Which of the following can be mixed in solution with H₂CO3 to make a buffer?OA. Na₂CO3OB. HFOC. NH3OD. NaHCO3

Answers

Answer 1

A buffer system usually will need a weak acid, like H2CO3, which is carbonic acid, and a strong base, and the only compound that could figure a fairly strong base among the options given is Na2CO3. NH3 and NaHCO3 are weak bases and HF is a strong acid. Therefore the best answer will be letter A


Related Questions

Adding up all of the _______ of all of the individual atoms within one molecule of a compound will determine the molecular mass of the compound.A) atomic massesB) electronsC) atomic numbersD) protons

Answers

1) Subatomic particles. There are three main subatomic particles. These subatomic particles are the protons, the neutrons, and the electrons.

The protons and the neutrons are a lot heavier than the electrons. So, they represent most of the weight of an atom.

The protons and the neutrons added together are what we call the mass number.

The correct answer is option A, atomic masses.

How many moles are in 91.5 grams of Helium?

Answers

In order to find the number of moles with a given mass of Helium, we need to use its molar mass, which is 4.0026g/mol, therefore we will have:

4.0026g = 1 mol of Helium

91.5g = x moles of Helium

x = 22.86 moles of Helium in 91.5 grams

What is the pH of a solution where [OH-] = 5.6 × 10-4 M?

Answers

The pH value indicates the concentration of H+ ions in the solution. We are given the value of the concentrations of the OH- ions, so we can find the pOH using the following equation:

[tex]pOH=-log\lbrack OH^-\rbrack[/tex]

The sum of pH and pOH will always be equal to 14, so we find the pH by clearing it from the following relationship:

[tex]pH+pOH=14[/tex]

So, pOH value will be:

[tex]pOH=-log\lbrack5.6\times10^{-4}\rbrack=3.3[/tex]

The pH will be:

[tex]\begin{gathered} pH=14-pOH \\ pH=14-3.3=10.7 \end{gathered}[/tex]

The pH of the solution will be 10.7

Why are triple bonds shorter than single bonds?

Answers

Due to the inverse relationship between bond length and bond strength, triple bonds, which are the strongest bonds, also have the shortest bond lengths.

Why do single bonds tend to be longer than triple bonds?

The strength of the bond affects how long the bond lasts. The link will be stronger and last longer. Because they are the strongest and shortest, triple bonds. Next are double bonds, which are between single and triple bonds in terms of strength.

What produces bonds with reduced lengths?

The quantity of bound electrons determines how long the bond will be (the bond order). The attraction between the two atoms is stronger and the bond length is shorter the higher the bond order.

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2. The following mistakes were made when carrying out the experiment. What effect does each have on the
calculated molar mass? Be specific. For example, too large because...
a. Only part of the pipet was immersed in the boiling water, so the temperature in part of the pipet was less
than that of the water bath.
b. The mass of the condensed liquid was not determined quickly. Instead, the pipet was allowed to stand for
a while before immersing it in room temperature water and then massing the pipet.

Answers

The actual volume of pipet is 23.8901 mL

Explanation:

The formula for the density of water can be used to calculate the volume of water transferred. For which, let us first calculate the mass of water transferred by taking the difference of mass of beaker.

Initial mass of the dry beaker:

initial mass of beaker (dry) = 57.5348 g

Mass of the water:

mass of the water  = final mass of the beaker - initial mass of the beaker

mass of the  water = 81.3743 - 57.5348

mass of the water  = 23.8395 g

The density of water at 21.5°C is 0.997882 g/mL

From the above data

The above calculations show that the volume transferred by pipet is 23.8901 mL.

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The mass number is used to calculate the numner of ____ in one atom of an element. In order to calculate the number of neutrons you must subtract the ___ from the ___

Answers

1) neutrons
2) atomic number
3) atomic mass

Find the oxidation numbersd) Oxidation number of K in K2SO3e) Oxidation number of S in K2SO3f) Oxidation number of O in K2SO3g) Oxidation number of S in S8

Answers

Answer:

d) The oxidation number of K in K2SO3 is +1.

e) The oxidation number of S in K2SO3 is +4.

f) The oxidation number of O in K2SO3 is -2.

g) The oxidation number of S in S8 is 0.

