The difference of the height of the buildings is 51.5 for the first building is 165 3/4 feet tall, and the second building is 114 1/4 feet tall.
Given that,
There are two building side of a park.
The first building is 165 3/4 feet tall, and the second building is 114 1/4 feet tall.
We have to find the difference of the height of the buildings.
We have to subtract the first building is 165 3/4 feet tall, and the second building is 114 1/4 feet tall.
165 3/4- 114 1/4
660+3/4- 456+1/4
663/4-457/4
165.75-114.25
51.5
Therefore, The difference of the height of the buildings is 51.5 for the first building is 165 3/4 feet tall, and the second building is 114 1/4 feet tall.
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Dilate the following points by each scale factor (k) provided.P(3, 4) by k=1/2 AndN(4, 15) by k=2
We are asked to dilate the given two points.
P(3, 4) by a scale factor of k = 1/2
Multiply the x and y coordinates by the scale factor.
[tex]P(3,4)\rightarrow P^{\prime}(\frac{1}{2}\cdot3,4\cdot\frac{1}{2})=P^{\prime}(1.5,2)[/tex]Therefore, the dilated point is P'(1.5, 2)
This is an example of reduction.
Similarly,
N(4, 15) by a scale factor of k = 2
Multiply the x and y coordinates by the scale factor.
[tex]N(4,15)\rightarrow N^{\prime}(2\cdot4,2\cdot15)=N^{\prime}(8,30)[/tex]Therefore, the dilated point is N'(8, 30)
This is an example of enlargement.
p varies directly as q. When q = 31.2, p = 20.8. Find p when q = 15.3.a.10.2b.22.95c.42.4i got B ...?
A direct relationship is an association between two variables such that they rise and fall in value together. In another terms, one of the variables is equal to the other times a constant. In our case, we have
[tex]p=kq[/tex]Where k is a constant. To find k, we can use the relation we already know the values.
[tex]\begin{gathered} p(31.2)=20.8 \\ \implies20.8=31.2k \\ k=\frac{20.8}{31.2} \\ k=\frac{2}{3} \end{gathered}[/tex]Then, the relation between our variables is
[tex]p=\frac{2}{3}q[/tex]Evaluating q = 15.3 on this expression, we have
[tex]p=\frac{2}{3}\times(15.3)=10.2[/tex]The answer is 10.2.
what's the difference between a coefficient and a variable
we have that
variables" because the numbers they represent can vary—that is, we can substitute one or more numbers for the letters in the expression. Coefficients are the number part of the terms with variables
example
5x
In the term 5x
x is the variable
5 is a coefficient
The following equation is a conic section written in polar coordinates.=51 + 5sin(0)Step 2 of 2: Find the equation for the directrix of the conic section.
For a conic with a focus at the origin, if the directrix is
[tex]y=\pm p[/tex]where p is a positive real number, and the eccentricity is a positive real number e, the conic has a polar equation
[tex]r=\frac{ep}{1\pm e\sin\theta}[/tex]if 0 ≤ e < 1 , the conic is an ellipse.
if e = 1 , the conic is a parabola.
if e > 1 , the conic is an hyperbola.
In our problem, our equation is
[tex]r=\frac{5}{1+5\sin\theta}[/tex]If we compare our equation with the form presented, we have
[tex]\begin{cases}e={5} \\ p={1}\end{cases}[/tex]Therefore, the directrix is
[tex]y=1[/tex]Please just give me the answer straightforward I don’t need an explanation
Explanation
We are given the function
[tex]y=\frac{1}{2}(3)^{-2x}+6[/tex]First, we have to find the y-intercept
The y-intercept is the point where the graph intersects the y-axis. From the graph, the y-intercept is 6.5
To get the horizontal asymptote
We approach a horizontal asymptote by the curve of a function as x goes towards infinity.
From the graph above,
The horizontal asymptote is
[tex]y=6[/tex]For the transformation
Pauline found the inverse of [9/7 4/3] to be [-3/7 4/-9]. Which calculations will confirm that his (or her) answer is correct? Select all that apply.
In this case, we'll have to carry out several steps to find the solution.
