When gas is added to the box, the number of molecules in the box will increase.
This will result in an increase in pressure as volume is fixed or constant.
As the box has a fixed volume, this will be an isochoric process.
In an isochoric process, the pressure is directly proportional to temperature, so the temperature will also increase.
Thus, pressure and temperature will increase when gas is added to a box.
A car travels at a constant speed of 12 m/s and has a momentum of 4800 kg∙m/s. What is the mass of the car?
Take into account that the momentum is given by the following formula:
[tex]p=mv[/tex]where,
m: mass of the car = ?
v: speed = 12 m/s
p: momentum = 4800 kg*m/s
Solve the equation above for m, replace the values of p and v, and simplify:
[tex]m=\frac{p}{v}=\frac{4800kg\frac{m}{s}}{12\frac{m}{s}}=400kg[/tex]Hence, the mass of the car is 400 kg
What is the total mechanical energy of a 3 kg object traveling at 7 m/s if its potential energy is 42 J?
The mechanical energy of the a 3kg object at 7m/s and having a potential energy of 42J is 115.5 J.
What is the mechanical energy of the object?Mechanical energy is simply energy accumulated due to performing some particular work. It is the sum of the potential energy and kinetic energy of an object. It is expressed as;
Mechanical energy = Potential energy + Kinetic energy
Given the data in the question;
Mass of the object m = 3kgVelocity of the object v = 7m/sPotential energy of the object = 42JFirst, we determine the kinetic energy of the object.
Kinetic energy = 1/2 × mass × ( velocity )²
Plug in the given values
Kinetic energy = 1/2 × 3kg × ( 7m/s)²
Kinetic energy = 1/2 × 3kg × 49m²/s²
Kinetic energy = 73.5kgm²/s²
Kinetic energy = 73.5J
Now, the mechanical energy of the object will be;
Mechanical energy = Potential energy + Kinetic energy
Plug in the values
Mechanical energy = 42J + 73.5J
Mechanical energy = 115.5 J
Therefore, the mechanical energy is 115.5 Joules.
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Answer:
The answer is 115.5 guyssss
Explanation:
A particular heating element draws 18.014 A of current and heats 176.251 g of water from 20oC to 87.714oC in 7.167 minutes. What is the resistance of the heating element ? Specific heat of water is 4.186 J/g deg C.
Given:
The current drawn by the heating element is: I = 18.014 A.
Mass of the water is: m = 176.251 g.
The temperature difference of water is: T = 87.714 deg C - 20 deg C = 67.714 deg C.
Time for which the change in temperature occurs: t = 7.167 minutes
The specific heat of water is: c = 4.186 J/g degC.
To find:
The resistance of the heating element.
Explanation:
The expression for the heat is given as:
[tex]Q=mcT[/tex]Substitute the values in the above equation, we get:
[tex]\begin{gathered} Q=176.251\text{ g}\times4.186\text{ J/g deg C}\times67.714\text{ deg C} \\ \\ Q=49958.4876\text{ J} \end{gathered}[/tex]Joule's equation for electric heating is given as:
[tex]Q=I^2Rt[/tex]Here, R is the resistance of the heating element.
Rearranging the above equation, we get:
[tex]R=\frac{Q}{I^2t}[/tex]Substituting the values in the above equation, we get:
[tex]\begin{gathered} R=\frac{49958.4876\text{ J}}{18.014^2\text{ A}^2\times7.167\text{ m}} \\ \\ R=\frac{49958.4876\text{ J}}{324.5042\text{ A}^2\times7.167\times60\text{ s}} \\ \\ R=0.3580\text{ }\Omega \end{gathered}[/tex]Final Answer:
The resistance of the heating element is 0.3580 Ω.
