Answers
SOLUTION
We are asked which point is located at (-1, -3)
From the diagram given, the point located on (-1, -3) is point E.
Hence option C is the correct answer
Related Questions
Solve the equation for A: 2*Cos A + 2 = 3.
Answers
Answer:
A=60 degrees
Explanation:
Given the equation:
[tex]2\cos A+2=3[/tex]Subtract 2 from both sides of the equation.
[tex]\begin{gathered} 2\cos A+2-2=3-2 \\ 2\cos A=1 \end{gathered}[/tex]Divide both sides by 2:
[tex]\begin{gathered} \frac{2\cos A}{2}=\frac{1}{2} \\ \cos A=\frac{1}{2} \end{gathered}[/tex]Finally, solve for A.
[tex]\begin{gathered} A=\arccos (\frac{1}{2}) \\ A=60\degree \end{gathered}[/tex]a jacket at Rick's clothing store originally costs $27 the store is having a 45% off sale on all of its merchandise what is the sale price of the jacket
Answers
Let:
Op = Original price
Sp = Sale price
r = Discount
Express the discount percentage as a decimal:
45% = 45/100 = 0.45
The sale price will be given by:
[tex]\begin{gathered} Sp=Op-0.45Op \\ where \\ Op=27 \\ so\colon \\ Sp=27-12.5 \\ Sp=14.85 \end{gathered}[/tex]$14.85
For the following figure, complete the statement for the specified pointsRS.199Points RT, S, and areboth collinear and coplanarcolinearcoplanarneither col near nor coplanar
Answers
From the figure, we can see that point R, T, S, Q are not on the same plane. Thus we can say they are neither colli coplanar
c. If x= 3 is specifically a hole (removable discontinuity) of f(x), then what would be true about g(3) and h(3)? Explain your reasoning.
Answers
Solution
We have the following function given:
f(x)= g(x)/h(x)
We have a point of discontinuity on x=3
c. If x= 3 is specifically a hole (removable discontinuity) of f(x), then what would be true about g(3) and h(3)? Explain your reasoning.
For this case we can conclude that g(3)/h(3) is not defined since f(3) is not defined for the function and that means that the function is not fully connected on x=3
what digit is in the
Answers
The number given in the statement is
2.113 pints.
To write in word form,
Two and one hundred thirteen thousandths.
As in the number from last we have thousand , hundred, tens and ones.
So, we can write the given number in word form.
Two and one hundred thirteen thousandths.
Hence the correct option is c.
Decide whether the given orderd pair is a solution to the stystem of equations?I don’t know how to to the bottom equation.
Answers
Given:
[tex]\begin{gathered} y=2x-6 \\ x+y=8 \end{gathered}[/tex]solve the equation for x and y then
[tex]\begin{gathered} x+y=8 \\ \text{put the value of y} \\ x+2x-6=8 \\ 3x=8+6 \\ 3x=14 \\ x=\frac{14}{3} \end{gathered}[/tex]so value of y is:
[tex]undefined[/tex]Graph triangle ABC with vertices A(0,5) B(4,3) and C(2,-1) and it’s image after a reflection in the line y=2
Answers
By reflecting the given points about y=2, the x-coordinates remain the same, then we have
[tex]\begin{gathered} (0,5)\longrightarrow(0,-1) \\ (4,3)\longrightarrow(4,1) \\ (2,-1))\longrightarrow(2,5) \end{gathered}[/tex]then, the new triangle is:
where the red line represents the line y=2. We found the new points by searching the points which are at the same distance of the original poinst to the line:
Then, the preimage and the image after the reflection are:
Jake, Becky, and Max are meeting at Charley's Pizza for dinner and then plan to go
pizza place,
each one of them has a different coupbn. They decide to use the coupon that will give them the best deal. movie. When they arrive. the
Jake's coupon is $19.99 for a pizza and pasta meal deal, Becky's
of the menu price; and Max's coupon is for three mediun
coupon is for two large one topping pizas-each at ]
one-topping pizzas - each at -off the menu price. Accordling
to the menu, a medium one-topping pizza is $8.99, and
large one-topping pizza $14.89. They also spend $1.25
for sodas and $5.00 on the tip. At the movie theater. Max has › coupon that's good for ãoff a third movie ticket when
you purchase two other movie tickets at the regular price.
