Can you pls help me with this question thank you
To solve this question, follow the steps below.
Step 01: Substitute j and k by its corresponding values.
j = 6
k = 0.5
Then,
[tex]\begin{gathered} 3.6j-2k \\ 3.6\cdot6-2\cdot0.5 \\ \end{gathered}[/tex]Step 02: Solve the multiplications.
[tex]21.6-1[/tex]Step 03: Solve the subtraction.
[tex]20.6[/tex]Answer: b. 20.6.
suppose each cube in this right rectangular prism is a 1/2-in unit cube
Answer:
The length of each cube is given below as
[tex]l=\frac{1}{2}in[/tex]Concept:
To figure out the dimension of the prism, we will calculate the number of cubes to make the length,width and height and multiply by 1/2
To figure out the length of the prism,
we will multiply 1/2in by 5
[tex]\begin{gathered} l=\frac{1}{2}in\times5 \\ l=2.5in \end{gathered}[/tex]To figure out the width of the prism,
we will multiply 1/2in by 4
[tex]\begin{gathered} w=\frac{1}{2}in\times4 \\ w=2in \end{gathered}[/tex]To figure out the height of the prism,
we will multiply 1/2 in by 3
[tex]\begin{gathered} h=\frac{1}{2}in\times3 \\ h=\frac{3}{2}in=1.5in \end{gathered}[/tex]Hence,
The dimensions of the prism are
Length = 2.5in
Width = 2in
Height = 1.5 in
2.5in by 2in by 1.5in
Part B:
To figure out the volume of the prism, we will use the formula below
[tex]\begin{gathered} V_{prism}=base\text{ area}\times height \\ V_{prism}=l\times w\times h \\ l=2.5in,w=2in,h=1.5in \end{gathered}[/tex]By substituting the values, we will have
[tex]\begin{gathered} V_{pr\imaginaryI sm}=l\times w\times h \\ V_{pr\mathrm{i}sm}=2.5in\times2in\times1.5in \\ V_{pr\mathrm{i}sm}=7.5in^3 \end{gathered}[/tex]Alternatively, we will calculate below by calculate the volume of each cube and then multiply by the total number of cubes
[tex]\begin{gathered} volume\text{ of each cube=} \\ =l^3=(\frac{1}{2})^3=\frac{1}{8}in^3 \\ The\text{ total number of cubes =} \\ =5\times4\times3 \\ =60cubes \\ Volume\text{ of the prism } \\ =\frac{1}{8}in^3\times60 \\ =7.5in^3 \end{gathered}[/tex]Hence,
The volume of the prism is = 7.5in³
What value of x would make lines land m parallel?5050°t55°75xº55m105
If l and m are parallel, then ∠1 must measure 55°.
The addition of the angles of a triangle is equal to 180°, in consequence,
Find the distance from P to l. Line l contains points (2, 4) and (5, 1). Point P has coordinates (1, 1).
First we need to find the equation of the line l passing through the points (2, 4) and (5, 1).
The equation of a line is expressed as y = mx+c
m is the slope
c is the intercept
m = y2-y1/x2-x1
m = 1-4/5-2
m = -3/3
m = -1
Get the intercept
Substitute any point (2, 4) and the slope m = -3 into the expression y = mx + c
4 = -3(2)+c
4 = -6 + c
c = 4+6
c = 10
The equation of line l is y = -3x+10
Next is to find the equation of the line w perpendicular to the line l, through P(1, 1).
Since the line w is perpendicular to lin
x^2-18x-57=6 solve each equation by completing the square
x=-3
x=21
I need help on this. and there's two answers that's right but I don't know
Answer
Options B and C are correct.
(5⁸/5⁴) = 625
(5²)² = 625
Explanation
We need to first know that
625 = 5⁴
So, the options that the laws of indices allow us to reduce to 5⁴
Option A
(5⁻²/5²) = 5⁻²⁻² = 5⁻⁴ = (1/5⁴) = (1/625)
This option is not correct.
