This is the last question we have been stuck on it is there anyway you can help us out

This Is The Last Question We Have Been Stuck On It Is There Anyway You Can Help Us Out

Answers

Answer 1

Clearly,

[tex]1.3\cdot10^{12}[/tex]

Is the largest number.

That's because it has more zeros due to its exponent is the most bigger of the four options.


Related Questions

Look at the graphs and their equations below. Then in the information about the ABCand D

Answers

Given:

Given a graph and their equations. Then in the information about the A,B, Cand D

Required:

To fill the blanks.

Explanation:

(a) For each coefficient choose whether it is positive or negative :

A : It has positive coefficient.

B : It has positive coefficient.

C : It has negative coefficient.

D : It has negative coefficient.

(b) Choose the coefficient with the least value:

The graph D.

(c)

5 + kx = 17Solve for x

Answers

1) To solve for x, is to leave the x on the left side the other variables on the right along with the constants, like this

[tex]\begin{gathered} 5\text{ +kx =17} \\ kx\text{ =17-5} \\ x=\frac{17-5}{k} \end{gathered}[/tex]

Note that, we subtracted 5 and then divided by x.

Answer:

5+kx=17

kx=17-5

kx=12

x= 12/k

What is the area of rectangle with a length of 24 meters and a height of 7 meters?A84 square meters84 square metersB600 square meters600 square metersC168 square meters168 square metersD300 square meters

Answers

Answer: C. 168 m²

Explanation

The area of a rectangle (A) is given by:

[tex]A=l\cdot h[/tex]

where l represents the length and h represents the height.

Then, in our case, l = 24m and h = 7m. By replacing the values and simplifying we get:

[tex]A=24m\cdot7m[/tex][tex]A=168m^2[/tex]

o points earned 21 Sally borrowed $500 to help pay for a car repair. The interest rate is 16% and the length of the loan is 30 months. How much money will Sally owe in total at the end of 30 months? Do not enter any spaces.

Answers

Answer:

$700

Explanation;

Givern the following

Amount borrowed = $500 (Principal)

Rate = 16%

Time = 30months = 30/12 yrs

Get the interest

Interest = PRT/100

Interest = 500*16*30/12*100

Interest = 5*16*30/12

Interest = $200

Amount owed at the end of 30months = Principal + Interest

Amount owed at the end of 30months = $500 + $200

Amount owed at the end of 30months = $700

Which of the following describes the graph of h(x)= -2^(x+3)-4. Thanks for the help!

Answers

SOLUTION:

Case: Graphs

Method:

The equation:

[tex]h(x)=-2^{(x+3)}-4[/tex]

We will plug in several values of x

(-3, ?), (0, ?)

[tex]\begin{gathered} (-5,?) \\ h(-3)=-2^{(-3+3)}-4 \\ h(-3)=-2^0-4 \\ h(-3)=-1-4 \\ h(-3)=-5 \\ (-3,-5) \end{gathered}[/tex]

And

[tex]\begin{gathered} (0,?) \\ h(0)=-2^{(0+3)}-4 \\ h(0)=-2^3-4 \\ h(0)=-8-4 \\ h(0)=-12 \\ (0,-12) \end{gathered}[/tex]

Final answer: 3rd Option

The graph:

Solve for x.
11x=2=8x+26

Answers

Answer:

X=8

Step-by-step explanation:

11x=2=8x=+26

11x -8x = -2 +26

3x=24

X=8

Max is scuba diving at elevation of -64.5 feet, when friend signals to come higher. Max makes 2 ascents, each an equal distance to reach an elevation of -21.4 feet, where his friend is located. What was max’s elevation after his first ascent?I come up with -43.1

Answers

Answer: - 42.95 feet

Explanation:

Let each ascent be x. Thus,

2 equal ascents = 2x

From the information given,

initial position = - 64.5 feet

Final position after 2 ascents = - 21.4 feet

This means that

- 64.5 + 2x = - 21.4

2x = - 21.4 + 64.5

2x = 43.1

x = 43.1/2

x = 21.55

Thus, Max's elevation after the first ascent is

- 64.5 + 21.55

= - 42.95 feet

2. A blanket is 4 feet wide. It is 3 times as long as it is wide. Draw a diagram of the blanket, and label its dimensions. b. Find the perimeter and area of the blanket.

