what is -2/3 times -12. This questions is related to converting slope point form into slope intercept form.

Answer:

The answer is

90 degrees the first one is I don't know about the rest sorry

Step-by-step explanation:

Answer:

45 degrees xxxxxxxxxx

Step-by-step explanation:

simple geo

Answer:

T (3 , -6)   O ( -6 , -4) and M (-9 , 6)

Step-by-step explanation:

(x , y) -> (-x , -y)

Answer:

[tex]\cot(x)+\cot(\frac{\pi}{2}-x)[/tex]

[tex]\cot(x)+\tan(x)[/tex]

[tex]\frac{\cos(x)}{\sin(x)}+\frac{\sin(x)}{\cos(x)}[/tex]

[tex]\frac{1}{\sin(x)}(\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)})[/tex]

[tex]\csc(x)(\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)})[/tex]

[tex]\csc(x)[\frac{\cos(x)\cos(x)}{\cos(x)}+\sin(x)\frac{sin(x)}{\cos(x)}][/tex]

[tex]\csc(x)[\frac{\cos(x)\cos(x)+\sin(x)\sin(x)}{\cos(x)}][/tex]

[tex]\csc(x)[\frac{\cos^2(x)+\sin^2(x)}{\cos(x)}][/tex]

[tex]\csc(x)[\frac{1}{\cos(x)}][/tex]

[tex]\csc(x)[\sec(x)][/tex]

[tex]\csc(x)[\csc(\frac{\pi}{2}-x)][/tex]

[tex]\csc(x)\csc(\frac{\pi}{2}-x)[/tex]

Step-by-step explanation:

I'm going to use [tex]x[/tex] instead of [tex]\theta[/tex] because it is less characters for me to type.

I'm going to start with the left hand side and see if I can turn it into the right hand side.

[tex]\cot(x)+\cot(\frac{\pi}{2}-x)[/tex]

I'm going to use a cofunction identity for the 2nd term.

This is the identity: [tex]\tan(x)=\cot(\frac{\pi}{2}-x)[/tex] I'm going to use there.

[tex]\cot(x)+\tan(x)[/tex]

I'm going to rewrite this in terms of [tex]\sin(x)[/tex] and [tex]\cos(x)[/tex] because I prefer to work in those terms. My objective here is to some how write this sum as a product.

I'm going to first use these quotient identities: [tex]\frac{\cos(x)}{\sin(x)}=\cot(x)[/tex] and [tex]\frac{\sin(x)}{\cos(x)}=\tan(x)[/tex]

So we have:

[tex]\frac{\cos(x)}{\sin(x)}+\frac{\sin(x)}{\cos(x)}[/tex]

I'm going to factor out [tex]\frac{1}{\sin(x)}[/tex] because if I do that I will have the [tex]\csc(x)[/tex] factor I see on the right by the reciprocal identity:

[tex]\csc(x)=\frac{1}{\sin(x)}[/tex]

[tex]\frac{1}{\sin(x)}(\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)})[/tex]

[tex]\csc(x)(\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)})[/tex]

Now I need to somehow show right right factor of this is equal to the right factor of the right hand side.

That is, I need to show [tex]\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)}[/tex] is equal to [tex]\csc(\frac{\pi}{2}-x)[/tex].

So since I want one term I'm going to write as a single fraction first:

[tex]\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)}[/tex]

Find a common denominator which is [tex]\cos(x)[/tex]:

[tex]\frac{\cos(x)\cos(x)}{\cos(x)}+\sin(x)\frac{sin(x)}{\cos(x)}[/tex]

[tex]\frac{\cos(x)\cos(x)+\sin(x)\sin(x)}{\cos(x)}[/tex]

[tex]\frac{\cos^2(x)+\sin^2(x)}{\cos(x)}[/tex]

By  the Pythagorean Identity [tex]\cos^2(x)+\sin^2(x)=1[/tex] I can rewrite the top as 1:

[tex]\frac{1}{\cos(x)}[/tex]

By the quotient identity [tex]\sec(x)=\frac{1}{\cos(x)}[/tex], I can rewrite this as:

[tex]\sec(x)[/tex]

By the cofunction identity [tex]\sec(x)=\csc(x)=(\frac{\pi}{2}-x)[/tex], we have the second factor of the right hand side:

[tex]\csc(\frac{\pi}{2}-x)[/tex]

Let's just do it all together without all the words now:

[tex]\cot(x)+\cot(\frac{\pi}{2}-x)[/tex]

[tex]\cot(x)+\tan(x)[/tex]

