Watch help videoKevin has a bag that contains orange chews, strawberry chews, and peach chews. Heperforms an experiment. Kevin randomly removes a chew from the bag, records theresult, and returns the chew to the bag. Kevin performs the experiment 32 times. Theresults are shown below:An orange chew was selected 5 times.A strawberry chew was selected 17 times.A peach chew was selected 10 times.Based on these results, express the probability that the next chew Kevin removesfrom the bag will be peach chew as a percent to the nearest whole number.Answer:Submit Answer

Answers

Answer 1

Divide the amount of times that a peach chew was selected over the total number of times that the experiment was performed to find the probability that the next chew will also be a peach chew:

[tex]\frac{10}{32}=0.3125=31.25\text{ \%}[/tex]

Then, as a percent to the nearest whole number, the probability that the next chew Kevin removes from the bag will be a peach chew, is:

[tex]31\text{ \%}[/tex]


Related Questions

Use a properly of equality to solve this equation: 4.5x = 18

Answers

To solve the equation you can use the property of the multiplicative inverse, like this

[tex]\begin{gathered} 4.5x=18​ \\ \frac{1}{4.5}\cdot4.5x=18​\cdot\frac{1}{4.5} \end{gathered}[/tex]

Dividing by 4.5 into both sides of the equation is the same as multiplying by the multiplicative inverse of 4.5 on both sides of the equation

[tex]x=\frac{18}{4.5}[/tex]

Therefore,

[tex]x=4[/tex]

Janelle invests in a piece of art that cost 600 British Pounds. A study found that art appreciates in value at a rate of 3.97% per year. Assuming this pattern continues, how much, in British Pounds, will Janelle's piece of art be valued at after 10 years? Round your answer to the hundredths place.

Answers

Step-by-step explanation:

The art piece originally costs £600.

And it appreciates at a rate of 3.97% each year.

And we want to find the value of the art after 10 years.

We can write an exponential function to model the situation. The standard exponential function is given by:

[tex]f(t)=a(r)^t[/tex]

Where t is the time in years.

Since it appreciates at a rate of 3.97% each year, the value after each year will be (100% + 3.97%) or 103.97%.

103.97% = 1.0397. So, r = 1.0397:

[tex]f(t)=a(1.0397)^t[/tex]

Our a is the initial value. Therefore:

[tex]f(t)=600(1.0397)^t[/tex]

Then the value of the piece of art after 10 years is:

[tex]f(10)=600(1.0397)^{10}=885.58793\approx885.59[/tex]

Hence, It will be worth about £885.59 after 10 years.

A glass jar contains 3 red, 13 green, 4 blue, and 8 yellow marbles. If a single marble is chosen at random from the jar, what is the probability of choosing a(a) red marble? (b) green marble? (c) blue marble?

Answers

Solution

(a) red marble?

[tex]p=\frac{\text{red}}{\text{total}}=\frac{3}{3+13+4+8}=\frac{3}{28}[/tex]

(b) green marble?

[tex]p=\frac{\text{gren}}{\text{total}}=\frac{13}{3+13+4+8}=\frac{13}{28}[/tex]

(c) blue marble?​

[tex]p=\frac{\text{blue}}{\text{total}}=\frac{4}{3+13+4+8}=\frac{4}{28}[/tex]

The endpoints of AB are A(9,4) and B(5,-4). The endpoints of its image after a dilation are A'(6,3) and B'(3,-3). Find the scale factor and explain each of your steps.

Answers

It is given that the line segment AB is dilated to give another line segment A'B'.

Since it is a dilation, the length of the image will be a multiple of the length of the preimage.

To find the scale factor, divide the length of the image by the length of the preimage.

