The volume of gas kept at a constant pressure varies inversely with the temperature T. If the temperature is 50 degrees, the volume is 20 quick feet. What will the volume be when the temperature is 100 degrees. V= , Temperature=. . Solution
Answers
Given that the volume of gas kept at constant pressure varies inversely with the temperature T and when the temperature is 50 degrees, the volume is 20 cubic feet.
We have to find the volume of gas when the temperature is 100 degrees.
Since it is given that volume varies inversely with the temperature. It means
[tex]T_1V_1=T_2V_2[/tex]Substitute T1 = 50, V1 = 20, T2 = 100.
[tex]\begin{gathered} 50\times20=100\times V_2 \\ 1000=100\times V_2 \\ \frac{1000}{100}=V_2 \\ 10=V_2 \end{gathered}[/tex]Thus, the volume of gas when the temperature is 100 degrees is 10 cubic feet.
Related Questions
(-3x² + 6x - 12) + (5x + 9) is equivalent to expression
Answers
Directoins: consider the leading coefficient of each polynomial function. what is the end behavior of the graph? can check using graphing calculator or Desmos.10. F(x) = 4×over 3 - 3x
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Concept
We can find the degree of a polynomial by identifying the highest power of the variable that occurs in the polynomial. The term with the highest degree is called the leading term because it is usually written first. The coefficient of the leading term is called the leading coefficient.
From the function
[tex]f(x)=4x^3\text{ - 3x}[/tex]Therefore,
The leading coefficient = 4
The degree = 3
Next, the end behavior of the function
The end behavior of a polynomial function is the behavior of the graph of f(x) as x approaches positive infinity or negative infinity. So, the sign of the leading coefficient is sufficient to predict the end behavior of the function.
Interpretations:
As x tends to positive infinity, f(x) tend to positive infinity
As x tends to negative infinity, f(x) tend to positive infinity
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Answers
Given:
Three numbers are 42, 90 and 144.
Required:
What is the highest common factor
Required:
We know the factors of 42
Answer: 42, 90 and 144.
Step-by-step explanation:
x - y + z = - 3x - y - z = - 35x - 5y + z = - 15Solution: _, _, _
Answers
Given -
x - y + z = -3
x - y - z = -3
5x - 5y + z = -15
To Find -
Solution =?
Step-by-Step Explanation -
x - y + z = -3 ........(1)
x - y - z = -3 ..........(2)
5x - 5y + z = -15 .........(3)
So, from equation 1:
z = -3 -x + y
Now, put the value of z in equation 2 and 3:
x - y - (-3 -x + y) = -3
2x - 2y = -6
x - y = -3 ........(4)
5x - 5y + (-3 -x + y) = -15
4x - 4y = -12
x - y = -3 ......(5)
Now, on subtracting equations (5) and (6):
x - y -(x - y) = -3 - (-3)
x - x + y - y = 3 - 3
0 = 0
So, The System of equations has infinitely many solutions
Final Answer -
Solution: infinitely many solutions
Find the probability of getting a 1, 5, or 6 when you roll a standard six-sided die.Select the correct answer below:1/61/31/22/35/6
Answers
Step 1
Write out the expression for the probability of an event occurring
[tex]Pr(\text{event occurring) = }\frac{number\text{ of required outcomes}}{\text{Total number of outcomes}}[/tex]Where,
Total of required outcomes= 6
Step 2
Find the probability of getting a 1
[tex]Pr(1)=\text{ }\frac{1}{6}[/tex]Step 3
Find the probability of getting a 5
[tex]Pr(5)\text{ =}\frac{1}{6}[/tex]Step 4
Find the probability of getting a 6
[tex]Pr(6)=\frac{1}{6}[/tex]Step 4
Find the probability of getting a 1,5 or 6
[tex]Pr(1,5\text{ or 6)=Pr}(1)+Pr(5)+Pr(6)_{}[/tex][tex]\begin{gathered} Pr(1,5\text{ or 6) = }\frac{1}{6}+\frac{1}{6}+\frac{1}{6} \\ Pr(1,5\text{ or 6) = }\frac{1}{2} \end{gathered}[/tex]Hence, the probability of getting a 1, 5 or 6 when you roll a standard six-sided die = 1/2
Nathan and Tony hiked in the woods yesterday and came home with poison ivy. Tony has 5 times as many spots as Nathan. How many spots does Nathan have, x? Which table represents this situation?