Answers

the width of the blanket is 4 ft

it is given that length is 3 times of width so the length is 3 * 4 = 12 ft

part b)

so the blanket is rectangular.

the perimeter of the blanket is

2(4+12) = 32

area of the blanket is

length x width

12 x 4 = 48 square ft

part a)

the diagram of the blanket is given as follows,

-8x+3y= 313x-3y= -18x=y=

Answers

Given the pair of simultaneous equation;

[tex]\begin{gathered} -8x+3y=3 \\ 13x-3y=-18 \end{gathered}[/tex]

We are going to use the method of elimination to solve this.

We will be eliminating the variable y first, since it has the same co-efficient in the two(2) equations.

Thus, we have:

[tex]\begin{gathered} -8x+13x=3-18 \\ 5x=-15 \\ x=-\frac{15}{5} \\ x=-3 \end{gathered}[/tex]

To solve for y, we are going to substitute for x = -3 into any of the two(2) equations.

Thus, we have:

[tex]\begin{gathered} \text{from equation i}i) \\ 13x-3y=-18 \\ 13(-3)-3y=-18 \\ -39-3y=-18 \\ -3y=-18+39 \\ -3y=21 \\ y=-\frac{21}{3} \\ y=-7 \end{gathered}[/tex]

it doesn't matter which of the two points on a line you choose to call (x1,y1) and which you choose to call (x2,y2) to calculate the slope of the line . true or false.

Answers

True

Explanation

the slope of a lines is the change in y over the change in x

[tex]\text{slope}=\frac{change\text{ in y}}{\text{change in x}}=\frac{y_2-y_1}{x_2-x_1}[/tex]

where

[tex]\begin{gathered} \text{P1}=(x_1,y_1) \\ P2=(x_2,y_2) \end{gathered}[/tex]

Step 1

Now, to prove , make

[tex]\begin{gathered} P1(x_2,y_2) \\ P2(x_1,y_1) \\ \end{gathered}[/tex]

now, replace

[tex]\begin{gathered} \text{slope}=\frac{y_1-y_2}{x_1-x_2} \\ \text{slope}=\frac{y_1-y_2}{x_1-x_2}=\frac{-(y_2-y_1)}{-(x_2-x_1)}=\frac{(y_2-y_1)}{(x_2-x_1)} \end{gathered}[/tex]

and we get the same slope, it does not matter wich one of the two points we choose to call P1 and P2.

True

I hope this helps you

What are the roots for the trinomial below? *x2 – 2x – 15O x=-5,x=-3Ox=5,x=-3Ox=3,x=5O x=-5,x=3

Answers

ANSWER:

[tex]x=5,=-3[/tex]

STEP-BY-STEP EXPLANATION:

We have the following equation:

[tex]x^2-2x-15[/tex]

We solve by factoring. We look for two numbers that product -15 and the sum is equal to -2:

[tex]\begin{gathered} 3\cdot-5=-15 \\ 3+(-5)=-2 \\ \text{Therefore:} \\ (x+3)\cdot(x-5)=0 \\ x+3=0\rightarrow x=-3 \\ x-5=0\rightarrow x=5 \end{gathered}[/tex]

Can someone please help me? I’ll give brainly :) question is in photo

Answers

Answer:

Step-by-step explanation:

So basically you would cut the block in half however you'd like but this is how I did it- first you would multiply one side the side I chose has the numbers 7*15*10 so you multiply those getting 1050 then set that aside and do the other side with the numbers of 6*5*10 which if you multiply you would get 300 then you add the first number 1050+300 = 1350 •tbh this might not be correct I tried•

[tex] \frac{1}{2} {x}^{2} + 1 = 2 \times - 1[/tex]Solve the equation

Answers

Solve the system of equations:

4x-2y=10 (1)

y=2x-5 (2)

We can substitute 2 in 1:

4x-2(2x-5)=10

4x-4x+10=10

0=0

Since the solution of the system of equation is 0=0 we can say that it has infinite solutions.