Explanation:

In each case, we can use the Periodic Table of Elements to consult the oxidation number of the elements.

d) In this case, K is in the group 1 of the Periodic Table, so it has always an oxidation number of +1.

f) Oxygen (O) always has an oxidation number of -2 (except in peroxides which has -1).

e) Knowing that the molecule of K2SO3 is neutral (the total charge of the molecule is equal 0), we can sum all the charges of the elements in the molecule, to find out which oxidation number has S in this molecule:

[tex]\begin{gathered} K_2SO_3 \\ K\text{ charge: }(+1)*2=+2 \\ O\text{ charge: }(-2)*3=-6 \\ \end{gathered}[/tex]

Now we have to sum them and find out the oxidation number of S that will made the total charge of the molecule equal 0:

[tex]\begin{gathered} K_2SO_3 \\ +2\text{ + S oxidation number -6 =0} \\ -4\text{ + S oxidation number =0} \\ -4+4=0 \end{gathered}[/tex]

So, the oxidation number of S is +4.

g) Finally, in this case, the oxidation number of S in S8 is 0, because it is a pure compound.

4.A gas occupies 8.7L at a temperature of 29.0°c. What is thevolume at 133°C? (Charles Law)

Answers

Answer:

11.7L

Explanations

According to Charles law, the volume of a given mass of gas is directly proportional to its temperature provided that the pressure is constant. Mathematically;

[tex]\begin{gathered} v\alpha T \\ v=kT \\ k=\frac{v_1}{T_1}=\frac{v_2}{T_2} \end{gathered}[/tex]

where:

• v1 and v2 are the ,initial and final ,volume

,

• T1 and T2 are the, initial and final, temperature

Given the following parameters

v1 = 8.7L

T1 = 29.0°C = 29 + 273

T1 = 302K

T2 = 133+ 273 = 406K

Substitute the given parameters into the formula

[tex]\begin{gathered} v_2=\frac{v_1T_2}{T_1} \\ v_2=\frac{8.7L\times406}{302} \\ v_2=\frac{3532.2}{302} \\ v_2=11.7L \end{gathered}[/tex]

Hence the volume of the gas at 133°C is 11.7L

An aqueous solution of a nonionic (that is, nonelectrolyte) solute has a freezing point of -0.435 °C. The solution contains 2.49 g solute dissolved in 95.0 g H2O. What is the molar mass of the solute? g/mol

Answers

To answer this question, we have to use the formula of the cryoscopic descent:

[tex]\Delta T_c=k_f\cdot m[/tex]

Where ΔTc is the difference between the freezing points of the pure solvent and the solution, kf is the cryoscopic constant (that for water it has a value of 1.86°C*kg/mol and m is the molality of the solution.

The first step we have to follow is to find the molality of the solution using this formula and the given values.

Estimate the difference between the freezing point of the water and the one of the solution:

[tex]\Delta T_c=0\degree C-(-0.435\degree C)=0.435\degree C[/tex][tex]\begin{gathered} 0.435\degree C=1.86\degree Ckg/mol\cdot m \\ m=\frac{0.435\degree C}{1.86\degree Ckg/mol} \\ m=0.234mol/kg \end{gathered}[/tex]

The molality of the solution is 0.234mol/kg.

Now we have to use this molality to find the amount of moles present in the solution.

Molality equals moles of solute/kg of solvent. We know that there are 95.0g of solvent, by converting this mass to kg and using the molality we can find the amount of moles of solute present in the solution, this way:

[tex]95.0g\cdot\frac{1kg}{1000g}=0.095kg[/tex][tex]0.095kg\cdot\frac{0.234mol}{kg}=0.02223mol[/tex]

It means that there are 0.02223 moles of solute in the solution.

Our last step to answer this question is to divide the mass of solute present in the solution by the amount of moles of it to find its molar mass:

[tex]\frac{2.49g}{0.02223mol}=112.01g/mol[/tex]

It means that the molar mass of the solute is 112.01g/mol.

