The question says we should turn into an inequality a speed limit of 65 miles per hour.
This means the speed should'nt be more than 65 miles per hour. In other words the speed shouldn't exceed 65 miles per hour.
Let represent the speed with a. Therefore,
a < 65 miles per hour
a < 65
x to the 9th power times x to the 5 power
What's the sum of ten terms of a finite arithmetic series if the first term is 13 and the last term is 89?
The sum of the n first terms in an arithmetic series is given by the following formula
[tex]S_n=n\cdot(\frac{a_1+a_n}{2})[/tex]Where a_1 represents the first term, a_n represents the n-th term, and n the amount of terms we want to sum.
The first term of our sequence is 13, the tenth term is 89 and the amount of terms is 10. Plugging those values in our formula, we have
[tex]S_{10}=10\cdot(\frac{13+89}{2})=10\cdot51=510[/tex]This sum is equal to 510.
(3,-4); m=6 write an equation in slope intercept form for the line through the given point with the given slope
y= 6x-22
Explanation
Step 1
Let
slope=6
Point (3,-4)
to find the equation in slope intercept form use
[tex]\begin{gathered} y-y_0=m(x-x_0) \\ \text{where} \\ (x_0,y_0)\text{ are the coordinates of the known point} \end{gathered}[/tex]Step 2
Replace,
[tex]\begin{gathered} \text{the know point = (3,-4) so} \\ y-y_0=m\left(x-x_0\right) \\ y-(-4)=6(x-3) \\ y+4=6x-18 \\ \text{substract 4 in both sides} \\ y+4-4=6x-18-4 \\ y=6x-22 \end{gathered}[/tex]I hope this helps you
In a direct variation, y = 18 when x = 6. Write a direct variation equation that shows therelationship between x and yWrite your answer as an equation with y first, followed by an equals signSubmit
Weights of 2-year-old girls are normally distributed with a mean of 253 lbs, and a standarddeviation of 1.12 lbs. According to this information, what weight would be the 33rd percentile? You must
We have here a case of a normally distributed variable. We can solve this kind of problem using the standard normal distribution, and the cumulative standard normal table (available in any Statistic Book, or on the internet).
We have that we can find z-scores to normalized the situation, and then, using the cumulative standard normal table, we can find the percentile. Then, we have:
[tex]z=\frac{x-\mu}{\sigma}[/tex]In this case, we need to find the raw value, x. We need to find a z-score that represents that before it there are 33% of the cases for this distribution: in this case, the value for z is approximately equal to z = -0.44.
Now, we have the mean (253 lbs), and the standard deviation (1.12 lbs):
[tex]-0.44=\frac{x-253}{1.12}[/tex]And now, we can determine the value, x, which is, approximately, the 33% percentile of this normal distribution:
1. Multiply by 1.12 to both sides of the equation:
[tex]1.12\cdot(-0.44)=\frac{1.12}{1.12}\cdot(x-253)\Rightarrow-0.4928=x-253[/tex]2. Add 253 to both sides of the equation:
[tex]-0.4928+253=x-253+253\Rightarrow252.5072=x\Rightarrow x=252.5072[/tex]Therefore, the weight that would be the 33rd percentile, is, approximately, x= 252.5072 or 252.51lbs (rounding to the nearest hundredth).
Triangle MNO was reflected over the x-axis Given M(-5,-1)Find the coordinate M
When we perform the reflection of a figure over the x-axis, we just have to change the sign of the y-coordinate of each point, like this: P(x,y) -> P'(x,-y).
Then after a reflection of the triangle, the point M goes from (-5,-1) to (-5, 1)
Then the correct answer is the last option (-5, 1)
show that the triangles are similar by measuring the lengths of their sides and comparing the ratios of their corresponding sides
ANSWER
EXPLANATION
The ratio between corresponding sides of similar triangles is constant - in other words, the ratio between each pair of corresponding sides gives the same value.
As shown in the questions, the ratios between corresponding sides are,
[tex]\begin{gathered} \frac{DE}{AB}=\frac{3}{2}=1.5 \\ \frac{DF}{AC}=\frac{1.5}{1}=1.5 \\ \frac{EF}{BC}=\frac{2.4}{1.6}=1.5 \end{gathered}[/tex]Since the three ratios between corresponding sides are the same, 1.5, the triangles are similar.
this temperature to Fahrenheil. 1.3 If 1 cm'- 1 ml and 1 000 cm -1 4. Determine the following: 1.3.1 How many cm' are in 875 ? 1.3.2 How many t are there in 35,853 cm'?