Give the domain and range of a quadratic function whose graph as described. The vertex is (-5,-6) and the parabola opens up. The domain of f is ___

Answers

We will have that it's domain goes from -infinity to infinity.

It's range, goes from infinity to -6.

Find the volume of this right rectangularprism.3 ft15 ft10 ft[? ]ft3

Answers

Given the following question:

[tex]\begin{gathered} volume=l\times b\times h \\ l=15 \\ b=10 \\ h=3 \end{gathered}[/tex][tex]\begin{gathered} volume=l\times b\times h \\ volume=15\times10\times3 \\ 15\times10=150 \\ 150\times3=450 \\ v=450ft^3 \end{gathered}[/tex]

Volume is equal to 450 feet^3.

a cylinder has a volume of 105 and a radius of eight what is the height of the cylinder give an exact answer or approximation to three decimals

Answers

We are asked to determine the height of a cylinder given its radius and its volume. To do that we will use the formula for the volume of a cylinder:

[tex]V=\pi r^2h[/tex]

now, we solve for the height, we get:

[tex]\frac{V}{\pi r^2}=h[/tex]

Now, we plug in the values:

[tex]\frac{105}{\pi(8)^2}=h[/tex]

Solving the operations:

[tex]0.522=h[/tex]

Therefore, the height is 0.522.

1. A function is given by the set of ordered pairs {(2,5),(4,9), (6,13), (8,17)). Write its domain and rangein roster form.Domain:Range:

Answers

The domains are:

{2, 4, 6, and 8}

The range are {5, 9, 13 and 17}

EXPLANATION

Given:

{(2,5),(4,9), (6,13), (8,17))

The above is given in the form (x, y)

where x is the domain and y is the range.

The domains are:

{2, 4, 6, and 8}

The range are {5, 9, 13 and 17}

Can I Plss get some help on this (Number 50)

Answers

EXPLANATION:

Given;

We are given a rectangle with sides as indicated.

Required;

We are required to find the area and the perimeter from the dimensions provided.

Step-by-step solution;

We shall begin by reconstructing the rectangle and show the missing sides. This is done below;

Take note that we can extract one of the triangles and use the dimensions to calculate the missing side. This is also shown below;

Observe that we now have a triangle with sides 17 units and 16 units.

We draw a perpendicular and we effectively split the triangle into two right angled triangles. We can now solve for the side x using the Pythagoras' theorem.

[tex]\begin{gathered} c^2=a^2+b^2 \\ Where: \\ c=hypotenuse \\ a,b=other\text{ }sides \end{gathered}[/tex]

We substitute these into the formula above;

[tex]\begin{gathered} 17^2=x^2+8^2 \\ \\ 289=x^2+64 \end{gathered}[/tex]

Subtract 64 from both sides;

[tex]225=x^2[/tex]

Take the square root of both sides;

[tex]\begin{gathered} \sqrt{225}=\sqrt{x^2} \\ \\ 15=x \end{gathered}[/tex]

Let us now reconstruct the quadrilateral with the new dimension calculated.

We now have the Length and Width of the rectangle and we can now calculate the area and perimeter.

[tex]\begin{gathered} AREA\text{ }OFA\text{ }RECTANGLE: \\ Area=l\times w \\ \\ Area=30\times16 \\ \\ Area=480 \end{gathered}[/tex][tex]\begin{gathered} PERIMETER: \\ Perimeter=2(l+w) \\ \\ Perimeter=2(30+16) \\ \\ Perimeter=2(46) \\ \\ Perimeter=92 \end{gathered}[/tex]

Therefore,

ANSWER:

[tex]\begin{gathered} Area=480units^2 \\ \\ Perimeter=92units \end{gathered}[/tex]

A garden table and a bench cost $669 combined. The garden table costs $81 less than the bench. What is the cost of the bench?