A lamp draws a current of 0.50 A when it is connected to a 120 V source. What is the resistance of the lamp?1) 4.17 10-2 ω2) 60 ω3) 2.4 102 ω4) 24 102 ω
Given data:
* The voltage of the given source is,
[tex]V=120\text{ Volts}[/tex]* The current through the lamp is,
[tex]I=0.5\text{ A}[/tex]Solution:
By the Ohm's law,
[tex]V=IR[/tex]where R is the resistance of the lamp,
Substituting the known values,
[tex]\begin{gathered} 120=0.5\times R \\ R=\frac{120}{0.5} \\ R=240\text{ }\Omega \\ R=2.4\times10^2\text{ }\Omega \end{gathered}[/tex]Thus, 3rd option is the correct answer.
Water flows with a velocity of 1.50 m/s through a tube with an internal diameter of 1.10 cm. As it exits the tube, the fluid velocity through the nozzle increases to 10 m/s. What is the inside diameter of the nozzle? You can treat the tube as a long cylinder so that the cross-sectional area both in the interior of the tube and the nozzle is the area of a circle.Group of answer choices
In order to calculate the inside diameter, we can use the following relation, since the volumetric flow is constant for any part of the tube:
[tex]\begin{gathered} Q_1=Q_2 \\ A_1V_1=A_2V_2 \end{gathered}[/tex]Where A is the cross-section area and V is the velocity.
Using V1 = 1.5 m/s, A1 = π*1.1²/4 and V2 = 10 m/s, we have:
[tex]\begin{gathered} \frac{\pi\cdot1.1^2}{4}\cdot1.5=A_2\cdot10 \\ \frac{\pi\cdot1.1^2}{4}\cdot1.5=\frac{\pi\cdot d^2_2}{4}\cdot10 \\ 1.1^2\cdot1.5=d^2_2\cdot10 \\ 1.21\cdot1.5=d^2_2\cdot10 \\ 1.81=d^2_2\cdot10 \\ d^2_2=0.181 \\ d_2=0.42\text{ cm}=4.2\text{ mm} \end{gathered}[/tex]Therefore the correct option is the first one.
Answer:
2.1 mm
Explanation:
I check it the 4.2mm answer is WRONG
A beaker of mass 1.2 kg containing 2.5 kg of water rests on a scale. A 3.8 kg block of a metallic alloy of density 3300 kg/m3 is suspended from a spring scale and is submerged in the water of density 1000 kg/m? as shown in the figure. a) What does the hanging scale read? acceleration of gravity is 9.8 m/s?Answer in units of N.b) what does the lower scale read? Answer in units of N.
ANSWER:
a) 25.97 N
b) 47.53 N
STEP-BY-STEP EXPLANATION:
Given:
Beaker mass = 1.2 kg
Water mass = 2.5 kg
Water density = 1000 kg/m^3
Block mass = 3.8 kg
Block density = 3300 kg/m^3
a)
The first thing is to calculate the volume of the block, like this:
[tex]\begin{gathered} d=\frac{m}{V} \\ V=\frac{m}{d} \\ \text{ we replacing} \\ V=\frac{3.8}{3300} \\ V=0.00115m^3 \end{gathered}[/tex]Mass of water displaced by the block is:
[tex]\begin{gathered} d=\frac{m}{V} \\ m=d\cdot V \\ m=1000\cdot0.00115 \\ m=1.15kg \end{gathered}[/tex]The block will receive a push from the water equal to the weight of the water displaced by the block, or the effective weight of the block will be reduced by the same amount:
[tex]\begin{gathered} W=(m_b-m)\cdot g \\ \text{ we replacing} \\ W=(3.8-1.15)\cdot9.8 \\ W=25.97\text{ N} \end{gathered}[/tex]Therefore, 25.97 N is the reading on the hanging scale.
b)
The bottom scale will gain by the same amount (1.15 kg). Therefore, the totalweight on the bottom scale is:
[tex]\begin{gathered} W=(1.2+2.5+1.15)\cdot9.8 \\ W=4.85\cdot9.8 \\ W=47.53\text{ N} \end{gathered}[/tex]Therefore, 47.53 N is the reading on the lower scale.
