Which of the following describes the graph of h(x)= -2^(x+3)-4. Thanks for the help!

Which Of The Following Describes The Graph Of H(x)= -2^(x+3)-4. Thanks For The Help!
Which Of The Following Describes The Graph Of H(x)= -2^(x+3)-4. Thanks For The Help!

Answers

Answer 1

SOLUTION:

Case: Graphs

Method:

The equation:

[tex]h(x)=-2^{(x+3)}-4[/tex]

We will plug in several values of x

(-3, ?), (0, ?)

[tex]\begin{gathered} (-5,?) \\ h(-3)=-2^{(-3+3)}-4 \\ h(-3)=-2^0-4 \\ h(-3)=-1-4 \\ h(-3)=-5 \\ (-3,-5) \end{gathered}[/tex]

And

[tex]\begin{gathered} (0,?) \\ h(0)=-2^{(0+3)}-4 \\ h(0)=-2^3-4 \\ h(0)=-8-4 \\ h(0)=-12 \\ (0,-12) \end{gathered}[/tex]

Final answer: 3rd Option

The graph:

Which Of The Following Describes The Graph Of H(x)= -2^(x+3)-4. Thanks For The Help!

Related Questions

Solve the equation for a: z = ma – b

Answers

From the given question

There are given that the equation:

[tex]z=ma-b[/tex]

Now,

For finding the value of a, first, add b in both sides of the equation

So,

[tex]\begin{gathered} z=ma-b \\ z+b=ma-b+b \\ z+b=ma \end{gathered}[/tex]

Then,

Divide by m on both sides the above equation

[tex]\begin{gathered} z+b=ma \\ \frac{z+b}{m}=\frac{ma}{m} \\ a=z+b \end{gathered}[/tex]

Hence, the value of a is z + b.

Use the graph of the function to estimate the interval on which the function is decreasing.Enter your answer in interval notation.Enter any values to one decimal place.

Answers

The Solution:

Given:

Required:

To determine the interval in which the function is decreasing.

From the given graph, the interval in which the function is decreasing is:

[tex](-2.5,1)[/tex]

Therefore, the correct answer is (-2.5, 1)

Which of the following functions best models the data shown in the scatterplot below? y=3x+5y=x2+10y=x+8y=2x+

Answers

Given:

a graph is given

Required:

To simplify which option is correct

Explanation:

From the graph we know the model should be line. And it passes through (15,60)

if the model is y=x+8 , y =15+8=23

there is too much difference between 23 and 60, so y=x+8 is wrong

and y=3x+5 is right

Required answer:

y=3x+5

a card is from a standard deck of cards is chosen at random, then a coin is tossed. what is the probability of getting ace and tails!?

Answers

A standard deck of cards consists of 52 cards with 4 aces.

The probability of getting an ace in a pack of the standard deck is;

[tex]P_1=\frac{4}{52}=\frac{1}{13}[/tex]

Find the inverse of the function. Is the inverse a function? Simplify your answer.F(x)=2x-1f^-1(x)=

Answers

The definition of the inverse function is

[tex]\begin{gathered} f(f^{-1}(x))=x \\ \text{and} \\ f^{-1}(f(y))=y \end{gathered}[/tex]

In our case,

[tex]f(x)=2x-1[/tex]

Then,

[tex]\begin{gathered} f^{-1}(f(x))=x \\ \Rightarrow f^{-1}(2x-1)=x \\ \Rightarrow f^{-1}(x)=\frac{x+1}{2} \end{gathered}[/tex]

We need to verify this result using the other equality as shown below

[tex]\begin{gathered} f^{-1}(x)=\frac{x+1}{2} \\ \Rightarrow f(f^{-1}(x))=f(\frac{x+1}{2})=2(\frac{x+1}{2})-1=x+1-1=x \\ \Rightarrow f(f^{-1}(x))=x \end{gathered}[/tex]

Therefore,

[tex]\Rightarrow f^{-1}(x)=\frac{x+1}{2}[/tex]

The inverse function is f^-1(x)=(x+1)/2.

We say that a relation is a function if, for x in the domain of f, there is only one value of f(x).