Step 01:
data:
matrix
Step 02:
inverse of a matrix:
[tex]AA^{-1}=\begin{bmatrix}{9} & {4} \\ {7} & {3}\end{bmatrix}\begin{bmatrix}{-3} & {4} \\ {7} & -{9}\end{bmatrix}=\begin{bmatrix}{1} & {0} \\ {0} & {1}\end{bmatrix}[/tex][tex]A^{-1}A=\begin{bmatrix}{-3} & {4} \\ {7} & {-9}\end{bmatrix}\begin{bmatrix}{9} & {4} \\ {7} & {3}\end{bmatrix}=\begin{bmatrix}{1} & {0} \\ {0} & {1}\end{bmatrix}[/tex]That is the full solution.
help me please i want to see if i did it correctly
-1/16
1) Considering that we have the following identity:
[tex]\begin{gathered} \cos (2x)=2\cos (2x)-1 \\ \end{gathered}[/tex]2) We can plug into that the cos (x).:
[tex]\begin{gathered} \cos (2x)=(\frac{\sqrt[]{15}}{4})^2-1 \\ \cos (2x)=\frac{15}{16}-\frac{16}{15} \\ \cos (2x)=-\frac{1}{16} \end{gathered}[/tex]Since for the Quadrant II cosine yields a negative value.
2v – 5V = -24muti step equation
2v - 5v = -24
2v - 5v = -3v, then
-3v = -24
-3 is multiplying on the left, then it will divide on the right
v = -24/(-3)
v = 8
suppose you have 5 apples and you subtract 2 of them, how many apples are left?
You are doing the next computation: 5 apples - 2 apples = 3 apples
What is the result of 2 apples - 5 apples?
you're planning to supply cookies for a staff party. You're thinking of purchasing platters and cookies containing 80 sugar cookies and 15 chocolate chip cookies. what is the ratio of sugar cookies to chocolate chip cookies?
We have the following:
To calculate the proportion, we must calculate the quotient between sugar cookies and chocolate chip cookies, as follows
[tex]\frac{80}{15}=\frac{16\cdot5}{3\cdot5}=\frac{16}{3}[/tex]Which means that for every 3 chocolate chip cookies there are 16 sugar cookies.
Convert: 15 meters=centimeters
EXPLANATION
The relationship between the meters and centimeters is the following:
[tex]1\text{ meter=100 centimeters}[/tex]By applying the unit method, we can get the conversion, as follows:
[tex]Number\text{ of }centimeters=15\text{ meters*}\frac{100\text{ centimeters}}{1\text{ meter}}[/tex]Multiplying terms:
[tex]Number\text{ of centimeters=1500 centimeters}[/tex]The solution is 1500 centimeters.
slo also has cell phone service from Varisoon Wireless. She pays a flat fee of $39.95for 350 minutes per month. Any minutes over 350 are at an additional cost. In November,Noslo's bill for wireless service was $108.70 for 475 minutes. What is the charge perminute for the minutes over 350 per month?
hello
Noslo spent 475minutes on call for that month, but we already know the price on the first 350 minutes
if Noslo is charged $39.95 for 350 minutes, we can subtract $39.95 from $108.70 and also 475 from 350 to know the cost and number of minutes respectively.
the number of minutes is
[tex]475-350=125\text{ minutes}[/tex]the cost of the minutes is
[tex]108.70-39.95=68.75[/tex]so, what this information implies is thar Noslo was charged $68.75 for 125 minutes.
we can easily find how much he's charged per minute from here.
let's make x represent that
[tex]\begin{gathered} 125=68.75 \\ 1=x \\ \text{cross multiply both sides} \\ x\times125=68.75 \\ 125x=68.75 \\ \text{divide both sides by the coefficient of x} \\ \frac{125x}{125}=\frac{68.75}{125} \\ x=0.55 \end{gathered}[/tex]from the calculations above, Nsolo was charged $0.55 per minute
What is the slope of the line that goes through the points (-4, 6) and (2, 8)
Hence the slope is 1/3
In the diagram, find the segment length of FD.(Assume FG is tangent.) G X +9 D 18 E 12
ANSWER
FD = 27
EXPLANATION
By the tangent-secant theorem:
[tex]FG^2=EF\cdot FD[/tex]So we have:
[tex]\begin{gathered} 18^2=12\cdot FD \\ FD=\frac{18^2}{12} \\ FD=27 \end{gathered}[/tex]can someone please help me with the following?