Recall that the length of a line segment with endpoints (a,b) and (c,d) is given as:

[tex]\sqrt[]{(c-a)^2+(d-b)^2}[/tex]

To find the length AB of the preimage, substitute the coordinates (a,b)=(9,4) and (c,d)=5,-4) into the formula:

[tex]AB=\sqrt[]{(5-9)^2+(-4-4)^2}=\sqrt[]{(-4)^2+(-8)^2}=\sqrt[]{16+64}=\sqrt[]{80}[/tex]

To find the length A'B' of the image, substitute the coordinates (a,b)=(6,3) and (c,d)=(3,-3) into the formula:

[tex]A^{\prime}B^{\prime}=\sqrt[]{(3-6)^2+(-3-3)^2}=\sqrt[]{(-3)^2+(-6)^2}=\sqrt[]{9+36}=\sqrt[]{45}[/tex]

Divide the length of the image by the length of the preimage to calculate the scale factor:

[tex]\frac{A^{\prime}B^{\prime}}{AB}=\frac{\sqrt[]{45}}{\sqrt[]{80}}=\sqrt[]{\frac{45}{80}}=\sqrt[]{\frac{9}{16}}=\frac{\sqrt[]{9}}{\sqrt[]{16}}=\frac{3}{4}[/tex]

Hence, the scale factor is 3/4.

The answer is 3/4.

Sarah took the advertising department from her company on a round trip to meet with a potential client. Including Sarah a total of 10 people took the trip. She was able to purchase coach tickets for $200 and first-class seats for $940 Sheyee her total budget for airfare for the trip, which was $4220. How many first-class tickets did she buy? How many coach tickets did she buy? number of first-class tickets bought = number of coach tickets bought =

Answers

Answer:

• The number of first-class tickets bought = 3

,

• The number of coach tickets bought =7

Explanation:

Let the number of first-class tickets bought = x

Let the number of coach tickets bought = y

A total of 10 people took the trip:

[tex]\implies x+y=10[/tex]

Her total budget for the trip's airfare = $4220.

[tex]\implies200y+940x=4220[/tex]

Next, solve the two equations simultaneously:

[tex]\begin{gathered} x+y=10\implies x=10-y \\ 940x+200y=4220 \end{gathered}[/tex]

Substitute x into the second equation:

[tex]\begin{gathered} 940(10-y)+200y=4220 \\ 9400-940y+200y=4220 \\ 9400-740y=4220 \\ 9400-4220=740y \\ 5180=740y \\ \frac{5180}{740}=y \\ y=7 \end{gathered}[/tex]

Recall: x=10-y

[tex]\begin{gathered} x=10-7 \\ x=3 \end{gathered}[/tex]

Thus:

• The number of first-class tickets bought, x = 3

,

• The number of coach tickets bought, y =7

A computer system was purchased by a small business for $12,000 and, for tax purposes, is assumed to have a salvage value of $2,000 after 8 years. If its value is depreciated linearly from $12,000 to $2,000, find the linear equation that relates the value V in dollars to the time t in years. A video production company is planning to produce instructional videotape. The producer estimates that it will cost $84,000 to shoot the video and $15 per unit to copy and distribute the tape. The wholesale price of the tape is $50 per unit. How many units must be manufactured and sold each month for the company to break even?

Answers

Second question

In order to break even,

total revenue must be equal to total cost. In this case, there is no profit

Let x represent the number of units of tape that would be manufactured to break even.

From the information given,

cost of shooting the video = 84000

If the cost of producing a unit is $15, it means that the cost of x units would be 15x

The total cost of producing x units is

15x + 84000

The wholesale price of the tape is $50 per unit. It means that the revenue from selling x units would be 50x

To break even, it means that

15x + 84000 = 50x

50x - 15x = 84000

35x - 84000

x = 84000/35

x = 2400

2400 units must be manufactured and sold each month for the company to break even

Chauncey is studying a 250-mg sample of a radioasubstance has a half-life of 5 days. Write an equatsubstance, s, is left after n days?aS =b= 250 (3)s = 250 (3)s = 250 (0.5)s = 250 (0.5)$5nd

Answers

Answer:

[tex]s=250(0.5)^{\frac{n}{5}}[/tex]

Step by step explanation:

Exponential functions are represented by the following expression:

[tex]\begin{gathered} f(x)=ab^x \\ \text{where,} \\ a=\text{initial amount} \\ b=\text{decay factor} \\ x=\text{time(days)} \end{gathered}[/tex]

Then, for this situation, we have an initial amount of 250, a decay factor of (0.5) in 5 days:

[tex]s=250(0.5)^{\frac{n}{5}}[/tex]

Is it always, sometimes, or never true that an equation in slope-intercept form represents a direct variation? Support your answer with examples

Answers

It is always true an equation in slope-intercept form represents a direct variation.

For example, the amount of money you earn by hours.

Let:

x = Number of hours

y = Amount of money

a = Money per hour = $5

The equation will be:

[tex]\begin{gathered} y=ax \\ y=5x \end{gathered}[/tex]

Supposed to 25% of the time Danny eat out twice a month 30% of the time he eats out once a month and 45% of the time he doesn’t eat out at all in a given month what is the expected value for the number of times daily eats out during a month

Answers

Answer

Expected value = 0.8 times per month

Explanation

The mean of the probability distribution is called expected value and it is given as

E(X) = Σxᵢpᵢ

where

xᵢ = each variable = Number of times Danny eats out

pᵢ = probability of each variable

n = number of variables

p = probability of one variable

We need to set up the probability distribution first

xᵢ | pᵢ

2 | 0.25

1 | 0.30

0 | 0.45

E(X)

= (2 × 0.25) + (1 × 0.30) + (0 × 0.45)

= 0.5 + 0.3 + 0

= 0.8

Hope this Helps!!!

10Ana wants to multiply out the brackets in the expression 2(3a-1).She writes 2(3a-1)=6a - 1.Ana is wrong. Explain why.1Show Your WorkYou have responded to 9 of 10 questions

Answers

Answer:

[tex]2(3a-1)=6a-2[/tex]

Step by step explanation:

To multiply the expression 2(3a-1), we need to use the distributive property of multiplication which states that:

[tex]a(b+c)=a\cdot b+a\cdot c[/tex]

Then, for the expression 2(3a-1), the correct answer would be:

[tex]\begin{gathered} 2(3a-1)=2\cdot3a-2\cdot1 \\ 2(3a-1)=6a-2 \end{gathered}[/tex]

Pamela's mother purchased five boxes of candy bars. If each box contains 20 bars, how many candy bars does Pamela's mother have? Explain your answer.

Answers

If each box contains 20 bars and Pamela's mother purchased 5 boxes

To get the number of candy bars Pamela's mother have, we will simply multiply the number of box by the number oc candy in each box

That is; 5 x 20bars = 100 candy bars

Hence Pamela's mother have 100 candy bars

what is the ratio 250 pieces of red construction paper and 114 blue construction paper

Answers

Answer

Check Explanation

Explanation

We need to find the ratio of red construction paper to blue construction paper.

250 : 114

Divide both sides by 2

125 : 57

That's how far we can go, since there is no number that can divide these two numbers.

Hope this Helps!!!

The coach of a soccer team keeps many stats on her teams performance. For example, she records if the team was ahead, behind, or tired with the opponent at the end of each half.pic is the summary of the data she got after 60 games. Supposed the coach continue recording the end-of-half results for 80 more games. In how many of these 80 games will the team be tied at the end of neither half. Use the data to make a prediction

Answers

Given:

The stat of the team is given in the table.

Required:

We have to find in how many of 80 games will the team be tied at the end of neither half.

Explanation:

The total number of games given in the table is

[tex]4+8+12+3+6+9+5+4+9=60[/tex]

The number of games in which the team has tied at the end of neither half is

[tex]4+8+3+6=21[/tex]

Then the percentage of the team has tied at the end of neither half is

[tex]\frac{21}{60}\times100=0.35\times100=35\text{ \%}[/tex]

Hence the number of games in which the team be tied at the end of neither half in those 80 games is

[tex]35\text{\% of }80=\frac{35}{100}\times80=0.35\times80=28[/tex]

Final answer:

Hence the final answer is

[tex]28[/tex]

A sailmaster decides to stitch a strip of binding right round the edge of a sail which is the shape of a right- angled triangle. The vertical and horizontal edges of the sail are 6.5m and 2.6m respectively. What length of binding is needed for the job?