The regular price of each movie ticket is $9.80.
Although Jake, Becky, and Max plan to split the cost of the pizza and movie, they decide that with the coupons, it's just
easier if one of them pays at each place. So, the friends agree that Jake will pay for the pizza and Becky will pay for the
movies. At the end of the night, they'll figure out how much Max owes
both Jake and Becky.
After all costs
split evenly, how much will each person contribute?
between $14 and $15
• between $15 and $16
• between $16 and $17
O between $17 and $18
Answers
Answer:
$16 and $17
Step-by-step explanation:
you have two fractions 2/5 and 3/10 and you want to rewrite them so that they have the same denominator what numbers could you use for the denominator is it A 20 or B 10 or C5 or D 15
Answers
By definition, a fraction has the following form:
[tex]\frac{a}{b}[/tex]When "a" is the numerator and "b" is the denominator.
In this case you have the following fractions:
[tex]\begin{gathered} \frac{2}{5} \\ \\ \frac{3}{10} \end{gathered}[/tex]Notice that the denominator of the first fraction is 5 and the denominator of the second fraction is 10.
The steps to find the a Common denominator are shown below:
1. Descompose 5 and 10 into their Prime factors:
[tex]\begin{gathered} 5=5 \\ 10=2\cdot5 \end{gathered}[/tex]2. In this case, you need to choose 5, because it is the common one. It will be the Common denominator of the fractions.
3. Divide the original denominator of the first fraction by the Common denominator 5. Multiply the the numerator by the result. Then:
[tex]\frac{2}{5}=\frac{2\cdot1}{5}=\frac{2}{5}[/tex]4. Apply the procedure explained in step 3 to the second fraction:
[tex]\frac{3}{10}=\frac{3\cdot2}{5}=\frac{6}{5}[/tex]5. You can identify that you can also get a common denominator multiplying the denominators and the numerators of both fractions by
The answer is: Option C.
Solve for h by using the inverse (opposite) operations. −5.3+h5=−19.4
Answers
Given:
The given term is -5.3+h/5=-19.4.
The objective is to find the value of h using inverse operation.
Inverse operation states that, if a term is in addition operation with another term, then it will change to subtraction operation while shifting to other side of the equation.
If a term is in multiplication operation, then it change to division operation while shifting to other side of the equation.
The value of h can be calculated as,
[tex]\begin{gathered} -5.3+\frac{h}{5}=-19.4 \\ \frac{h}{5}=-19.4+5.3 \\ \frac{h}{5}=-14.1 \\ h=-14.1(5) \\ h=-70.5 \end{gathered}[/tex]Thus, the value of h is -70.5.
Hence, option (c) is the correct answer.
Write a system of equations to describe the situation below, solve using any method, and fill in the blanks. The volleyball team and the wrestling team at Brookfield High School are having a joint car wash today, and they are splitting the revenues. The volleyball team gets $2 per car. In addition, they have already brought in $92 from past fundraisers. The wrestling team has raised $16 in the past, and they are making $4 per car today. After washing a certain number of cars together, each team will have raised the same amount in total. What will that total be? How many cars will that take?
Answers
Data:
Volleyball team: V
Wrestling team: W
x: number of cars
V: $2 per car. Initial $92
W: $4 per car. Initial $16
You have the next equations:
[tex]\begin{gathered} V=2x+92 \\ W=4x+16 \end{gathered}[/tex]To find the total amount you have the next equation:
As each team have raised the same amount:
[tex]\begin{gathered} V=W \\ \\ 2x+92=4x+16 \end{gathered}[/tex]You solve x to find the number of cars each team wash in total:
[tex]\begin{gathered} 2x-4x+92=4x-4x+16 \\ -2x+92=16 \\ \\ -2x+92-92=16-92 \\ -2x=-76 \\ \\ \frac{-2}{-2}x=\frac{-76}{-2} \\ x=38 \end{gathered}[/tex]You use that value of x to find the final amount of each team:
[tex]\begin{gathered} V=2(38)+92=76+92=168 \\ \\ W=4(38)+12=152+12=168 \end{gathered}[/tex]Then, (the total of each team is $168) Total $336, (each team wash 38 cars) The total number of cars 76Match the steps to put them in the correct order of something. You will not use all of the options.