Technically, how would you know if any work was done on an object? Work referring to the physics Term
ANSWER and EXPLANATION
We want to know how to tell if work is done on an object.
Work is a result of a force acting on an object that thereby causes a displacement of the object. It is defined mathematically as:
[tex]W=F\cdot d[/tex]where F = force; d = displacement
Therefore, we say that work is done on an object when a force is applied to the object and it causes the object to move a certain distance.
A4 resistor is connected to a 12-V battery. What is thecurrent through the battery? What is the power dissipatedby the resistor?
According to Ohm's law,
So the current is given as,
The power dissipated by the resistor is given as,
Hence, 3 A of current passes through the resistor and power dissipated is 36 W.
[tex]\begin{gathered} P=I^2R \\ =(3A)^2\times4\text{ }\Omega \\ =36\text{ W} \end{gathered}[/tex][tex]\begin{gathered} I=\frac{V}{R} \\ I=\frac{12\text{ V}}{4\text{ }\Omega} \\ I=3\text{ A} \end{gathered}[/tex][tex]V=IR[/tex]Sound travels with an average speed of 340m/s. Lightning from a distant storm cloud is seen almost immediately. If the sound reaches our ear 2s later. how far is the storm
Hello..!
To calculate its distance we apply the following data.
Data:
V = 340m/sT = 2sD = ?Then, we apply the formula that is.
Formula:
D = V • TFinally we develop the problem.
Developing:
D = (340m/s) • (2s)D = 680mThe storm is at a distance of 680 meters
Answer:
Formula
D = V • TResolve:
D = (340m/s) • (2s)D = 680mHope this helped
A beam of microwaves has a frequency of 3.0*10^ 11Hz. Radio waves have a frequency of 3.0*10^9 Hz. Calculate the wavelength of each. Which type of radiation has the longer wavelength?
We will have the following:
Assuming both are traveling in vacuum we will have the following:
Microwaves:
[tex]\lambda_m=\frac{3.00\cdot10^8}{3.0\cdot10^{11}}\Rightarrow\lambda_m=1\cdot10^{-3}m[/tex]Radio:
[tex]\lambda_r=\frac{3.0\cdot10^8}{3.0\cdot10^9}\Rightarrow\lambda_r=1\cdot10^{-1}m[/tex]So, radio waves have a longer wavelength.
i) How many grams of CO₂ is formed when 73.9g of propane is burnt? C3H8+ O2 CO2 + H₂O
73.9g CO₂ is formed when 73.9g or 1 mole of propane is burnt
C₃H₈+ 5O₂ ⇄ 3CO₂ + 4H₂O
1 mole C₃H₈ gives 3 moles of CO₂
44 g C₃H₈ gives 44 g CO₂
73.9g C₃H₈ gives 73.9g CO₂
Quantifying the amount of a substance is made easier with the help of the mole concept. It is understood that even a single gram of a pure element has a sizable number of atoms when dealing with particles at the atomic (or molecular) level. In this regard, the mole notion is frequently used. The "mole," which is a count of a large number of particles, is the most commonly used unit of measurement.
The letter NA is typically used to indicate the value 6.02214076*1023, also known as the Avogadro constant. Atoms, molecules, monoatomic and polyatomic ions, as well as other particles, are among the elementary entities that can be represented in moles (such as electrons).
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Unit 5 Discussion 2 Graded Discussion Exit Discussion Topic Please post detailed answers to the following questions. Please use complete sentences. Sometimes, foodborne illness causes an outbreak that affects a large number of people. These cases tend to make news, either to report on the condition of victims or to warn the public of a possible danger. Research one recent outbreak connected to foodborne illness. Discuss what the cause of the outbreak was, whether it was caused by a pathogen or parasite, what signs the victims showed, and how the outbreak might have been prevented.
