Answer: A ball rolling down the driveway.
Explanation:
Kinetic is when an object is in motion. Potential is when an object rests.
If mass of an empty 7.0 mL pycnometer is 10.2g and the mass of the same pycnometer with an unknown liquid is 21.8g. Determine the density of the unknown liquid to ONE DECIMAL PLACE in g/mL.
The formula for calculating density is expressed as
Density = mass/volume
From the information given,
mass of empty pycnometer = 10.2
mass of the same pycnometer with an unknown liquid is 21.8.
Mass of unkown liquid = 21.8 - 10.2 = 11.6
volume of unknown liquid = 7
Thus,
Density = 11.6/7
Density = 1.7 g/ml
A 0.0500-kg ice cube at −30.0ºC is placed in 0.400 kg of 35.0ºC water in a very well-insulated container. What is the final temperature?
The amount of heat that is gained by water is equal to the amount of heat loss by the ice. Therefore, we have the following relationship:
[tex]-Q_w=Q_i[/tex]Where "Qw" is the heat of water and "Qi" is the heat of ice. The heat of water is given by:
[tex]Q_w=m_wC_w(T_f-T_{0w})[/tex]The amount of heat of ice must be calculated for the two states, solid and liquid. For the solid-state the temperature will be from -30 degrees to 0 degrees, therefore, we have:
[tex]Q_i=m_iC_i(T_f-T_{0i})[/tex]Where Ci is the specific heat of ice in solid-state and is equal to:
[tex]C_i=2090\frac{kJ}{\operatorname{kg}}[/tex]Replacing the values:
[tex]Q_i=(0.05\operatorname{kg})(2090\frac{kJ}{\operatorname{kg}K})(0-(-30C))[/tex]Solving the operations we get:
[tex]Q_i=3135J[/tex]Now we need to determine the amount of heat that needs the ice to convert into liquid. This is given by:
[tex]Q_{i-l}=m_iL_f[/tex]Lf is the latent heat of ice and is equal to:
[tex]L_f=334\frac{kJ}{\operatorname{kg}}[/tex]Replacing the values we get:
[tex]Q_{i-l}=(0.05\operatorname{kg})(334\frac{kJ}{\operatorname{kg}})[/tex]Solving the operations:
[tex]Q_{i-l}=16.7kJ=16700J[/tex]Now we need the amount of heat of liquid ice to its final temperature, this is given by:
[tex]Q_l=m_iC_l(T_f-0)[/tex]Applying the relationship:
[tex]-m_wC_w(T_f-T_{0w})=m_iC_i(T_f-T_{0i})+m_iL_f+m_iC_w(T_f-0)[/tex]Cw is the specific heat of water and is equal to:
[tex]C_w=4184\frac{J}{\operatorname{kg}K}[/tex]And the specific heat of ice is:
[tex]C_i=4184\frac{J}{\operatorname{kg}K}[/tex]Replacing the values. The first two terms on the right side we already calculated and the final temperature is the same for both:
[tex]-(0.4\operatorname{kg})(4184\frac{kJ}{\operatorname{kg}K})(T_f-35)=3135J+16700J+(0.05)(4184\frac{kJ}{\operatorname{kg}K})(T_f)[/tex]Solving operations:
[tex]-1673.6\frac{kJ}{K}(T_f-35)=19835J+209.2\frac{kJ}{K}T_f[/tex]Now we solve for the final temperature:
[tex]-1673.6T_f+58576=19835+209.2T_f[/tex]Subtracting 19835 to both sideS:
[tex]\begin{gathered} -1673.6T_f+58576-19835=209.2T_f \\ -1673.6T_f+38741=209.2T_f \end{gathered}[/tex]Now we add 1673Tf to both sides:
[tex]\begin{gathered} 38741=209.2T_f+1673.6T_f \\ 38741=1882.8T_f \end{gathered}[/tex]Now we divide both sides by 1882.2
[tex]\frac{38741}{1882.8}=T_f[/tex][tex]20.57=T_f[/tex]Therefore, the final temperature is 20.57 °C. This value can be converted into Kelvin using the following relationship:
[tex]T_K=T_C+273.15[/tex]Replacing the temperature:
[tex]T_K=20.57+273.15=293.72[/tex]Therefore, the final temperature is 293.72 K.
