(a) Mutual inductance = 6.818 × 10⁻³ Hz
(b) Total flux = 3.27 × 10⁻⁴ Wb
(c) Induced EMF = 2.45 × 10⁻³ V
What is induced EMF?When the bar magnet is pushed out, an electromotive force is induced in the coil. An EMF of opposite sign is produced by moving in the opposite direction, and the EMF is also flipped by reversing the poles. You can get the same result by moving the coil instead of the magnet - relative motion is important.
For mutual inductance:
M = ∈/(Δi/Δ)
Where, M = mutual inductance
∈ = 1.65 × 10⁻³ V
Δi/Δt = -0.242 A/s
M = 1.65 × 10⁻³/ -0.242
M = 6.818 × 10⁻³ Hz or 6.818 mHz
For the calculation of the flux through each turn:
∅ = MI/N
Where, ∅ = Total flux
M = Mutual inductance
I = Current through one coil
N = Number of turns
∅ = (6.818 × 10⁻³ × 1.20)/25
∅ = 3.27 × 10⁻⁴ Wb
For induced EMF:
∈ = M × (Δi/Δt)
∈ = induced EMF
M = 6.818 × 10⁻³ Hz
Δi/Δt = 0.360 A/s
∈ = 6.818 × 10⁻³ × 0.360
∈ = 2.45 × 10⁻³ V
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Now, consider the special case where the block of mass m1 is not present. find the magnitude, t , of the tension in the rope. try to do this without equations; instead, think about the physical consequences.
Since the mass is not present, the tension in the rope T = 0 N.
What is tension in physics?Tension, in physics, is be defined to be the pulling force transmitted axially by the means of a string, a rope, chain, or similar object. The opposite of tension could be compression.
At the atomic level, when atoms/molecules are pulled apart from each other and gain potential energy with a restoring force still existing, the restoring force might create tension.
Tension is a pulling force since it is exerted when a mass being pulled by a rope or a similar object. If the mass is not present, then there is no tension (pulling force) exerted by the rope, hence T = 0 N.
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True or false. A small amount of mass can produce a large amount of energy
The satement is true.
This comes from the fact that, according to Einstein:
[tex]E=mc^2[/tex]and since c² is a very large number then, if we find a way to convert all the mass in energy a small amount will produce a large amount of energy.
A small child weighs 18 kg. If his mom left him sitting on top of the stairs, which are 10m high, how much energy does the child have?
Explanation:
Find an energy is E=mgh, so E=18*10*10=1800J
An object is moving to the right at a constant velocity. What will happen if a force of 20 n starts acting on it in the opposite direction?.
If a force of 20 n begins acting on the object in the opposite direction, its velocity will rise.
What happens when things are moving at a constant speed?If there are no forces acting to accelerate or decelerate an object that is already moving with a constant speed, it will continue to move at that speed in a straight line. By defining force as a vector quantity, Newton helped to clarify the aforementioned statement.
Newton's first law of motion states that any object moving at a constant speed experiences no net external forces, so the total amount of forces acting on the object must be zero.
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A voltage of 12 V is applied across a circuit with one 3 0hm resistor in series and three 3 Ohm resistors in parallel. What is the total voltage drop in the first 3 Ohm resistor in the circuit? Select one:a. 3 Volts b. 9 Volts c. 36 Volts d. 6 VoltsThe total current is 3 A.
In order to calculate the voltage drop in a resistor, we can use the formula below:
[tex]V=I\cdot R[/tex]If the current passing through the resistor is 3 A and its resistance is 3 ohms, so the voltage drop is:
[tex]\begin{gathered} V=3\cdot3\\ \\ V=9\text{ Volts} \end{gathered}[/tex]Therefore the correct option is b.
The element magnesium has 12 electrons. In how many energy levels are the electrons of magnesium?
Answer: energy level 2
Explanation:
i did this before
Answer: Magnesim’s electrons are in 3 energy levels .