In our case, notice that for any value of x, there is only one value of (x+1)/2=x/2+1/2.

The function is indeed a function, it is a straight line on the plane that is not parallel to the y-axis.

The inverse f^-1(x) is indeed a function

Which of the following polynomial has roots at 3, -4, and a double root at-2?

Answers

The second polynomial [tex]f(x) = (x - 3)(x+4)(x+2)^2[/tex]  has roots 3, -4 and a double root at -2.

What is root of polynomial?

The values of a variable for which the provided polynomial equals zero are referred to as a polynomial's roots. P(a) = 0 if an is the polynomial's root for x.

Since, if x is a root of the polynomial then x is a zero of the polynomial.

That means f(x) = 0

Consider, the first polynomial, [tex]f(x) = (x+3)(x-4)(x-2)^2[/tex]

plug x = 3,  [tex]f(3) = (9)(-1)(1)^2 = -9[/tex] ≠ 0

Plug x = -4, [tex]f(-4) = (-1)(-8)(36) = 368[/tex] ≠ 0

Plug x = -2, [tex]f(-2) = (1)(-6)(16) = -96[/tex] ≠ 0

Therefore, 3, -4 and -2 are not the roots of the first polynomial.

Now consider the second polynomial,  [tex]f(x) = (x-3)(x+4)(x+2)^2[/tex]

Plug x = 3,  [tex]f(3) = 0[/tex]

Plug x = -4, [tex]f(-4) = 0[/tex]

Plug x = -2, [tex]f(-2) = 0[/tex]

Therefore, x = 3, -4, -2 are the roots of the second polynomial.

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(4+3i)-(2-i)Simplify, leave in a+bi form

Answers

The given expression is

(4 + 3i) - (2 - i)

We would simplify the terms inside the parentheses. The negative sign(- 1) outside the second parentheses would be used to multiply each term inside. We have

4 + 3i + - 1 * 2 + - 1 * - i

4 + 3i - 2 + i

By collecting like terms, we have

4 - 2 + 3i + i

2 + 4i

Thus, the answer in a + bi form is

2 + 4i

Due 05/05/200:00Tickets to a school play cost $3 for students and $8 for adults. On opening night, $1,000 was collected and 150 tickets sold Use substitution to solvea system of equations to find how many of each kind of ticket were sold? Enter your answers in the boxesstudent ticketsadult tickets

Answers

We will use the next variables

x is the number of tickets sold for students

y is the number of tickets sold for adults

First equation

x+y=150

Second equation

3x+8y=1000

we isolate the x of the first equation

x=150-y

we substitute the equation above in the second equation

3(150-y)+8y=1000

450-3y+8y=1000

we sum like terms

5y=1000-450

5y=550

y=550/5

y=110

Then we substitute the value of y in the equation with x isolate

x=150-y=150-110=40

x=40 and y=110

The students sold

40 tickets for students

110 tickets for adults

Hi so sorry i need help in geometry i think its asking if the two given angles are coterminal or not

Answers

Given these two angles:

[tex]\frac{5\pi}{4}[/tex][tex]-\frac{3\pi}{4}[/tex]

You need to remember that, by definition, two angles are coterminal if the Difference (the result obtained by subtracting them) is:

[tex]360\text{\degree or }2\pi[/tex]

Then, you need to set up:

[tex]\frac{5\pi}{4}-(-\frac{3\pi}{4})[/tex]

Solving the Subtraction, you get:

[tex]=\frac{5\pi}{4}+\frac{3\pi}{4}[/tex][tex]=\frac{8\pi}{4}[/tex][tex]=2\pi[/tex]

Hence, the answer is: They are Coterminal Angles.

8.9.Find the slopes of the lines that are (a) parallel and (b) perpendicular to the line through the pairof points.(3, 3) and (-5, -5)OA-3335B 0; 0C 1; -1OD -1; 1Determine whether the lines are parallel, perpendicular, skew, or neither.

Answers

We know that the equation of the line that pass through the pair of points (3, 3) and (-5, -5) is x = y, so the slope of a paralell line is 1 and a perpendicular line is -1.

