Answers
Answer:
it’s the last one chemical covered to mechanical
Explanation:
asked my science teacher to make sure it’s correct
Related Questions
Gamma rays require _____ to be stopped.1) paper2) glass3) aluminum4) lead
Answers
The gamma rays are having very large frequency. Thus, the energy acquired by the gamma ray photons is very large.
To stop the gamma ray, highly dense material is required.
The density of the lead is more than any other element in the given opitons.
Thus, the lead is used to stop the gamma rays.
Hence, 4th option is the correct answer.
Describe the cause of waves as a fluid motion
Answers
Wind is the most frequent cause waves. The friction between the wind and the surface of the water produces wind-driven waves, also known as surface waves. A wave crest is produced when wind continuously disturbs the water's surface in an ocean or lake.
Waves that include longitudinal and transverse motions include water waves, for instance. The particles move in clockwise rings through the waver as a wave passes over it. The circles' radius gets smaller the deeper into the ocean you go.The disturbance propagates through the medium as a result of the medium's particles oscillating repeatedly and periodically about their equilibrium position. Without any real transfer of the medium's particles, energy and momentum are moved from one place to another.To know more about waves
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Two skaters with the same mass face each other standing still. Both skaters push off each other and they love in opposite directions. What’s the momentum before pushing off? Total momentum after pushing off? Momentum of each in comparison to each other after pushing off
Answers
We will have the following:
Total momentum before pushing each other off: 0.
Total momentum after pushing each other off: 0.
Momentum of each other after pushing off in comparison to each other:
*Person 1: A positive value.
*Person 2: A negative value of equal magnitude to the momentum of person 1.
This week we discuss injuries to the head, neck and spine. There are so many long term affects of so many different head injuries. One of the biggest changes to head injuries that we have seen in the last decade is the implementation of concussion protocol. No matter the age or activity, the medical world has a recommended protocol for possible concussions and any head injury.
This weeks assignment. Research concussion protocol and submit the following in a written paper format.
-What is a concussion?
-Why do we need to have a concussion protocol?
-Who needs a concussion protocol? This is in regards to caring for injuries, not the injured person itself,
-Is there a standard concussion protocol should you follow? What is it?
-At a minimum, concussion protocol steps should include the what people in the process?
-Have you or anyone you know had to follow concussion protocol for a head injury? Tell me about it.
This is due Sunday I want to get started on it please someone help me ?
Answers
Answer:
Concussion is the most common type of mild traumatic brain injury and can have serious consequences
Explanation:
A spring stores 68 J of potential energy when it is stretched by 6 cm. What is the spring constant?
Answers
The formula for calculating the elastic potential energy is expressed as
Elastic potential energy = 1/2kx^2
where
k represents the spring constant
x represents the compression or distance by which the spring was stretched.
From the information given,
Elastic potential energy = 68
x = 6 cm
we would convert 6 cm to m. Recall,
100cm = 1 m
6 cm = 6/100 = 0.06 m
By substituting these values into the formula, we have
68 = 1/2 x k x 0.06^2
68 = 0.0018k
k = 68/0.0018
k = 37777.78 N/m
The spring constant is 37777.78 N/m
A turkey with a mass of 9kg is running straight at you with a velocity of 5 m/s.What is the momentum of the turkey?
Answers
Given,
The mass of the turkey, m=9 kg
The velocity of the turkey, v=5 m/s
The momentum of a body is given by the product of the mass of the body and its velocity.
Thus the momentum of the turkey is given by,
[tex]p=mv[/tex]On substituting the known values,
[tex]p=9\times5=45\text{ kg}\cdot\frac{m}{s}[/tex]Thus, the momentum of the turkey is 45 kg·m/s
i’m a really confused on what to do the teacher didn’t really explain it well so i’m clueless on what to do..
Answers
ANSWER:
0, no direction
balanced
STEP-BY-STEP EXPLANATION:
We must add all the forces, the horizontal and vertical.
We must take into account the direction of the force, to the right and up are positive while to the left and down are negative.
Therefore:
[tex]\begin{gathered} F_{Rvertical}=F_n+F_g=20+(-20)=20-20=0 \\ F_{\text{Rhorizontal}}=F_{\text{app}}+F_{\text{fric}}=20+(-20)=20-20=0 \end{gathered}[/tex]Being the vertical and horizontal forces 0, the net force is 0 as it has no magnitude and no direction.