Answers
SOLUTION
[tex]\begin{gathered} Given \\ 2h+9=21 \end{gathered}[/tex][tex]\begin{gathered} Step\text{ 1:} \\ Subtract\text{ 9 from both sides} \\ 2h+9-9=21-9 \\ 2h=12 \end{gathered}[/tex][tex]\begin{gathered} Step\text{ }2: \\ Divide\text{ both sides by 2} \\ \frac{2h}{2}=\frac{12}{2} \\ h=6 \end{gathered}[/tex][tex]\begin{gathered} Final\text{ answer:} \\ h=6 \end{gathered}[/tex]12 more than the product of 5 and a number x
Answers
Answer: (5*x) + 12 or 5x + 12
Step-by-step explanation: differant sites let you do it defferent ways but if the multipaction sign in an "x" I would do the 2nd one :) Hope it's right, have a great day!
hi can someone help me solve this thank you!!
Answers
For the given inequality, the smallest value of x is a whole number which is exactly divisible by both 2 and 5.
As given in the question,
Given inequality :
[tex]4x/5 - 1x/2 > 18[/tex]
[tex][2(4x) + 5(-x)]/5.2 > 18[/tex]
[tex](2.4x - 5x) / 5.2 > 18[/tex]
[tex](8x-5x)/10 > 18[/tex]
[tex]3x/10 > 18[/tex]
[tex]3x > 180 \\3x/3 > 180/3\\x > 60\\[/tex]
x ∈ (60, ∞)
∵ Since 60 is whole number and divisible by 2 and 5 both.
therefore answer is option e.
Therefore, for the given inequality, the smallest value of x is a whole number which is exactly divisible by both 2 and 5.
Learn more about inequality here
brainly.com/question/28823603
#SPJ1
Find the derivative of the function y=(4x^ 3 -5x^ 2 )(3x^ 6 +2x^ 5 )10 two different ways. First, multiply the factors togethercollect like terms, then use the basic rules to find the derivative. Second, apply the Product Rule to the function as is currently written.
Answers
Given:
The given function is:
[tex]y=(4x^3-5x^2)(3x^6+2x^5)[/tex]First method: Multiplying factors and differentiating after arranging like terms together.
[tex]\begin{gathered} y=(4x^3-5x^2)(3x^6+2x^5) \\ =4x^3(3x^6+2x^5)-5x^2(3x^6+2x^5) \\ =12x^9+8x^8-15x^8-10x^7 \\ =12x^9-7x^{8^{}}-10x^7 \end{gathered}[/tex]Now we will differentiate y with respect to x by basic rules:
[tex]y^{\prime}=12(9)x^{9-1}-7(8)x^{8-1}-10(7)x^{7-1}[/tex]Solving further,
[tex]y^{\prime}=108x^8-56x^7-70x^6[/tex](b) Second method: Apply product rule to find the derivative:
Again,
[tex]y=(4x^3-5x^2)(3x^6+2x^5)[/tex]The product rule states:
[tex](uv)^{\prime}=u^{\prime}v+v^{\prime}u[/tex]Where u and v are the two factors multiplied.
So here we have:
[tex]\begin{gathered} u=4x^3-5x^2 \\ v=3x^6+2x^5 \end{gathered}[/tex]Finding the derivatives:
[tex]\begin{gathered} u^{\prime}=4(3)x^{3-1}-5(2)x^{2-1} \\ =12x^2-10x \end{gathered}[/tex]Similarly,
[tex]\begin{gathered} v^{\prime}=3(6)x^{6-1}+2(5)x^{5-1} \\ =18x^5+10x^4 \end{gathered}[/tex]Now put the values in the product rule,
[tex]\begin{gathered} y^{\prime}=(uv)^{\prime} \\ =u^{\prime}v+v^{\prime}u \\ =(12x^2-10x)(3x^6+2x^5)+(18x^5+10x^4)(4x^3-5x^2) \end{gathered}[/tex]Simplifying further,
[tex]\begin{gathered} y^{\prime}=12x^2(3x^6+2x^5)-10x(3x^6+2x^5)+18x^5(4x^3-5x^2)+10x^4(4x^3-5x^2) \\ =36x^8+24x^7-30x^7-20x^6+72x^8-90x^7+40x^7-50x^6 \\ =108x^8-56x^7-70x^6 \end{gathered}[/tex]This is the derivative obtained.