A recent food poisoning has caused an outbreak that is affecting many people. Reported in June 2007.
Explain a disease outbreak?An outbreak can be explained as sudden increase in the number of cases of a disease. It may occur in one community or geographical area, or affect multiple countries. It may last for days to weeks sometime even years. Several outbreaks are expected each year. B. Influenza.
The recent ground beef recall was expanded to 5.7 million pounds after 14 E. coli O₁₅₇:H₇ were identified, according to the United States Department of Agriculture (USDA), which discusses E. coli outbreaks associated with ground beef.
Outbreak was the result of extensive contamination of ground beef.
E. coli infections vary, but the most common signs of infection are:
Severe stomach cramps.Vomiting.Diarrhea/Bloody stoolSlight feverSymptoms of a severe E. coli infection may include:
Bloody urineReduced urine outputBruisingPale skinDehydrationThere is no vaccine against E. coli infection and no drugs recommended for prevention. Taking antibiotics can affect your gut flora and increase your susceptibility to intestinal infections. However, there are some things you can do to reduce your risk.
How to prevent E. coli infection
Wash fruits and vegetables well Avoid cross-contamination by using clean utensils, pans and serving dishes. Keep raw meat away from other foods and clean surfaces. Do not defrost meat on the counter, but defrost it in the refrigerator or microwave.To know more about E. coli visit:
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Hey I need help with my homework not understanding the problem can someone please help
Answer:
a. 4 g/mL
Explanation:
First, we need to find the volume of the object. The volume is equal to the volume of the water displaced. So, it can be calculated as the difference in the volumes
75 mL - 50 mL = 25 mL
Then, the volume of the object is 25 mL and the mass is 100 g. Now, we can calculate the density as follows
density = mass/volume
density = 100 g/25 mL
density = 4 g/mL
Therefore, the answer is
a. 4 g/mL
which are types of matter?select all that apply subtance mixtureforcecompoundsunlight
The following choices are matter:
• substance
,• mixture
,• compound
Which of the following is a pair of vector quantities?1) Speed — Distance2) Velocity — Distance3) Velocity — Displacement4) Speed — Displacement
Remember that vector quantities include a magnitude and direction, while scalar quantities include only a magnitude.
Speed is a scalar quantity.
Distance is a scalar quantity.
Velocity is a vector quantity.
Displacement is a vector quantity.
Then, from the options, the one which is a pair of vector quantities, is:
3) Veocity - Displacement
A cube has a drag coefficient of 0.8. What would be the terminal velocity of a sugar cube 1 cm on a side in air ( = 1.2 kg/mº)? Take thedensity of sugar to be 2.0 x 103 kg/m3. im/s
0.495 m/s
Explanation
the formula for the terminal velocity is given by:
[tex]\begin{gathered} v=\sqrt[]{\frac{2mg}{\sigma AC}} \\ \text{where} \\ \end{gathered}[/tex]m is the mass
g is 9.81 m/s²
ρ is density
A is area
C is the drag coefficient
then
Step 1
Let's find the mass
[tex]\begin{gathered} \sigma=\frac{m}{v} \\ m=\sigma\cdot v \\ \text{mass}=(2\cdot10^3\frac{\operatorname{kg}}{m^3})\cdot(0.01m)^3 \\ \text{mass}=(2\cdot10^3\frac{\operatorname{kg}}{m^3})\cdot(1\cdot10^{-6}) \\ \text{mass}=2\cdot10^{-3}\operatorname{kg} \\ \text{mass}=0.002\text{ kg } \\ \text{Area}=(0.01\text{ m}\cdot0.01m)=0.0001m^2 \end{gathered}[/tex]now, replace
[tex]\begin{gathered} v=\sqrt[]{\frac{2mg}{\sigma AC}} \\ v=\sqrt[]{\frac{2(0.002kg)(9.81\text{ }\frac{m}{s^2})}{(2\cdot10^3\frac{\operatorname{kg}}{m^3})(0.0001m^2)0.8}} \\ v=\sqrt[]{\frac{0.03924\frac{\operatorname{kg}m}{s^2}}{0.16\frac{\operatorname{kg}}{m^{}}}} \\ v=\sqrt[]{0.2452\frac{m^2}{s^2}} \\ v=0.495\text{ m/s} \end{gathered}[/tex]hence, the answer is 0.495 m/s
How do I solve this problem? 1. Draw the forces -trailer: weight downwards, normal force upwards, tension right and drag lefttruck: weight downwards, normal force upwards, tension left, drag left, thrust/applied right2. The system is moving with a constant speed, so the forces are balanced!3. Start by just looking at the trailer. The tension to the right must balance the drag. This will also be equal to the tension on the truck. 4. Now, just look at the truck. The thrust/applied force must balance the drag plus the tension.