How many total atoms are there in 19.3 g of hydrazine (N_{2}*H_{2})

Answers

Answer:[tex]3.87*10^{23}atoms[/tex]

Explanations:

Given the following parameters

Mass of hydrazine = 19.3 grams

Determine the moles of hydrazine

[tex]\begin{gathered} moles\text{ of N}_2H_2=\frac{mass}{molar\text{ mass}} \\ moles\text{ of N}_2H_2=\frac{19.3}{30.02928} \\ moles\text{ of N}_2H_2=0.6423moles \end{gathered}[/tex]

According to the Avogadro's constant

[tex]1mole\text{ of a substance}=6.02\times10^{23}atoms[/tex][tex]\begin{gathered} atoms\text{ of N}_2H_2=0.643\times6.02\times10^{23} \\ atoms\text{ of N}_2H_2=3.87\times10^{23}atoms \end{gathered}[/tex]

Therefore the total atoms that are there in 19.3 g of hydrazine is 3.87 * 10^23 atoms

Using the Gay-Lussac LawIf I have 7.7 moles of gas at a pressure of 0.09 atm at a temperature of 56 C°, what is the volume of the container that the gas is in?

Answers

ANSWER

EXPLANATION

Given that;

The number of moles of the gas is 7.7 moles

The pressure of the gas is 0.09 atm

The temperature of the gas is 56 degrees Celcius

Follow the steps below to find the volume of the gas in the container

Step 1; Convert the temperature to degrees Kelvin

[tex]\text{ T K = t}\degree C\text{ + 273.15}[/tex][tex]\begin{gathered} \text{ T K = 56 + 273.15} \\ \text{ T K = 329.15K} \end{gathered}[/tex]

Step 2; Apply the ideal gas equation

[tex]\text{ PV = nRT}[/tex][tex]\begin{gathered} \text{ Recall, that R = 0.08205 L atm mol}^{-1}K^{-1} \\ \text{ 0.09 }\times\text{ V = 7.7 }\times\text{ 0.08205 }\times\text{ 329.15} \\ \text{ 0.09V = 207.95} \\ \text{ Divide both sides by 0.09} \\ \text{ V = }\frac{\text{ 207.95}}{\text{ 0.09}} \\ \text{ V = 2310.58 Liters} \end{gathered}[/tex]

Therefore, the volume of the container is 2310.58 liters

how many litres of gas is in 8.3 mol N2O in STP

Answers

According to STP, and furthermore, we assume ideal gas conditions:

1 mol N2O = 22.4 L

Procedure:

1 mol N2O -------------- 22.4 L

8.3 moles N2O------------- X

X= 186 L (approx.)

Answer: 186 L

I really need help on this problem for chemistry, please help!

Answers

answer and explanation

we are given the balanced reaction and so we begin by calculating the number of mols of each reactant

for Al

mols = mass/Molar mass

= 22.0g / 26.98g/mol

= 0.82 mols

for oxygen

mols = mass / Molar mass

= 26.0g / 16.00g/mol

= 1.6 mols

theerefore

a. the limiting reagent is Al

b. theoretical yield will be determine using the limiting reagent.

from the balanced reaction we see that the mol ratio between aluminum and aluminum oxide is 4:2

therefore

2/4 x0.82 = 0.41 mols of aluminum oxide will form

the mass will be

mass = n x M

= 0.41 mols x 101.96g/mol

= 41.8 grams

c. percentage yield is:

actual yield/ theorectical yield x 100

= 40.0/41.8 x 100%

= 95.7 %

When reacting 5.00 g of MgCl2 with 15.0 g of AgNO3 , what is the limiting reagent based on the following equation?MgCl2 (aq) + 2 AgNO3(aq) --> 2 AgCl (s) + Mg(NO3)2 (aq)

Answers

Answer:

[tex]AgNO_3\text{ is the limiting reagent}[/tex]

Explanation:

Here, we want to get the limiting reactant

The limiting reactant is the reactant that would produce less amount of the solid precipitate

Firstly, we need to get the number of moles of each of the reactants

To get this, we divide their masses by the molar masses

The molar mass of magnesium chloride is 95 g/mol

The number of moles would be:

