What are bacteria? Chapter 7 lesson 2 AYU

Answer: Aspirin

Explanation:

Answer:

Glass

1.microscopes

2.mirrors

3.glass shelves

4.wrist watch glass

5.magnifying glass

Metal

1.keys

2.automobile body parts

3.coins

4.window frames

5.screws and nails

Plastic

1.bottles

2.boxes

3.balls

4.carry bags

5.buckets and mugs

Wood

1.chairs

2.tables

3.shoe stand

4.dressing table

5.shelves

The given reaction is the type of Decomposition reaction. A decomposition reaction occurs when one reactant splits into many products.

Chemistry reaction reactions of decomposition. Decomposition reactions occur when complex chemical entities split apart into smaller components. Decomposition reactions often demand energy input.

Decomposition reactions are those that divide or break the compounds into two simpler products. Because two or more reactants are combined to create a single product in a combination reaction, they are known as the reverse of combination reactions.

It entails the severing of ties. Energy is necessary to dismantle the bonding between atoms. Decomposition advances when energy in the form of heat or electricity is provided. As the bond is broken during this reaction, energy is given to them, making them endothermic processes.

To know more about the decomposition reaction visit:

https://brainly.com/question/16728382

#SPJ1

Answer:

42g if CaO can be produced from 30g and 31.5g of CaO will be produced from 18g of O

Explanation:

40g of CA =56g

30g =×

cross multiple

=56*30/40

=42g

32g of O =56g

18g =×

cross multiple

=56*18/32

=31.5g

theoretical yield

42-31.5= 10.5

just guessing

Answer:

Yes, it is a good conductor of electricity.

Explanation:

They allow electric particles to pass through them (the bases).

(Hope this made sense)

Answer:

Specific heat is the amount of energy that must be added, in the form of heat, to one unit of mass of the substance in order to cause an increase of one unit in temperature.

Explanation:

Answer:

Specific heat is the amount of energy that must be added, in the form of heat, to one unit of mass of the substance in order to cause an increase of one unit in temperature.

Explanation:

Answer:

15. The velocity of a sound wave is affected by two properties of matter: the elastic properties and density.

16. The greater the density of a medium, the slower the speed of sound. This observation is analogous to the fact that the frequency of a simple harmonic motion is inversely proportional to m, the mass of the oscillating object.

17. Temp °C 0 m/s2 m/s

50 360.51 361.62

18. Molecules at higher temperatures have more energy, thus they can vibrate faster. Since the molecules vibrate faster, sound waves can travel more quickly. The speed of sound in room temperature air is 346 meters per second. ... The speed of sound is also affected by other factors such as humidity and air pressure.

Answer:

Calcium nitrate is an inorganic compound with the chemical formula Ca(NO3)2. ... It is a nitrate salt of Calcium which contains calcium and nitrogen and oxygen. Calcium nitrate is a white or whitish-grey coloured granular solid which absorbs moisture from the air and is usually found as a tetrahydrate compound Ca(NO3)2.

Explanation:

Answer:

Group 1A: 1+

Group 3A: 3+

Group 5A: 3+ or 5+

Explanation:

Answer and Explanation:

For each reaction, it is useful to detail which are the reactants (left side of the equation) and which are the products (right side of the equation), to deduce the chemical formulas.

1. Solid lithium reacts with water to produce hydrogen gas and a solution of lithium hydroxide.

Reactants: lithium element in solid-state (Li(s)) and water (H₂O) in the liquid-state. Products: hydrogen gas which is a diatomic molecule (H₂) and lithium hydroxide, which is a base formed by lithium cation Li⁺ and OH⁻ anion (LiOH).

Li(s) + H₂O(l) → H₂(g) + LiOH(aq)

2. Solid sodium reacts with gaseous chlorine to produce sodium chloride.

Reactants: sodium metal in solid-state (Na(s)) and chlorine which is a diatomic gas (Cl₂). Products: sodium chloride, which is a salt formed by sodium and chloride together (NaCl).

