The wavelength of wave is 0.15×10⁸m if its frequency is 20Hz.Waves need medium to travel from one place to another.
Expecting a sinusoidal wave moving at a proper wave speed, frequency is conversely corresponding to recurrence of the wave: waves with higher frequencies have more limited frequencies, and lower frequencies have longer wavelengths.
Frequency relies upon the mode (for instance, vacuum, air, or water) that a wave goes through. Instances of waves are sound waves, light, water waves and occasional electrical signs in a conduit.
For electromagnetic wave ,we know an expression
c=ν × λ
where c is the defined as the speed of wave in any medium,
ν is defined as the frequency of the wave and
λ is defined as the wavelength of the wave.
We know that value of c=3×10⁸m/sec and we have v=20Hz
Therefore,3×10⁸=20×λ
=>λ=(3×10⁸)/20
=>λ=0.15×10⁸m
Hence, wavelength of wave is 0.15×10⁸m.
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A 8. 0-m long wire with a mass of 10 g is under tension. A transverse wave for which the frequency is 570 hz, the wavelength is 0. 10 m, and the amplitude is 3. 7 mm is propagating on the wire. The maximum transverse acceleration of a point on a wire is closest to.
The maximum transverse acceleration of a point on a wire is 47410.0839m/sec² having mass of 10g.
Transverse Wave travels from highest point of positive amplitude to negative highest point amplitude. Amplitude is the point where potential energy of wave is highest. Transverse wave travels in definite direction. We have mass=10g=0.001kg,length of wire is 8m,frequency of transverse wave is 570Hz,wavelength =0.10m
Now, we need to transverse wave acceleration, for this we need angular frequency because there is co-relation between transverse wave acceleration and angular frequency.
We know that angular frequency=2πf where f is the angular frequency.
ω=2×π×570
=>ω=2×3.14×570
=>ω=6.28×570
=>ω=3579.6/sec
Now, for acceleration we know that =ω²A where A is the amplitude of the wave.
=>a = (3579.6)²×3.7mm
=>a=((3579.6)²×3.7×1/1000)m/sec²
=>a=[(12813,536.2)×3.7×1]/1000m/sec²
=>a=47410083.8/1000m/sec²
=>a=47410.0839m/sec²
Hence, maximum transverse acceleration is 47410.0839m/sec²
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What is the frequency of a wave Travelling at 500 m/s with a wavelength of 25 m?
The frequency of the travelling wave is found to be 20 Hertz.
The relationship between the frequency of the wave, the wavelength of the wave and the speed of the wave is given by
V = fy
Where,
V is the speed of the travelling wave,
F is the frequency of the travelling wave,
y is the wavelength of the travelling wave.
The speed of the travelling wave is given to be 500m/s and the wavelength of the travelling wave is 25m.
Now, putting all the values,
500 = f(25)
f = 500/25
f = 20Hz
So, the frequency of the travelling wave is 20Hz.
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a diatomic ideal gas at pressure p and volume v is expanding to three times its initial volume under constant pressure. t or f
True. A diatomic ideal gas at pressure P and volume V is expanding to three times its initial volume under constant pressure.
Pressure Variations of a Diatomic Ideal Gas During ExpansionThe pressure of the gas will remain constant as the volume expands, therefore the ideal gas law states that the product of pressure and volume will remain constant, meaning the pressure will decrease as the volume increases.
As the diatomic ideal gas expands to three times its initial volume, the pressure of the gas will remain constant due to the ideal gas law, which states that the product of pressure and volume must remain constant. As the volume of the gas increases, the pressure must decrease in order to maintain the constant product. Therefore, although the pressure remains constant, the volume of the gas will increase three-fold.
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a 2 mm diameter meteor of specific gravity 2.9 has a speed of 6 km/s at an altitude of 50,000 m where the air density is 1.03 x 10-3 kg/m3. if the drag coefficient at this large mach number condition is 1.5, determine the deceleration of the meteor.
