From the graph given in the question, we can find out that
49% of the college graduates say that their college education was very useful for helping develop specific skills and knowledge for the workplace.
From the given question, the total percentage of college graduates who have found that their degree very helpful to develop specific skills and knowledge for the workplace is 49%
What is the horizontal and vertical shift for the absolute value function below?f(x) =|x-5|+1The graph shifts right 5 and up 1.The graph shifts left 5 and up 1.The graph shifts left 5 and down 1.The graph shifts right 5 and down 1.
The correct answer is option A;
The graph shifts right 5 and up 1
14. What is the volume of a box with these dimensions? 4 cm 5 cm 10 cm.
The volume of a rectangular prism is given by the product of its three dimensions.
Since the box dimensions are 4 cm, 5 cm and 10 cm, its volume is:
[tex]\begin{gathered} V=4\cdot5\cdot10 \\ V=200\text{ cm}^3 \end{gathered}[/tex]So the volume of the box is equal to 200 cm³.
what is an equation of the line that passes through the point (-2,-3) and is parallel to the line x+3y=24
Solve first for the slope intercept form for the equation x + 3y = 24.
[tex]\begin{gathered} \text{The slope intercept form is }y=mx+b \\ \text{Convert }x+3y=24\text{ to slope intercept form} \\ x+3y=24 \\ 3y=-x+24 \\ \frac{3y}{3}=\frac{-x}{3}+\frac{24}{3} \\ y=-\frac{1}{3}x+8 \\ \\ \text{In the slope intercept form }y=mx+b,\text{ m is the slope. Therefore, the slope of} \\ y=-\frac{1}{3}x+8,\text{ is }-\frac{1}{3}\text{ or } \\ m=-\frac{1}{3} \end{gathered}[/tex]Since they are parallel, then they should have the same slope m. We now solve for b using the point (-2,-3)
[tex]\begin{gathered} (-2,-3)\rightarrow(x,y) \\ \text{Therefore} \\ x=-2 \\ y=-3 \\ \text{and as solved earlier, }m=-\frac{1}{3} \\ \\ \text{Substitute the values to the slope intercept form} \\ y=mx+b \\ -3=(-\frac{1}{3})(-2)+b \\ -3=\frac{2}{3}+b \\ -3-\frac{2}{3}=b \\ \frac{-9-2}{3}=b \\ b=-\frac{11}{3} \end{gathered}[/tex]After solving for b, complete the equation.
[tex]y=-\frac{1}{3}x-\frac{11}{3}\text{ (final answer)}[/tex]A team digs 12 holes every 20 hours, what is the unit rate?
The unit rate = 0.6 holes per hour
Explanation:Number of holes dug by the team = 12
Total time taken = 20 hours
The unit rate = (Number of holes) / (Time)
The unit rate = 12/20
The unit rate = 0.6 holes per hour
i really need help writting the slope intercept form
Equation in slope intercept form is written as
y = mx + b
If slope m = 1/3 and y-intecept b = 3
Equation form using the information above is
[tex]y\text{ =}\frac{1}{3}x\text{ + 3}[/tex]Point slope form using the point (3, 4)
simply use the formula
y - y₁ = m( x- x₁ )
[tex]y\text{ -4=}\frac{1}{3}(x-3)[/tex]
I am having a tough time solving this problem from my prep guide, can you explain it to me step by step?
The range in the average rate of change in temperature of the substance is from a low temperature of -[tex]22^{0}[/tex]F to a high of [tex]16^{0}[/tex]F
The domain of the function f(x) = sin x includes all real numbers, but its range is −1 ≤ sin x ≤ 1. The sine function has different values depending on whether the angle is measured in degrees or radians. The function has a periodicity of 360 degrees or 2π radians.
