) ≈ 40.43 m/s
(b) Given that the material wheel moves along polystyrene track, the sound released will be minimal and almost all the kinetic energy will be converted to heat energy when the train stops, therefore, the thermal energy will increase by K.E. = 607,268.76 J
The thermal energy change of the system is 624,492 J.
We know that in the roller coaster, there is an energy transformation from gravitational potential energy to kinetic energy. As such we can write;
mgh = 1/2mv^2
Where we cancel out the mass from both sides, we are left with;
gh=0.5v^2
v= √gh/0.5
v = √10 × 83.4 m/0.5
v = 41 ms-1
Now the kinetic energy is converted also into heat energy hence;
Thermal energy change of the system = 1/2 mv^2 = 0.5 × 743.0 kg × ( 41 ms-1)^2 = 624,492 J
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A storage tank has the shape of an inverted circular cone with height 15 m and base radius of 5 m. It is filled with water to a height of 11 m. Find the work required to empty the tank by pumping all of the water to the top of the tank. (The density of water is 1000 kg/m3. Assume g = 9.8 m/s2 is the acceleration due to gravity. Round your answer to the nearest integer.) g
Answer:
THE CORRECT ANSWER FOR THIS KS
Explanation:
STOP USING THIS APP FOR ANSWERS U KNOW NOTHING
14
How many
electrons
are in the
atom
pictured?
9 p*
10 nº
Answer:
9 electrons
Explanation:
The structure has 9 protons and hence the number of electrons equals the number of protons that's why it is said to be electrical neutral
How effective are child care programs for children compared to at-home care ?
Answer:
in my opinion i would say that at home cares of more effective because half of the time your child is safe and sound but in child care programs sometimes you have no idea what is going on when you are not around
Explanation:
During a blood transfusion, gravity is used to provide the pressure to overcome the blood pressure and force the flow through a small needle into a vein. Consider a case where the needle is 3.0 cm long and has an internal diameter of 0.75 mm. If the required rate of flow is 0.03 cm3/s and the blood pressure in the vein is 11.00 kPa higher than atmospheric pressure (Pa), how high should the bottle be placed above the needle
Density of blood = 1.06x10³
Viscosity = 4 mpas
Answer:
It should be 1.10 higher
Explanation:
L = 0.93
D = 0.75
R = 0.75/2 = 0.375
Q = 0.03x10^-3
Blood pressure = 11x10³
Pn = 4x10^-3
n = 4 x 10^-3
Density of blood = 1.06x10³
Pn - Pv = 8*Q*n*L/pi*r⁴
Pn - pv = 463.57pa
Pn - pv = 463.57pa
Make pn subject
Pn = Pv + 463.57pa ----1
Vn = Q/An
= 0.0679m/s
To get height above needle
Pn + 1/2pv²n = Pa + pgh ----2
We equate 1 and 2 together
We get
Pgh = 11466
To get h we divide through by pg
h = 11466/pg
h = 11466/(1.06x10³)x9.81
h = 1.1026
Approximately
Height = 1.1 meters
So it should be 1.10 meters higher
the full calculations are in the attachment.
thank you!
NEED HELP ASAP TEST IS DUE TMR
What is the angular displacement of a wheel with a 3mm radius and an angular speed of 6 rad/s over a time period of 2.5 seconds?
Answer:
The answer should be uranus
Explanation:
Which of these statements is true about the effect of a force exerted upon an object?
A. A large force always produces a large change in the object’s momentum.
B. A small force always produces a large change in the object’s momentum.
C. A small force applied over a long time interval can produce a large change in the object’s momentum.
D. A large force produces a large change in the object’s momentum only if the force is applied over a very short time interval.
Answer:
D. A large force produces a large change in the object’s momentum only if the force is applied over a very short time interval.
Explanation:
Momentum can be defined as the multiplication (product) of the mass possessed by an object and its velocity. Momentum is considered to be a vector quantity because it has both magnitude and direction.
Mathematically, momentum is given by the formula;
[tex] Momentum = mass * velocity [/tex]
Also, the impulse of an object is given by the formula;
[tex] Impulse = force * time [/tex]
In accordance with the impulse-momentum theorem, the statement which is true about the effect of a force exerted upon an object is that a large force produces a large change in the object’s momentum only if the force is applied over a very short time interval.
