Answer: x=0.75
Step-by-step explanation:
What is the area of a circle with a circumference
of 25.12 meters?
Area of a circle=πr^2
circumference of a circle= 2πr
circumference of a circle=25.12
2πr=25.12
r=25.12÷2π=4
radius=4
Are of circle= πr^2=π4^2=50.28cm^2
Consider the cylinder with a volume of 132 cm3.
What is the volume of a cone with the same radius and
height as the cylinder?
O 337 cm
O 447 cm
O 66 cm
O 132 cm
3
V = 132 cm
HELPPP
Answer:
447 cm or 337 cm can be both
The volume of the cone whose height and radius are equal to that of given cylinder`s height and radius is equal to 44cm³.
The volume of given cylinder is = 132cm³
The volume of a cylinder of radius r and height h is given by
V=πr²h
Therefore, πr²h=132
Now volume of cone of same radius and height is = (1/3)πr²h
=(1/3)×132
=44cm³
Hence, the volume of the cone with same radius and height as of given cylinder is 44cm³.
To learn more about cylinder click here:
https://brainly.com/question/21999117
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please help me with this math wuestion
Answer:
A) 3 1/4
Step-by-step explanation:
x+1/2 = 3 3/4
x = 3 3/4 - 2/4 = 3 1/4
Someone help please
Answer:
x = 30
Step-by-step explanation:
To compare the dry braking distances from 30 to 0 miles per hour for two makes of automobiles, a safety engineer conducts braking tests for 35models of Make A and 35 models of Make B. The mean braking distance for Make A is 41feet. Assume the population standard deviation is 4.6 feet.The mean braking distance for Make B is 45feet. Assume the population standard deviation is 4.3 feet.At alphaequals0.10,can the engineer support the claim that the mean braking distances are different for the two makes of automobiles
Answer:
There is sufficient evidence to support the claim.
Step-by-step explanation:
Given
[tex]\alpha = 0.10[/tex]
Make A
[tex]\bar x_1 = 41[/tex]
[tex]\sigma_1= 4.6[/tex]
[tex]n = 35[/tex]
Make B
[tex]\bar x_2 = 45[/tex]
[tex]\sigma_2 = 4.3[/tex]
[tex]n = 35[/tex]
First, we state the null and alternate hypothesis
[tex]H_0 : \mu_1 = \mu_2[/tex]
[tex]H_1 : \mu_1 \ne \mu_2[/tex]
Next, calculate test statistic:
[tex]z = \frac{(\bar x_1 - \bar x_2)-(\mu_1 - \mu_2)}{\sqrt{\frac{\sigma_1^2}{n_1}+\frac{\sigma_2^2}{n_2}}}[/tex]
[tex]z = \frac{(41- 45)-0}{\sqrt{\frac{4.6^2}{35}+\frac{4.3^2}{35}}}[/tex]
[tex]z = \frac{-4}{\sqrt{0.6046+0.5283}}[/tex]
[tex]z = \frac{-4}{\sqrt{1.1329}}[/tex]
[tex]z = \frac{-4}{1.0643}[/tex]
[tex]z = -3.7583[/tex]
The critical value at [tex]\alpha = 0.10[/tex] is: [tex]\±1.282[/tex]
[tex]-3.7583 < -1.282[/tex]
So, we reject [tex]H_0[/tex]
This implies that; there is sufficient evidence to support the claim.
I need help with this question
Answer:
No idea for this question
Mr. Smith’s factory produces 58 brake pads per hour with the current machines. He has decided to invest in new machines that produce 86 brake pads per hour. By what approximate percent will the new machines increase the production of brake pads at the factory?
Answer:
48%
Step-by-step explanation:
Can someone plz help me with my whole homework?
1.The original price is $20. The Percent of Discount is 20%. What is the sale price?
2.The original price is $95. The Percent of Discount is 35%. What is the sale price?
3.The Percent of Discount is 75%. The sale price is $55.50. What is the original price?
4.The Percent of Discount is 40%. The sale price is $78. What is the original price?
5.Find the selling price. The cost to store: $20. The markup: 15%.
6.Find the selling price. The cost to store: $56. The markup: 80%.
7.Find the selling price. The cost to store: $110. The markup: 140%.
8.A store buys an item for $10. To earn a profit of $25, what percent does the store need to markup the item?
9.An account earns simple interest. Find the interest earned.
$400 at 7% for 3 years
10.An account earns simple interest. Find the balance of the account.
$400 at 7% for 3 years
11.An account earns simple interest. Find the interest earned.
$1200 at 5.6% for 4 years
12.An account earns simple interest. Find the balance of the account.
$1200 at 5.6% for 4 years
13.Find the annual interest rate.
I = $18, P = $200, t = 18 months
14.Find the annual interest rate.
I = $310, P = $1000, t = 5 years
15.Find the amount of time.
I = $60, P = $750, r = 4%
16.Find the amount of time.
I = $825, P = $72500, r = 5.5%
17.You put $500 in a savings account. The account earns $15.75 simple interest in 6 months. What is the annual interest rate?
