Answer:
Associative and commutative properties of addition
Explanation:
The one thing that the associative property of addition says that
[tex](a+b)+y=a+b+y[/tex]and the commutative property of addition says
[tex]a+b=b+a[/tex](the order of addition does not matter )
Now, the steps we take to solve our equation are the following:
[tex]\begin{gathered} \mleft(3x+4y\mright)+5x=8x+4y \\ 3x+4y+5x=8x+4y\text{ (the associative property of addition )} \end{gathered}[/tex]The second step is
[tex]\begin{gathered} 3x+4y+5x=8x+4y\text{ } \\ 3x+5x+4y=8x+4y\text{ (commutative property of addition.)} \end{gathered}[/tex]which simplifies to
[tex]\begin{gathered} 8x+4y=8x+4y \\ 4y=4y \end{gathered}[/tex]Hence, we used associative and commutative properties of addition to solve our equation.
Please be clear with the answer thank you bye-bye bye-bye
Solve the system of equations:
3x + 3y = 3
5x + y = 13
Solving the second equation for y:
y = 13 - 5x
Substituting in the first equation:
3x + 3(13 - 5x) = 3
Opeating:
3x + 39 - 15x = 3
Simplifying:
-12x + 39 = 3
Subtracting 39:
-12x = -36
Dividing by -12:
x = -36 / (-12)
x =3
Substituting in the equation for y:
y = 13 - 5(3)
y = -2
Answer: x = 3, y = -2
Answer: x = 3, y = -2
Step-by-step explanation:
e = radians. Identify the terminal point and tan e.O A. Terminal point: (33) tan = 13B. Terminal point: (1, 1); tan 6 = 73(1,1)tan 0 = 2C. Terminal point:; tane3D. Terminal point:
The correct answer is Option D
This following are the steps to take:
Step1: Convert the angle from radians to degrees
[tex]\begin{gathered} 1\pi radians=180^o \\ \text{Thus }\frac{\pi}{6}\text{ radians = }\frac{180^o}{6} \\ \text{ }\frac{\pi}{6}\text{ radians =}30^o \end{gathered}[/tex]Step 2: Draw a unit circle (with a radius of 1 unit), and show the line which forms angle 30 degrees with the x -axis
Step 3: Compute the values of the terminal points:
[tex]\begin{gathered} Th\text{e x-coordinate of the terminal point = 1 }\times cos30^0\text{ = }\frac{\sqrt[]{3}}{2} \\ Th\text{e y-coordinate of the terminal point = 1 }\times\sin 30^0\text{ = }\frac{1}{2} \\ \text{Thus the coordinates of ther terminal point = }(x,y)\text{ = (}\frac{\sqrt[]{3}}{2},\text{ }\frac{1}{2}\text{)} \end{gathered}[/tex]Step 4: Compute the values of the tangent of the angle:
[tex]\begin{gathered} \tan 30^0\text{ = }\frac{y}{x}=\frac{\frac{1}{2}}{\frac{\sqrt[]{3}}{2}}=\frac{1}{\sqrt[]{3}}\text{ } \\ \\ \tan 30^o=\frac{1}{\sqrt[]{3}}\text{ }\times\frac{\sqrt[]{3}}{\sqrt[]{3}}\text{ =}\frac{\sqrt[]{3}}{3} \\ \\ \tan 30^{o\text{ }}=\text{ }\frac{\sqrt[]{3}}{3} \end{gathered}[/tex]I'm terrible at explaining answers and this is one of them...
We see that the sign is a triangle and the area of a triangle is given by the expression:
[tex]A=\frac{1}{2}\text{base}\times height[/tex]base=36
height=32
Then,
[tex]\begin{gathered} A=\frac{1}{2}36\times32 \\ A=\frac{1152}{2}=576\text{ square inches} \end{gathered}[/tex]Hi are you a tutor for the HESI exam for nursing Maria can walk 3 1/2 miles in one hour. At this time how far can Maria walk in 1/2 hour?
Given that Maria can walk 3 1/2 miles in one hour.
[tex]\text{Speed}=3\text{ }\frac{1}{2}\text{ miles per hour}[/tex][tex]\text{Distance =sp}eed\times time[/tex]The distance that Maria can walk in 1/2 hour is
[tex]\text{Distance =3}\frac{1}{2}\times\frac{1}{2}\text{ miles}[/tex]Multiply the 3 1/2 miles by 1/2 to compute the distance covered in 1/2 hour.