We will solve it as follows:
1.3.1: We transform liters to cubic centimeters:
[tex]x=\frac{875\cdot1000}{1}\Rightarrow x=875000[/tex]So, there are 875 000 cubic centimeters.
1.3.2: We transfrom cubic centimenters into liters:
[tex]x=\frac{1\cdot35853}{1000}\Rightarrow x=35.853[/tex]So, there are 35.853 liters.
Round $43,569.14 the nearest dollar
To find:
Round $43,569.14 the nearest dollar
Solution:
The number after the decimal is less than 50. So, the amount $43,569.14 rounded to the nearest dollar is $43,569.
Thus, the answer is $43569.
A principal of S2400 is invested at 8.75% interest compounded annually How much will the investment be worth after 7 years?
Explanation
The question wants us to determine the amount $2400 will yield after 7 years if compounded annually at a rate of 8.75%
To do so, we will use the formula:
[tex]\begin{gathered} A=P(1+r)^t \\ where \\ P=\text{ \$2400} \\ r=8.75\text{ \%=}\frac{8.75}{100}=0.0875 \\ t=7 \end{gathered}[/tex]Thus, if we substitute the values above we will have
[tex]\begin{gathered} A=\text{ \$}2400(1+0.0875)^7 \\ A=\text{ }\$2400\lparen1.0875\rparen^7 \\ A=\text{ \$2400}\times1.79889 \\ A=\text{ \$4317.34} \end{gathered}[/tex]Therefore, after 7 years, the investment will be worth $4317.34
Simple Interest Practice P5(A)-2135-7-MATH / Simple Interest 2. What was the original amount deposited on an account with a total amount of $80 in the account after 8 years with a 2% interest rate?
The formula to use for solving simple interest rate problems is:
[tex]i=\text{Prt}[/tex]Where
i is interest accumulated
P is the initial, or principal, amount
r is the rate of interest [in decimal]
t is the time
Given,
Total amount in account is 80 [principal plus interest]
rate is 2%
time is 8 years
Let's write:
[tex]\begin{gathered} 80=P+\text{Prt} \\ 80=P(1+rt) \\ 80=P(1+(0.02)(8)) \\ 80=P(1+0.16) \\ 80=P(1.16) \\ P=\frac{80}{1.16} \\ P=68.9655 \end{gathered}[/tex]The amount in the account was around $68.97
Find from first principles the derivative of f:x maps to (x+2)all squared
Given:
[tex]f(x)=(x+2)^2[/tex]Required:
To find the first principles
Explanation:
First principle,
[tex]\lim_{h\to0}\frac{f(x+h)-f(x)}{h}[/tex][tex]=\lim_{h\to0}\frac{(x+h+2)^2-(x+2)^2}{h}[/tex][tex]=\lim_{h\to0}\frac{x^2+(h+2)^2+2x(h+2)-x^2-4-4x}{h}[/tex][tex]=\lim_{h\to0}\frac{h^2+4+4h+2xh+4x-4-4x}{h}[/tex][tex]\begin{gathered} =\lim_{h\to0}\frac{h^2+4h+2xh}{h} \\ \\ =\lim_{h\to0}\frac{h(h+4+2x)}{h} \\ \\ =\lim_{h\to0}(h+4+2x) \\ =2x+4 \end{gathered}[/tex]Final Answer:
[tex]2x+4[/tex]please help! I don't need a huge explanation I was just wondering if my answer is right
In the expression, there are 3 terms so polynomial is trinomial.
In trinomial the highest degree of term
[tex]10y^5[/tex]is 5. So degree of the polynomial is 5.
Anwer:
Trinomial
Degree is 5.
I need to find the composite function with these two equations. I also need to find the domain.
Recall that:
[tex](f\circ f)(x)=f(f(x)).[/tex]Therefore:
[tex](f\circ f)(x)=f(\sqrt[]{x+2})=\sqrt[]{\sqrt[]{x+2}+2}.[/tex]Now, the above function is well defined as long as x+2 remains positive, therefore, it is well defined as long as x is greater or equal to -2.
