A student plans a two-step synthesis of 1-ethyl-3-nitrobenzene from benzene. The first step is nitration of benzene to give nitrobenzene, and the second step is a Friedel-Crafts alkylation using CH3CH2Cl and AlCl3. The plan is flawed because: A : When the alkyl halide interacts with AlCl3, the resulting carbocation can rearrange before it has a chance to react with the aromatic ring. B : Nitrobenzene is too deactivated (by the nitro group) to undergo a Friedel-Crafts alkylation. C : The nitro group will direct the incoming alkyl group para position, rather than to the meta position. D : A blocking group is required to achieve this synthesis.
Answer:
Nitrobenzene is too deactivated (by the nitro group) to undergo a Friedel-Crafts alkylation.
Explanation:
The benzene ring in itself does not easily undergo electrophilic substitution reaction. Some groups activate or deactivate the benzene ring towards electrophilic substitution reactions.
-NO2 ia a highly deactivating substituent therefore, Friedel-Crafts alkylation of nitrobenzene does not take place under any conditions.
This reaction scheme is therefore flawed because Nitrobenzene is too deactivated (by the nitro group) to undergo a Friedel-Crafts alkylation.
The equivalence point in a titration refers to the point when
A. the mł of the acid equals the mL of the base.
B. the molarity of the acid used in the reaction equals the molarity of the base used in the reaction.
C. the number of moles of one reactant reacts completely with the moles of the other reactant.
D. the acid in the flask turns clear.
Answer:
C) the number of moles of one reactant reacts completely with the moles of the other reactant.
Explanation:
it's right put it
Answer:
C
Explanation:
Astronauts go to live on the International Space Station for a period of ________ month(s). A one B three C six D nine
Answer:
The answer is C. six months
Explanation:
I hope this helps you bestie:))
What is the product of the equation shown?
2 Na + S203
A. Na S203
B. NaS40
C. Na2S205
D. Na2S2O3
Answer:
D
Explanation:
balancing of chemical equations
A triangle has one angle that measures 81° and one that measures 37° what is the measure of a third angle
In the process of performing a spectrophotometric determination of iron, an analyst prepares a calibration curve using a single-beam spectrophotometer. After preparing the calibration curve, the analyst drops and breaks the cuvette. The analyst acquires a new cuvette, measures the absorbance of the sample, and determines the %w/w Fe in the sample. Does the change in cuvette lead to a determinate error in the analysis
Answer:
Yes.
Explanation:
Yes, the change in cuvette lead to a determinate error in the analysis if the different cuvette is used for the analysis because the amount of liquid sample that is used has different volume. If both cuvette are of the same type and has no difference in their structure and size then there is error occurs in the analysis but if both cuvette are different from one another then the error will occur in the analysis. because the amount of liquid that is used has different volume.
(b) The student collects the H2(g) produced by the reaction and measures its volume over water at 298 K after carefully
equalizing the water levels inside and outside the gas-collection tube, as shown in the diagram below. The volume is
measured to be 45.6 mL. The atmospheric pressure in the lab is measured as 765 torr, and the equilibrium vapor pressure
of water at 298 K is 24 torr,
45
46
Gas
Water
Calculate the following.
() The number of moles of h2 produced in the reaction
Answer:
The pressure of H₂(g) = 741 torr
Explanation:
Given that:
The atmospheric pressure measured in the lab = 765 torr
The vapor pressure of water = 24 torr
By applying Dalton's Law of Partial Pressure :
Making The Pressure inside the tube due to the H₂(g) the subject of the formula :
we have:
= (765 -24) torr
= 741 torr
According to ideal gas law and Dalton's law of partial pressure, 0.0136 moles of hydrogen are produced in the reaction.
What is ideal gas law?The ideal gas law is a equation which is applicable in a hypothetical state of an ideal gas.It is a combination of Boyle's law, Charle's law,Avogadro's law and Gay-Lussac's law . It is given as, PV=nRT where R= gas constant whose value is 8.314.The law has several limitations.It is applicable to ideal gases which have hypothetical existence.Law was proposed by Benoit Paul Emile Clapeyron.
