Naturally occurring Uranium: 99.2745 %
Nuclear fuel for power generation: 97%
Nuclear bombs: 90 %
With a relative abundance of 99%, uranium-238 (238U or U-238) is the most prevalent isotope of uranium to be discovered in nature. It is non-fissile, unlike uranium-235, hence it cannot support a chain reaction in a thermal-neutron reactor.
A 1000 MWe pressurized water reactor needs about 27 tonnes of uranium per year, or over 18 million fuel pellets contained in more than 50,000 fuel rods. In contrast, a coal power plant of comparable scale would require more than 2.5 million tonnes of coal to generate the same amount of electricity.
15 kilograms: weight of a solid sphere of 100 percent uranium-235, just large enough to reach a critical mass with a beryllium reflector, nuclear weapons normally use a concentration of more than 90 percent.
Hence, the percentages are 99.27, 97 and 90% respectively.
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What is the molality of a solution containing 10.0 g Na»SO dissolvedin 1000.0 g of water?
Given Data
mass of solute Na 10.0 g
mass of solvent 1000.0g water
to calculate:
molality of solution
molalilty is defined as the mols of a solute divided by the Kg of the solvent
therefore mols of Na = mass/ molar mass
= 10.0g/22.98g/mol
= 0.44 mols
1 Kg = 10000. grams
Therefore molality of solution
= 0.44 mols/ 1 Kg
= 0.44 mols/Kg
Research: Find 4 strategies that are used to prevent rusting of car parts and/or water pipes? Briefly explain how they work in your own words. What are some pros and cons of these methods?
Question
Research: Find 4 strategies that are used to prevent rusting of car parts and/or water pipes? Briefly explain how they work in your own words. What are some pros and cons of these methods?
Answer
Method 1: Applying Oil - Coating materials with oil will help to prevent rust or slow its formation since it prevents moisture from reaching the iron, which can get oxidized.
Pros: It can be applied easily to most materials and it's of relatively low cost
Cons: Some materials can't be covered with oil because they can interfere with the process they are designed for. Example: Food transport machinery
Method 2: Paint the metal - Similarly to the oil a good amount of paint can cover the metallic parts and prevent moisture from the air to get in direct contact with the iron.
Pros: It is easy to apply paint to most metals.
Cons: Contrarily to oil, paint can be more expensive depending on the application.
Method 3: Galvanization - is the process of applying a protective zinc coating to iron or steel materials to prevent or slow the rusting processes.
Pros: The galvanization process makes steel highly durable and the material usually becomes scratch free.
Cons: Steel structures that are either too big or too small are unsuitable for the galvanization process.
Method 4: Store in a controlled environment - Metals corrode easily when exposed to environments with high humidity. To preserve a metal in good condition, it should be stored in environments with low humidity content and not in contact with salts or acids.
Pros: It does not alter the properties of the equipment.
Cons: Not all metal objects can be stored in environments containing low humidity.
A slime mold is one of the slowest-moving organisms, traveling at top speeds of 1.02 millimeters per hour. What is the speed of a slime mold in inches per day?
We are given a speed of 1.02 mm/hr and we have to convert that speed into inches/day. To find the answer to our problem we can use a 2 steps conversion. First we can convert mm into inches and then the hr into days.
We know that there are 25.4 mm in 1 inch. So let's convert it.
25.4 mm = 1 inch
Speed = 1.02 mm/hr * 1 inch / (25.4 mm) = 0.04016 inch/hr
Speed = 0.04016 inch/hr
Then we know that there are 24 hours in 1 day.
24 hrs = 1 day
Speed = 0.04016 inch/hr * 24 hr/(1 day) = 0.964 inch/day
Speed = 0.964 inch/day
The speed of a slime mold in inches per day is 0.964.
How has computer modeling made weather
predictions more accurate?
Answer:
Smaller grid spacing closes the gap on observations in time and space, resulting in higher resolution model output that is more accurate and reliable.
Determine the pOH of a solution that has a [H+] of 0.0059
answer and explanation
the sum of pH and pOH is always equal too 14
and so if we apply that principle we have the following
pOH + pH = 14
and we are told that the pH is 0.0059 so we substitute this in the equation
pOH +0.0059 = 14
pOH = 14 - 0.0059
pOH = 13.99
How does the force that holds ions together explain the properties of an ionic compound?
There are a lot of properties of ionic compounds to explain.
The most characteristic ones are:
- High melting points
- Hard and brittle
- Electrical conductivity
All of these can be explained by the forces in ionic compounds.