[tex]\frac{5}{95}\text{ = 0.053 mol}[/tex]

Now, from the equation of reaction, 1 mole of MgCl2 produced 2 moles of AgCl

Then: 0.053 mole of MgCl2 will produce 2 * 0.053 mol = 0.106 mol AgCl

For AgNO3, the molar mass is 170 g/mol

The number of moles would be:

[tex]\frac{15}{170}\text{ = 0.088 mol}[/tex]

Now, looking at the equation of reaction:

2 moles of AgNO3 produce 2 moles of AgCl

0.088 mol AgNO3 will also produce 0.088 mol AgNO3

Now, looking at the values of the number of moles of AgCl produced, we can see that AgNO3 produces less of the product

This means that AgNO3 is the limiting reactant

Answer the following question:Reminder R= .0821. If you have a gas at 6 Atm and 4 L, how many moles are present if the temp is 300 K?

Answers

Answer

0.975609756 mol

Explanation

Given:

Pressure, P = 6 atm

Volume, V = 4 L

Temperature, T = 300 K

Molar gas constant, R = 0.082

What to find:

The moles, n present.

Step-by-step solution:

The mole, n present can be calculated using the ideal gas equation, PV = nRT

6 x 4 = n x 0.082 x 300

24 = 24.6n

Diivide both sides by 24.6

24/24.6 = 24.6n/24.6

n = 0.975609756 mol

Hence, the moles that are present = 0.975609756 mol

A piece of sodium metal reacts completely with water. The hydrogen gas generated is collected over water at 25oC. The volume of the gas is 252mL measured at 1.00atm. Calculate the number of grams of hydrogen that was collected

Answers

The mass or number of grams of hydrogen that was collected in the experiment is 0.02 g.

What is the number of moles of hydrogen gas collected at the given conditions of temperature and pressure?

The number of moles of hydrogen gas collected at the given conditions of temperature and pressure is calculated using the ideal gas equation as follows:

PV = nRT

Where;

P is pressure = 1.00 atm

V is volume = 252 mL or 0.252 L

n is the number of moles = ?

R is molar gas constant = 0.082 L.atm/K.mol

T is temperature = 273 + 25 K

T = 298 K

n = PV/RT

n = 1 * 0.252 / (298 * 0.082)

n = 0.01 moles

1 mole of hydrogen gas has a mass of 2.0 g

mass of 0.01 moles of hydrogen = 2 * 0.01

Mass of  0.01 moles of hydrogen = 0.02 g

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Determine the molar mass of an unknown monoprotic acid to two decimal places if 16.98 mL of a 0.086 M NaOH solution were used to titrate 0.236 g of the unknown acid

Answers

1 ) Chemical equation

[tex]\text{NaOH + HX}\rightarrow H_2O+Na^++X^-[/tex]

HX represents the unknown acid.

2) Moles of NaOH in the reaction

[tex]M=\frac{\text{moles of solute}}{\text{liters of solution}}[/tex]

Convert mL into L

[tex]L=16.98mL\cdot\frac{1L}{1000mL}=0.01698L[/tex]

Plug in known values in the equation and solve for moles.

[tex]0.086M=\frac{\text{moles of NaOH}}{0.01698L}[/tex][tex]\text{mol NaOH= 0.086M}\cdot0.01698L=0.00146028\text{ mol NaOH}[/tex]

3) Moles of the unknown acid that reacted with 0.00146028 mol NaOH

Molar ratio

1 mol NaOH: 1 mol HX

[tex]\text{mol HX=0.00146028 mol NaOH}\cdot\frac{1\text{ mol HX}}{1\text{ mol NaOH}}=0.00146028\text{ mol HX}[/tex]

4) Molar mass of the unknown monoprotic acid

[tex]\text{Molar Mass=}\frac{\text{mass of solute (g)}}{moles\text{ of solute}}[/tex]

Plug in known values and solve

[tex]\text{Molar Mass}=\frac{0.236\text{ g HX}}{0.00146028\text{ mol HX}}=161.61\text{ g/mol}[/tex]

The molar mass of the unknown monoprotic acid is 161.61 g/mol

.