In the given problem, according to Dalton's law of partial pressure, pressure =765-24=741 torr
Substituting the given values in the ideal gas equation, n=PV/RT
n=741×45.6×10[tex]^-3[/tex]/8.314×298=0.0136 moles.
Thus 0.0136 moles of hydrogen are produced in the reaction.
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PLS HELP TEST IS TIMED!!
The temperature of a solution can change the solubility of a substance. The chart shows the solubility of the same solute at different temperatures in water.
A 3-column table with 4 rows. The first column labeled solution has entries W, X, Y, Z. The second column labeled temperature degrees C has entries 40, 59, 55, 48. The third column labeled grams per 100 grams of water has entries 50, 200, 150, 80.
Based on the chart, which solution was at the optimal temperature to allow for the greatest solubility?
Answer:
Temperature can change the solubility of a solute.
Explanation:
Answer:
Temperature can change the solubility of a solute.
Explanation:
Zinc metal reacts with copper sulfate through the following
reaction:
Zn + CuSO4 → Cu + ZnSO4
The percent yield for a reaction in which 32.5 g of Zn is reacted
in excess CuSO4 solution is 85.0 %. What is the actual yield of
copper of this reaction?
g
Answer:26.9
Explanation:
What is the molar mass of AIC13?
Scientists have been classifying living organisms for centuries. In the 1970s, organisms were classified in a five-kingdom
classification scheme. However, two decades later, organisms called Archaebacteria were discovered. This led to a three-domain
system of classification that combined some of the previous five-kingdom schemes.
What does this change in classification methods demonstrate?
Answer:
Classification is important because it allows scientists to identify, group, and properly name organisms via a standardized system (Linnaeus Taxonomy); based on similarities found in the organisms DNA/RNA (genetics), Adaptations (Evolution), and Embryonic development (Embryology) to other known organisms to better.
Hope I helped!!
The five kingdoms of classifications were animalia, plant, fungi, protista and monera. Later Archaebacteria was discovered and this led to the 3 kingdom classification animalia, plantae and protista.
What is biological classification?There are different classifications for living things based on their nature, body and origin. The kingdom animalia includes all the animals including human beings.
Kingdom plante includes all the plants and kingdom fungi, protista and monera are of microbes. Later the discovery and study of Archaebacteria proved that they exhibit similar body type and functions as bacterias.
After that, scientists turned into 3 kingdom classification, where all the prokaryotic organisms including protists, monera and fungi classified as one. The evolutional changes originated in them made this classification.
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Draw the structure formula for
1-ethyl-2,3-dimethylbenzene
Please help me
Answer:
Please see the attached picture.
Explanation:
1) Draw a benzene ring
2) On the first carbon, add a CH₂CH₃ (known as ethyl) since its location number is 1.
3) 'Dimethyl' refers to 2 methyl (CH₃) branches. The location numbers are 2 and 3, thus add a CH₃ on the 2nd and 3rd carbons.
Please answer this question
Answer:
K^2O
Explanation:
I remember a question like this one and I got it right its K^2O
(aka its C)
What is the name or symbol of the element in group 17 and
period 3 of the periodic table?
Answer:
Chlorine
Explanation:
Chlorine is the element located in period 3, group 17 of the periodic table.
Which of this is formed when a metal reacts with steam ? *
Carbon dioxide
A Salt
An oxide
A metal hydroxide
Can u please help me name which one it is
Answer:
I think it is C
Explanation:
An example of a suspension is:
A. blood
B. gelatin
C. muddy water
D. milk
Put the following type of radiations in order of increasing energy: red, radio, UV, infrared, blue, and x-ray
Answer: The order of increasing energy is: radio < infrared < red < blue < UV < x rays
Explanation:
Electromagnetic wave is defined as the wave which is associated with both electrical and magnetic component associated with them.