From above two methods, we can see the derivative is same in both the cases.
You invested $28,000 in two accounts paying 7% and 9% annual interest, respectively. If the total interest earned for the year was $2180, how much was invested at each rate?
Answers
We are given the following information:
total of $28,000 invested in 2 accounts
7% and 9% interest rates for each account
total interest was $2,180
We are asked to calculate the amount invested at each rate.
To do this, let us first identify our variable and what it stands for. Let us use the variable x to represent the amount invest at 7%. That leaves us t
O DATA ANALYSIS AND STATISTICSFinding the mode and range of a data setEach day, Susan records the number of news articles she reads. Here are her results for the last eight days.3, 6, 6, 9, 1, 6, 9,6Find the range and the mode for the data.
Answers
We are given the following data set:
[tex]3,6,6,9,1,6,9,6[/tex]We are asked to determine the range. To do that we will arrange the data from smallest to greatest values, like this:
[tex]1,3,6,6,6,6,9,9[/tex]Now, the range is the difference between the smallest and greatest value, therefore:
[tex]\text{Rage}=9-1=8[/tex]Therefore, the range is 8
Now, the mode is the value that repeats the most. In this case, we have that the value "6" is repeated 4 times, therefore, the mode is:
[tex]\mod e=6[/tex]graph f(x)=(x-4)^3-2
Answers
Explanation:
Before we plot the graph, you need to understand the transformation process of the parent function x³
x - 4 inside the parenthesis talks about the horizontal shift of the graph. -4 means that the graph will move to the right by 4.
The constant value outside the parenthesis talks about the graph movement. The constant -2 shows that the graph moves downward by 2.
Find the graph of the function below:
A certain car is rated to get 24 miles per gallon. How far can it travel on 14.5 gallons of gas?
Answers
348 miles
Explanation
Step 1
[tex]\text{rate}=24\text{ }\frac{miles\text{ }}{\text{gallon}}[/tex]
it indicates that for every gallon the car can travel 24 miles, Now to know the total miles it can travel with 14.5 gallons of gas, just multiply the rate by the numbers of gallons
so
let
[tex]\begin{gathered} \text{rate}=24\text{ }\frac{miles\text{ }}{\text{gallon}} \\ gallons=14.5 \end{gathered}[/tex]make the product
[tex]\begin{gathered} \text{distace}=\text{rate}\cdot Number\text{ of gallons} \\ \text{replace} \\ \text{distance}=24\frac{miles\text{ }}{\text{gallon}}\cdot14.5\text{ gallons} \\ \text{distance}=348\text{ miles} \end{gathered}[/tex]therefore, the answer is 348 miles
I hope this helps you.
Jada and Priya are trying to solve the equation 2/3 + x = 4 Jada says I think we should multiply each side by 3/2 because that is the reciprocal of 2/3 Priya since I think we should add -2/3 to each side because that is the opposite of 2/3
Answers
The equation they are trying to solve is
[tex]\frac{2}{3}+x=4[/tex]In order to solve this equation, they need to add -2/3 on each side (the opposite of 2/3).
[tex]\begin{gathered} \frac{2}{3}-\frac{2}{3}+x=4-\frac{2}{3} \\ x=4-\frac{2}{3} \end{gathered}[/tex]Hence, Priya is correct because they need to use the opposite of 2/3, not the reciprocal.
An equation that can be solved using Jada's strategy is
[tex]\frac{2}{3}x=4[/tex]This equation would need to use a reciprocal, as Jada said.