[tex]3\frac{1}{2}\times\frac{1}{2}=\frac{3\times2+1}{2}\times\frac{1}{2}[/tex][tex]=\frac{7}{2}\times\frac{1}{2}=\frac{7}{4}[/tex][tex]=1\frac{3}{4}\text{ miles.}[/tex]Maria can walk 1 3/4 miles in 1/ 2 hour.
Select all nat apply.Which steps are involved in multiplying fractions?Multip, the denominators togetherMultiply the numerators togetherCheck to see if the product can be simplifiedFind a common denominatorConvert the problem to a division problem
We want to list the steps involved in multiplying fractions;
Taking an example;
[tex]\frac{2}{3}\times\frac{3}{4}[/tex]First steps are;
- Multiply the numerators together
- Multiply the Denominators together
[tex]\begin{gathered} =\frac{2\times3}{3\times4} \\ =\frac{6}{12} \end{gathered}[/tex]Next is to;
Check to see if the product can be simplified;
[tex]\frac{6}{12}=\frac{1}{2}[/tex]So, we get the product to be;
[tex]\frac{1}{2}[/tex]name a situation when a domain could not have a negative values
The domain of a function is the set of numbers that can be used as an input. For every case when we are dealing with real world objects the domain can't have negative numbers. For example: If a function is modeling the revenue of a parking lot as a function of the number of cars that park there in a month, there is no negative car, therefore we can't have negative values as inputs. The worst case scenario would be a situation where no cars visited the parking lot for the whole month, which would be an input of 0.
12.The graph of y=x + 3 is a vertical translation ofthe graph of y = x + 1, 2 units upward. Examine the intercepts of both linesand state another way that the geometric relationship between the two graphscan be described.
The graph of y=x + 3 is a vertical translation of
the graph of y = x + 1, 2 units upward. Examine the intercepts of both lines
and state another way that the geometric relationship between the two graphs
can be described.
we have
step 1
y=x+3
Find the x-intercepts
Value of x when the value of y is equal to zero
For y=0
0=x+3
solve for x
x=-3
step 2
y=x+1
Find the x-intercepts
Value of x when the value of y is equal to zero
For y=0
0=x+1
x=-1
step 3
The graph of y=x+3 is a horizontal translation 2 units at left of the graph of y=x+1
The rule is
(x,y) -------> (x-2,y)
Use an explicit formula to find the 10th term of the geometric sequence. 2,8, 32, 128, ...
To find the explicit formula of a geometric sequence you use the next:
[tex]a_n=a_1\cdot r^{n-1}[/tex]a1 is the first term in the sequence
r is the ratio between each pair of terms
2,8,32,128,...
Find r:
[tex]\begin{gathered} \frac{8}{2}=4 \\ \\ \frac{32}{8}=4 \\ \\ \frac{128}{32}=4 \end{gathered}[/tex]Find the explicit formula:
[tex]a_n=2\cdot4^{n-1}[/tex]To find the 10th term you substitute the n in the formula for 10:
[tex]\begin{gathered} a_{10}=2\cdot4^{10-1} \\ \\ a_{10}=2\cdot4^9_{}_{} \\ \\ a_{10}=2\cdot262144 \\ \\ a_{10}=524288 \end{gathered}[/tex]Then, the 10th term is 524,288in a 45-45-90 triangle, given the hypotenuse 9√2, find the leg of the triangle
Hypothenuse Z= 9√2
then
Z^2 = X^2 + X^2= 2X^2
(9√2)^2 = 2X^2
then
(9√2)/√2= X
cancel √2, then
9 = X
Then now find perimeter
Perimeter P= Z + X + X = 9√2 + 9 + 9 =
P = 9√2 + 18 = 9•(√2 + 2)
Answer is length of triangle= 9√2 + 18
Leg of triangle X= 9
How many years will it take for an initial investment of $10,000 to grow to $25,000? Assume a rate of interest of 3% compounded daily.
The formula for compounded interest is the following:
[tex]A=P(1+\frac{r}{n})^{nt}[/tex]Where A is the final amount, P is the principal, the initial investment, r is the annual rate of interest, n is how many times it is compounded per year and t is the time in years.
So, assuming the given rate of interest is annual, we have:
[tex]\begin{gathered} A=25000 \\ P=10000 \\ r=3\%=0.03 \\ n=365 \\ t=? \end{gathered}[/tex]Where we got n = 365 because it is compounded daily and there are 365 days in an year.