Question 2 of 10Which of the following substances is a chemical that is made only bychemists?A. BleachB. CopperOC. WaterO D. Nitrogen

Answers

Answer: The best option to answer the question is letter A (bleach)

Explanation:

The question requires us to choose, among the options given, which one corresponds to a chemical compound that is only made by chemists.

Nitrogen (N2) is a gas found in our atmosphere, corresponding to 78% (by volume) in dry air. Therefore, N2 is found in nature.

Water (H2O) is also found in nature, as it is present in our atmosphere, rivers, lakes and oceans (among others).

Copper (Cu) is a metal that is also found in nature, occuring naturally in metal form and being present in minerals.

On the other hand, bleach corresponds to a mixture of chemicals where the main ingredient is sodium hypochlorite.

Therefore, among the options given, bleach is the only one that is made only by chemists (and it is not found as it is in nature).

The best option to answer the question is letter A (bleach).

6. A sample of nitrogen gas weighs 130 g. Write the chemical formula for nitrogen gas. Howmany molecules of elemental nitrogen is this? How many atoms of nitrogen are in this sample?

Answers

Chemical formula for nitrogen gas is N₂.

To find the number of molecules in the given sample, we have to convert the mass of the sample to moles by using the molecular mass of elemental nitrogen (N₂).

[tex]130gN_2\cdot\frac{1molN_2}{28gN_2}=4.64molN_2[/tex]

Now, we have to use Avogadro's number (6.022x10^23) that indicates the number of molecules in one mole of substance:

[tex]4.64molN_2\cdot\frac{6.022\times10^{23}molecules}{1molN_2}=2.79\times10^{24}molecules[/tex]

It means that there are 2.79x10^24 molecules of elemental nitrogen.

To find the number of atoms we just have to multiply the number of molecules by 2, which is the number of atoms of nitrogen per molecule of elemental nitrogen:

[tex]2.79\times10^{24}molecules\cdot\frac{2atoms}{1molecule}=5.59\times10^{24}atoms[/tex]

There are 5.59x10^24 atoms of nitrogen in the sample.

Explain the role electronegativity plays in the polarity of a molecule.

Answers

Electronegativity is the force of an atom to attract electrons to itself, and Polarity represents the distribution of electron density of a molecule.

When the atoms of a molecule have very different electronegativities, zones with different electron densities are generated, and poles are formed.

So, the role that electronegativity plays in the polariry of a molecule is very important because knowing the electronegativity of atoms we can know if a molecule is polar or nonpolar.

What part of a cell provides instructions for the processes within the cell

DNA _ Chloroplasts _ Cell wall or Glucose

Answers

The information for the cellular process is provided by DNA. DNA has genes on it, so by expressing the gene, the characteristics are expressed in the cell.

       

What is a gene?

Genes are present in the DNA of both prokaryotes and eukaryotes. The information of the cell is present in the gene, and it is expressed by the processes of transcription and translation in the cell.

Because of differences in gene expression, different cells, such as the nerve cell, the cardiac cell, the epithelial cell contain different proteins. Not all genes are expressed in all cells of the body. Only those genes are expressed that are transcriptionally activated and make mRNA.

Hence, DNA provides the information to the cell for the cellular process.

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5. You have 7 moles of NaCl. How many particles are present?

Answers

1) List the known and unknown quantities.

Sample: 7 mol NaCl

Particles: unknown

2) Convert moles of NaCl to particles of NaCl.

Avogadro's number is 6.022*10^23

1 mol = 6.022*10^23

[tex]particles\text{ }NaCl=7\text{ }mol\text{ }NaCl*\frac{6.022*10^{23}\text{ }particles}{1\text{ }mol\text{ }NaCl}=4.21*10^{24}\text{ }particles[/tex]

7 mol NaCl is equal to 4.21*10^24 parcicles.