Explanation: since magnesium has 12 electrons and first shell can only accommodate up to 2 electrons , as shown in picture too, magnesium will have 2 electrons in this first shell or energy level.
Now about rest 10 electrons, 8 will be in 2nd energy level and remaining 2 will be valance electrons and will occupy 3rd shell.
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Conditions for uniform circular motion are constant speed and circular path. (True or false)
Uniform circular motion is a motion that is uniform in terms of speed and circular in terms of its path.
Uniform means constant speed and its path is circular.
Thus, the statement is true.
Please help me complete. The second picture is the options you have to choose from from each
This drawing helps us understand the contribution of each the magnetic field of each wire. Wire 1 will contribute with positive field for everything on its left, and with negative field for everything on its right. The opposite is true for wire 2, so, if we analyse regions I, II and III:
Region I: Wire 1 contributes with positive and Wire 2 contributes with negative. As any point on region I will be closer to Wire 1, its contribution will be more significant, and the field will be positive
Region II: Wire 1 and 2 contribute with negative field. Thus, the resulting field will be negative
Region III: Wire 1 contributes with negative field and Wire 2 contributes with positive field. As any point on region III will be closer to Wire 2, its contribution will be more significant, and the field will be positive.
Now all we have to do is calculate the value of the fields. The field on point P1 will have positive contribution from Wire 2 and negative contribution from Wire 1, which will be:
[tex]P1=\frac{\mu_0*I}{2\pi d}-\frac{\mu_0*I}{2\pi(2d)}=\frac{4\pi *10^{-7}}{2\pi *11.4*10^{-2}}-\frac{4\pi *10^{-7}}{4\pi *11.4*10^{-2}}=0.8772\mu T[/tex]The field on the midpoint (distance d/2 from each wire) will be negative, as the contribution from both wires will be negative, thus:
[tex]P_{med}=-2*\frac{4\pi *10^{-7}*5.4}{2\pi *(\frac{11.4}{2})*10^{-2}}=-37.8947\mu T[/tex]The field on point P2 will be positive, which can be written as:
[tex]P2=\frac{\mu_0I}{2\pi *2d}-\frac{\mu_0I}{2\pi *(3d)}=\frac{4\pi *10^{-7}*5.4}{2\pi *(2*11.4*10^{-2})}-\frac{4\pi *10^{-7}*5.4}{2\pi *(3*11.4*10^{-2})}[/tex][tex]P2=1.5789\mu T[/tex]Summary:
a) Pmed = -37.8947uT into the screen
b) P1 = 0.8772uT out of the screen
c) P2 = 1.5789uT out of the screen
what is the apparent weight of a 95 KG astronaut on this rocket
Given:
• Acceleration of rocket = 28.0 m/s²
,• Mass of astronaut = 95 kg
Let's find the apparent weight of the astranaut.
In a direct rocket motion, as we are coming towards the Earth the weight reduces while as the rocket is going up, you feel more weighted.
Now, to find the apparent weight of the astranaut, apply the formula:
[tex]A_w=m(g+a)[/tex]Where:
Aw is the apparent weight
m is the mass = 95 kg
g is acceleration due to gravity = 9.8 m/s²
a is the acceleration of the rocket = 28.0 m/s²
Thus, we have:
[tex]\begin{gathered} A_w=95(9.8+28) \\ \\ A_w=95(37.8) \\ \\ A_w=3591\text{ N }\approx3.591\text{ kN} \end{gathered}[/tex]Therefore, the apparent weight of the astranaut is 3.591 kN
ANSWER:
3.591 kN
What is the maximum speed at which a car can safely travel around a circular track of radius 142 meters if the coefficient of friction between the tires and the road is 1.07? Include units in your answer. Answer must be in 3 significant digits.
Given that the radius of the circular path is r = 142 m and the coefficient of the friction is
[tex]\mu=1.07[/tex]The condition for the car to travel safely is
Frictional force = centrifugal force
[tex]\mu mg=\frac{mv^2}{r}[/tex]Here, m is the mass of the car and the acceleration due to gravity is g = 9.8 m/s^2.
v is the maximum speed of the car.
[tex]\begin{gathered} v=\sqrt[]{ugr} \\ =\sqrt[]{1.07\times9.8\times142} \\ =38.58\text{ m/s} \end{gathered}[/tex]a sample of a gas is compressible; i.e., its volume can be significantly decreased. this is because multiple choice question. there are attractive forces between particles in the gas phase, whereas in the liquid and solid phases there are not. particles in the gas phase are smaller than they are in the liquid and solid phases. particles in the gas phase are separated by relatively large distances.
A sample of a gas is compressible; i.e., its volume can be significantly decreased because the particles in the gas phase are separated by relatively large distances.
A gas is a substance that has no constant size or form. Whilst inside a closed container, gasoline will amplify to fill the field. An instance of gas is the air you breathe. The gas interior of your digestive tract is fabricated from the air and different gases.
Traits of Gases :
* Gases have neither definite shape nor particular volume. They expand to the dimensions of their container.
* Gases are fluid and go with the flow effortlessly.
* Gases have low density, except compressed.
* Gases diffuse (mix and unfold out) and effuse (tour thru small holes).
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what element will transfer heat most quickly?
How are testes and ovaries different?
The testicles are the female gonads, whereas the ovaries are the male gonads. The production of gametes is one of the special traits and functions of gonads.
What distinguishes the ovaries and testes?The gonads in males are the testes, whereas those in females are the ovaries. They both work to produce sex hormones and gametes (eggs and sperm). The ovaries are responsible for producing progesterone and estrogen as well as eggs. Sperm and the hormone testosterone are produced by the testes.
What features do ovaries and testes have in common?By secreting steroid hormones and creating gametes, adult testes and ovaries both perform crucial functions in the reproductive system (Hossain et al., 2012). The healthy growth of both the gonadal somatic cells and germ cells is necessary for gonadal functional maintenance and gametogenesis.
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Last question please help!!!!!
Answer:
it is true
Explanation:
Answer:
True, changes of heat can be Endothermic or Exothermic only.
Explanation:
At 2:00 p. M. Two cars start toward each other from towns 240 miles apart. If the rate of one car is 10 mph faster than the other, how fast does each car go if they meet at 5:00 p. M. ? if 3x represents the distance that the slower car traveled, then which expression represents the distance the faster car traveled? 3 x + 10 3 x + 30 3(240).
135 miles represents the distance the faster car traveled.
Just what is distance?Distance is an object's overall movement, regardless of direction. Regardless of an object's starting or ending point, distance can be defined as the amount of ground it has travelled.
If we call the slower vehicle's speed S, the other vehicle's speed is S + 10 mph.
They've been on the road for three hours as of 5:00 p.m. The faster car travels 3(S+10) miles, while the slower one travels 3S miles.
However, the sum of the two distances has to be 240 miles, so 3S+3(S+10)=240,
3S+3S+30=240,
6S=210, and
S=35 mph.
The faster vehicle travels at 45 mph. We can see that 3S is equal to 3x, which means that x=S=35 mph and that the faster vehicle travels 3×45=135 miles.
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HELPSSJDIGFDiuea 50 ptss
Suppose you can lift a barrel or roll it up an inclined plane. In which scenario do you do more work?
Both are the same amount of work.
Lifting the barrel is more work.
Rolling the barrel is more work.
Neither do any work.
Rolling the barrel is more work.
What is work?Work in physics is the energy that is transferred to or from an item when a force is applied along a displacement. In its simplest form, it equals the product of the force's magnitude and the distance traveled for a constant force directed in the direction of motion.
Work = force x distance. In units, Joules = Newtons x meters.
When a body is lift than angle is right angle so work done is zero as force and displacement is perpendicular while in case of rolling it is at theta angle so work is done in this case.
Rolling the barrel is more work.
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If you are on a moving train and you drop a ball, why does it land at your feet instead of flying backwards?
Answer:
cause you feet block the air
1000 kg car is driving forward with a speed of 25 m/s. it comes to rest in a distance of 100m what is its change in kinetic energy during this process
If a 1000 kg car is driving forward with a speed of 25 m/s and it comes to rest in a distance of 100m, the change in kinetic energy during this process is - 312.5 KJ
KE = 1 / 2 m v²
KE = Kinetic energy
m = Mass
v = Velocity
m = 1000 kg
Initially,
v = 25 m / s
KEi = 1 / 2 * 1000 * 25²
KEi = 312500 J
Finally,
v = 0, since the object comes to rest.
KEf = 1 / 2 * 1000 * 0
KEf = 0
ΔKE = KEf - KEi
ΔKE = Change in kinetic energy
ΔKE = 0 - 312500
ΔKE = - 312500
ΔKE = - 312.5 KJ
Therefore, the change in kinetic energy during this process is - 312.5 KJ
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Hello, I needed help with the question boxes on what to fill in.
Given:
To find:
Fill in the blanks
Explanation:
1) Energy can undergo conversion, changing from one form to another. For example, a wind turbine converts the mechanical energy of the wind into electric energy in the power grid. This power grid can then be converted into thermal energy by an electric heater.
2) Solar panels generate electrical energy by taking radiant energy from the sun and having it undergo conversion. This process does obey the law of conservation of energy because energy isn't randomly created, but it is simply converted.
A lighthouse is located on a small island 5 km away from the nearest point p on a straight shoreline and its light makes nine revolutions per minute. How fast is the beam of light moving along the shoreline when it is 1 km from p? (round your answer to one decimal place. ).
The beam of light moving along the shoreline is at a rate of 293.9 km/min. The result is obtained by using the differentiation formula.
What is the differentiation formula?The differentiation formula is commonly used to calculate the rate of change of a function.
Given the case a lighthouse on a small island 5 km away from the nearest point p on a straight shoreline. The light makes 9 revolutions/min.
When it is 1 km from p, how fast is the beam of light moving along the shoreline?
We have the angular speed of the beam.
dθ/dt = 9 rev/min
dθ/dt = 9 × 2π rads/min
dθ/dt = 18π rads/min
See the diagram in the attachment! We get √26 with the Pythagorean Theorem. The linear speed of the beam of light moving along the shoreline can be described in the differentiation of dx/dt.
tan θ = x /3
d/dt (tan θ) = d/dt (x/5)
sec² θ . dθ/dt = 1/5 . dx/dt
5 sec² θ . dθ/dt = dx/dt
dx/dt = 5 . (√26/5)² . 18π
dx/dt = 90 . 26/25 π
dx/dt = 93.6π
dx/dt ≈ 293.9 km/min
Hence, the linear speed of the beam of light moving along the shoreline is 293.9 km/min.
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where is thermocouple thermometer used
Explanation:
Thermocouples are used in applications that range from home appliances to industrial processes, to electric power generation, to furnace monitoring and control, to food and beverage processing, to automotive sensors, to aircraft engines, to rockets, satellites and spacecraft.
