To find the quotient of 491 by 3,
We have to divide 491 by 3
So,
[tex]\frac{491}{3}=163.66[/tex]Answer : 163.66
What is 5,421 rounded to the nearest hundred?A.4,000B.5,000C.5,4000D.5,200
We have the following number:
[tex]5,421[/tex]By rounding down this number to the nearest hundred, we get
[tex]5,400[/tex]which corespond to option C
LMNO is a rhombus find at 3s + 12 5x - 2y -6
In this case the answer is very simple. .
To find the solution to the exercise we'll have to carry out several steps.
(3x + 12) = (5x -2)
12 + 2 = 5x - 3x
14 = 2x
14 /2 = x
7 = x
The answer is:
x = 7
For each ordered pair, determine whether it is a solution to the system of equations -5x+4y=2. 3x-5y=4 solution? (x, y) (6,8) it is a solution yes or no. (-4,-4) it is a solutions yes or no. (-7,0) it is a solution yes or no. (3,1) it is a solution yes or no
Check the solutions
(6,8)
(-4,-4)
(-7,0)
(3,1)
To check if the pair is a solution to teh system of equations you must replace x and y on both of the equations and see if the equation is fulfilled
(6,8) Is not a solution to the system of a solutions
[tex]\begin{gathered} \begin{aligned}-5(6)+4(8)=2 \\ 3(6)-5(8)=4\end{aligned} \\ \\ -30+32=2\longrightarrow2=2 \\ 18-40=4\longrightarrow-22\ne4 \end{gathered}[/tex](-4,-4) is not a solution to the system of equations
[tex]\begin{gathered} \begin{aligned}-5(-4)+4(-4)=2 \\ 3(-4)-5(-4)=4\end{aligned} \\ \\ 20-16=2\longrightarrow4\ne2 \\ -12+16=4\longrightarrow4=4 \end{gathered}[/tex](-7,0) is not a solution to the system of equations
[tex]\begin{gathered} \begin{aligned}-5(-7)+4(0)=2 \\ 3(-7)-5(0)=4\end{aligned} \\ \\ 35+0=2\longrightarrow35\ne2 \\ -21-0=4-21\ne4 \end{gathered}[/tex](3,1) is not a solution to the system of equations
[tex]\begin{gathered} \begin{aligned}-5(3)+4(1)=2 \\ 3(3)-5(1)=4\end{aligned} \\ \\ -15+4=2\longrightarrow-11\ne2 \\ 9-5=4\longrightarrow4=4 \end{gathered}[/tex]Write the series using sigma notation to find the sum of the termsDrag the tiles to the correct location is not a tiles will be used
The number over the sigma sign is 5
Explanation:
5 represent the finale value
If possible, find the area of the triangle defined by the following: a = 7, b = 4, y = 43°9.5 square units19.3 square units14 square units16.8 square units
So C = 180 - 23.7 - 35
= 121.3°
[tex]\begin{gathered} \text{ }\frac{C\text{ }}{\sin\text{ C}}\text{ = }\frac{B}{\sin \text{ B}} \\ \frac{C}{\sin\text{ 121.3}}\text{ = }\frac{100}{\sin \text{ 35}} \\ \text{ C = }\frac{100\sin \text{ 121.3}}{\sin \text{ 35}} \\ C\text{ = }\frac{85.44}{0.57} \\ C\text{ = 150 mi} \end{gathered}[/tex]Sally invested $1,200 in an account where interest compounded quarterly. After two years, she had $1,351.79 in her account. What was her interest rate?
use the formula
[tex]A=P(1+\frac{r}{t})^{n\cdot t}[/tex]clear the formula for the rate
[tex]A=P(1+\frac{r}{t})^{n\cdot t}[/tex].
Write an inequality for each of the following Mrs. Champlin needs to make at least 28 costumes for the school play
ok
x = number of costumes
The inequality is:
[tex]\text{ x }\ge\text{ 28}[/tex]where "x" is the number of costumes
In the sentence given, they use the terms "at least", that means that the number must be equal or greater than 28.