It is balanced, since the net force is 0
Lorem ipsum dolor sit amet, consectetur adipiscing elit, sed do eiusmod tempor incididunt ut labore et dolore magna aliqua. Ut enim ad minim veniam, quis nostrud exercitation ullamco laboris nisi ut aliquip ex ea commodo consequat.
Answers
Here is the answer of a tutor
Take a look.
[tex]\sqrt[2]{24+5}[/tex]When you describe a metal surface as smooth, what property are youdescribing?7O A. ColorO B. HardnessO C. ShapeO D. TextureSUBMIT
Answers
Answer: D. Texture
Explanation:
Texture is used to describe the characteristics of a surface. A surface can be described as smooth or rough. Thus, the correct option is
D. Texture
A cyclist advances 38 km in 1 hour and 30 minutes. Your average speed was: Select one: 47 0 25.3 km/h OR 22 km/h OR 18 km/h OR 38 km/h
Answers
Hello..!
We initially apply the data to the problem.
Data:
D = 38kmT = 1.5hV = ?Then, we apply the formula that is.
Formula:
V = D/TFinally we develop the problem.
Developing:
V = 38km / 1.5hV = 25.3km/hTherefore the correct option is 25.3 kilometers per hour.
Answer:
Formula
V = d/tResolve
V = 38km / 1.5hV = 25.3 km/hHope this helped
Abby, who has a mass of 45.0 kg, is riding at 40.0 m/s in her red sports car whenshe must suddenly slam on the brakes to avoid hitting a deer crossing the road. Shestrikes the air bag, that brings her body to a stop in 0.500 s. What average forcedoes the seat belt exert on her?
Answers
We are given the following information
Mass = m = 45.0 kg
Initial speed = vi = 40.0 m/s
Time = t = 0.500 s
We are asked to find the average force that the seat belt exerted on her.
Recall from Newton's second law of motion,
[tex]F=m\cdot a[/tex]Where a is the acceleration of the car and is given by
[tex]v_f=v_i+a\cdot t[/tex]Where vf is the final velocity of the car that must be 0 since the car was stopped.
[tex]\begin{gathered} 0=40.0+a\cdot0.500 \\ a=\frac{-40.0}{0.500} \\ a=-80\; \; \frac{m}{s^2} \end{gathered}[/tex]The negative sign indicates deacceleration since the card was stopped.
So, the force is
[tex]\begin{gathered} F=m\cdot a \\ F=45\cdot80 \\ F=3600\; N \end{gathered}[/tex]Therefore, the seat belt exerted a force of 3600 N on her.
1. what is the range of the infrared part of the electromagnetic spectrum A.microwaves to red light B.radio waves to microwavesC. X-rays to gamma raysD. ultraviolet to x-rays
Answers
The range of the infrared wave is from the red to the microwave.
the rannge of wavelength of the infrared is ,
[tex]2-14\mu m[/tex]Hence, A is the correct option.
A strobe-light series of pictures is taken of a red ball and a blue ball. The red ball was allowed to drop straight down, and the blue ball was given an initial horizontal velocity. Lines are drawn connecting each red ball image with the corresponding blue ball image. Describe the lines connecting the images.1) The lines slope down from the red ball to the corresponding blue ball.2) The lines slope up from the red ball to the corresponding blue ball.3) The lines are vertical.4) The lines are horizontal.
Answers
The lines are horizontal.
Horizontal velocity doesn't have any effect on the acceleration or speed of falling. In every picture, the red and the blue are both at the same HEIGHT, even though the blue one is pulling away horizontally.
I need to know how to do these and the formula too.
Answers
Answer:
a = 4m kgm/s & b. v = 4 m/s
Explanation:
a:
A is approaching in the opposite direction of B
So let's take the velocity of A as negative.
