Use a 30 - 60 - 90 triangle to find the tangent of 60 Degrees

Use A 30 - 60 - 90 Triangle To Find The Tangent Of 60 Degrees

Answers

Answer 1

Let's put more details in the given figure to better understand the solution:

Let's now determine the Tangent of 60 degrees:

[tex]\text{ Tangent (60}^{\circ})\text{ = }\frac{\text{ Opposite}}{\text{ Adjacent}}[/tex][tex]\text{ = }\frac{\text{ }\sqrt[]{3}}{1}[/tex][tex]\text{ Tangent (60}^{\circ})\text{ = }\sqrt[]{3}[/tex]

Therefore, the tangent of 60 degrees is √3.

The answer is Option 1 : √3

Use A 30 - 60 - 90 Triangle To Find The Tangent Of 60 Degrees

Related Questions

Write a quadratic inequality represented by the graph.

Answers

The quadratic inequality represented by the graph is y > -x².

What is meant by quadratic inequality?

Simply put, an equation of the type with the highest degree of two and no equal sign is known as a quadratic inequality. There is a technique for resolving quadratic inequalities called the wavy curve approach. It is the same to solve quadratic equations as it is solving quadratic inequalities. When plotted, quadratic inequalities show a parabola, much like quadratic equations do. Quadratic inequalities can be solved to provide a variety of solutions. For instance, the quadratic equation x²+6x+5=0 has two solutions: x² + 6 x + 5 = 0 and x² + 6x + 5 = 0. A second-degree equation with a quadratic inequality substitutes an inequality sign for an equal sign. The quadratic inequalities x- 6x - 16 0, 2x² - 11x + 12 > 0, x² + 4> 0, and x² - 3x + 20 are some examples.

From the graph, we can see that it is a parabola with vertex points (0,-9)

Thus, y= -3² is the equation at the vertex and the equation of the parabola will be y= -x².

The graph is an increasing function, so the inequality will be

y > - x²

To know more about quadratic inequality, visit:

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10 Students share 1 hour to give their science reports

Answers

Answer:

1/10

Explanation:

If 10 students share 1 hour, we need to divide 1 hour into 10 students. So, the fraction is

[tex]\frac{1\text{ hour}}{10\text{ students}}=\frac{1}{10}[/tex]

It means that each student has 1/10 hour to give the science report.

A bag contains:• 3 red marbles• 2 orange marbles• 1 yellow marble• 4 green marblesRico will randomly choose a marble. Then he will put itback and randomly choose another marble. What isthe probability that he will choose a red and then anorange marble?

Answers

The probability is given by the following formula:

Probability = number of favorable outcomes / total number of outcomes

The total number of outcomes is 10, 3 of the initial number of marbles are red and 2 of them are orange.

The probability of getting a red marble in the first draw is:

Probability = 3/10

The probability of getting an orange marble in the second draw is:

Probability = 2/10 = 1/5

the probability that he will choose a red and then an orange marble can be calculated by multiplying the probabilities that we found, then we get:

Probability = 3/10 × 1/5 = 3/150 = 1/50

Then, the answer is 1/50

Triangle ABC shown below has m B = 38°, a = 8, and c = 16. Find the area of the triangle. Round your answer to the nearest tenth and do not include units in your answer.

Answers

The area of triangle is determined as

[tex]A=\frac{1}{2}a\times c\times\sin B[/tex][tex]A=\frac{1}{2}\times8\times16\times\sin 38=64\sin 38^{\circ}[/tex][tex]A=39.4\text{ squnit}[/tex]

Thus the area of triangle is 39.4 sq.unit.

A system of equations is given below.x + 2y = 24x − 5y = 8Identify the constant that can be multiplied by both sides of the first equation to eliminate the variable x when the equations are added together.thenWrite the revised system of equations.

