Three times each day, a quality engineer samples a component from a recently manufactured batch and tests it. Each part is classified as conforming (suitable for its intended use), downgraded (unsuitable for the intended purpose but usable for another purpose), or scrap (not usable). An experiment consists of recording the categories of the three parts tested in a particular day.
a. Let A be the event that all the parts fall into the same category. List the outcomes in A.
b. Let B be the event that there is one part in each category. List the outcomes in B.
c. Let C be the event that at least two parts are conforming. List the outcomes in C.
d. List the outcomes in A⋂C
e. List the 27 outcomes in the sample space.
f. List the outcomes in A U B.
g. List the outcomes in A⋂Cc
h. List the outcomes in Ac⋂C.
i. Are events A and C mutually exclusive? Explain.
j. Are events B and C mutually exclusive? Explain.

Answers

Answer 1

Answer:

a. Outcomes of A = { (C,C,C) , (D,D,D), (S,S,S) }

b. Outcomes of B = { (C,D,S),(C,S,D),(D,C,S),(D,S,C),(S,C,D),(S,D,C) }

c. Outcomes of C = { (C,C,C),(C,C,D),(C,C,S),(C,D,C),(C,S,C),(D,C,C),(S,C,C) }

d. Outcomes of A⋂C = { (C,C,C) }

e. Outcomes of Sample space = { (C,C,C), (C,C,D), (C,C,S), (C,D,C), (C,D,D), (C,D,S), (C,S,C), (C,S,D), (C,S,S), (D,C,C), (D,C,D),(D,C,S), (D,D,C), (D,D,D), (D,D,S), (D,S,C), (D,S,D), (D,S,S),   (S,C,C), (S,C,D), (S,C,S), (S,D,C), (S,D,D), (S,D,S), (S,S,C), (S,S,D), (S,S,S) }

f. Outcomes of A U B = { (C,C,C) , (D,D,D), (S,S,S), (C,D,S),(C,S,D),(D,C,S),(D,S,C),(S,C,D),(S,D,C) }

g. Outcomes of A⋂[tex]C^{c}[/tex] = { (D,D,D), (S,S,S) }

h. Outcomes of [tex]A^{c}[/tex]⋂C = {(C,C,D),(C,C,S),(C,D,C),(C,S,C),(D,C,C),(S,C,C)}

i. Events A and C are not mutually exclusive

j. Events B and C are mutually exclusive

Step-by-step explanation:

Given - Three times each day, a quality engineer samples a component

             from a recently manufactured batch and tests it. Each part is

             classified as conforming (suitable for its intended use),  

             downgraded (unsuitable for the intended purpose but usable for  

             another purpose), or scrap (not usable). An experiment consists

             of recording the categories of the three parts tested in a particular

              day.

To find - a. Let A be the event that all the parts fall into the same

                  category. List the outcomes in A.

              b. Let B be the event that there is one part in each category.

                  List the outcomes in B.

              c. Let C be the event that at least two parts are conforming.

                  List the outcomes in C.

              d. List the outcomes in A⋂C

              e. List the 27 outcomes in the sample space.

               f. List the outcomes in A U B.

              g. List the outcomes in A⋂[tex]C^{c}[/tex]

              h. List the outcomes in ⋂C.

              i. Are events A and C mutually exclusive? Explain.

              j. Are events B and C mutually exclusive? Explain.

Proof -

Let

Conforming part = C

Downgraded part = D

Scrap part = S

a.)

Given , Let A be the event that all the parts fall into the same category.

Outcomes of A = { (C,C,C) , (D,D,D), (S,S,S) }

b.)

Given, Let B be the event that there is one part in each category.

Outcomes of B = { (C,D,S),(C,S,D),(D,C,S),(D,S,C),(S,C,D),(S,D,C) }

c.)

Given,  Let C be the event that at least two parts are conforming.

Outcomes of C = { (C,C,C),(C,C,D),(C,C,S),(C,D,C),(C,S,C),(D,C,C),(S,C,C) }

d.)

Outcomes of A⋂C = { (C,C,C) }

e.)