Here we'd need to solve this using conservation of momentum.
m1u1 + m2u2 = m1v1 + m2v2
So initial momentum = (m X (-4)) + (m X 8) = -4m + 8m = 4m
b:
After collision sphere A stops, so v = 0 for sphere A
Using the conservation of momentum formula, we get
(m X (-4)) + (m X 8) = (0 X m) + (m X v) [let the final velocity of B be v]
⇒ 4m = vm
⇒ v = 4 m/s
What happens to Centripedal force on the planet around a star if the radius of an orbit is doubled ? assume that velocity remains the same A) the Centripedal force will be half of its original value B) the Centripedal force will be double its original value C) the Centripedal force will be 1/4 of its original value D) the Centripedal force will not change
Answers
We will have the following:
We know that:
[tex]F_c=\frac{mv^2}{r}[/tex]If we double the radius, then:
[tex]F_c=\frac{mv^2}{(2r)}\Rightarrow F_c=\frac{1}{2}\frac{mv^2}{r}[/tex]So, the centripetal force will be half of its original value. [Option A]
What percentage of the speed of light in vacuum is the speed of light in a diamond? Incorrect: Your answer is incorrect. answer in:_____%
Answers
Explanation
Step 1
find the speed of ligth in the diamond:
to do that we can use the formula
[tex]refractive\text{ index\lparen}\mu)=\frac{c(\text{ speed of light in vaccum\rparen}}{s(\text{ speed of light in the material\rparen}}[/tex]we know that :
[tex]\begin{gathered} refractive\text{ index of diamond\lparen}\mu)=2.42 \\ speed\text{ of llight in the vaccum=c=300000 }\frac{km}{s} \end{gathered}[/tex]so, replace and solve for speed of light in the diamond
[tex]\begin{gathered} refractive\text{ index\lparen}\mu)=\frac{c(\text{ speed of light in vaccum\rparen}}{s(\text{ speed of light in the material\rparen}} \\ 2.42=\frac{3*10^5\frac{km}{s}}{s} \\ s=\frac{3\times10^5\frac{km}{s}}{2.42} \\ s=123966.9\text{ }\frac{km}{s} \\ \end{gathered}[/tex]finally, to find the percentage apply this formula
[tex]\begin{gathered} \text{ \% }=\frac{speed\text{ of light in diamond}}{spped\text{ of ligth invaccum}}*100\text{ \%} \\ replace \\ \text{ \%=}\frac{123966.9\frac{km}{s}}{3*10^5\frac{km}{s}}*100\text{ \%} \\ \text{ \%=0.413*100\%} \\ \text{ \%=41.3 \%} \\ rounded\text{ 41\%} \end{gathered}[/tex]so, the answer is
41 %
I hope this helps you
Match each expression on the left with an equivalent expression on the right. Some answer choices on the right will not be used.1/50.451/80.6259/203/40.1250.24/55/8
Answers
1/5 = 0.2
1/8 = 0.125
9/20 = 0.45
3/4 = 0.75
4/5 = 0.8
5/8 = 0.625
Explanations:This exercise is to convert the given fractions to decimals
Let us find the decimal equivalents of each of the fractions first, then the equivalent choices can be matched together
1/5 = 0.2
1/8 = 0.125
9/20 = 0.45
3/4 = 0.75
4/5 = 0.8
5/8 = 0.625
A closed-pipe resonator is closed at both ends. Is this true or false?
Answers
A closed cylinder air column must have a closed end and an open end.
Then, the answer is:
[tex]\text{False}[/tex]An aluminum sphere is 8.55 cm in diameter. What will be it's % change in volume if it is heated from 30 C to 155 C?
Answers
We know that
• The sphere diameter is 8.55 cm.
,• The temperature change is from 30 C to 155 C.
First, we have to find the radius of the sphere. The radius is the half diameter.
[tex]\begin{gathered} r=\frac{d}{2}=\frac{8.55\operatorname{cm}}{2} \\ r=4.275\operatorname{cm} \end{gathered}[/tex]Now we have to find the volume of the sphere using the following formula.
[tex]V=\frac{4}{3}\pi(r)^3[/tex]Where r = 4.275 cm.
[tex]\begin{gathered} V=\frac{4}{3}\pi(4.275\operatorname{cm})^3 \\ V\approx327.26(cm)^3 \end{gathered}[/tex]Then, we use the following formula
[tex]V_2-V_1=BV_0(T_2-T_1)[/tex]Where the initial volume is 327.26 cubic cm, B is a constant about thermal expansion for aluminum, and we have to find the final volume to then calculate the percentage change.