A force diagram of the given situation is shown below:
where,
N1 and N2: normal forces on truck and trailer
fg1 and fg2: weights of truck and trailer
d1 and d2: drag forces on truck and trailer
T: tension in the cable
Based on the previous diagram and the given information, you can conclude:
Forces acting on the truck = 5
Forces acting on the trailer = 4
The forces of the system are balanced becasue the speed of the motion for both truck and trailer is constant.
You can notice that drag force on the trailer is opposite to tension in the cable, then:
T = d2 = 600N
T = 600N
The tension in the cable is 600N
Consider that all horizontal forces on the truck are balanced, then, you can write:
th = T + d1
th = 600N + 750N
th = 1350N
The truck generates 1350N of force
So I have these kinematics questions and I’m having a hard time answering it. It says:While riding a hot air balloon, which is steadily descending at a speed of 2.52 m/s, you accidentally drop your cell phone.(a) After 4.00 s, what is the speed of the cell phone?(b) How far is the cell phone below the balloon after this time?(c) What are your answers to part (a) and (b) if the balloon id rising steadily at 2.52 m/s?
a)
Objects moving under free fall have a constant acceleration g, which is the gravitational acceleration, directed downwards:
[tex]g=9.81\frac{m}{s^2}[/tex]Since the balloon is descending at a speed of 2.52 m/s, the initial speed of the phone is 2.52 m/s. To find the speed after 4.00 seconds, use the formula that comes from the definition of acceleration:
[tex]v_f=v_0+gt[/tex]Substitute the value for each parameter:
[tex]\begin{gathered} v_f=2.52\frac{m}{s}+(9.81\frac{m}{s^2})(4.00s) \\ =2.52\frac{m}{s^2}+39.24\frac{m}{s} \\ =41.76\frac{m}{s} \end{gathered}[/tex]b)
From the reference frame of the balloon, the cellphone starts falling from rest, and accelerates with a constant acceleration g.
The equation that describes the distance traveled by an object that starts from rest and moves with constant acceleration g is:
[tex]d=\frac{1}{2}gt^2[/tex]Substitute the values of g and t to find how far is the cell phone below the balloon after 4 seconds:
[tex]\begin{gathered} d=\frac{1}{2}(9.81\frac{m}{s^2})(4.00s)^2 \\ =78.48m \end{gathered}[/tex]c)
If the balloon is rising steadly at 2.52 m/s instead of descending, then the acceleration of the cellphone will be directed in the opposite direction of its initial speed. Then, the initial speed and the acceleration must have opposite signs. Considering the upward direction as positive, we have that the initial speed of the phone is 2.52 m/s and its acceleration is -g. Then:
[tex]\begin{gathered} v_f=(2.52\frac{m}{s})-(9.81\frac{m}{s})(4.00s) \\ =2.52\frac{m}{s}-39.24\frac{m}{s} \\ =-36.72\frac{m}{s} \end{gathered}[/tex]The speed is the modulus of the velocity. Then, the speed of the phone after 4 seconds in this situation, would be 36.72 m/s.