Answers

First, we will use the Pythagorean theorem to compute the hypotenuse:

[tex]\begin{gathered} h^2=(6.5m)^2+(2.6m)^2 \\ =42.25m^2+6.76m^2 \\ =49.01m^2. \end{gathered}[/tex]

Then:

[tex]h\approx7.0m.[/tex]

Therefore, the sail master will need:

[tex]6.5m+2.6m+7m=16.1m[/tex]

of blinding.

Answer: 16.1m

Can someone help me with this question?

Answers

So the average decrease will be 50% for the season of 5 weeks as the definition of percent decrease will be "The difference between starting and ending values is the percentage decrease. It displays a percentage loss of value compared to the original regardless of the units. The difference between the initial and final amounts is the amount of decrease".

What is percent decrease?

The difference between starting and ending values is the percentage decrease. It displays a percentage loss of value compared to the original regardless of the units. The difference between the initial and final amounts is the amount of decrease.

Here,

The percent decrease will be,

48000-24000=24000

24000/48000*100=50%

24000-12000=12000

12000/24000*100=50%

12000-6000=6000

6000/12000*100=50%

6000-3000=3000

3000/6000*100=50%

3000-1500=1500

1500/3000*100=50%

Due to the definition of percent decrease being a season of five weeks, the average decrease will be 50% "The percentage decrease is the difference between the starting and ending values. Regardless of the units, it shows a percentage decline in value relative to the starting point. The amount of decrease is the difference between the initial and final amounts ".

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For each of the following, find the Lateral Area, Surface Area, and Volume. Leave answers in terms ofFt, and if applicable, round to the nearest tenth.1. TA =V=A sphere with radius of 21 cm.

Answers

Given a sphere with radius R, the volume and the surface area formulas are expressed as:

[tex]\begin{gathered} V=\frac{4}{3}\pi R³ \\ \\ A=4\pi R² \end{gathered}[/tex]

Now, if we have a sphere of radius R = 21 cm = 0.688976 ft. Then, using the formulas:

For the volume

[tex]\begin{gathered} V=\frac{4}{3}\pi(0.688976)³ \\ \\ \therefore V=1.37\text{ ft^^b3} \end{gathered}[/tex]

For the surface area

[tex]\begin{gathered} A=4\pi(0.688976)² \\ \\ \therefore A=5.97\text{ ft^^b2} \end{gathered}[/tex]

what is the area of a semicircle with a diameter of 2 ?

Answers

we have that

the area of semicircle is equal to

[tex]A=\frac{1}{2}\cdot\pi\cdot r^2[/tex]

we have

r=2/2=1

substitute

[tex]\begin{gathered} A=\frac{1}{2}\cdot\pi\cdot1^2 \\ A=\frac{\pi}{2} \end{gathered}[/tex]area is equal to pi/2 square units

How large is the sample space when rolling a die five times?

Answers

7776

Explanation

The size of the sample space is the total number of possible outcomes.for example, for a dice, the possible outcomes are 1, 2,3 4, 5 or 6, when rolling a dice five times we have:

Each time you roll the dice there are 6 possible outcomes. (1 of 6)

[tex]6[/tex]

now, you have to roll the dice five times

then

[tex]\text{sample space=6}^5=6\cdot6\cdot6\cdot6\cdot6=7776[/tex]

I hope this helps you

To solve rational equation shown below, find the common denominator

Answers

Given:

[tex]\frac{3}{2x+1}=\frac{5}{4x+3}[/tex][tex]3(4x+3)=5(2x+1)[/tex][tex]12x+9=10x+5[/tex][tex]12x-10x=5-9[/tex][tex]2x=-4[/tex][tex]x=-\frac{4}{2}[/tex][tex]x=-2[/tex]

Use the correct trigonometric function to solve for both x and y .

Answers

As per given by the question.

There are given that a triangle.

Now,

Suppose given triangle is ABC.

Then, redraw the given triangle.

Now,

For finding the value of x, and y;

First find the value of x with the help of sine trigonometric function.