Answers
Here, we want to get the correct equation and select the correct table
From the question, we have it that Tony has 5 times what Nathan had
Hence, given that Nathan has x, Tony has 5 times this and we have it as;
[tex]5\times x\text{ = 5x}[/tex]What this mean is that the right column of the table will be 5 times what is on the left column
Hence, the correct table here is the table with the heading 5x
A bag contains 31 coins, some dimes and some quarters. The total amount of money in the bag is $4.45. How many dimes and how many quarters are in the bag?_____dimes_____quarters
Answers
A bag contains 31 coins, some dimes and some quarters. The total amount of money in the bag is $4.45. How many dimes and how many quarters are in the bag?
_____dimes
_____quarters
we know that
1 quarter=$0.25
1 dime=$0.10
Let
x -----> the number of quarters
y ----> the number of dimes
we have that
x+y=31 ------> equation A
0.25x+0.10y=4.45 -----> equation B
Solve the system of equations
Isolate the variable x in equation A
x=31-y ------> equation C
Substitute equation C in equation B
so
0.25(31-y)+0.10y=4.45
solve for y
7.75-0.25y+0.10y=4.45
0.25y-0.10y=7.75-4.45
0.15y=3.30
y=22 dimes
Find the value of x
x=31-22
x=9 quarters
therefore
the answer is
22 dimes9 quarters3(2x - 5) – 4x > 7x + 10.Please help
Answers
EXPLANATION.
To solve the inequality we must follow some steps:
1.1.the number 3 must multiply the values that are inside the parentheses
Hi, can you help me answer this question please, thank you!
Answers
Given:
Two populations
Sample Size (n₁) = 202
Success (x₁) = 122
Sample size (n₂) = 340
Success (x₂) = 220
Find: test statistic and p-value of this sample
Solution:
Based on the given data, we have two proportions here and its sample size is large. The test statistic that is appropriate for this would be Test of Two Proportions and the formula is:
[tex]z=\frac{p_1-p_2+cont\text{ }}{\sqrt[]{\frac{p(1-p)}{n_1}+\frac{p(1-p)_{}}{n_2}}}[/tex]in which,
[tex]p=\frac{x_1+x_2}{n_1+n_2}[/tex]Let's solve the value of p first. Let's plug in the given data that we have above.
[tex]p=\frac{122+220}{202+340}=\frac{342}{542}=\frac{171}{271}[/tex]Now that we have the value of p, let's calculate p₁ and p₂. Formula is:
[tex]\begin{gathered} p_1=\frac{x_1}{n_1}=\frac{122}{202}=\frac{61}{101} \\ p_2=\frac{x_2}{n_2}=\frac{220}{340}=\frac{11}{17} \end{gathered}[/tex]Lastly, let's calculate the value of cont or continuity correction. Formula is:
[tex]cont=\frac{F}{2}(\frac{1}{n_1}+\frac{1}{n_2})\text{ }[/tex]For our claim p₁ < p₂, our F = 1.
[tex]cont=\frac{1}{2}(\frac{1}{202}+\frac{1}{340})=0.0039458[/tex]Let's plug these values to the test of two proportions formula:
[tex]\begin{gathered} z=\frac{p_1-p_2+cont\text{ }}{\sqrt[]{\frac{p(1-p)}{n_1}+\frac{p(1-p)_{}}{n_2}}} \\ z=\frac{\frac{61}{101}-\frac{11}{17}+0.0039458}{\sqrt[]{\frac{\frac{171}{271}(1-\frac{171}{271})}{202}+\frac{\frac{171}{271}(1-\frac{171}{271})_{}}{340}}} \end{gathered}[/tex][tex]z=\frac{-0.03915259}{\sqrt[]{\frac{0.2328399668}{202}+\frac{0.2328399668}{340}}}=\frac{-0.03915259}{0.04286603008}\approx-0.913[/tex]Hence, the test statistic is -0.913.
The equivalent p-value for this is 0.1805.
The p-value is greater than α = 0.05.
Since p-value is greater than α, we fail to reject the null hypothesis.
3. A business account was opened with $225,000earning 6.25% interest compounded yearly. Whatis the balance in the account after 3 years? Howmuch interest is earned after 3 years?
Answers
Answer:
Balance = 269,897.15
Interest earned 44,879.15
Explanation:
The compound interest formula is
[tex]A=P(1+r)^t[/tex]where P is the principal amount, is the interest rate, and t is the time interval.