Answers

Answer:

[tex]constant\rightarrow-4[/tex]

Explanation: We have to find the constant that when multiplied to the first equation and added to the second, the variable x gets canceled out, the two equations are as follows:

[tex]\begin{gathered} x+2y=2\rightarrow(1) \\ 4x-5y=8\rightarrow(2) \end{gathered}[/tex]

Multiplying the equation (1) by -4 and adding it to the equation (2) gives the following answer:

[tex]\begin{gathered} -4\times(x+2y)=-4\times2\rightarrow-4x-8y=-8 \\ \begin{equation*} -4x-8y=-8 \end{equation*} \\ + \\ \begin{equation*} 4x-5y=8 \end{equation*} \\ ---------------------- \\ -3y=0 \end{gathered}[/tex]

Therefore the value of the constant is -4.

Write the equation to represent the following relationship. y varies inversely with x. When y = 4, x = 3.

Answers

EXPLANATION

The relationship that represents the equation is the following:

[tex]y=\frac{k}{x}[/tex]

Plugging in x=3 and y=4 into the equation:

[tex]4=\frac{k}{3}[/tex]

Multiply 3 to both sides:

[tex]3*4=k[/tex]

Multiplying numbers:

[tex]12=k[/tex]

Switching sides:

[tex]k=12[/tex]

Therefore, the equation is the following:

y= 12/x

Find the difference. (10m+ 3) - (4m-2) O A. 14m-1 OB. 6m+ 5 O C. 6m-1 D. 14m + 5

Answers

(10m + 3) - (4m -2)

Firstly, use the negative sign to open the parenthesis

(10m + 3) -1 x 4m -1 x (-2)

minus x minus = plus

(10m + 3) -4m + 2

10m + 3 - 4m + 2

Collect the like terms

10m - 4m + 3 + 2

m(10-4) + 5

m(6) + 5

6m + 5

The answer is OPTION B

Given `lim_(x -> 2) 2x - 3 = 1`, use the formal definition of a limit to find the value of δ that corresponds to ε = 0.3.

A. 0.05
B. 0.15
C. 0.30
D. 0.50

Answer: B. 0.15

Your Welcome :)

Answers

Answer: B. 0.15 thats the closest to it

Given the definitions of f(x) and g(x) below, find the value of g(f(-2)). f(x) = 5x + 4 g(x) = x^2 - 6x - 13

Answers

f(-2) = 5(-2) + 4

= -10 + 4

= -6

g(f(-2))

= -6^2 -6*-6 -13

= 36 + 36 - 13

= 59

If f(1) = 2 and f(n) = f(n - 1)^2 – 5 then find the value of f (4).

Answers

We are asked to calculate f(4) by means of the following function:

f(n) = f(n - 1)² - 5

As you can see, in order to calculate f(n) first we have to specify the value of f(n - 1), we are given the value of f(1), so we can calculate the value of f(2), then f(3) and finally f(4), like this:

f(2) = f(2-1)² - 5 = f(1)² - 5 = 2² - 5 = 4 - 5 = -1

Then, f(2) = -1, now we can calculate f(3) like this:

f(3) = f(3 - 1)² - 5 = f(2)² - 5 = (-1)² - 5 = -4

Then f(3) = -4, now we can calculate f(4) like this:

f(4) = f(4 - 1)² - 5 = f(3)² - 5 = (-4)² - 5 = 16 - 5 = 11

Then, f(4) equals 11

Use a graphing utility to find or to approximate the x-intercepts of the graph of the function.y=3x2−8x+

Answers

Answer:

The x-intercepts are x = 0.6667, 2

Explanation:

The graph of the function y = 3x² - 8x + 4 is:

Then, the x-intercepts are the points where the graph crosses the x-axis.

So, an approximation for the x-intercepts are x = 0.6667 and x = 2

Therefore, the answer is:

The x-intercepts are x = 0.6667, 2

Learning Diagnostic Analytics Recommendations Skill plans Social stu La Language arts All Science Math Eighth grade ) T.11 Volume of cones YYR A cone has a height of 14 meters and a diameter of 12 meters. What is its volume? Use A 3.14 and round your answer to the nearest hundredth. cubic meters Submit

Answers

The volume of a cone is calculated as follows:

[tex]V=\pi\cdot r^2\cdot\frac{h}{3}[/tex]

where r is the radius and h is the height of the cone.