A 2 mm diameter meteor of specific gravity 2.9 has a speed of 6 km/s at an altitude of 50,000 m where the air density is 1.03 x 10-3 kg/m3. if the drag coefficient at this large number condition is 1.5, 5km/s is the deceleration of the meteor.
A material's density in respect to a standard substance is determined by its specific gravity, also referred to as relative density. When comparing the densities of solids like meteor and liquids, water is commonly used as a reference because it has a density of one kilogram per litre at 4 °C (39.2 °F) (62.4 pounds per cubic foot). At standard conditions (0 °C and 1 standard atmosphere), dry air, which is widely used to compare gases, has a density of 1.29 grams per litre (1.29 ounces per cubic foot). For instance, liquid mercury has a density of 13.6 kg per litre and a specific gravity of 13.6. Even though it has a standard density of 1.976 grams per litre, the gas carbon dioxide has a specific gravity of 1.53 (= 1.976/1.29). The ideas of specific gravity and buoyancy, or an object's propensity to float in water or the atmosphere, are interrelated.
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Where is infrared located on the electromagnetic spectrum in relation to other kinds of radiation?
Infrared rays are located in the electromagnetic spectrum between radio waves and gamma waves.
Electro magnetic radiation travels in waves, just like waves in an ocean. The energy of the radiation depends on the distance between the crests (highest points) of the waves, or the wavelength. In general, the smaller the wavelength, the higher the energy of the radiation. Gamma rays have wavelengths less than ten trillionths of a meter which is about the size of the nucleus of an atom. This means that gamma rays have very high energy.
Radio waves, on the other hand, have wavelengths that range from less than one centi-meter to greater than 100 metres. The energy of radio waves is much lower than the energy of other types of electro magnetic radiation. The only type of light detectable by the human eye is visible light. It has wavelengths about the size of a bacteria cell and its energies fall between those of radio waves and gamma rays.
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a rock with a mass of 525 g in air is found to have an apparent mass of 372 g when submerged in water. show answer no attempt 33% part (a) what mass, in grams, of water is displaced?
Ac rock with a mass of 525 g in air is found to have an apparent mass of 372 g when submerged in water mass, in grams, of water is displaced 153 g
When the rock is submerged into the water, there are two forces acting on the rock:
- its weight, equal to W = mg (m=mass, g=acceleration of gravity), downward
- the buoyant force, equal to B = mwg (mw=mass of water displaced), upward
So the resultant force, which is the apparent weight of the rock (W'), is
W' = W - B
which can be rewritten as
m'g = mg - mwg
where m' is the apparent mass of the rock. Using:
m = 540 g
m' = 372 g
we find the mass of water displaced
mw = m - m' = 525g - 372g = 153g
=mass, in grams, of water is displaced 153 g
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why do astronomers think the black hole in our galactic center has the event horizon with the largest angular size?
The black hole in our galactic center has an event horizon's size increases linearly with the mass of the black hole; a black hole with a solar mass of 10 would have an event horizon of 30 km.
The radius of a black hole increases with its mass. For the Sun or any object with a solar mass of one, the event horizon is 3 km (a little under two miles).
The matter will be broken down into its tiniest subatomic pieces once it enters the black hole's event horizon and finally be compressed into the singularity. The event horizon of the black hole grows proportionally as more matter is drawn into the singularity.
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How did you determine the coordinates of the vertices of the dilated image?
To dilate something in the coordinate plane, we need to multiply each coordinate by the scale factor. This is called mapping. A scale factor is labeled \(k\).e (x,y)→(kx,ky).
For any dilation, the mapping has a center and a scale factor. The center is the point of reference for the dilation, and the scale factor tells us how much the figure stretches or shrinks.
A dilation of a triangle is a stretch or a shrink of a triangle by a scale factor. The scale factor for dilation is the proportion by which the original figure is stretched or shrunk. The center of dilation is a reference point by which the dilation of a figure is stretched or shrunk.