Find the length of the legs.(4,4)[](-2,-2)[?]Enter the number thatbelongs in the green boxEnter
Answers
We have a right triangle and we have to find the length of the legs.
We first analyse the hypotenuse.
It is a line that is defined by two points: (4,4) and (-2,-2).
The line passes through the center of coordinates, but we will check it:
The slope can be calculated as:
[tex]m=\frac{y_2-y_1}{x_2-x_1}=\frac{4-(-2)}{4-(-2)}=1[/tex]We can now write the slope-point equation as:
[tex]\begin{gathered} y-y_0=m(x-x_0) \\ y-4=1(x-4) \\ y-4=x-4 \\ y=x \end{gathered}[/tex]Then, we know that the equation of the line that defines the hypotenuse is y=x.
If the legs are parallel to the axis, we can find the angle that is defined by the hypotenuse and the horizontal leg as:
[tex]\begin{gathered} \tan (\theta)=m=1 \\ \theta=\arctan (1)=45\degree \end{gathered}[/tex]As we have an angle of 45 degree for one leg, the other has to have an equal angle, as 180-90-45=45 (Note: we are substracting from the sum of the 3 angles, 180 degrees, the already known angles, 90 and 45 degrees, so we are left with 45 degrees that correspond to the third angle).
If the two angles for the legs are equal, their lengths are equal too.
So we can start by calculating the length of the hypotenuse: it is the distance between (4,4) and (-2,-2).
[tex]\begin{gathered} D=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}=\sqrt[]{(4-(-2))^2+(4-(-2))^2} \\ D=\sqrt[]{6^2+6^2}=\sqrt[]{2\cdot6^2}=6\sqrt[]{2} \end{gathered}[/tex]Then, we can write the Pythagorean theorem as (a and b are the legs, and c is the hypotenuse):
[tex]\begin{gathered} a^2+b^2=c^2 \\ a=b\longrightarrow2a^2=c^2=(6\sqrt[]{2})^2=36\cdot2=72 \\ a^2=\frac{72}{2} \\ a^2=36 \\ a=\sqrt[]{36} \\ a=b=6 \end{gathered}[/tex]Answer: the length of the legs is 6 units.
Each of the four graphs below represents a function.Which function has an inverse that is also a function?
Answers
For the given question, we will choose the function that has an inverse that will be a function
So, the function must be a one-to-one function
We will use the horizontal line test to check if the function is a one-to-one function or not
the horizontal line will intersect with the graph of the function at only one point
So, the answer will be option 4 as shown in the following figure:
Can someone please help me with my math ;( ?
Answers
Step 1:
copy and complete the table below by inputting the data provided.
The marginal frequency numbers are the numbers at the edges of the table except for the number at the bottom right-most corner.
B) Marginal relative frequency is the ratio of the sum of the joint relative frequency in a row or column and the total number of data values
Hence,
[tex]\text{ the lowest marginal frequency }=\frac{107}{232}=0.461[/tex]Joint relative frequency the ratio of the frequency in a particular category and the total number of data values
Therefore,
[tex]\text{ the largest joint frequency }=\frac{63}{111}=0.568[/tex]C)For the circled number, the preferred style is Gothic given that the member is male and the percentage is 0.57
D) The total number of males surveyed = 111
the total number of members surveyed = 232
Hence, the percentage of the total number of choir students surveyed that were males are:
[tex]\frac{111}{232}=0.48[/tex]For each triangle, check all that apply. 60° Triangle A 60° Scalene Isosceles O Equilateral 60° 5 Triangle B 11 7 O Scalene O Isosceles O Equilateral 60 triangles by side... Triangle C 30° Scalene Isosceles O Equilateral Triangle D 8 O Scalene O Isosceles O Equilateral
Answers
Given:
Four triangles A, B, C and D are given as below
Find:
we have to classify each triangle.
Explanation:
Triangle A:
Since, in the triangle A, all the three angles are equal to 60 degree.Therefore, all three sides of triangle A are equal.
So, Triangle A is Equilateral.
Triangle B:
In triangle B all the three sides are different.
Therefore, triangle B is Scalene.
Triangle C:
In triangle C, all the angles are diffrent, so all three sides are different.