Option B
(5⁸/5⁴) = 5⁸⁻⁴ = 5⁴ = 625
This option is correct.
Option C
(5²)² = 5⁴ = 625
This option is correct.
Option D
(5⁴) (5⁻²) = 5⁴⁻² = 5² = 25
This option is not correct.
Hope this Helps!!!
please help me solve. The answer I have is in yellow. They are wrong.
Let's simplify the radicals:
[tex]\begin{gathered} \sqrt[]{30}\cdot\sqrt[]{5}=\sqrt[]{30\cdot5} \\ =\sqrt[]{150} \\ =\sqrt[]{25\cdot6} \\ =\sqrt[]{25}\sqrt[]{6} \\ =5\sqrt[]{6} \end{gathered}[/tex]What is the solution to the equation below? 3x = x + 10 O A. x = 10 B. x = 0 C. X = 5 D. No Solutions
Hence, the correct option is C: x=5
2. The length of Sally's garden is 4 meters greater than 3 times the width. Theperimeter of her garden is 72 meters. Find the dimensions of Sally's garden.The garden has a width of 8 and a length of 28.
L = length
W = width
L = 4 + 3*W
The perimeter of a rectangle is the sum of its sides: 2L + 2W. Since it's 72, we have:
2L + 2W = 72
Now, to solve for L and W, the dimensions of the garden, we can use the first equation (L = 4 + 3*W) into the second one (2L + 2W = 72):
2L + 2W = 72
2 * (4 + 3*W) + 2W = 72
2 * 4 + 2 * 3W + 2W = 72
8 + 6W + 2W = 72
8W = 72 - 8
8W = 64
W = 64/8 = 8
Then we can use this result to find L:
L = 4 + 3W = 4 + 3 * 8 = 4 + 24 = 28
Therefore, the garden has a width of 8 and a length of 28.
thank you for viewing my question I seem to be stuck on this and need help thank you
ANSWER
[tex]\begin{gathered} A=\frac{1}{4} \\ B=\frac{1}{2} \\ C=\frac{1}{4} \end{gathered}[/tex]EXPLANATION
From the given data;
Event A; Alternating even and odd numbers means;
EOE and OEO
Number of favourable outcome is 2 while number of possible outcome is 8
Hence, the probability of Event A IS;
[tex]\begin{gathered} Prob(A)=\frac{2}{8} \\ =\frac{1}{4} \end{gathered}[/tex]In Event B; More even numbers than odd means having;
EEE,OEE,EEO and EOE
[tex]\begin{gathered} EEE,OEE,EEOandEOE \\ Prob(B)=\frac{4}{8} \\ =\frac{1}{2} \end{gathered}[/tex]For Event C; an even number on both the first and the last rolls;
EEE and EOE
[tex]\begin{gathered} EEEandEOE \\ Prob(C)=\frac{2}{8} \\ =\frac{1}{4} \end{gathered}[/tex]Find the values of the variables so that the figure is aparallelogram.
Given the following question:
[tex]\begin{gathered} \text{ The property of a }parallelogram \\ A\text{ + B = 180} \\ B\text{ + C = 180} \\ 64\text{ + }116\text{ = 180} \\ 116+64=180 \\ y=116 \\ x=64 \end{gathered}[/tex]y = 116
x = 64
what is the ratio of sin b
we have that
sin(B)=56/65 -----> by opposite side angle B divided by the hypotenuse
Help on question on math precalculus Question states-Which interval(s) is the function decreasing?Group of answer choicesBetween 1.5 and 4.5Between -3 and -1.5Between 7 and 9Between -1.5 and 4.5
We have a function of which we only know the graph.
We have to find in which intervals the function is decreasing.
We know that a function is decreasing in some interval when, for any xb > xa in the interval, we have f(xa) < f(xb).