The forces that maintain the ions together are electrostatic forces, which come from the charged ions with opposite signs.
Electrostatic forces are very strong, so and in ions this occur in a crystal lattice, so we need a lot of energy to break this attraction. Because of that, we need a high temperature to make it has enough energy to break this attraction and melt.
This strong attraction also makes the ionic compounds hard to break, because we will need a lot of force to break the ions appart. However, once enough force is applied, its lattice structure is shifted and ions with same charge becomes close to each other, making a repulsive force that breaks them appart, giving them the brittle property.
An electrical conductivity happens when there are free charges in a system. The ionic compounds are composed by charged particles, so if they are free to move, they will conduct electricity. So, when the compound is melted of dissolved, the charged ions, that once were together by the electrostatic force, now can conduct electricity.I have finished answering the question.
Dichlorobenzene exists in three forms. For each of the following write the name of the compound with a numerical designation indicating the location of the chlorine atoms A. Ortho - dichlorobenzene B. Para - dichlorobenzeneC. Meta - diclorobenzine
Please, look at the next drawing:
One of the reactions used to inflate automobile airbags involves sodium azide (NaN3): 2NaN3(s) ⇨ 2Na(s) + 3N2(g)Determine the mass of N2 produced from the decomposition of NaN3 shown at right
Step 1
The reaction provided:
2 NaN3 (s) ⇨ 2 Na (s) + 3 N2 (g) (completed and balanced)
---------------------
Step 2
Information provided:
100.0 g NaN3 decomposes
-----
Information needed:
The molar masses of:
NaN3) 65.00 g/mol
N2) 28.00
(please, the periodic table is useful here)
---------------------
Step 3
Procedure
By stoichiometry,
2 NaN3 (s) ⇨ 2 Na (s) + 3 N2 (g)
2 x 65.00 g NaN3 ----------------- 3 x 28.00 g N2
100.0 g NaN3 ----------------- X
X = 100.0 g NaN3 x 3 x 28.00 g N2/2 x 65.00 g NaN3
X = 64.62 g
Answer: 64.62 g of N2 produced
ch3)2c(oh)ch2ch3 skeletal structure, Functional groups, compound type & alcohol class if it’s an alcohol
The skeletal structure of an organic compound is an abbreviated representation of its molecular structure, they are quick and easy to draw.
For example, the following image shows the skeletal structure of a compound:
The peaks represent the carbons. We must remember that carbon can have a maximum of 4 bonds.
Now, I will show you how is the structure of this specific compound:
This is ternary alcohol, called 2-methyl-2-butanol. If you see carefully, you will notice that each carbon has 4 bonds. The functional groups present will be OH. The skeletal structure will be:
Solutions of potassium iodide and lead (II) are mixed. The resulting lead compound is a precipitate.a) substitute symbols and formulas for words b) predict the products. If no reaction occurs, write "NR" after the yields sign. c) include abbreviations for the physical state d) balance the equation
The two compounds that react are:
Potassium iodide: KI
Lead (II):
[tex]Pb^{+2}[/tex]When the two solutions are mixed the following reaction takes place:
[tex]2KI(aq)+Pb^{+2}(aq)\text{ }\rightarrow2K^{+1}(aq)+PbI_2\text{ (s)}[/tex]The resulting product is called lead (II) Iodide.
Hi I hope can make a better deal for you and this is a wonderful
To answer this question we have to find the value of ka, to do it, we can use the value of kb. The product of the kb of a base and the ka of its conjugated base is kw(1x10^-14):
[tex]\begin{gathered} k_a\cdot k_b=k_w \\ k_a=\frac{k_w}{k_b} \\ k_a=\frac{1\times10^{-14}}{4.38\times10^{-5}} \\ k_a=2.88\times10^{-10} \end{gathered}[/tex]Now, we have to use the equation of Hendersson and Hasselbach:
[tex][/tex]What is the name of the compound P4Cl7?
1. phosphorus(IV) heptachloride
2. phosphorus hexachloride
3. potassium(IV) chloride
4. tetraphosphorus heptachloride
5. quattrophosphorus sevenchloride
6. tetraphosphorus chlorate
4
beacause it is4 is teta and 7 is hepta
If a solution contained a substance of 4.67kg (molar mass of 34.6 g/mol) in 350mL, what is the molarity of the solution?
The molarity of a solution is the molar concentration of it.
It is calculated by:
[tex]M=\frac{n}{V}[/tex]Where n is the number of moles of the substance in the solution and V is the total volume of the solution.