Q.5 Louisa rolls a ball with 31N of force. She observes that it has a acceleration
of 2.1m/s2. What is the mass of the ball?
Answer:
F = M a Newton's Second Law
M = F / a = 31 N / 2.1 m/s^2 = 14.8 kg
Rather heavy since 1 kg mass weighs about 2.2 lbs force
A 0.4 kg object is attached to a spring with
a spring constant 145 N/m so that the object
is allowed to move on a horizontal frictionless
surface. The object is released from rest when
the spring is compressed 0.14 m.
Find the force on the object when it is
released.
Answer in units of N.
20.3 Newton spring force on the object when it is released.
Force on the object when it is released,
F = kx (Hooke's law)
k=spring constant
x=spring compression
F = 145 N/m × 0.14 = 20.3 N
Basic Harmonic Periodic motion includes motion. In SHM, the relationship between the restoring force Fx and the displacement x is straightforward. The displacement and the restoring force always have opposing signs. Forming the equation for the force is achievable thanks to the proportionality constant k. F = kx This connection, known as Hooke's Law for springs, will depend on the spring constant, k. k is measured in Newton per meter in the SI.
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Geremy rolled a can of soup off the kitchen table. The can landed 0.75m from the table. The height of the table is 1.35m. At what velocity did Geremy roll the can horizontally?
Please show all work, thank you
The velocity used by Geremy to roll the can horizontally is 1.44 m/s
How do I determine the horizontal velocity used by Geremy?First we shall obtain the time taken for the can to reach the ground. This is shown below:
Height (h) = 1.35 mAcceleration due to gravity (g) = 9.8 m/s²Time (t) =?h = ½gt²
1.35 = ½ × 9.8 × t²
1.35 = 4.9 × t²
Divide both side by 4.9
t² = 1.35 / 4.9
Take the square root of both side
t = √(1.35 / 4.9)
t = 0.52 second
Finally, we shall determine the velocity used by Geremy to roll the can horizontally. Detail below:
Horizontal distance (s) = 0.75 mTime (t) = 0.52 secondHorizontal velocity (u) = ?s = ut
0.75 = u × 0.52
Divide both sides by 0.52
u = 0.75 / 0.52
u = 1.44 m/s
Thus, we can conclude that the horizontal velocity used is 1.44 m/s
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The average kinetic energy
of the particles in matter?
The average kinetic energy of the substance's particles is its temperature.
What is average kinetic energy?The average kinetic energy of a substance's particles is inversely correlated with that substance's temperature, according to the kinetic-molecular hypothesis.
When a substance is heated, some of the energy received is retained by the particles, while other energy quickens the motion of the particles. The material's temperature increases as a result of this.
The average kinetic energy of a substance's particles is directly proportional to the substance's temperature. These particles must move more quickly as the temperature rises because their mass is constant.
Lowering the system's temperature causes a decrease in a particle's kinetic energy.
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When a pole vaulter reaches the top of her vault, how does her potential energy compare to her kinetic energy?.
Answer
Explanation:
the kinetic energy is twice the amount of potential energy.
A 50 kg ball traveling at 20 m/s would haveA50 kg ball traveling at 5 m/s would haveA 50 kg person falling at 10 m/s would havekinetic energy✓ kinetic energykinetic energythe same2 times more2 times less4 times more4 times lessDoneIntro5 of 9
We have the next formula to calculate the kinetic energy
[tex]KE=\frac{1}{2}mv^2[/tex]where m is the mass and v is the velocity
For the kinetic energy of ball 50 kg traveling at 10 m/s
[tex]KE=\frac{1}{2}(50)(10)^2=2500\text{ joules}[/tex]For the kinetic energy of ball 50 kg traveling at 20 m/s
[tex]KE=\frac{1}{2}(50)(20)^2=10000\text{ joules}[/tex]A 50 kg ball traveling at 20 m/s would have 4 times kinetic energy.