[tex]\begin{gathered} \Delta V=75\times10^{-6}\cdot327.26(155-30) \\ \Delta V=75\times10^{-6}\cdot327.26(125) \\ \Delta V\approx3.07(cm)^3 \end{gathered}[/tex]This means that the volume change is 3.07 cubic centimeters.
At last, we have to divide the volume change by the initial volume, and then we have to multiply it by 100% to express it as a percentage.
[tex]\frac{\Delta V}{V_1}\times100=\frac{3.07}{327.26}\times100\approx0.938[/tex]Therefore, the percentage change is 0.938%.11. If 100. g of gold-198 decays to 12.5 g in 25.3 days, what is the half-life of gold-198?
Answers
Given data
*The amount of gold-198 is N = 100 g
*The gold-198 decays is n = 12.5 g
*The given time is T = 25.3 days
The expression for the radioactivity decay is given as
[tex]N=n(\frac{1}{2})^{\frac{T}{t}}[/tex]Substitute the values in the above expression as
[tex]\begin{gathered} 100=12.5(\frac{1}{2})^{\frac{25.3}{t}} \\ t=8.43\text{ days} \end{gathered}[/tex]The metric unit of charge, the Coulomb, is ________.A) the charge of just one electron or protonB) the smallest unit of charge used in scienceC) is an amount of energy equivalent to equal numbers of electrons and protonsD) equivalent to a large number (6.25 x 1018) of unitary charges
Answers
The meteric unit of charge, the Coulomb, is equivalent to a large number of (6.25 x 10^18) of unitary charges.
Hence, the correct option is (D)
b)= combined resistance of the 2 Ω and 4 Ω resistors connected in series
Answers
R1=6 Ω
R2=3 Ω
R3=2 Ω
R4=4 Ω
6 Ω and 3Ω resistances are connected in parallel.
First, find the equivalent resistance:
ER1 = R1*R2/(R1+R2)= 6*3/6+3 = 18/9 = 2Ω
The resistances of 2 Ω and 4 Ω are connected in series:
TR2 = R3+R4 = 2 Ω+4 Ω= 6 Ω (b)
ER1 and TR2 are connected in parallel.
RT = ER1*TR2/ ER1+TR2= 2*6/2+6=12/8 = 1.5 Ω
Now, we can calculate the I (current)
On parallel circuits, Voltage is always the same. (12V)
But for series is VT=V1+V2
We have to find the current flowing across R3 and R4 (TR2)
V= I*R
I= V/R = 12/TR2= 12/6 = 2 A
With that current, we can calculate the voltage (potential difference) on R3 (2 Ω)
V=I*R= 2*2 = 4V (ai)
(aii) potential difference across the 3 Ω resistor
Since it is a parallel circuit , potential difference is always the same = 12V
b.combined resistance of the 2 Ω and 4 Ω resistors connected in series
R3+R4 = 2 Ω+4 Ω= 6 Ω (b)
A vector has the components Ax=22 m and Ay=13 m. What is the magnitude of thisvector? What angle does this vector make with the positive x axis?
Answers
Answer:
Magnitude = 25.55 m
Angle = 30.58 degrees
Explanation:
If the vector has the components Ax = 22 and Ay = 13, we can represent the vector as:
Therefore, the magnitude of this vector is the magnitude of the red vector. It means that we can calculate its length using the Pythagorean theorem where 22 and 13 are the legs, so:
[tex]\sqrt[]{Ax^2+Ay^2}=\sqrt[]{22^2+13^2}=\sqrt[]{484+169}=\sqrt[]{653}=25.55\text{ m}[/tex]Then, we can find the angle using the trigonometric function tangent, so:
[tex]\begin{gathered} \tan \theta=\frac{Ay}{Ax} \\ \tan \theta=\frac{13}{22} \\ \tan \theta=0.5909 \\ \theta=\tan ^{-1}(0.5909) \\ \theta=30.58 \end{gathered}[/tex]So, the answers are:
Magnitude = 25.55 m
Angle = 30.58 degrees
The figure below is made of 1-inch cubes. Two cubes have been removed from each row of the middle layer of a prism.What is the volume of the figure above? A. 34 in3 B. 38 in3 C. 40 in3 D. 36 in3
Answers
The volume of the prism is given by:
[tex]\begin{gathered} V=w\cdot l\cdot h \\ so\colon \\ V=4\cdot2\cdot5 \\ V=40in^3 \end{gathered}[/tex]Since two cubes have been removed from each row, the new volume is:
[tex]V_T=40in^3-4in^3=36in^3[/tex]Answer:
36 in³
a car travels 680 km in a time of 4 h calculate its speed
Answers
Hello..!