Answer: The domain is:
[tex]\lbrack-2,\infty).[/tex]The composition is:
[tex](f\circ f)(x)=f(\sqrt[]{x+2})=\sqrt[]{\sqrt[]{x+2}+2}.[/tex]Val measures the diameter of a ball as 14 inches. How many cubic inches of air does this ball hold, to thenearest tenth? Use 3.14 forn.The ball holds aboutcubic inches of air.
we know that
The volume of the sphere is equal to
[tex]V=\frac{4}{3}\cdot\pi\cdot r^3[/tex]In this problem we have
r=14/2=7 in ----> the radius is half the diameter
pi=3.14
substitute the given values
[tex]\begin{gathered} V=\frac{4}{3}_{}\cdot(3.14)\cdot(7^3) \\ V=1,436.0\text{ in\textasciicircum{}3} \end{gathered}[/tex]answer is 1,436.0 cubic inchesUse a calculator to find θ to the nearest tenth of a degree, if 0° < θ < 360° and sin θ = -0.9945
Solution:
Given:
[tex]\sin \theta=-0.9945[/tex]Using the inverse trigonometric function,
[tex]\begin{gathered} \theta=\sin ^{-1}(-0.9945) \\ \theta=-83.988 \\ \theta\approx-84.0^0\text{ to the nearest tenth} \end{gathered}[/tex]However, since the sine of the angle is negative, it shows that the angle is in the third or fourth quadrant.
Hence, the possible values of the angle are,
[tex]\begin{gathered} \theta=-84+360=276.0^0 \\ \theta=180-(-84)=264.0^0 \end{gathered}[/tex]Therefore, the value of the angle to the nearest tenth of a degree is 264.0 degrees or 276.0 degrees.
The size of a population of bacteria is modeledby the function P, where P(t) gives thenumber of bacteria and t gives the number ofhours after midnight for 0 < t < 10. Thegraph of the function P and the line tangent toP at t= 8 are shown above. Which of thefollowing gives the best estimate for theinstantaneous rate of change of P at t = 8?
Answer: The graph of the P(t) has been provided, we have to find the instantaneous slope of P(t) at t = 8:
[tex]Slope=m=\frac{\Delta y}{\Delta x}=\frac{y_2-y_1}{x_2-x_1}[/tex]Therefore we need two y values and two x values, which can be obtained as follows:
[tex]\begin{gathered} t=8 \\ \\ \therefore\Rightarrow \\ \\ x_1=t_1=8-0.1=7.9 \\ \\ y_1=P(t_1)=P(7.9) \\ \\ x_2=t_2=8+0.1=8.1 \\ \\ y_2=P(t_2)=P(8.1) \\ \\ \therefore\rightarrow \\ \\ Slope=\frac{P(8.1)-P(7.9)}{t_2-t_1}\rightarrow(1) \\ \end{gathered}[/tex]Equation (1) corresponds to the third, option, therefore that is the answer.
ZABC is a right angle.А2197032°Bс
Given that angle ABC is a right angle, then:
21° + x° + 32° = 90°
x = 90° - 21° - 32°
x = 37°
This corresponds to the option: subtract 21° and 32° from 90°, x = 37°.
A researcher wants to study the amount of protein in pet food. Which one of the following is most likely to give theresearcher more accurate results?-take a sample of cat foods alone-take a sample of dog foods alone-take a sample of all pet foods mixed together-divide the pet foods into two different groups, cat and dog, and take a sample from each group
He will need to take sample of at least two different sample of pet food in order to analyze it more accurate. So, the researcher should:
divide the pet foods into two different groups, cat and dog, and take a sample from each group.
NO LINKS!! Use the method of substitution to solve the system. (If there's no solution, enter no solution). Part 11z
Answer:
smaller x value: -1,-8larger x value: 5,16The parenthesis part is already taken care of by the teacher.
=================================================
Explanation:
y is equal to x^2-9 and also 4x-4. We can equate those two right hand sides and get everything to one side like this
x^2-9 = 4x-4
x^2-9-4x+4 = 0
x^2-4x-5 = 0
Then we can use the quadratic formula to solve that equation for x.
[tex]x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x = \frac{-(-4)\pm\sqrt{(-4)^2-4(1)(-5)}}{2(1)}\\\\x = \frac{4\pm\sqrt{36}}{2}\\\\x = \frac{4\pm6}{2}\\\\x = \frac{4+6}{2} \ \text{ or } \ x = \frac{4-6}{2}\\\\x = \frac{10}{2} \ \text{ or } \ x = \frac{-2}{2}\\\\x = 5 \ \text{ or } \ x = -1\\\\[/tex]
Or alternatively
x^2-4x-5 = 0
(x-5)(x+1) = 0
x-5 = 0 or x+1 = 0
x = 5 or x = -1
------------------------------
After determining the x values, plug them into either original equation to find the paired y value.