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rank the following series from low frequency to high frequency. a. infrared light, radio waves, x-rays b. black light, nuclear energy, cell phone c. visible light, television waves, gamma rays
The following series from low frequency to high frequency are:
Radio waves-cellphone-television waves-infrared light-x-rays- black light-nuclear energy-visible light-gamma rays
In physics, frequency is the number of waves that pass a fixed point in a unit of time as well as the number of cycles or vibrations that a body in periodic motion experiences in a unit of time. After moving through a sequence of situations or locations and then returning to its initial position, a body in periodic motion is said to have experienced one cycle or one vibration. See also basic harmonic motion and angular velocity.
The frequency is 2 per second if the period, or time interval, needed to complete one cycle or vibration is 1/2 second; it is 100 per hour if the duration is 1/100 of an hour. The reciprocal of the period, or time interval, is typically the frequency.
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Most of the radiation released from the failed nuclear reactor was from fission products.a. Trueb. False
The fission products iodine-131, cesium-134, and cesium-137 made up the majority of the radiation produced by the failed nuclear reactor. Iodine-131 is rapidly consumed through the air and has a tendency to localize in the thyroid gland, despite having a half-life of only eight days, according to UNSCEAR.
Does radiation come from nuclear fission?
Atoms split apart during nuclear fission, releasing energy in the process. Nuclear fission is used in all nuclear power reactors, and uranium atoms are used in the majority of them. In the process of nuclear fission, a neutron splits a uranium atom after colliding with it, releasing a significant quantity of energy in the form of heat and radiation.
If a fission reactor malfunctioned, what would happen?
Because of the potential for radioactive elements to escape from all containment and enter the environment, causing radioactive pollution and fallout and perhaps poisoning nearby people and animals, a meltdown is thought to be extremely severe.
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the total number of points of work a team can accomplish in each scrum period is called . group of answer choices speed degree velocity score
The total number of points of work, a team can accomplish in each scrum period is called velocity.
The high data growth speed is another thing is currently a problem. In a way, this problem is closely related to the data volume problem, because the speed of data created is generally directly proportional to the data volume. Data not only come in large numbers but also in a shorter tempo and even some that are real-time.
The burden of storing and processing data in a data warehouse will be more useful if it is utilized for data that is directly related to the business - transaction, financial and consumer data.
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what is the momentum of a car with a mass of 2,000 kg moving at a constant velocity of 20 m/s?(1 point)
the momentum of a car with a mass of 2,000 kg moving at a constant velocity is 40,000 kg. m/s
The kinetic energy is 400kJ
The kinetic energy is
K.E=(1/2)mv2
The mass is m = 2000kg
The velocity is v = 20ms−1
So, K.E = (1/2)x2000x202 = 400000J = 400kJ
In physics, the kinetic energy of an object is the energy that it possesses due to its motion. It is defined as the work needed to accelerate a body of a given mass from rest to its stated velocity. Having gained this energy during its acceleration, the body maintains this kinetic energy unless its speed changes. Kinetic energy is the energy an object has because of its motion. If we want to accelerate an object, then we must apply a force. Applying a force requires us to do work. After work has been done, energy has been transferred to the object, and the object will be moving with a new constant speed.
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What happens when a rock is under pressure?
Answer: Stress that makes one rock squeeze or push against another.
Explanation:
The theory that dark matter is not real and is just a a problem with our theory of gravity has been falsified by:_______.
The theory that dark matter is not real and is just a problem with our theory of gravity has been falsified by an observation of what happens when clusters of galaxies collide. The term dark matter was coined in 1933 by Fritz Zwicky.
The observed evidence for dark matter is quite strong, and we know it's unlikely to be a mathematical artifact because different galaxies appear to have different amounts of dark matter, with some not having any at all. If our model of gravity were in error, we would expect to see the same error in all galaxies we observe. This is not the case.
Instead, we observe that some galaxies behave exactly as the model says they should, and some behave as if they're heavier than they ought to be.