For kinetic energy of the ball 50 kg at 5m/s
[tex]KE=\frac{1}{2}\mleft(50\mright)\mleft(5\mright)^2=625\text{ joules}[/tex]A 50 kg ball traveling at 5 m/s would have 4 times less kinetic energy
For the person 50kg falling 10 m/s
[tex]KE=\frac{1}{2}\mleft(50\mright)\mleft(10\mright)^2=2500joules[/tex]A 50 kg person falling at 10 m/s would have the same kineticenergy}.
The solution is
A 50 kg ball traveling at 20 m/s would have 4 times more kinetic energy.
A 50 kg ball traveling at 5 m/s would have 4 times less kinetic energy.
A 50 kg person falling at 10 m/s would have the same kinetic energy.
11. The temperature of a 50 kg block increases by 15°C when337,500 J of thermal energy are added to the block. (Chapter5- Pages 141-142)a. What is the specific heat of the object? Show theappropriate equation from your book and show your workwith units.b. What is the block made of? Use the chart on page 141.c. Is this block a good material for insulators or conductors
0.45 kJ/kg/°C is the specific heat of the object when the temperature of a 50 kg block increases by 15°C when337,500 J of thermal energy are added to the block.
Heat = mass × specific heat × change in temperature
q = m C ΔT
Given:
q = 337500 J
m = 50 kg
ΔT = 15°C
now, place values
337500 J = (50 kg) C (15°C)
C = 450 J/kg/°C
Specific heat is usually recorded in J/g/°C or kJ/kg/°C. Converting:
C = 0.45 J/g/°C = 0.45 kJ/kg/°C
the amount of heat needed to increase a substance's temperature by one degree Celsius in one gram, also known as specific heat. Typically, calories or joules per gram per degree Celsius are used as the units of specific heat. For instance, water has a specific heat of 1 calorie (or 4.186 joules) per gram per degree Celsius.
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Help me please!!!!!!!
lab report shows water changing state of matter is an endothermic process with changing temperature this is an example of physical change.
When some of a material's properties change but the identity of the material does not, there is a physical change to the substance. Reversible and irreversible physical changes are further separated into two types. Since the melted ice cube can be refrozen, melting is a physically reversible process.
For instance, when water is heated, the temperature and energy of the water molecules rise, causing the liquid water to vaporize into water. When this occurs, some sort of alteration has occurred, but the water's molecular makeup remains unchanged. A bodily transformation like this is an example.
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How much pressure does a box whose sides are 1.44 m long each exert on the ground due to gravity?Assume that the box has a mass of 17.3 kg. HINT: Look at the definition of pressure - what force is doing the "pushing?" What's the area?
Pressure = Force / area
m= mass = 17.3 kg
g= gravity = 9.8 m/s^2
Force = m * g = 17.3 kg * 9.8 m/s^2 = 169.54 N
P = F / A
A = area = 1.44^2 = 2.0736 m^2
P = 169.54 N/ 2.0736 m^2 = 81.76 Pa
What is the percentage efficiency of a 70W bulb that produces 210J of light energy over a minute?
Answer:
5%
Explanation:
here
power = 70w
output = 210 J
time = 1 mins = 60 secs
for total input we get
input energy = P*t
= 70*60 = 42000J
for the efficiency we know that
%efficiency = (total output / total input ) * 100%
= (210/42000) * 100%
= 5%
Answer:
Explanation:
Given:
P = 70 W - Lamp power
A = 210 J - Lamp energy
t₀ = 1 min = 60 s - Time
_________
ε - The percentage efficiency
t = A / P = 210 / 70 = 3 s
ε = t / t₀ = 3 / 60 = 0.05 or ε = 0,05·100% = 5%
At what decibel Level two sounds starts to becomeHarmful to the ears and the hearing?
Sound intensity more than 70 dB (noise) for a long period of time may start to damage your hearing.
A loud noise with sound intensity more than 120 dB can cause immediate harm to your ears.