Object 1 has a mass (M1) and a velocity (V1). Object 2 has a mass half the size of object 1 and a velocity that is 3 times the speed, but in the opposite direction. They collide in a linear elastic collision. Find the final velocity of both objects in terms of M1 and V1. (reduce the final answer to one term, reduced as much as possible with no fractions or decimals in major divisions)
Mass of object 1 = m₁
Velocity of object 1, = u₁
The mass of object 2 is half that of object 1
m₂ = m₁/2
The velocity of object 2 is three times the speed of object 1 but in the opposite direction
u₂ = -3u₁
The final velocity of both object is represented by v
Applying the principle of momentum conservation
[tex]\begin{gathered} m_1u_1+m_2u_2=m_1v_1+m_2v_2 \\ \\ m_1u_1+\frac{1}{2}m_1(-3u_1)=m_1v_1+\frac{1}{2}m_1v_2 \\ \\ m_1u_1-\frac{3(m_1u_1)}{2}=\frac{2m_1v_1+m_1v_2}{2} \\ \\ \frac{2m_1u_1-3m_1u_1}{2}=\frac{2m_1v_1+m_1v_2}{2} \\ \\ -m_1u_1=2m_1v_1+m_1v_2 \\ \\ m_1v_2=-m_1u_1-2m_1v_1 \\ \\ v_2=\frac{-m_1(u_1+2v_1)}{m_1} \\ \\ v_2=-(u_1+2v_1) \\ \\ \end{gathered}[/tex]From the last equation, make v₁ the subject of the formula instead
[tex]\begin{gathered} v_2=-(u_1+2v_1) \\ \\ v_2=-u_1-2v_1 \\ \\ 2v_1=u_1-v_2 \\ \\ v_1=\frac{u_1-v_2}{2} \\ \\ \end{gathered}[/tex]A football is punted at an angle with a velocity of 29.2 m/s. If the ball has a total hangtime of 6.7 how long does it take to reach the top of the trajectory?
Answer:
So your gonna have to calculate the speed
Explanation:
how far could you pedal a bicycle at 15 km/hkm/h on the energy in 3.0 galgal of gas? (1 galgal of gas has a mass of 3.2 kgkg .)
The amount of effort or energy transferred over a given period of time is referred to as an object's mechanical power. The SI unit for mechanical power is WATT. It is a scalar number.
What does a gallon of gasoline cost?3.7855 litres
A gallon is equal to 3.785 liters, 128 fluid ounces, 4 quarts, 8 pints, or 16 cups in American measures.
What's the weight of a gallon of gas?A gallon of regular fuel (like gasoline) weighs six pounds, according to the Science and Technology Desk Reference. Contrarily, a gallon of water weighs around 8.4 pounds.
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If you start with 500g of water in your pot, and after it boils away, the steam takes up 2 m3 of space, what is the density of the steam in g/m3?
Density of the steam will be 250 g/m³
What is density?Density (volumetric mass density or specific mass) is the mass of matter per unit volume. The most common symbol for density is ρ (lowercase Greek letter rho), but the Latin letter D can also be used. Mathematically, density is defined as:
Density = [tex]\frac{Mass}{Volume}[/tex]
Or ρ = [tex]\frac{m}{V}[/tex]
Where ρ = density, m = mass, and V = volume.
The density of matter changes with temperature and pressure. This variation is typically small for solids and liquids and much larger for gases. Increasing the pressure on an object decreases the volume of the object, thus increasing its density. Increasing the temperature of a substance (with some exceptions) increases its volume and decreases its density. In most materials, heating the bottom of the liquid causes convection of heat from the bottom to the top as the density of the heated liquid decreases, increasing the density compared to a denser, unheated material.
Given,
Mass of water evaporated = 500g
Volume of steam = 2m³
Density = [tex]\frac{500}{2}[/tex]
Density = 250 g/m³
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How much work is done pushing a block 200 m with a force of 30 newtons?
A 1000 n crate is lifted to a height of 3. 0 m. How much work is done to lift the crate?.
The work done in lifting a 1000 N crate 3.0 m high is 3000 Joules (J).
Here, we have been told that the mass of the crate is = 1000 N (i)
We have to lift up the crate to a height of = 3.0 m (ii)
The mass of the crate is given here in Newtons which is also the SI unit of Force.
We know that work is the product of force and distance moved in the direction of the force. The formula used for calculating the work done is
= W = Force * Distance moved (iii)
Using the values of (i), (ii) and putting them in the given formula (iii), we get = W = (1000)*(3)
= W = 3000 Joules
Therefore, we know that the work done in lifting a crate of mass/force to a height of 3.0 m is 3000 J.