Answer:
Step-by-step explanation:
Answer:
people may not be doing it because u have it up for 5 points and it is alot of work.
Step-by-step explanation:
1
2
3
Or
4?
Look at the picture.
Thank u!
Answer:
Option 1
Step-by-step explanation:
Answer:
1
Step-by-step explanation:
0.08= 8/10. so it would be simple multiplication using fractions. 2/3x8/10 giving us 16/30= 8/15. sorry got wrong answer at first.
-4x=16 what is x in the equation
Answer: x=-4
Step-by-step explanation:
-4x=16
Divide by -4 on each side to cancel it out
x=-4
Can y’all help me on question nine?!
Answer:
24
Step-by-step explanation:
x=2
x³+7x+2
2³+14+2
8+14+2
24
Which trigonometric ratios are correct for triangle
ABC? Select three options.
Answer:
Options (1), (3) and (4)
Step-by-step explanation:
From ΔABC given in the picture,
By Pythagoras theorem
Hypotenuse² = (Leg 1)² + (Leg 2)²
BC² = AB² + AC²
(18)² = 9² + AC²
AC = [tex]\sqrt{324-81}[/tex]
AC = [tex]9\sqrt{3}[/tex] cm
sin(C) = [tex]\frac{\text{Opposite side}}{\text{Hypotenuse}}[/tex]
= [tex]\frac{AB}{BC}[/tex]
= [tex]\frac{9\sqrt{3}}{18}[/tex]
sin(C) = [tex]\frac{\sqrt{3} }{2}[/tex]
sin(B) = [tex]\frac{AC}{BC}[/tex]
= [tex]\frac{9}{18}[/tex]
= [tex]\frac{1}{2}[/tex]
cos(B) = [tex]\frac{\text{Adjacent side}}{\text{Hypotenuse}}[/tex]
= [tex]\frac{9\sqrt{3}}{18}[/tex]
= [tex]\frac{\sqrt{3} }{2}[/tex]
tan(B) = [tex]\frac{\text{Opposite side}}{\text{Adjacent side}}[/tex]
= [tex]\frac{AC}{AB}[/tex]
= [tex]\frac{9}{9\sqrt{3} }[/tex]
= [tex]\frac{1}{\sqrt{3} }[/tex]
tan(C) = [tex]\frac{AB}{AC}[/tex]
= [tex]\frac{9\sqrt{3}}{9}[/tex]
= [tex]\sqrt{3}[/tex]
Therefore, Options (1), (3) and (4) are the correct options.
Answer:
Options (1), (3) and (4)
Step-by-step explanation:
From ΔABC given in the picture,
By Pythagoras theorem
Hypotenuse² = (Leg 1)² + (Leg 2)²
BC² = AB² + AC²
(18)² = 9² + AC²
AC =
AC = cm
sin(C) =
=
=
sin(C) =
sin(B) =
=
=
cos(B) =
=
=
tan(B) =
=
=
=
tan(C) =
=
=
Therefore, Options (1), (3) and (4) are the correct options.Step-by-step explanation:
Find the perimeter of the polygon.
a. 25 cm
b. 20 cm
C. 30 cm
d. 28 cm
25 hope that helps you out
Solve for h
h – 5 = -30
Make sure to show your work for full points!
Answer:
h = -25
Step-by-step explanation:
h - 5 = - 30
+5 +5
h = -25
Sina Au,Jho at Tess ay anak ng mag asawang sing ng
Roy at Aling Lita, Si Ay ay 7 taon na mas matanda kay the
at 2 taon mas bata kay Tess, Kung ang kabuyang edad ay
70. llan taon si Au?
Answer: Sina Au,Jho at Tess ay anak ng mag asawang sing ng
Roy at Aling Lita, Si Ay ay 7 taon na mas matanda kay the
at 2 taon mas bata kay Tess, Kung ang kabuyang edad ay
70. llan taon si Au?
Step-by-step explanation:
Evaluate the expression for the given value of the variable.
4 * (x + 5); when x = 3 the star means multiply
Answer:
4 * (3 + 5)
4 * 8
32
Step-by-step explanation:
What is the measure of angle x?
Answer:
43
Step-by-step explanation:
90-47=43
why is angle 3 congruent to angle 7?
Answer:
they are congruent because they are corresponding angles
Step-by-step explanation:
Lee el siguiente planteamiento y resuelve los problemas:
Un globo electrostáticamente cargado ejerce una fuerza de atracción sobre un papel de tal forma que se pueden identificar dos cargas positivas en la periferia del globo y una negativa en la periferia del papel. Las cargas del globo y del papel están colocadas en los vértices de un triángulo equilátero cuyos lados tienen una longitud de 5 cm, tal como se muestra en la figura. Se sabe que la carga q1 tiene polaridad negativa con un valor de 20 μC (microcoulomb), la carga q2 tiene polaridad positiva con una magnitud de 10 μC y la carga q3 también tiene polaridad positiva con una intensidad de 30 μC.