Now in our case, we have
P = $225,000
r = 6.25%/100
t = 3 years
therefore, the final amount is
[tex]A=225,000(1+\frac{6.25}{100})^3[/tex][tex]\boxed{A=\$269,879.15}[/tex]which is the balance earned in 3 years.
The interest earned is the final amount minus the initial amount
[tex]\begin{gathered} I=A-P \\ I=\$269,879.15-\$225,000 \end{gathered}[/tex][tex]\boxed{I=\$44,879.15}[/tex]which is the interest earned in 3 years.
I need help with math
Answers
a)
3000x - 2000 = 10 000
Add 2000 to both-side of the equation
3000x - 2000 + 2000 = 10 000 + 2000
3000x = 12000
Divide both-side of the equation by 3000
3000x/3000 = 12000/3000
x = 4
b) -2x/3
[tex]\frac{-2x}{3}-\frac{x}{7}=\text{ 17}[/tex]Multiply through the equation by 21
[tex]21(\frac{-2x}{3})-21(\frac{x}{7})=\text{ 17(21)}[/tex][tex]7(-2x)\text{ - 3x =357}[/tex]-14x - 3x = 357
-17x = 357
Divide both-side of the equation by -17
x = -21
c)
[tex]\frac{5}{2}x-\frac{1}{3}=\text{ 13}[/tex]Add 1/3 to both-side of the equation
[tex]\frac{5x}{2}=13\text{ +}\frac{1}{3}[/tex][tex]\frac{5x}{2}=\text{ }\frac{39+1}{3}[/tex][tex]\frac{5x}{2}=\frac{40}{3}[/tex]cross-multiply
15x = 80
Divide both-side of the equation by 15
x= 5.33
d)
[tex]\frac{3}{10}+\frac{2x}{5}=\frac{1}{2}[/tex]multiply through the equation by 10
[tex]10(\frac{3}{10})+10(\frac{2x}{5})=10(\frac{1}{2})[/tex]3 + 2(2x) = 5
3 + 4x = 5
subtract 3 from both-si
A train is traveling at a constant speed of 105 mph how many feet does a travel in three seconds remember that 1 mile is 5280 feet
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We are given that a train is traveling at the following constant speed:
[tex]v=\frac{105\text{ miles}}{hour}[/tex]We are asked to determine the distance after 3 seconds. To do that, let's remember that speed is the ratio between distance and time, that is:
[tex]v=\frac{d}{t}[/tex]Where:
[tex]\begin{gathered} d=\text{ distance} \\ t=\text{ time} \end{gathered}[/tex]Since we want to determine the distance we will multiply both sides of the equation by "t":
[tex]vt=d[/tex]Now, we substitute the values:
[tex]\frac{105\text{ miles}}{hour}\times(3s)=d[/tex]Since the velocity is given per unit of hour, we need to convert the 3 seconds into hours. We do that using the following conversion factor:
[tex]1\text{hour}=3600s[/tex]Now we multiply the time by the conversion factor:
[tex]3s\times\frac{1h}{3600s}=\frac{1}{1200}h[/tex]Now we substitute in the formula for the distance:
[tex]\frac{105\text{ miles}}{hour}\times(\frac{1}{1200}hour)=d[/tex]Solving the operations:
[tex]\frac{7}{80}miles=d[/tex]Now, we convert the miles into feet using the given conversion factor:
[tex]1\text{mile}=5280\text{feet}[/tex]Now, we multiply by the conversion factor:
[tex]d=\frac{7}{80}\text{miles}\times\frac{5280feet}{1mile}[/tex]Solving the operations:
[tex]d=462feet[/tex]Therefore, the distance is 462 feet.
A store sells packages of candy for $52. Each packet cost $4 to make and contains $48 flavored gum and candy.Rolando knows how much each candy cost per pound and knows how many pounds of each candy are packed in each package. Let x represent the amount of gum per pound in each package and y represent the amount of candy per pound in each package.Use the following equation to complete the questions: x+y=180.75x+5.25y+4=52how many pounds of candy are in a box?what is the price per pound for a piece of candy?what does the term 0.75x represents in the second equation?
Answers
Let:
x be the amount of gum in pounds in each package.
y be the amount of candy in pounds in each package.
Each box or package cost $52: a packaging that cost $4 and $48 in gum and candy.
The amount of candy (in pounds) in each package is shown in the equation:
[tex]x+y=18[/tex]As this is the sum of the amount of gum x and the amount of candy y, we can say that each package has 18 pounds of candy and gum.