Given f(x) = -19sin(7/3x + 1/6) – 3
We have to the range in the average rate of change in temperature of the substance is from a low temperature of ___F to a high of ___F
We know that the range of sin x is [-1, 1]
f(x) = -19 sin(7/3x + 1/6) – 3
We know
-1 ≤ sin(7/3x + 1/6) ≤ 1
Now multiply with -19 on both sides
19 ≥ -19sin(7/3x + 1/6) ≤ -19
-19 ≤ -19sin(7/3x + 1/6) ≤ 19
Now subtract 3 from both sides
-19 - 3 ≤ -19sin(7/3x + 1/6) - 3 ≤ 19 - 3
-22 ≤ -19sin(7/3x + 1/6) ≤ 16
-22 ≤ f(x) ≤ 16
Therefore the range in the average rate of change in temperature of the substance is from a low temperature of -220F to a high of 160F
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The sum of the measures of the angles of a triangle is 180. The sum of the measures of the second and third angles is nine times the measure of the first angle. The third angle is 26 more than the second let x,y, and z represent the measures of the first second and third angles, find the measures of the three angles
Answer:
x = 18, y = 68, z = 94.---------------------------------
Set equations as per given details.The sum of the measures of the angles of a triangle is 180:
x + y + z = 180 (1)The sum of the measures of the second and third angles is nine times the measure of the first angle:
y + z = 9x (2)The third angle is 26 more than the second:
z = y + 26 (3)SolutionSubstitute the second equation into first:
x + y + z = 180,y + z = 9x.Solve for x:
x + 9x = 180,10x = 180,x = 18.Substitute the value of x into second and solve for y:
y + z = 9x,y + z = 9*18,y + z = 162,y = 162 - z.Solve the third equation for y:
z = y + 26,y = z - 26.Compare the last two equations and find the value of z:
162 - z = z - 26,z + z = 162 + 26,2z = 188,z = 94.Find the value of y:
y = 94 - 26,y = 68.Answer:
x = 18°
y = 68°
z = 94°
Step-by-step explanation:
Define the variables:
Let x represent the first angle.Let y represent the second angle.Let z represent the third angle.Given information:
The sum of the measures of the angles of a triangle is 180°. The sum of the measures of the second and third angles is nine times the measure of the first angle. The third angle is 26 more than the second.Create three equations from the given information:
[tex]\begin{cases}x+y+z=180\\\;\;\;\;\;\:\: y+z=9x\\\;\;\;\;\;\;\;\;\;\;\;\;\: z=26+y\end{cases}[/tex]
Substitute the third equation into the second equation and solve for x:
[tex]\implies y+(26+y)=9x[/tex]
[tex]\implies 2y+26=9x[/tex]
[tex]\implies x=\dfrac{2y+26}{9}[/tex]
Substitute the expression for x and the third equation into the first equation and solve for y:
[tex]\implies \dfrac{2y+26}{9}+y+26+y=180[/tex]
[tex]\implies \dfrac{2y+26}{9}+2y=154[/tex]
[tex]\implies \dfrac{2y+26}{9}+\dfrac{18y}{9}=154[/tex]
[tex]\implies \dfrac{2y+26+18y}{9}=154[/tex]
[tex]\implies \dfrac{20y+26}{9}=154[/tex]
[tex]\implies 20y+26=1386[/tex]
[tex]\implies 20y=1360[/tex]
[tex]\implies y=68[/tex]
Substitute the found value of y into the third equation and solve for z:
[tex]\implies z=26+68[/tex]
[tex]\implies z=94[/tex]
Substitute the found values of y and z into the first equation and solve for x:
[tex]\implies x+68+94=180[/tex]
[tex]\implies x=18[/tex]
Solve the following system of equations using the elimination method. Note that the method of elimination may be referred to as the addition method. (If there is no solution, enter NO SOLUTION. If there are infinitely many solutions, enter INFINITELY MANY.)20x − 5y = 208x − 2y = 8(x, y) =
Given
The system of equations,
20x − 5y = 20
8x − 2y = 8
To find: The solution.
Explanation:
It is given that,
20x − 5y = 20 _____(1)
8x − 2y = 8 _____(2)
That implies,
Divide (1) by 5 and (2) by 2.
Then, (1) and (2) becomes,
4x - y = 4.
Hence, there is infinitely many solution.
what is 3(x+5) 12 please help I’ve been stuck on it
Given data:
The given inequality is 3(x+5) >12.