So the answe is C. 1, -1.

Write in point slope and convert to slope intercept form: a line with a slope -5 that goes through the point (1.-7)

Answers

Weare asked to use the "point-slope" form of a line that has slope -5 and goes though the point (1, -7) on the plane.

Therefore we use the form:

y - yp = m (x - xp)

where "m" is the slope, and xp and yp are the coordinates of the point on the plane the line goes through. So in our case we have:

y - (-7) = -5 (x - 1)

now we proceed to remove parenthesis using distributive property:

y + 7 = -5 x + 5

and finally express the equation in slope-intercept form by isolating "y" on the left:

Subtract 7 from both sides and combine:

y = -5 x + 5 - 7

y = -5 x - 2

Heather invested $19,400 in a growth fund at 3.16% compounded quarterly for 9 years and 6 monthsA) calculate the maturity value of this amount at the end of the termB) Calculate the amount of compounded interest earned

Answers

GIVEN:

We are given the details of an investment as follows;

Initial investment = $19,400

Interest rate = 3.16%

Period of investment = 9 years and 6 months

Required;

To use the information given to calculate

(a) The maturity value at the end of the term

(b) The amount of compound interest earned.

Step-by-step solution;

The formula applied in calculating the maturity value is as follows;

[tex]A=P(1+r)^t[/tex]

Where the variables are;

[tex]\begin{gathered} A=Maturity\text{ }value \\ \\ P=Initial\text{ }investment\text{ }(19400) \\ \\ r=rate\text{ }of\text{ }interest\text{ }(0.0316) \\ \\ t=time\text{ }in\text{ }years\text{ }(9.5) \end{gathered}[/tex]

However, for an investment whose interest is compounded at different intervals within 1 year, the formula becomes modified as shown below;

[tex]A=P(1+\frac{r}{n})^{tn}[/tex]

Where the variable n is the number of times interest is compounded annually. For an investment whose interest is compounded quarterly, that is, four times a year, the formula becomes;

[tex]A=P(1+\frac{r}{4})^{4t}[/tex]

We can now calculate as follows;

[tex]\begin{gathered} A=19400(1+\frac{0.0316}{4})^{4\times9.5} \\ \\ A=19400(1+0.0079)^{38} \\ \\ A=26161.6208681 \\ \\ A\approx26161.62 \end{gathered}[/tex]

We can now determine the amount of compound interest earned by deducting the initial amount invested from the maturity value. Thus we have;

[tex]\begin{gathered} Interest=A-P \\ \\ Interest=26161.62-19400 \\ \\ Interest=6761.62 \end{gathered}[/tex]

Therefore,

ANSWER:

[tex]\begin{gathered} Maturity\text{ }value=26,161.62 \\ \\ Interest=6,761.62 \end{gathered}[/tex]

The wholesale price for a pillow is  $4.50 . A certain department store marks up the wholesale price by 90% . Find the price of the pillow in the department store. Round your answer to the nearest cent, as necessary.

Answers

The wholesale price for a pillow is $4.50 .

The store marks up the wholesale price by 90%.

That is, 90% of $4.50 has been aadded with the wholesale price as the store price (SP).

Therefore we have, '

[tex]Sp=4.50+\frac{90}{100}\times4.50=8.55[/tex]

Thus, the store price is $8.55

Solve by substitution 4x + 2y =-14 x -2y =4

Answers

In order to solve by subdtitution, first, solve the second equation for x:

x - 2y = 4 add 2y both sides

x = 4 + 2y

next, replace the previous expression for x into the first equation and solve for y:

4x + 2y = -14 replace x=4+2y

4(4 + 2y) + 2y = -14 apply distribution property

16 + 8y + 2y = -14 subtract 16 both sides

8y + 2y = -14 - 16 simplify like terms both sides

10y = -30 divide by 10 both sides

y = -30/10

y = -3

next, replace y=-3 into x = 4 + 2y

x = 4 + 2y = 4 + 2(-3) = 4 -6 = -2

x = -2

Hence, the solution to the given system of equations is:

x = -2

y = -3

12. Write the equation of the line that is perpendicular to the line x - 4y = 20 and passes through the point (2,-5).

Answers

Two perpendicular lines have reciprocal and opposite slopes.