A neutral atom of on element has two electrons
with n=1, eight electrons with n=2, eight electrons
with n=3 and one electron with n =4 and has mass
number of 39. Deduce the following from the above
information
i the atomic number of the element.
is number of neutrons in the nucleus
i total number of s electrons.
iv total number of p electrons .
v the group the element belongs to

Answers

A neutral atom of on element has two electrons with n=1, eight electrons with n=2, eight electrons with n=3 and one electron with n =4 and has mass number of 39 then the atomic number of element is 39 and number of neutron in the nucleus is 50 and total number of s electron is 2 and total number of p electron is 8 and the group is 3rd group

Yttrium is a metallic element with atomic number 39 usually included in the rare earth group that occur usually with other rare earth element in minerals and is used especially in phosphorous and YAG laser and alloy etc and element with mass number of 39 is yttrium and the atomic number of element is 39 and number of neutron in the nucleus is 50 and total number of s electron is 2 and total number of p electron is 8 and the group is 3rd group

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A sample of an unknown gas with a molar mass of 85.74 is placed in a vessel with avolume of 1,681 mL at a temperature of 58.6 °C. If the pressure is 5.4 atm, howmany grams of this gas are present?

Answers

Answer

28.58 grams

Explanation

Given:

Molar mass of the gas, M = 85.74 g/mol

Volume, V = 1,681 mL = 1.681 L

Temperature, T = 58.6 °C = (58.6 + 273.15 K) = 331.75 K

Pressure, P = 5.4 atm

What to find:

The mass of the gas in grams present.

Step-by-step solution:

The mass in grams of the gas present can be calculated using the ideal gas equation:

[tex]\begin{gathered} PV=nRT \\ \\ n=moles=\frac{Mass}{Molar\text{ }mass} \\ \\ \Rightarrow PV=\frac{Mass}{Molar\text{ }mass}RT \end{gathered}[/tex]

Putting the values of the given parameters and R = 0.0821 atm•L/mol•K into the formula:

[tex]\begin{gathered} 5.4atm\times1.681L=\frac{Mass}{85.74g\text{/}mol}\times0.0821atm•L/mol•K\times331.75K \\ \\ 9.0774atm•L=Mass(0.317665908atm•L/g) \\ \\ Divide\text{ }both\text{ }sides\text{ }by\text{ }0.317665908atm•L/g \\ \\ \frac{9.0774atm•L}{0.317665908atm•L/g}=\frac{Mass(0.317665908atm•L)}{0.317665908atm•L\text{/}g} \\ \\ \Rightarrow Mass=28.58\text{ }grams \end{gathered}[/tex]

The mass of the gas in grams present = 28.58 grams.

This is a 6 mark question. Please spend some time explaining it, answering it and helping me.

Answers

Answer:

Explanation:

Here, we want to explain the factors responsible for the differences in the polymers presented

We proceed as follows:

a) High melting Point

Although the two polymers contain carbon and hydrogen atoms only, the presence of hydrogen bonding in Polymer Y may lead to it having a high melting point compared to Z.

Other factors that can cause this include the presence of double bonds, aromatic groups or the availability of bulky side groups or branches in the polymer molecule Y.

These and more are responsible for the differences

b) Rigidity and Flexibility

This is due to the existence of some degree of rotation around the atoms' valency. Polymer Z would be flexible due to this.

The absence of this in Polymer Y will make this a difficulty

c) Stretching

How entangled the chain of the polymers are could be responsible for the stretching of the polymers. Since polymer Z is easily stretched, there would be a low degree of entanglement in its chain compared to polymer Y.


Based on Table H, what is the vapor pressure of CH3COOH at 90.°C?
A 150 kPa
B 114 kPa
40 kPa
48 k

Answers

The equilibrium vapor pressure provides information about the rate of evaporation of a liquid. The vapor pressure of CH₃COOH at 90.°C  is 40 kpa.

What is vapor pressure ?

Pressure of vapor or equilibrium the pressure that a vapor exerts on its condensed phases in a closed system when they are in thermodynamic equilibrium with one another at a specific temperature is known as vapor pressure.

It is significant to remember that when a liquid boils, the pressure of its vapor equals the atmospheric pressure. For instance, water's vapor pressure is 1 atmosphere when it boils at sea level since the surrounding pressure is also 1 atmosphere.

Thus, the vapor pressure of CH₃COOH at 90.°C  is 40 kpa.