Given that the diameter of the cone is 12 meters, then its radius is 12/2 = 6 meters

Substituting into the equation with h = 14 m, and r = 6 m, we get:

[tex]\begin{gathered} V=3.14\cdot6^2\cdot\frac{14}{3} \\ V=3.14\cdot36\cdot\frac{14}{3} \\ V=527.52m^3 \end{gathered}[/tex]

In order to pass a science lab, you have to measure a beaker (container) of water with 5% error or less. The beaker has 12 ounces of water in it. You measure 13.2 ounces of water. Did you pass the lab? Why or why not?

Answers

Data:

Error: 5%

Volume of water in the Beaker: 12oz

Your measure: 13.2oz

As the error is 5% it means that the measure can be actually 5% more or 5% less.

Then, you calculate the 5% of the measure you have to measure: 12oz

[tex]12\cdot\frac{5}{100}=0.6oz[/tex]

Then, the measure you need to take to pass the lab is between: 11.4oz and 12.6oz

[tex]12oz\pm0.6oz[/tex][tex]\begin{gathered} 12oz+0.6oz=12.6oz \\ 12oz-0.6oz=11.4oz \end{gathered}[/tex]

Then, your measure of 13.2oz is not between the 5% of error. You didn't pass the lab.

Kiran read for x minutes, and Andre read 5/8 more than that. Write an equation that relates the number of minutes Kiran read with Y ,the number of minutes Andre read. "Use decimals in the equation.DO NOT ROUND"

Answers

The time for which Kiran read is x minutes.

Determine the time for which Andre read.

[tex]\begin{gathered} Y=x+\frac{5}{8}\cdot x \\ =x+0.625x \\ =\text{1}.625x \end{gathered}[/tex]

Thus answer is Y = 1.625 x.

-7.9 cm 26.2 cm 6.2 cm 19.1 cm 2.8 cm The perimeter of the figure is (Type a whole number or a decal.) .

Answers

ANSWER

The perimeter is 81.5 cm

EXPLANATION

The perimeter of any polygon is the sum of the length of its sides. The perimeter of this figure is:

[tex]P=7.9+26.2+6.2+22.8+18.4=81.5\operatorname{cm}[/tex]

9(m - 3) + 3m = 7m + 43

Answers

[tex]\begin{gathered} 9(m-3)+3m=7m+43 \\ \text{Multiply the parenthesis by 9 and you have} \\ \\ (9\times m-9\times\lbrack-3\rbrack)+3m=7m+43 \\ \text{Next you have} \\ 9m-27+3m=7m+43 \\ \text{Note that the 9 multiplies the m to get 9m,} \\ \text{and the 9 also multiplies the negative 3 to arrive at negative 27.} \\ \text{After applying 9 to open the parenthesis, you now have } \\ 9m-27+3m=7m+43 \\ \text{You collect like terms. In this case all expressions that have m are like terms} \\ \text{The ones that does not have m are also like terms but, separate} \\ \text{Collect like terms with m on to the left hand side} \\ 9m+3m-7m=43+27 \\ \text{Note that whenever a positive number moves over across the sign of equality,} \\ it\text{ becomes a negative number and vice versa.} \\ \text{Hence 7m has moved and now becomes -7m} \\ \text{Also -27 has moved and now becomes +27} \\ 9m+3m-7m=43+27 \\ 5m=70 \\ \text{Divide both sides by 5 to eliminate it from the left side} \\ \text{and hence m would now stand alone} \\ \frac{5m}{5}=\frac{70}{5} \\ m=14 \end{gathered}[/tex]

A quality control worker at a factory selects the first 10 items she sees as her sample for the day.What type of sample is this?

Answers

This is a convinience sample because the first 10 items are easy to select.

Each person has two parents, four grandparents, eight great-grandparents, and so on. What is the total number of ancestors a person has, going back five generations? twelve generations?

Answers

62

8190

1) Gathering the data:

So Adding the 2 + 4 +8 +16+32 Then we can write that up to the 5th generation each person has 62 ancestors.

2) Or we can check. Let's write out considering that the ratio is 2 and the first term is 2 since the person per se is not counted.