So,

[tex]\sin 35^{\circ}=\frac{AB}{AC}[/tex]

Then,

Substitute the value x for AB and 22 for AC.

SO,

[tex]\begin{gathered} \sin 35^{\circ}=\frac{AB}{AC} \\ \sin 35^{\circ}=\frac{x}{22} \\ 0.57=\frac{x}{22} \\ x=0.57\times22 \\ x=12.54 \end{gathered}[/tex]

Now,

For finding the value of y,

Here, use pythagoras theorem in triangle ABC.

So, from the pythagoras theorem;

[tex]AB^2+BC^2=AC^2[/tex]

Then,

Substitute the value in above formula;

So,

[tex]\begin{gathered} AB^2+BC^2=AC^2 \\ x^2+y^2=(22)^2 \end{gathered}[/tex]

Now, put the value 12.54 for x,

So,

[tex]\begin{gathered} x^2+y^2=(22)^2 \\ (12.54)^2+y^2=(22)^2 \\ 157.25+y^2=484 \\ y^2=484-157.25 \\ y^2=326.75 \end{gathered}[/tex]

Then,

[tex]\begin{gathered} y^2=326.75 \\ y=\sqrt[]{326.75} \\ y=18.076 \end{gathered}[/tex]

Hence, the value of x is 12.54 and the value of y is 18.076.

Susan is making a pennant in the shape of a triangle for her senior class photo. She wants the base length of this triangle to be 4 inches. The area of the pennant must be at least 12 square inches. (The pennant has to be seen in the photo.) Write an Inequality that describes the possible heights (in inches) of the triangle. Use h for the height of the triangular pennant.

Answers

Susan is making a pennant in the shape of a triangle for her senior class photo. She wants the base length of this triangle to be 4 inches. The area of the pennant must be at least 12 square inches. (The pennant has to be seen in the photo.) Write an Inequality that describes the possible heights (in inches) of the triangle. Use h for the height of the triangular pennant.​

Remember that

the area of the triangle is

[tex]A=\frac{1}{2}b\cdot h[/tex]

we have

b=4 in

at least -----> is greater than or equal to

so

[tex]A\ge12\text{ in2}[/tex]

therefore

[tex]\begin{gathered} \frac{1}{2}\cdot(4)\cdot h\ge12 \\ \text{solve for h} \\ 2h\ge12 \\ h\ge6\text{ in} \end{gathered}[/tex]

the height of triangle must be greater than or equal to 6 inches

Rangers wanted to estimate the total number of elk in region of Montana. they tagged 12 elk and sent them back to the area. two months later the Rangers observed 4 of the tagged elk out of 25 total Elk observed. estimate the size of the elk population in that region of Montana

Answers

Total number of elks tagged = 12

Number of a sample of the tagged elks from 25 total Elk observed = 4

Total number of 25 Elk observed = 12/4 = 3

Size of the elk population in the region of Montana ​ = 3 x 25

= 75

i need help with -1=-4/7t

Answers

The equation is:

[tex]-1\text{ = -}\frac{4}{7}\text{ t}[/tex]

To find t you need to isolate t.

First, pass the 7 multiplying and the 4 dividing:

[tex]-1\cdot\frac{7}{4}=-t[/tex]

Finally, pass the minus sign:

[tex]-t\text{ = (-1)}\cdot t=-1.\frac{7}{4}\Rightarrow\text{ t = (-1)}\cdot\frac{7}{4}\frac{1}{(-1)}=\frac{7}{4}[/tex]

Solve the system of linear equations by eliminations-- 3x + 4y = 186x+2y = -6does thia system have a solution?