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Predict the formula for each ionic compoundbarium sulfate:lithium nitrate :cesium sulfide:

Answers

INFORMATION:

We have the following ionic compounds:

- barium sulfate

- lithium nitrate

- cesium sulfide

And we must write their formulas

STEP BY STEP EXPLANATION:

1. Barium sulfate:

To write its formula, we need to use that:

- the element symbol for Barium is Ba, and it has a charge of 2+

- in the given table, sulfate is a polyatomic ion represented by SO4, and it has a charge of 2-

Now, we must add up the charges to verify if the ionic compound is neutral

[tex]2^++2^-=0[/tex]

Since the compound has a net charge of zero, we can write its formula as

[tex]BaSO_4[/tex]

2. Lithium nitrate:

To write its formula, we need to use that:

- the element symbol for Lithium is Li, and it has a charge of 1+

- in the given table, nitrate is a polyatomic ion represented by NO3, and it has a charge of 1-

Now, we must add up the charges to verify if the ionic compound is neutral

[tex]1^++1^-=0[/tex]

Since the compound has a net charge of zero, we can write its formula as

[tex]LiNO_3[/tex]

3. Cesium sulfide:

To write its formula, we need to use that:

- the element symbol for Cesium is Cs, and it has a charge of 1+

- the element symbol for sulfide is S, and it has a charge of 2-

Now, we must add up the charges to verify if the ionic compound is neutral

[tex]1^++2^-=1^-[/tex]

Since the compound has a net different from zero, we need to analyze the compound.

So, if we have just one atom of Cs, the charge would be 1+, but if we take two atoms the charge would be 2(1+) = 2+

Now, verifying the net charge

[tex]2^++2^-=0[/tex]

Now, we can write its formula as

[tex]Cs_2S[/tex]

ANSWER:

barium sulfate:

[tex]BaSO_4[/tex]

lithium nitrate :

[tex]LiNO_3[/tex]

cesium sulfide:

[tex]Cs_2S[/tex]

The energy of a photon that has a wavelength of 8.33 × 10^-6 m is ________ J.A) 2.20 × 10^-26 B) 3.60 × 10^13C) 2.39 × 10^-20 D) 2.7 × 10^9E) 4.5 × 10^-25

Answers

The energy of a photon can be found using the following equation:

What we're going to do is to replace the values of the constant and the value of the wavelength in the expression above. This is:

Therefore, the correct answer option is C. 2.39 × 10^-20 J.

HURRY! NEED WITHIN 10 MINS

Answers

The equation of photosynthesis is shown in the image attached to this question.

What is photosynthesis?

The term photosynthesis has to do with a kind of reaction that helps plants to make their own food. The process involves the combination of carbon dioxide and water in the presence of sunlight to give glucose and water only.

We know that the green plants are autotrophic thus they are able to make their own food. The process of photosynthesis produces the food that is passed along the food chain in the ecosystem.

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The half-life for the first order radioactive decay of lodine - 131 is 8.0 days. After 3 half lives, what percentage of a sample of locine-131)remains?O 50.%O 25%,O 12.5%O 1%

Answers

Answer:

12.5 %.

Explanation:

Let's see the half-life formula:

[tex]N(t)=N_0\cdot(\frac{1}{2})^{t\text{/h}}.[/tex]

Where N₀ is the initial amount, t is time, and h is the half-life.

We want to know what would be the percentage of a sample of iodine-131 that remains. This is the same that N(t)/N₀, so we have to replace the given data in the formula and multiply it by 100 because it is a percentage.

The half-life of iodine-131 is 8.0 days, and 3 half-lives are equal to 24 days (8.0 x 3 = 24):

[tex]\begin{gathered} \frac{N(t)}{N_0}=(\frac{1}{2})^{t\text{/h}}, \\ (\frac{1}{2})^{24\text{/8}}=(\frac{1}{2})^3=\frac{1}{8}=0.125. \\ We\text{ want the result in percentage, so multiplying by 100}\%,\text{ we obtain:} \\ 0.125\cdot100\%=12.5\%. \end{gathered}[/tex]

The answer would be 12.5 %.

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