Here, we want to use a model to solve the multiplication
We have this as follows;
Mathematically;
[tex]\frac{2}{3}\times6\text{ = 4}[/tex]The net of a rectangular prism is shown below. The surface area of each is labeled
Given:
Area of box I = 48 cm²
Area of box 2 = 24 cm²
Area of box 3 = 48 cm²
Area of box 4 = 24 cm²
Area of box 5 = 72 cm²
Area of box 6 = 72 cm²
• Let's find the values which represent the dimensions of the prism.
Let L represent the length.
Let w represent the width
Let h represent the height.
Now, to find the surface area of a rectangular prism apply the formula:
A = 2(wL + Lh + wh)
Now, given each rectangular face, we have:
Area of length and width, Lw = 72 cm²
Area of length and height, Lh = 48 cm²
Area of width and height, wh = 24 cm²
Now to find the dimensions, we have:
[tex]\begin{gathered} \frac{Lh}{wh}=\frac{48}{24} \\ \\ \frac{L}{w}=2 \\ \\ L=2w \end{gathered}[/tex]Now, substitute 2w for L in Lw:
[tex]\begin{gathered} Lw=72 \\ \\ 2w(w)=72 \\ \\ 2w^2=72 \\ \\ w^2=\frac{72}{2} \\ \\ w^2=36 \\ \\ \text{ take the square root of both sides:} \\ \sqrt{w^2}=\sqrt{36} \\ \\ w=6 \end{gathered}[/tex]Therefore, the width is 6 cm.
Now, substitute 6 for w in wh:
[tex]\begin{gathered} wh=24 \\ \\ 6*h=24 \\ \\ Divide\text{ both terms by:} \\ \frac{6*h}{6}=\frac{24}{6} \\ \\ h=4 \end{gathered}[/tex]Now, substitute 4 for h in Lh:
[tex]\begin{gathered} Lh=48 \\ \\ L*4=48 \\ \\ \text{ Divide both sides by 4:} \\ \frac{L*4}{4}=\frac{48}{4} \\ \\ L=12 \end{gathered}[/tex]Therefore, the values which represent the dimensions are:
4, 6, 12
ANSWER:
4, 6, 12
Compare f(-4) and g(-4)f(-4) is >, <, or = to g(-4)
The answer is f(-4)
EXPLANATION
When we check the value of -4 for both functions on the graph
f(-4) gives 3
g(-4) gives a number slightly greater than 1
Therefore f(-4)>g(-4)
solve the following equation for x..[tex]5x { }^{2} = 180[/tex]
The square root of 36 has 2 results, one positive and one negative.
[tex]\begin{gathered} x=\sqrt[]{36} \\ x=\pm6 \\ or \\ x_1=6\text{ and }x_2=-6\text{ } \end{gathered}[/tex]Pls look at Question and answer pls If it’s a compound then you will need to choose if it’s conjunctional, disjunction, conditional, or biconditional
Three statements are given. It is required to determine if the statements are simple or compound, and if it's compound, it is required to choose which type.
Recall that a simple statement is a statement containing no connectives like 'or', 'and', and so on.
Recall also that a compound statement is a combination of two or more simple statements which are joined by connectives.
Compound statements joined by 'or' are called disjunctions, while those joined by 'and' are called conjunctions.
Compound statements with 'if-then' are called conditional, while the ones with 'if and only if' are called biconditional.
a) The first statement is: My cousins each have some sort of engineering degree.
Since the statement is not joined by any connectives, it is a simple statement.
b) The second statement is: My eyes are bad or this print is tiny.
Since it is a combination of two simple statements joined by the connective 'or', then, it is a compound statement, which is a disjunction.
c) The third statement is: The cat will come to you if and only if you set well.
Since it is a combination of two simple statements joined by the connective 'if and only if ', it follows that it is a compound statement and it is a biconditional.
Can someone please help me solve the following?Please put numbers on graph
Given:
The equation of the hyperbola is given as,
[tex]\frac{y^2}{25}-\frac{x^2}{4}=1........(1)^{}[/tex]The objective is to graph the equation of the hyperbola.