Answers

Given:

The cost of garden table and bench is, 669.

The garden table costs 81 less than bench.

Let us take x as the cost of the bench and y as the cost of the table. Then we have,

[tex]\begin{gathered} x+y=669\ldots\text{.}.(1) \\ y=x-81\ldots.(2) \end{gathered}[/tex]

Now, substituting the value of y in equation 1, we get,

[tex]\begin{gathered} x+x-81=669 \\ 2x=669+81 \\ 2x=750 \\ x=\frac{750}{2}=375 \end{gathered}[/tex]

Thus, the cost of bench is 375.

The annual interest on a $2000 investment exceeds the interest earned on a $1000 investment by $55.The $2000 is invested at a 0.5% higher rate of interest thanthe $1000. What is the interest rate of each investment?

Answers

from the question;

The annual interest on $2000 ivestment exceeds the interest earned on $1000 investment by $55 and the $2000 is invested at a 0.5% higher rate of interest than the $1000

let P = principal

I = interest

R = interest rate

first

[tex]\begin{gathered} \text{Let} \\ P_1=\text{ \$1000 investment} \\ I_1\text{ = x} \\ R_1\text{ = r\%} \end{gathered}[/tex]

given the above information on $1000 investment above and the information above

[tex]\begin{gathered} \text{let } \\ P_2\text{ = \$2000 investment} \\ I_2\text{ = x + 55} \\ R_2\text{ = (r + 0.5)\%} \end{gathered}[/tex]

applying the formula for Interest

[tex]\text{Interest I = }\frac{P\text{ }\times T\text{ }\times\text{ R}}{100}[/tex]

for $1000 investment

[tex]\begin{gathered} u\sin g\text{ the interest formula and inserting the appropriate values} \\ we\text{ get} \\ x\text{ = }\frac{1000\text{ }\times\text{ 1 }\times\text{ r}}{100} \\ x\text{ = 10r -------- (1)} \end{gathered}[/tex]

for $2000 investmet

[tex]\begin{gathered} u\sin g\text{ the interest formula and applying the appropriate values} \\ we\text{ get} \\ x\text{ + 55 = }\frac{2000\text{ }\times\text{ 1 }\times\text{ (r + 0.5)}}{100} \\ x\text{ + 55 = 20(r + 0.5)} \\ x\text{ + 55 = 20r + 10} \\ x\text{ - 20r = 10 - 55} \\ x\text{ - 20r = -45 ----------(2)} \end{gathered}[/tex]

combine the two equations;

[tex]\begin{gathered} x\text{ = 10r -------------(1)} \\ x\text{ - 20r = - 45 ---------(2)} \end{gathered}[/tex]

substitute x=10r into equation 2; we get

[tex]\begin{gathered} 10r\text{ - 20r= -45} \\ -10r\text{ = - 45} \\ \text{divide both sides by -10} \\ \frac{-10r}{-10}\text{ = }\frac{-45}{-10} \\ r\text{ = 4.5} \end{gathered}[/tex]

Therefore,

the interest rate on $1000 investment = 4.5%

The interest rate on $2000 investment is (4.5 + 0.5)% = 5.0%

find the prime factorization ofa) 2205 and b)2525

Answers

(a) 2205.

The prime factorization consist in finding prime numbers which multiplication gives the initial number, to find those prime numbers, we divide the number by 2, 3, or 5, depending on the case. Let's do it.

2205 | 5

441 | 3

147 | 3

49 | 7

7 | 7

1

So, the prime factorization is

[tex]2205=5\times3\times3\times7\times7[/tex]

(b) 2525.

Let's repeat the process as we did with (a).