This means that when x increases, f(x) decreases.
We can see this intervals in the graph as:
We assume each division represents one unit of x. Between divisions, we can only approximate the values.
Then, we identify all the segments in the graph where f(x) has a negative slope, meaning it is decreasing.
We have the segments: [-3, -1.5), (1,5, 4.5) and (7,9].
Answer:
The right options are:
Between 1.5 and 4.5
Between -3 and -1.5
Between 7 and 9
If Mason made 20 free throws, how many free throws did he attempt in all?
Answer:
what is the shooting percentage?
Suppose that our section of MAT 012 has 23 students, and the other two sections of MAT 012 have a total of 44 students. What percent of all the students taking MAT012 are in our section of MAT 012?
Explanation
We can deduce from the information that MAT 012 has 3 sections, namely:
Our section, and two other sections
Then, we can also infer that MAT012 has a total of:
[tex]23+44=67\text{ students}[/tex]Our task will be to get the percentage of our section taking MAT 102
Since our section has 23
Then we can calculate the answer as
[tex]\frac{23}{67}\times100=34.33\text{ \%}[/tex]Thus, the answer is 34.33%
Write a word problem that the bar model in problem 2 could represent.
An example of a problem for the given diagram:
You go to a store to buy the school supplies you will need for the next term. There are boxes of 7 pencils each, and you decide to buy 5 of those boxes. How many pencils do you end up buying?
If 6 times a certain number is added to 8, the result is 32.Which of the following equations could be used to solve the problem?O6(x+8)=326 x=8+326 x+8 = 326 x= 32
Answer: 6x + 8 = 32
Explanation:
Let x represent the number
6 times the number = 6 * x = 6x
If we add 6x to 8, it becomes
6x + 8
Given that the result is 32, the equation could be used to solve the problem is
6x + 8 = 32
I’m circle P with m ∠NRQ=42, find the angle measure of minor arc NQ
Here we must apply the following rule:
[tex]arc\text{ }NQ=2\cdot m\angle NRQ[/tex]Since m ∠NRQ = 42°, we have:
[tex]arc\text{ }NQ=2\cdot42=84\degree[/tex]Question 31 of 50 2 Points An assumption about a population parameter that is verified based on the results of sample data is a/an OA. statistical hypothesis OB. assumption OC. presumptive statement OD. prediction
From the question, it is:
An assumption about a population parameter that is verified based on the real results of sample data is a/an Statistical Hypothesis.
Hypothesis testing is a form of statistical inference that uses data from a sample to draw conclusions about a population parameter or a population probability distribution.
Therefore, the correct options is A, which is Statistical Hypothesis.
The relation described in the following diagram is function. A. True B. False
Answer:
False
Explanation:
A relation is a function each term of the first set is related to only one term of the second set. In this case, 1 is related to 5 and to 10, so it is not a function.
Therefore, the answer is
False
Write an equation of the line perpendicular to the line –4x + 3y = –15 and passes through the point (–8, –13)
4y = -3x - 76
Explanations:The given equation is:
-4x + 3y = -15
Make y the subject of the formula to express the equation in the form
y = mx + c
[tex]\begin{gathered} -4x\text{ + 3y = -15} \\ 3y\text{ = 4x - 15} \\ y\text{ = }\frac{4}{3}x\text{ - }\frac{15}{3} \\ y\text{ = }\frac{4}{3}x\text{ - 5} \end{gathered}[/tex]Comparing the equation with y = mx + c
the slope, m = 4/3
the y-intercept, c = -5
The equation perpendicular to the equation y = mx + c is:
[tex]y-y_1\text{ = }\frac{-1}{m}(x-x_1)[/tex]The line passes through the point (-8, -13). That is, x₁ = -8, y₁ = -13
Substitute m = 4/3, x₁ = -8, y₁ = -13 into the equation above
[tex]\begin{gathered} y\text{ - (-13) = }\frac{-1}{\frac{4}{3}}(x\text{ - (-8))} \\ y\text{ + 13 = }\frac{-3}{4}(x\text{ + 8)} \\ y\text{ + 13 = }\frac{-3}{4}x\text{ - 6} \\ y\text{ = }\frac{-3}{4}x\text{ - 6 - 13} \\ y\text{ = }\frac{-3}{4}x\text{ - 19} \\ 4y\text{ = -3x - }76 \end{gathered}[/tex]6. An odometer shows that a car has traveled 56,000 miles by January 1, 2020. The car travels 14,000 miles each year. Write an equation that represents the number y of miles on the car's odometer x years after 2020.