Explanation:
The general equation of hyperbola open in the vertical axis of up and down is,
[tex]\frac{(y-h)^2}{a^2}-\frac{(x-k)^2}{b^2}=1\text{ . . . . . . . .(2)}[/tex]Here, (h,k) represents the center of the hyperbola.
The focal length can be calculated as,
[tex]c=\sqrt[]{a^2+b^2}\text{ . . . . (3)}[/tex]On plugging the values of a and b in equation (3),
[tex]\begin{gathered} c=\sqrt[]{5^2+2^2} \\ =\sqrt[]{25+4} \\ =\sqrt[]{29} \end{gathered}[/tex]The foci can be calculated as,
[tex]\begin{gathered} F(h,k\pm c)=F(0,0\pm\sqrt[]{29}) \\ =F(0,\pm\sqrt[]{29}) \end{gathered}[/tex]The vertices can be calculated as,
[tex]\begin{gathered} V(h,k\pm a)=V(0,0\pm5) \\ =V(0,\pm5) \end{gathered}[/tex]To obtain graph:
The graph of the given hyperbola can be obtained as,
Hence, the graph of the given hyperbola is obtained.
Determine the degree of the polynomial 2w with exponent of 2+ 2w:
The degree of the polynomial is 2, because the degree of a polynomial is defined as the same as the greater exponent on the polynomial.
In this case, w² is the greater, then the degree is 2.
How many real solutions does the equation \displaystyle -2x^2-6x+15=2x+5−2x 2 −6x+15=2x+5 have?
-2x² - 6x + 15 = 2x +5
Re-arrange the equation
-2x² - 6x -2x+ 15-5=0
-2x² -8x + 10 = 0
Multiply through by negative one
2x² + 8x - 10 =0
Now;
solve by factorization
Find two numbers such that its product give -20x² and its sum gives 8x and 8x by them
That is;
2x² + 10x - 2x - 10 = 0
2x(x+5) -2(x+5) = 0
(2x - 2) (x+5) = 0
Either 2x - 2 = 0
2x = 2
x= 1
Or
x+5 = 0
x=-5
Hence it has 2 real solutions
Which of the following represents the LCM of 98 ab^ 3 and 231 a^ 3 ?
The Least Common Multiple (LCM) for 98 and 231, notation LCM (98, 231), is 3234.
Solution by using the division method:
This method consists of grouping by separating the numbers that will be decomposed on the right side by commas while on the left side we put the prime numbers that divide any of the numbers on the right side. We starting with the lowest prime numbers, divide all the row of numbers by a prime number that is evenly divisible into 'at least one' of the numbers. We stop when it is no longer possible to divide (the the last row of results is all 1's). See below how it works step-by-step.
2 | 98, 231
3 | 49, 231
7 | 49, 77
7 | 7, 11
11 | 1, 11
1 | 1, 1
The LCM is the product of the prime numbers in the first column, so:
LCM = 2 . 3 . 7 . 7 . 11 = 3234
Solution by listing multiples:
This method consists of listing the multiples of all the numbers that we want to find the LCM. Multiples of a number are calculated by multiplying that number by the natural numbers 2, 3, 4, ..., etc. See below:
* The multiples of 98 are 98, 196, 294, 392, 490, 588, ..., 3234
* The multiples of 231 are 231, 462, 693, 924, 1155, ..., 3234
Because 3234 is the first number to appear on both lists of multiples, 3234 is the LCM of 98 and 231.
Hence the answer is The Least Common Multiple (LCM) for 98 and 231, notation LCM (98, 231), is 3234.
To learn more about LCM click here https://brainly.com/question/233244
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Which of the following numbers is irrational? (A)-1.325 (B)√8 (C)2 (D)4
Answer:
(B)√8
Explanation:
Irrational numbers are numbers which when converted to decimal can be written indefinitely without repeating.
Irrational Numbers are numbers that cannot be written as a terminating or repeating decimal.