The given inequality can be written as,
[tex]\begin{gathered} 3\mleft(x+5\mright)>12 \\ 3x+15>12 \\ 3x>-3 \\ x>-1 \\ x\in(-1,\text{ }\infty) \end{gathered}[/tex]The graph of the above solution is,
Thus, the solution of the given inequality is (-1, ∞).
A 76.00 pound flask of mercury costs $150.50. The density of mercury is 13.534 g/cm3.It takes 4.800 in^3 of mercury to make one manometer. Find the price of the mercury used to make 21 manometers by first calculating the cost of mercury for one manometer.What is the price of mercury used to make one manometer?
Price of one pound of mercury is derived as follows;
[tex]\begin{gathered} Price\text{ of 1lb of merc}=\frac{Cost\text{ of flask}}{Pounds\text{ of merc in the flask}} \\ \text{Price of 1 lb}=\frac{150.50}{76} \\ \text{Price of 1 lb}=1.98 \end{gathered}[/tex]This means 1 pound of mercury costs $1.98
1 pound = 453.6 grams
Therefore;
[tex]\begin{gathered} 1lb=453.6gms \\ 76lb=34,473.6gms \end{gathered}[/tex]The price of 1 gram of mercury would be;
[tex]\begin{gathered} Price\text{ of 1 gram}=\frac{Price\text{ per pound}}{\text{grams in 1 lb}} \\ \text{Price of 1 gram}=\frac{1.98}{453.6} \\ \text{Price of 1 gram}=0.004365 \end{gathered}[/tex]This means 1 gram of mercury costs $0.004365
Note that you have 13.534 grams per cubic centimeter of mercury. Therefore, the price of 1 cubic centimeter of mercury shall be calculated as follows;
[tex]\begin{gathered} \text{Price of 1 cubic cm}=grams\text{ per cubic cm x price of 1 gram} \\ \text{price of 1 cubic cm}=13.534\times0.004365 \\ \text{Price of 1 cubic cm}=0.059 \end{gathered}[/tex]This means 1 cubic centimeter of mercury would cost $0.059
Note also that, 1 cubic inch = 16.387 cubic centimeters. Hence,
[tex]\begin{gathered} Price\text{ of 1 cubic inch}=16.387\text{ cubic cm x }price\text{ of 1 cubic cm} \\ \text{Price of 1 cubic inch}=16.387\times0.059 \\ \text{Price of 1 cubic inch}=0.9668 \end{gathered}[/tex]This means 1 cubic inch costs $0.9668
It takes 4.800 cubic inches to make 1 manometer.
Therefore, the cost of 4.800 cubic inches would be;
[tex]\begin{gathered} Price\text{ of 4.800 cubic inches}=Price\text{ of 1 cubic inch x 4.800 cubic inches} \\ Price\text{ of 4.800 cubic inches}=0.9668\times4.800 \\ \text{Price of 4.800 cubic inches}=4.64 \end{gathered}[/tex]If it costs 4.800 cubic inches to make 1 manometer, then the cost of 1 manometer would be $4.64
Therefore, to make 21 manometers, we would have;
[tex]\begin{gathered} 1\text{ manometer}=4.64 \\ 21\text{ manometers}=21\times4.64 \\ 21\text{ manometers}=97.44 \end{gathered}[/tex]ANSWER:
The price of mercury required to make 21 manometers would be $97.44
factoring quadratics h^2+12h+11
Which of the following functions have the ordered pair (2, 5) as a solution?4 + x = yy = 2 x7 - x = yx + 3 = y
Given
The ordered pair (2,5).
To find which of the functions have the ordered pair as a solution.
Explanation:
It is given that,
The ordered pair (2,5).
Then, put x=2, and y=5 in the function x+3=y.
That implies,
[tex]\begin{gathered} 2+3=5 \\ 5=5 \end{gathered}[/tex]Hence, the ordered pair (2,5) is a solution of the function x+3=y.
Also, substitute x=2, y=5 in the function 7-x=y.
That implies,
[tex]\begin{gathered} 7-2=5 \\ 5=5 \end{gathered}[/tex]Hence, the ordered pair (2,5) is a solution of the function 7-x=y.