Therefore, Triangle C is Scalene.
Triangle D:
In triangle D, two sides are equal.
Therefore, Triangle D is isosceles
true or false18. In the circle: x^2+(y-2)^2=12, the radius is 12
Answers
The general equation of a circle is:
[tex](x-h)^2+(y-k)^2=r^2[/tex]where (h,k) is the center and r is the radius of the circle.
Comparing the given equation of a circle and the above general equation we get:
[tex]r^2=12[/tex]Then, the radius of this circle is:
[tex]r=\sqrt[]{12}[/tex]In conclusion, the sentence is false.
What is the remainder when j(x)=x4+2x3−5x2+2x+4 is divided by x+3
Answers
From the problem, we have a function :
[tex]j(x)=x^4+2x^3-5x^2+2x+4[/tex]The remainder when j(x) is divided by x + 3 is the value of the function when x = -3
x = -3 comes from :
x + 3 = 0
x = -3
Substitute x = -3 to the function,
[tex]\begin{gathered} j(-3)=(-3)^4+2(-3)^3-5(-3)^2+2(-3)+4 \\ j(-3)=81-54-45-6+4 \\ j(-3)=-20 \end{gathered}[/tex]The answer is -20
In how many months were there more than two days with thunderstorms? 1 3 5 7
Answers
To find how many months have more than 2 days look at the heights
of the bars
You need to count the bars which height more than 2
There are 5 bars that have a height of more than 2
The answer is 5
f(x) = -x2 + 7x - 13 Find f(-3)
Answers
Given the function :
[tex]f(x)=-x^2+7x-13[/tex]To find f(-3) , substitute with x = -3 , into the given function:
So,
[tex]\begin{gathered} f(-3)=-(-3)^2+7\cdot-3-13 \\ \\ f(-3)=-9-21-13 \\ \\ f(-3)=-43 \end{gathered}[/tex]
A student is taking a test in which items of type A are worth 8 points and items of type B are worth 12 points. It takes 3 min to complete each item of type A and 6 min to complete each item of type B. The total time allowed is 60 min and Anna answers exactly 16 questions. How many questions of each type did she complete? Assuming that all her answers were correct, what was her score? She completed questions of type A.
Answers
Type A questions are worth 8 points each.
Type B questions are worth 12 points each.
it takes 3 minutes to answer a Type A question
it takes 6 minutes to answer a Type B question.
total time allowed = 60 minutes
She answered a total of 16 questions.
let
number of question answer on type A = x
number of question answered on type B = y
Therefore,
3x + 6y = 60
x + y = 16
then,
[tex]\begin{gathered} 3x+6y=60 \\ x+y=16 \\ x=16-y \\ 3(16-y)+6y=60 \\ 48-3y+6y=60 \\ 3y=60-48 \\ 3y=12 \\ y=\frac{12}{3} \\ y=4 \\ x=16-4 \\ x=12 \end{gathered}[/tex]She answered 12 questions on type A and 4 questions on type B.
If all her answer is correct her score can be computed below
[tex]undefined[/tex]which equation shows x^2+6x-4=0 rewritten by completing the squarea) (x+3)^2=36b) (x+3)^2=4c) (x+3)^2=9d) (x+3)^2=13
Answers
Solution
Step 1
Write the equation:
[tex]x^2\text{ + 6x - 4 = 0}[/tex]Step 2:
Rewrite the equation:
[tex]x^2\text{ + 6x = 4}[/tex]Step 3
[tex]\begin{gathered} Add\text{ }\frac{b^2}{4a\text{ }}\text{ to both sides to get a perfect square.} \\ \text{a = 1, b = 6} \\ \frac{b^2}{4a}\text{ = }\frac{6^2}{4\times1}\text{ = }\frac{36}{4}\text{ = 9} \end{gathered}[/tex][tex]\begin{gathered} x^2\text{ + 6x + 9 = 4 + 9} \\ Add\text{ similar terms:} \\ (x\text{ + 3\rparen}^2\text{ = 13} \end{gathered}[/tex]Final answer
[tex]d)\text{ \lparen x + 3\rparen}^2\text{ = 13}[/tex]