Outcomes of Sample space = { (C,C,C), (C,C,D), (C,C,S), (C,D,C), (C,D,D), (C,D,S), (C,S,C), (C,S,D), (C,S,S), (D,C,C), (D,C,D),(D,C,S), (D,D,C), (D,D,D), (D,D,S), (D,S,C), (D,S,D), (D,S,S),   (S,C,C), (S,C,D), (S,C,S), (S,D,C), (S,D,D), (S,D,S), (S,S,C), (S,S,D), (S,S,S) }

f.)

Outcomes of A U B = { (C,C,C) , (D,D,D), (S,S,S), (C,D,S),(C,S,D),(D,C,S),(D,S,C),(S,C,D),(S,D,C) }

g.)

Outcomes of [tex]C^{c}[/tex]  =  {  (C,D,D), (C,D,S), (C,S,D), (C,S,S), (D,C,D),(D,C,S), (D,D,C), (D,D,D), (D,D,S), (D,S,C), (D,S,D), (D,S,S), (S,C,D), (S,C,S), (S,D,C), (S,D,D), (S,D,S), (S,S,C), (S,S,D), (S,S,S) }

Outcomes of A⋂[tex]C^{c}[/tex] = { (D,D,D), (S,S,S) }

h.)

Outcomes of [tex]A^{c}[/tex] = {(C,C,D), (C,C,S), (C,D,C), (C,D,D), (C,D,S), (C,S,C), (C,S,D), (C,S,S), (D,C,C), (D,C,D),(D,C,S), (D,D,C),  (D,D,S), (D,S,C), (D,S,D), (D,S,S),   (S,C,C), (S,C,D), (S,C,S), (S,D,C), (S,D,D), (S,D,S), (S,S,C), (S,S,D), }

Outcomes of [tex]A^{c}[/tex]⋂C = {(C,C,D),(C,C,S),(C,D,C),(C,S,C),(D,C,C),(S,C,C) }

i.)

As we two that Two events A and C are mutually exclusive iff A ∩ C = ∅

Now,

A ∩ C = { (C,C,C) }

⇒Events A and C are not mutually exclusive.

j.)

As we two that Two events B and C are mutually exclusive iff B ∩ C = ∅

Now,

B ∩ C = ∅

⇒Events B and C are mutually exclusive.


Related Questions

The profit for a company this year was $100,000. Each year the profit increases at a rate of 1.2% per
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a. f(t) = 100,000 0.012^t
b. f(t) = 100,000(1 + 1.2)^t
c. f(t) = 100,000(1 + 0.012)^t
d. f(t) = 100,000 - 1.2^t

Answers

Given:

Initial profit = $100,000

Increasing rate of profit = 1.2%

To find:

The function that shows the company's profit as a function of time in years.

Solution:

The exponential growth model is defined as:

[tex]f(t)=a(1+r)^t[/tex]

Where, a is the initial value, b is the growth rate and t is the time period.

Putting a=100,000 and r=0.012, we get

[tex]f(t)=100,000(1+0.012)^t[/tex]

Where, t is the number of years.

Therefore, the correct option is c.

An archer releases an arrow with an initial velocity of 20 feet per second at a height of 12 feet. The path the arrow takes can be modeled using the function f(x)=−16x2+20x+12, where f(x) represents the height, in feet, of the arrow and x represents the time the arrow travels in seconds. What is the maximum height, in feet, reached by the arrow? Round your answer to the nearest hundredth if necessary. Do not include units in your answer

Answers

Answer: 18.25

Step-by-step explanation:

The arrow reaches its highest point at the y-value of the turning point. Thus, we need to find the maximum quadratic function.

-16x^2+20x+12

We know that the maximum( or minimum) of a parabola is reached at x= -b/(2a)= -20/ 2(-16)= 18.25

Showing that the object will reach a maximum height of 18.25 feet

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Step-by-step explanation:

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Answers

Answer:

Hii, the answer B. 46

Step-by-step explanation:

x+ 53 = 99

So to find what x equals we just do simple subtraction

99 - 53 = 46

so x = 46

Hope this helps!