Answer:
y=14000x
Step-by-step explanation:
x represents years after 2020 and y is the number of miles
The required equation for the distance travelled versus number of years after 2020 is given as y = 14000x + 56000.
How to represent a straight line on a graph?To represent a straight line on a graph consider two points namely x and y intercepts of the line. To find x-intercept put y = 0 and for y-intercept put x = 0. Then draw a line passing through these two points.
The given problem can be solved as follows,
Suppose the year 2020 represents x = 0.
The distance travelled per year can be taken as the slope of the linear equation.
This implies that slope = 14000.
And, the distance travelled by January 1, 2020 is 56000.
It implies that for x = 0, y = 56000.
The slope-point form of a linear equation is given as y = mx + c.
Substitute the corresponding values in the above equation to obtain,
y = 14000x + c
At x = 0, y = 56000
=> 56000 = 14000 × 0 + c
=> c = 56000
Now, the equation can be written as,
y = 14000x + 56000
Hence, the required equation for number of miles and years for the car is given as y = 14000x + 56000.
To know more about straight line equation click on,
brainly.com/question/21627259
#SPJ2
Given the following data: {3, 7, 8, 2, 4, 11, 7, 5, 9, 6),a. What is the median? (remember to put the data in order first)
Solve the equation algebraically. x2 +6x+9=25
We must solve for x the following equation:
[tex]x^2+6x+9=25.[/tex]1) We pass the +25 on the right to left as -25:
[tex]\begin{gathered} x^2+6x+9-25=0, \\ x^2+6x-16=0. \end{gathered}[/tex]2) Now, we can rewrite the equation in the following form:
[tex]x\cdot x+8\cdot x-2\cdot x-2\cdot8=0.[/tex]3) Factoring the last expression, we have:
[tex]x\cdot(x+8)-2\cdot(x+8)=0.[/tex]Factoring the (x+8) in each term:
[tex](x-2)\cdot(x+8)=0.[/tex]4) By replacing x = 2 or x = -8 in the last expression, we see that the equation is satisfied. So the solutions of the equation are:
[tex]\begin{gathered} x=2, \\ x=-8. \end{gathered}[/tex]Answer
The solutions are:
• x = 2
,• x = -8
△GHI~△WVU.51010IHG122UVWWhat is the similarity ratio of △GHI to △WVU?Simplify your answer and write it as a proper fraction, improper fraction, or whole number.
Answer: 5
To get the similarity ratio, we must know that for the given triangles:
[tex]\frac{IG}{UW}=\frac{GH}{WV}=\frac{HI}{VU}[/tex]From the given, we know that:
UW = 2
WV = 2
VU = 1
IG = 10
GH = 10
HI = 5
Substitute these to the given equation and we will get:
[tex]\begin{gathered} \frac{IG}{UW}=\frac{GH}{WV}=\frac{HI}{VU} \\ \frac{10}{2}=\frac{10}{2}=\frac{5}{1} \\ 5=5=5 \end{gathered}[/tex]With this, we have the similarity ratio of ΔGHI to ΔWVU is 5
2. When we are in a situation where we have a proportional relationship between two quantities, what information do we need to find an equation?
Answer:
If two quantites have a proportional relatio
-3.9-3.99-3.999-4-4.001-4.01-4.10.420.4020.4002-41.5039991.53991.89try valueclear tableDNEundefinedlim f(2)=lim f(2)=2-)-4+lim f (30)f(-4)-4
In order to determine the limit of f(x) when x tends to -4 from the right (4^+), we need to look in the table the value that f(x) is approaching when x goes from -3.9 to -3.99 to -3.999.
From the table we can see that this value is 0.4.
Then, to determine the limit of f(x) when x tends to -4 from the left (4^-), we need to look in the table the value that f(x) is approaching when x goes from -4.1 to -4.01 to -4.001.
From the table we can see that this value is 1.5.
Since the limit from the left is different from the limit from the right, the limit when x tends to -4 is undefined.
Finally, the value of f(-4) is the value of f(x) when x = -4. From the table, we can see that this value is -4.
A tepee in the shape of a right cone has a slant height of 18.5 feet and a diameter of 20 feet. Approximately how much canvas would be needed to cover the tepee?
To find:
The area of canvas needed to cover the tepee.
Solution:
Given that the tepee is in the shape of a right cone, with slant height 18.5 feet and diameter of 20 feet then the radius is 10 feet.
The area of canvas is equal to the curved surface area of the tepee. It is known that the curve surface area of the cone is given by:
[tex]CSA=\pi rl[/tex]Where, r is the radius of the cone and l is the slant height of the cone. So,
[tex]\begin{gathered} CSA=3.14\times10\times18.5 \\ =580.9ft^2 \end{gathered}[/tex]Thus, the approximate canvas that would be needed to cover the tepee is 580.9 ft^2.
581Answer:
Step-by-step explanation:
Kwan had 16 3/4 inches of wire. He cut of 4 2/4 inches of wire to use in a craft project how much wire does kwan have left
We know that the total is 40 students, and 24 of them are girls, then the fraction that represents it is
[tex]\frac{24}{40}[/tex]But we must simplify the fraction, let's divide the denominator and numerator by 4
[tex]\frac{24}{40}=\frac{6}{10}[/tex]Now we can do it again by 2
[tex]\frac{24}{40}=\frac{6}{10}=\frac{3}{5}[/tex]Therefore the correct answer is the letter B.
[tex]\frac{3}{5}[/tex]Answer: 12 1/4
Step-by-step explanation: 16 =4 is 12, and 3/4 - 2/4 is 1/4
hope this helps :)
the item to the trashcan. Click the trashcan to clear all your answers.
Factor completely, then place the factors in The proper location on the grid.3y2 +7y+4
We are asked to factor in the following expression:
[tex]3y^2+7y+4[/tex]To do that we will multiply by 3/3:
[tex]3y^2+7y+4=\frac{3(3y^2+7y+4)}{3}[/tex]Now, we use the distributive property on the numerator:
[tex]\frac{3(3y^2+7y+4)}{3}=\frac{9y^2+7(3y)+12}{3}[/tex]Now we factor in the numerator on the right side in the following form:
[tex]\frac{9y^2+7(3y)+12}{3}=\frac{(3y+\cdot)(3y+\cdot)}{3}[/tex]Now, in the spaces, we need to find 2 numbers whose product is 12 and their algebraic sum is 7. Those numbers are 4 and 3, since:
[tex]\begin{gathered} 4\times3=12 \\ 4+3=7 \end{gathered}[/tex]Substituting the numbers we get:
[tex]\frac{(3y+4)(3y+3)}{3}[/tex]Now we take 3 as a common factor on the parenthesis on the right:
[tex]\frac{(3y+4)(3y+3)}{3}=\frac{(3y+4)3(y+1)}{3}[/tex]Now we cancel out the 3:
[tex]\frac{(3y+4)3(y+1)}{3}=(3y+4)(y+1)[/tex]Therefore, the factored form of the expression is (3y + 4)(y + 1).