Examples of Irrational Numbers are:
[tex]\sqrt{2},\text{ }\pi,\text{ }\frac{22}{7},\text{ }\sqrt{5}\text{, etc.}[/tex]From the given options, the number which is irrational is √8.
a vector w has initial point (0,0) and terminal point (-5,-2) write w in the form w=ai+bj
The initial point is (0,0) and the terminal point (-5,-2).
First, graph the points:
Lets say that A= (0,0) and B = (-5,-2)
So my vector w= line(AB)
Use the component form
Replace the values <-5-0, -2-0>
Then <-5,-2>
In the form w=ai+bj
w = -5i -2j
Looking at the graph we have -2 on the y-axis and -5 on the x-axis.
solve the equation1/4p-2/5=3/4p+7P=
Solve:
[tex]\frac{1}{4}p-\frac{2}{5}=\frac{3}{4}p+7[/tex]The LCM of the denominators is 4*5 = 20. So we multiply each term by 20 to eliminate denominators:
[tex]20\cdot\frac{1}{4}p-20\cdot\frac{2}{5}=20\cdot\frac{3}{4}p+20\cdot7[/tex]Operating:
[tex]5p-8=15p+140[/tex]Adding 8 and subtracting 15p:
[tex]5p-15p=8+140[/tex]Simplifying:
[tex]-10p=148[/tex]Dividing by -10:
[tex]p=\frac{148}{-10}[/tex]Simplifying:
[tex]p=-\frac{74}{5}[/tex]There were 55.5 million people enrolled in Medicare in 2015. In 2009, there were 46.6million enrolled. Which value best represents the unit rate of change (slope) in millions per year?a)-1.48b) 1.48c) 19.1%d) -0.674
Let the number of people enrolled in Medicare be represented by y
Let the year be represented by x
So that,
[tex]\begin{gathered} (x_1,y_1)=(2015,55.5\text{ million)} \\ (x_2,y_2)=(2009,46.6\text{ million)} \end{gathered}[/tex]The unit rate of change (slope) in millions per year can be calculated by:
[tex]\begin{gathered} slope=\frac{y_2-y_1}{x_2-x_1} \\ \text{Hence,} \\ slope=\frac{46.6million_{}-55.5million_{}}{2009_{}-2015_{}} \\ slope=\frac{-8.9}{-6} \\ slope=1.48 \\ \end{gathered}[/tex]Therefore, the unit rate of change in millions per year is 1.48 [Option B]
if -x - 3y = 2 and -8x + 10y = 9 are true equations, what would would be the value of -9x + 7y?
To find the value we add both equations:
[tex]\begin{gathered} (-x-3y)+(-8x+10y)=2+9 \\ -9x+7y=11 \end{gathered}[/tex]Therefore the value of the expression given is 11.
Solve the equation below 4X. If your answer is not a whole number enter it as a fraction in lowest terms, using the slash mark (/) as the fraction bar x-5=8x+9X=
Simplify the equation x - 5 = 8x + 9 to obtain the value of x.
[tex]\begin{gathered} x-5=8x+9 \\ x-8x=9+5 \\ -7x=14 \\ x=\frac{14}{-7} \\ =-2 \end{gathered}[/tex]So x = -2.
Which function could represent the height in feet, h, of a soccer ball t seconds after being kicked from an initial height of 1 foot?
Let h is the height of the ball after t seconds
The acceleration upward = -32 feet/sec.^2
This situation must be represented by a quadratic function
The form of the function is:
[tex]h=ut+\frac{1}{2}at^2+h_0[/tex]u is the initial velocity
a is the acceleration of gravity
t is the time
h0 is the initial height
From the given, the initial height is 1 foot
The acceleration of gravity is a constant value -32 ft/s^2
The initial velocity is unknown
Let us substitute the values given in the function
[tex]\begin{gathered} h=ut+\frac{1}{2}(-32)t^2+1 \\ h=ut-16t^2+1 \end{gathered}[/tex]Let us arrange the terms from greatest power of t
[tex]h=-16t^2+ut+1[/tex]We have only 1 function in the choices similar to our function
[tex]h=-16t^2+25t+1[/tex]The answer is the second choice
i need help with this question parts c d and e
ANSWER :
c. None
d. 0
e. (-1, 0)
EXPLANATION :
c. Values of x in which f(x) = -2
From the illustration, the graph does not pass through the y = -2
So there's NO values of x that will give f(x) = -2
d. Values of x in which f(x) = -3
From the illustration, when x = 0, f(x) will be -3
So the value of x is 0
e. x-intercepts are the points in which the graph intersects the x-axis.