So let's start by solving for t:
[tex]\begin{gathered} A=P(1+\frac{r}{n})^{nt} \\ \frac{A}{P}=(1+\frac{r}{n})^{nt} \\ \log \frac{A}{P}=\log (1+\frac{r}{n})^{nt} \\ \log \frac{A}{P}=nt\log (1+\frac{r}{n}) \\ \frac{\log\frac{A}{P}}{n\log(1+\frac{r}{n})}=t \\ t=\frac{\log\frac{A}{P}}{n\log(1+\frac{r}{n})} \end{gathered}[/tex]Where the log base can be anyone, but it has to be the sme for both log.
Let's calculate the numerator and denominator separately first, using base 10:
[tex]\log _{}\frac{A}{P}=\log \frac{25000}{10000}=_{}\log 2.5=0.39794\ldots[/tex][tex]\begin{gathered} n\log (1+\frac{r}{n})=365\log (1+\frac{0.03}{365})=365\log (1+0.0000821918\ldots)= \\ =365\log (1.0000821918\ldots)=365\cdot0.000035694\ldots=0.013028\ldots \end{gathered}[/tex]Putting them together, we have:
[tex]t=\frac{\log\frac{A}{P}}{n\log(1+\frac{r}{n})}=\frac{0.39794\ldots}{0.013028\ldots.}=30.54\ldots\approx31[/tex]So, it will take between 30 and 31 years, closer to 31 years for it to grow to $25,000.
Solve 2(x-6)+7x = 5-3(x-2)
To solve x, let's eliminate the parenthesis first by multiplying 2 and -3 to it.
[tex]2x-12+7x=5-3x+6[/tex]Next, let's combine all like terms on either side. We will move -3x to the left side of the equation and -12 to the right side of the equation. Note that when a term crosses the equal symbol, the sign reverses. From -3x to +3x and from -12 to +12.
[tex]2x+7x+3x=5+6+12[/tex]Next, add the terms on both sides.
[tex]12x=23[/tex]Lastly, divide both sides by 12 to isolate x.
[tex]\begin{gathered} \frac{12x}{12}=\frac{23}{12} \\ x=\frac{23}{12} \end{gathered}[/tex]The value of x is 23/12.
Let's check if this is right by substituting the value of x to the equation.
[tex]\begin{gathered} 2(\frac{23}{12}-6)+7(\frac{23}{12})=5-3(\frac{23}{12}-2) \\ 2(-\frac{49}{12})+\frac{161}{12}=5-3(-\frac{1}{12}) \\ -\frac{98}{12}+\frac{161}{12}=5+\frac{3}{12} \\ \frac{63}{12}=\frac{63}{12} \\ \frac{21}{4}=\frac{21}{4} \end{gathered}[/tex]Since we got the same 21/4 on both sides of the equation, our x value 23/12 is correct.
The price-demand and cost functions for the production of microwaves are given as p= 205 - q/70 and C(q) = 18000 + 20q,where q is the number of microwaves that can be sold at a price of p dollars per unit and C(q) is the total cost (in dollars) of producing q units.(A) Find the marginal cost as a function of q.C'(q)= (B) Find the revenue function in terms of q.R(q) =(C) Find the marginal revenue function in terms of q.R'(q)=
(A)
Find the derivative of C(q):
[tex]\begin{gathered} C^{\prime}(q)=0+20(1) \\ C^{\prime}(q)=20 \end{gathered}[/tex](B)
The revenue function is:
[tex]\begin{gathered} R(q)=q\cdot p \\ so: \\ R(q)=q(205-\frac{q}{70}) \\ R(q)=205q-\frac{q^2}{70} \end{gathered}[/tex](C)
The derivative of R(q) is:
[tex]\begin{gathered} R^{\prime}(q)=205(1)-\frac{1}{70}(2q) \\ so: \\ R^{\prime}(q)=205+\frac{q}{35} \end{gathered}[/tex]In the diagram below of circle A. diameter MP = 26. m_GAI = 30° and radiGA and Al are drawn.MАP30°G1if MG IP, find the area of the sector MAG in terms of me and approximateto the nearest hundredth.The area of the sector in terms of u isTTThe area of the sector rounded to the nearest hundredth isunitssquared.
To find the area of a sector of a circle in terms of π having the angle in degrees you use the next formula:
[tex]A=\frac{\theta}{360}\cdot\pi\cdot r^2[/tex]r is the radius
To find area of sector MAG:
1. Find the angle of the sector MAG.
The semicircle has an angle of 180° and it is divided into 3 sectors MAG, GAI, and IAP.