[tex]\begin{gathered} S=\frac{a_1(1-r^n)}{1-r} \\ S_5=\text{ }\frac{2(1-2^5)^{\square}}{1-2}=62 \\ S_{12}=\frac{2(1-2^{11})}{1-2}=8190 \end{gathered}[/tex]

3) Hence, each person has counting back up to the 5th generations 62 ancestors and 4094 when it comes to 11 generations

Hello am I correct, if not can you help me understand?

Answers

total kilometer of journey = 353miles

she stopped at mile 36

This statics question has me stumped if you could hope me I would rlly appreciate it! Have a nice night :).

Answers

Spinner A

Sample space = 1,2,3,4,5,6

Number of total outcome = 6

Odd numbers = 1,3,5

Number of odd numbers = 3

[tex]\text{Probability = }\frac{n\text{umber of required outcomes}}{\text{total number of possible outcome}}[/tex]

Probability of spinning an odd number = 3/6 = 1/2

Spinner B

Sample space = yellow, brown, red

Number of total outcome = 3

Not yellow = brown, red

Number of not yellow = 2

Probability of not yellow = 2/3

Since the two spinners are independent events, then the probability that you spin an odd number and not yellow are multiplied together

Thus we have,

Probability of spinning an odd number X Probability of not yellow

[tex]\frac{1}{2}\text{ X }\frac{2}{3}\text{ = }\frac{2}{6}[/tex]

Final answer is 1/3.

Train A travels 30 miles in 20 minutes at a constant speed. Train B travels 20 miles in 15 minutes at a constant speed. Redo Which train is going faster? Circle your answer and show how you figured it out below, Train A Train B

Answers

[tex]\begin{gathered} \text{Train A}\Rightarrow\frac{30\text{ miles}}{20\text{ minute}}=1.5\text{ miles/minute} \\ \text{ Train B}\Rightarrow\frac{20\text{ miles}}{15\text{ minute}}=1.34\text{ miles/minute} \\ \text{The train A is going faster.} \end{gathered}[/tex]

The product of 5 – 2i and i is1) 72) 2 + 5i3) 5 – 2i4) -2 + 5i

Answers

Answer:

2) 2 + 5i

Explanation

Fom the given question, we are find the product of 5-2i and i

i(5-2i)

Expand

= 5i - 2(i^2)

From complex number i^2 = -1

Substitute

= 5i - 2(-1)

= 5i + 2

= 2 + 5i

Hence the product is 2 + 5i

Solve the equation.g−37=27g− 73 = 72 g, minus, start fraction, 3, divided by, 7, end fraction, equals, start fraction, 2, divided by, 7, end fractiong=g=g, equals

Answers

ANSWER

[tex]\text{ g = }\frac{5}{7}[/tex]

EXPLANATION

We want to solve for g in:

[tex]g\text{ - }\frac{3}{7}=\frac{2}{7}[/tex]

Collect like terms by moving 3/7 to the right hand side:

[tex]\begin{gathered} g\text{ = }\frac{2}{7}+\frac{3}{7} \\ \Rightarrow\text{ g = }\frac{5}{7} \end{gathered}[/tex]

For a winter-themed Valentine's Day party, Mr. Rivera made 12 cups of hot chocolate. Does he have enough hot chocolate to give 26 kids 1/2 of a cup each?

Answers

Multiply the number of kids by the number of cups for each kid. This is 26 times 1/2.

[tex]26\cdot\frac{1}{2}=\frac{26}{2}=13[/tex]

It means 13 cups are needed to give each of the 26 kids 1/2 of a cup of chocolate.

Mr. Rivera does not have enough hot chocolate to give 26 kids 1/2 of a cup of chocolate.

The data are at the ordinal level of measurement.What is wrong with the given calculation?Identify the level of measurement of the data, and explain what is wrong with the given calculation.In a set of data, blood lead levels are represented as 10 for low, 20 for medium, and 30 for high. The average (mean) of the 595 blood lead levels is 25.4.A. One must use a different method to compute the average (mean) of such data.B. Such data should not be used for calculations such as an average (mean).C. The true average (mean) is 18.2.D. There is nothing wrong with the given calculation.

Answers

Answer: Blood lead levels are represented as 10 for low, 20 for medium, and 30 for high.