2525 | 5

505 | 5

101 | 101

1

So, the prime factorization is

[tex]2525=5\times5\times101[/tex]

17 people fit comfortably in a 7 feet by 7 feet area. Use this value to estimate the size of a crowd that is 21 feet deep on both sides of the street along a 3-mile section of a parade route. (Hint: 1mile= 5,280ft) Draw a diagram

Answers

In order to estimate the size of the crowd, let's find the area of the parade route.

The length is 3 miles, that is, 3 * 5280 = 15840 ft.

The width is 2 times 21, so 42 ft.

Therefore the area is:

[tex]A=15840\cdot42=665280[/tex]

Now, to estimate the size of the crowd, let's use a rule of three, knowing that the area for 17 people is 7 * 7 = 49 ft²:

[tex]\begin{gathered} 17\text{ people}\to49\text{ ft}^2 \\ x\text{ people}\to665280\text{ ft}^2 \\ \\ \frac{17}{x}=\frac{49}{665280} \\ x=\frac{665280\cdot17}{49} \\ x=230811.43 \end{gathered}[/tex]

Rounding to the nearest integer, we have 230,881 people.

I need help with number 13 and can you please write your answer using only positive exponents

Answers

Answer:

[tex]\frac{1}{x^{45}}[/tex]

Explanation:

The given expression is

[tex](x^{-5})^9[/tex]

In this case, we can multiply the exponents to get

[tex]x^{-5\cdot9}=x^{-45}[/tex]

Then, to use positive exponents, we need to write it as a fraction

[tex]\frac{1}{x^{45}}[/tex]

Therefore, the answer is

[tex]\frac{1}{x^{45}}[/tex]

A department store is having a clothing sale. If a $35.00 pair of pants has a discount tag of 25% off, what is the sale price? 

Answers

Given Data:

The prise of the pair of the pant is: p= 35

the percentage of discount is: 25%

The expression to calculate the discount sale price is,

[tex]d=p\times\frac{25}{100}[/tex]

Substitute values in the above expression.

[tex]\begin{gathered} d=35\times\frac{25}{100} \\ =35\times0.25 \\ =8.75\text{ } \end{gathered}[/tex]

Thus, the discount price of the pant is $8.75.

Michelle sells new and used kayaks. She makes a 10.5% commission on every kayak she sells and she also gets paid $495.50 per week. a) Develop an equation for the way Michelle is paid. b) Last month, the total value of the kayaks she sold was $19 425. Use the equation you’ve developed to find out how much Michelle was paid for that month.

Answers

Michelle was paid for that month is $ 4021.625

A linear equation is an algebraic equation of the form y=mx+b. regarding only a regular and a first-order (linear) time period, in which m is the slope and b is the y-intercept. on occasion, the above is called a "linear equation of two variables," where y and x are the variables.

Calculation:-

Percentage of commission = 10.5%

per week paid = $495.50

a. Equation of Michelle paid = 10.5/100X + 495.50

b. The total value of the kayaks she sold was $19 425.

  Michelle was paid for that month = 19 425 × 10.5/100 + 4 × 495.50

                                                          = 2039.625 + 1982

                                                          = $ 4021.625

A linear equation bureaucracy is an immediate line on a graph. A nonlinear equation paperwork an S-curve, bell curve, or any other nonlinear form on a graph. experts in mathematics and physics view linear equations as simple. specialists in mathematics and physics view nonlinear equations as complex.

A linear equation in a single variable is an equation wherein there is handiest one variable present. it is of the form Ax + B = 0, wherein A and B are any real numbers and x is an unknown variable that has the handiest one answer. for instance, 9x + 78 = 18 is a linear equation in one variable.

Learn more about linear equations here:-https://brainly.com/question/2030026

#SPJ1

Instructions: Factor the polynomial expression.7x²-13x +6Answer:

Answers

Explanation

Given the polynomial

[tex]7x^2-13x+6[/tex]

We can find its factors below.