In this case, the graph intersects at point (-1, 0)
Sketch the right triangle and find the length of the side not given if necessary approximate the light to the nearest thousandth
Let's take a look at our triangle:
Using the pythagorean theorem, we'll have that:
[tex]h^2=12^2+16^2[/tex]Solving for h,
[tex]\begin{gathered} h^2=12^2+16^2 \\ \rightarrow h=\sqrt[]{12^2+16^2} \\ \rightarrow h=\sqrt[]{400} \\ \\ \Rightarrow h=20 \end{gathered}[/tex]This way, we can conlcude that the missing side measures 20 units.
Name all the sets of numbers to which real number belongs: 6.5
Given the number 6.5
The number belongs to:
1) Rational Numbers because it can be written as a/b
RecommendationsSkill plansMathLE Language artsScienceSocial studiesDE TX StandaAlgebra 10.11 Solve a system of equations using elimination: word problems NHRYou have prizes to reveal! Go toWrite a system of equations to describe the situation below, solve using elimination, and fill inthe blanks.Students in a poetry class are writing poems for their portfolios. The teacher wants them towrite stanzas with certain numbers of lines each. Dan wrote 7 short stanzas and 6 longstanzas, for a total of 140 lines. Jim wrote 7 short stanzas and 2 long stanzas, for a total of84 lines. How many lines do the two sizes of stanzas contain?The short stanzas containlines and the long ones containlines.Submit
Answer:
Short stanzas contains 8 lines
Long stanzas contains 14 lines
Explanations:
Let the number of short stanzas be "x"
Let the number of long stanzas be "y"
If Dan wrote 7 short stanzas and 6 long stanzas, for a total of 140 lines, this is expressed mathematically as:
7x + 6y = 140 ............................ 1
Similarly, if Jim wrote 7 short stanzas and 2 long stanzas, for a total of
84 lines, this is expressed as:
7x + 2y = 84 ......................... 2
Solve both equations simultaneously using elimination method
7x + 6y = 140 ............................ 1
7x + 2y = 84 ......................... 2
Subtract both equations
6y - 2y = 140 - 84
4y = 56
y = 56/4
y = 14
Substitute y = 14 into equaton 1.
Recall that 7x + 6y = 140
7x + 6(14) = 140
7x + 84 = 140
7x = 140 - 84
7x = 56
x = 56/7
x = 8
This shows that the short stanzas contains 8 lines and the long ones contains 14 lines
How do you multiply 6x 1 1/3?
To multiply a mixed number, first, we have to convert it into a fraction as follows:
[tex]1\frac{1}{3}=\frac{1\cdot3+1}{3}=\frac{4}{3}[/tex]Now, we need to multiply 6 by 4/3, as follows:
[tex]6\cdot1\frac{1}{3}=6\cdot\frac{4}{3}=\frac{6\cdot4}{3}=\frac{24}{3}=8[/tex]xP(x)00.2510.0520.1530.55Find the standard deviation of this probability distribution. Give your answer to at least 2 decimal places
The Solution:
Given:
Required:
Find the standard deviation of the probability distribution.
Step 1:
Find the expected value of the probability distribution.
[tex]E(x)=\mu=\sum_{i\mathop{=}0}^3x_iP_(x_i)[/tex][tex]\begin{gathered} \mu=(0\times0.25)+(1\times0.05)+(2\times0.15)+(3\times0.55) \\ \\ \mu=0+0.05+0.30+1.65=2.0 \end{gathered}[/tex]Step 2:
Find the standard deviation.