Calcula la fuerza de q3 sobre q1. Para ello, hay que sustituir los valores de las respectivas cargas en la ecuación de la ley de Coulomb y el valor de la distancia d , la cual corresponde a la separación entre q1 y q3.
Realiza el cálculo de la fuerza de q2 sobre q1.
a. Utiliza el plano cartesiano para graficar los resultados de las fuerzas solicitadas.
Determina la magnitud de la fuerza de atracción resultante que ejercen las cargas q2 y q3 sobre q1 y el ángulo del vector de la resultante.
a. Utiliza el plano cartesiano para graficar el resultado, de la magnitud de la fuerza de atracción.
Answer:
I am read well any things please I don't know how to run this app please helpe I don't need this app by saying this much i want to stop my points
thanks
Need Help ASAP WILL MARK YOU BRAINLYEST
he divided by 2 instead of taking the square root so the actual answer should be 26 and for the second the 20 is across from the 90 so its suppose to be c
the answer should be 16
What is the area of this figure?
Question 10 options:
124 in2
112 in2
184 in2
Answer:
112 in2
Step-by-step explanation:
6 x 4 / 2 + 10 x 10 = 24 / 2 + 100
12 + 100 = 112 in2
Hope that helps!
what is the square root of -20
Answer:
4.47213595
Simplify in the tenths place and get 4.47
Step-by-step explanation:
Please I need help it’s an emergency
Answer:
i think its b
Step-by-step explanation:
i might be wrong but i think its
[tex]4 \sqrt{3 } [/tex]
Find X using these two
24x-19
16x+13
Step-by-step explanation:
24x-19=0
24x=19
x=19/24
16x+13=0
16x=-13
x=-13/16
why is angle 3 congruent to angle
explain why
Answer:
Angle 3 is = to angle 2 because:
Angle 3 & angle 7 are corresponding angles, meaning they have the same measure.
Angle 7 & angle 2 are vertical angles, meaning they also have the same measure.
Therefore, if angle 7 is equal to angle 3, then angle 2 must also be equal to angle 3.
Hope this helps! Have a great day!
Can somebody help me?
Answer:smsjsjsjsjsjss
Step-by-step explanation:idididididisjsnsbuxxjhx
Ssjsjsjsjjssjsjmsjsjsjs
Through: (1,-4) and (-3,1)
Answer:
of a slope?
Step-by-step explanation:
PLEASE HELP!!!!!! ILL GIVE BRAINLIEST *EXTRA 40 POINTS** !! DONT SKIP :((
Answer:
Yes
Step-by-step explanation:
Substitute 2+1=3
3=3
Equal means solution
Answer:
Yes (2,3) is a solution to this system of equations
Step-by-step explanation:
(x,y) (2,3) so x=2 y=3
3=3
3=2+1
Equations are true so it's a solution
A large operator of timeshare complexes requires anyone interested in making a purchase to first visit the site of interest. Historical data indicates that 20% of all potential purchasers select a day visit, 50% choose a one-night visit, and 30% opt for a two-night visit. In addition, 10% of day visitors ultimately make a purchase, 30% of onenight visitors buy a unit, and 20% of those visiting for two nights decide to buy. Suppose a visitor is randomly selected and is found to have made a purchase. How likely is it that this person made a day visit? A one-night visit? A two-night visit?
Answer:
0.087 = 8.7% probability that this person made a day visit.
0.652 = 65.2% probability that this person made a one-night visit.
0.261 = 26.1% probability that this person made a two-night visit.
Step-by-step explanation:
Conditional Probability
We use the conditional probability formula to solve this question. It is
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]
In which
P(B|A) is the probability of event B happening, given that A happened.
[tex]P(A \cap B)[/tex] is the probability of both A and B happening.
P(A) is the probability of A happening.
In this question:
Event A: Made a purchase.
Probability of making a purchase:
10% of 20%(day visit)
30% of 50%(one night)
20% of 30%(two night).
So
[tex]p = 0.1*0.2 + 0.3*0.5 + 0.2*0.3 = 0.23[/tex]
How likely is it that this person made a day visit?
Here event B is a day visit.
10% of 20% is the percentage of purchases and day visit. So
[tex]P(A \cap B) = 0.1*0.2 = 0.02[/tex]
So
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.02}{0.23} = 0.087[/tex]
0.087 = 8.7% probability that this person made a day visit.
A one-night visit?
Event B is a one night visit.
The percentage of both(one night visit and purchase) is 30% of 50%. So
[tex]P(A \cap B) = 0.3*0.5 = 0.15[/tex]
So
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.15}{0.23} = 0.652[/tex]
0.652 = 65.2% probability that this person made a one-night visit.
A two-night visit?
Event B is a two night visit.
The percentage of both(two night visit and purchase) is 20% of 30%. So
[tex]P(A \cap B) = 0.2*0.3 = 0.06[/tex]
Then
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.06}{0.23} = 0.261[/tex]
0.261 = 26.1% probability that this person made a two-night visit.
which is the least -1 1/4 or -3/2
Answer:
-3/2
Step-by-step explanation: