let 'x' and 'y' be two numbers that have a sum of -10 and a difference of -2, then, we have the following system of equations:
[tex]\begin{gathered} x+y=-10 \\ x-y=-2 \end{gathered}[/tex]notice that if we add both equations at the same time, we get:
[tex]\begin{gathered} x+y=-10 \\ x-y=-2 \\ --------- \\ 2x=-12 \\ \Rightarrow x=\frac{-12}{2}=-6 \\ x=-6 \end{gathered}[/tex]now that we have that x = -6, we can find the value of y substituting x = -6 on any equation:
[tex]\begin{gathered} -6+y=-10 \\ \Rightarrow y=-10+6=-4 \\ y=-4 \end{gathered}[/tex]therefore, x = -6 and y = -4. Next, we have that the product is (-6)(-4) = 24
please answer both i will give brainliest and thanks!!!! please quickly!!! hurry pleaseeee!!!
1.
The nth term is given by,
[tex]\begin{gathered} f(n)=f(n-1)+7 \\ f\mleft(1\mright)=2 \end{gathered}[/tex]The common difference can be calculated as,
[tex]\begin{gathered} f(1)=2 \\ f(2)=f(1)+7=9 \\ f(3)=f(2)+7=16 \\ d=\text{ 7} \end{gathered}[/tex]Therefore the tenth term can be calculated as,
[tex]\begin{gathered} a_n=a_1+d(n-1) \\ a_{10}=a_1+7\times9=2+63=65 \end{gathered}[/tex]2.
SImilarly,
[tex]\begin{gathered} f(1)=30 \\ f(n)=2(fn-1)-50 \\ f(2)=2\times30-50=10 \\ f(3)=2\times10-50=-30 \\ d=-20 \end{gathered}[/tex]Thus, the tenth term is,
[tex]f(10)=30-20\times(9)=-150[/tex]Thus, the answer is -150.
The Barnett triplets went to the school carnival. Henry rode on 5 rides, bought 2 drinks , 1 bag of popcorn and spent $20.50. Mary spent $16.50 on 3 rides, 3 drinks and 1 bag of popcorn. While Tim rode rode on 6 rides only purchased 1 drink and spent $20.00. How much did each ride cost?a: $12b: $3c: $2d: $4
Let:
x = Cost of each ride
y = Cost of each drink
z = Cost of each bag of pocorn
so:
Henry rode on 5 rides, bought 2 drinks , 1 bag of popcorn and spent $20.50:
[tex]5x+2y+z=20.50_{\text{ }}(1)[/tex]Mary spent $16.50 on 3 rides, 3 drinks and 1 bag of popcorn:
[tex]3x+3y+z=16.5_{\text{ }}(2)[/tex]Tim rode rode on 6 rides only purchased 1 drink and spent $20.00:
[tex]6x+y=20_{\text{ }}(3)[/tex]Solve the system:
[tex]\begin{gathered} (1)-(2) \\ 5x-3x+2x-3y+z-z=20.5-16.5 \\ 2x-y=4_{\text{ }}(4) \end{gathered}[/tex][tex]\begin{gathered} (3)+(4) \\ 6x+2x+y-y=20+4 \\ 8x=24 \\ x=\frac{24}{8} \\ x=3 \end{gathered}[/tex]Answer:
Each ride cost $3
Hello, I'm unsure about the process of this equation, please help me.
Answer:
144 employees
Explanation:
• The ratio of men to women = 3:5
,• The number of men in the company = 54.
Let the total number of employees = x.
The proportion of men in the company will be:
[tex]\frac{3}{3+5}=\frac{3}{8}[/tex]Since there are 54 men in the company, we can then say that:
[tex]\begin{gathered} \frac{3}{8}\text{ of x}=54 \\ \implies\frac{3}{8}x=54 \end{gathered}[/tex]Multiply both sides by 8/3 to solve for x.
[tex]\begin{gathered} \frac{8}{3}\times\frac{3}{8}x=\frac{8}{3}\times54 \\ x=144 \end{gathered}[/tex]The total number of employees is 144.
Santa bought a jacket that was marked 55% off the original price of $48. The sales tax was 6%. What did he pay altogether for the jacket? Find the discount price first and then find the tax. Round your answer to the nearest cent.