[tex]Standard\text{ Deviation}=\sqrt{\sum_{i\mathop{=}0}^3(x_i-\mu)^2P_(x_i)}[/tex][tex]=(0-2)^2(0.25)+(1-2)^2(0.05)+(2-2)^2(0.15)+(3-2)^2(0.55)[/tex][tex]=4(0.25)+1(0.05)+0(0.15)+1(0.55)[/tex][tex]=1+0.05+0+0.55=1.60[/tex]Thus, the standard deviation is 1.60
Answer:
1.60
the ratio of the cost price to selling price is 8:9 . If the cost price of the power generator is 8500 what is the selling price?
The price of hamburger increased from .50 cent to .60 cent. What is the percent increase
The hamburguer was .50 cent and increased to 0.60 cent. Let's calculate the percent increase:
The percent increase may be calculated using the formula:
percent increase = [(final value - initial value)/initial value]*100
So:
[tex]\begin{gathered} \frac{0.6-0.5}{0.5}\cdot100= \\ \frac{0.1}{0.5}\cdot100= \\ 0.2\cdot100=20 \end{gathered}[/tex]So, the percent increase was 20%
2 2. 8 friends are going on a camping trip. 5 friends own a sleeping bag. How many friends need a sleeping bag? + Il8-5=3
If 8 friends go camping and only 5 friends have sleeping bag
Then of the 8 friends, the number that need a sleeping bag would be
= 8 - 5
= 3
Hence 3 friends will be in need of a sleeping bag
Suppose that E and F are independent P(E) = 0.8 and P(F) = 0.4What is P(E and F)?
Answer:
P(E and F) = 0.32
Explanation:
Given that E and F are independent, then
P(E and F) is the multiplication of P(E) and P(F).
P(E) = 0.8, and P(F) = 0.4
P(E and F) = 0.8 * 0.4 = 0.32
using trig to find a side
we have that
tan(16)=NO/OM -------> by opposite side divided by the hypotenuse
solve for NO
NO=OM*tan(16)
x=16*tan(16)
x=4.6 ftMacy is hosting a party to celebrate her son's baptism. There will be 6 children at the
party. Each child will receive 1/3 of a regular size adult portion. How many full adult
portions will be made to feed the 6 children?
Answer:
2
Step-by-step explanation:
three 1/3 makes a whole and there are 6 children so 3 and 3 is 6 so its 2
Find an equation of the line that has a slope of -1 and a y intercept of 2. Write your answer in the formy = mx + b.
Based on the information the equation would be:
y = -1x + 2
m=slope
b= y-intercept
When graphing an inequality in slope-intercept form, which of the folowing indicates that you have to shade ABOVE the boundary line? Select ALL that apply.
Explanation
When graphing an inequality in slope-intercept form, we are asked to find which of the folowing indicates that you have to shade ABOVE the boundary line. This can be seen below.
The symbols
[tex]>\text{ and }\ge[/tex]Indicates that one should shade above the boundary line, The only difference is that the boundary line is broken in the case of greater than and unbroken in the case of greater than or equal to.
Answer:
[tex]>\text{ and }\ge[/tex]
A Use the information given to answer the question. A student works at a job in order to save money to buy a desktop computer. • The student works 80 hours each month. • The desktop computer costs $850. Part B If the student has already saved $150 and plans to save an additional $100 each week, the function g(w) = 100w + 150 represents the total amount of money, in dollars, saved after w weeks. What is the value of g(5)?
The function given is:
[tex]g\mleft(w\mright)=100w+150[/tex]Where
w represents the week
g(w) represents the total money
We want to fing g(5).
This means, put "5" into the function g.
Put "5" in place of "w" in the function g.
Shown below:
[tex]\begin{gathered} g(w)=100w+150 \\ g(5)=100(5)+150 \\ g(5)=500+150 \\ g(5)=650 \end{gathered}[/tex]