First, we transform the mixed fractions into improper fractions:
[tex]\begin{gathered} 2\frac{1}{2}=\frac{2\cdot2+1}{2}=\frac{5}{2}, \\ 1\frac{1}{4}=\frac{1\cdot4+1}{4}=\frac{5}{4}. \end{gathered}[/tex]Then, we multiply the improper fractions:
[tex]\frac{5}{2}\cdot\frac{5}{4}=\frac{5\cdot5}{2\cdot4}=\frac{25}{8}\text{.}[/tex]Finally, we transform the improper fraction into a mixed fraction:
[tex]\frac{25}{8}=\frac{24+1}{8}=\frac{3\cdot8+1}{8}=3\frac{1}{8}\text{.}[/tex]Answer:
[tex]3\frac{1}{8}\text{.}[/tex]How can you compare two or more fractions so as to arrange them in ascending or descending order?
There are two ways to arrange them in ascending or descending order.
The first way is to convert them into similar fractions (if they are not similar fractions yet), and arrange them in the order that you like.
[tex]\begin{gathered} \text{Example} \\ \frac{2}{3},\frac{1}{2},\frac{3}{4} \end{gathered}[/tex]Convert them to similar fractions, by getting their LCD and we have
[tex]\begin{gathered} \text{LCD}(2,3,4)=12 \\ \frac{2}{3}=\frac{8}{12} \\ \frac{1}{2}=\frac{6}{12} \\ \frac{3}{4}=\frac{9}{12} \end{gathered}[/tex]We can now arrange them based on their numerators
[tex]\begin{gathered} \text{Ascending} \\ \frac{6}{12},\frac{8}{12},\frac{9}{12}\Longrightarrow\frac{1}{2},\frac{2}{3},\frac{3}{4} \\ \\ \text{Descending} \\ \frac{9}{12},\frac{8}{12},\frac{6}{12}\Longrightarrow\frac{3}{4},\frac{2}{3},\frac{1}{2} \end{gathered}[/tex]Another way to arrange them is to get their decimal equivalent, and arrange them accordingly
[tex]\begin{gathered} \text{Example} \\ \frac{2}{3}=0.67 \\ \frac{1}{2}=0.5 \\ \frac{3}{4}=0.75 \\ \\ \text{Ascending} \\ 0.5,0.67,0.75\Longrightarrow\frac{1}{2},\frac{2}{3},\frac{3}{4} \\ \\ \text{Descending} \\ 0.75,0.67,0.5\rightarrow\frac{3}{4},\frac{2}{3},\frac{1}{2} \end{gathered}[/tex]I need to figure out how or where to find the standard deviation and mean for this problemGiven that z is a standard normal random variable, compute the following probabilities.a. P(z≤−1.0)b. P(z≥−1)c. P(z≥−1.5)d. P(−2.5≤z)e. P(−3
a.
P(z≤−1.0)
Using the z - score table, that gives the probabilities to the left side of the z score:
P ( z ≤−1.0) = 0.1587
b. P(z≥−1)
1 - P ( z ≤−1.0) = 1 - 0.1587 = 0.8413
c. P(z≥−1.5)
1 - P(z≤−1.5) = 1 -0.0668 = 0.9332
d. P(−2.5≤z)
P (z ≥ -2.5)
1 - P (z ≤-2.5) = 1 - 0.0062 = 0.9938
e. P(−3
P ( z≤0 ) = 0.5
P ( z ≤ -3 ) = 0.0013
P ( z ≤ 0 ) -P (z < -3) = 0.5 - 0.0013 = 0.4987
In the figure below, ∠ABC ≅ ∠DEC and ∠GFE ≅ ∠DCE. Point C is the point of intersection between segment AG and segment BD , while point E is the point of intersection between segment AG and segment DF.
Prove ΔABC ∼ ΔGEF.
A figure is given with :-
∠ABC ≅ ∠DEC
∠GFE ≅ ∠DCE
Point C is the point of intersection between segment AG and segment BD.
Point E is the point of intersection between segment AG and segment DF.
We have to prove that ΔABC ∼ ΔGEF.
As ∠ABC ≅ ∠DEC
We can write,
∠DEC = ∠FEG (Vertically opposite angles)
Similarly,
As ∠GFE ≅ ∠DCE
We can write,
∠DCE = ∠ ACB (Vertically opposite angles)
Hence,
∠ ACB = ∠DCE = ∠GFE
∠ ACB = ∠GFE
Also,
∠FEG = ∠DEC = ∠ ABC
∠FEG = ∠ ABC
Hence, by using AA corollary, we can write,
ΔABC ∼ ΔGEF
Hence, proved.