In maths, there are five symbol that we can use in inequalities.
= means equal
< means less than
> means greater than
[tex]\begin{gathered} \ge\text{ means greater or equal than} \\ \leq\text{ means less or equal than} \end{gathered}[/tex]
In the sentence given, as they use at least, we must use greater or equal, it means it could be 28 or a greater number.
Can you please me with the question on the picture
Solution
[tex]\begin{gathered} \text{Total marbles= 6+}5+4_{} \\ \text{Total marbles =15 marbles} \end{gathered}[/tex]6blue marbles
5 red marbles
4 white marbles
Part A
Formula
Not white means it blue or 5 = 11
[tex]P(\text{Blue given not white)}=\frac{P(B\text{ n W)}}{P(W)}=\frac{\frac{6}{15}\times\frac{6}{15}}{\frac{11}{15}}=\frac{6}{15}[/tex]Part B
Please finish the following proof using the "prove steps" and write the two-column statements.
Based on the AAS congruence theorem, ΔADB ≅ ΔCDB. The two-column proof for this is explained below.
What is the AAS Congruence Theorem?The AAS congruence theorem states that two triangles are equal or congruent to each other if they have two pairs of congruent angles and a pair of non-included congruent sides.
We are given that ∠ADB and ∠CDB are right angles, therefore, they are congruent to each other. We are also given that ∠A ≅ ∠C.
Also, BD ≅ BD based on the reflexive property of congruency.
Therefore, according to the AAS congruence theorem, ΔADB ≅ ΔCDB.
The two-column proof would be stated as shown below:
Statement Reasons
1. ∠ADB and ∠CDB are right angles 1. Given
2. ∠A ≅ ∠C 2. Given
3. BD ≅ BD 3. Reflexive property
4. ΔADB ≅ ΔCDB 4. AAS congruence theorem
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An archer hits a bullseye 64% of the time. What is the probability the archer hitsthe bullseye exactly 4 times during 10 total attempts?a. 242b. .365C..077d. 168
If the probability of hitting the bullseye is 64% (P(H) = 0.64), then the probability of not hitting the bullseye (P(H_bar)) is:
[tex]P(\bar{H})=1-P(H)=1-0.64=0.36[/tex]Now, if we have 10 attempts, and the archer hits 4 times, then he misses 6 times.
So we have 4 cases of hitting (P(H)) and 6 cases of not hitting(P(H_bar)), and the probability is the product of the probabilities of each case:
[tex]P=P(H)^4\cdot P(\bar{H})^6=(0.64)^4\cdot(0.36)^6=0.16777\cdot0,0021767=0\text{.}0003652[/tex]We also need to multiply this probability by a combination of 10 choose 4, because the 4 hits among the 10 attempts can be any of the 10, in any order:
[tex]C(10,4)=\frac{10!}{4!(10-4)!}=\frac{10!}{4!6!}=\frac{10\cdot9\cdot8\cdot7}{4\cdot3\cdot2}=210[/tex]So the final probability is:
[tex]P^{\prime}=P\cdot C(10,4)=0.0003652\cdot210=0.077[/tex]So the answer is C.