First we need to find the discount
48 * 55%
48 *.55
26.40
Subtract this from the price of the jacket
48-26.40
21.60
The sale price is 21.60
Now we need to find the sales tax
21.60 * 6%
21.60 * .06
1.296
Rounding to the nearest cent
1.30
Add the sales tax to the price of the jacket
21.60 +1.30
22.90
Santa will have to pay 22.90 for the jacket.
ge bank offers a checking account without monthly fees of $538 and wrote a check for $325. how much should he transfer from his savings account to avoid paying a service fee on his cheeking account. express as an inequality.
I’m here to help you. Just give me a few mins to look over your question.
Step 01:
Checking account no monthly fees (minimum balance) = $300
Daniel's balance checking account = $538
Daniel's check = $325
transfer from savings account ===> ?
Step 02:
transfer from savings account ≥ Checking account minimum balance - (Daniel's balance - Daniel's check)
transfer from savings account ≥ $300 - ($538 - $325)
transfer from savings account ≥ $300 - $213
transfer from savings account ≥ $87
The answer is:
Daniel should transfer from his savings account at least $87.
match each system with its solution setoptions:A. (8, 2)B. no solutionC. infinite solutionsD. (2, 8)
• 1.
x+y=3
2x+2y= 6
Multiply the first equation by 2, and then subtract both equations.
2x+2y=6
-
2x+2y=6
_______
0x+0y=0
0
Since both variables are eliminated, there are INIFINITE SOLUTIONS
• 2.
y= 2x-3
-2x+y=6
Put the first equation into the second equation, (replace y )
-2x+(2x-3) = 6
Solve for x
-2x+2x-3=6
-3= 6
Since -3 is not equal to 6, there is NO SOLUTION.
• 3.
X+3y = 14
-5x+6y=-28
Multiply the first equation by 2, then subtract the equations:
2x+6y=28
-
-5x+6y=-28
_________
7x= 56
x= 56/7
x= 8
Replace x=8 on any equation and solve for y:
8+3y= 14
3y=14-8
3y= 6
y=6/3
y=2
Solution = (8,2)
• 4.
-1/2x+3y=23
y=5x-2
Put the second equation into the first equation ( replace y) and solve for x
-1/2x + 3 (5x-2)= 23
-1/2x+ 15x - 6 = 23
-1/2x +15x = 23+ 6
29/2 x = 29
x = 29/ (29/2)
x = 2
Replace x on any equation and solve for y
y= 5x-2
y=5(2)-2
y= 10-2
y=8
Solution: (2,8)
Find the equation of a line parallel to2y=2x+4 and passes through the point ( -5,-1)
Slope-Intercept Equation of the Line
Given a line, we can express it in the form:
y = mx + b
Where m is the slope and b is the y-intercept.
We are given the equation of a line:
2y = 2x + 4
Dividing by 2:
y = x + 2
Comparing with the generic equation in slope-intercept form, we can see that m = 1 and b=2.
Now we have to find the equation of a line that is parallel to that line and passing through the given point.
Parallel lines have the same value of the slope. Thus, the slope of our required line is m'=1
The equation of the line is so far:
y = x + b'
We need to find the value of b'. Here comes handy the use of the point (-5,-1). Substituting in the equation:
-1 = -5 + b'
Solving for b':
b' = -1 + 5 = 4
Now we have the complete equation of the line as required:
y = x + 4
Identify the range of the function shown in the graph?
Answer:
C
Step-by-step explanation:
The range is the lowest and highest y point on the graph, -1 and 1
a bakery typically sells its cupcakes for $24 per box for the first week of school they have a sale of $10 off of each box of cupcakes how much will a box of cupcakes cost during the first week of school
cupcakes = $24/box
If they sold each box $10 off, the sold each box for only 24 - 10 = $14
Each box was sold for $14.00
Simplify the expression below (w^0*x^{-3})^{-2} The base is AnswerThe exponent is Answer
given expression,
[tex](w^0\ast x^{-3})^{-2}[/tex]let us simplify,
[tex]\begin{gathered} (w^0\ast x^{-3})^{-2} \\ =\frac{1}{(w^0\ast x^{-3})^2} \\ =\frac{1}{w^0}\ast\frac{1}{(x^{-3})^2} \\ =1\ast\frac{1}{x^{-6}} \\ =\frac{1}{\frac{1}{x^6}} \\ =x^6 \end{gathered}[/tex]the base is x.
the exponent is 6.
Which conic section is defined by the set of all points in a plane that areequidistant from a single point and a line?A. HyperbolaB. EllipseC. ParabolaD. Circle
Given:
The conic section that is defined by the set of all points in a plane that are equidistant from a single point and a line is a parabola since the parabola is equidistant from a fixed point that we call a focus and a fixed line that we call a directrix.
Therefore, the conic section is a PARABOLA.
Hence, option (C) is correct.
Suppose that the dollar value v(t) of a certain car that is t years old is given by the following exponential function.v (t) = 19,900(0.91)^tFind the initial value of the car.Does the function represent growth or decay?By what percent does the value of the car change each year?
The general form of an exponential function is:
[tex]f(x)=ab^x[/tex]where a = initial value and b = the rate of growth.
In the given equation that we have,
[tex]v(t)=19,900(0.91)^t[/tex]we can see that the value of a = 19, 900. Hence, this is the initial value of the function and thus, the initial value of the car is 19, 900.
We can also see that the rate of growth is 0.91. Since the rate of growth is between 0 and 1, the function represents exponential decay.
The value of the car decreases by 9% each year.
Give the domain of the function represents in the table x: 3,-2,1 y:2,-8,-2
We have the following table:
The domain of a function is the set into which all of the input of the function is constrained to fall. In other words, its the set of departure:
where f is the function.
Therefore, the domain is the set {3,-2,1}.
Rewrite the following equation in slope intercept form3x + 17y = -4Write your answer using integers, proper fractions, and improper fractions in simplest form.
the given expression is,
3x + 17y = -4
17y = -4 - 3x
y = -3/17x - 4/17
thus, the answer is,
[tex]y=-\frac{3}{17}x-\frac{4}{17}[/tex]Perform the indicated operation. Write your solution in scientific notation: 0.00000936 0.00000003 a. 3.12 x 102 son b. 3.12 x 10-14 C. 3.12 x 1048 3 d. 3.12 x 104
1) To write a scientific notation number we must write a rational number followed by its power of 10.
2) So we can write:
[tex]undefined[/tex]In distributive property; 6(30+4)
Un paquete de queso de 12 oz cuesta $1.38 ¿ Cuanto cuesta 1 Lb del mismo queso ?
Given:
A 12 oz package of cheese costs $ 1.38 How much does 1 Lb of the same cheese cost?
First, we will convert from Lb to an ounce
so,
1 Lb = 16 ounces
Using the ratio and proportions
Weight : Price
12 oz : $1.38
16 oz : x
So, we will find x as follows using the cross product
[tex]x=\frac{16}{12}\times1.38=1.84[/tex]So, the answer will be:
The cost of 1Lb of cheese = $1.84
8 students were in the cafeteriaThey increased to 12 students. What is percent of change?
Percentage of change = 50%
Explanation:Old number of students in the cafeteria= 8
New number of students in the cafeteria= 12
percentage of change = (New - old)/old × 100
percentage of change = (12 - 8)/8 × 100
= 4/8 × 100
= 1/2 × 100
Percentage of change = 50%
I've tried similar questions to this I still don't understand it also I'm not entirely sure if the top piece is correct
One way to make sure that the regression you made is by replacing one of the values of c, from your table and see if the predicted value that your regression gives you is close to the actual value from your table.
In this case, when we replace the first value of c (11.5) into the equation that you got from the regression, we can see that the value of p equals 13.73, which is actually close to the value reported in the table (13.8), since it is a regression it is not expected to obtain the exact value but the closest one.
If we want to find how many murders per 100000 residents we could have when c equals 8400, we just have to use the formula that you found (the regression) and calculate p, the result would be:
[tex]p=0.829\times8400+4.199=6967.799[/tex]If we want to know the number of weapons, we just have to solve for c from the equation of the regression and replace the number of murders per 100000 residents, like this:
[tex]\begin{gathered} p=0.829\times c+4.199 \\ p-4.199=0.829\times c \\ \frac{p-4.199}{0.829}=c \\ c=\frac{p-4.199}{0.829} \end{gathered}[/tex]Now, we can calculate the value of c, by replacing 9.5 into p
[tex]c=\frac{9.5-4.199}{0.829}=6.39[/tex]then c=6, since we have to round it to the nearest whole number
I dont understand the thing with the parallel lines and the perpendicular
Given;
[tex]\begin{gathered} \bar{AD}\perp\bar{DB} \\ \bar{DB}\perp\bar{BC} \\ \bar{AB}\cong\bar{CD} \end{gathered}[/tex]Line AD is perpendicular to line DB, line DB is perpendicular to line BC and line AB is congruent to line CD.
To prove that line AB is perpendicular to line DC, we have to establish that the alternate angles ABD and BDC are congruent.
[tex]\angle ABD\cong\angle BDC[/tex]From congruent triangles, we know that when two triangles have two congruent sides (Hypothenuse and a side) and both have a right angle then they are congruent (RHS - Right angle Hypothenuse Side).
For Triangle ADB and triangle CBD,
The sides AD and CB are congruent, and also side DB is congruent to BD.
[tex]\begin{gathered} \bar{AB}\cong\bar{CD}\text{ ----Hypothenuse} \\ \bar{DB}\cong\bar{BD}\text{ -----side} \\ \angle ADB\cong\angle CBD\cong90^{0\text{ }}-----Right\text{ angle} \end{gathered}[/tex]Therefore, triangle ADB and triangle CBD are congruent.
So, corresponding sides and angles of the two congruent triangles are also congruent.
[tex]\begin{gathered} \bar{AD}\cong\bar{BC} \\ \angle ABD\cong\angle BDC \end{gathered}[/tex]Therefore, since the alternate angles ABD and BDC then line AB is parallel to DC.
[tex]\bar{AB}\parallel\bar{DC}[/tex]Reason: Alternate interior angles.
If two lines are cut by a transversal and the alternate interior angles are equal (or congruent), then the two lines are parallel.
Search topics and ska Learning DIQQOUTE Analytics Recommendations Sodal studies Language arts Scance Y 2 Find the shop om uwa points 20 Find the slope of the line that passes through (8,6) and (3, 15). Simplify your answer and write it as a proper fraction, improper fraction, or integer. Submit Work it out
Given the points:
(x1, y1) ==> (8, 6)
(x2, y2) ==> (3, 15)
To find the slope of the line that passes through the points, use the slope formula below:
[tex]slope,m\text{ = }\frac{y2-y1}{x2-x1}[/tex]Input the values into the formula:
[tex]\begin{gathered} m=\frac{15-6}{3-8} \\ \\ m\text{ = }\frac{9}{-5} \\ \\ m=-\frac{9}{5} \end{gathered}[/tex]The slope is an improper fraction
[tex]-\frac{9}{5}[/tex]ANSWER:
[tex]-\frac{9}{5}[/tex]#6-7 identify angles name a pair of complementary angles and a pair of supplementary angles?
6. ∠STR and ∠UWV are complementary (their addition makes 90°)
∠QTS and ∠UWV are supplementary (their addition makes 180°)
7. ∠GLH and ∠HLJ are complementary (their addition makes 90°)
∠GLJ and ∠JLK are supplementary (their addition makes 180°)
Identify the domain and range to the following relations and state whether or not the relations are functions. State why or why not the relation is a function.
Here, we want to get the range and the domain of the function
The domain refers to the x-values
Looking at the plot, we can see the x-values from 2 to 6
In an interval form, we have this as;
[tex]2\leq x\leq6\text{ or \lbrack{}2,6\rbrack}[/tex]For the range values, we have these as the possible y-values
We can see that the lowest y value is at -4 and the highest y-value is at the point y = 5
So the range is;
[tex]-4\leq y\leq5[/tex]Now, we want to answer if the relation is a function
For a relation to be a function, no domain value will have 2 range values
But, we can have a single range value having two domain values
As we can see, this rule is correctly followed on the plot and thus, we can confirm that the relation is a function
It is a function because each of the x-values have a single y-value. This means that for every domain value, there is only a range value attached
Help me please and thank you I just need part a and d please
a. To complete the table, we have to assign the corresponding study hours per week to the hours worked per week.
For example, for the first interval 0≤h<4, the credits taken are 18 (according to the first table). When the credits taken are 18, the study hours per week are 39 (according to the second table). It means that for the interval 0≤h<4, the study hours per week is 39.