To learn more about Vertically opposite angles, here:-
https://brainly.com/question/18045519
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the ferris wheel is drawn on a coordinate plane so that the first car is located at the point ( 0, 80). what are the coordinates of the first car after a 270° counterclockwise about the originthe coordinate of the first car are........ after a rotation of 270° about the origin
We can draw the following picture:
That is, the coordinates are (80,0)
simply 3 (sqrt(c^2)) if c is > or equal to 0I can upload a picture
Recall that:
[tex]\begin{gathered} \text{For all x}\in\R \\ \sqrt[]{x^2}=|x|\text{.} \end{gathered}[/tex]Therefore:
[tex]3\sqrt[]{c^2}=3|c|\text{.}[/tex]Now, since c≥0, we get that:
[tex]|c|=c\text{.}[/tex]Substituting the above result in 3|c| we get:
[tex]3\sqrt[]{c^2}=3c\text{.}[/tex]Answer:
[tex]3c\text{.}[/tex]The perimeter of a square is 56 cm. What is the approximate length of its diagonal ? 10.6 cm 14.0 cm15.0 cm18.8 cm
We are given the perimeter of a square. Since a square has all of the sides of the same length the perimeter is, therefore:
[tex]P=4l[/tex]Where "l" is the length of the side. Solving for "l" by dividing both sides by 4:
[tex]\frac{P}{4}=l[/tex]Replacing the value of "P":
[tex]\frac{56}{4}=l[/tex]Solving the operations:
[tex]l=14[/tex]The length of the diagonal of a square is given by:
[tex]d=l\sqrt[]{2}[/tex]Replacing the value of the length we get:
[tex]d=14\sqrt[]{2}[/tex]Solving the operation:
[tex]d=19.8[/tex]Therefore, the length of the diagonal is 19.8 cm.
The function h(x) = 1/x-7 can be expressed in the form f(g(x)), where g(x) = x-7), and f(x) is defined as:f(x) =
Answer:
f(x) = 1 /x
Explanation:
We know that
[tex]h(x)=f(g(x))=\frac{1}{x-7}[/tex]and
[tex]g(x)=x-7[/tex]Now, what must be the form of f(x)?
Let us guess.
If we said
[tex]f(x)=\frac{1}{x}[/tex]then what would be f(g(x)) in this case?
To find out we simply replace x with g(x). This gives
[tex]f(g(x))=\frac{1}{g(x)}[/tex][tex]\Rightarrow f(g(x))=\frac{1}{x-7}[/tex]which is exactly the form we are told f(g(x)) take! This means our guess was correct and
[tex]\boxed{f(x)=\frac{1}{x}\text{.}}[/tex]Hi, can you help me answer this question please, thank you
The test statistic, z, is computed as follows:
[tex]z=\frac{\bar{x}-\mu}{\frac{\sigma}{\sqrt[]{n}}}[/tex]where:
x: sample mean
μ: population mean
σ: standard deviation
n: number of samples
Substituting with x = 89.7, μ = 84.9, σ = 13.9, and n = 61, we get:
[tex]\begin{gathered} z=\frac{\bar{89.7}-84.9}{\frac{13.9}{\sqrt[]{61}}} \\ z=2.697 \end{gathered}[/tex]The graph of Ax), shown below, resembles the graph of G(X) = x2, but it hasbeen changed somewhat. Which of the following could be the equation ofFx)?600 = x2-5OTFC) = ?AO A. F(X) = 3(x - 2)2 - 2B. F(x) = -3(x - 2)2 - 2C. F(x) = -3(x+ 2)2 - 2D. F(x) = 3(x + 2)2 - 2
The correct answer is option C
Explanation
First observation; the graph f(x) is n- shaped, so the coefficient of x^2 must be negative. This means option A and option D cannot be the answer
We have to channel our focus to option B or C
From the graph f(x), when x = -1, f(-1) = -5
Test option B and option C by substituting x= -1 into f(x) and check which options gives -5 as the answer
Testing option c
f(-1) = -3(-1 + 2)^2 -2
=-3(1) -2
= -3 - 2
=-5
f(-1) = -5
Since f(-1) = -5, which gives a correct value as we have on the graph,
Then the answer is option C
Find the 5 number summary for the data shownx2.72.97.27.58.511.215.418.3
2.7 ,2.9, 7.2, 7.5, 8.5, 11.2,15.4, 18.3
The minimum is the smallest number in the data : 2.7
The maximum is the largest number in the data : 18.3
Next, we find the median, which is the middle number in the data when arranged from smallest to largest. There are 8 numbers, so we will average the middle 2 numbers
2.7 ,2.9, 7.2, 7.5, 8.5, 11.2,15.4, 18.3
The middle is between the 4th and 5th numbers
( 7.5 + 8.5) / 2 = 16/2 = 8
The median(Q2) is 8
To find Q1 ( the 1st quartile), we take the numbers below the mean
2.7 ,2.9, 7.2, 7.5,
and find the median of these numbers
There are 4 numbers so the middle is between the 2nd and 3rd numbers
2.7 , 2.9, 7.2, 7.5,
(2.9+7.2) /2 =5.05
Q1 = 5.05
We will do the same process for Q3, which is the third quartile. We will use the numbers above the median
8.5, 11.2,15.4, 18.3
( 11.2 + 15.4) /2 =13.3
Q3 = 13.3
compute the monthly cost of the cellular phone for use of the following anytime minutes.