To calculate its speed we apply the following data.
Data:
D = 680kmT = 4hrsV = ?Then, we apply the formula that is.
Formula:
V = D/TFinally we develop the problem.
Developing:
V = 680km / 4hV = 170km/hThe speed of the car is 170 kilometers per hour.
Tory experiments with pulleys in physics class. She applies 60 newtons of force to a single pulley to lift a bowling ball. By adding another pulley, she'd get a mechanical advantage of 2. Whats the minimum input force she'll need to lift the ball if she adds another pulley?
Answers
Given,
The force applied by Tory, F=60 N
Mechanical advantage after adding the second pulley, MA=2
As Tory applies 60 N of force when there is only one pulley, the weight of the ball is 60 N.
Thus the output force is 60 N.
The mechanical advantage is given by,
[tex]MA=\frac{\text{output force}}{input\text{ force}}[/tex]On substituting the known values,
[tex]\begin{gathered} 2=\frac{60}{\text{input force}} \\ \Rightarrow input\text{ force}=\frac{60}{2} \\ =30\text{ N} \end{gathered}[/tex]Thus the minimum input force tory need to apply is 30 N
Traumatic brain Injury such as concussion results when the undergoes very large acceleration Generally an than 800 m/s ^ 2 lasting for any length of time will not , whereas an acceleration greater than 1, 000 m/s ^ 2 for at least 1 injury. Suppose a small child rolls off a bed that is 0.47 m above the floor. If the floor is hardwood the child’s head is brought to rest in approximately 2.1 mm. If the floor is carpeted,this stopping distance is increased to about 1.3 cm . Calculate the magnitude and duration of the deceleration in both cases, to determine the risk of injury. Assume the child remains horizontal during the fall to the floor. Note that a more complicated fall could result in a head velocity greater or less than the speed you calculate. Hardwood floor magnitude m/s^2Hardwood floor duration msCarpeted floor magnitude m/s^2Carpeted floor duration ms
Answers
ANSWER:
Hardwood floor magnitude: 2193.15 m/s^2
Hardwood floor duration: 1.38 ms
Carpeted floor magnitude: 354.27 m/s^2
Carpeted floor duration: 8.56 ms
STEP-BY-STEP EXPLANATION:
We have the following information:
Distance of the bed from the floor: 0.47 m
Stopping distance by hardwood: 2.1 mm
Stopping distance by carpet: 1.3 cm
We must find the speed of the child when he hits the ground using the following formula:
[tex]v^2=u^2+2gh[/tex]Where v is the final velocity, u is the initial velocity, g is the gravitational acceleration and h is the distance traveled.
Replacing and solving for v
[tex]\begin{gathered} v^2=0^2+2\cdot9.8\cdot0.47 \\ v=\sqrt[]{9.212} \\ v=3.035\text{ m/s} \end{gathered}[/tex]We can find the deceleration provided by the hardwood when stopping the child using the formula:
[tex]v^2=u^2-2aS[/tex]Since the child will stop, the final speed will be 0, the initial speed will be the speed gained by the child while falling that we found in the first step, and the distance S to stop is given in the question.