[tex]\frac{\cos(x)}{\sin(x)}+\frac{\sin(x)}{\cos(x)}[/tex]

[tex]\frac{1}{\sin(x)}(\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)})[/tex]

[tex]\csc(x)(\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)})[/tex]

[tex]\csc(x)[\frac{\cos(x)\cos(x)}{\cos(x)}+\sin(x)\frac{sin(x)}{\cos(x)}][/tex]

[tex]\csc(x)[\frac{\cos(x)\cos(x)+\sin(x)\sin(x)}{\cos(x)}][/tex]

[tex]\csc(x)[\frac{\cos^2(x)+\sin^2(x)}{\cos(x)}][/tex]

[tex]\csc(x)[\frac{1}{\cos(x)}][/tex]

[tex]\csc(x)[\sec(x)][/tex]

[tex]\csc(x)[\csc(\frac{\pi}{2}-x)][/tex]

[tex]\csc(x)\csc(\frac{\pi}{2}-x)[/tex]

Answer:

Slope = 0

Step-by-step explanation:

Given the pair of points: (-3,2) (7,2)

Slope formula: y2-y1/x2-x1

2-2/7-(-3) = 0/10

0/10 = 0

Answer:

D

Step-by-step explanation:

Answer:

x= 8

Step-by-step explanation:

5.5(x-3)=17+10.5

5.5x - 16.5= 27.5

5.5x= 44

x= 8

Answer:

x=8

Step-by-step explanation:

this is answer hdhshshshshshuebbdjidusgwbendjdihshe

Answer:

volume = 2 x 2 x 2 = 8 cm²

Step-by-step explanation:

Answer:

No solution

Step-by-step explanation:

because the are parallel lines they never meet so they are inconsistent so there is no solution

Casually puts a link to a weird website..

https://theuselessweb.com

*whistles*

Answer:

there is no solution-

Step-by-step explanation:

there's no solution because its impossible for a to have 2 different values; you see that 0.1 and 0.01 are not equal, therefore a can not be equal,, otherwise the equation would be false

Answer:C

Step-by-step explanation:

C. 2/3 cm/s

Answer:

25,0000000000000pmc squared

Step-by-step explanation:

because it's math.

Answer:

why did you call us losers?

i think it's B

Answer:

y = 8 root 2

Step-by-step explanation:

Since it is a 90-45-45 triangle, y is s root 2

s = 8

so, y = 8 root 2

Answer:

y=8√2

Step-by-step explanation:

Because 2 of the angles are the same, the triangle is isosceles (because of base angles theorem). Therefore, x=8. Using Pythagoras theorem, y=8√2.

answer:

you just have to shrink it down to 4cm then to 2cm

i wish i could help out more, but i would need to have access to the form

hopefully, this helps anyhow :)

good luck

have a great day !!

Answers:

So,

The general rule is that the upper boundary is found computing Q3+1.5*IQR, where IQR is the interquartile range. Recall that IQR = Q3-Q1. The Q1 and Q3 are the first and third quartiles respectively.

Another rule is that the lower boundary is found by computing Q1 - 1.5*IQR

On a box and whisker plot, outliers are points that are not connected to the main plot itself. You can think of them as islands far from the mainland.

What are Outliers?

If a number in distribution is more than 1.5 times the length of the box away from either of the upper and lower quartile of the distribution, then that number is said to be an outlier.  

The lower quartile is [tex]Q_1[/tex] and the upper quartile of distribution is [tex]Q_3[/tex]

Then lower boundary is given by [tex]=Q_1-1.5\times IQR[/tex]

The Upper boundary is given by  [tex]=Q_3+1.5\times IQR[/tex]

If any number or value of the distribution is greater than [tex]Q_3+1.5\times IQR[/tex] then that is called Upper Outlier.

Similarly, if any value or number of the distribution is less than [tex]Q_1-1.5\times IQR[/tex] then that is called Lower Outlier.

So the answers in the boxes are given by:

Learn more about Outliers here -

https://brainly.com/question/3631910

#SPJ2

Answer:

Does this count as stander form 6.95880148018

Step-by-step explanation:

Answer:

1, 2 and 5

Step-by-step explanation:

Answer: The measurement of angle B is 50 degrees

Step-by-step explanation: we know all triangles add up to 180 degrees so substitute 40 with a degrees and solve

Step-by-step explanation:

According to the Triangle Sum Theorem, all angles in triangle are sum of 180⁰. This means that m<a + m<b + m<c = 180⁰. You will first solve for a.

m<a + m<b + m<c = 180⁰

2a⁰ + a + 10⁰ + a⁰ = 180⁰ combine like terms.