The electromagnetic radiations consist of gamma rays , X rays , Ultraviolet , Visible , Infra red , microwaves and radio waves arranged in order of decreasing frequency and increasing wavelengths. The visible region consists of violet , indigo , blue , green , yellow, orange and red lights in order of decreasing frequency or increasing wavelength
The relationship between energy and frequency of the wave follows the equation:
[tex]E=h\times \nu[/tex]
where,
[tex]\nu[/tex] = frequency of the wave
E = energy of wave
From the above relation, it is visible that energy and frequency follow direct relation. For increase in value of frequency, energy increases and vice-versa.
Thus the order of increasing energy is: radio < infrared < red < blue < UV < x rays
what makes a substance a good insulator
Answer:
zoo wee mama
Explanation:
The particles that make up an object are held together by bonds. Insulators have strong bonds that hold their particles rigidly in place. This prevents particles from gaining energy and increasing the temperature. Wool, dry air, plastics, and polystyrene foam are all examples of good insulators.
State the coefficient required to correctly balance the following chemical equation:
_____ Ca3(PO4)2+ _____ NaCl ---------> _____ Na3PO4 + _____ CaCl2
Answer:
1 Ca3(PO4)2+ 6 NaCl ---------> 2 Na3PO4 + 3 CaCl2
What is the percent composition of a 16.75 g sample of a compound containing 14.02 g oxygen and 2.73 g hydrogen? Select the correct answer below: 83.7% oxygen, 16.3% hydrogen O 17% oxygen, 13% hydrogen O 68.2% oxygen, 31.8% hydrogen 89.5% oxygen, 10.5% hydrogen
Answer:
83.7% oxygen, 16.3% hydrogen
Explanation:
Mass of compound = 16.75 g
Mass of Oxygen = 14.02 g
Mass of Hydrogen = 2.73 g
Percentage composition = Mass of element / Mass of compound 100%
Percentage composition of Oxygen = 14.02 g / 16.75 g * 100%
Percentage composition of Oxygen = 0.837 * 100 = 83.7%
Percentage composition of Hydrogen = 2.73 g / 16.75 g * 100%
Percentage composition of Hydrogen = 0.163 * 100 = 16.3%
The correct option is;
83.7% oxygen, 16.3% hydrogen
Answer:
83.7% oxygen, 16.3% hydrogen
Explanation:
To determine the percent composition we can divide, our mass by total mass and afterwards, multiply by 100.
(Mass of O / Total mass) . 100 = % O
(Mass of H / Total mass) . 100 = % H
Remember that:
% O + % H = 100
Mass of O / Total mass + Mass of H / Total mass = 1
(14.02 g / 16.75g) . 100 = 83.7 %
(2.73 g /16.75g) . 100 = 16.3 %
help someone i need this
? I JUST DONT UNDERSTAND
Answer:
5SiO2 + 2CaC2 → 5Si + 2CaO + 4CO2
Explanation:
When you are balancing an equation, you use coefficients to change the number of atoms of each type that are on each side of the equation.
You cannot change subscripts, the small numbers to the right of the substances. You can only add coefficients, the large numbers to the left of substances.
A balanced equation has the same number and type of atoms on both sides of the equation (the reactants on the left, the products on the right).
To begin, this equation has:
1 Si
2 O
1 Ca
2 C
on the left and
1 Si
1 Ca
3 O
1 C
on the right. Those numbers don't match!
By adding coefficients we end up with 5 Si, 10 O, 2 Ca and 4 C on both sides.
How many grams of air are required to complete the combustion of 120 g of phosphorous to diphosphorous pentoxide, assuming the air to be 23% oxygen by mass?
Answer:
Explanation:
522 g
Explanation:
Your starting point here will be the balanced chemical equation for this combustion reaction
4
P
(s]
+
5
O
2(g]
→
2
P
2
O
5(s]
Notice that you have a
4
:
5
mole ratio between phosphorus and oxygen. This means that, regardless of how many moles of phosphorus you have, the reaction will always need
5
4
time more moles of oxygen gas.
Use phosphorus' molar mass to determine how many moles you have in that
93.0-g
sample
93.0
g
⋅
1mole P
30.974
g
=
3.0025 moles P
Use the aforementioned mole ratio to determine how many moles of oxygen you would need for many moles of phosphorus to completely take part in the reaction
3.0025
moles P
⋅
5
moles O
2
4
moles P
=
3.753 moles O
2
Calculate the mass, in grams, of 0.540 mol of manganese (Mn).