First we have to write the given line in the slope-intercept form:

[tex]y=mx+b[/tex]

Where m is the slope and b is the y-intercept.

We have this equation:

[tex]x-4y=20[/tex]

To write it in the slope-intercept form we have to clear y:

[tex]\begin{gathered} x-20=4y \\ \downarrow \\ y=\frac{1}{4}x-5 \end{gathered}[/tex]

The slope is 1/4 and the y-intercept is -5.

The slope of the perpendicular line will be the opposite and reciprocal of 1/4, that's -4.

For now we have the perpendicular line's equation:

[tex]y_p=-4x+b[/tex]

There are a lot of lines that are perpendicular to the given line, but only one that passes through (2, -5). We use this point to find the y-intercept by replacing x = 2 and y = -5 into the expression above and solving for b:

[tex]\begin{gathered} -5=-4\cdot2+b \\ -5=-8+b \\ -5+8=b \\ b=3 \end{gathered}[/tex]

The y-intercept of the perpendicular line is 3.

The equation of a line perpendicular to the given line that passes through the point (2,-5) is

[tex]y_p=-4x+3[/tex]

In one city, the probability that a person will pass his or her driving test on the first attempt is 0.63. 11 people are selected at random from among those taking their driving test for the first time. What is the probability that among these 11 people, the number passing the test is between 2 and 4 inclusive?

Answers

The probability that among these 11 people, the number passing the test is between 2 and 4 inclusive is 0.0665

What is Probability?

Probability gives us the information about how likely an event is going to occur

Probability is calculated by Number of favourable outcomes divided by the total number of outcomes.

Probability of any event is greater than or equal to zero and less than or equal to 1.

Probability of sure event is 1 and probability of unsure event is 0.

Now

Binomial distribution of probability will be used

Here, n = 11, p = 0.63,

P(X = x) = [tex]{n\choose x} p^x(1-p)^{n-x}[/tex]

P(X= 2) = [tex]{11\choose 2} 0.63^2(1-0.63)^{11-2}[/tex]

            = 0.0028

P(X = 3) = [tex]{11\choose 3} 0.63^3(1-0.63)^{11 - 3}\\[/tex]

             = 0.0144

P(X = 4) = [tex]{11\choose 4} 0.63^4(1-0.63)^{11 - 4}\\\\[/tex]

             = 0.0493

The probability that among these 11 people, the number passing the test is between 2 and 4 inclusive =  0.0028 + 0.0144 + 0.0493

                                                = 0.0665

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main and Range HAMAD SALIM 12 Range 12 The graph below represents the function y = f(x). State the domain and range of this function. 1 I US

Answers

Remember that the domain is the data set of all possibles values of x and the range is the data set of all possibles values of y

so

Looking at the graph

Domain is the interval for x

[-5,8}

All real numbers greater than or equal to -5 and less than or equal to 8

Range is the interval for y

[-3,2]

All real numbers greater than or equal to -3 and less than or equal to 2

Two matrices can always be multiplied if the have the same dimensions. True False

Answers

SOLUTION:

Case: Matrices multiplication

Given:

Two matrices can always be multiplied if they have the same dimensions.

Method:

From the image above, if and only if the number of items of columns matches the number of items of the columns, then it is possible to multiply.

Final answer:

True,

Two matrices can always be multiplied if they have the same dimensions

Pls help with this math problem pl

Answers

Using the slope intercept equation, the equation of the line in fully simplified slope intercepted form is y=4x−4.

In the given question we have to write the equation of the line in fully simplified slope intercepted form.

As we know that slope intercept form of equation of line is given by

y=mx+c

where m=slope

c=intercept of the line (i.e point where line cut y-axis )

From graph we can easily find two point of the line that is (1,0)(0,−4).