As the arcs MG and IP are congruents (have the same measure) the angles of the sectors MAG and IAP are also congruent.
[tex]\begin{gathered} m\angle\text{MAG}+m\angle\text{GAI}+m\angle\text{IAP}=180 \\ \\ m\angle MAG=m\angle IAP \\ m\angle GAI=30 \\ \\ 2m\angle MAG+m\angle GAI=180 \\ 2m\angle MAG+30=180 \end{gathered}[/tex]Use the equation above to find the measure of angle MAG:
[tex]\begin{gathered} 2m\angle MAG=180-30_{} \\ 2m\angle MAG=150 \\ m\angle MAG=\frac{150}{2} \\ \\ m\angle MAG=75 \end{gathered}[/tex]2. Find the area of sector MAG:
Angle 75°
radius= half of the diameter (26/2 = 13)
r=13
[tex]\begin{gathered} A=\frac{75}{360}\cdot\pi\cdot(13)^2 \\ \\ A=\frac{75}{360}\cdot\pi\cdot169 \\ \\ A=\frac{12675}{360}\pi \\ \\ A=\frac{845}{24}\pi \\ \\ A\approx35.21\pi \\ \\ A\approx110.61 \end{gathered}[/tex]The exact area of the sector MAG is 845/24 π units squared.
Rounded to the nearest hundredth 35.21 π units squared or 110.61 units squared
insert the values given in the problem then scale up or down to find the missing value
Given the statements in the image, 2% of the fans implies that 2/100 of the fans in attendance equals to 120 teenagers. i.e,
[tex]\frac{2}{100}\text{ of fans }=120[/tex]Let the total number of fans equal to x. We have the following ratio:
[tex]\frac{2}{100}=\frac{120}{x}[/tex]To get x by scaling up our ratios, we multiply both numerator and denominator by a common factor of 60 to have:
It can be seen that:
[tex]\begin{gathered} 2\times60=120 \\ 100\times60=x \\ 6000=x \\ x=6000 \end{gathered}[/tex]Hence, the total number of people at the stadium is 6000.
If Erik checks his pulse for 8 minutes, what is his rate if he counts 600 beats? beats per minute.
Given
Time taken by Erik to check his pulse = 8minutes
Count = 600 beats
To get his rate in beats per minute, you will use the formula:
Beat rate = Count (in beat)/Time taken (in minutes)
Sustitute the given paremeters into the formula given as shown:
Beat rate = 600beats/8minutes
Beat rate = 75beats per minutes
Hence his rate is 75 beats per minute.
form
is the point (1,3) a solution to the linear equation 5x - 9y = 32?
We are given the following equation:
[tex]5x-9y=32[/tex]To determine if the point (1, 3) is a solution to this equation we will replace the given values since the point (1, 3) means that when x = 1, y = 3. Replacing in the equation:
[tex]5(1)-9(3)=32[/tex]Solving the operation we should get the same value on both sides of the equation:
[tex]\begin{gathered} 5-27=32 \\ -22\ne32 \end{gathered}[/tex]Since both sides are different this means that the point (1, 3) is not a solution to the equation.
Answer:
89
Step-by-step explanation:
Data with a correlation coefficient of 0.05 has a _[blank A]_ correlation, and data with a correlation coefficient of −0.80 has a _[blank B]_ correlation.Which answers provide the words that fill in the blanks in the previous sentence, in the correct order, to make it a true statement?Select two answers. Select one answer for the blank labeled "A," and select one answer for the blank labeled "B."
We have two correlations:
1) One with r = 0.05.
2) Another with r = -0.80.
The absolute value of r tells us how strong or weak is the correlation: strong correlation have values of |r| closer to 1, while weak correlations have values of |r| closer to 0.
The sign of r tells us if the correlation is positive or negative, independently of how strong it is.
Then, for a correlation with r = 0.05 we can conclude that it is a weak positive correlation.
For a correlation r = -0.80 we can conclude that it is a strong negative correlation.
Answer:
The correct options are
B: strong negative [second option]
A: weak positive [seventh option]
Kellen earned $52.92 for waitressing at a burger restaurant on Friday night.if she waitressed for 4.5 hours,on average how much did she earn per hour?
Given data:
The amount Kellen earned in 4.5 hours is $52.92.
The expression for the given statement is,
[tex]\begin{gathered} 4.5\text{ hours=\$52.92} \\ 1\text{ hour= \$11.76} \end{gathered}[/tex]Thus, Kellen earned $11.76 per hour.
The rectangular rug has side lengths of 3 and 4 ft. What is the length of the diagonal? Draw a picture of the problem and solve. Round to the nearest tenth
ANSWER
The length of the diagonal is 5 ft
EXPLANATION
The diagram of the rug with the diagonal is:
The diagonal and the sides form a right triangle, so we can use the Pythagorean theorem to find x, the length of the diagonal:
[tex]\begin{gathered} x^2=3^2+4^2 \\ x=\sqrt[]{9+16} \\ x=\sqrt[]{25} \\ x=5 \end{gathered}[/tex]Construct a circle through pointsX, Y, and Z.
When you need to construct a circle, the major factor to consider is the radius.
The radius is the same distance from any point around the circumference of the circle to the centre. Since the radius is not given, you however need to look for clues.
You start by joining the points to arrive at two lines, for example, join points X and Y and then join points Y and Z.
Next you bisect each of the two lines one after the other (bisect along the perpendicular)
You will observe that both perpendicular bisectors would touch at a point. That point where they touch or "cross each other" is the center of your circle.
Next you place the sharp tip of your compass on the center of your circle, adjust its distance to the pencil end (that is your radius) and as soon as it touches one of the three points, you draw your circle.
What is the volume of the cone when the radius is 10 and the height is 18
The volume of the cone is given by the formula:
The perpendicular bisectors of triangle ABC intersect at point G and are shown in blue. Find BG
Answer:
9
Explanation:
A perpendicular bisector of a triangle is a line that is perpendicular to the side and passes through the midpoint of the triangle.
So when three perpendicular bisectors of the sides of a triangle meet at a point in a triangle, that point is called a circumcenter.
From the circumcenter theorem, we know that the circumcenter is equidistant from the vertices of a triangle, that is, the circumcenter is the same distance from each of the vertices of the triangle.
Looking at the given triangle, we can see that G is the circumcenter of the triangle because all the perpendicular bisectors DG, EG, and FG meet at this point.
We can see that AG is 9 which is the distance from vertex A to the circumcenter, G, since the circumcenter is equidistant from the vertices of a triangle according to the circumcenter theorem, therefore, BG will also be 9.
Simplify: 2x^2 + 19x + 35/2x^2 +11x +15 a) 7/3b) 19x + 35/11x + 15c) 2x + 7/2x + 3d) x + 7/x + 3
SOLUTION
We want to simplify
[tex]\frac{2x^2+19x+35}{2x^2+11x+15\text{ }}[/tex]Factorising the numerator and denominator, we have
[tex]\begin{gathered} \frac{2x^2+19x+35}{2x^2+11x+15\text{ }} \\ \frac{2x^2+14x+5x+35}{2x^2+6x+5x+15\text{ }} \\ \frac{2x(x+7)+5(x+7)}{2x(x+3)+5(x+3)} \\ \frac{(2x+5)(x+7)}{(2x+5)(x+3)} \end{gathered}[/tex]Canceling out the common factor which is
[tex]2x+5[/tex]We have our answer as
[tex]\frac{x+7}{x+3}[/tex]Hence the answer is option D
O 9,976 15) An air-conditioning fan makes 125 revolutions per second. How many revolutions will it make if it runs for 30 minutes?
An air-conditioning fan makes 125 revolutions per second. How many revolutions will it make if it runs for 30 minutes?
we know that
1 min=60 sec
we have
125 rev/sec
so
1 sec=1/60 min
substitute
125 rev/sec=125/ (1/60)=7,500 rev/min
Multiply by 30 min
7,500*30=225,000 rev
therefore
the answer is225,000 revolutionsA movie with an aspect ratio of 1.25:1 is shown as a pillarboxed image on a 36-inch 4:3 television. Calculate the Areas of the TV, the Image and One Blackbar
Explanation
The television has a diagonal that measures 36 inches:
And the ratio is 4:3
[tex]\begin{gathered} \frac{w}{h}=\frac{4}{3} \\ w=\frac{4}{3}h \end{gathered}[/tex]We can use the Pythagorean theorem to find the height of the TV:
[tex]\begin{gathered} 36^2=h^2+w^2 \\ 36^2=h^2+(\frac{4}{3}h)^2 \\ 36^2=h^2(1+\frac{4^2}{3^{2}}) \\ 1296=h^2(1+\frac{16}{9}) \\ 1296=h^2\times\frac{25}{9} \\ h^2=1296\times\frac{9}{25} \\ h=\sqrt[]{1296\times\frac{9}{25}}=21.6 \end{gathered}[/tex]The height of the TV is 60 inches. It's width is:
[tex]w=\frac{4}{3}h=\frac{4}{3}\times21.6=28.8[/tex]w=80 inches
Therefore the area of the TV is
[tex]A_{TV}=w\times h=28.8\times21.6=622.08in^2[/tex]The move has an aspec ratio of 25:1 shown as a pillarboxed image. This means that this is what we see:
So we know that the image height is the same as the TV's, 21.6 inches.