Answer:
y^2 = -12x
Explanation:
For a parabola whose vertex is at (0,0), its standard equation is
[tex]y^2=-4ax[/tex]where the directrix is given by x = a.
Now in our case, the vertex of our parabola is at (0,0) and the directrix is x = 3. This tells us that a = 3 and so the above equation gives
[tex]y^2=-4\cdot3x[/tex][tex]\boxed{y^2=-12x\text{.}}[/tex]which is our answer!
Linear Models: Glaciersm= 745-1000= -255, 15-0= 15, -255/15= -17The average annual rate of retreat of the glacier is 17 meters per year.2. Fill in the table below using the information about the average annual rate of retreatand the length of each glacier in 2010.YearLength in meters201020202030204020503. Create an equation that represents the length of the Easton Glacier as a function ofthe number of years since 2010.
I guess the annual retreat of the glacier is linear, and two points in the line are
[tex](0,1000),(15,745)[/tex]Where x is in years and y in meters.
We can find the equation of a line given two points by using the formula below
[tex]y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]In our case,
[tex]\begin{gathered} y-1000=\frac{745-1000}{15-0}(x-0) \\ \Rightarrow y-1000=-17x \\ \Rightarrow y=-17x+1000 \end{gathered}[/tex]2) Suppose that x=0 corresponds to the year 2010. Then, the information in the table is:
[tex]\begin{gathered} 2010\to-17(0)+1000=1000 \\ 2020\to-17(10)+1000=830 \\ 2030\to-17(20)+1000=660 \\ 2040\to-17(30)+1000=490 \\ 2050\to-17(40)+1000=320 \end{gathered}[/tex]The answers are 1000,830,660,490,320 to to bottom
c)
We already obtained the equation we are asked for in this part of the problem. Remember that we used the points (0,1000) and (15,745)
The equation is:
[tex]y=-17x+1000[/tex]y=-17x+1000
if sin = -3/5 and cos >0 what is exact value of cot?5/3-4/33/4-4/5
Explanation
Given the following information:
[tex]\begin{gathered} Sin=\frac{-3}{5} \\ Cos>0 \end{gathered}[/tex]This implies that the value of sin is negative while that of cos is positive.
This occurs in the fourth quadrant. This also means that the value of tan is negative.
We know that sin uses the value of the opposite and the hypotenuse.
We need to determine the value of the adjacent.
[tex]\begin{gathered} Adjacent=\sqrt{Hyp^2-Opp^2} \\ where \\ Hyp=5 \\ Opp=3 \end{gathered}[/tex][tex]\begin{gathered} Adjacent=\sqrt{5^2-3^2}=\sqrt{25-9}=\sqrt{16} \\ Adj=4 \end{gathered}[/tex]We know that cot is the reciprocal of tan. The value of tan is given as:
[tex]\begin{gathered} Tan=\frac{Opp}{Adj}=\frac{3}{4} \\ But\text{ tan is negative in the fourth quadrant. } \\ \therefore Tan=\frac{-3}{4} \end{gathered}[/tex]We can now determine the value of cot to be:
[tex]Cot=\frac{-4}{3}(reciprocal\text{ of tan\rparen}[/tex]Hence, the answer is the second option i.e. -4/3.
Identify the like terms. 4y, (–7x), 9y, 13
Like terms are terms that have the same variables of similar exponents.
The given terms are:
4y, (–7x), 9y, 13
URGENT!! ILL GIVE
BRAINLIEST!!!! AND 100 POINTS!!!!!
Answer:
c
Step-by-step explanation:
Which measurements could not represent the side lengths of a right triangle?A) 3cm, 4cm, 5cmB)3cm, 5cm, 9cmC)12cm, 16cm, 20cmD)16cm, 63cm, 65cm
The Pythagorean theorem states that for a rigth triangle, the square of the hypothenuse is equal to the sum of squares of the other two sides, symbolically:
[tex]a^2+b^2=c^2[/tex]To check if these sides lengths are of a rigth triangle you have to square them.
Remember that the hypothenuse is always the longest side.