If you start with 500g of water in your pot, and after it boils away, the steam takes up 2 m3 of space, what is the density of the steam in g/m3?
The density of the steam is 250g/m³.
What is the procedure for determining density?d = M/V
Density is defined as d = m/v, where m stands for mass, and for volume. The unit of density that is most frequently used is grams per cubic centimeter. For instance, the density of Earth is 5.51 grams per cubic centimeter, while the density of water is 1 gram per cubic centimeter.
A material's density is determined by how much space a given amount of the substance occupies relative to its mass (volume). A substance's density is based on the mass, size, and arrangement of its atoms. Density (D) is defined as the substance's mass divided by its volume.
Given,
mass = 500g
volume = 2m³
density = 500/2
density = 250g/m³.
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Objects with smaller masses have more gravitational energy than objects with larger masses. True or false?
Answer:
False
Explanation:
The greater the size of the mass, the greater the size of the gravitational force/energy.
when the meteorite is halfway to the surface, however, the rope breaks. what is the acceleration of the meteorite as it sinks back to the bottom of the pool?
The acceleration of the meteorite as it sinks back to the bottom of the pool is 8.46 m/s2
sinc we are given the Weight of the meteorite iron which is 1000 N, the Density of meteorite iron which is 7300 kg/m³, the density of water which is 1000 kg/m3, and the Maximum force of 450 N.Since the mass of the meteorite iron, m = W / g =1000/ 9.80 =102.04 kg, and the volume of the meteorite iron, V = 102.04/7300 =1.40×10⁻² m³ .Since The minimum force, the curator has to apply to lift the meteorite from the bottom of the water is the apparent weight of the meteorite in the water. so the minimum force will be :
Fmin=W−Fb =W−Vρ₂g = 1000−1.40×10⁻²×1000×9.8 = 862.8 N
Now since lifting the rope of the crane breaks and the meteorite sinks back into the pool. In such a case, the net downward force acting on the meteorite is the apparent weight of the meteorite. So the acceleration of the meteorite is :
a= W /m = 862.8 N/ 102.04 kg= 8.46 ms⁻²
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The curator of a science museum is transporting a chunk of meteorite iron (i.e., a piece of iron that fell from the sky) from one part of the museum to another. Since the chunk of iron weighs 1000 N and is too big for her to lift by herself, she is using a hand cart. While passing through the marine mammal section of the museum, she accidentally hits a bump, and the meteorite tips off the hand truck and into the dolphin pool. Fortunately, the iron didn't hit the dolphin, but it quickly sinks to the bottom. Unfortunately, the meteorite has many sharp edges and she is worried the dolphins, curious creatures that they are, will come to inspect it and be cut when they rub against it. She wants to get it up out of the pool as quickly as possible. Fortunately, the meteorite has lots of holes in it and there are ropes with hooks on one end lying around. If she could get a hook into one of the holes, she might be able to pull it up to the top. Unfortunately, she remembers that the meteorite is too heavy for her to lift. When the meteorite is halfway to the surface, however, the rope breaks. What is the acceleration of the meteorite as it sinks back to the bottom of the pool?
How can you does units help you to solve a problem?
Answer:
They help by knowing what you are using them for.
Explanation:
i.e: you know you're solving for length if the units are meters
you're solving for time if you are using seconds
etc..
Question 9 of 10: you purchased $100 each of three different stocks in january. stock a increased 30% in value. stock b increased 15% in value. stock c lost 20% of its original value. what was the overall net percentage of gain in the three stocks? (round to the nearest percent.)
The overall net percentage of gain in the three stocks purchased each with $ 100 in which stock a increased 30% in value. stock b increased 15% in value. stock c lost 20% of its original value is 8.3 %
Value of Stock a = 100 + 30%
Value of Stock a = $ 130
Value of stock b = 100 + 15%
Value of stock b = $ 115
Value of stock c = 100 - 20%
Value of stock c = $ 80
Net percentage gain = ( Net profit / Total investment - 1 ) * 100
Net profit = 130 + 115 + 80
Net profit = $ 325
Total investment = 100 + 100 + 100
Total investment = $ 300
Net percentage gain = ( 325 / 300 - 1 ) * 100
Net percentage gain = ( 0.083 ) * 100
Net percentage gain = 8.3 %
Therefore, the the overall net percentage of gain in the three stocks is 8.3 %
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A roller coaster car is cresting a hill at 10 m/s . if the hill has a 30 m radius, what force will the 70 kg rider feel from the seat of the coaster? (the seat force is the normal force)
Answer:
A 53.5-kg rider on a roller coaster car is moving 10.3 m/s at the top of a loop which has a radius of curvature of 7.29 m.