Anthony has already taken 1 quiz during past quarters, and he expects to have 5 quizzes during each week of this quarter. How many weeks of school will Anthony have to attend this quarter before he w have taken a total of 31 quizzes?
The first step to solve the problem is to create a function that relates the number of quizzes he attends by the number of weeks that elapses. Since he alread took one quizz, then the function must start from that and must grow at a rate of 5 quizzes per week. We have:
[tex]\text{quizzes(w)}=5\cdot w+1[/tex]We want to know how many weeks until he takes 31 quizzes, then we need to make the expression equal to 31 and solve for the value of w. We have:
[tex]\begin{gathered} 5\cdot w+1=31 \\ \end{gathered}[/tex]Then we subtract both sides by 1.
[tex]\begin{gathered} 5\cdot w+1-1=31-1 \\ 5\cdot w=30 \end{gathered}[/tex]Then we divide both sides by 5.
[tex]\begin{gathered} \frac{5\cdot w}{5}=\frac{30}{5} \\ w=6 \end{gathered}[/tex]It'll take 6 weekes before he have taken a total of 31 quizzes.
The standard form of the equation of a parabola isy=x²-4x+21. What is the vertex form of the equation?O A. y = ¹/(x-4)² +13OB. y=(x-4)² +21C. y = 1/(x+4)² +1+13O D. y = 1/(x+4)² +21
Answer:
[tex]y=\frac{1}{2}(x-4)^2+13\text{ }\operatorname{\Rightarrow}(A)[/tex]Explanation: We have to find the vertex form of the parabola equation from the given standard form of it:
[tex]y=\frac{1}{2}x^2-4x+21\rightarrow(1)[/tex]The general form of the vertex parabola equation is as follows:
[tex]\begin{gathered} y=A(x-h)^2+k\rightarrow(2) \\ \\ \text{ Where:} \\ \\ (h,k)\rightarrow(x,y)\Rightarrow\text{ The Vertex} \end{gathered}[/tex]Comparing the equation (2) with the original equation (1) by looking at the graph of (1) gives the following:
[tex](h,k)=(x,y)=(-4,13)[/tex]
Therefore the vertex form of the equation is as follows:
[tex]y=\frac{1}{2}(x-4)^2+13\Rightarrow(A)[/tex]Therefore the answer is Option(A).
If y=kx, where k is a constant, and y=24 when x=6, what is the value of y when x=5?A. 6B. 15C. 20D. 23
First, we will find the value of k
We can do this by sybstituting y=24, x=6 in;
y=kx and then solve for k
24= k(6)
divide both-side of the equation by 6
24/6 = k
4 = k
k=4
Then when x = 5, we will substitute x=5 and k=4 in; y=kx and then solve for y
y= (4)(5)
y = 20
Net force = ?Net force = ?16 NThe net force for example A isNAThe net force for example B is NA
Part A
The net force is 4 N up
Part B
The net force is 3 N to the left
A training field is formed by joining a rectangle and two semicircle. The rectangle is 87m long and 64m wide. What is the length of a training track running around the field? ( Use the value 3.14 pie, and do not round your answer. Be sure to include the correct unit in your answer.)
The legth of running around this track will be the length of both semi-circles plus the two bigger sidesof the rectangle.
The length of a semi -circle is half the length of a circle, and can be expressed as:
[tex]S=\frac{2\pi r}{2}=\pi r[/tex]Where r is the radius of the semi-circle. The diameter of the semi-circles is the same as the smaller sides of the rectangle and its radius is half the diameter, so:
[tex]r=\frac{d}{2}=\frac{64}{2}=32[/tex]So, the total length, as said above, is the sum of the length of both semi-circles plus two times the bigger side:
[tex]\begin{gathered} L=2S+2w \\ L=2\cdot\pi r+2\cdot87 \\ L=2\cdot3.14\cdot32+2\cdot87 \\ L=200.96+174 \\ L=374.96 \end{gathered}[/tex]Al the measures used were in meters and length is given in meters to the first power, so the unit of the result is also meters, or just "m".