The relation between it's height and it's width is:
[tex]\begin{gathered} \frac{w}{h}=\frac{1.25}{1} \\ w=1.25h \\ \text{if h = 21.6 in} \\ w=27in \end{gathered}[/tex]The area of the image is:
[tex]A_{\text{image}}=w_{\text{image}}\times h=27\times21.6=583.2[/tex]The area of the two blackbars is the difference between the area of the TV and the area of the image:
[tex]A_{2-blackbars}=A_{TV}-A_{image}=622.08-583.2=38.88in^{2}[/tex]Since we need to find the area of just one blackbar, we just have to divide the area of both blackbars by 2:
[tex]A_{1-blackbar}=\frac{A_{2-blackbars}}{2}=\frac{38.88}{2}=19.44in^{2}[/tex]Answer
• Area of the TV: ,622.08 in²
,• Area of the image: ,583.2 in²
,• Area of one blackbar: ,19.44 in²
12 1 point Which trig function should Sharlot use to find the measure of angle A ? C 1 B cosine 3 tangent 4 pythagorean theorem sine 6
using trigonometric ratio
[tex]\begin{gathered} \cos A=\frac{adjacent}{\text{hypotenuse}} \\ \cos A=\frac{5}{12} \end{gathered}[/tex]We have to use cosine to find angle A
D. 62B. 1811. Madison bought a sweater and a pair of jeans at the mall for $47. Thesweater cost $7 less than twice the cost of the jeans. How much did thesweater cost?c. $20A $29D. $13B. $27
Answer:
$29
Step-by-step explanation:
If I have 2 and a 1/2 bags of mortar
or every 100 cement blocks how many bags of water Mason needed for 350 blocks
The number of bags for 350 blocks is 8.75 bags
How to determine the number of bags for 350 blocks?From the question, we have the following parameters that can be used in our computation:
Bags of mortal = 2 and a 1/2 bags
Number of cements blocks = 100 blocks
The above parameters can be represented using the following ratio
Ratio = Bags of mortal : Number of cements blocks
Substitute the known values in the above equation, so, we have the following representation
Bags of mortal : Number of cements blocks = 2 and a 1/2 bags : 100 blocks
When the number of blocks is 350, we have the following equation
Bags of mortal : 350 = 2 and a 1/2 bags : 100 blocks
Express the ratio as fraction
Bags of mortal/350 = 2.5/100
Multiply both sides by 350
Bags of mortal = 350 * 2.5/100
Evaluate the products
Bags of mortal = 8.75
Hence, the number of bags is 8.75
Read more about ratio at
https://brainly.com/question/2328454
#SPJ1
The product of the polynomials (2ab + b) and (a^2 - b^2) is 2(a^3b)-2a(b^3) + (a^2)b - b^3.If this product is multiplied by (2a + b), the result is a polynomial with_____ terms.
Ok, so
We know that the product of the polynomials (2ab + b) and (a^2 - b^2) is 2(a^3b)-2a(b^3) + (a^2)b - b^3.
Now, we have to multiply the last result per (2a+b)
If me multiply term by term, we get a new polynomial that will has 8 terms.
That's because we have four different terms and we're multiplying each term by 2 different ones. So, there's 8.
hello. I need help with solving log6 129 on a calculator.
With the aid of a scientific calculator (most smart phones are equipped with one), you need to look out for the "LOG" button.
The button usually has the inscription shown as;
[tex]\text{Log}_{10}[/tex]Press the Second Function button and this key changes to;
[tex]\text{Log}_y[/tex]This second function button means,
"The log of x base y".
In this case it means, you take the log of 129, base 6.
The steps are;
[tex]\begin{gathered} (1)\text{Press 129} \\ (2)\text{Press Second Function button} \\ (3)\text{Press 6} \\ (4)\text{Press the "equal to" button} \end{gathered}[/tex]