Explanation:
Which of the following objects has gravitational energy? CHOOSE TWO ANSWERS
a book on the edge of a table
a ball sitting on the floor
a falling skydiver
a car driving on a road
A 25.5 kg video cart is rolled down a hallway. It is accelerated at 0.12 m/s2. If a force of 30 N is applied to move the cart, what force of friction do the wheels have against the floor??
A 25.5 kg video cart is rolled down a hallway. It is accelerated at 0.12 m/s2. If a force of 30 N is applied to move the cart . The wheels have 26.4 N force of friction against the floor
Force of friction is that force that resists the sliding or rolling of one solid object over another
F(applied) - friction = F net
30 - fr = mass * acceleration
30 - fr = 25.5 * 0.12
fr = 30 - 3.06
= 26.4 N
The wheels have 26.4 N force of friction against the floor
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A baseball player throws a ball horizontally off a cliff that is 19.8 m tall. The ball lands 29.3 m away from the base of the cliff. What is the horizontal velocity of the ball?
Answer:
v = 58.893 m/s
Explanation:
I assume we are assuming -10 for gravity
Vertically:
Thrown vertically so initial vertical velocity is 0
Δy = vi*t + 0.5*a*t^2
-19.8 = 0*t + 0.5*-9.8*t^2
t^2 = 4.0408
t = 2.01s
Horizontally:
v = d*t
v = 29.3m * 2.01s
v = 58.893 m/s
A horizontal pipe of diameter D = 3.0 cm passes through a reservoir dam at depth d = 5.0 m. A plug secures the pipe opening. The water density is p = 1.0 x103 kg/m3. (a) Find the magnitude of the frictional force between the plug and pipe wall. (b) If the plug is removed, what water volume exits the pipe in 1.0 minute? Ignore water viscosity. (c) If the pipe is h = 10.0 m above the ground, how far will the water travel horizontally from the pipe exit when hitting the ground? Ignore air friction.
Given data
*The given horizontal piper of diameter is D = 3.0 cm = 0.03 m
*The given depth is d = 5.0 m
*The given water desnsity is
[tex]p=1.0\times10^3kg/m^3[/tex](a)
The magnitude of the frictional force between the plug and pipe wall is given as
[tex]\begin{gathered} F=\text{pgd}\times A \\ =\text{pgd}\times\pi r^2 \end{gathered}[/tex]*Here r = d/2 is the radius
Substitute the values in the above expression as
[tex]\begin{gathered} F=(1.0\times10^3)(9.8)(5.0)\times3.14\times(\frac{0.03}{2})^2 \\ =34.61\text{ N} \end{gathered}[/tex](b)
The volume flow rate is calculated as
[tex]\begin{gathered} V=Av \\ =\pi r^2\sqrt[]{2gd} \\ =3.14\times(\frac{0.03}{2})^2\times\sqrt[]{2\times9.8\times5.0} \\ =6.99\times10^{-3} \end{gathered}[/tex]The total volume is calculated as
[tex]\begin{gathered} V_{T_{}}=V\times t \\ =6.99\times10^{-3}\times1.0\times60 \\ =0.4194m^3 \end{gathered}[/tex]what happens when atoms gain, lose, or share electrons
Answer:
They form ions, or charged particles
Explanation:
Some atoms become more stable by gaining or losing an entire electron (or several electrons). When they do so, atoms form ions, or charged particles. Electron gain or loss can give an atom a filled outermost electron shell and make it energetically more stable.
hope it helped please tell me if im wrong.