Let's plug x = 5 into the first equation:
y = x^2-9
y = 5^2-9
y = 25-9
y = 16
Or you could pick the second equation:
y = 4x-4
y = 4(5)-4
y = 20-4
y = 16
We have x = 5 lead to y = 16
One solution is (x,y) = (5,16)
This is one point where the two curves y = x^2-9 and y = 4x-4 intersect.
If you repeat the same steps with x = -1, then you should find that y = -8 for either equation.
The other solution is (x,y) = (-1,-8)
Answer:
[tex](x,y)=\left(\; \boxed{-1,-8} \; \right)\quad \textsf{(smaller $x$-value)}[/tex]
[tex](x,y)=\left(\; \boxed{5,16} \; \right)\quad \textsf{(larger $x$-value)}[/tex]
Step-by-step explanation:
Given system of equations:
[tex]\begin{cases}y=x^2-9\\y=4x-4\end{cases}[/tex]
To solve by the method of substitution, substitute the first equation into the second equation and rearrange so that the equation equals zero:
[tex]\begin{aligned}x^2-9&=4x-4\\x^2-4x-9&=-4\\x^2-4x-5&=0\end{aligned}[/tex]
Factor the quadratic:
[tex]\begin{aligned}x^2-4x-5&=0\\x^2-5x+x-5&=0\\x(x-5)+1(x-5)&=0\\(x+1)(x-5)&=0\end{aligned}[/tex]
Apply the zero-product property and solve for x:
[tex]\implies x+1=0 \implies x=-1[/tex]
[tex]\implies x-5=0 \implies x=5[/tex]
Substitute the found values of x into the second equation and solve for y:
[tex]\begin{aligned}x=-1 \implies y&=4(-1)-4\\y&=-4-4\\y&=-8\end{aligned}[/tex]
[tex]\begin{aligned}x=5 \implies y&=4(5)-4\\y&=20-4\\y&=16\end{aligned}[/tex]
Therefore, the solutions are:
[tex](x,y)=\left(\; \boxed{-1,-8} \; \right)\quad \textsf{(smaller $x$-value)}[/tex]
[tex](x,y)=\left(\; \boxed{5,16} \; \right)\quad \textsf{(larger $x$-value)}[/tex]
simplified (-4+2i)(3-9i)
6 + 42i
Expanding the expression, by using FOIL acronym
(-4+2i)(3-9i)
-12+36i+6i-18i²
-12 +42i -18i² Remember i²= -1
-12 + 42i -18(-1)
-12 + 42i +18
6 + 42i
2) Now we have that complex number in the form a +bi
-
The length of your step is 34 inches (in.). If you walk 10,000 steps in a day, how many feet (ft.) will you walk? ?
In this case, we'll have to carry out several steps to find the solution.
Step 01:
Data
step length = 34 inches
walking = 10000 steps
Step 02:
feet to inches
1 feet = 12 inches
1 step --------------- 34 inches
10000 steps ------- x
1 * x = 10000 * 34
x = 340000
340000 inches * ( 1 feet / 12 inches)
28333.33 feet
The answer is:
You will walk 28333.33 feet .
What is the equation of the line that passes through the given points (2,3) and (2,5)
Solution:
The equation of a line that passes through two points is expressed as
[tex]\begin{gathered} y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1) \\ where \\ (x_1,y_1)\text{ and} \\ (x_2,y_2)\text{ are the coordinates of the points } \\ through\text{ which the line passes} \end{gathered}[/tex]Given that the line passes through the points (2,3) and (2, 5), this implies that
[tex]\begin{gathered} x_1=2 \\ y_1=3 \\ x_2=2 \\ y_2=5 \end{gathered}[/tex]By substitution, we have
[tex]\begin{gathered} y-3=\frac{5-3}{2-2}(x-2) \\ \Rightarrow y-3=\frac{2}{0}(x-2) \\ multiply\text{ through by zero} \\ 0(y-3)=2(x-2) \\ \Rightarrow0=2x-4 \\ add\text{ 4 to both sides} \\ 0+4=2x-4+4 \\ \Rightarrow4=2x \\ divide\text{ both sides by the coefficient of x, which is 2} \\ \frac{4}{2}=\frac{2x}{2} \\ \Rightarrow x=2 \\ \end{gathered}[/tex]Hence, the equation of the line that passes through the given points (2,3) and (2,5) is
[tex]x=2[/tex]which of the following is equivalent to the expression i^41?
The Solution:
Given:
[tex]i^{41}[/tex]Required:
Find the equivalent of the given expression.
[tex]i^{41}=i^{40}\times i^1=i[/tex]Answer:
[option A]
When 27 is subtracted from the square of anumber, the result is 6 times the number. Findthe negative solution.
