which inequality represents all values for x for which the quotient below is defined? square root of 8x squared divided by the square root of 2x

Answer: 31112

Step-by-step explanation:

Answer: It's 31,112.

Step-by-step explanation:

Graph: y=−2x is a linear equation in slope-intercept form: ... The x-intercept is the value of x when y=0 , and the y-intercept is the value of y when x=0 .

Hope this helps! Have a great day!

Answer:

I think it's C

Step-by-step explanation:

Answer:

(4, 1)

Step-by-step explanation:

Since there's a graph, the answer is the intersection: (4, 1)

But here's the cancellation method for future use :)

Answer:

Slope = 0

Step-by-step explanation:

Given the pair of points: (-3,2) (7,2)

Slope formula: y2-y1/x2-x1

2-2/7-(-3) = 0/10

0/10 = 0

Answer:

x=57

Step-by-step explanation:

a triangle has a sum of 180 degrees

that angle 51 is vertical to the angle across it so it is 51

we do math now

180-72-51=57

I hope this helped :))

Answer:

The answer is

90 degrees the first one is I don't know about the rest sorry

Step-by-step explanation:

Answer: There were 525 pine trees.

Step-by-step explanation:

Given: Total trees = 1250

Percentage of oak trees = 32%

Percentage of birch trees = 26%

Since remaining trees are pine trees.

Percentage of pine trees = 100% - 32% - 26%

=42%

The number of pine trees = 42% of 1250

= 0.42 ×1250

= 525

Hence, there were 525 pine trees.

Answer:

No solution

Step-by-step explanation:

because the are parallel lines they never meet so they are inconsistent so there is no solution

Answer:

7/8

Step-by-step explanation:

Answer:

34%

Step-by-step explanation:

I meant be a couple PREcents OFF BUT IM SORRY THIS IS MY BEST ANSWR :( hope this helps tho :)

Answer:

because they are both similar. they both accept the law of karma and release from the cycle of birth. one of the key differences is

buddhist only believe in one god. hinduism believes in multiple gods

Answer:

hey emanii

Step-by-step explanation:

Answer:

it's is the last one 1 out of 6

Answer:

Harry is paid £64

Step-by-step explanation:

To work this out you have to divide 48 ÷ 6 to get 8.

8 hours x £8 = £64

Answer:

64

you have to find the LCM of 48 including 6 and use the other number which is 8 and multiply it by how long Harry worked 8 hours which gives you £64

Answer:

answer is B

Step-by-step explanation:

he goes up

Answer:

P will remain the same

Step-by-step explanation:

Given

[tex]V(t) = P(1 + r)^t[/tex] --- Coin value formula [Missing from the question]

Required

What happens to p when r increases

The coin value function is an exponential function which is of the general  form:

[tex]y = a(1 + b)^x[/tex]

From the given function: [tex]V(t) = P(1 + r)^t[/tex]

P represents the initial value and r represents the rate

The rate of change (r) and the initial value (P) of a function are both independent, and they do not depend on one another for their values.

An increment or decrement in r will not affect the value of P.

Conclusively, when the rate (r) changes, the initial value (P) will remain the same.

Answer:

20 ≥ x

Step-by-step explanation:

Alex has $20 or less to spend at the store

Answer:

the mechanical advantage increases as the height increases.

Step-by-step explanation:

Answer:

x = 23

y = 17

Step-by-step explanation:

x = 1st number

y = 2nd number

System of Equations:

x + y = 40

x - y = 6;    this can be used as x = 6+y

6+y + y = 40

6 + 2y = 40

2y = 34

y = 17

x + 17 = 40

x = 23

[tex]\huge\text{Hey there!}[/tex]

[tex]\large\text{c + 28 = 67}\\\\\large\text{SUBTRACT by 28 to BOTH SIDES}\\\\\large\text{c + 28 - 28 = 67 - 28}\\\\\large\text{Cancel out: 28 - 28 because that gives you 0}\\\\\large\text{Keep: 67 - 28 because it helps you solve for your c-value}\\\\\large\text{67 - 28 = 39}\\\\\boxed{\boxed{\large\text{Answer: \bf c = 39}}}\huge\checkmark[/tex]

[tex]\text{Good luck on your assignment and enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

Answer:

y = 8 root 2

Step-by-step explanation:

Since it is a 90-45-45 triangle, y is s root 2

s = 8

so, y = 8 root 2

Answer:

y=8√2

Step-by-step explanation:

Because 2 of the angles are the same, the triangle is isosceles (because of base angles theorem). Therefore, x=8. Using Pythagoras theorem, y=8√2.

Answer:

y = 5

Step-by-step explanation:

The y-axis and any lines that are parallel to it are vertical. Therefore, a line that would be perpendicular to the y-axis would need to be horizontal. All horizontal lines have a slope equal to 0 and are represented by the equation y = a constant, or a single number with no variables.  

The only option that follows that format is y = 5, thus that is the answer.  