ANSWER:
(a) $29.99
(b) $37.49
(c) $30.24
STEP-BY-STEP EXPLANATION:
We have a function by part to calculate the monthly cost of a cell phone plan.
If the consumption is between 0 and 300 minutes, the value will always be $29.99. While if the consumption is greater than 300 minutes, the value is given by the following equation:
[tex]C\mleft(x\mright)=0.25x-45.01[/tex]Knowing the above, we calculate in each case:
(a) 190 minutes.
It is in the interval between 0 and 300 minutes, therefore, the cost is $29.99.
C (190) = $29.99
(b)
[tex]\begin{gathered} C(330)=0.25\cdot330-45.01 \\ C(330)=82.5-45.01 \\ C(330)=37.49 \end{gathered}[/tex](c)
[tex]\begin{gathered} C(301)=0.25\cdot301-45.01 \\ C(301)=75.25-45.01 \\ C(301)=30.24 \end{gathered}[/tex]an item is regularly priced at $30. it is on sale for 40% off the regular price. how much (in dollars) is discounted from the regular price? thank you for helping
ANSWER
$12
EXPLANATION
The item is regularly priced at $30.
It is on sale for 40% off. So, 40% of the price is cut off, so that the buyer only pays 60%.
The amount discounted from the original price is 40% of $30. That is:
[tex]\begin{gathered} \frac{40}{100}\text{ of \$30} \\ \Rightarrow\text{ }\frac{40}{100}\cdot\text{ 30} \\ =\text{ }\frac{40\cdot\text{ 30}}{100} \\ =\text{ }\frac{1200}{100} \\ =\text{ \$12} \end{gathered}[/tex]The answer is $12
If the coefficient of determination is 0.233, what percentage of the variation in the data about the regression line is explained?5.43%76.7%23.3%46.6%
We need the coefficient of determination definition
The coefficient of determination (R²) is a number between 0 and 1 that measures how well a statistical model predicts an outcome. You can interpret the R² as the proportion of variation in the dependent variable that is predicted by the statistical model
So if we have a coefficient of determination of 0.233 we multiply by 100 to get the percentage
Answer: 23.3%
Pls help some one and can you explain how you do it
Answer:
about 37
Step-by-step explanation:
(8x-23) ----> divide
---- ----
8. 8. ------> 8x cancels out and is just x
x- 2.875+34 =. 37
a sofa is on sale for $289, which is 32% less than the regular price what is the regular price
6149488990ay, this is the solution:
Let's use the Direct Rule of Three for answering this problem, this way:
Price Percentage
289 68
x 100
___________________
28,900 = 68x
68x/68 = 28,900/68
x = 425
The regular price of the sofa is $ 425, and you will save $ 136 if you buy it on sale.
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What percent of the runs are intermediate
Solution
For this case we have the following
[tex]\frac{56}{144}\cdot100=38.89[/tex]If we round to the nearest whole number we got:
39%
Expand the expression.3(x - 5)
solve for x
[tex]\begin{gathered} 3x=15 \\ \frac{3x}{3}=\frac{15}{3} \\ x=5 \end{gathered}[/tex]A cylindrical can that is four inches tall and has a radius of 1.5 inches can hold 10¢
worth of soda. Assuming that the value of the contents is proportional to the size
(volume) of the can, what would be the value of the soda contained in a can that is 8
inches tall with a radius of 3 inches?