Write each ratio in simplest form1- 300:1082- 5280:8003- 42:1204- 20:965- 24:16
Given:
1) 300:108
[tex]\begin{gathered} \frac{300}{108} \\ \text{Greatest common factor of 300 and 108 is 12.} \\ \frac{300}{108}=\frac{25\cdot12}{9\cdot12}=\frac{25}{9}\Rightarrow25\colon9 \end{gathered}[/tex]2) 5280:800
[tex]\begin{gathered} \frac{5280}{800} \\ \text{Greatest common factor of 5280 and 800 is 160.} \\ \frac{5280}{800}=\frac{33\cdot160}{5\cdot160}=\frac{33}{5}\Rightarrow33\colon5 \end{gathered}[/tex]3) 42:120
[tex]\begin{gathered} \frac{42}{120} \\ \text{Greatest common factor of 42 and 120 is 6.} \\ \frac{42}{120}=\frac{7\cdot6}{20\cdot6}=\frac{7}{20}\Rightarrow7\colon20 \end{gathered}[/tex]4) 20:96
[tex]\begin{gathered} \frac{20}{96} \\ \text{Greatest common factor of 20 and 96 is 4.} \\ \frac{20}{96}=\frac{4\cdot5}{4\cdot24}=\frac{5}{24}\Rightarrow5\colon24 \end{gathered}[/tex]5)
[tex]\begin{gathered} \frac{24}{16} \\ \text{Greatest common factor of 24 and 16 is 8.} \\ \frac{24}{16}=\frac{3\cdot8}{2\cdot8}=\frac{3}{2}\Rightarrow3\colon2 \end{gathered}[/tex]i need some help on this word problem please do it for me (12)
The first thing we need to do is identify the important values, our variables, and our equations that model or describe our problem.
• A total of 560 tickets were sold.
• Tickets can be ,A,dult or ,S,tudent
[tex]A+S=560\to(1)[/tex]• The total of tickets sold $3166
,• The value of the Adult ticket is $8
,• The value of the Student ticket is $3.5
[tex]8A+3.5S=3166\to(2)[/tex]We can see that A and S correspond to the number of Adult or Student tickets sold. We solve the equations to find our numbers.
[tex]A=560-S\to\text{(1)}[/tex][tex]\begin{gathered} 8(560-S)+3.5S=3166 \\ 8\times560-8S+3.5S=3166 \\ S(3.5-8)=3166-4480 \\ -4.5S=-1314 \\ S=\frac{-1314}{-4.5} \\ S=292 \end{gathered}[/tex][tex]\begin{gathered} A=560-292 \\ A=268 \end{gathered}[/tex]In total, 292 Student tickets and 268 Adult tickets were sold.I need the answer as fast as you can give it to me
Explanation
Given
[tex](256x^{16})^{\frac{1}{4}}[/tex]We can simplify the expression below;
[tex]\begin{gathered} =256^{\frac{1}{4}}\times x^{16\times\frac{1}{4}} \\ =\sqrt[4]{256}\times x^{\frac{16}{4}} \\ =4x^4 \end{gathered}[/tex]Answer:
A figure has an area of 100 units `2 what will the new area be after dilation with a scale factor of 2\5
16 u²
1) If a figure has an area and it's been dilated of k= 2/5
2) Then we can sketch that situation, concerning to areas:
So, we can state this dilated figure is going to have an area of 16 u².
Hence, the answer is 16 u²
A If mzABD 61, and mzDBC = 59, then mABC = [ ?P
891 to which closer to hundred
891 is closer to 900.
Consider the following:
800, 820, 840, 860, 880, 900
891 is found between 880 and 900
Thus, the hundred 891 is closer to is 900
bailey buys new winter clothes for $136 she has to pay 8.25% sales tax on her purchase. how much is the sales tax for her new clothes?
Given :
The cost of the new winter clothes = $136
The sales tax = 8.25%
So, the sales tax = 8.25% of 136 =
[tex]\frac{8.25}{100}\cdot136=11.22[/tex]So, the answer is : the sales tax = $11.22
can you please help me
We have two types of crust, each of them with a different type of sauce and choice of toppings. The answer would be 54 single topping pizzas because we have two types of crust for 3 types of sauce 2*3 = 6
and 9 choices of toppings for each of them 6*9 = 54
I need some help on finding the surface area. i don't know how to solve with a triangular base?