Answer:

multiply both numbers and if im correct it should be 124ft sorry if im wrong

Answer:

a. False

b. z = 8

Step-by-step explanation:

a. Equation answer:2 + 6 = 10 Real answer:2 + 6 = 8

b. 3 + 5 = 8

Answer:

Does this count as stander form 6.95880148018

Step-by-step explanation:

Answer:

volume = 2 x 2 x 2 = 8 cm²

Step-by-step explanation:

Answer:

[tex]\cot(x)+\cot(\frac{\pi}{2}-x)[/tex]

[tex]\cot(x)+\tan(x)[/tex]

[tex]\frac{\cos(x)}{\sin(x)}+\frac{\sin(x)}{\cos(x)}[/tex]

[tex]\frac{1}{\sin(x)}(\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)})[/tex]

[tex]\csc(x)(\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)})[/tex]

[tex]\csc(x)[\frac{\cos(x)\cos(x)}{\cos(x)}+\sin(x)\frac{sin(x)}{\cos(x)}][/tex]

[tex]\csc(x)[\frac{\cos(x)\cos(x)+\sin(x)\sin(x)}{\cos(x)}][/tex]

[tex]\csc(x)[\frac{\cos^2(x)+\sin^2(x)}{\cos(x)}][/tex]

[tex]\csc(x)[\frac{1}{\cos(x)}][/tex]

[tex]\csc(x)[\sec(x)][/tex]

[tex]\csc(x)[\csc(\frac{\pi}{2}-x)][/tex]

[tex]\csc(x)\csc(\frac{\pi}{2}-x)[/tex]

Step-by-step explanation:

I'm going to use [tex]x[/tex] instead of [tex]\theta[/tex] because it is less characters for me to type.

I'm going to start with the left hand side and see if I can turn it into the right hand side.

[tex]\cot(x)+\cot(\frac{\pi}{2}-x)[/tex]

I'm going to use a cofunction identity for the 2nd term.

This is the identity: [tex]\tan(x)=\cot(\frac{\pi}{2}-x)[/tex] I'm going to use there.

[tex]\cot(x)+\tan(x)[/tex]

I'm going to rewrite this in terms of [tex]\sin(x)[/tex] and [tex]\cos(x)[/tex] because I prefer to work in those terms. My objective here is to some how write this sum as a product.

I'm going to first use these quotient identities: [tex]\frac{\cos(x)}{\sin(x)}=\cot(x)[/tex] and [tex]\frac{\sin(x)}{\cos(x)}=\tan(x)[/tex]

So we have:

[tex]\frac{\cos(x)}{\sin(x)}+\frac{\sin(x)}{\cos(x)}[/tex]

I'm going to factor out [tex]\frac{1}{\sin(x)}[/tex] because if I do that I will have the [tex]\csc(x)[/tex] factor I see on the right by the reciprocal identity:

[tex]\csc(x)=\frac{1}{\sin(x)}[/tex]

[tex]\frac{1}{\sin(x)}(\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)})[/tex]

[tex]\csc(x)(\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)})[/tex]

Now I need to somehow show right right factor of this is equal to the right factor of the right hand side.

That is, I need to show [tex]\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)}[/tex] is equal to [tex]\csc(\frac{\pi}{2}-x)[/tex].

So since I want one term I'm going to write as a single fraction first:

[tex]\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)}[/tex]

Find a common denominator which is [tex]\cos(x)[/tex]:

[tex]\frac{\cos(x)\cos(x)}{\cos(x)}+\sin(x)\frac{sin(x)}{\cos(x)}[/tex]

[tex]\frac{\cos(x)\cos(x)+\sin(x)\sin(x)}{\cos(x)}[/tex]

[tex]\frac{\cos^2(x)+\sin^2(x)}{\cos(x)}[/tex]

By  the Pythagorean Identity [tex]\cos^2(x)+\sin^2(x)=1[/tex] I can rewrite the top as 1:

[tex]\frac{1}{\cos(x)}[/tex]

By the quotient identity [tex]\sec(x)=\frac{1}{\cos(x)}[/tex], I can rewrite this as:

[tex]\sec(x)[/tex]

By the cofunction identity [tex]\sec(x)=\csc(x)=(\frac{\pi}{2}-x)[/tex], we have the second factor of the right hand side:

[tex]\csc(\frac{\pi}{2}-x)[/tex]

Let's just do it all together without all the words now:

[tex]\cot(x)+\cot(\frac{\pi}{2}-x)[/tex]

[tex]\cot(x)+\tan(x)[/tex]

[tex]\frac{\cos(x)}{\sin(x)}+\frac{\sin(x)}{\cos(x)}[/tex]

[tex]\frac{1}{\sin(x)}(\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)})[/tex]

[tex]\csc(x)(\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)})[/tex]

[tex]\csc(x)[\frac{\cos(x)\cos(x)}{\cos(x)}+\sin(x)\frac{sin(x)}{\cos(x)}][/tex]

[tex]\csc(x)[\frac{\cos(x)\cos(x)+\sin(x)\sin(x)}{\cos(x)}][/tex]

[tex]\csc(x)[\frac{\cos^2(x)+\sin^2(x)}{\cos(x)}][/tex]

[tex]\csc(x)[\frac{1}{\cos(x)}][/tex]

[tex]\csc(x)[\sec(x)][/tex]

[tex]\csc(x)[\csc(\frac{\pi}{2}-x)][/tex]

[tex]\csc(x)\csc(\frac{\pi}{2}-x)[/tex]