From the point x(1)=1, y(1)=0, x(2)=0, y(2)=−4

Slope (m)=(y(2)−y(1))/(x(2)−x(1))

m=(−4−0)/(0−1)

m=-4/−1

m=4

As we know that c is a point where line cut y axis so c=−4

Hence, slope-intercept form of equation is y=4x−4.

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SA bag contains 1 gold marbles, 6 silver marbles, and 21 black marbles. Someone offers to play this game: Yourandomly select one marble from the bag. If it is gold, you win $3. If it is silver, you win$2. If it is black, youlose $1.What is your expected value if you play this game?

Answers

We are given that a bag contains 1 gold marble, 6 silver marbles, and 21 black marbles. First, we need to determine the total number of marbles. The number of marbles of each color is:

[tex]\begin{gathered} N_{gold}=1 \\ N_{silver}=6 \\ N_{\text{black}}=21 \end{gathered}[/tex]

The total number is then:

[tex]N_t=N_{\text{gold}}+N_{\text{silver}}+N_{\text{black}}[/tex]

Substituting the values:

[tex]N_t=1+6+21=28[/tex]

Therefore, there are a total of 28 marbles. Now we determine the probability of getting each of the marbles by determining the quotient of the number of marbles of a given color over the total number of marbles. For the gold marbles we have:

[tex]P_{\text{gold}}=\frac{N_{\text{gold}}}{N_t}=\frac{1}{28}[/tex]

For silver we have:

[tex]P_{\text{silver}}=\frac{N_{silver}}{N_t}=\frac{6}{28}=\frac{3}{14}[/tex]

For the black marbles:

[tex]P_{\text{black}}=\frac{N_{\text{black}}}{N_t}=\frac{21}{28}=\frac{3}{4}[/tex]

Now, to determine the expected value we need to multiply each probability by the value that is gained for each of the colors. We need to have into account that is it is a gain we use a positive sign and if it is a lose we use a negative sign:

[tex]E_v=(3)(\frac{1}{28})+(2)(\frac{3}{14})+(-1)(\frac{3}{4})_{}[/tex]

Solving the operations we get:

[tex]E_v=-0.21[/tex]

Therefore, the expected value is -$0.21.

Hi can you help me with this question real quick please

Answers

The volume of a sphere is given by

[tex]V=\frac{4}{3}\pi r^3[/tex]

where V denotes the volume and r the radius. In our case,

[tex]r=\frac{3}{2}in[/tex]

Then, by substituting this value into the formula, we have

[tex]V=\frac{4}{3}\pi(\frac{3}{2})^3[/tex]

which gives

[tex]\begin{gathered} V=\frac{4}{3}\pi\frac{3^3}{2^3} \\ V=4\pi\frac{3^2}{8} \\ V=\pi\frac{9}{2} \end{gathered}[/tex]

By taking Pi as 3.14, we get

[tex]V=14.13in^3[/tex]

So , by rounding to the nearest tenth, the answer is 14.1 cubic inches.

Need help. Not understanding how to start with each of these

Answers

Given

mean = 84 pounds

standar deviation = 13 pounds

Procedure

a. New hippo weighs between 90 and 109 pounds

Areas under portions of a normal distribution can be computed by using calculus. Since this is a non-mathematical treatment of statistics, we will rely on computer programs and tables to determine these areas.

[tex]\begin{gathered} \mu=84 \\ \sigma=13 \\ \end{gathered}[/tex]

Between 90 and 109

Results:

Area (probability) = 0.295

b. What weight corresponds with the 6th percentile?

The score you have entered means that the hippo is at the sixth percentile – their percentile rank is 6%

Given P(xZ = -1.555

The value of the z-score tells you how many standard deviations you are away from the mean.

[tex]\begin{gathered} z=\frac{x-\mu}{\sigma} \\ x=z\sigma+\mu \\ x=-1.555\cdot13+84 \\ x=63.785 \end{gathered}[/tex]

63.785 is the weight for the 6th percentile

c. What percentages of hippos are born weighing 27 pounds or less?