So for the first set:
A)
3cm, 4cm and 5 cm
Lets take the side length 5cm as the hypothenuse
So a=3, b=4 and c=5
If the theorem checks then
[tex]3^2+4^2=5^2[/tex]Square all sides:
[tex]\begin{gathered} 3^2=9 \\ 4^2=16 \\ 5^2=25 \end{gathered}[/tex]Add both squared sides:
[tex]9+16=25[/tex]The result is equal to the square of the hypotenuse, this means that this side lengths corresponds to a rigth triangle.
*-*-*
B)
a=3 cm
b=5 cm
c=9 cm (hypothenuse)
Square the three sides:
[tex]\begin{gathered} a^2=3^2=9 \\ b^2=5^2=25 \\ c^2=9^2=81 \end{gathered}[/tex]If the theorem checks then 9 + 25 must be equal to 81
[tex]9+25=34[/tex]The square sum of both sides is different from the quare of the hypotenuse, these side lengths do not correspond to a rigth triangle.
C)
a=12cm
b= 16 cm
c= 20 cm (hypothenuse)
Square the sides:
[tex]\begin{gathered} a^2=12^2=144 \\ b^2=16^2=256 \\ c^2=20^2=400 \end{gathered}[/tex]If the theorem checks then 144 plus 256 must be 400
[tex]144+256=400[/tex]The sum of squares of the sides is equal to the square of the hypothenuse, this set of side lengths belong to a right triangle.
D)
a=16cm
b=63cm
c=65cm (hypothenuse)
Square the sides:
[tex]\begin{gathered} a^2=16^2=256 \\ b^2=63^2=3969 \\ c^2=65^2=4225 \end{gathered}[/tex]If the theorem checks out, then 256 + 3969 must be equal to 4225:
[tex]256+3969=4225[/tex]The sum of squares of the sides is equal to the square of the hypothenuse, this set of side lengths belong to a right triangle.
In a sequence of numbers, a4= 98, a5= 99.2, a6= 100.4, a7= 101.6, and a8= 102.8. Based on this information,which equation can be used to find an, the nth term in the sequence?
Given:
a4 = 98
a5 = 99.2
a6 = 100.4
a7 = 101.6
a8 = 102.8
Use the arithmetic sequence formula below:
[tex]a_n=a_1+(n-1)d[/tex]Where,
an = nth term
a1 = first term
n = number of terms
d = common differnce
Let's solve for the common differnce.
d = a5 - a4 = 99.2 - 98 = 1.2
Use the 8th term a8, to find the first term:
[tex]\begin{gathered} 102.8=a_1+(8-1)1.2_{} \\ \\ 102.8=a_1+(7)1.2 \\ \\ 102.8=a_1+8.4 \\ \\ a_1=102.8-8.4\text{ = 94.4} \end{gathered}[/tex]Therefore, the first term a1 = 94.4
Thus, the equation for the nth term will be:
Input 94.4 for a1, 1.2 for d in the arithmetic formula above
[tex]\begin{gathered} a_n=94.4+(n-1)1.2 \\ \\ a_n=94.4+1.2n-1.2 \\ \\ \text{combine like terms:} \\ a_n=1.2n+94.4-1.2 \\ \\ a_n=1.2n+93.2 \end{gathered}[/tex]ANSWER:
[tex]a_n=1.2n+93.2[/tex]the length of cuboid is twice the breadth and thrice the height. if the volume of the cuboid is 972cm3 find the breadth of the cuboid
The breadth of the cuboid is 9 cm with the volume as 972 cm³.
Given:
length of the cuboid is twice the breadth and thrice of the height.
If the volume of the cuboid is 972 cm³ then find the breadth of the cuboid= ?
Let breadth of cuboid =x cm
(since length=2*breadth)
hence length=2x
(since given length=3*height
hence height=length/3)
hence height=(2x)/3
volume of cuboid
=length*breadth*height
=972 cm³ (given)
or x*2x*2x/3=972
or 4x³=972*3
or x³=243*3
hence x=(729)⅓
x=(9³)⅓ cm.
(breadth) x=9 cm
Hence the breadth of the cuboid is 9 cm.
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Identify the measure of each exterior angle of a regular dodecagon
Solution:
Given:
A dodecagon is a 12-sided polygon.
A regular dodecagon is a figure with sides of the same length and internal angles of the same size.
The sum of exterior angles of a polygon is 360°.