A. 40€
B. 90d
C. 20¢
E. None of these
D. 80¢
Find the quadratic equation using the points given (-1,2), (0,1) and (-2,5).
The general equation for a quadratic equation is,
[tex]y=ax^2+bx+c[/tex]Substititute the values to obtain the equations for the coefficients.
[tex]\begin{gathered} 2=a(-1)^2+(-1)b+c \\ a-b+c=2 \end{gathered}[/tex][tex]\begin{gathered} 1=a(0)^2+b(0)+c \\ c=1 \end{gathered}[/tex]and
[tex]\begin{gathered} 5=a(-2)^2+b(-2)+c \\ 4a-2b+c=5 \end{gathered}[/tex]Substitute the value of c in the equation a-b+c=2 to obtain the equation for a and b.
[tex]\begin{gathered} a-b+1=2 \\ a=1+b \end{gathered}[/tex]Substitute the value of a and c in the equation 4a-2b+c=5 to obtain the value of b.
[tex]\begin{gathered} 4(1+b)-2b+1=5 \\ 4-2b+1=5 \\ 2b=0 \\ b=0 \end{gathered}[/tex]Substitute the value of b in the equation a=1+b to obtain the value of a.
[tex]\begin{gathered} a=1+0 \\ a=1 \end{gathered}[/tex]So quadratic equation for a=1, b=0 and c=1 is,
[tex]y=x^2+1[/tex]In the following diagram, AB bisects CD at E. Which of the following must be true?(1) CE is twice the length of CD(2) BE is half the length of AB(3) AE and BE are the same length (4) E is the midpoint of CD
EXPLANATION:
In the graph we can see that by bisecting point E in line C and D it does not remain in equal parts as if it can be seen in A and B, then the most accurate answer according to the graph would be the following:
(1) CE is twice the length of CD.
the winner in a recent Los Angeles marathon ran the 26-mile race in 2.23 hours. How many yards per minute did he run? Round to the nearest hundredth
Distance = 26 miles
Time = 2.23 hours
1 mile = 1760 yards
26 m = 26 x 1760 = 45760 yards
1 hours = 60 minutes
2.23 h = 2.23 x 60 = 133.8 minutes
Speed rate = distance / time
Replacing:
S = 45760 y / 133.8 m = 342 yards per minute
There are 5 blue marbles, 2 red marbles, and 3 green marbles in a bag. What is theprobability of selecting a red marble? Your answer can be a fraction, decimal orpercent.
Given
There are 5 blue marbles, 2 red marbles, and 3 green marbles in a bag
[tex]\begin{gathered} \text{Total Marbles =5+2+3} \\ \text{Total Marbles =10} \end{gathered}[/tex]Probability of selecting a red marble
[tex]\text{Probability of selecting a red marble =}\frac{2}{10}=\frac{1}{5}[/tex]The final answer
The probability of selecting a red marble
[tex]\frac{1}{5}[/tex]Determine the scale factor for each dilation. Determine whether the dilation is an enlargement, reduction, orisometry dilation.A8DD
The length of sides of the original image ABCD is
AB = 4
BC = 4
CD = 4
DA = 4
The length of the sides of ABCD after the dilation is
A'B' = 2
B'C' = 2
C'D' = 2
D'A' = 2
As you can see, the lengths are reduced by one-half (1/2).
So, it is clearly a reduction.
Therefore, the correct answer is the 2nd option.
1/2, reduction
How much does a customer pay for three memory cards if the store increases the percent of discount in part (b) by 2%.Part (b) was 5%
discount was 2%
Cost of 3 mem cards
A + B + C = X
2% of X = X+ (2/100)X
Then
Cost of 2 mem cards= $47.50
5% of $47.50 = $2.375
Cost of 3 mem cards = 47.50 + 47.50/2= 47.50 + 23.75= $71.25
Now find 2% 0f 71.25
= (2/100)x71.25= $1.425
Then
customer pays
$71.25 - $1.425= 69.83
Answer is
customer pays $69.83 for three memory cards
Find the volume of this object.Use 3 for a.Volume of a CylinderV=Tir2h4 cm7 cm8 cm]1 cm V ~ [?]cm31
Explanation
The volume of the object is the sum of the volumes of the composite solids that make up the object. Since each solid is a cylinder, we will make use of the formula below.