Na(s) + Cl₂(g) → NaCl(s)

3. Solid calcium carbonate breaks down into carbon dioxide gas, oxygen gas, and solid calcium.

It is a decomposition reaction, so we have only one reactant: calcium carbonate, which is a salt composed of carbonate anion (CO₃⁻²) and calcium ion (Ca²⁺). Products: carbon dioxide (CO₂), oxygen gas which is diatomic (O₂), and solid calcium (Ca(s)).

CaCO₃(s) → CO₂(g) + O₂(g) + Ca(s)

4. Solid iron(II) sulfate and a solution of barium chloride react to form solid barium sulfate and a solution of  iron (II) chloride.

Reactants: iron(II) sulfate which is an ionic compound formed by the sulfate ion (SO₄²⁻) and iron ion (with two positive charges: Fe²⁺), and barium chloride which is a salt of barium ion (Ba²⁺) and two chloride ions (Cl⁻). Products: the salts formed by ion exchange, barium sulfate (BaSO₄), and iron (II) chloride (FeCl₂).

FeSO₄(s) + BaCl₂(aq) → BaSO₄(s) + FeCl₂(aq)

5. Solutions of hydrochloric acid and sodium hydroxide react to produce liquid water with sodium chloride  dissolved in it.

It is the classical neutralization reaction. Reactants: hydrochloric acid (HCl) and the strong base sodium hydroxide (NaOH). Products: water (H₂O) and the salt formed by the anion provided by the acid (Cl⁻) and the cation provided by the base (Na⁺): NaCl.

HCl(aq) + NaOH(aq) → H₂O(l) + NaCl(aq)

Answer:

the second one

Explanation:

THE answers is b

Answer:

20.8L = Final volume of the gas

Explanation:

Based on Charles's law, the volume of a gas is directly proportional to the temperature of the gas under pressure constant. The equation is:

[tex]\frac{V_1}{T_1} =\frac{V_2}{T_2}[/tex]

where V is volume and T absolute temperature of 1, initial state and 2, final state.

If initial volume is 22.5L, initial T = 365K and final temperature 338K:

22.5L / 365K = V₂ / 338K

Answer:

Reaction:

[tex]2Mg + Br_{2} >> 2MgBr[/tex]

Explanation:

Hello there, I think this is a limiting agent question.

When 3 moles of Mg is reacted with 2 moles of Br2, because of ratio, we just need 1.5 moles of Br2, so Mg is a limiting agent.

So 3 moles of Mg will make 3 moles of MgBr

Taking into account the stoichiometry of the reaction, 2 moles of magnesium bromide are formed when 3.0 moles of magnesium reacts with 2.0 moles of bromine.

The balanced reaction is:

Mg + Br₂ ⇒ MgBr₂

Then, by stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

On the other side, the limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

To determine the limiting reagent, it is possible to a simple rule of three as follows: if by stoichiometry 1 mole of bromine reacts with 1 moles of magnesium, how much moles of bromine will be needed if 3moles of magnesium react?

[tex]moles of bromine=\frac{1 moles of bromineX3 mole of magnesium}{1 mole of magnesium}[/tex]

moles of bromine=3 moles

But 3 moles of bromine are not available, 2 moles are available. Since you have less moles than you need to react with 3 moles of magnesium, bromine will be the limiting reagent.

Finally, the following rule of three can be applied: if by reaction stoichiometry, 1 mole of bromine forms 1 mole of magnesium bromide, 2 moles of bromine forms how many moles of magnesium bromide?

[tex]moles of magnesium bromide=\frac{2 moles of bromine*1 moles of magnesium bromide}{1 mole of bromine}[/tex]

moles of magnesium bromide= 2 moles

In summary, 2 moles of magnesium bromide are formed when 3.0 moles of magnesium reacts with 2.0 moles of bromine.

Learn more about stoichiometry of the reaction:

Answer: True

Explanation: It always has the same number because the both have or are using the same product.