The average (mean) of the 595 blood lead levels is 25.4, assuming that each blood lead level is also known, then:

[tex]A=\frac{\sum_i^{595}x_i}{595}=25.4\Rightarrow\text{ Average}\rightarrow(1)[/tex]

As (1) is the perfectly reasonable mathematical approach to calculating the average, however, the blood lead levels are reported in 10 20 30 levels only, therefore, the answer is:

[tex]\text{ Such data should not be used for calculations such as an average \lparen mean\rparen}\Rightarrow\text{ Option\lparen B\rparen}[/tex]

Or the Option(B).

Customers can pick their own blueberries at Blueberry Hill. They pay $5 toenter the patch and $4 per pound for the blueberries they pick. Write anequation to model the total cost, y, for x pounds of blueberries.

Answers

SOLUTION

Step1; Write out the parameters

[tex]\begin{gathered} \text{entry fe}e=\text{ \$5} \\ \cos t\text{ of blueberries per pound=\$4} \end{gathered}[/tex]

Step2: Write out the variables

[tex]\text{let y=total cost and x=number of bluerries}[/tex]

Step3: write out the model

[tex]\begin{gathered} \text{The total cost=number of blueberries}\times\text{\$}4+\text{ the entry fe}e \\ y=4x+5 \end{gathered}[/tex]

There

Convert the Fahrenheit temperature to the equivalent Celsius temperature round to 1 decimal Places if necessary

Answers

Given

[tex]19^0F[/tex]

To convert the given to Celsius

Solution

The formula connecting Fahrenheit and degree Celsius is given as

[tex]\begin{gathered} =\frac{5(F-32)^{}}{9} \\ =\frac{5(19-32)}{9} \\ =\frac{5(-13)}{9}=-7.222^0C \end{gathered}[/tex]

Hence

19⁰F = -7.2⁰C

Need help with this exercise. It’s from a review the real test is next week need more explanation so I already know what to do on the test.

Answers

ANSWER

Options 1 and 4

EXPLANATION

First, let us find the length of the third side of the right triangle. To do this apply the Pythagoras theorem.

Let the length of the third side of the triangle be x.

It implies that:

[tex]\begin{gathered} x^2+8^2=17^2 \\ x^2=17^2-8^2 \\ x^2=289-64=225 \\ x=\sqrt[]{225} \\ x=15 \end{gathered}[/tex]

Now, we can find the value of sinA, tanA, and sinC.

According to trigonometric ratios, SOHCAHTOA, we have that:

[tex]\begin{gathered} \sin A=\frac{\text{opposite}}{\text{hypotenuse}} \\ \tan A=\frac{\text{opposite}}{\text{adjacent}} \\ \sin C=\frac{\text{opposite}}{\text{hypotenuse}} \end{gathered}[/tex]

Therefore:

[tex]\begin{gathered} \sin A=\frac{15}{17} \\ \tan A=\frac{15}{8} \\ \sin C=\frac{8}{17} \end{gathered}[/tex]

Hence, the correct options are options 1 and 4.

Allen is choosing a 2 letter password from the letters ABCD. the password cannot be the same letter repeated in it .how many such passwords are possible?

Answers

Since we can choose 2 letters and they can not be the same, we have the following possibilities:

[tex]{}\lbrace AB,AC,AD,BC,BD,BA,CB,CA,CD,DA,DB,DC\rbrace[/tex]

As we can note, there are 12 possible combinations of 2 different letters. So, How many such passwords are possible?​ The answer is 12 passwrods

I need help with this questionthe question to this question is below is a graph of a logarithmic function, identify it key characteristics. match accordingly

Answers

The answers to the problem :

[tex]\begin{gathered} 1.\text{ Domain : x >-6} \\ 2\text{ Range : -}\infty\text{ to +}\infty \\ 3.\text{ Aymptote : x = -6} \\ 4\text{. Transformation : left 6, down 1} \\ 5.\text{ End behaviour : As x approaches }\infty,\text{ f(x) approaches }\infty.\text{ As x approaches -6, f(x) approaches -}\infty \\ 6.\text{ x-intercept : (-4,0)} \end{gathered}[/tex]

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