We will have the following:
First, we recall that momentum is given by:
[tex]m_1v_0+m_2v_0=m_1v_1+m_2v_2[/tex]So:
[tex]\begin{gathered} (60kg)(0m/s)+(80kg)(0m/s)=(60kg)v_1+(80kg)v_2 \\ \\ \Rightarrow v_1=\frac{-(80kg)v_2}{(60kg)}\Rightarrow v_1=-\frac{4}{3}v_2 \end{gathered}[/tex]Then:
[Let's assume that when astronaut 2 moved 12 meters = t]
[tex]\begin{gathered} x_1=v_1t\Rightarrow x_1=-\frac{4}{3}v_2t \\ \\ x_2=v_2t\Rightarrow t=\frac{12}{v_2} \end{gathered}[/tex]Then:
[tex]x_1=-\frac{4}{3}v_2\ast\frac{12}{v_2}\Rightarrow x_1=-16m[/tex]Finally, the total distance will be:
[tex]\begin{gathered} d=|x_1|+|x_2|\Rightarrow d=16m+12m \\ \\ \Rightarrow d=28m \end{gathered}[/tex]Jack is selling lemonade at a stand outside his house. He is charging $1.50 per cup. He needs to make at least enough money to cover the cost of his supplies, which were $15.25.What is the minimum number of cups of lemonade Jack needs to sell?
Given,
Charge of one cup of lemonade, c=$1.50
The amount Jack needs, T=-$15.25
The number of cups Jack needs to sell in order to have the given amount can be calculated as,
[tex]N=\frac{T}{c}[/tex]On substituting the known values,
[tex]\begin{gathered} N=\frac{15.25}{1.5} \\ =10.17 \end{gathered}[/tex]The number of cups of lemonade that can be sold should be a whole number. If Jack sells 10 cups, which is lesser than the answer, he will have less amount than he wanted.
Thus he has to sell 11 cups.
Therefore the minimum number of cups Jack needs to sell is 11.
Answer: I have all answers in screen shots
Hope this helps
Gamma rays require _____ to be stopped.1) paper2) glass3) aluminum4) lead
The gamma rays are having very large frequency. Thus, the energy acquired by the gamma ray photons is very large.
To stop the gamma ray, highly dense material is required.
The density of the lead is more than any other element in the given opitons.
Thus, the lead is used to stop the gamma rays.
Hence, 4th option is the correct answer.
Match each expression on the left with an equivalent expression on the right. Some answer choices on the right will not be used.1/50.451/80.6259/203/40.1250.24/55/8
1/5 = 0.2
1/8 = 0.125
9/20 = 0.45
3/4 = 0.75
4/5 = 0.8
5/8 = 0.625
Explanations:This exercise is to convert the given fractions to decimals
Let us find the decimal equivalents of each of the fractions first, then the equivalent choices can be matched together
1/5 = 0.2
1/8 = 0.125
9/20 = 0.45
3/4 = 0.75
4/5 = 0.8
5/8 = 0.625
A turkey with a mass of 9kg is running straight at you with a velocity of 5 m/s.What is the momentum of the turkey?
Given,
The mass of the turkey, m=9 kg
The velocity of the turkey, v=5 m/s
The momentum of a body is given by the product of the mass of the body and its velocity.
Thus the momentum of the turkey is given by,
[tex]p=mv[/tex]On substituting the known values,
[tex]p=9\times5=45\text{ kg}\cdot\frac{m}{s}[/tex]Thus, the momentum of the turkey is 45 kg·m/s
The picture below shows a skateboarder just before he drops down a ramp. Assume the skateboarder does not experience any friction.Which correctly shows the potential energy and kinetic energy of the skateboarder as he moves down the left side of the ramp and up to the top of the right side?
We are given that a skater is on top of a ramp. At this point the skater has the maximum gravtitaional potential energy "PE" and a minimum kinetic energy "KE". The gravitational potential enery depends on the height of the skater and the kinetic energy depends on his velocity.
When the skater is at the bottom of the ramp his gravitational potential energy is minimum since his height is the lowest and his kientic energy is maximum since all the gravitational potential eerngy has turn into kinetic energy. This means that at the lowest point the velocity is also maximum.
Whe teh sketer reaches the highest point in the right side his kinetic energy has converted again into gravitational potential energy since the height has increased. Now, the kinetic energy is minimum and the gravitational potential energy is maximum.
This can be seen represented next:
The graph should be a representation of the fluctuations in kinetic and potential energy, therefore, the only graph that represetns this is B.
Describe the cause of waves as a fluid motion
Wind is the most frequent cause waves. The friction between the wind and the surface of the water produces wind-driven waves, also known as surface waves. A wave crest is produced when wind continuously disturbs the water's surface in an ocean or lake.
Waves that include longitudinal and transverse motions include water waves, for instance. The particles move in clockwise rings through the waver as a wave passes over it. The circles' radius gets smaller the deeper into the ocean you go.The disturbance propagates through the medium as a result of the medium's particles oscillating repeatedly and periodically about their equilibrium position. Without any real transfer of the medium's particles, energy and momentum are moved from one place to another.To know more about waves
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1. what is the range of the infrared part of the electromagnetic spectrum A.microwaves to red light B.radio waves to microwavesC. X-rays to gamma raysD. ultraviolet to x-rays
The range of the infrared wave is from the red to the microwave.
the rannge of wavelength of the infrared is ,
[tex]2-14\mu m[/tex]Hence, A is the correct option.
I need help with questions number 2 I have the answer to number 1
Given,
the distance from Redd's door to the park, s=15 m
The total distance is the sum of the distance from her door to the park and the distance from the park to her door.
That is,
[tex]\begin{gathered} \text{total distance}=s+s \\ =15+15 \\ =30\text{ m} \end{gathered}[/tex]The displacement is defined as the shortest distance from the starting and ending point of a path. The starting and ending point of Redd's path is the door.
Therefore the total displacement is zero meters.
Therefore, distance = 30 m
and displacement = 0 m
An aluminum sphere is 8.55 cm in diameter. What will be it's % change in volume if it is heated from 30 C to 155 C?
We know that
• The sphere diameter is 8.55 cm.
,• The temperature change is from 30 C to 155 C.
First, we have to find the radius of the sphere. The radius is the half diameter.
[tex]\begin{gathered} r=\frac{d}{2}=\frac{8.55\operatorname{cm}}{2} \\ r=4.275\operatorname{cm} \end{gathered}[/tex]Now we have to find the volume of the sphere using the following formula.
[tex]V=\frac{4}{3}\pi(r)^3[/tex]Where r = 4.275 cm.
[tex]\begin{gathered} V=\frac{4}{3}\pi(4.275\operatorname{cm})^3 \\ V\approx327.26(cm)^3 \end{gathered}[/tex]Then, we use the following formula
[tex]V_2-V_1=BV_0(T_2-T_1)[/tex]Where the initial volume is 327.26 cubic cm, B is a constant about thermal expansion for aluminum, and we have to find the final volume to then calculate the percentage change.
[tex]\begin{gathered} \Delta V=75\times10^{-6}\cdot327.26(155-30) \\ \Delta V=75\times10^{-6}\cdot327.26(125) \\ \Delta V\approx3.07(cm)^3 \end{gathered}[/tex]This means that the volume change is 3.07 cubic centimeters.
At last, we have to divide the volume change by the initial volume, and then we have to multiply it by 100% to express it as a percentage.
[tex]\frac{\Delta V}{V_1}\times100=\frac{3.07}{327.26}\times100\approx0.938[/tex]Therefore, the percentage change is 0.938%.Can you help me with this question? Find the sum of -2x^2 - 4x - 12 and - x^2 - 2x The answer I got was -3x^2 - 6x - 12 Just want to see if I did it correctly*Last tutor got disconnected
You have the following sum of expression:
(-2x^2 - 4x - 12) + (-x^2 - 2x)
In order to find the sum, simplify like terms (terms with the same variable and same exponent). Then, you have:
(-2x^2 - 4x - 12) + (-x^2 - 2x) =
-2x^2 - x^2 - 4x - 2x -12 =
-3x^2 - 6x - 12
Hence, the answer is -3x^2 - 6x - 12
A strobe-light series of pictures is taken of a red ball and a blue ball. The red ball was allowed to drop straight down, and the blue ball was given an initial horizontal velocity. Lines are drawn connecting each red ball image with the corresponding blue ball image. Describe the lines connecting the images.1) The lines slope down from the red ball to the corresponding blue ball.2) The lines slope up from the red ball to the corresponding blue ball.3) The lines are vertical.4) The lines are horizontal.
The lines are horizontal.
Horizontal velocity doesn't have any effect on the acceleration or speed of falling. In every picture, the red and the blue are both at the same HEIGHT, even though the blue one is pulling away horizontally.
I need to know how to do these and the formula too.
Answer:
a = 4m kgm/s & b. v = 4 m/s
Explanation:
a:
A is approaching in the opposite direction of B
So let's take the velocity of A as negative.
Here we'd need to solve this using conservation of momentum.
m1u1 + m2u2 = m1v1 + m2v2
So initial momentum = (m X (-4)) + (m X 8) = -4m + 8m = 4m
b:
After collision sphere A stops, so v = 0 for sphere A
Using the conservation of momentum formula, we get
(m X (-4)) + (m X 8) = (0 X m) + (m X v) [let the final velocity of B be v]
⇒ 4m = vm
⇒ v = 4 m/s
The barrel of a rifle has a length of 0.983m. A bullet leaves the
muzzle of a rifle with a speed of 602m/s. What is the
acceleration of the bullet while in the barrel? A bullet in a rifle
barrel does not have constant acceleration, but constant
acceleration is to be assumed for this problem.
Answer in units of m/s^2
According to the solving, the acceleration of the bullet while in the barrel is 184335.7 m/s^2.
What is acceleration?Any action where the velocity changes are said to it as acceleration. There are only two ways to accelerate: altering your speed or altering your direction, or altering both. This happens because velocity is both a speed and a direction.
According to the given data,
The length of the barrel of the rifle is 0.983 m.
The speed of the bullet is 602m/s.
We know,
v^2 = u^2+ 2aS
Initial velocity, u=0
v=602m/s.
S= 0.983 m.
So,
v^2=u^2+2aS
(602)^2= 0+ 2*a*0.983
1.966a=362404
a=362404/1.966
a= 184335.7 m/s^2.
According to the solving, the acceleration of the bullet while in the barrel is 184335.7m/s^2.
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URGENT!! ILL GIVE
BRAINLIEST!!!! AND 100 POINTS!!!!!!
Answer:
First option
Explanation:
The battery contains chemicals and the electrical energy will be produced FROM those chemicals and then when it goes into the bell the bell uses that energy to turn into sound using an electromagnet
Answer: chemical energy from the battery will be transformed into electricity energy which is this Transformer by the Dell to the security energy
Explanation:
You have been given 3.152 g of copper from which you are to fashion a wire whose resistance is 2,473.562 ohms. The density of copper is 8900 kg/m 3 and the resistivity of copper is 1.7 x 10 -8 ohm m. What will the diameter, in mm, of the wire be that you fashion?
Given:
Mass of copper, m = 3.152 g = 0.003152 kg
Resistance = 2,473.562 ohms
Density of copper = 8900 kg/m³
Resistivity of copper = 1.7 x 10⁻⁸ ohm.m
Let's find the diameter of the wire.
Apply the density formula to find the volume:
[tex]\begin{gathered} \rho=\frac{m}{v} \\ \\ v=\frac{m}{\rho}=\frac{0.003152}{8900} \\ \\ v=3.54*10^{-7}\text{ m}^3 \\ \\ (\pi r^2)l=3.54*10^{-7}\text{ m}^3 \end{gathered}[/tex]Now, apply the formula:
[tex]\begin{gathered} R=\frac{\rho l}{A} \\ \\ l=\frac{RA}{\rho} \\ \\ l=\frac{2473.562*\pi r^2}{1.7*10^{-8}} \\ \\ \frac{l}{\pi r^2}=\frac{2473.562}{1.7*10^{-8}} \\ \\ \frac{l}{\pi r^2}=1.455*10^{11} \\ \\ l=1.455*10^{11}*\pi r^2 \end{gathered}[/tex]Now, combine both expressions for L:
[tex]1.455*10^{11}*\pi r^2*\pi r^2=3.54*10^{-7}[/tex]Solving further:
[tex]\begin{gathered} (\pi r^2)^2=\frac{3.54*10^{-7}}{1.455*10^{11}} \\ \\ (\pi r^2)=\sqrt{2.434*10^{-18}} \\ \\ \pi r^2=1.56*10^{-9} \\ \\ r^2=\frac{1.56*10^{-9}}{\pi} \\ \\ r=\sqrt{\frac{1.56*10^{-9}}{\pi}} \\ \\ r=2.228*10^{-5} \end{gathered}[/tex]r is the radius.
We know that:
Diameter = 2 x radius
Thus, we have:
[tex]\begin{gathered} d=(2.228*10^{-5})*2 \\ \\ d=4.4569*10^{-5}\text{ m} \\ \\ d=0.044569*10^{-3}m \\ \\ d=0.0446\text{ mm} \end{gathered}[/tex]Therefore, the diameter in mm will be 0.0446 mm
ANSWER:
0.0446 mm
The neutrons within the nucleus of an atom have what charge?Question 15 options:negativesame as an electronsame as a protonno charge
The nuclues of an atom contains the proton and the nuetron. The proton is positively charged while the nuetron has no charge.
Lorem ipsum dolor sit amet, consectetur adipiscing elit, sed do eiusmod tempor incididunt ut labore et dolore magna aliqua. Ut enim ad minim veniam, quis nostrud exercitation ullamco laboris nisi ut aliquip ex ea commodo consequat.
Here is the answer of a tutor
Take a look.
[tex]\sqrt[2]{24+5}[/tex]Near the top of the Citigroup Center building in New York City, there is an object with mass of 4.00 ✕ 105 kg on springs that have adjustable force constants. Its function is to dampen wind-driven oscillations of the building by oscillating at the same frequency as the building is being driven—the driving force is transferred to the object, which oscillates instead of the entire building.(a) What effective force constant (in N/m) should the springs have to make the object oscillate with a period of 2.10 s? N/m(b) What energy (in J) is stored in the springs for a 1.80 m displacement from equilibrium? J
ANSWERS
(a) 3.58 x 10⁶ N/m
(b) 5.8 x 10⁶ J
EXPLANATION
Given:
• The mass of the object hanging from the spring, m = 4.00 x 10⁵ kg
Find:
• (a), The force constant the springs should have to make the object oscillate with a period of 2.10 s
,• (b), The energy stored in the springs for a 1.80 m displacement from equilibrium.
(a) The period of an object in a spring is,
[tex]T=2\pi\sqrt{\frac{m}{k}}[/tex]Where m is the mass of the object and k is the spring constant.
We want to find k for T = 2.10 s, so we have to solve this equation for k, which gives us,
[tex]k=m\cdot\left(\frac{2\pi}{T}\right)^2[/tex]Replace the known values and solve,
[tex]k=4\cdot10^5\cdot\frac{4\pi^2}{(2.1)^2}\approx3,580,808.85N/m\approx3.58\cdot10^^6N/m[/tex]Hence, the force constant is 3.58 x 10⁶ N/m.
(b) The energy stored in a spring with force constant k when the mass is displaced x meters from equilibrium is,
[tex]U_s=\frac{1}{2}kx^2[/tex]Replace the known values and solve to find the energy stored in this spring,
[tex]U_s=\frac{1}{2}\cdot3.58\cdot10^6N/m\cdot1.8^2m^2\approx5.8\cdot10^6J[/tex]Hence, the energy stored in the spring for a 1.80 m displacement from equilibrium is 5.8 x 10⁶ J.
Bluetooth and Wi-Fi use the same frequency band. Give one reason why Bluetooth signal does not interfere with Wi-Fi signal.
There is interference between both signals especially if they are operated in same time and space. The technology that bluetooth uses helps reduce interference from wifi signals. This technoogy is called the frequency hopping spread spectrum which changes channel frequency. This only reduces interference.
This week we discuss injuries to the head, neck and spine. There are so many long term affects of so many different head injuries. One of the biggest changes to head injuries that we have seen in the last decade is the implementation of concussion protocol. No matter the age or activity, the medical world has a recommended protocol for possible concussions and any head injury.
This weeks assignment. Research concussion protocol and submit the following in a written paper format.
-What is a concussion?
-Why do we need to have a concussion protocol?
-Who needs a concussion protocol? This is in regards to caring for injuries, not the injured person itself,
-Is there a standard concussion protocol should you follow? What is it?
-At a minimum, concussion protocol steps should include the what people in the process?
-Have you or anyone you know had to follow concussion protocol for a head injury? Tell me about it.
This is due Sunday I want to get started on it please someone help me ?
Answer:
Concussion is the most common type of mild traumatic brain injury and can have serious consequences
Explanation:
A vector has the components Ax=22 m and Ay=13 m. What is the magnitude of thisvector? What angle does this vector make with the positive x axis?
Answer:
Magnitude = 25.55 m
Angle = 30.58 degrees
Explanation:
If the vector has the components Ax = 22 and Ay = 13, we can represent the vector as:
Therefore, the magnitude of this vector is the magnitude of the red vector. It means that we can calculate its length using the Pythagorean theorem where 22 and 13 are the legs, so:
[tex]\sqrt[]{Ax^2+Ay^2}=\sqrt[]{22^2+13^2}=\sqrt[]{484+169}=\sqrt[]{653}=25.55\text{ m}[/tex]Then, we can find the angle using the trigonometric function tangent, so:
[tex]\begin{gathered} \tan \theta=\frac{Ay}{Ax} \\ \tan \theta=\frac{13}{22} \\ \tan \theta=0.5909 \\ \theta=\tan ^{-1}(0.5909) \\ \theta=30.58 \end{gathered}[/tex]So, the answers are:
Magnitude = 25.55 m
Angle = 30.58 degrees
Two skaters with the same mass face each other standing still. Both skaters push off each other and they love in opposite directions. What’s the momentum before pushing off? Total momentum after pushing off? Momentum of each in comparison to each other after pushing off
We will have the following:
Total momentum before pushing each other off: 0.
Total momentum after pushing each other off: 0.
Momentum of each other after pushing off in comparison to each other:
*Person 1: A positive value.
*Person 2: A negative value of equal magnitude to the momentum of person 1.
How much work must you do to stretch the spring 0.030 m ? and how much work must you do to compress it 0.030m ?
Given:
The force constant of spring is
[tex]k\text{ =2.5}\times10^4\text{ N/m}[/tex]To find the work done when spring is stretched to 0.03 m and work done when compressed to 0.03 m.
Explanation:
The work done to stretch the spring will be
[tex]\begin{gathered} W\text{ =}\frac{1}{2}kx^2 \\ =\frac{1}{2}\times2.5\times10^4\times(0.03)^2 \\ =\text{ 11.25 J} \end{gathered}[/tex]The work done to compress the spring will be
[tex]\begin{gathered} W\text{ =-}\frac{1}{2}kx^2 \\ =-\frac{1}{2}\times2.5\times10^4\times(0.03)^2 \\ =-11.25\text{ J} \end{gathered}[/tex]When you describe a metal surface as smooth, what property are youdescribing?7O A. ColorO B. HardnessO C. ShapeO D. TextureSUBMIT
Answer: D. Texture
Explanation:
Texture is used to describe the characteristics of a surface. A surface can be described as smooth or rough. Thus, the correct option is
D. Texture
a car travels 680 km in a time of 4 h calculate its speed
Hello..!
To calculate its speed we apply the following data.
Data:
D = 680kmT = 4hrsV = ?Then, we apply the formula that is.
Formula:
V = D/TFinally we develop the problem.
Developing:
V = 680km / 4hV = 170km/hThe speed of the car is 170 kilometers per hour.
A girl weighs 58kg and runs up a staircase 52m high in 23seconds. Find her minimum power output
Given,
The mass of the girl, m=58 kg
The height of the staircase, h=52 m
The time she takes to run up the staircase, t=23 s
The work the girl does to climb up the staircase is equal to the change in the potential energy of the girl.
Thus the work done is given by,
[tex]W=\text{mgh}[/tex]Where g is the acceleration due to gravity.
On substituting the known values,
[tex]\begin{gathered} W=58\times9.8\times52 \\ =29.56\times10^3\text{ J} \end{gathered}[/tex]The power output is equal to the rate at which the work is done
Thus the power output is given by,
[tex]P=\frac{W}{t}[/tex]On substituting the known values,
[tex]\begin{gathered} P=\frac{29.56\times10^3}{23} \\ =1285.22\text{ W} \end{gathered}[/tex]Thus the maximum power output is 1285.22 W
Traumatic brain Injury such as concussion results when the undergoes very large acceleration Generally an than 800 m/s ^ 2 lasting for any length of time will not , whereas an acceleration greater than 1, 000 m/s ^ 2 for at least 1 injury. Suppose a small child rolls off a bed that is 0.47 m above the floor. If the floor is hardwood the child’s head is brought to rest in approximately 2.1 mm. If the floor is carpeted,this stopping distance is increased to about 1.3 cm . Calculate the magnitude and duration of the deceleration in both cases, to determine the risk of injury. Assume the child remains horizontal during the fall to the floor. Note that a more complicated fall could result in a head velocity greater or less than the speed you calculate. Hardwood floor magnitude m/s^2Hardwood floor duration msCarpeted floor magnitude m/s^2Carpeted floor duration ms
ANSWER:
Hardwood floor magnitude: 2193.15 m/s^2
Hardwood floor duration: 1.38 ms
Carpeted floor magnitude: 354.27 m/s^2
Carpeted floor duration: 8.56 ms
STEP-BY-STEP EXPLANATION:
We have the following information:
Distance of the bed from the floor: 0.47 m
Stopping distance by hardwood: 2.1 mm
Stopping distance by carpet: 1.3 cm
We must find the speed of the child when he hits the ground using the following formula:
[tex]v^2=u^2+2gh[/tex]Where v is the final velocity, u is the initial velocity, g is the gravitational acceleration and h is the distance traveled.
Replacing and solving for v
[tex]\begin{gathered} v^2=0^2+2\cdot9.8\cdot0.47 \\ v=\sqrt[]{9.212} \\ v=3.035\text{ m/s} \end{gathered}[/tex]We can find the deceleration provided by the hardwood when stopping the child using the formula:
[tex]v^2=u^2-2aS[/tex]Since the child will stop, the final speed will be 0, the initial speed will be the speed gained by the child while falling that we found in the first step, and the distance S to stop is given in the question.
Replacing and solving for a:
[tex]\begin{gathered} 2.1\text{ mm }\cdot\frac{1\text{ m}}{1000\text{ mm}}=2.1\cdot10^{-3}m \\ 0^2=3.035^2-2\cdot a\cdot(2.1\cdot10^{-3}) \\ 2\cdot a\cdot(2.1\cdot10^{-3})=9.211 \\ a=\frac{9.211}{2\cdot(2.1\cdot10^{-3})} \\ a=2193.15\text{ }\frac{m}{s^2} \end{gathered}[/tex]From the calculated deceleration, we can find the time it takes for the child to stop after hitting the hardwood using the formula:
[tex]\begin{gathered} v=u-at \\ \text{replacing and solving for t:} \\ t=\frac{v-u}{-a} \\ t=\frac{0-3.035}{-2193.15} \\ t=0.00138\text{ s} \\ t=1.38\text{ ms} \end{gathered}[/tex]We repeat the same procedure but now with the data of the carpet, therefore:
[tex]\begin{gathered} 1.3\text{ cm }\cdot\frac{1\text{ m}}{100\text{ cm}}=1.3\cdot10^{-2}m \\ 0^2=3.035^2-2\cdot a\cdot(1.3\cdot10^{-2}) \\ 2\cdot a\cdot(1.3\cdot10^{-2})=9.211 \\ a=\frac{9.211}{2\cdot(1.3\cdot10^{-2})} \\ a=354.27\text{ }\frac{m}{s^2} \end{gathered}[/tex]Time for stopping by the carpet:
[tex]\begin{gathered} t=\frac{v-u}{-a} \\ t=\frac{0-3.035}{-354.27} \\ t=0.00856\text{ s} \\ t=8.56\text{ ms} \end{gathered}[/tex]A cyclist advances 38 km in 1 hour and 30 minutes. Your average speed was: Select one: 47 0 25.3 km/h OR 22 km/h OR 18 km/h OR 38 km/h
Hello..!
We initially apply the data to the problem.
Data:
D = 38kmT = 1.5hV = ?Then, we apply the formula that is.
Formula:
V = D/TFinally we develop the problem.
Developing:
V = 38km / 1.5hV = 25.3km/hTherefore the correct option is 25.3 kilometers per hour.
Answer:
Formula
V = d/tResolve
V = 38km / 1.5hV = 25.3 km/hHope this helped
b)= combined resistance of the 2 Ω and 4 Ω resistors connected in series
R1=6 Ω
R2=3 Ω
R3=2 Ω
R4=4 Ω
6 Ω and 3Ω resistances are connected in parallel.
First, find the equivalent resistance:
ER1 = R1*R2/(R1+R2)= 6*3/6+3 = 18/9 = 2Ω
The resistances of 2 Ω and 4 Ω are connected in series:
TR2 = R3+R4 = 2 Ω+4 Ω= 6 Ω (b)
ER1 and TR2 are connected in parallel.
RT = ER1*TR2/ ER1+TR2= 2*6/2+6=12/8 = 1.5 Ω
Now, we can calculate the I (current)
On parallel circuits, Voltage is always the same. (12V)
But for series is VT=V1+V2
We have to find the current flowing across R3 and R4 (TR2)
V= I*R
I= V/R = 12/TR2= 12/6 = 2 A
With that current, we can calculate the voltage (potential difference) on R3 (2 Ω)
V=I*R= 2*2 = 4V (ai)
(aii) potential difference across the 3 Ω resistor
Since it is a parallel circuit , potential difference is always the same = 12V
b.combined resistance of the 2 Ω and 4 Ω resistors connected in series
R3+R4 = 2 Ω+4 Ω= 6 Ω (b)
A block of aluminum weighing 140 g is cooled from 98.4°C to 62.2°C with the release of 1080 joules of heat. From this data, calculate the specific heat of aluminum.Group of answer choices2.11 J/g °C4.29 J/g °C0.213 J/g °C
213 J/g °C is the specific heat of aluminum when a block of aluminum weighing 140 g is cooled from 98.4°C to 62.2°C with the release of 1080 joules of heat.
C=Specific heat
Q=heat energy (J)0.14 K
M =Mass (Kg)
∆T= change in temperature (K)
M= 140 g = 0.14Kg
Q - 1080 Joules.
∆T=98.4 – 62.2 = 36.2
Q=MC∆T
C =Q/M∆T
C= 1080÷0.14×36.2
C=213 J/g °C
The term "specific heat" refers to the quantity that quantifies how a substance's additional heat energy affects its temperature. The unit is J/g °C. It is generally used in Thermodynamics.
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