Given: A statement, "When 27 is subtracted from the square of a
number, the result is 6 times the number."
Required: To determine the number.
Explanation: Let the number be x. Then according to the question-
[tex]x^2-27=6x[/tex]Rearranging the equation as -
[tex]x^2-6x-27=0[/tex]The quadratic equation can be simplified as follows-
[tex]\begin{gathered} x^2-9x+3x-27=0 \\ x(x-9)+3(x-9)=0 \\ (x+3)(x-9)=0 \\ x=-3\text{ or }x=9 \end{gathered}[/tex]Final Answer: The negative solution is-
[tex]x=-3[/tex]What is 6 x 1/4 in the simplest form
Answer:
[tex]6\cdot\frac{1}{4}=\frac{3}{2}[/tex]Step-by-step explanation:
Divide 6 by 4:
[tex]6\cdot\frac{1}{4}=\frac{6}{4}=\frac{3}{2}[/tex]Calculating number of periods?How long will an initial bank deposit of $10,000 grow to $23,750 at 5% annual compound interest?
For an initial amount P with an annually compounded interest rate r, after t years the total amount A is is given by:
[tex]A=P(1+r)^t[/tex]Then we have:
[tex]\begin{gathered} \frac{A}{P}=(1+r)^t \\ \ln\frac{A}{P}=t\ln(1+r) \\ t=\frac{\ln\frac{A}{P}}{ln(1+r)} \end{gathered}[/tex]For P = $10,000, A = $23,750 and r = 0.05, we have:
[tex]t=\frac{\ln\frac{23750}{10000}}{\ln(1+0.05)}\approx17.73\text{ years}[/tex]Write a similarity relating the two triangles in each diagram.
We know by the figure that angles
A random sample of n= 100 observations is selected from a population with u = 30 and 6 = 21. Approximate the probabilities shown below.a. P(x228) b. P(22.1sxs 26.8)c. P(xs 28.2) d. P(x 2 27.0)Click the icon to view the table of normal curve areas.a. P(x228)(Round to three decimal places as needed.)
Problem Statement
We have been given random sample of 100 observations and we have been asked to find the probabilities of getting certain observed values given the population mean of 30 and a standard deviation of 21.
Method
To solve this question, we need to:
1. Find the z-score of the observations. The formula for calculating the z-score is:
[tex]\begin{gathered} z=\frac{X-\mu}{\sigma} \\ \text{where,} \\ X=\text{ The observed value} \\ \mu=\text{population mean} \\ \sigma=\text{ standard deviation} \end{gathered}[/tex]2. Convert the z-score to probability using the z-score table.
Implementation
Question A
1. Find the z-score of the observations.:
[tex]\begin{gathered} X\ge28 \\ \mu=30,\sigma=21 \\ z\ge\frac{28-30}{21} \\ z\ge-\frac{2}{21} \\ \\ \therefore z\ge-0.0952 \end{gathered}[/tex]2. Convert the z-score to probability using the z-score table.:
Using a z-score calculator, we have the probability to be:
[tex]P(z\ge-0.0952)=0.037938[/tex]This probability is depicted in the drawing below:
If the mean is represented by 0 and the right-hand side of 0 has a probability of 0.5, then the probability of getting greater than or equal to 28, is the addition of the probability 0.037938 gotten above with the 0.5 on the right-hand side of zero.
Thus, the answer to Question A is:
[tex]\begin{gathered} P(X\ge28)=0.037938+0.5=0.537938 \\ \\ \therefore P(X\ge28)\approx0.538\text{ (To 3 decimal places)} \end{gathered}[/tex]
Question B:
[tex]undefined[/tex]Directions: Solve the problems below on a separate sheet of paper. You will use a variety of strategies (drawingpictures, building multiple towers, area models, algorithms, and partial products method for division) to solvethe problems. Please submit your answer by writing a complete sentence that expresses the final answer.1. Books are on sale for $8. Peter has $25 in his wallet. How many books can he buy?
books are on sale for $8
Peter has $25 dollar in his wallet
let the numbers of book be x
so,
if a book cost $8
x number of books cost $25
lets put it into mathematical statement
1 = $8
x = $25
lets cross multiply
1 X 25 = 8 X x
25 = 8x
8x = 25
divide both sides by 8
8x/8 = 25/8
x = 25/8
x = 3.125
x = 3 (approximately)
recall, we say x is the numer of books
so,
the number of books peter can by with is $25 in his wallet is 3atement
1