The surface area(A) of a triangular pyramid can be found using the formula:
[tex]A\text{ = }\frac{1}{2}\text{ }\times\text{ a }\times\text{ b + }\frac{3}{2}\text{ }\times b\text{ }\times\text{ s}[/tex]Given the triangular prism:
Hence, we have:
a = 3.5 m
b = 4m
s = 11.1 m
Substituting the values into the formula:
[tex]\begin{gathered} A\text{ = }\frac{1}{2}\times3.5\text{ }\times4\text{ + }\frac{3}{2}\text{ }\times\text{ 4 }\times\text{ 11.1} \\ =\text{ 7 + 66.6} \\ =\text{ 73.6 m}^2 \end{gathered}[/tex]Hence, the surface area of the pyramid is 73.6 square meter
3x=4 1/2 I need help to solve for x
We need to solve the equation:
[tex]3x=4\frac{1}{2}[/tex]First, notice that the mixed number 4 1/2 can be written as:
[tex]4\frac{1}{2}=4+\frac{1}{2}[/tex]Now, we can solve the equation for x by dividing both sides of the equation by 3. We obtain:
[tex]\begin{gathered} \frac{3x}{3}=\frac{\mleft(4+\frac{1}{2}\mright)}{3} \\ \\ x=\mleft(4+\frac{1}{2}\mright)\cdot\frac{1}{3} \\ \\ x=4\cdot\frac{1}{3}+\frac{1}{2}\cdot\frac{1}{3} \\ \\ x=\frac{4}{3}+\frac{1}{6} \\ \\ x=\frac{8}{6}+\frac{1}{6} \\ \\ x=\frac{9}{6} \\ \\ x=\frac{3}{2} \\ \\ x=1\frac{1}{2} \end{gathered}[/tex]Therefore, the solution is:
[tex]\mathbf{x=1\frac{1}{2}}[/tex]Answer:
Exact form:
x = 3/2
decimal form:
x = 1.5
mixed number form:
x = 1
1/2
Step-by-step explanation:
I need help with a math assignment i linked the picture below with the question
Answer:
[tex]P\text{ = 29x+5}[/tex]Explanation:
Here, we want to get the perimeter of the rectangle
Mathematically, that is:
[tex]P\text{ = 2(L + B)}[/tex]Where L is the length of the rectangle, given as 6.5x + 9 ft and B is the width of the rectangle which is 8x-6.5
Substituting these values into the formula, we have the perimeter of the rectangle as follows:
[tex]\begin{gathered} P=2(6.5x\text{ + 9 +8x-6.5)} \\ P\text{ = 2(14.5x+2.5)} \\ P\text{ = 29x+5} \end{gathered}[/tex]When planning a cruise, you have a choice of 2 destinations: Cozumel (C) or Jamaica (J); a choice of 4 types of rooms: balcony (B), inside view (I), ocean view (O), or suite (S); and a choice of 2 types of excursions: water sports (W) or horseback riding (H). If you are choosing only one of each, list the sample space in regard to the vacations (combinations of destinations, rooms, and excursions) you could pick from.
Given
There are 2 options for a destination: Cozumel (C) or Jamaica (J)
There are 4 types of rooms : Balcony (B), Inside View (I), Ocean View (O), Suite (S)
There are two types of excursions : Water sports (W) or Horseback (H)
The sample space is a combination of all the available options and can be calculated using the formula:
[tex]\begin{gathered} Sample\text{ space = Number of options for A }\times\text{ Number of options for B }\times \\ Number\text{ of options C} \end{gathered}[/tex]Applying the formula:
[tex]\begin{gathered} Sample\text{ space = 2 }\times\text{ 4 }\times\text{ 2} \\ =\text{ 16 } \end{gathered}[/tex]The list of the combinations is shown below:
CBW, CBH, CIW, CIH , COW, COH, CSW, CSH, JBW, JBH, JIW, JIH, JOW, JOH, JSW, JSH
Use the specified row transformation to change the given matrix.6R_1+R_2
ANSWER:
[tex]6\cdot R_1+R_2=\begin{bmatrix}{0} & 39 & {23} \\ {-6} & {9} & {-1} \\ {3} & {7} & {0}\end{bmatrix}[/tex]STEP-BY-STEP EXPLANATION:
We have the following matrix:
[tex]\begin{bmatrix}{1} & 5 & {4} \\ {-6} & {9} & {-1} \\ {3} & {7} & {0}\end{bmatrix}=\begin{cases}R_1 \\ R_2 \\ R_3\end{cases}[/tex]Now, we apply the following changes
[tex]\begin{gathered} 6\cdot R_1+R_2 \\ 6\cdot R_1=\begin{bmatrix}{6\cdot1} & 6\cdot5 & 6\cdot{4} \\ {-6} & {9} & {-1} \\ {3} & {7} & {0}\end{bmatrix}=\begin{bmatrix}{6} & 30 & {24} \\ {-6} & {9} & {-1} \\ {3} & {7} & {0}\end{bmatrix} \\ 6\cdot R_1+R_2=\begin{bmatrix}{6+(-6)} & 30+9 & {24+(-1)} \\ {-6} & {9} & {-1} \\ {3} & {7} & {0}\end{bmatrix}=\begin{bmatrix}{0} & 39 & {23} \\ {-6} & {9} & {-1} \\ {3} & {7} & {0}\end{bmatrix} \\ 6\cdot R_1+R_2=\begin{bmatrix}{0} & 39 & {23} \\ {-6} & {9} & {-1} \\ {3} & {7} & {0}\end{bmatrix} \end{gathered}[/tex]Find the area of the semicircle. Round to the nearest tenih. Use 3.14 for 3.8 yda. 22.7 yd²b. 23.9 yd²c. 45.3 yd²d. 11.9 yd²
Answer:
[tex]A[/tex]Explanation:
Here, we want to calculate the area of the semi-circle
To get this, we have to calculate the area of the circle and divide by 2
Mathematically, we have that as follows:
[tex]A\text{ = }\frac{\pi r^2}{2}[/tex]where pi is 3.14 and r which is the radius of the circle is 3.8 yd
Mathematically, we calculate the area as follows:
[tex]A\text{ = }\frac{3.14\times3.8^2}{2}\text{ = 22.7 yd}^2[/tex]write a linear equation that has m=4 and has an x intercept of (5,0)
the equation is of the form y = mx + b, then
for b:
[tex]\begin{gathered} 0=4(5)+b \\ 0=20+b \\ 0-20=20+b-20 \\ b=-20 \end{gathered}[/tex]the equation is:
[tex]y=4x-20[/tex]Back | Next Question 2 Indicate the answer choice that best completes the statement or answers the question. Determine if the two figures are congruent by using transformations. Explain your reasonin a. congruent; a rotation followed by a reflection Ob. congruent; a reflection followed by another reflection Oc. congruent; a reflection followed by translation O d. not congruent
b. congruent; a reflection followed by another reflection
If grey shape is reflected across the x-axis and then the y-axis, or viceversa, white shape is obtained.
Use substitution to solve.Solve the first equation for y and substitute it into the second equation. The resulting equati
The first equation is given as,
[tex]\begin{gathered} 2X^2\text{ = 5 +Y} \\ Y\text{ = }2X^2\text{ - 5\_\_\_\_\_\_\_(1)} \end{gathered}[/tex]The second equation is given as,
[tex]4Y\text{ = }-20\text{ }+8X^2_{_{_{_{}}}}\text{ \_\_\_\_\_\_\_\_\_(2)}[/tex]Substituting equation ( 1 ) in equation (2),
[tex]4(\text{ }2X^2\text{ - 5) = }-20\text{ }+8X^2_{_{_{_{}}}}\text{ }[/tex]Simplifying further,
[tex]8X^2-20\text{ = -20 + }8X^2[/tex]Thus the required answer is
[tex]8X^2-20\text{ = -20 + }8X^2[/tex]please solve this for me
The equation of the line in slope intercept form is y = -x + 6
How to write equation of a line in slope intercept form?The equation of a line in slope intercept form can be represented as follows:
y = mx + b
where
m = slopeb = y-interceptThe slope of the line can be found as follows:
using (6, 0) and (5, 1)
m = slope = 1 - 0 / 5 - 6
slope = 1 / -1
slope = -1
Therefore, let's find the y-intercept of the line using (0, 6).
y = -x + b
6 = -(0) + b
b = 6
Therefore, the equation of the line is y = -x + 6
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What is the volume of the solid?8 cm12 cm12 cm16 cm2 cmWe talenteΟ Α112 cubic cmОв192 cubic cmОс224 cubic cmOD304 cubic cm
In this case, we'll have to carry out several steps to find the solution.