Z = (27 - 84)/13

Z-score = -4.38462

0% of hippos are born at 27 pounds or less

Use the distributive property to remove the parenthesis (X+7)12

Answers

Answer

Use the distributive property to remove the parenthesis

[tex]\begin{gathered} a(b+c) \\ ab+ac \end{gathered}[/tex]

Now , Given

[tex]\begin{gathered} (x+7)12 \\ x\times12\text{ +7}\times12 \\ 12x+84 \end{gathered}[/tex]

The final answer

[tex]12x+84[/tex]

13 inches by 6 inches by 4 inches. what is the maximum lenght

Answers

[tex]\begin{gathered} \text{The representation of the length width and height is,} \\ \Rightarrow L\times B\times H=13\times6\times4 \\ \text{Here, Ma}\xi mum\text{ length is 13 inch} \end{gathered}[/tex]

graph at least one full cycle of the following trig function, lable the amplitude midline and maximum and the intervals f(x)=2sin(x-pi/2)-1

Answers

[tex]\begin{gathered} f(x)=2\sin (x-\frac{\pi}{2})-1 \\ Maximum=1 \\ \text{midline}=\frac{1+(-3)}{2}=\frac{1-3}{2}=\frac{-2}{2}=-1 \\ \text{midline}=-1 \\ The\text{ midline is y=-1} \\ \text{Interval = (0,2}\pi\text{)} \end{gathered}[/tex]

2.Evaluate the following mixed numbers, then simplify.7 1/2 divide 1 1/8

Answers

Given the numbers : 7 1/2 and 1 1/8

We will divide them

so,

[tex]\begin{gathered} 7\frac{1}{2}\div1\frac{1}{8} \\ \\ =\frac{15}{2}\div\frac{9}{8} \\ \\ =\frac{15}{2}\times\frac{8}{9} \\ \\ =\frac{8}{2}\times\frac{15}{9}=4\times\frac{5}{3}=\frac{20}{3}=6\frac{2}{3} \end{gathered}[/tex]

The Harris school district gives awards to its schools based on overall student attendance. The data for attendance are shown in the table below, where Min represents the fewest days attended and Max represents the most days attended for a single student:SchoolMinMaxRangeMeanMedianIQRσHigh School A1071808216915048.533.6High School B921807214113944.527.0High School C1041807516115154.532.4Part A: If the school district wants to award the school that has the most consistent attendance among its students, which high school should it choose and why? Justify your answer mathematically. (5 points)Part B: If the school district wants to award the school with the highest average attendance, which school should it choose and why? Justify your answer mathematically. (5 points) (10 points)

Answers

Answer to part A :

The school that gets the award for the highly consistent attendance among its students is school B . Because its range is the smallest that is there exists a smaller variation in the highest and the lowest value and also because the interquartile range is the smallest means that the data is spread out the least.

Answer to part B :

The school that gets the award for the highest average attendance among its students is High school A . This is because its mean and median are the highest which means that there are more kids attended school on average.

Find two solutions for the equation 4x+3y=24 , draw it's graph .

Answers

The equation of consideration is:

[tex]4x\text{ + 3y = 24}[/tex]

Since two unknowns ( x and y) are given in just one equation, to get each set of the solutions, we are going to choose a value of x and get a corresponding value of y

Let x = 0, to get the value of y at point x = 0, substitute this value of x into the given equation:

[tex]4(0)\text{ + 3y = 24}[/tex][tex]3y\text{ = 24}[/tex][tex]y\text{ = }\frac{24}{3}\text{ = 8}[/tex]

The first set of solutions is therefore:

[tex]x\text{ = 0, y = 8}[/tex]

To get the second set of solution, let us choose x = 3 and substitute this value into the given equation:

[tex]4(3)\text{ + 3y = 24}[/tex][tex]12\text{ + 3y = 24; 3y = 24 - 12; 3y = }12;\text{ y = 12/3; y = 4}[/tex]

The second set of equation is:

[tex]x\text{ = 3, y = 4}[/tex]

The above is the graph showing the two sets of solutions

Rachel is conducting a study in her cognitive psychology lab about people's ability to remember rhythms. She played a short Rhythm to 425 randomly chosen people. One minute later, she asked him to repeat it by clapping. If 121 people were able to successfully reproduce the rhythm, estimate the proportion of the population (including the margin of error) that would be able to successfully reproduce the rhythm. Use a 95% confidence interval.