Please help me with this 29 points
Answer:
)Give the definition of poverty line as defined by the World Bank.
6xy from -12xy
please give me a answer this question
6 floors down from 12 floors underground = 18 floors underground.
6 degrees colder than 12 degrees below zero = 18 degrees below zero
6 brown cows taken away from -12 brown cows = -18 brown cows
6 cars sold from a dealer that 12 cars were stolen from = 18 cars gone
6xy taken away from -12xy = -18xy
A long, straight, current-carrying wire runs from north to south.
a. A compass needle placed above the wire points with its north pole toward the east. In What direction is the current flowing
b. If a compass is put underneath the wire, in which direction will the compass needle point?
Answer:
a. The current is flowing from South to North. So, the current flows in the North direction
b. West
Explanation:
a. A compass needle placed above the wire points with its north pole toward the east. In What direction is the current flowing?
Using Maxwell's corkscrew rule, with the thumb of the right hand pointing in the direction of the current and the closed fingers pointing in the direction of the magnetic field.
Since the compass is placed above the wire and points east, the direction of the magnetic field at that point is east.
Since the magnetic field is tangential to the circular path around the wire, to produce an eastward magnetic field above the wire, the current must go from South to North. So, the current flows in the North direction.
b. If a compass is put underneath the wire, in which direction will the compass needle point?
If the compass is put underneath the wire, using Maxwell's corkscrew rule, since the current points northward, and the magnetic field is tangential to the circular path around the wire, the magnetic field below the wire points west.
So, the direction of the compass needle when the compass is put beneath the wire is west.
Select True or False for the following statements about electromagnetic waves. A vertical automobile antenna is sensitive to electric fields polarized horizontally. Ultraviolet radiation causes common sunburn. Radio waves travel in vacuum at a lower speed than the visible light. The sun's radiation is most intense in the visible region. Gamma rays can be produced in transitions of an atomic nucleus from one state to another. Radio waves have wavelengths longer than 1 m. X-rays travel in vacuum at a higher speed than the visible light.
Answer:
a) False, b) True, c) true, d) true, e) True, g) False
Explanation:
Se pide que analicemos cada expresión, f) true
a) False. La antena vertical tiene cargas eléctricas que se pueden mover en la direccion vertical, una onda electromagnética polarizada horizontal el campo eléctrico esta en la dirección horizontal por lo cual no puede mover los electrones que están en direccional vertical
be) True. La radiación ultravioleta es absorvidad por la melanina del la piel y crea las quemaduras comunes de insolación.
C) False. Todas la ondas electromagnetismo viajan en la misma velocidad c
d) True. La Temperatura del sol es 5800K por lo cual la radiación mas intensa esta en el rango visible
e) True. Los rayos gamma son de muy alta energía, por lo cual se producen en ransicio0n de los núcleos atmicos.
f) True. El rango de frecuencia para las onda de radio va desde 500 Kahoy hasta 110 MHz, por lo tanto el rango de longitudes de onda es
c= lam f
lam = c/f
lam = 3 108/500 103
lam = 6 102 m
lam = 3 108 / 110 106
lam = 2,72 m
los lo ttnato en todo el rango de las frecuecias de radio la lambda> 1 m
g) False. Todas las ondas electromagnéticas viajan a la misma velocidad c( 3 108m/s)
A custodian pulls a vacuum 13.5 m
with a 33.9 N force at a 55.0°
angle, against a 14.2 N friction
force. Find the total work done on
the vacuum.
(Unit = J)
Answer:
Horizontal component of pull = (cos 55 x 33.9) = 19.4N.
Net horizontal force = (19.4 - 14.2) = 5.2N.
Work = (fd) = (5.2 x 13.5) = 70.2 Joules.
Rounded to 1 decimal place throughout.
Explanation:
The total work done on the vacuum is 70.2 J.
What is work done?
Work done is equal to product of force applied and distance moved.
Work = Force x Distance
Given is a custodian pulls a vacuum 13.5 m with a 33.9 N force at a 55.0° angle, against a 14.2 N friction force.
Horizontal component of pull = (cos 55 x 33.9) = 19.4N.
Net horizontal force = (19.4 - 14.2) = 5.2N.
Work done by vacuum will be
Work =5.2 x 13.5
Work =70.2 J
Thus, the total work done on the vacuum is 70.2 J.
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A woman stands still holding a 350 Newton bag (about 80 pounds) 2 meters off the ground. How much work does the woman do?
Answer:
700 Joules
Explanation:
What we know:
Force = 350 Newton
Distance = 2 meters
Work = ?
The formula for work is:
Work = force x distance
Plugging values into equation:
Work = 350 Newtons x 2 meters
Work = 700 Joules
I had the same question on the homework assignment with the answers provided:
a) It depends on how long she holds the bag
b) 350 Joules
c) none
d) 350 Newtons
The final answer would be c) none. The work done is 700 Joules. Hope this helps!
PLEASE CLICK ON THIS IMAGE I NEED HELP
Answer:
Second option
Explanation:
"Uniform" pretty much means the same thing happens.
You are driving your car on a very cold late Fall day. You clear a turn and see a couple of pedestrians standing at the cross walk. They are eager to cross the road and to get into the warmth of their apartment as soon as possible. You have two options: continue driving your car as you were without lowering your speed and drive right by the pedestrians OR slow down, stop right at the crosswalk, and yield to the pedestrians. Although by Virginia law the choice is clear, what about Physics laws? Which scenario (passing by or slowing down and stopping at the crosswalk to yield) will minimize the time the pedestrians are out in the cold freezing before they can cross the road?
Make the following assumptions in your argument. Before you noticed the pedestrians, you are moving with a constant velocity v=22 miles/hour. The distance at which you noticed the pedestrians is D=23 meters. Write down a symbolic expression for the amount of time, tpass , the pedestrians will have to wait till they cross the road if you simply drive by without slowing down or speeding up.
Write down a symbolic expression for the amount of time, tstop, the pedestrians will have to wait till they cross the road if you slow down, come to a complete stop at the crosswalk and yield to the pedestrians.
Answer:
t_pass = 2.34 m
t_stop = 4.68 s
Thus, for the car passing at constant speed the pedestrian will have to wait less.
Explanation:
If the car is moving with constant speed, then the time taken by it will be given as:
[tex]t_{pass} = \frac{D}{v}[/tex]
where,
t_pass = time taken = ?
D = Distance covered = 23 m
v = constant speed = (22 mi/h)(1609.34 m/1 mi)(1 h/3600 s) = 9.84 m/s
Therefore,
[tex]t_{pass} = \frac{23\ m}{9.84\ m/s} \\[/tex]
t_pass = 2.34 m
Now, for the time to stop the car, we will use third equation of motion to get the acceleration first:
[tex]2as = v_{f}^{2} - v_{i}^2\\a = \frac{v_{f}^{2} - v_{i}^2}{2D}\\\\a = \frac{(0\ m/s)^{2}-(9.84\ m/s)^2}{(2)(23\ m)}\\\\a = -2.1\ m/s^2[/tex]
Now, for the passing time we use first equation of motion:
[tex]v_{f} = v_{i} + at_{stop}\\t_{stop} = \frac{v_{f}-v_{i}}{a}\\\\t_{stop} = \frac{0\ m/s - 9.84\ m/s}{-2.1\ m/s^2}[/tex]
t_stop = 4.68 s
Constant velocity is the velocity which covers the same distance for each interval of the time.
The time required to pass is 2.34 seconds and the time to stop is 4.68 seconds.
What is constant velocity?Constant velocity is the velocity which covers the same distance for each interval of the time.
It can be given as,
[tex]v=\dfrac{x}{t}[/tex]
As the distance covered by the car is 23 meters and the constant velocity of the car is 22 miles per second.
Convert the unit of velocity in m/s the value obtained will be 9.84 m/s.
Thus amount of time, [tex]t_{pass}[/tex] is,
[tex]9.84=\dfrac{23}{t_{pass} } \\t_{pass} =\dfrac{23}{9.84} \\t_{pass} =2.34[/tex]
As the distance covered by the car is 23 meters and the constant velocity of the car is 22 miles per second.
Convert the unit of velocity in m/s the value obtained will be 9.84 m/s.
Thus amount of time, [tex]t_{pass}[/tex] is,
[tex]9.84=\dfrac{23}{t_{pass} } \\t_{pass} =\dfrac{23}{9.84} \\t_{pass} =2.34[/tex]
According to the third equation of the motion acceleration can be given as,
[tex]v^2-u^2=2ax\\a=\dfrac{v^2-u^2}{2x}\\a=\dfrac{0^2-9.84^2}{2\times 23}\\a=-2.1 \rm \; m/s^2[/tex]
Now, use the first equation of motion, to get the required time,
[tex]v=u+at\\0=9.84+(-2.1)t\\t=4.68\rm \; s[/tex]
Therefore, the time required to pass is 2.34 seconds and the time to stop is 4.68 seconds.
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The local church is hosting a carnival which includes a bumper car ride. Bumper car A and its driver have a mass of 300 kg; bumper car B and its driver have a mass of 200 kg. Bumper car A has a velocity to the right of 2 m/s and bumper car B is at rest. At t = 0 s, bumper car A and B are separated by 10 m. Bumper car A accelerates at 1 m/s2 to a velocity of 4 m/s and continues at this constant speed until colliding with bumper car B.
Calculate the time required for bumper car A to travel the 10 m to collide with bumper car B.
Calculate the speed of bumper car A following the collision with bumper car B, which now has a velocity to the right of 3 m/s.
Is the direction of motion for bumper car A following the collision with bumper car B to the right, to the left, or is bumper car A at rest?
Is the collision elastic? Justify your answer.
Answer:
a. 20 s
b. 0 m/s
c. right
d.no its inelastic because when the car b was at rest and a was coming in at it, since b had no force what so ever car a swept it away with it moving to the right
Explanation:
im not sure though
By applying conservation of linear momentum, the answers are:
1. Time = 2 s
2. 3 m/s
3. same direction
4. Inelastic collision
COLLISIONThere are for types of collision. They are;
Elastic CollisionPerfectly elastic collisionInelastic collisionPerfectly Inelastic collisionGiven that a local church is hosting a carnival which includes a bumper car ride. Bumper car A and its driver have a mass of 300 kg; bumper car B and its driver have a mass of 200 kg. Bumper car A has a velocity to the right of 2 m/s and bumper car B is at rest. At t = 0 s, bumper car A and B are separated by 10 m. Bumper car A accelerates at 1 m/s2 to a velocity of 4 m/s and continues at this constant speed until colliding with bumper car B.
1. The time required for bumper car A to travel the 10 m to collide with bumper car B can be calculated by using first equation of linear motion.
V = U + at
Where
V = 4 m/s
U = 2 m/s
a = 1 m/[tex]s^{2}[/tex]
Substitute all the parameters into the formula
4 = 2 + t
t = 4 - 2
t = 2s
2. To calculate the speed of bumper car A following the collision with bumper car B, which now has a velocity to the right of 3 m/s, we will apply conservation of linear momentum
[tex]m_{1}u_{1}[/tex] = [tex]m_{1}v_{1}[/tex] + [tex]m_{2}v_{2}[/tex]
300 x 4 = 300V + 200 x 3
1200 = 300V + 300
300V = 1200 - 300
300V = 900
V = 900/300
V = 3 m/s
3. Since the final velocity of car A is positive, the direction of motion for bumper car A follows the collision with bumper car B to the right.
4. Since the both move at the same velocity, the collision inelastic.
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A scientist plans to release a weather balloon from ground level, to be used for high-altitude atmospheric measurements. The balloon is spherical, with a radius of 2.10 m, and filled with hydrogen. The total mass of the balloon (including the hydrogen within it) and the instruments it carries is 24.0 kg. The density of air at ground level is 1.29 kg/m3. (a) What is the magnitude of the buoyant force (in N) acting on the balloon, just after it is released from ground level
Answer:
Fb = 490.4 N
Explanation:
According to Archimedes' principle, any object submerged in a fluid, receives a push upward (which we call buoyant force) equal to the weight of the volume of the fluid removed by the object.We can express this force (Fb), in terms of the density and the volume of the fluid, as follows:[tex]F_{b} = \rho * V * g (1)[/tex]
The volume removed from the fluid by the balloon is just the volume of the balloon, assuming that it is a perfect sphere, as follows:[tex]V = \frac{4}{3}*\pi * R^{3} = \frac{4}{3} *\pi *(2.1m)^{3} = 38.8 m3 (2)[/tex]
Replacing by the givens and (2) in (1), we get:[tex]F_{b} = \rho * V * g = 1.29 kg/m3* 38.8m3*9.8m/s2 = 490.4 N (3)[/tex]
g Design an experiment you can use to determine the mass of the metal cylinder. When you explain your experiment, be sure to mention: What is the underlying model (equation) that you can use to determine the mass from your measurements
Answer:
m = [tex]\frac{k}{g}[/tex] x,
graph of x vs m
Explanation:
For this exercise, the simplest way to determine the mass of the cylinder is to take a spring and hang the mass, measure how much the spring has stretched and calculate the mass, using the translational equilibrium equation
F_e -W = 0
k x = m g
m = [tex]\frac{k}{g}[/tex] x
We are assuming that you know the constant k of the spring, if it is not known you must carry out a previous step, calibrate the spring, for this a series of known masses are taken and hung by measuring the elongation (x) from the equilibrium position, with these data a graph of x vs m is made to serve as a spring calibration.