On the other hand, in the reference frame of the rising balloon, the phone still starts moving at rest and accelerating uniformly towards the floor. The answer will be the same, and the phone will be 78.48 m below the balloon after 4 seconds.
Therefore, the answers with the correct amount of significant figures, are:
a)
[tex]41.8\frac{m}{s}[/tex]b)
[tex]78.5m[/tex]c)
[tex]\begin{gathered} a) \\ 36.7\frac{m}{s} \end{gathered}[/tex][tex]\begin{gathered} b) \\ 78.5m \end{gathered}[/tex]Consider the equation −4x−y=3 A line parallel to the above line would have a slope of Correct A line perpendicular to the above line would have a slope of
ANSWER:
Paralell: -4
Perpendicular: 1/4
STEP-BY-STEP EXPLANATION:
We have the following equation:
[tex]-4x-y=3[/tex]Now, we have that an equation of a line in its slope-intercept form has the following form:
[tex]\begin{gathered} y=mx+b \\ \text{where m is the slope and b is y-intercept} \end{gathered}[/tex]We apply it in this case:
[tex]\begin{gathered} -y=4x+3 \\ y=-4x-3 \\ \text{therefore} \\ m=-4 \end{gathered}[/tex]When two lines are parallel, the slope is the same, while when they are perpendicular, the product of the slopes is equal to -1, we calculate each case below as follows:
[tex]\begin{gathered} \text{ Parallel} \\ m_1=m_2 \\ m_2=-4 \\ \\ \text{ Perpendicular} \\ m_1\cdot m_2=-1 \\ m_2=\frac{-1}{m_1} \\ m_2=\frac{-1}{-4} \\ m_2=\frac{1}{4} \end{gathered}[/tex]Two straight wires located one-fifth of a meter from each other carry current in different directions. Current I1 = 13 A is into the page and I2 = 18 A is out of the page. Determine the magnitude and direction of the magnetic field for each of the wire and determine the magnitude of the magnetic field between the two wires.
The given situation can be illustrated as follow:
The red circles repersent the magnetic field produced by the currents on the wire.
As you can notice, between the wires the direction of the magnetic field is the same.
Consider that the magnetic field produced by a current I in a wire, at a distance r, is given by the following formula:
[tex]B=\frac{\mu_0I}{2\pi r}[/tex]where,
r: distance at the center betwen the wires = 0.20m/2 = 0.10m
μ0: permeability of free space = 4π*10^-7 Tm/A
Then, the total magnetic field between the wire is the sum of the magnetic fields generated by each wire:
[tex]B=\frac{\mu_0}{2\pi(0.10m)^2}(I_1+I_2)=\frac{4\pi\cdot10^{-7}Tm\text{ /A}}{2\pi(0.10m)^2}(13A+18A)=6.2\cdot10^{-4}T[/tex]using the ladder method, what is 480 cm = ________m
We have
480 cm
In order to know how many meters are 480 cm, we need to move the point two units to the left because the prefix centi represents 0.01 of the unit
therefore
480 cm = 4.8m
Two equal, but oppositely charged particles are attracted to each other electrically. The size of the force of attraction is 56.46 N when they are separated by 50.91 cm. What is the magnitude of the charges in microCoulombs?