Molten steel, melted steel, liquid steel, and solid steel are different because of Energy Oxygen Phases Matter ??
The molten steel is the or melted
I need help with this question someone
The properties of group 18 elements, also referred to as noble gases or group 8 elements.
Eight valence electrons make them up.
They have enough electrons in their octet, therefore they don't need any more (stable).
are steady
Noble gases are those that are not reactive.
Why do elements desire to create ions?In order to gain or lose valence electrons to the element they interact with, elements create ions. They acquire a whole octet as a result. You might be wondering what a whole octet is. When an element contains all 8 valence electrons and is stable, it is said to have an octet, rendering it nonreactive.
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A satellite is orbiting Earth at a distance of 42.0 kilometers. The satellite has a mass of 900kilograms. What is the force between the planet and the satellite? Hint: Recall Earth's mass aradius from earlier problems.
Answer:
8716.97 N
Explanation:
The force between the planet and the satellite can be calculated using the following equation
[tex]F=G\frac{m_1m_2}{d^2}[/tex]Where G = 6.67 x 10^(-11) N m²/kg², m1 is the mass of the satellite, m2 is the mass of the Earth and d is the distance from the center of the Earth to the satellite
Since the radius of the Earth is 6,371 km, we get
d = 42 km + 6,371 km = 6413 km
Then, to convert to m, we need to multiply by 1000
d = 6413 km x 1000 m/km = 6.413 x 10^6 m
Finally, replacing m1 = 900 kg, m2 = 5.972 x 10^24 kg, and d = 6.413 x 10^6 m, we get:
[tex]\begin{gathered} F=6.67\times10^{-11}\frac{(900)(5.972\times10^{24})}{(6.413\times10^6)^2} \\ F=8716.97\text{ N} \end{gathered}[/tex]Therefore, the force between the planet and the satellite is 8716.97 N
4) A 200 kg empty cart moves east at 15 m/s. A 50kg rock is dropped straight down into th
moving cart. What is the final speed of the railroad cart?
The final speed of the railroad cart is equal to 12 m/s.
What is law of conservation of linear momentum?According to the law of conservation of momentum, the sum of the momentum before and after the collision of the objects must be equal.
m₁u₁ + m₂u₂ = m₁ v₁ + m₂ v₂
Where m₁ and m₂ are the mass of the objects, u₁ and u₂ are the initial speed while v₁ & v₂ is the final speed.
The momentum of an object is defined as the product of the mass times the velocity of that object.
Given the mass of the empty cart, m₁ = 200 Kg
The mass of the rock, m₂ = 50 Kg
The initial velocity of the empty cart, u₁ = 0
m₁ u₁ + m₂ u₂ = (m₁ + m₂)× V
200 × 15 + 50 × 0= (200 + 50) × V
V = 12 m/s
Therefore, the final speed of the railroad cart is equal to 12 m/s.
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Tariah is riding on her bike at 4m/s (North). If she accelerates at a rate of 1.5 m/s^2 for 2 s, what is her final velocity?
ANSWER:
7 m/s
STEP-BY-STEP EXPLANATION:
Given:
Initial velocity (u) = 4 m/s
Acceleration (a) = 1.5 m/s^2
Time (t) = 2 s
We can calculate the final velocity using the following formula:
[tex]v=u+a\cdot t[/tex]We replace and calculate the value of the final velocity:
[tex]\begin{gathered} v=4+2\cdot1.5 \\ v=4+3 \\ v=7\text{ m/s} \end{gathered}[/tex]The final velocity is equal to 7 m/s.
Please help tonight!!! 50 points! Two objects producing 0.004 N of gravitational force one object had a mass of 3000 kg in another object had a mass of 2600 kg what is the distance between them
Answer:
Explanation:
Given:
m₁ = 3 000 kg
m₂ = 2 500 kg
F = 0.004 N
___________
r - ?
F = G·m₁·m₂ / r²
r = √ (G·m₁·m₂ / F)
r = √ (6.67·10⁻¹¹·3000*2500 / 0.004) ≈ 0.35 m