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the pressure exerted by a phonograph needle on a record is surprisingly large. if the equivalent of 1.00 g is supported by a needle, the tip of which is a circle 0.200 mm in radius, what pressure is exerted on the record in n/m2 (1 pa
77,985.92 N/m^2 pressure is exerted on the record in n/m2
Equation: Pressure, P = Force, F / Surface Area, A
Force, F = Weight, mg = 1/1000*9.81 = 9.81 * 10-3 N
Surface area, A = πr^2
= π*(0.200 / 1000)^2
= 1.2566 * 10-7 m2
P = F / A = (9.81*10^–3)/(1.2566*10^–7) = 77,985.92 N/m^2 as a result.
The normal force exerted by the record is supporting the needle of the record player, and this normal force will be equal to the force of gravity pulling the needle downward. If we were to look at the end of the needle, its radius would be a circle with a radius of 0.200 millimeters. Since the prefix "milli-" indicates times 10 to minus 3, we will translate that into 0.200 times 10 to minus 3 meters.
And since this region of the circle will be r squared, we can calculate the pressure at that point. The force per area, or mg, is what determines pressure. Therefore, mg equals the force, and r squared equals the area. Therefore, the pressure equals 7.80 times 10 to the 4 pascals, or 1.00 times 10 to the minus 3 kilograms times 9.80 newtons per kilogram divided by times its radius in meters squared.
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Anna and jon sit on a seesaw. Anna has a mass of 60 kg and sits 2 m from the center. Jon has a mass of 70 kg. How far from the center should jon sit so the seesaw is balanced?.
In order to balance the seesaw, John should sit at a distance of 1.7m from the center.
This question can be solved using the concept of moment. in order to balance on the seesaw the moment on the center of seesaw should be zero or in other words
∑M = 0
Now, the moment is expressed by the formula
∑M = F × d
where, ∑M is the Algebraic sum of moments in the center of the balance, M is the moment in the center point ( N*m), F is the Force (N) and d is the distance of the force to the the center point(N*m).
Now, we have
Mass of Anna (M) = 60kg
Mass of John (m) = 70kg
Distance from Anna to the center of the seesaw (dA) = 2m
Distance from John to the center of the seesaw (dJ) = ?
Acceleration due to gravity (g) = 9.8 m/s²
Also, W = mass × g. So, W = Anna's weight and w = John's weight
Now, to find the distance we write the Moment equation as
∑M = 0
(W)(dA) - (W)(dJ) = 0
(M*g)(dA) - (m*g)(dJ) = 0
We divide the equation by g
(M)(dA) - (m)(dJ)= 0
(M)(dA) = (m)(dJ)
dJ = M(dA)/m
dJ = 60×2/70
dJ = 120/70
dJ = 1.7m which is distance of John from center.
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a possible means for making an airplane invisible to radar is to coat the plane with an antireflective polymer. if radar waves have a wavelength of 3.00 cm and the index of refraction of the polymer is n 5 1.50, how thick would you make the coating?
The coating should be made 0.5 cm thick.
Wavelength of the radar waves = λ = 3 cm
Index of refraction of the polymer = n = 1.50
Thickness required = t
Generally the equation for Destructive interference for Normal incidence is mathematically given by:
= 2 X n X t = 0.5 X m X λ
If we calculate at minimum thickness, then m = 1.
Thus, thickness = t =
= 2 X n X t = 0.5 X λ
= 2 X 1.5 X t = 0.5 X 3
= t = (0.5 X 3) / (2 X 1.5)
= t = 0.5 cm
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Light passes through the entire thickness of the neural layer of the retina to excite the photoreceptors. A) True B) False
It is true to say that the light passes through the entire thickness of the neural layer of the retina to excite the photoreceptors. So,correct option is A.
At the point when the light raises a ruckus around town (a light-touchy layer of tissue at the rear of the eye), extraordinary cells called photoreceptors transform the light into the electrical signs. These electrical signs travel from the retina through the optic nerve to the cerebrum.