The volume was given:
[tex]V=350mL=0.350L[/tex]And the number of moles we can calculate using the given mass and the molar mass:
[tex]\begin{gathered} m=4.67\operatorname{kg}=4670g \\ MM=34.6g/mol \end{gathered}[/tex]So:
[tex]\begin{gathered} MM=\frac{m}{n} \\ n=\frac{m}{MM}=\frac{4670g}{34.6g/mol}=134.97\ldots mol \end{gathered}[/tex][tex]M=\frac{134.97\ldots mol}{0.350L}=385.63\ldots mol/L\approx386mol/L[/tex]Thus, the molarity is approximately 386 mol/L.
Patrick is a 16 year old boy whose body has stopped producing osteoclasts. What does this mean for his bones? What other parts of
his body will be affected by this?
Answer:
Osteoclasts are the only bone resorbing cells, so, when his body stops producing osteoclasts, it results in deficiency of bone turnover and In osteopetrotic-like diseases.The bone will be affected by this.
Determine the pH of a 0.536002 M C6H5CO2H M solution if the Ka of C6H5CO2H is 6.5 x 10-5. Record your answer to two decimal places
To solve this problem, we could use the ICE table as follows:
First of all, the reaction that we're working with is:
[tex]C_6H_5CO_2H\leftrightarrow C_6H_5CO^-_2+H^+_{}[/tex]Now, let's make the table:
As you can notice, the initial concentration of C6H5CO2H is 0.536002M, and as the products haven't been formed yet, their concentration is 0.
When the change happen, the concentration of the reactant will decay "x" and the concentration of the products will increase "x". (That's the reason of the signs).
And finally, the equilibrium.
We also know that:
[tex]K_a=6.5\cdot10^{-5}[/tex]And, this equilibrium constant comes from the following:
[tex]K_a=6.5\cdot10^{-5}=\frac{\lbrack H^+\rbrack\lbrack C_6H_5CO^-_{2^{}}\rbrack}{\lbrack C_6H_5CO_2H\rbrack}[/tex]Where all concentrations are the equilibrium concentrations.
If we replace, we got that:
[tex]\begin{gathered} 6.5\cdot10^{-5}=\frac{\lbrack H^+\rbrack\lbrack C_6H_5CO^-_{2^{}}\rbrack}{\lbrack C_6H_5CO_2H\rbrack} \\ \\ 6.5\cdot10^{-5}=\frac{x\cdot x}{0.536002-x} \\ \\ 6.5\cdot10^{-5}=\frac{x^2}{0.536002-x} \end{gathered}[/tex]We're going to solve this equation for x:
[tex]\begin{gathered} 6.5\cdot10^{-5}(0.536002-x)=x^2 \\ =3.484013\cdot10^{-5}-6.5\cdot10^5x-x^2=0 \end{gathered}[/tex]And, using the quadratic formula we obtain that the value of x is 0.000587014 approximately.
Now, if x=0.000587014, that means that [H+] = 0.000587014
And finally, remember that the pH of a solution is defined as:
[tex]\begin{gathered} pH=-\log \lbrack H^+\text{\rbrack} \\ pH=-\log \lbrack0.000587014\rbrack \\ pH=3.23 \end{gathered}[/tex]Therefore, the pH is 3.23.
Calculate the [H3O+] of the following solutions: ph = 11.8
Answer:
The [H3O+] is 1.58x10-12 M.
Explanation:
To calculate the [H3O+] from the pH, we can use the pH formula and replace the value of pH:
[tex]\begin{gathered} pH=-log{}\lbrack H_3O^+\rbrack \\ 11.8=-log\lbrack H_3O^+\rbrack \\ 10^{(-11.8)}=\lbrack H_3O^+\rbrack \\ 1.58*10^{-12}=\lbrack H_3O^+\rbrack \end{gathered}[/tex]So, the [H3O+] is 1.58x10-12 M.
Silver nitrate reacts with potassium chloride according as indicated by the balanced equation:AgNO₃ + KCl -----> AgCl + KNO₃How many grams of KCl would be required to react with 380 mL of 0.71 M AgNO₃ solution?.Answer in units of grams
Silver nitrate reacts with potassium chloride according as indicated by the balanced equation:
AgNO₃ + KCl -----> AgCl + KNO₃
How many grams of KCl would be required to react with 380 mL of 0.71 M AgNO₃ solution?.