[tex]\text{Volume of a cylinder =}\pi r^2h[/tex]The question gives the following parameters for the solids
[tex]\begin{gathered} \text{Solid 1 }\mleft\lbrace r=\frac{4}{2}=2;h=7\mright\rbrace \\ Solid\text{ 2 }\mleft\lbrace r=\frac{8}{2}=4;h=1\mright\rbrace \\ \text{where }\pi=3 \end{gathered}[/tex]We can substitute the parameters into the formula.
[tex]\begin{gathered} \text{Volume of solid 1=}3\times2^2\times7=84\operatorname{cm}^3 \\ \text{Volume of solid 2 = }3\times4^2\times1=48cm^3 \end{gathered}[/tex]Therefore;
[tex]\text{Volume of the object }=84+48=132\operatorname{cm}^3[/tex]Answer:
[tex]132\operatorname{cm}^3[/tex]A line passes through the point (-1,-13) and has a slope of 6. An equation of the line is
Recall that the slope-intercept form of the equation of a line is:
[tex]y=mx+b,[/tex]where m is the slope of the line and b is the y-intercept.
To take the given equation to its slope-intercept form, first, we multiply it by x+1 and get:
[tex]\begin{gathered} y+13=6(x+1), \\ y+13=6x+6. \end{gathered}[/tex]Subtracting 13, we get:
[tex]\begin{gathered} y=6x+6-13, \\ y=6x-7. \end{gathered}[/tex]Answer:
[tex]y=6x-7.[/tex]Find the volume of the solid who’s base is the region in the first quadrant bounded by y=x^3, y=1, and the y-acid and who’s cross sections perpendicular to the y axis are equilateral triangles
The given parameters are:
y=x^3, y=1
From the question,
If Mike buys 2 pounds of basmati rice and 3.9 pounds of brown rice, how much will he spend? brown rice $3 per lb basmati rice $4 per lb white rice $4 per lb Bhutanese red rice $3 per lb sticky rice $3 per lb
Mike wants to buy 2 lb of basmati rice and 3.9 lb of brown rice.
The prices are given as
Basmati rice = $4 per lb
Brown rice = $3 per lb
How much will he spend?
Simply multiply the quantity of rice by its price
[tex]\begin{gathered} Basmati\: rice=2\times\$4=\$8 \\ Brown\: rice=3.9\times\$3=\$11.7 \end{gathered}[/tex]So the total amount is
[tex]Total\: amount=\$8+\$11.7=\$19.7[/tex]Therefore, Mike will spend $19.7
Mr. Weinberg harvests apples from his apple tree each autumn. As the tree has matured since it's first crop, the weight in lbs, W, of the apple harvest has increased exponentially by 60% every 4 years according to the function W (t)=80(1.6)^ t/4, where the t is the number of years since the first crop.Based on this model, which is the best estimate for the percent change in the weight of the apple harvest from year to year?-26.5%-15.0%-40.0%-8.8%-12.5%
Answer:
12.5%
Explanation:
To know the percent of change from year to year, we will calculate the Weight for 2 consecutive years.
So, when t = 0, we get that W is equal to:
[tex]\begin{gathered} W_0=80(1.6)^{\text{ t/4}} \\ W_0=80(1.6)^{\text{ 0/4}} \\ W_0=80 \end{gathered}[/tex]Then, when t = 1, we get:
[tex]\begin{gathered} W_1=80(1.6)^{\text{ t/4}} \\ W_1=80(1.6)^{\text{ 1/4}} \\ W_1=89.97 \end{gathered}[/tex]Now, we can calculate the percentage of change as:
[tex]\frac{W_1-W_0}{W_0}\times100=\frac{89.97-80}{80}\times100=12.47\text{ \%}[/tex]Therefore, the best estimate is 12.5%
there are 4 girls and 16 boys on the dodgeball team. What is the ratio of girls to the total number of kids on the team?
Given:
The number of girsl is, 4
The number of boys is, 16
Therefore the total number of kids is,
[tex]16+4=20[/tex]Taking the ratio of number of girsl to the tital number of kids, we have,
[tex]\frac{4}{20}=\frac{1}{5}[/tex]The required ratio is 1 : 5.