The vision cycle depends intensely on the capacity of the eye to refract light. This happens at both the cornea and the focal point of the eye. The course of vision initially begins with the light going through the cornea. Since the cornea has a round surface it behaves like a uniting focal point.
Hence, option A is correct.
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A black hole…
A. is a gateway to another dimension.
B. has the gravitational pull to devour an entire galaxy.
C. cannot exist, according to the laws of physics.
D. has an escape velocity of the speed of light or greater.
Answer:
D
Explanation:
A black hole is not a gateway to another dimension.
It is impossible for a blackhole to devour an entire galaxy.
Black holes do exist.
Therefore, the answer is D.
Answer:
We are going to leave the quantum theory of gravitation and return to Einstein's general relativity to describe those very exotic objects that so appeal to the imagination of young people, black holes. They are objects whose gravitational attraction is so great that not even light can escape from their surface. We already know what the escape velocity is, so what we mean is that, when we calculate the escape velocity in a black hole (see the end of Topic 1) we get a value of 300,000 km/s or more.
Explanation:
A star is born when
A. it first starts to fuse hydrogen into helium.
B. it first starts to fuse helium into hydrogen.
C. it gets its first planet.
D. when it goes supernova.
Determine whether each of the following statements about the thermodynamic functions are True or False as they apply to chemical reactions.1. Enthalpy and temperature are multiplied in the Gibbs free energy.2. All spontaneous chemical reactions have no heat of reaction.3. The heat of reaction at constant pressure is always equal to the work done by the reaction.4. Positive enthalpy changes increase spontaneity.5. The entropy change does not effect spontaneity.
The quantity of heat needed to increase a substance's temperature by one degree Celsius per gramme is known as its specific heat capacity. As a result, the relationship between enthalpy and a substance's specific heat capacity is direct.
Describe enthalpy.
The term "enthalpy" is essentially used in thermodynamics to show the total energy that a substance possesses. Enthalpy mathematically directly correlates with a substance's specific heat capacity.
The Gibbs free energy is reduced by temperature and entropy. Spontaneity is boosted by favourable enthalpy shifts. Spontaneity is increased by positive entropy changes. Positive entropy changes are present in all spontaneous chemical reactions. As a result, the relationship between enthalpy and a substance's specific heat capacity is direct.
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the human ear canal is, on average, 2.5cm long and aids in hearing by acting like a resonant cavity that is closed on one end and open on the other. the length of the ear canal is partially responsible for our sensitivities to certain frequencies. use 340m/s for the speed of sound when performing the following calculations.Part A
What is the first resonant frequency?
Part B
What is the wavelength at second resonance?
Part C
How does the first resonant frequency change if the ear canal is full of water?Part D
At a listener's ear, the intensity of a conversation is 4×10−6W/m24×10−6W/m2 and a typical adult's ear has a surface area of 210×10−3m2210×10−3m2. What is the power of the sound waves on the ear?
Part E
Long-term exposure to loud noises can damage hearing. If a loud machine produces sounds with an intensity level of 100dB100dB, what would the intensity level be if the intensity were reduced by a factor of 4?
The first resonance frequency is 3400 Hz and the wavelength at second frequency is 3.33 cm. After the ear canal is full of water the first resonance frequency increases. The power of sound waves on the year is 840 X 10⁻⁹ W and if the intensity of sound is reduced by a factor of 4, then the intensity level will be 135 dB.
(a) The ear, being open at one end and closed at the other, is equivalent to a closed pipe. For a closed pipe, the first resonant frequency occurs when one quarter of the wavelength is equal to the length of the pipe.
= λ/4 = l
= λ = 4l
Now, Speed is given by
= v = fλ
where f = frequency
= f = v/λ
At the first resonant frequency,
= f = v/λ
= f = v/4l
= f = 340 / (4 X 2.5 X 10⁻²) m
= f = 3400 Hz
(b) At second resonance,
= (3/4)λ = l
= λ = (4/3) X l
= λ = (4/3) X 2.5 X 10⁻²
= λ = 3.33 cm
(c) Since, sound travels faster in a liquid than in gas, the first resonance frequency increases when the ear canal is filled with water as speed increases. This is because, speed is directly proportional to intensity.