First we have to find the number of moles in the solution of AgNO₃, then we can find the number of moles of KCl that will react with those moles of AgNO₃, and finally we can convert the moles of KCl into grams using the molar mass of KCl.
So, molarity is defined as the number of moles of solute divided the volume of solution in L.
Molarity = moles of AgNO₃/volume of solution in L
moles of AgNO₃ = molarity * volume of solution in L
We have 1000 mL in 1 L. We can use that conversion to find the volume of solution in L.
1000 mL = 1 L
Volume of solution in L = 380 mL * 1 L /1000 mL = 0.380 L
Volume of solution in L = 0.380 L
Now we can find the number of moles contained in 380 ml (or 0.380 L) of 0.71 M AgNO₃ solution.
moles of AgNO₃ = molarity * volume of solution in L
moles of AgNO₃ = 0.71 M * 0.380 L
moles of AgNO₃ = 0.270 moles
AgNO₃ + KCl -----> AgCl + KNO₃
We can compare the equation of a chemical reaction with a recipe. The coefficients are the quantities of that recipe. Since all the coefficients are 1, we can read our reaction like this: "1 mol of AgNO₃ will react with 1 mol of KCl to produce 1 mol of AgCl and 1 mol of KNO₃".
The reaction between AgNO₃ and KCl is 1 to 1. We will use that relationship to find the number of moles of KCl that will react with 0.270 moles of AgNO₃.
number of moles of KCl = 0.270 moles of AgNO₃ * 1 mol of KCl/(1 mol of AgNO₃)
number of moles of KCl = 0.270 moles of KCl
Since the reaction is 1 to 1, 0.270 moles of KCl will react with 0.270 moles of AgNO₃.
Finally we can find the mass of KCl. We need the molar mass of KCl.
atomic mass of K = 39.10 amu
atomic mass of Cl = 35.45 amu
molar mass of KCl = 74.55 g/mol
mass of KCl = number of molses of KCl * molar mass of KCl
mass of KCl = 0.270 moles * 74.55 g/mol
mass of KCl = 20.1 g
Answer: 20. g of KCl would be required.
Why does the ice pack get colder when the inside barrier is broken and the chemicals mix together?
The ice pack gets colder when the inside barrier is broken and the chemicals mix together as instant cold packs employ this type of endothermic reaction.
Endothermic reactions are those that involve the absorption of heat.When the chemical ammonium nitrate is dissolved in water, the resultant solution is colder than either of the starting ingredients. This is an illustration of an endothermic process. Instant cold packs employ this type of endothermic reaction.Water is the substance that fills the cold pack. Another plastic bag or tube carrying fertilizer ammonium nitrate is submerged in the water. The tube is broken when you strike the cold pack, allowing the water and fertilizer to mix. The endothermic reaction this mixture produces results in heat absorption.
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Accessibility ModePrintFindPart II: Limiting Reactant1. Consider the reaction: 5C +2SO₂ → CS₂ + 4COa.) If you had 10 mol of Carbon, how many moles of carbon monoxide would be produced?b.) If you had 10 mol of sulfur dioxide, how many moles of carbon monoxide would beproduced?c.) If you had 10 mol of C and SO2 which reactant would be limiting?d.) What is the theoretical yield of CO, in moles if you react 10 moles of each reactant?SAMEFaPmenSavarہےEP Immersive Reader
Answer:
a.) 8 moles of carbon monoxide (CO).
b.) 20 moles of carbon monoxide (CO)
c.) C is the limiting reactant.
d.) The theoretical yield of CO would be 8 moles.
Explanation:
Let's write the chemical equation:
[tex]5C+2SO_2\rightarrow CS_2+4CO.[/tex]a.) You can see that 5 moles of carbon (C) reacted produces 4 moles of carbon monoxide (CO), so if we want to know how many moles of carbon monoxide can be produced, we can multiply each coefficient in the chemical equation by 2 (because we will have 10 moles of carbon):
[tex]10C+4SO_2\operatorname{\rightarrow}2CS_2+8CO.[/tex]The answer is that we will produce 8 moles of carbon monoxide (CO) by 10 moles of carbon (C).
b.) We can apply the same logic to this case. In the chemical equation, we have 2 moles of sulfur dioxide (SO2) reacted that produces 4 moles of carbon monoxide (CO), so if we want to know how many moles of carbon monoxide can be produced, we can multiply each coefficient by 5 so we will have 10 moles of sulfur dioxide:
[tex]25C+10SO_2\operatorname{\rightarrow}5CS_2+20CO.[/tex]The answer is that we will produce 20 moles of carbon monoxide (CO) by 10 moles of sulfur dioxide (SO2).
c.) We have already known that 10 moles of C will produce 8 moles of CO, and 10 moles of SO2 will produce 20 moles of CO. If we react 10 moles of C and 10 moles of SO2, you can note that we're going to have an excess of SO2 because we don't have enough amount of C to produce 20 moles of CO as SO2 do. So based on this logic, C is being consumed first and C would be the limiting reactant.
d.) Remember that the theoretical yield indicates the amount of a product obtained in a chemical reaction.