Thus the answer is 374.96 m.
Identify any congruent figures in the coordinate plane. Explain. This is a fill in the blank question based off of the options that are listed down below!
Solution
For this case we can conclude the following:
triangle HJK ≅ triangle QRS because one is rotation of 90º about the origin of the other
Rectangle DEFG ≅ rectangle MNLP because one is a translation of the other
triangle ABC ≅ no given figure because one is not related by rigid motions of the other
verizon charges $200 to start up a cell phone plan. then there is a $50 charge each month. what is the total cost (start up fee and monthly charge) to use the cel phone plan for 1 month?
write the total costs a linear function in the form
[tex]y=mx+b[/tex]in which:
y= total cost
x= number of months
m= charge per month
b= fixed start up fee
replace all data in the equation
[tex]\begin{gathered} y=50\cdot x+200 \\ y=50x+200 \end{gathered}[/tex]Since the question is the cost for 1 month, x=1
[tex]\begin{gathered} y=50(1)+200 \\ y=250 \end{gathered}[/tex]The cost for the use of the cellphone is $250
If twice the age of a stamp is added to the age of a coin, the result is 45. The difference between three times the age of a stamp and the age of a coin is 5. What is the age of the stamp?
10 years
1) Considering that we can call the age of a stamp by "s" and the age of a coin by "c" we can write out the following system of Linear Equations:
[tex]\begin{gathered} 2s+c=45 \\ 3s-c=5 \end{gathered}[/tex]Note that we can solve it using the Elimination Method.
2) So let's add simultaneously both equations:
[tex]\begin{gathered} 2s+c=45 \\ 3s-c=5 \\ -------- \\ 5s=50 \\ \frac{5s}{5}=\frac{50}{5} \\ s=10 \end{gathered}[/tex]We can plug into that s=10 and find the age of a coin as well:
[tex]\begin{gathered} 2(10)+c=45 \\ c=45-20 \\ c=20 \end{gathered}[/tex]Note that we subtracted 20 from both sides.
3) Hence, the age of a stamp is 10 years
Graph the linear function using the slope and the y-intercept.y = 2x + 3CORTUse the graphing tool to graph the linear equatium. Use the slope and y-intercept when drawing the line.Click toenlargegraph
Answer:
Explanation:
If we have a linear equation of the form
[tex]y=mx+b[/tex]then m = slope and b = y-intercept.
Now in our case, we have
[tex]y=2x+3[/tex]which means that slope = 2 and y-intercept = 3
Therefore, we graph a line that has a slope of 2 and a y-intercept of 3.
A slope of 2 means that for every step you take to the right on a graph, you move 2 steps up to get to a point on the line.
The y-intercept of 3 means that the line passes through the point (0, 3).
Using these two facts about the line, we draw the following line.
From the above plot, we can clearly see that the line has a slope of 2 and a y-intercept of 3 - the same line described by y = 2x + 3.
Can someone please help me solve #6 on this packet?
The distance between the two camper stations are 60.44 km and 62.95 km. as calculated using the law of sines.
Let us consider the the first ranger station is A and the second ranger station is C and the camper is at the position B.
It is given that AC = 10 km
∠BAC = 100°
∠BCA = 71°
∴∠ABC = 180 - (100 + 71) = 9
Now we will use this to find the distance between each ranger station and the camper by using the law of sines.
From the law of sines we know that :
[tex]{\displaystyle {\frac {a}{\sin {\alpha }}}\,=\,{\frac {b}{\sin {\beta }}}\,=\,{\frac {c}{\sin {\gamma }}}\,}[/tex]
Now we will use this ratio to calculate the other sides of the triangle.
10 / sin 9 = BC / sin 100
or, BC = 10 × sin 100 / sin 9
or, BC = 62.95 km
Again:
10 / sin 9 = AB / sin 71
or. AB = 60.44 km
Therefore the distance between the two camper stations are 60.44 km and 62.95 km.