(d) Intensity = i = 4 X 10⁻⁶ W/m²
Surface area = a = 210 X 10 ⁻³ m²
Power of the sound waves = p =
= p = i X a
= p = 4 X 10⁻⁶ X 210 X 10 ⁻³
= p = 840 X 10⁻⁹ W
(e) Intensity level = l = 100 dB
If the intensity is reduced by 4, then using the relationship between decibel and sound intensity is :
= β = 10 X log(I₁ / I₂)
= β = 10 log (0.25/10⁻¹²) dB
= β = 135 dB
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What is the relationship between heat and pressure?
The relationship between heat and pressure is that they are directly proportional to each other by Gay-lussac law.
What is Heat?Heat is the energy that moves from one thing to another when temperatures are different. Heat passes from the hotter to the colder body when two bodies with different temperatures are brought together. Usually, but not consistently, this energy transfer results in a rise in the heat of the colder body and a fall in the temperature of the hotter body.
By switching from one physical situation (or phase) to the other, such as melting from a solid to a liquid, sublimation from a solid to a vapor, boiling from a liquid to steam or changing from one stable state to another, a substance can absorb heat without increasing in temperature.
The relationship between pressure and temperature for a given volume of gas is straightforward. Pressure rises in systems when temperature increases, and vice versa. The Gay-law Lussac specifies the link between a gas's pressure and temperature.
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4. A truck travels a curve of radius 10 m at 18 km/hr on a force of 15000 N. What is the mass of the truck?
Answer:
The mass of the truck is 1500 Kg.
Explanation:
Given;F = 15000 NWe know that,
F = mg
g = acceleration due to gravity = 10m/s²m = F/g
m = 15000/10
m = 1500 Kg
m = 1500 KgThus, The mass of the truck is 1500 Kg.
The specific gravity of an material is defined as the ratio of the density of the material to the density of water. The specific gravity of ice is 0.917, whereas that of seawater is 1.025.What fraction of an iceberg is above the surface of the water?
The fraction of the ice that lies above the water is obtained as 0.11.
What is the density?We know that the term density has to do with the ratio of the mass to the volume of an object. In this case we can see that the density has to be looked upon as a kind of property that we can use so as to obtain the identity of a given material.
In this case, we can see that what we have been given in each case is the specific gravity. However, the specific gravity is the ratio of the density of the object to the density of water.
Thus;
Density of ice = 0.917 g/cm^3
Density of sea water = 1.025 g/cm^3
Then we know that the fraction that is above the surface of the water can be obtained by the use of the formula;
Volume above = Density of liquid - Density of ice/ Density of liquid
Volume above = 1.025 - 0.917/ 1.025
= 0.11
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a particle moves along the x-axis. the velocity of the particle at time t is 2 6 . t t - what is the total distance traveled by the particle from time t
The total distance of the particle is 7.33
How to calculate total distance ?Distance is the sum of an object's movements, regardless of direction. Distance can be defined as the amount of space an object has covered, regardless of its starting or ending position.
The distance between two sites is the length of the route. The metric unit of length is the metre.
It's interesting to observe that while some physics symbols, like "d" for distance, are extremely relatable, others, like "c" for light speed, are not.
The distance formula is a formula used to determine how far apart two places are from one another. The dimensions of these points are unlimited.
Given,
Distance s = ∫03It2 - 6t + 8Idt
= ∫02(t2 - 6t + 8)dt + ∫23(6t - t2 - 8)dt
= (t3/3 - 3t2 + 8t)02 + (3t2 - t3/3 - 8t)23
=(8/3 - 12 + 16) + (27 - 9 - 24) - (12 - 8/3 - 16)
= 20/3 - 6 + 20/3 = 22/3
=7.33
Therefore the total distance is 7.33
The complete question is : A particle travels along the x-axis so that at time t≥0 its velocity is given by v(t)=t2−6t+8. What is the total distance the particle travels from t = 0 to t = 3?