The values of this table will be, respectively:
39, 32, 24, 21, 17, 14, 12.
d. An student works between 12 and 16 hours every week, that allows him take 15 credits, which means that he has to use 21 hours to study. He wants to study 32 hours per week, that way, he can take 17 credits. To achieve it he needs to reduce its working hours to 4 to 8 hours per week, that way he would be able to take 17 credits and study 32 hours per week.
Find the value of each variable in the parallelogram.lg + 4) 7.16- h65°g=h=
h = 9
g = 61°
Explanation:The opposite sides of a parallelogram are parallel and congruent.
This means the opposite sides are equal
equating the sides:
7 = 16 - h
subtract 16 from both sides:
7 - 16 = - h
-9 = -h
divide both sides by -1
-9/-1 = -h/-1
h = 9
The opposite angles of a parallelogram are equal
equating the angles:
(g + 4)° = 65°
g + 4 = 65
subtract 4 from both sides:
g + 4 -4 = 65 -4
g = 61°
A diagram of a basketball court uses the scale of 1 inch: 4 feet. If the length of the diagram is 16 inches, what’s the length of the actual basketball court? Show your work
Since the scale factor is 1in:4ft, we get that 1 inch in the diagram represents 4 feet in the actual basketball court.
Therefore:
[tex]16in=16\cdot1in\rightarrow16\cdot4ft=64ft.[/tex]Then, the fulfilled table is:
Therefore, the length of the actual basketball court is 64ft.
Answer:
Therefore, the length of the actual basketball court is 64ft.
For a given set of rectangles, the length varies inversely with the width. In one ofthese rectangles, the length is 77 and the width is 2. For this set of rectangles,calculate the width of a rectangle whose length is 14.
Ok, so
Let L represent length of rectangle and W represent width of the rectangle.
We have been given that for a given set of rectangles, the length varies inversely with the width.
We know that the equation:
y = k/x
represents the relation where y is inversely proportional to x and k is the constant of proportionality.
So our required equation would be:
L = k/W.
In this case, we know that L = 77 and W = 2, so we're going to find k:
77 = k / 2
And k = 77*2, which is equal to 154.
Now, we know that k = 154, so our general equation would be:
L = 154/W
Finally, we replace the value of our lenght, which is 14.
14 = 154 / W
And W = 154/14
W=11
Therefore, the width of a rectangle whose length is 14, will be 11
wants to buy some boxes of candy that cost $1.50 each.If Billy has $7.50 remaining, which of the following equations will give you the number of boxes, X, thatBilly could buy?a.) 1.5x = 7.5Ob.) x= 7.51.5c.) 7.5x = 1.5d.) X= 1.575 =
Equation for the given statement is, 1.50[tex]x[/tex] = 7.50
option (a) is correct
Linear equation in one variable:
Equation having one variable and and degree is one, called linear equation in one variable.
given,
Cost of each box of candy is $1.50
Billy has $7.50 remaining
Billy bought x number of boxes,
so,
1.50[tex]x[/tex] = 7.50
[tex]x = \frac{7.50}{1.50} \\x = 5[/tex]
Thus we can say the equation for above statement will be,
1.50[tex]x[/tex] = 7.50
while value of x will be 5
Hence, Option (a) is correct
To learn more about Linear equation in one variable visit:
https://brainly.com/question/28773343
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HELPP PLEASEEEEEEEeeee
Answer:
60°
Step-by-step explanation:
basically if you rotate the figure by a specified amount it will return to the original orientation, in this case is is asking you to do this with the least angle rotation
Which expression can be used to find the price of a $400 telescope after a 32% markup? Select all that apply.A.400 • 0.32B.400 • 3.2C.400 • 1.32D.400 + 400(0.32)E.400 • 400(1.32)
We want to know an expression that let us find the price of a telescope of $400, after a 32% markup. We remember that briefly, the markup determines the percent of earning you will receive from selling a product.
On this case, for finding the cost, we will have to add the percent of earnings to the cost. Then we find the excedent given by the expression:
[tex]400(0.32)[/tex]And we add it to the original price:
[tex]400+400(0.32)[/tex]which is an expression to find the price after the markup.
Another option is to find the 100% + 32% of the original price, this is, multiply the original price by 1.32. We obtain that another expression for finding the price will be:
[tex]400\cdot1.32[/tex]Those two are the only options, ok?C and D, those are the ones I wrote.Yes, I am here.Do you see what I'm writing?