Replacing and solving for a:
[tex]\begin{gathered} 2.1\text{ mm }\cdot\frac{1\text{ m}}{1000\text{ mm}}=2.1\cdot10^{-3}m \\ 0^2=3.035^2-2\cdot a\cdot(2.1\cdot10^{-3}) \\ 2\cdot a\cdot(2.1\cdot10^{-3})=9.211 \\ a=\frac{9.211}{2\cdot(2.1\cdot10^{-3})} \\ a=2193.15\text{ }\frac{m}{s^2} \end{gathered}[/tex]From the calculated deceleration, we can find the time it takes for the child to stop after hitting the hardwood using the formula:
[tex]\begin{gathered} v=u-at \\ \text{replacing and solving for t:} \\ t=\frac{v-u}{-a} \\ t=\frac{0-3.035}{-2193.15} \\ t=0.00138\text{ s} \\ t=1.38\text{ ms} \end{gathered}[/tex]We repeat the same procedure but now with the data of the carpet, therefore:
[tex]\begin{gathered} 1.3\text{ cm }\cdot\frac{1\text{ m}}{100\text{ cm}}=1.3\cdot10^{-2}m \\ 0^2=3.035^2-2\cdot a\cdot(1.3\cdot10^{-2}) \\ 2\cdot a\cdot(1.3\cdot10^{-2})=9.211 \\ a=\frac{9.211}{2\cdot(1.3\cdot10^{-2})} \\ a=354.27\text{ }\frac{m}{s^2} \end{gathered}[/tex]Time for stopping by the carpet:
[tex]\begin{gathered} t=\frac{v-u}{-a} \\ t=\frac{0-3.035}{-354.27} \\ t=0.00856\text{ s} \\ t=8.56\text{ ms} \end{gathered}[/tex]I need help with questions number 2 I have the answer to number 1
Answers
Given,
the distance from Redd's door to the park, s=15 m
The total distance is the sum of the distance from her door to the park and the distance from the park to her door.
That is,
[tex]\begin{gathered} \text{total distance}=s+s \\ =15+15 \\ =30\text{ m} \end{gathered}[/tex]The displacement is defined as the shortest distance from the starting and ending point of a path. The starting and ending point of Redd's path is the door.
Therefore the total displacement is zero meters.
Therefore, distance = 30 m
and displacement = 0 m
The neutrons within the nucleus of an atom have what charge?Question 15 options:negativesame as an electronsame as a protonno charge
Answers
The nuclues of an atom contains the proton and the nuetron. The proton is positively charged while the nuetron has no charge.
You have been given 3.152 g of copper from which you are to fashion a wire whose resistance is 2,473.562 ohms. The density of copper is 8900 kg/m 3 and the resistivity of copper is 1.7 x 10 -8 ohm m. What will the diameter, in mm, of the wire be that you fashion?
Answers
Given:
Mass of copper, m = 3.152 g = 0.003152 kg
Resistance = 2,473.562 ohms
Density of copper = 8900 kg/m³
Resistivity of copper = 1.7 x 10⁻⁸ ohm.m
Let's find the diameter of the wire.
Apply the density formula to find the volume:
[tex]\begin{gathered} \rho=\frac{m}{v} \\ \\ v=\frac{m}{\rho}=\frac{0.003152}{8900} \\ \\ v=3.54*10^{-7}\text{ m}^3 \\ \\ (\pi r^2)l=3.54*10^{-7}\text{ m}^3 \end{gathered}[/tex]Now, apply the formula:
[tex]\begin{gathered} R=\frac{\rho l}{A} \\ \\ l=\frac{RA}{\rho} \\ \\ l=\frac{2473.562*\pi r^2}{1.7*10^{-8}} \\ \\ \frac{l}{\pi r^2}=\frac{2473.562}{1.7*10^{-8}} \\ \\ \frac{l}{\pi r^2}=1.455*10^{11} \\ \\ l=1.455*10^{11}*\pi r^2 \end{gathered}[/tex]Now, combine both expressions for L:
[tex]1.455*10^{11}*\pi r^2*\pi r^2=3.54*10^{-7}[/tex]Solving further:
[tex]\begin{gathered} (\pi r^2)^2=\frac{3.54*10^{-7}}{1.455*10^{11}} \\ \\ (\pi r^2)=\sqrt{2.434*10^{-18}} \\ \\ \pi r^2=1.56*10^{-9} \\ \\ r^2=\frac{1.56*10^{-9}}{\pi} \\ \\ r=\sqrt{\frac{1.56*10^{-9}}{\pi}} \\ \\ r=2.228*10^{-5} \end{gathered}[/tex]r is the radius.
We know that:
Diameter = 2 x radius
Thus, we have:
[tex]\begin{gathered} d=(2.228*10^{-5})*2 \\ \\ d=4.4569*10^{-5}\text{ m} \\ \\ d=0.044569*10^{-3}m \\ \\ d=0.0446\text{ mm} \end{gathered}[/tex]Therefore, the diameter in mm will be 0.0446 mm
ANSWER:
0.0446 mm