Then, the following equation,
[tex]0.75x+5.25y+4=52[/tex]seems to be the total cost, as it results in 52, that is the total cost of the box. There is also a term with value 4, that corresponds to the packaginf cost.
The other terms represent the cost of the gum (0.75 * x) and the candy (5.25 * y).
We can read from this equation that the price per pound of the gum is 0.75, because it is the factor that multiply the amount x to calculate the cost.
In the same way, we can say that 5.25 is the price per pound of the candy, as it is the factor that multiplies y.
Answers
How many pounds of candy are in a box? 18 pounds
What is the price per pound for a piece of candy? 5.25 $/lb
What does the term 0.75x represents in the second equation? The second equation represents the sum of all the costs (gum, candy and packaging cost). The term 0.75x represents the cost of the gum, as it multiplies the price of the gum per pound (0.74 $/lb) and the amount of gum (x, in lb/package).
IF LA = LB and LB = LC, then LA = LC. What property has been illustrated? a. Transitive b. Substitutionc. Distributived. Reflexive
Answers
The transitive property states that if x = y and y = z, then x = z
Considering the given scenario, IF LA = LB and LB = LC, then LA = LC, by comparing this statement with the earlier statement, we can see that
LA = x
LB = y
LC = z
Thus, the property being illustrated is
a. Transitive
8 pounds of bananas cost $24. How much would 31 pounds cost
Answers
31 pounds cost $93
Explanation
you can easily solve this by using a rule of three.
Step 1
Let x represents the cost for 31 pounds,the proportion is
[tex]\frac{x}{31}[/tex]Now
[tex]\begin{gathered} 24\text{ usd}\rightarrow8\text{ Pounds} \\ \text{the proportion must be the same, then} \\ \frac{24}{8}=\frac{x}{31} \\ 3=\frac{x}{31} \\ \end{gathered}[/tex]Step 2
solve for x
[tex]\begin{gathered} 3=\frac{x}{31} \\ x=3\cdot31 \\ x=93 \end{gathered}[/tex]Hence, 31 pounds cost $93
I hope this helps you
Last year, Jenny opened an investment account with $7400. At the end of the year, the amount in the account had decreased by6.5%. How much is this decrease in dollars? How much money was in her account at the end of last year?
Answers
if the decreasing amount is 6.5% the r in our decay function will be:
[tex]1-0.065=0.935[/tex]and in one yeat t=1 so the equation will be:
[tex]\begin{gathered} y=7400(0.936)^1 \\ y=6925.4 \end{gathered}[/tex]john ran at a pace of 3.5 miles per hr for a distance of 10.5 miles. how many minutes did it take them to run 10.5miles? use the distance formula: d= rt to where d is total distance, r is rate and t is time
Answers
d=rt
divide both-side of the equation by r
t =d/r
distance = 10.5 miles
we will go ahead and find the rate r
r = 3.5/60
r=0.05833
substituting into t= d/r
t = 10.5 / 0.05833
t=180 minutes
Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the correct position in the answer box. Release your mouse button when the item is place. If you change your mind, drag the item to the trashcan. Click the trashcan to clear all your answers. Click on an item at the bottom of the problem. Click again to drop each statement in the appropriate spot in the flow chart for adding fractions.
Answers
Let's say we want to add 1/2 and 1/3. Since they both have different denominators, first we find the LCD:
[tex]\text{LCD}(2,3)=2\cdot3=6[/tex]Now that we have the LCD, we express the fractions with a common denominator:
[tex]\frac{1}{2}+\frac{1}{3}=\frac{3}{6}+\frac{2}{6}[/tex]Now that we have both fractions with the same denominator, we can add directly the numerators and keep the denominator:
[tex]\frac{3}{6}+\frac{2}{6}=\frac{5}{6}[/tex]We have that 1/2+1/3=5/6. Since 5/6 can't be reduced anymore, we have found the result.
To summarize, the algorithm to solve addition of fraction would be like this:
Scooby needs to ship some DVDs. He has 16 comedy movies, 12 scary movies and 8 action movies. He can pack only one type of DVD in each box and he must pack the same number of DVDs in each box. What is the greatest number of DVDs Scooby can pack in each box?A.2B.4C.6D.8
Answers
He has 16 comedy movies, 12 scary movies and 8 action movies.
He can pack only one type of DVD in each box and he must pack the same number of DVDs in each box
So, we need to find the greatest common factor between 16 , 12 and 8
16 = 2 * 2 * 2 * 2
12 = 2 * 2 * * 3
8 = 2 * 2 * 2
---------------------------------
2 * 2 = 4
So,
The greatest number of DVDs Scooby can pack in each box = 2 * 2 = 4
The answer is option B. 4
----------------------------------------------------------
More explanations :
So, he will pack 16 comedy movies at 4 packs, each pack has 4 DVDs
And he will pack 12 scary movies at 3 packs, each pack has 4 DVDs
And he will pack 8 action movies at 2 packs, each pack has 4 DVDs
So, the total number of packs = 4 + 3 + 2 = 9 packs
11. Write ____ as a single radical using the smallest possible root.
Answers
Answer:
[tex]\sqrt[6]{n^{23}}[/tex]Explanation:
The given expression is
[tex]\sqrt{n^5}\sqrt[3]{n^4}[/tex]To simplify, we first need to write them in exponent form
[tex]n^{\frac{5}{2}}\cdot n^{\frac{4}{3}}[/tex]Now, we can add the exponents
[tex]\begin{gathered} n^{\frac{5}{2}}\cdot n^{\frac{4}{3}}=n^{\frac{5}{2}+\frac{4}{3}}=n^{\frac{23}{6}} \\ \\ Because \\ \frac{5}{2}+\frac{4}{3}=\frac{5(3)+2(4)}{2(3)}=\frac{15+8}{6}=\frac{23}{6} \end{gathered}[/tex]Finally, we can write the expression in radical form
[tex]n^{\frac{23}{6}}=\sqrt[6]{n^{23}}[/tex]Therefore, the answer is
[tex]\sqrt[6]{n^{23}}[/tex]did the teacher go wrong in making the square in the circle?! that’s what the question is asking pls help
Answers
Given two arcs, we follow the steps:
1) Label the intersection point of each pair of arcs as U and V:
2) Next, we need to construct the perpendicular bisector of the segment UV and label the intersection points to the circumference as P and Q:
3) Finally, we draw four line segments connecting the successive points on the circumference of the circle:
Looking at the steps given in the problem, the answer is:
The teacher makes a mistake in Step 2
What is the volume of the triangular prism?3.2 cm length 6 cm height5.4 cm width A: 8.64 cmB: 17.28 cmC: 51.84 cmD: 103.68 cm
Answers
The volume of a prism can be calculated by multiplying the area of the base of the prism times its height:
[tex]V=A\cdot h[/tex]On the other hand, the area of the base of a triangle can be found by multiplying 1/2 times its base times its height (don't confuse the height of the triangle with the height of the prism):
[tex]A=\frac{1}{2}b\times h[/tex]Substitute the values for the base of the triangle and its height to find the area of the base. Then, substitute the result for the area and the value of the height of the prism to find the volume of the triangular prism.
If the base of the triangle has a length of 5.4cm, and its height is 3.2cm, then:
[tex]\begin{gathered} A=\frac{1}{2}\times5.4\operatorname{cm}\times3.2\operatorname{cm} \\ =8.64cm^2 \end{gathered}[/tex]If the height of the prism is 6cm, then its volume is:
[tex]\begin{gathered} V=8.64cm^2\times6\operatorname{cm} \\ =51.84cm^3 \end{gathered}[/tex]Therefore, the volume of the triangular prism, is:
[tex]51.84cm^3[/tex]b Exit Ticket COS 28 = C 12 tan 28 = b с 12 28 b Download image X
Answers
Answer
b = 22.6 units
c = 25.6 units
Explanation
In a right angle triangle, the side opposite the right angle is the Hypotenuse, the side opposite the given angle that is non-right angle is the Opposite and the remaining side is the Adjacent.
For this question,
Hypotenuse = c
Opposite = 12
Adjacent = b
Trignometric ratios can then be used to find b and c.
CAH and TOA
Cos 28° = (Adj/Hyp)
Cos 28° = (b/c)
Tan 28° = (Opp/Adj)
Tan 28° = (12/b)
Cross multiply
b = 12/(Tan 28°)
b = 12/0.5317
b = 22.57
We can then solve for c
Cos 28° = (b/c)
Cos 28° = (22.57/c)
Cross multiply
c = (22.57/Cos 28°)
c = (22.57/0.8829)
c = 25.56 units
Hope this Helps!!!