q = 40.3 microCoulombs
Explanation:The force of attraction between two charges is given by the formula:
[tex]F=\frac{kq^2}{r^2}[/tex]The force of attraction. F = 56.46 N
The separation, r = 50.91 cm
r = 50.91/100
r = 0.5091 m
The electrostatic constant is:
[tex]k=9\times10^9Nm^2C^{-2}[/tex]Solve for the magnitude of charge q
[tex]\begin{gathered} F=\frac{kq^2}{r^2} \\ \\ 56.46=\frac{9\times10^9\times q^2}{0.5091^2} \\ \\ 56.46\times0.5091^2=9\times10^9\times q^2 \\ \\ q^2=\frac{56.46\times0.5091^2}{9\times10^9} \\ \\ q^2=1.63\times10^{-9} \\ \\ q=\sqrt{1.63\times10^{-9}} \\ \\ q=4.03\times10^{-5}C \\ \\ q=40.3\mu C \end{gathered}[/tex]A race car traveling northward on a straight, level track at a constant speed travels 0.739 km in 18.0 s. The return trip over the same track is made in 23.0 s.What is the average velocity (in m/s) for the total trip?answer in : m/s
The average velocity of an object is given by:
[tex]\begin{gathered} v=\frac{\Delta x}{t} \\ \text{ where }\Delta x\text{ is the displacement and }t\text{ is the time } \end{gathered}[/tex]In this case we know that the car travelled a track and the return on it; this means that the displacement of the car is zero and therefore, the average velocity is zero
The graph below shows the motion of an object. What is the velocity of the moving object between 8s and 18s
We have the next graph
As we can see in red we can see the velocity of the moving object between 8s and 18s , therefore the velocity is -5
ANSWER
Option A.
I need help with all these all in da bottomA bike moves 50 m in 5 seconds. calculate the speed
Answer:
Step 1
S = ?
ΔD = 50 m
ΔT = 5 s
Step 2
S = ΔD/ΔT
Step 3
S = ΔD/ΔT
Step 4
S = (50 m)/(5 s)
Step 5
S = 10 m/s
Explanation:
Step 1. variables.
The variables are the speed S, the distance traveled ΔD, and the time ΔT. Taking into account the given information, the speed is unknown, the distance traveled is 50 m and the time is 5 s. so:
S = ?
ΔD = 50 m
ΔT = 5 s
Step 2. Formula
We will use the following formula
S = ΔD/ΔT
Step 3. Solve for the unknown variable
Since the unknown variable is S, the equation is the same, so
S = ΔD/ΔT
Step 4. Plug in number
Now, we need to replace ΔD = 50 m and ΔT = 5 s on the equation
S = (50 m) /(5s)
Step 5. Calculate the answer
Then, the speed is equal to
S = 10 m/s
Therefore, the answer is:
10 m/s
Determine Force. 589J of work was accomplished over a distance of 1100m, how much force was exerted? Include the correct units.
Answer:
Explanation:
Given:
A = 589 J
D = 1 100 m
____________
F - ?
A = F·D
F = A / D = 589 / 1100 ≈ 0.54 N
An object has a kinetic energy of 12,000 J and a mass of 48.7 kg. Find the velocity of the object.I need help with this problem pls
Given:
The kinetic energy of the object is K = 12000 J.
The mass of the object is m = 48.7 kg
To find the velocity of the object.
Explanation:
The velocity of the object will be
[tex]\begin{gathered} K=\frac{1}{2}mv^2 \\ v=\sqrt{\frac{2K}{m}} \\ =\sqrt{\frac{2\times12000}{48.7}} \\ =22.199\text{ m/s} \end{gathered}[/tex]Thus, the velocity of the object is 22.199 m/s.
Can you please help me with #6 (the 6 was wrong in the question it meant #5 as you can see I tried to change it)
You drop a rock down a well that is 11.5m deep. How long does it take the rock to hit the bottom of the well?
a. 2.3 s
b. 2.8 s
c. 1.5 s
d. 3.1 s
The electromagnetic force that acts on the protons in the nucleus of an atom is _____ the strong nuclear force that acts on the same nucleus.Question 10 options:stronger thanweaker thanthe same asapproximately half
ANSWER
Weaker than
EXPLANATION
There are four fundamental forces that occur in nature (in atoms):
=> Strong force
=> Electromagnetic force
=> Gravitational force
=> Weak force
Of all these forces, the strong force is the strongest.
This means that the electromagnetic force that acts on the protons in the nucleus of an atom is weaker than the strong nuclear force that acts on the same nucleus.
The answer is 'weaker than".