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80 students scores recorded 68 84 75 82 68 90 62 88 76 93 73 88 73 58 93 71 59 58 5161 65 75 87 74 62 95 78 63 72 66 96 79 65 74 77 95 85 78 8671 78 78 62 80 67 69 83 76 62 71 75 82 89 67 58 73 74 73 6581 76 72 75 92 97 57 63 83 81 82 53 85 94 52 78 88 77 71mean exam score
Solution
We have the following values:
68,84,75,82,68,90,62,88,76,93,73,79,88,73,58,93,71,59,
58,51,61,65,75,87,74,62,95,78,63,72,66,96,79,65,74,77,95,
85,78,86,71,78,78,62,80,67,69,83,76,62,71,75,82,89,67,58,
73,74,73,65,81,76,72,75,92,97,57,63,68,83,81,82,53,85,94,
52,78,88,77,71
Part a
Range = Max- Min= 97-51= 46
Part b
The mean is given by:
[tex]\text{Mean}=\frac{\sum ^n_{i\mathop=1}x_i}{n}=75[/tex]Part c
The median is given by:
Position 40 ordered= 75 and Position 41 ordered= 75
Then the median is:
[tex]\text{Median}=\frac{75+75}{2}=75[/tex]Part d
The most is the most frequent value and for this case is:
Repeated 5 times
Mode = 78
Part e
The data within the interval 50-54 is:
51 52 53
The variance is given by:
[tex]s^2=\frac{\sum ^n_{i\mathop=1}(x_i-Mean)^2}{n-1}=1[/tex]And the deviation si:
[tex]s=\sqrt[]{1}=1[/tex]
2x + 2/3y= -2 x, y intercept
We need to find the points at which the expression below intercept the axis of the coordinate plane:
[tex]2x+\frac{2}{3}y=-2[/tex]To find the "x" intercept we need to find the value of "x" that results in a value of "y" equal to 0. We have:
[tex]\begin{gathered} 2x+\frac{2}{3}\cdot0=-2 \\ 2x+0=-2 \\ 2x=-2 \\ x=\frac{-2}{2}=-1 \end{gathered}[/tex]To find the "y" intercept we need to find which value of "y" the function outputs when we make x equal to 0.
[tex]\begin{gathered} 2\cdot0+\frac{2}{3}y=-2 \\ \frac{2}{3}y=-2 \\ 2y=-6 \\ y=\frac{-6}{2}=-3 \end{gathered}[/tex]The x intercept is -1 and the y intercept is -3.
Nimol talks on the phone [tex]3 \frac{1}{2} [/tex] more than his brother. His parents scolded him and asked him to cut down on phone calls.He reduced[tex] \frac{2}{5} [/tex] of the time he used to. How long did his brother spend talking on the Phone.
His brother spent talking on the phone
Step - by - Step Explanation
What to find?
Time Nimol's brother spent talking on phone.
Let x be the time Nimol spent in talking on phone.
Let y be the time Nimol's brother spent talking on phone.
x = y + 3 1/2
x =2/5 ( y + 3 1/2)
I need help with this. Also, i’m aware you can’t see all the graphs listed so just let me know what coordinates would be appropriate and i’ll choose whichever graph has those coordinates.
Answer: Provided the sunglasses inventory which has the number of sunglasses and days in two columns, we have to find the graph which represents this table.
The table can be modeled by a linear equation:
[tex]\begin{gathered} y(x)=mx+b\Rightarrow(1)\Rightarrow\text{ y glasses as function of days x} \\ \\ \end{gathered}[/tex]Finding the slope and y intercept of this equation (1) leads to the following:
[tex]\begin{gathered} m=\frac{\Delta y}{\Delta x}=\frac{(42-58)}{(10-2)}=\frac{-16}{8}=--2 \\ \\ \\ \\ y(x)=-2x+b \\ \\ 58=-2(2)+b\Rightarrow b=58+4=62 \\ \\ \\ \therefore\Rightarrow \\ \\ y(x)=-2x+62\Rightarrow(2) \end{gathered}[/tex]The answer, therefore, is the plot of equation (2) which is as follows:
What are the coordinates of point B on AC such that the ratio of AB to BC is 5 : 6
We have a segment AC, with the point B lying between A and C.
The ratio AB to BC is 5:6.