As we saw before, C is the limiting reactant if we react 10 moles of each reactant, so we have already known that 10 moles of C reacted produces 8 moles of CO, so the theoretical yield of CO would be 8 moles.
Read the water level with the correct number of significant figures.
Reading significant figures. When you're reading signif
Tin forms an ion with a 2+ charge. What is the Electron configuration of this ion?
STEP-BY-STEP EXPLANATION
What to find? The electronic configuration of tin ion
Tin is an element with an atomic number of 50.
NB: Atomic number = number of proton
Hence, the number of proton of tin = 50
[tex]Sn^{2+}[/tex]The above tin ion means it has lost two electrons, which make it has a total electron of 48
To write the electronic configuration of tin ion, we will be using the SPDF Notation
spdf are names given to orbitals that hold electrons in atoms.
s - orbital
p- orbital
d- orbital
f -orbital
[tex]\begin{gathered} \text{Electronic configuration of Sn}^{2+}\text{ is written below} \\ 1s^22s^22p^63s^23p^64s^23d^{10}4p^65s^24d^{10} \end{gathered}[/tex]When copper is heated with an excess of sulfur, copper(I) sulfide is formed. In a given experiment, 0.0970 moles of copper was heated with excess sulfur to yield 2.37 g copper(I) sulfide. What is the percent yield?
Answer: the percent yield of the reaction is 30.7%
Explanation:
The question requires us to determine the percent yield of the reaction that produces copper(I) sulfide, given the theoretical yield and actual yield.
The following information was provided by the question:
Amount of Cu used = 0.0970 mol of Cu
Actual yield of reaction = 2.37 g of Cu2S
To solve this problem, we'll need to determine the theoretical yield of the reaction, considering the amount of copper (Cu) used and the balanced chemical equation for this reaction, and then calculate the percent yield of the reaction.
1) Determining the theoretical yield of reaction:
The reaction between copper and sulfur to produce copper (II) sulfide can be written as:
[tex]2Cu\text{ + S}\rightarrow Cu_2S[/tex]Considering that 0.0970 moles of Cu were used in excess of S, and the stoichiometry of the reaction, we can calculate the amount of Cu2S produced:
2 mol Cu ---------------------- 1 mol Cu2S
0.0970 mol Cu ------------ x
Solving for x, we have that 0.0485 moles of Cu2S should be obtained from the reaction.
2) Calculating the percent yield of the reaction:
The percent yield of a chemical reaction can be calculated using the following equation:
[tex]percent\text{ yield = }\frac{theoretical\text{ yield}}{actual\text{ yield}}\times100\%[/tex]Note that the theoretical and actual yield values must be used in the same units. Thus, we need to convert the mass given for actual yield (2.37g) to number of moles, considering the molar mass of copper (I) sulfide (159.16 g/mol):
[tex]\begin{gathered} number\text{ of moles = }\frac{mass\text{ of sample \lparen g\rparen}}{molar\text{ mass \lparen g/mol\rparen}} \\ \\ number\text{ of moles = }\frac{2.37g}{159.16g/mol}=0.0149\text{ mol} \end{gathered}[/tex]Therefore, the actual yield corresponds to 0.0149 moles of Cu2S.
Now, we can calculate the percent yield of the reaction:
[tex]percent\text{ yield = }\frac{0.0149\text{ mol}}{0.0485\text{ mol}}\times100\%=30.7\%[/tex]Therefore, the percent yield of the reaction is 30.7%.
Use but-2-ene to illustrate the difference between e and z isomers
The but-2-ene is a molecule with four carbons and the middle bond, (the second one) is a double-bond.
So, its structure is H₃C-CH=CH-CH₃.
However, the double bond makes two possible isomers, the "e" and "z":
The double bond, differently from the single bond, does not rotate, so these structures are not the same.
In the left one, the carbon groups have higher priority, and they are in alternating sides, bottom and top, and so it is called the E isomer.