2a⁰ + a + a⁰ + 10⁰ = 180⁰

4a⁰ + 10⁰ = 180⁰ subtract 10 from both sides.

4a⁰ + 10⁰ - 10⁰ = 180⁰ - 10⁰

4a⁰ = 170⁰ Divide 4 from both sides.

4a⁰ / 4 = 170⁰ / 4

a = 42.5⁰

Now that you found a, plug 42.5⁰ in place of in all angles and solve.

m<a :-

2a⁰

2(42.5)⁰

85⁰

m<b :-

a + 10⁰

42.5⁰ + 10⁰

52.5⁰

m<c :-

a⁰

42.5⁰

m<a = 85⁰

m<b = 52.5⁰

m<c = 42.5⁰

Remember that all angle must sum up to 180⁰ in a triangle. So we will now add all of our angle to find it if it equals 180⁰.

m<a + m<b + m<c = 180⁰

85⁰ + 52.5⁰ + 42.5⁰ = 180⁰

180⁰ = 180⁰

Thus, m<b = 52.5⁰.

Hope this helps, thank you :) !!

Answer:

i can.

Step-by-step explanation:

Answer:

17.96m/s

Step-by-step explanation:

Based on law of conservation of momentum;

m1u1 +m2u2 =(m1+m2)v

v is the velocities of the car after impact

Substitute the given values

1300(20)+900(15) = (1300+900)v

26000 + 13500 = 2200v

39500 = 2200v

v = 39500/2200

v = 17.96m/s

Hence the speed of the cars after impact is 17.96m/s

Answer:

because they are both similar. they both accept the law of karma and release from the cycle of birth. one of the key differences is

buddhist only believe in one god. hinduism believes in multiple gods

Answer:

hey emanii

Step-by-step explanation:

9514 1404 393

Answer:

Step-by-step explanation:

The zeros are the values of t that make the factors zero.

  1 -t = 0   ⇒   t = 1

  8 +16t = 0   ⇒   t = -8/16 = -1/2

The equation is used to model height after the ball is thrown. We don't expect it to be a good model before the ball is thrown (t < 0), so the zero in that region is extraneous.

Only the positive zero is in the function's domain, so that is the only one that is meaningful.

__

When t = 0 (at the time the ball is thrown), the function value is ...

  h(0) = (1 -0)(8 +0) = 8

The ball is thrown from a height of 8 feet.

Answer:

chicken wing chicken wing hot dog and baloney chicken and macaroni chillen with my homie

Step-by-step explanation:

Answer:

a=-2

Step-by-step explanation:

[tex]2(3a + 4) = - 8 \\( 2 \times 3a = 6a)(2 \times 2 = 4) \\ - 8 - 4 = - 12 \\ 6a \div - 12 = - 2[/tex]

Answer:

The time it takes the first kitten to unwind the balls of yarn alone is 15 minutes

The time it takes the second kitten to unwind the balls of yarn alone is 10 minutes

Step-by-step explanation:

The time it takes the two kitten to unwind the balls of yarn = 9 minutes faster than the first kitten working alone

The time it takes the two kitten to unwind the balls of yarn = 4 minutes faster than the second kitten working alone

Let 'x' represent the time it takes the first kitten to unwind the balls of yarn alone, let 'y' represent the time it takes the second kitten to unwind the balls of yarn alone, and let 't' represent the time it takes the two kitten to unwind the balls of yarn we have;

x = t + 9

y = t + 4

The rate of working, per ball of yarn, of the first kitten = 1/x = 1/(t + 9)

The rate of working, per ball of yarn, of the second kitten = 1/y = 1/(t + 4)

The amount of work each kitten does in the time 't', added together to unwind 1 ball of yarn is given as follows;

t/(t + 9) + t/(t + 4) = 1

(t·(t +4) + t·(t + 9))/(t + 4)×(t + 9) = 1

Using a graphing calculator, we have;

(2·t²+13·t)/(t² + 13·t + 36) = 1

∴ (2·t² + 13·t) = (t² + 13·t + 36)

(2·t² + 13·t) - (t² + 13·t + 36) = 0

t² - 36 = 0

t = √36 = 6

t = 6

x = t + 9 = 6 + 9 = 15

The time it takes the first kitten to unwind the balls of yarn alone, x = 15 minutes

y = t + 4 = 6 + 4 = 10

The time it takes the second kitten to unwind the balls of yarn alone, y = 10 minutes

Answer:

15 and 10 are correct

Step-by-step explanation:

Answer:

20 ≥ x

Step-by-step explanation:

Alex has $20 or less to spend at the store