[tex]\begin{gathered} 7x^2-13x+6 \\ =7x^2-7x-6x+6 \\ =7x(x-1)-6(x-1) \\ =(7x-6)(x-1) \end{gathered}[/tex]

Answer: (7x-6) and (x-1)

If the scale factor is 5:8, and the actual width of the model is 20 feet, what is the model width?

Answers

If the scale factor is 5:8, it is the same as 5/8.

In order to calculate the width of the model, just multiply its actual width by the scale factor, as follow:

width of the model = (20 ft)(5/8) = 12.5 feet

Hence, the width of the model is 12.5 feet

I need help with 3 , 7 ,4 and 8

Answers

Solution:

Question 3:

The image below gives a vivid explanation of the question

Concept:

The sum of angles in a triangle is

[tex]=180^0[/tex][tex]\begin{gathered} \angle A+\angle B+\angle C=180^0 \\ \angle A=61^0 \\ \angle B=90^0 \\ \angle C=4f+1 \end{gathered}[/tex]

By substituting the values, we will have

[tex]\begin{gathered} \angle A+\angle B+\angle C=180^0 \\ 61^0+90^0+4f+1=180^0 \\ \text{collect similar terms, we will have} \\ 61+90+1+4f=180^0 \\ 152^0+4f=180^0 \\ 4f=180-152^0 \\ 4f=28^0 \\ \text{Divide both sides by 4} \\ \frac{4f}{4}=\frac{28}{4} \\ f=7^0 \end{gathered}[/tex]

Hence,

The final answer is f = 7°

graph the inequality x-2y less than or equal to 0

Answers

To graph the inequality, we can do the following steps.

Step 1: We rearrange the equation so y is on the left and everything else is on the right.

[tex]\begin{gathered} x-2y\le0 \\ \text{ Subtract x from both sides} \\ x-2y-x\le0-x \\ -2y\le-x \\ \text{ Divide by -2 from both sides} \\ \frac{-2y}{-2}\le\frac{-x}{-2} \\ y\ge\frac{x}{2} \end{gathered}[/tex]

Step 2: We plot the line associated with the inequality. For this, we choose two values of x and replace them in the below equation.

[tex]\begin{gathered} x=2 \\ $$\boldsymbol{y=\frac{x}{2}}$$ \\ y=\frac{2}{2} \\ y=1 \\ \text{ Then, the lines passes through the point (2,1).} \end{gathered}[/tex][tex]\begin{gathered} x=4 \\ y=\frac{x}{2} \\ y=\frac{4}{2} \\ y=2 \\ \text{ Then, the lines passes through the point (4,2).} \end{gathered}[/tex]

Since inequality has the symbol ≥, we make a solid line.

Step 3: Since inequality has the symbol ≥, we shade above the line. Therefore, the graph of the inequality is:

Let X represent number of sundaes sold and y represent the number of banana splits sold.Sundaes are sold for $2 each and banana splits for $3 each. They made a total of $150. Equation____________The number of sundaes sold is 5 times more than the number of banana splits sold. Equation________Solve the system of problem questions by substitution

Answers

Given that the total income was $150 by selling 'x' sundaes and 'y' banana splits,

[tex]\begin{gathered} \text{Total Cost}=\text{ Cost per sundae}\cdot\text{ Number of sundae}+\text{ Cost per banana splits}\cdot\text{ Number of banana splits} \\ 150=2x+3y \\ 2x+3y=150\ldots(1) \end{gathered}[/tex]

Also given that the number of sundaes sold is 5 times more than the number of banana splits sold,

[tex]\begin{gathered} x=y+5y \\ x=6y\ldots(2) \end{gathered}[/tex]

Substitute this value in equation (1),

[tex]\begin{gathered} 2(6y)+3y=150 \\ 12y+3y=150 \\ 15y=150 \\ y=10 \end{gathered}[/tex]

The corresponding value of 'x' is calculated by using equation (2) as,

[tex]\begin{gathered} x=6(10) \\ x=60 \end{gathered}[/tex]

Thus, the solution to the system of problem

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