Answer:

1.81

Explanation:

3*16=n(0.0821)(48+273)

Answer:

n = 2 moles (1 sig-fig)

Explanation:

Using the Ideal Gas Law equation (PV = nRT), solve for n (= moles) and substitute data for ...

pressure = P(atm) = 100atm

volume =V(liters) = 50L

gas constant = R = 0.08206L·atm/mol·K

temperature = T(Kelvin) = °C + 273 = (35 + 273)K = 308K

PV = nRT => n = PV/RT = (100atm)(50L)/(0.08206L·atm/mol·K)(308K)

∴ n(moles) = 1.978moles ≅ 2 moles gas (1 sig-fig) per volume data (= 50L) that has only 1 sig-fig. (Rule => for multiplication & division computations round final answer to the measured data having the least number of sig-figs).

Moles are the ratio of the mass and the molar mass of the substance. In a 50.0 L cylinder, 2 moles of gas are present at 100 atm and 35 degrees celsius.

An ideal gas equation states the relationship between the moles of the substance, temperature, pressure, and volume. The ideal gas equation is given as,

[tex]\rm PV = nRT[/tex]

Given,

The pressure of the gas (P) = 100.0 atm

Volume of the gas (V) = 50.0 L

Temperature (T) = 308 K

Gas constant (R) =  0.08206 L atm/mol K

Substituting values in equation moles (n) is calculated as:

[tex]\begin{aligned} \rm n&= \rm \dfrac{PV}{RT}\\\\&= \dfrac{100 \times 50}{0.08206 \times 308}\\\\&= 1.978\end{aligned}[/tex]

Therefore, 1.978 or 2 moles of gas are present.

Learn more about moles here:

https://brainly.com/question/20343774

Answer:

V = 0.0496 L

Explanation:

Given that,

The mass of a sample, m = 352.2 g

The density pf sample, d = 7.10 g/mL

We need to find the volume of the sample. We know that the density of an object is given by :

[tex]d=\dfrac{m}{V}\\\\V=\dfrac{m}{d}\\\\V=\dfrac{352.2}{7.1}\\\\V=49.6\ mL[/tex]

or

V = 0.0496 L

So, the volume of the sample is 0.0496 L.

Answer:

7.63 × 10²³ molecules

Explanation:

First, convert grams to moles using the molar mass of water (32.988 g/mol).

41.8 g  ÷  32.988 g/mol  =  1.267 mol

Next, convert moles to molecules using Avogadro's number (6.022 × 10²³).

1.267 mol  ×  6.022 × 10²³ molecules/mol = 7.63 × 10²³ molecules

Answer:

Assignment Summary

For this assignment, you will develop a model that shows a roller coaster cart in four different positions on a track. You will then use this model to discuss the changes in potential and kinetic energy of the cart as it moves along the track.

Background Information

The two most common forms of energy are potential energy and kinetic energy. Potential energy is the stored energy an object has due to its position. Kinetic energy is the energy an object has due to its motion. An object’s kinetic energy changes with its motion, while its potential energy changes with its position, but the total energy stays the same. If potential energy increases, then kinetic energy decreases. If potential energy decreases, then kinetic energy increases.

Potential energy related to the height of an object is called gravitational potential energy. Gravitational potential energy is directly related to an object’s mass, the acceleration due to gravity, and an object’s height.

Materials

 One poster board per student  Drawing utensils

Assignment Instructions

Step 1: Prepare for the project.

a) Read the entire Student Guide before you begin this project.

b) If anything is unclear, be sure to ask your teacher for assistance before you begin.

c) Gather the materials you will need to complete this project.

Step 2: Create your poster.

a) On the poster board, draw a roller coaster track that starts with one large hill, then is followed by a valley and another, smaller hill.

b) Draw a cart in four positions on the track as outlined below.

i. Draw the first cart at the top of the first hill. Label it A.

ii. Draw the second cart going down the first hill into the valley. Label it B.

iii. Draw the third cart at the bottom of the valley. Assume that the height of the cart in this position is zero. Label it C.

iv. Draw the last cart at the top of the second, smaller hill. Label it D.

c) Make sure that your name is on the poster. Step 3: Type one to two paragraphs that describe the energy of the cart.

a) Type one to two paragraphs describing the changes in potential and kinetic energy of the cart. Be sure to discuss how the potential and kinetic energy of the cart changes at each of the four positions along the track, and explain why these changes occur.

b) Make sure your name is on the document.

c) Later, you will submit this document through the virtual classroom.