The formula for calculating the size of each exterior angle is;
[tex]\begin{gathered} \text{Each exterior angle = }\frac{360}{n} \\ \text{where n is the number of sides of the polygon} \end{gathered}[/tex]For a dodecagon, n = 12
Hence,
[tex]\begin{gathered} \text{Each exterior angle = }\frac{360}{12} \\ \text{Each exterior angle = }30^0 \end{gathered}[/tex]Therefore, each exterior angle of a regular dodecagon is 30 degrees.
Meg plans to build a fence around her yard. She draws this diagram of the yard.How many meters of fencing material does Meg need?
The required figure is,
The length of fencing material required = Perimeter of the figure.
Perimeter is calculated as,
[tex]\begin{gathered} Perimeter\text{ = sum of the length of all the sides} \\ Perimeter\text{ = 11.8 m + 18.5 m + 12.1 m +5.4 m + 6.4 m + 6.4 m } \\ Perimeter\text{ = 60.6 m} \\ \end{gathered}[/tex]Thus 60.6 m of fencing material is needed.
This is a intro to statistics question, I was wondering if i can have the work shown soni can see the process, thanks :)Charges for advertising on a TV show are based on the number of viewers, which is measured by the rating. The rating is a percentage of the population of 110 million TV households. The CBS television show 60 Minutes recently had a rating of 7.8, indicating that 7.8% of the households were tuned to that show. An advertiser conducts an independent survey of 100 households and finds that only 10 were tuned to 60 Minutes. Assuming that the 7.8 rating is correct, find the probability of surveying 100 randomly selected households and getting 10 or fewer tuned to 60 Minutes. What does this suggest? Does the advertiser have grounds for claiming a refund on the basis that the size of the audience was exaggerated?
Step-by-step explanation:
7.8% were viewing the show.
so, when picking a single household the probability that is is watching the show is 0.078.
that also means that the probability that this household is not watching the show is 1 - 0.078 = 0.922.
"only" 10 of 100 were watching the show ? that is 10% and therefore a higher rate than measured by the rating agency.
there is no indication that the audience was exaggerated.
anyway, the probability to get 10 or fewer out of randomly picked 100 households to watch the show is
the probability of exactly 10 households watching +
the probability of exactly 9 households watching +
the probability of exactly 8 households watching +
...
the probability of exactly 1 household watching +
the probability of no (0) household watching.
to get the probabilty of any of these events :
x = number of households watching out of the overall 100.
w = probability of a household to watch = 0.078
a = probability of a household to be absent (= not watching) = 0.922
probability(x) = p(x) = w^x × a^(100-x) × c(100, x)
in other words :
the combined probability of "x" households watching and "a" households not watching (which must be 100-x) multiplied by the number of combinations of picking x households out of 100.
so, for the first one, x = 10, we get
p(10) = 0.078¹⁰ × 0.922⁹⁰ × 100! / (10! × (100 - 10)!) =
= 0.078¹⁰×0.922⁹⁰×100×99×...×91 / 10×9×8×...×2 =
= 8.335775831e-012 ×
0.00066955... ×
1.731030945644e+13 =
= 0.096612596...
the rest is then best via Excel or other spreadsheet applications.
p(9) = 0.125496...
p(8) = 0.145117...
p(7) = 0.147558...
p(6) = 0.129888...
p(5) = 0.096969...
p(4) = 0.059699...
p(3) = 0.0291
p(2) = 0.01053
p(1) = 0.002515...
p(0) = 0.000297...
and the sum of all that is the probability to have 10 or fewer households in randomly picked 100 watching the show :
0.843782...
the vast majority of samples of 100 households is expected to have 10 or fewer households watching the show.
this covers the general rating (that would suggest that 7.8 households of 100 are watching the show), some even better ranges (more than 7.8 households), but also everything that is worse than the original rating (below 7.8 households).
when we look at the individual probabilities, we see that the largest probabilities by far are in the categories of 9, 8, 7 and 6 households out of 100 are watching.
so, these are the main expected results when picking samples of 100 households.
therefore, I don't see any indication that the advertiser was "cheated".