The coordinates for A and C are:
A=(2,-6)
C=(-4,2)
We can calculate the coordinates of B for each axis, using the ratio of 5:6.
[tex]\begin{gathered} \frac{x_a-x_b}{x_b-x_c}=\frac{2-x_b}{x_b+4}=\frac{5}{6}_{} \\ 6\cdot(2-x_b)=5\cdot(x_b+4) \\ 12-6x_b=5x_b+20 \\ -6x_b-5x_b=20-12_{} \\ -11x_b=8 \\ x_b=-\frac{8}{11}\approx-0.72\ldots \end{gathered}[/tex]We can do the same for the y-coordinates:
[tex]\begin{gathered} \frac{y_a-y_b}{y_b-y_c}=\frac{-6-y_b}{y_b-2}=\frac{5}{6} \\ 6(-6-y_b)=5(y_b-2) \\ -36-6y_b=5y_b-10 \\ -6y_b-5y_b=-10+36 \\ -11y_b=26 \\ y_b=-\frac{26}{11}\approx-2.36\ldots \end{gathered}[/tex]The coordinates of B are (-8/11, -26/11).
A surveyor wants to find the height of a tower used to transmit cellular phone calls. He stands 125 feet away from the tower and meandered the angle of elevation to be 40 degrees. How tall is the tower?
Given
Answer
[tex]\begin{gathered} \tan 40=\frac{h}{125} \\ 0,84\times125=h \\ h=105\text{ ft} \end{gathered}[/tex]height of tower is 105 ft
Find cosθ, cotθ, and secθ, where θ is the angle shown in the figure. Give exact values, not decimal approximations.cosθ=cotθ=secθ=
First let's find the missing value of the hypotenuse:
[tex]\begin{gathered} c^2=a^2+b^2 \\ a=4 \\ b=5 \\ \Rightarrow c^2=(4)^2+(5)^2=16+25=41 \\ \Rightarrow c=\sqrt[]{41} \\ \end{gathered}[/tex]we have that the hypotenuse equals sqrt(41). Now we can find the values of the trigonometric functions:
[tex]\begin{gathered} \cos (\theta)=\frac{adjacent\text{ side}}{hypotenuse} \\ \Rightarrow\cos (\theta)=\frac{4}{\sqrt[]{41}} \\ \sec (\theta)=\frac{1}{\cos (\theta)} \\ \Rightarrow\sec (\theta)=\frac{1}{\frac{4}{\sqrt[]{41}}}=\frac{\sqrt[]{41}}{4} \\ \tan (\theta)=\frac{opposite\text{ side}}{adjacent\text{ side}} \\ \Rightarrow\tan (\theta)=\frac{5}{4} \\ \cot (\theta)=\frac{1}{\tan (\theta)} \\ \Rightarrow\cot (\theta)=\frac{1}{\frac{5}{4}}=\frac{4}{5} \end{gathered}[/tex]The sum of three numbers is 106. The second number is 2 times the third. The first number is 6 more than the third. What are the numbers?First numberSecond number Third number
Let's call the numbers a, b and c.
The first statement tells us that the sum of the three numbers is 106, so:
[tex]a+b+c=106.[/tex]The second statement tells us that the second number is two times the third so:
[tex]b=2c\text{.}[/tex]The final statement tells us that the first number is 6 more than the third, so:
[tex]a=c+6.[/tex]This gives us a system of three equations with three variables. Let's take the value of a given by the third equation, use it in the first one and isolate another variable:
[tex](c+6)+b+c=106,[/tex][tex]2c+b+6=106,[/tex][tex]2c+b=100,[/tex][tex]b=100-2c\text{.}[/tex]Let's take this value of b and use it in the second equation:
[tex]100-2c=2c,[/tex][tex]100=4c,[/tex][tex]c=25.[/tex]Now we know the exact value of c, so let's go back to the third equation:
[tex]a=25+6=31,[/tex]and now we also know the exact value of a, so let's go back to the second equation:
[tex]b=2(25)=50.[/tex]So, the first number (a) is 31, the second (b) is 50 and the third (c) is 25.
31+50+25=106.