Answers

[tex]\begin{gathered} 3x+4y=18 \\ 3x+y=-3 \\ \\ \text{After subtracting both equations we get} \\ 3y=21 \\ \frac{3y}{3}=\frac{21}{3} \\ y=7 \\ \\ \text{Put the value of Y on one of the initial equations} \\ 6x+2(7)=-6 \\ 6x+14=-6 \\ 6x+14(-14)=-6(-14) \\ 6x=-20 \\ \frac{6x}{6}=\frac{-20}{6} \\ x=-\frac{10}{3} \end{gathered}[/tex]

Sketch a graph of g (x) = V (x-3) + 2 Label at least 4 points including X-and y-intercepts, explain

Answers

The equation is given as

[tex]g(x)=\sqrt[]{x-3}+2[/tex]

To find the coordinates of the equation,

Hence the graph of the equation is

Five CDs cost $80 . If each CD costs the same, how much does one cost

Answers

solution:

5 CDs ----> $80

1 CDs ----> x

then

[tex]x=\frac{80}{5}=16[/tex]

answer: one CD cost $16

Seth charges $42 for 2 hours of baseball lessons. Bennie charges $65 for 3 hours of baseball lessons. Who offers the better deal? Why?

Answers

Answer:

Seth offers the better deal, because his charge per hour is lower.

Explanation:

Given that;

Seth charges $42 for 2 hours of baseball lessons.

Seth's Charge rate per hour would be;

[tex]\begin{gathered} r_s=\frac{\text{ \$42}}{2\text{ hours}} \\ r_s=\text{ \$21 per hour} \end{gathered}[/tex]

Also, Bennie charges $65 for 3 hours of baseball lessons.

[tex]\begin{gathered} r_b=\frac{\text{ \$65}}{3\text{ hours}} \\ r_b=\text{ \$21.67 per hour} \end{gathered}[/tex]

From the given deals, the deal with the lower Charge rate per hour offers the better deal.

So, Seth offers the better deal, because his charge per hour is lower.

which word phrase represents the following expression n-3A) the quotient of n and 3B) 3 less than nC) n less than 3

Answers

Answer:

B) 3 less than n

Explanation:

Given the expression:

[tex]n-3[/tex]

This means that the value of n is being reduced by 3.

Thus, the appropriate word phrase is: 3 less than n.

The correct choice is B.

It’s B because it’s just B

To start a new business Beth deposits $1500 at the end of each six-month period in an account that pays 8%, compounded semiannually. How much will she have at the end of 9 years?

Answers

The amount Beth deposit every six-month is A = $1500.

The rate percent is 8% or 0.08.

The time after which futre value determined is t = 9 years.

Determine the rate percent for semi-annually.

[tex]\begin{gathered} i=\frac{0.08}{2} \\ =0.04 \end{gathered}[/tex]

Determine the value of time (t) for semi-annualy.

[tex]\begin{gathered} n=2\cdot9 \\ =18 \end{gathered}[/tex]

The formula for the future value is,

[tex]FV=\frac{A}{i}\lbrack(1+i)^n-1\rbrack[/tex]

Substitute the values in the formula to determine the future value.

[tex]\begin{gathered} FV=\frac{1500}{0.04}\lbrack(1+0.04)^{18}-1\rbrack \\ =37500\lbrack(1.04)^{18}-1\rbrack \\ =38468.11933 \\ =38468.12 \end{gathered}[/tex]

So answer is 38468.12

Estimate the instantaneous rate of change of the function f(x)=x2−2x+1 at x=−1 using the average rate of change over successively smaller intervals.

Answers

The instantaneous rate of change of the function f(x)=x²−2x+1 at x=−1 using the average rate of change over successively smaller intervals is 4.

What is function?

A function from a set X to a set Y assigns exactly one element of Y to each element of X. The set X is known as the function's domain, and the set Y is known as the function's codomain. A function is an expression, rule, or law in mathematics that defines a relationship between one variable (the independent variable) and another variable (the dependent variable). A function is defined as a relationship between a set of inputs that each have one output. A function is a relationship between inputs in which each input is related to exactly one output. Every function has a domain and a codomain, as well as a range. In general, a function is denoted by f(x), where x is the input.

Here,

x²-2x+1

x=-1

(-1)²-2*-1+1

1+2+1=4

the instantaneous rate of change=4

Using the average rate of change over successively smaller intervals, the instantaneous rate of change of the function f(x)=x²-2x+1 at x=1 is 4.

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