Step 4: Evaluate your project using this checklist.

If you can check each criterion below, you are ready to submit your project.

 Did you draw a model of a roller coaster track with one large hill, a valley, and a smaller hill?

 Did you draw a cart on the track in the four required positions A–D? Did you label the cart at each of the four positions?

 Did you type a paragraph describing the changes in potential and kinetic energy of the cart at each of the four positions on the roller coaster track? Did you explain why the changes in potential and kinetic energy occur?

Step 5: Revise and submit your project.

a) If you were unable to check off all of the requirements on the checklist, go back and make sure that your project is complete.

b) When you have completed your project, submit your poster to your teacher for grading. Be sure that your name is on it.

c) Submit the typewritten document through the virtual classroom. Be sure that your name is on it.

Step 6: Clean up your work space.

a) Clean up your work space. Return any reusable materials to your teacher and throw away any trash.

b) Congratulations! You have completed your project.

Explanation:

Answer:

It will be halve of T

Explanation:

V1 = V

T1 = T

V2 = ½V

T2 = x

V1/T1 = V2/T2

V/T = ½V/x

Vx = ½VT

2Vx = VT

2x = T

x = ½T

Answer:

by centrifugation

Explanation:

in such cases filtration cannot be used for separation

The basic requirement while writing the electronic configuration of an element (atom) is its atomic number.

Explanation:

    [tex]1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p, 6s, 4f, 5d, 6p, 7s, 5f, 6d...[/tex]

For example:

  The atomic number of gallium is 31, its electronic configuration will be:

   [tex][Ga]=1s^2 2s^2 2p^63s^2 3p^6 4s^2 3d^{10} 4p^1[/tex]

Learn more about an electronic configuration of an atom here:

brainly.com/question/11628377

brainly.com/question/18444398

Explanation:

A photon is a quantum of EM radiation. Its energy is given by E = hf and is related to the frequency f and wavelength λ of the radiation by

E=hf=hcλ(energy of a photon)E=hf=hcλ(energy of a photon),

where E is the energy of a single photon and c is the speed of light. When working with small systems, energy in eV is often useful. Note that Planck’s constant in these units is h = 4.14 × 10−15 eV · s.

Since many wavelengths are stated in nanometers (nm), it is also useful to know that hc = 1240 eV · nm.

These will make many calculations a little easier.

All EM radiation is composed of photons. Figure 1 shows various divisions of the EM spectrum plotted against wavelength, frequency, and photon energy. Previously in this book, photon characteristics were alluded to in the discussion of some of the characteristics of UV, x rays, and γ rays, the first of which start with frequencies just above violet in the visible spectrum. It was noted that these types of EM radiation have characteristics much different than visible light. We can now see that such properties arise because photon energy is larger at high frequencies.

Answer:

Beautiful, scary, a different experience, full of imaginations.

Answer:

c.) 22.4 L/1 mole

Explanation:

Using the general gas law equation as follows:

PV = nRT

Where;

P = pressure (atm)

V = volume (L)

n = number of moles (mol)

R = gas law constant (0.0821 Latm/molK)

T = temperature (K)

The standard values for a gas are as follows:

Standard pressure of a gas = 1 atm

Standard temperature of a gas = 273K

According to the information in the question, n = 12.3 moles

Using PV = nRT

V = nRT/P

V = 12.3 × 0.0821 × 273/1

V = 275.68 L

Based on this value of volume in liters for 12.3moles of Br gas, the volume per mole at standard temperature and pressure will be 275.68/12.3 = 22.4 Litres per mole. Hence, the answer is 22.4 L/1 mole.