Step 01:
Data:
diagram:
solid
Step 02:
geometry:
volume:
we must analyze the figure to find the solution.
volume solid 1:
rectangle:
V = l * w * h
V1 = 12 cm * (16 cm - 12 cm) * 2 cm = 12 cm * 4 cm * 2 cm = 96 cm³
volume solid 2:
rectangle:
V = l * w * h
V2 = 12 cm * 2 cm * (16 cm - 8 cm) = 12 cm * 2 cm * 8 cm = 192 cm³
Total volume:
VT = V1 + V2 = "96 cm + ³192 cm = ³
 Exponential Transformations: Identify if they represent growth or decay, range, horizontal move, vertical move, flip, stretch or shrink Y = 3(1/2) ^x+3 Y = 4^x-3 + 6Y = -2^x - 5 Y = (2/3)^x-2 +1
If b > 1 then it's an exponential growth
If b < 1 then it's an exponential decay
Y = 3(1/2)^(x+3) decay
Y = 4^(x-3) + 6 growth
Y = -2^x - 5 decay
Y = (2/3)^(x-2) +1 decay
The y-intercept is found replacing x = 0 into the equation.
Y = 3(1/2)^(0+3)
Y = 3(1/2)^3
Y = 3(1/8)
Y = 3/8
Y = 4^(0-3) + 6
Y = 4^(-3) + 6
Y = 1/64 + 6
Y = 385/64
Y = -2^0 - 5
Y = -1 - 5
Y = -6
Y = (2/3)^(0-2) +1
Y = (2/3)^(-2) +1
Y = (3/2)^(2) +1
Y = 9/4 +1
Y = 13/4
The vertical movement is found identifying k in the equations.
Y = 3(1/2)^(x+3) k = 0 no vertical move
Y = 4^(x-3) + 6 k = 6 vertical move 6 units up
Y = -2^x - 5 k = -5 vertical move 5 units down
Y = (2/3)^(x-2) +1 k = 1 vertical move 1 unit up
If the equation is flipped or not is seen in the a parameter. If a < 0, it's flipped, if a > 0, it isn't flipped
Y = 3(1/2)^(x+3) a > 0 not flipped
Y = 4^(x-3) + 6 a > 0 not flipped
Y = -2^x - 5 a < 0 flipped
Y = (2/3)^(x-2) +1 a > 0 not flipped
The range is found with help of the vertical move and the flip
Y = 3(1/2)^(x+3) no vertical move, not flipped range: [0, ∞]
Y = 4^(x-3) + 6 vertical move 6 units up, not flipped range: [6, ∞]
Y = -2^x - 5 vertical move 5 units down range: [-5, -∞]
Y = (2/3)^(x-2) +1 vertical move 1 unit up, not flipped range: [1, ∞]
The horizontal movement is found identifying h in the equations.
Y = 3(1/2)^(x+3) h = 3 horizontal move 3 units left
Y = 4^(x-3) + 6 h = -3 horizontal move 3 units right
Y = -2^x - 5 h = 0 no vertical move
Y = (2/3)^(x-2) +1 h = -2 horizontal move 2 units right
If the equation is stretched or shrunk is seen in the a parameter. If a > 1, the function stretches, if 0 < a < 1, 1, the function shrinks
Y = 3(1/2)^(x+3) a = 3 stretches
Y = 4^(x-3) + 6 a = 1 doesn't stretch nor shrink
Y = -2^x - 5 a = -1 doesn't stretch nor shrink
Y = (2/3)^(x-2) +1 a = 2/3 shrinks