Report your answer with three significant figures.
Answer:
m = 29.6 grams
Explanation:
Given that,
Number of moles = 0.540
The molar mass of manganese = 54.93 g/mol
We know that,
Number of moles = given mass/molar mass
[tex]m=n\times M\\\\m=0.540 \times 54.93\\\\m=29.6\ g[/tex]
So, the required mass of the Manganese is equal to 29.6 grams.
HELP I WILL GIVE YOU BRAINLIST!!!
Pick one substance (ex: water and table salt) and compare two of the atoms connected to each other (ex: H and O, Na and Cl) and answer the following questions for each pair:
1)Are they close or far away from each other on the periodic table?
Do they have similar atomic radii?
2)Do they have a large or small difference in ionization energy? What about for electron affinity?
How many grams of water can be made from 6 moles of oxygen
Which of the following chemical substances has a triple
covalent bond?
A. carbon dioxide (CO2)
B. oxygen (0)
C. carbon monoxide (CO)
D. water (H,0)
Answer:
C. Carbon monoxide
Explanation:
Chemical substance which has a triple covalent bond is carbon monoxide.
What is a covalent bond?Covalent bond is defined as a type of bond which is formed by the mutual sharing of electrons to form electron pairs between the two atoms.These electron pairs are called as bonding pairs or shared pair of electrons.
Due to the sharing of valence electrons , the atoms are able to achieve a stable electronic configuration . Covalent bonding involves many types of interactions like σ bonding,π bonding ,metal-to-metal bonding ,etc.
Sigma bonds are the strongest covalent bonds while the pi bonds are weaker covalent bonds .Covalent bonds are affected by electronegativities of the atoms present in the molecules.Compounds having covalent bonds have lower melting points as compared to those with ionic bonds.
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Balance the following equation and
then provide the coefficients for each
molecule.
_SnO2+ _H2 --> _Sn + _H20
Answer:
jbisibjas bhijjoijnc
Explanation:
The human body can get energy by metabolizing proteins, carbohydrates or fatty acids, depending on the circumstances. Roughly speaking, the energy it gets comes mostly from allowing all the carbon atoms in the food molecules to become oxidized to carbon dioxide CO2 by reaction with oxygen from the atmosphere. Hence the energy content of food is roughly proportional to the carbon content.
Let's consider alanine, C3H7NO2, one of the amino acids from which proteins are made, and glucose C6H12O6, one of the simplest carbohydrates. Using the idea above about energy content, calculate the ratio of the energy the body gets metabolizing each gram of alanine to the energy the body gets metabolizing each gram of glucose.
Answer:
the ratio of the energy the body gets metabolizing each gram of alanine to the energy the body gets metabolizing each gram of glucose is 1.0111
Explanation:
Given the data in the question;
To determine the ratio of the energy the body gets metabolizing each gram of alanine to the energy the body gets metabolizing each gram of glucose, first we get the molar masses of both alanine and glucose
we know that;
Molar mass of alanine ( C₃H₇NO₂ ) = 89.09 g/mol
Molar mass of glucose ( C₆H₁₂O₆ ) = 180.16 g/mol
now, { metabolizing each gram }
moles of alanine = mass taken / molar mass
= 1g / 89.09 g/mol = 1/89.09 moles
moles of glucose = mass taken / molar mass
= 1g / 180.16 g/mol = 1/180.16 moles
In each molecule of alanine, we have 3 atoms of carbon.
Also, in each molecules of glucose, we have 6 atoms of carbon
so,
number of moles of Carbons in alanine = 3 × 1/89.09 moles = 0.03367
number of moles of Carbons in glucose = 6 × 1/180.16 moles = 0.0333
so ratio of energy will be the ratio of carbon atoms, which is;
⇒ 0.03367 / 0.0333 = 1.0111
Therefore, the ratio of the energy the body gets metabolizing each gram of alanine to the energy the body gets metabolizing each gram of glucose is 1.0111