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consider the two stars in the constellation orion, rigel with an apparent magnitude of 0.18 and saiph with an apparent magnitude of 2.07.which star is brighter, rigel or saiph?
The two stars in the constellation orion, rigel with an apparent magnitude of 0.18 and saiph with an apparent magnitude of 2.07 and Brightest Star is rigel.
What is Rigel?A blue supergiant star in the constellation of Orion is called Rigel. The Bayer designation for it is Orionis, which can also be spelled Beta Orionis or Ori in Latin. A stellar system of at least four stars that, to the unaided eye, appears as a single blue-white point of light contains Rigel as its brightest and most massive member. Rigel also serves as the star system's eponym. The distance between this system and the Sun is roughly 860 light-years (260 pc).Rigel, a star with the spectral classification B8Ia, is estimated to be between 61,500 and 363,000 times more massive and bright than the Sun, depending on the methodology and presumptions utilised. Its radius exceeds 70 times that of the Sun.To learn more about Rigel refer to:
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Jacky starts biking to meet up with her friend. She determines that she will be 3 minutes late if she bikes at a speed of 10 mph and 2 minutes early if she goes 12 mph. How much time does she have left before the appointed meeting time?.
There are 26.88 minutes left before Jacky's scheduled time.
Let x be the separation between Jacky & her buddies.
Let t be the typical travel time that Jacky would take to go to her friend's house.
Time = Distance ÷ Speed
He will arrive at the meeting three minutes late if she rides at a speed of 10 mph.
Time of lateness in hours = 3 ÷ 60 = 0.05 hours
t + 0.05 = x ÷ 10
10t + 0.5 = x
She will arrive two minutes before the scheduled meeting time if she rides at a speed of 12 mph.
2 seconds equal 0.033 hours
t - 0.033 = x ÷ 12
12t - 0.396 = x
Compare equations from 10t + 0.5 = x and 12t - 0.396 = x.
10t + 0.5 = 12t - 0.396
12t - 10t = 0.5 + 0.396
2t = 0.896
t = 0.896/2
t = 0.448 hours
t = 0.448 x 60
t = 28.88 minutes
Jacky has 27 minutes well before the scheduled time or 26.88 minutes.
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A box slides on the ground. It has a 20N applied force pushing it to the right. The friction between the box and the ground is 8N. What is the magnitude of the net force on the box?
Answer:
12 N
Explanation:
Fnet = 20 N - 8 N = 12 N
Force of friction is always in the direction opposite to the direction of motion of the object.
a fire truck is driving quickly toward you with siren blaring. how does the frequency of the sound change compared to a siren at rest?
The frequency of the sound will increase as the fire truck approaches, as the sound waves are compressed together, creating a higher pitch. As the fire truck passes by, the frequency will gradually decrease, as the sound waves spread out, creating a lower pitch.
The frequency of the sound produced by a fire truck siren changes as it approaches. This is because of the Doppler effect, which states that the frequency of sound waves increases as the source of the sound approaches, and decreases as it moves away.
Step 1: When the firetruck is at rest, the sound waves emitted by the siren travel in a straight line in all directions. This means that the frequency of the sound waves heard at any given point is the same as the frequency emitted by the siren.
Step 2: As the fire truck moves closer to the observer, the sound waves leave the siren at a faster rate than when the truck was at rest. This causes the sound waves to bunch up closer together, which in turn causes the frequency of the sound to increase.
Step 3: As the fire truck continues to move closer to the observer, the sound waves continue to bunch up, resulting in an even higher frequency of sound.
Step 4: Finally, when the fire truck passes the observer, the sound waves start to spread apart again. This causes the frequency of the sound to decrease.
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