Use the formula P = 2l + 2w to find the length l of a rectangular lot if the width w is 55 feet and the perimeter P is 260 feet.l = ? feet
In order to determine the length of the given rectangle, Solve the equation for the perimeter of the rectangle for l and replace w=55ft and P=260ft, and simplify:
[tex]\begin{gathered} P=2l+2w \\ 2l=P-2w \\ l=\frac{P-2w}{2} \\ l=\frac{260ft-2(55ft)}{2} \\ l=\frac{260ft-110ft}{2} \\ l=\frac{150ft}{2}=75ft \end{gathered}[/tex]Hence, the length of the rectangle is 75ft
What is the initial value of the function represented by this table?ху04192140004.0509
The initial value, or y-intercept, is the output value when the input of a linear function is zero.
From the table provided, the y-intercept is obtained when x=0
The answer
I'm having trouble with this problem "Solve the equation -8 + 6m = 1/2 (-4m +16) for m"
Let's begin by listing out the given information:
[tex]\begin{gathered} -8+6m=\frac{1}{2}(-4m+16) \\ \end{gathered}[/tex]Let's proceed to expand the bracket. We have:
[tex]\begin{gathered} -8+6m=\frac{1}{2}(-4m+16) \\ -8+6m=-2m+8 \\ \end{gathered}[/tex]We will put like terms together, we have:
[tex]\begin{gathered} 6m+2m=8+8 \\ 8m=16 \\ \text{Divide both sides by ''8'', we have:} \\ m=\frac{16}{8}=2 \\ m=2 \end{gathered}[/tex]In the trapezoid below, if < BAC = 124 °, what is the measure of < DCA.
ANSWER
[tex]56[/tex]Option B
EXPLANATION
Given;
[tex]\angle BAC=124[/tex]Recall;
[tex]\begin{gathered} \angle DCA+\angle BAC=180 \\ \angle DCA+124=180 \\ \angle DCA=180-124 \\ =56 \end{gathered}[/tex]Which polynomial matches the description below?A binomial with two different variables and a degree of five.
A binomial has two monomials, that discard b and d options.
Two different variables discard a.
Therefore, the correct option is c.
+0.049 where t is in hours after 6:00 AM last Sunday12The temperature in Middletown Park at 6:00 AM last Sunday was 434 degrees Fahrenheit. The temperature was changing at a rate given by r(t) = 3.27 cosROUND ALL ANSWERS TO 2 DECIMAL PLACESAt 10 00 AM last Sunday, the temperature in the park was increasing at a rate ofabout 1.68 degrees per hourFrom 6:00 AM to 1:00 PM last Sunday, the temperature in the park increasedby _degreesWhat was the temperature in the park at 1:00 PM last Sunday? _degreesWhat was the temperature in the park at 4:00 PM Last Friday (5 days later)? _degrees
1 ) According to the question, the temperature has been changing according to this function:
[tex]r(t)\text{ =}3.27\text{ }\cos (\frac{\pi t}{12})+0.049[/tex]Where t is the number of hours after 6:00 am last Sunday
b) From 6 am to 1 pm last Sunday, the temperature in the park increased by
6 am to 1 pm = 7 hours, let's plug into that:
[tex]\begin{gathered} r(t)\text{ =}3.27\text{ }\cos (\frac{\pi t}{12})+0.049 \\ r(7)\text{ =}3.27\text{ }\cos (\frac{7\pi}{12})+0.049 \\ r(7)=3.31732 \\ r(7)\approx3.32 \end{gathered}[/tex]The rate of change in 7 hours was approximately 3.32 degrees per hour
c)
The temperature in the park at 6 am was 43.4 ºF. To find the temperature we must find the value for y, 1 pm Last Sunday. Let's plug the value already found: 1.68 for r.
Considering that according to question a, the temperature increased by 1.68º per hour. 6 am to 10 pm: 4 hours
c)
Since the question wants the temperature from 6 am to 1 pm, and it has been increasing by 3.32 degrees per hour, in 7 hours
7 x 3.32 =23.24º
43.4º+23.24=110.04ºF
d) On Friday, 5 days later there was
5 x 24 at 6am + 10 hours =120+10=130 hours
[tex]\begin{gathered} r(130)\text{=}3.27\text{ }\cos (\frac{130\pi}{12})+0.049 \\ r(130)\text{ =2.7}6 \end{gathered}[/tex]Starting from 43.4º F +2.76 =46.16ºF