Answers

Given:

Sample Size (n) = 425

No. of Success = 121

Find: estimate the proportion of the population

Solution:

Let's calculate first the success proportion in the sample by dividing no. of success over the total number of people then multiply it by 100.

[tex]\frac{121}{425}\times100\%=28.47\%[/tex]

Our sample proportion p = 28.47%.

Then, for the margin of error, the formula is:

[tex]MOE=z\sqrt{\frac{p(1-p)}{n}}[/tex]

where z = critical value, p = sample proportion, and n = sample size.

For our z-value, since we are using a 95% confidence interval, the value of z = 1.645.

[tex]MOE=1.645\sqrt{\frac{.2847(1-.2847)}{425}}[/tex]

Then, solve.

[tex]MOE=1.645\sqrt{\frac{0.203648}{425}}[/tex][tex]MOE=1.645(0.02189)[/tex][tex]MOE=0.036[/tex]

Let's multiply the MOE by 100%.

[tex]0.036\times100\%=3.6\%[/tex]

Therefore, about 28.47% ± 3.6% or between 24.87% to 32.07% of the population would be able to successfully reproduce the rhythm.

Find the area of the shaded region in the figure. Use the pi key for pi.The area of the shaded region in the figure is approximately: (Type an integer or decimal rounded to the nearest tenth as needed.)

Answers

Hello there. To solve this question, we'll need to remember some properties on geometry and areas of figures.

First, the area of a square is equal to the square of its side length.

The area of a circle is given by pi * the square of its radii, being this radii half of the diameter:

In this case, the side of the square is 1.5' and the diameter of the circle is 5.8'.

Finding the radii of the circle:

r = d/2 = 5.8'/2 = 2.9'

Calculating the area of the square and the circle

Asquare = 1.5² = 2.25 and Acircle = pi * 2.9² = pi * 8.41

The area of the shaded region is calculated by the difference between the area of the circle and the square

Ashaded = Acircle - Asquare

Ashaded = 8.41pi - 2.25

This is the area of the region we've been looking for.

Other Questions
Which group was losing power in the early 1900s in Oklahoma?A.progressivesB.populists C.governmentD.corporations 120 lb to 180 lb increase or decrease I need to determine the length in feet of arc BC?? Is my answer correct? 3. Where do the producers get their energy from? 11 less than 4G leaves 37 translate into an expression To support their other promotional efforts, firms use ________blank to generate free media attention. There are 27 students in Mrs. Mello's class. fin the total number of pages they read by the end of November. 6. The line in each graph represente y = 2x Which grach represents 2> y? How is electroplating done?A. The anode is replaced by the object to be electroplated.B. A precipitation reaction is used to plate the cathode with an ion.OC. The metals in the anode and cathode electrodes trade positions.OD. Ions of one metal are reduced onto a cathode made of a differentmetal. write a linear equation that passes through the points (3,1) and (-2,6) Two times x, minus the quantity 7 times y, equals 20 Can you show the steps in how to solve it Which region shows the greatest increase in immigration during the time period shown on the graph? f(x) = x^2 - 8x + 7Find the vertexaxis of symmetrygraph itfind the domainfind the range blake needed at least 225 votes to become president of his seventh-grade class. if three-fourths of the seventh-grade students voted for him and he won. how many seventh-grade students could there be?im looking for the inequality and answer. thank you. To ___ is to make a statement that a product is or does more than is actually true. 4. Calculate the pH of 0.90M HPO4?Ka HPO4^2- = 4.5 x 10-13(a) 7(b) 14(c) 12.3(d) 8.20(e) 6.20 Name the ordered pair for a fourth point. Q. so that points P.Q.R. and S will be the vertices of a Given: Points P6.-1), R(0.-1) and S(4.-5) rectangle Response 1 Find the area of the triangle given below and type your result in the empty box. 19 cm 15 cm 12 cm Find the greatest number that divides 30 and 60 without leaving a remainder.