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determine the intercepts of the line
x intercept (__ , __)
y intercept (__ , __) ​

Answers

Answer:

i think y=2 and x=-7

Step-by-step explanation:

Select all expressions that are equal to 3⋅3⋅3⋅3⋅3.
3^5
3^4 ⋅ 3
5 ⋅ 3
5^3

Answers

[tex]\huge\text{Hey there!}[/tex]

[tex]\mathsf{3\times3\times3\times3\times3}\\\\\mathsf{3\times3=\bf9}\\\\\mathsf{9\times9\times3}\\\\\mathsf{9\times9=\bf81}\\\\\mathsf{81\times3=\bf result}\\\\\mathsf{= \bf \underline{243}}\large\checkmark[/tex]

[tex]\text{Option A. }\downarrow\\\mathsf{3^5}\\\\\mathsf{3^5= 3\times3\times3\times3\times3}\\\\\mathsf{3\times3\times3\times3\times3}\\\\\mathsf{3\times3 = 9}\\\\\mathsf{9\times9\times3}\\\\\mathsf{9\times9 = 81}\\\\\mathsf{81\times3= 243}\\\\\large\text{\bold{Option A.} could possibly be your \bf ANSWER}\huge\checkmark[/tex]

[tex]\text{Option B. }\downarrow\\\mathsf{3^4\times5}\\\mathsf{3^4 = 3\times3\times3\times3}\\\\\mathsf{3\times3\times3\times3}\\\\\mathsf{3\times3=9}\\\\\mathsf{9\times9= 81}\\\\\mathsf{81\times3=243}\\\\\large\text{Option B. could possibly be your \bf ANSWER}\huge\checkmark[/tex]

[tex]\text{Option C. }\downarrow\\\mathsf{3\times5}\\\\\maths{3+3+3+3+3}\\\\\mathsf{3+3=6}\\\\\mathsf{6+6+3}\\\\\mathsf{6+6=12}\\\\\mathsf{12+3=15}\\\\\mathsf{15\neq243}\\\\\large\text{Option C is NOT your ANSWER}[/tex]

[tex]\text{Option D.}\downarrow\\\mathsf{5^3}\\\\\mathsf{5^3=5\times5\times5}\\\\\mathsf{5\times5\times5}\\\\\mathsf{5\times5=25}\\\\\mathsf{25\times5 = 125}\\\\\mathsf{125\neq243}\\\\\large\text{Option D. is NOT your ANSWER}[/tex]

[tex]\boxed{\boxed{\large\text{Answers: \boxed{\boxed{\mathsf{\bf{Option\ A.)\ 3^5 \ \& \ Option\ B.)\ 3^4 \times 3}}}}}}}}\huge\checkmark[/tex]

[tex]\text{Good luck on your assignment and enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

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Step-by-step explanation:

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Answers

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The relation is:

(-3,1),(-2,3),(-1,5),(0,7),(1,9),(2,11)

To find:

The slope and y-intercept for the given relation.

Solution:

Consider any two points from the given relation.

Let the two points are (0,7) and (1,9). So, the slope of the given relation is:

[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]

[tex]m=\dfrac{9-7}{1-0}[/tex]

[tex]m=\dfrac{2}{1}[/tex]

[tex]m=2[/tex]

The slope of the given relation is 2.

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1️⃣Remove parentheses

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2️⃣Collect like terms

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1️⃣Remove parentheses.

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-2z-3+(4c+3c)+(6y+y)

3️⃣Simplify

-2z-3+7c+7y

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QUESTION 3      

1️⃣Subtracting (7.8 - 5.1t) from (2.8 - 3.2t)  

(2.8 - 3.2t) - (7.8 - 5.1t)  

2️⃣Remove the parentheses.  

2.8 - 3.2t - 7.8 + 5.1t  

= 5.1t - 3.2t + 2.8 - 7.8 (we have now shown the difference in another way)  

3️⃣Subtracting the like terms, will give:

1.9t - 5  

4️⃣Recall  

(2.8 - 3.2t) - (7.8 - 5.1t).  

(-3.2t + 2.8) - (-5.1t + 7.8)

Answer:

a. (-3.2t + 2.8) - (-5.1t + 7.8)  

b. 1.9t - 5  

c. (-3.2t + 2.8) - (-5.1t + 7.8)

QUESTION 4

1️⃣Simplify

1/2p-(1/4p-4)

2️⃣Simplify

p2-(p/4-4)

3️⃣Simplify

p2-p/4+4

4️⃣Combine Terms

(p/2-p/4)+4

5️⃣Combine Terms

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Answers

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