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How much energy is required to freeze 20 ml of water already at 0.0 0C?
Given
Amount of water,
[tex]m=20\text{ ml}[/tex]Temperature is,
[tex]T=0.00C[/tex]To find:
Energy required to freeze the water.
Explanation:
The latent heat of fusion is
[tex]L=33.5\times10^4\text{ J/}kg[/tex]Converting the amount of water to kg,
[tex]m=0.020kg[/tex]Thus the energy required is:
[tex]\begin{gathered} H=mL \\ \Rightarrow H=0.020\times33.5\times10^4=0.67\times10^4J \end{gathered}[/tex]Conclusion:
The amount of energy required is
[tex]0.67\times10^4J[/tex]Consider a father pushing a child on a playground merry-go-round. The system has a moment of inertia of 84.4 kg • m2. The father exerts a force on themerry-go-round perpendicular to its radius to achieve an angular acceleration of 4.44 rad/s2.(a) How long (in s) does it take the father to give the merry-go-round an angular velocity of 2.29 rad/s? (Assume the merry-go-round is initially atrest.)S(b) How many revolutions must he go through to generate this velocity?revolutions(C) If he exerts a slowing force of 270 N at a radius of 1.25 m, how long (in s) would it take him to stop them?s
a)
Since we have a constant angular acceleration we have that:
[tex]\alpha=\frac{\omega-\omega_0}{t}[/tex]Plugging the values we know we have that:
[tex]\begin{gathered} 4.44=\frac{2.29-0}{t} \\ t=\frac{2.29}{4.44} \\ t=0.516 \end{gathered}[/tex]Therefore it will take 0.516 (rounded to three decimals) seconds to achive this angular velocity.
b)
To find how many revolutions he needs we first calculate the change in angular position using the formula:
[tex]\begin{gathered} \omega^2-\omega^2_0=2\alpha(\theta-\theta_0) \\ (\theta-\theta_0)=\frac{\omega^2-\omega^2_0}{2\alpha} \\ (\theta-\theta_0)=\frac{2.29^2-0^2}{2(4.44)} \\ (\theta-\theta_0)=0.590551801 \end{gathered}[/tex]Now we divide this change in angular position by 2pi (the angle equivalent to a revolution) to get the revolutions:
[tex]\frac{0.590551801}{2\pi}=0.094[/tex]Therefore it takes 0.094 (round to three decimals) revolutions to get to this angular velocity.
c)
The torque is the force by the radius, then we have:
[tex]\tau=(270)(1.25)=337.5[/tex]But the torque is also equal to the moment of inertia multiplied by the angular acceleration:
[tex]\tau=I\alpha[/tex]Then we have:
[tex]\begin{gathered} 337.5=84.4\alpha \\ \alpha=\frac{337.5}{84.4} \\ \alpha=3.998815166 \end{gathered}[/tex]Now we use the formula for angular acceleration to get the time:
[tex]\begin{gathered} -3.998815166=\frac{0-2.29}{t} \\ t=\frac{-2.29}{-3.998815166} \\ t=0.573 \end{gathered}[/tex]Therefore it takes 0.573 seconds to stop the merry go round.
A baby elephant trots in a straight line along river. The horizontal position of the elephant in meters over time is shown below. Questions: 1. What is the displacement of the elephant between 8 s and 24 s ?2. What is the distance traveled by the elephant between 8s and 24s?
looking at the graph,
1) Displacement includes direction
Displacement from 8s to 16s = 15 - 6 = 9
Displacement fbetween 16s and 24s = 0 - 15 = - 15
Displacemet between 8s and 24s = 9 - 15
Displacemet between 8s and 24s = - 6m
2)
Distance does not include direction
from 8s to 16s,
distance travelled = 15 - 6 = 9 m
From 16s to 24s,
distance travelled = 15 - 0 = 15
Total distance between 8s and 24s = 9 + 15
Total distance between 8s and 24s = 24 m