In the right one, the carbon groups are on the same side, so it is called the Z isomer.
A chemist prepares a solution of copper(II) sulfate CuSO4 by measuring out 27.μmol of copper(II) sulfate into a 300.mL volumetric flask and filling the flask to the mark with water. Calculate the concentration in mol/L of the chemist's copper(II) sulfate solution. Round your answer to 2 significant digits.
Step 1: Identify the given and do necessary conversions.
• 27.mol of copper ,
we know that 1 = 1*10^-6 mole ,
So, 27.mol*1*10^-6 = 27*10 ^-6 mole of copper.
• Volume of the solution = 300ml ,
300ml/1000ml = 0.3L
Step 2: Calculate the concentration in mol/L
Molarity( M /mole/L) = moles of the solute / volume
=27*10 ^-6 mole/ 0.3 L
=0.00009mol/L
• Therefore ,Concentraion of copper(II) sulfate =9.0x10^-5mol/L
( 2 significant digits)
Which property suggests that magnesium is a transition metal? A. It burns in oxygen to form the oxide mno2, B. It forms coloured compunds?, c. It has only one isotope,D. It reacts with dilute hydrochloric acid to give hydrogen
Answer:
D
Explanation:
as a transition metal, when put in dilute hydrochloric acid it will bubble vigorously and produce hydrogen gas
Engineers increase the concentration of uranium-235 atoms in nuclear fuelduring what process?A. Uranium-235 modificationB. Half-lifeC. Nuclear fuel modificationD. Enrichment
Explanation:
The majority of nuclear reactors use the isotope uranium-235 as fuel; however, it is only a small part of the natural uranium mined. The concentration must be increased through a process called enrichment. Enrichment is the process of increasing the concentration of uranium-235 atoms in nuclear fuel.
Answer: D. Enrichment
An unstable nucleusA-increases its half-lifeB - emits energy when it decaysC- increases its nuclear mass by fissionD- expels all of its protons
Explanation:
A nucleus consists o both electrons and proton. Therefore, an unstable nucleus undergoes radiation. And this causes a formation of a new atom. This is known as radioactive decay. Therefore, an unstable nucleus emits energy as it decays.
Answer:
The correct answer is B.herefore, an unstable nucleusherefore, an unstable nucleusR
Match the reaction to the type that best describes it.NaF + KBr →NaBr + KF?CombinationMg + MnCl2 →Mn + MgCl2?Decomposition2HCl → H2 + Cl2?Single replacementaw2Na + O2 →Na202?Double replacement
Explanation
Let us first define the different types of reaction.
A combination reaction is one in which two reactants combine to form a single product.
[tex]2Na+O_2\rightarrow Na_2O_2[/tex]A decomposition reaction will be one in which a reactant breaks down into two or more products.
[tex]2HCl\rightarrow H_2+Cl_2[/tex]A simple displacement reaction will be one in which a reagent, which is in its natural state, displaces one element bound to another. As a product, we will have the previously linked element now in its free form.
[tex]Mg+MnCl_2\rightarrow Mn+MgCl_2[/tex]In a double displacement reaction two linked elements move past each other and take each other's place.
[tex]NaF+KBr\rightarrow NaBr+KF[/tex]After being ignited in a Bunsen burner flame, a piece of magnesium ribbon burns brightly, giving off heat and light. In this situation, the Bunsen burner flame providesA)ionization energyB)activation energyC)heat of reactionD)heat of vaporization
The reaction that involves the combustion of Magnesium will not start unless some amount of energy is added to it, therefore we need the Bunsen burner flame to be the source of the activation energy for the reaction properly occur, since the reaction would not occur in a spontaneous way. Therefore answer letter B
Describe a real-world example that demonstrates this relationship. In your description identify the two variables (temperature and volume) and describe how one changes as the other is increased or decreased.
A real-world example that can demonstrate the relationship between the variables temperature and volume is, for example, when we inflate a balloon for a party.
- First, we fill the ballon with a gas (air).
- Second, if we tie the balloon and heat it with some source of heat, we will see that the ballon begins to increase in volume.
So, as we increase the temperature of the gas inside the ballon, the balloon increases in volume.
This happens because temperature and volume are variables directly proportional through the Ideal Gas Law, whose formula is:
[tex]P\mathrm{}V=n\mathrm{}R\mathrm{}T[/tex]In the formula:
P is the pressure of the gas.
V is the volume of the gas.
n is the number of moles.
R is the constant of the gases.
T is the temperature of the gas.