Really need help solving this, having trouble with it. It is trigonometry and it is from my online ACT prep guide
Answers
Solution
For this case we have the following:
Statement True False
sin (60º)= sqrt(3)/2 X
cot (pi)= 1 X
cos (-240º)= 1/2 X
csc(3pi/4)= sqrt(2)/2 X
Use the graph to find the indicated values:line with y intercept at (0,3) and x intercept at (2,0)f(0)=AnswerIf f(x)=0 then x=?Answerf^{-1}(0)=AnswerIf f^{-1}(x)=0 then x=?Answer
Answers
From the graph:
[tex]f(0)=3[/tex]If:
[tex]\begin{gathered} f(x)=0 \\ then \\ x=2 \end{gathered}[/tex]For the last ones, we can use this fact:
The domain of the inverse of a function is the same as the range of the original function. Therefore:
[tex]f^{-1}(0)=2[/tex]If:
[tex]\begin{gathered} f^{-1}(x)=0 \\ then \\ x=3 \end{gathered}[/tex]What would be the angles for K, J, and L?
Answers
The given is a triangle. As we know that the sum of all the interior angles in a triangle is 180 degrees, we have,
[tex]\begin{gathered} 6x-5+x+8+2x-3=180 \\ 9x=180 \\ x=\frac{180}{9}=20 \end{gathered}[/tex]Therefore, the angles can be calculated as,
[tex]\begin{gathered} K=6\times20-5=115 \\ J=20+8=28 \\ L=2\times20-3=37 \end{gathered}[/tex]need answer with steps[tex](7 + 9i) + ( - 5i)[/tex]
Answers
Gy, this is the solution:
(7 + 9i) + ( - 5i)
Solving the parenthesis:
7 + 9i - 5i
7 + 4i
In triangle ABC, angle A is a right angle. What are possible measurements for B & C?
Answers
Given the triangle ABC.
Angle A is a right angle which equals 90 degree.
And sum of angles in a triangle equals 180 degree.
[tex]\begin{gathered} A+B+C=180^0 \\ 90^0+B+C=180^0 \\ B+C=180^0-90^0 \\ B+C=90^0 \end{gathered}[/tex]So, the possible measurement of B and C must be the ones who's sum is 90 degree.
[tex]\begin{gathered} 40\text{ \& 50 }\rightarrow40+50=90 \\ 30\text{ \& 60}\rightarrow30+60=90 \\ 45\text{ \& 45}\rightarrow45+45=90 \\ 80\text{ \& 30}\rightarrow80+30=110 \\ 60\text{ \& 40}\rightarrow60+40=100 \end{gathered}[/tex]Therefore, the ones whose sum equals 90 degree are the answers;
[tex]\begin{gathered} 40\text{ \& 50} \\ 30\text{ \& 60} \\ 45\text{ \& 45} \end{gathered}[/tex]please help me solve. blank I have 9 and blank 2 I have 5. blank 2 is correct but not blank 1.
Answers
We have that
[tex]\begin{gathered} 3\cdot\sqrt[]{45}=3\cdot(\sqrt[]{9\cdot5}) \\ =\text{ 3(}\sqrt[]{9}\cdot\sqrt[]{5}\text{)} \\ =\text{ 3(3 }\cdot\sqrt[]{5}) \\ =9\cdot\sqrt[]{5} \end{gathered}[/tex]So the answer is
[tex]9\cdot\sqrt[]{5}[/tex]part 1- Selected Response
Which of the following linear equations
have a negative y- intercept? Circle all that
apply.
A. y = 6x
Cy=
-3x +2
2
E. y=
• X
3
B.y=-5 + 2x
D.y=-x+8
F.y=-5
Answers
Answer: B, C, D and F
Step-by-step explanation: The y-intercept of a linear equation is the point at which the line crosses the y-axis. The y-axis is the vertical axis on a graph, and it is the axis where the x-coordinate is always 0. To find the y-intercept of a linear equation, we can set the x-coordinate to 0 and solve for the y-coordinate.
For example, consider the linear equation y = 6x. If we set the x-coordinate to 0, we get the equation 0 = 6 * 0, which simplifies to 0 = 0. Therefore, the y-intercept of this equation is (0, 0).
On the other hand, consider the linear equation y = -3x + 2. If we set the x-coordinate to 0, we get the equation 0 = -3 * 0 + 2, which simplifies to 0 = 2. Therefore, the y-intercept of this equation is (0, -2).
In general, a linear equation will have a negative y-intercept if the constant term in the equation is negative. In this case, the linear equations that have a negative y-intercept are B, C, D, and F. Therefore, the correct answer is B, C, D, and F.