In the latter case, the elongation measured with the cylinder is found on the graph and the corresponding ordinate is the mass
A 0.242 g sample of potassium is heated in oxygen. The result is 0.292 g of a crystalline compound. What is the formula of this compound?
A.
KO3
B.
KO2
C.
KO
D.
K2O
Answer:
Hello there Dude answer is B :D hope it helped mark me brainliest.
The formula of the compound formed has been [tex]\rm \bold {K_2O}[/tex]. Thus, option D is correct.
The sample of potassium has mass of 0.242 g. Since, the substance has been heated in the presence of oxygen, the gain in the weight has been corresponds with the mass of oxygen.
The given sample has:
Mass of potassium, [tex]m_K=0.242\;\text g[/tex]
Mass of heated sample, [tex]m_S=0.292\;\text g[/tex]
The mass of oxygen ([tex]m_O[/tex]) in the sample has been given as:
[tex]m_O=m_S-m_K[/tex]
Substituting the values:
[tex]m_O=0.292\;-\;0.242\;\text g\\m_O=0.05\;\text g[/tex]
The mass of oxygen in the sample has been 0.05 g.
The moles (M) of compounds in the sample has been given as:
[tex]M=\dfrac{m}{mwt}[/tex]
Where, m has been the mass of the compound, and
mwt has been the molecular weight of the compound.
The moles of potassium ([tex]M_K[/tex]) has been given as:
[tex]M_K=\dfrac{0.242}{39.098}\\M_K=0.006\;\text mol[/tex]
The moles of oxygen ([tex]M_O[/tex]) has been given as:
[tex]M_O=\dfrac{0.05}{16}\\M_O=0.003\;\text mol[/tex]
The molecular compound has been formed with Potassium and oxygen in the ratio of their moles as:
[tex]\rm \dfrac{K}{O}=\dfrac{0.006}{0.003}\\ \dfrac{K}{O}= \dfrac{2}1}[/tex]
Thus, the molecular formula of the compound has been [tex]\rm \bold {K_2O}[/tex]. Thus, option D is correct.
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Identify two technologies that can be used to find the locations of objects. Identify the type or types of waves each
technology uses.
[O.05]Which of these Earth spheres interact with oceans during beach erosion?
geosphere
hydrosphere
cryosphere
atmosphere
Answer:
hydrosphere of these Earth spheres interact with oceans during beach erosion.
Answer:
Geosphere
Explanation:
The geosphere is the solid parts of the earth including rocks, minerals, and sand on the beach. The shoreline is where the geosphere meets the ocean. This is how they interact during erosion.
It is not the hydrosphere because the ocean is a part of the hydrosphere.
A car can go from 0 m/s to 27 m/s in 4.5 seconds. If a net force of 6600 N acted on the car, what is its mass? (Hint: You must first calculate the acceleration then plug into Newton’s second law.)
Answer:
1100 kg
Explanation:
acceleration:
[tex]a=(27-0)/4.5[/tex]
[tex]a=6ms^{-2}[/tex]
Newton's second law:
[tex]F=ma[/tex]
[tex]6600=6m\\m=1100 kg[/tex]
A wave with a frequency of 5Hz travels a distance of 40mm in 2 seconds.What is the speed of the wave
Answer:
20mm per second
Explanation: